An appliance company determines that in order to sell x dishwashers, the price per dishwasher must be p = 420 - 0.3x. It also determines that the total cost of producing x dishwashers is given by C(x) = 5000 + 0.3x2. How many dishwashers must the company produce and sell in order to maximize profit? g

Answers

Answer 1

The company must produce and sell 350 dishwashers in order to maximize profit.

How to determine  the number of dishwashers

To determine the number of dishwashers the company must produce and sell in order to maximize profit, we need to find the value of x that corresponds to the maximum point of the profit function.

The profit (P) is given by the equation:

P(x) = Revenue - Cost

The revenue is calculated by multiplying the price per dishwasher (p) by the number of dishwashers sold (x):

Revenue = p * x

The cost is given by the function C(x):

Cost = C(x)

Therefore, the profit function can be expressed as:

P(x) = p * x - C(x)

Substituting the given expressions for p and C(x):

P(x) = (420 - 0.3x) * x - (5000 + 0.3x²)

Expanding and simplifying the equation:

P(x) = 420x - 0.3x² - 5000 - 0.3x²

Combining like terms:

P(x) = -0.6x² + 420x - 5000

To find the value of x that maximizes profit, we need to find the vertex of the quadratic function. The x-coordinate of the vertex can be determined using the formula:

x = -b / (2a)

In our case, a = -0.6 and b = 420:

x = -420 / (2 * -0.6)

x = -420 / (-1.2)

x = 350

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Answer 2

350 dishwashers must the company produce and sell in order to maximize profit.

Maxima means a point at which the function attains the maximum value.

Given the following information:

Price per dishwasher, p = 420 - 0.3x

Total cost of producing x dishwashers, C(x) = 5000 + 0.3x2

Profit= Total Selling price- Total Cost Price

Total Selling price of x dishwasher, S.P= xp

S.P=x(420 - 0.3x)

S.P=420x - 0.3x²

Profit= 420x - 0.3x² - ( 5000 + 0.3x²)

Profit= 420x - 0.3x² - 5000 - 0.3x²

Profit=  -0.6x²+420x-5000

So, profit, f(x)=-0.6x²+420x-5000

To determine the value of x so that maximum profit is possible:

1. Calculate the first derivative of profit function and calculate the value of x by equating it to zero.

2. Select that value of x for which the profit function attains the maximum value, to check the maxima calculate 2nd derivative, if it gives a negative value for the value of x. Then, x is the point of maxima for the given function.

[tex]f(x)=-0.6x^2+420x-5000\\f\prime(x)=-1.2x+420\\f\prime(x)=0\\-1.2x+420=0[/tex]

Calculating the value of x by transposing,

x=420/1.2

x=350

To check maxima, calculating second derivative.

[tex]f\prime(x)=-1.2x+420=0\\f\prime\prime(x)=-1.2[/tex]

2nd derivative is negative, it means that x=350 is the point of maxima.

Thus, a company must produce and sell 350 dishwashers in order to maximize profit.

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Related Questions

Find the coordinate vector [Bold x ]Subscript Upper B of x relative to the given basis BequalsStartSet Bold b 1 comma Bold b 2 comma Bold b 3 EndSet

Answers

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

In the question equation is missing so, the equation and its solution can be defined as follows:

[tex]B={b_1,b_2}\\\\b_1= \left[\begin{array}{c}5&5\end{array}\right] \ \ \ \ \b_2= \left[\begin{array}{c}2&-5\end{array}\right] \ \ \ \ \x= \left[\begin{array}{c}-7&-35\end{array}\right][/tex]

[tex]\left[\begin{array}{c}a&c\end{array}\right] =?[/tex]

[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= a\left[\begin{array}{c}5&5\end{array}\right]+c \left[\begin{array}{c}2&-5\end{array}\right] \\[/tex]

[tex]\to \left[\begin{array}{c}-7&-35\end{array}\right]= \left[\begin{array}{c}5a+2c&5a-5c\end{array}\right]\\\\\to 5a+2c=-7....(1)\\\\\to 5a-5c=-35....(2)\\\\[/tex]

subtract equation 1 from equation 2:

[tex]\to 7c=28\\\\\to c=\frac{28}{7}\\\\\to c= 4\\\\[/tex]

put the value of c in equation 1

[tex]\to 5a+2(4)=-7\\\to 5a+8=-7\\\to 5a=-7-8\\\to 5a=-15\\\to a= -3[/tex]

coordinate  value is [-3,4].

weights of men: 90% confidence; n = 14, x=161.3 lb, s =12.6 lb

Answers

Answer:

The answer is below

Step-by-step explanation:

Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation . Assume that the population has a normal distribution. Round the confidence interval limits to the same number of  decimal places as the sample standard deviation.

Answer: Given that:

Sample size (n) = 14, mean ([tex]\mu[/tex]) = 161.3, standard deviation ([tex]\sigma[/tex]) = 12.6

Confidence(C)= 90% = 0.9

α = 1 - C = 1- 0.9 = 0.1

α/2 = 0.1 / 2 = 0.05

The z score of α/2 correspond to a z score of 0.45 (0.5 - 0.05). This gives:

[tex]z_{\frac{\alpha}{2} }=1.645[/tex]

The margin of error (E) is given by the formula:

[tex]E=z_{\frac{\alpha}{2} }\frac{\sigma}{\sqrt{n} } =1.645*\frac{12.6}{\sqrt{14} }=5.5[/tex]

The confidence interval = μ ± E = 161.3 ± 5.5 = (155.8, 166.8)

The confidence interval is between 155.8 lb and 166.8 lb. There is a 90% confidence that the mean is between 155.8 lb and 166.8 lb.

Consider the y-intercepts of the functions. F(c)=1/5lx-15l, g(x) =(x-2)2, the y-coordinate of the greatest y-intercept is ______

Answers

Answer: 4

Step-by-step explanation:

Given functions:

[tex]f(x)=\dfrac{1}{5}|x-15|\\\\ g(x)=(x-2)^2[/tex]

We know that the y--intercept of a function is the value of the function at x=0.

so, put x=0 in both the functions.

The y-coordinate of the y-intercept of f(x) = [tex]f(0)=\dfrac{1}{5}|0-15|=\dfrac{15}{5}=3[/tex]

The y-coordinate of the y-intercept of g(x) = [tex]g(0)=(0-2)^2=2^2=4[/tex]

As 4 > 3, that means he y-coordinate of the greatest y-intercept is 4.

6th grade math, help me please:)

Answers

Answer:

A. 3/5

Step-by-step explanation:

Simple math, 9/15. Divide both by 3.

3*3=9 and 3*5=15 so answer is 3/5!

Answer:

answer is A

Step-by-step explanation:

this is a probability question

divide the number of baskets made by the total number of attempts

9/15 = 3/5

He claims that the measures of the three sides of triangle ABX are all equal to AX, making AABX equilateral. Since this makes central angle AXB
measure 60°,mAB = 60°. Dylan also claims that by repeatedly applying the same argument, he can prove that the inscribed hexagon is regular.
Which statement is true?

Answers

The answer would have to be 60

Statement A " Dylan's reasoning about arc AB is correct, and the hexagon is regular. option (A) is correct.

What is a regular polygon?

A polygon is a geometric figure with a finite number of sides in two dimensions. On the sides or edges of a polygon, straight-line segments are joined end to end to form a closed shape. The vertices, also known as corners, are the points where two line segments meet and form an angle.

[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

Three sides of the triangle ABX are all equal to AX, making ΔABX equilateral. Since this makes central angle AXB measure 60°,

m(arc)AB = 60°

AX = BX = AB

The measure of AXB = 60 degrees

m(arc)AB = 60 degrees

On applying the same argument, the inscribed hexagon is regular.

Statement A is correct.

Thus, statement A " Dylan's reasoning about arc AB is correct, and the hexagon is regular. option (A) is correct.

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Algebra 2, I need help!!! Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious for me. Thank you.

Answers

Answer:

Third option

Step-by-step explanation:

We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:

x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2

a person can do a job in 6 day days . another can do the same job in 4days . if they work together, how long do they need to finish the job?

Answers

Answer:

It will take them 2 2/5 days working together

Step-by-step explanation:

To find the time worked

1/a + 1/b = 1/t

Where a and b are the times worked individually and t is the time worked together

1/4 + 1/6 = 1/t

Multiply each side by 12t to clear the fractions

12t( 1/4 + 1/6 = 1/t)

3t + 2t =12

Combine like terms

5t = 12

Divide by 5

t = 12/5

t = 2 2/5

It will take them 2 2/5 days working together

what is the quotient of (2x^4-3x^3–3x^2+7x-3)/(c^2-2x+1)

Answers

Answer:

[tex]2x^2 + x - 3[/tex]

Step-by-step explanation:

We want to divide [tex]2x^4 - 3x^3 - 3x^2 + 7x - 3[/tex] by [tex]x^2 - 2x + 1[/tex]

To do the long division, divide each term by [tex]x^2[/tex] and then subtract the product of the result and [tex]x^2 - 2x + 1[/tex]  from the remaining part of the equation.

Whatever term/value you obtain from each step of the division is a part of the quotient.

When you reach 0, you have gotten to the end of the division.

Check the steps carefully and follow them below:

Step 1:

Divide [tex]2x^4[/tex] by [tex]x^2[/tex]. You get [tex]2x^2[/tex].

Step 2

Multiply [tex]2x^2[/tex] by  [tex]x^2 - 2x + 1[/tex]  and subtract from [tex]2x^4 - 3x^3 - 3x^2 + 7x - 3[/tex]:

 [tex]2x^4 - 3x^3 - 3x^2 + 7x - 3 - (2x^4 - 4x^3 + 2x^2)[/tex] = [tex]x^3 - 5x^2 + 7x - 3[/tex]

Step 3

Divide [tex]x^3[/tex] by [tex]x^2[/tex]. You get x.

Step 4

Multiply x by  [tex]x^2 - 2x + 1[/tex]  and subtract from  [tex]x^3 - 5x^2 + 7x - 3[/tex]:

[tex]x^3 - 5x^2 + 7x - 3 - (x^3 - 2x^2 + x) = -3x^2 +6x - 3[/tex]

Step 5

Divide [tex]-3x^2[/tex] by [tex]x^2[/tex]. You get -3

Step 6

Multiply -3 by [tex]x^2 - 2x + 1[/tex]  and subtract from [tex]-3x^2 +6x - 3[/tex]:

[tex]-3x^2 +6x - 3 - (-3x^2 + 6x -3) = 0[/tex]

From the three divisions, we got [tex]2x^2[/tex], x and -3.

Therefore, the quotient is [tex]2x^2 + x - 3[/tex].

The automatic opening device of a military cargo parachute has been designed to open when the parachute is 135 m above the ground. Suppose opening altitude actually has a normal distribution with mean value 135 and standard deviation 35 m. Equipment damage will occur if the parachute opens at an altitude of less than 100 m. What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes? (Give your answer to four decimal places.)

Answers

Answer:

the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215

Step-by-step explanation:

Let consider Q to be the opening altitude.

The mean μ = 135 m

The standard deviation = 35 m

The probability that the equipment damage will occur if the parachute opens at an altitude of less than 100 m can be computed as follows:

[tex]P(Q<100) = P(\dfrac{X- 135}{\sigma} < \dfrac{100 - 135}{35}})[/tex]

[tex]P(Q<100) = P(z< \dfrac{-35}{35}})[/tex]

[tex]P(Q<100) = P(z<-1)[/tex]

[tex]P(Q<100) = 0.1587[/tex]

If we represent R to be the number of parachutes which have equipment damage to the payload out of 5 parachutes dropped.

The probability of success = 0.1587

the number of independent parachute n = 5

the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes can be computed as:

P(R ≥ 1) = 1 - P(R < 1)

P(R ≥ 1) = 1 - P(R = 0)

The probability mass function of the binomial expression is:

P(R ≥ 1) = [tex]1 - (^5_0)(0.1587)^0(1-0.1587)^{5-0}[/tex]

P(R ≥ 1) =[tex]1 - (\dfrac{5!}{(5-0)!})(0.1587)^0(1-0.1587)^{5-0}[/tex]

P(R ≥ 1) = 1 - 0.5785

P(R ≥ 1) = 0.4215

Hence, the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215

The numbers of regular season wins for 10 football teams in a given season are given below. Determine the​ range, mean,​ variance, and standard deviation of the population data set.

2​, 10​, 15​, 4​, 11​, 10​, 15​, 10​, 2​, 10

Answers

Answer:

a

   [tex]R =13[/tex]

b

  [tex]\= x =8.9[/tex]

c

 [tex]var(x) = 16.57[/tex]

d

 [tex]\sigma = 4.1[/tex]

Step-by-step explanation:

From the question we are given a data set  

      2​, 10​, 15​, 4​, 11​, 10​, 15​, 10​, 2​, 10

     The sample size is  n  = 10

 The range is  

         [tex]R = maxNum - MinNum[/tex]

Where maxNum  is the maximum number on the data set  which is 15

 and  MinNum  is the minimum  number on the data set  which is  2

   So

           [tex]R = 15 - 2[/tex]

           [tex]R =13[/tex]

The mean is mathematically represented as

          [tex]\= x = \frac{\sum x_i}{N}[/tex]

substituting values

          [tex]\= x = \frac{2 + 10 + 15 + 4 + 11 + 10 + 15 + 10 + 2 + 10 }{10}[/tex]

         [tex]\= x =8.9[/tex]

The variance is mathematically evaluated as

        [tex]var(x) = \frac{\sum (x - \= x)^2}{N}[/tex]

substituting values

      [tex]var(x) = \frac{(2 - 8.9 )^2 + (10 - 8.9 )^2 + (15 - 8.9 )^2 +(4 - 8.9 )^2 +(11 - 8.9 )^2 +(10 - 8.9 )^2 +(15 - 8.9 )^2 +(10 - 8.9 )^2 +} {10}[/tex]                    [tex]\frac{(2 - 8.9 )^2 +(10 - 8.9 )^2 }{10}[/tex]

[tex]var(x) = 16.57[/tex]

The standard deviation is  [tex]\sigma = \sqrt{var(x)}[/tex]

substituting values

         [tex]\sigma = \sqrt{16.57}[/tex]

        [tex]\sigma = 4.1[/tex]

The exact heights of different elephants Choose the correct answer below. A. The data are continuous because the data can only take on specific values. B. The data are discrete because the data can take on any value in an interval. C. The data are discrete because the data can only take on specific values. D. The data are continuous because the data can take on any value in an interval.

Answers

Answer:

Option d: The data are continuous because the data can take on any value in an interval.

Step-by-step explanation:

The data are continuous if they can take on any value within a range. In this case study, there are different elephants including small/young ones and big ones/old ones.

Thus, their heights will vary and can take on any value within a particular range.

The eighth grade class at Seven Bridges Middle School has 93 students. Each student takes a current events class, a foreign language class, or both a current events class and a foreign language class. There are 70 eighth graders taking a current events class, and there are 54 eighth graders taking a foreign language class. How many eighth graders take only a current events class and not a foreign language class?

Answers

Answer:

31

Step-by-step explanation:

The computation of eighth graders take only a current events class and not a foreign language class is shown below:-

We will assume the x that shows the number of students which we will take  both languages

So, the equation will be

70 + 54 - x = 93

-x = 93 - 124

x =  31 students

So the number of eighth graders only take a current event class is

= 70 - 39

= 31 students

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.


Match the trigonometric ratios with their values based on the triangle shown in the diagram.






Answers

Answer:

 A-2, B-DNE*, C-3, D-DNE, E-4, F-1

---------------------

The first attachment shows the solutions to A and C.

The second attachment shows the solutions to E and F.

There are no real number solutions to systems B and D.

_____

In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.

A.

 (3-x) +12 = x^2 +x

 15 = x^2 + 2x

 16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root

 ±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A

__

B.

 (x -1) -15 = x^2 +4x

 -16 = x^2 +3x

 -13.75 = x^2 +3x +2.25 = (x +1.5)^2

roots are complex: -1.5 ±i√13.75

__

C.

 (1-2x) +5 = x^2 -3x

 6 = x^2 -x

 6.25 = x^2 -x + .25 = (x -.5)^2

 ±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C

__

remaining problems are done in a similar way.

_____

* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.

---------------------

Hope this helps!

Brainliest would be great!

---------------------

With all care,

07x12!

Wren recorded an outside temperature of –2°F at 8 a.m. When she checked the temperature again, it was 4°F at 12:00 p.m. If x represents the time and y represents the temperature in degrees Fahrenheit, what is the slope of the line through these two data points? Answer choices 0.5 -0.5 1.5 -1.5

Answers

Answer:

[tex]\boxed{1.5}[/tex]

Step-by-step explanation:

First point is given (8, -2)

                               (x₁, y₁)

Second point is given (12, 4)

                                     (x₂, y₂)

Apply the slope formula.

[tex]slope=\frac{rise}{run}[/tex]

[tex]slope=\frac{change \: in \: y}{change \: in \: x}[/tex]

[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]slope=\frac{4-(-2)}{12-8}[/tex]

[tex]slope=\frac{6}{4}=1.5[/tex]

A slope is also known as the gradient of a line. The slope of the line through these two data points is 1.5°F per hour.

What is Slope?

A slope also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.

slope = (y₂-y₁)/(x₂-x₁)

Given that the temperature recorded at 8 am is –2°F, while the temperature recorded at 12 pm is 4°F. The number of hours between 8:00 am to 12 pm is 4 hours. Therefore, the slope of the line through these two data points is,

Slope, m = [4°F – (–2°F)] / 4 hours = 6°F / 4 hours = 1.5°F per hour

Hence, the slope of the line through these two data points is 1.5°F per hour.

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an auto dealer offers a compact car, a midsize, a sport utility vehicle, and a light truck, each either in standard, custom, or sport styling, a choice of manual or automatic transmission, and a selection from 7 colors. How many ways of buying a vehicle from this dealer are there?

Answers

Answer: 168

Step-by-step explanation:

First, let's count the types of selection:

We can select:

Type of car: a compact car, a midsize, a sport utility vehicle, and a light truck (4 options)

Pack: standard, custom, or sport styling, (3 options)

type of transmission: Manual or automatic (2 options)

Color: (7 options)

The total number of combinations is equal to the product of the number of options in each selection:

C = 4*3*2*7 = 168

Tom compared 2/12 and 7/6 by first comparing each fraction to 1/2 and 1. In which step did Tom make his first mistake?

Answers

Answer:

2/12 is not 1/2 it is 1/6 and 7/6 is greater than 1

Step-by-step explanation:

His comparison to each fraction was incorrect, to simplify fractions you must do to the numerator what you do to the denominator. Find the common number between them and divide. In the case of 2/12 the number would be 2, divide each by that and you get 1/6, Toms comparisons are not proportionate

A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find the length and the width

Answers

Answer: 78

Step-by-step explanation:

Length and width are 78 meters and 114 meters

A triangle has an area of 900m2 . If a parallelogram has the same height and base as the triangle, what is the area of the parallelogram?

Answers

Answer:

1800 [tex]m^{2}[/tex] is the area of parallelogram.

Step-by-step explanation:

Given that:

Area of a triangle = 900 [tex]m^{2}[/tex]

To find:

Area of a parallelogram which has same height and base as that of the given triangle.

Solution:

First of all, let us have a look at the formula for Area of a parallelogram:

[tex]Area_{Par} = Base \times Height[/tex] ...... (1)

So as to find the area of a parallelogram, we need to have the product of Base and Height of Parallelogram.

Now, let us have a look at the formula for area of a triangle:

[tex]Area_{Tri} = \dfrac{1}{2} \times Base \times Height[/tex]

Given that height and base of triangle and parallelogram are equal to each other.

So,the product of base and height will also be equal to each other.

[tex]900 = \dfrac{1}{2} \times Base \times Height\\\Rightarrow Base \times Height = 2 \times 900\\\Rightarrow Base \times Height = 1800\ m^2[/tex]

By equation (1):

Area of parallelogram = 1800 [tex]m^{2}[/tex]

Find three consecutive odd integers so that the sum of twice the first, the second
and three times the third is 152.

Answers

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

A clinic treated 536 children over a 4month period how many children did the clinic treat in 1month

Answers

536 children = 4 months

536/4 children = 4/4 months ... divide both sides by 4

134 children = 1 month

The clinic treated 134 children in 1 month. This is assuming that every month was the same number of patients.

Answer: 134

Step-by-step explanation:

Solution,

Number of children treated in 4 months = 536

Now, let's find the number of children treated in one month:

[tex] = \frac{total \: number \: of \: childrens \: }{total \: month} [/tex]

Plug the values

[tex] = \frac{536}{4} [/tex]

Calculate

[tex] = 134 \: [/tex] childrens

Therefore, A clinic treated 134 childrens in one month.

Hope this helps...

Best regards!!

water drips from a faucet at a rate of 41 drops/ minute. Assuming there are 15,000 drops in gallon, how many minutes would it take for the dripping faucet to fill a 1 gallon bucket? Round your answer to the nearest whole number​

Answers

Answer:

366 Minutes

Step-by-step explanation:

What is the current value of a zero-coupon bond that pays a face value of $1,000 at maturity in 6 years if the appropriate discount rate is 4%.

Answers

Answer:4

Step-by-step explanation:

A zero-coupon bond  doesn’t make any payments. Instead, investors purchase the zero-coupon bond for less than its face value, and when the bond matures, they receive the face value.

To figure the price you should pay for a zero-coupon bond, you'll follow these steps:

Divide your required rate of return by 100 to convert it to a decimal.

Add 1 to the required rate of return as a decimal.

Raise the result to the power of the number of years until the bond matures.

Divide the face value of the bond to calculate the price to pay for the zero-coupon bond to achieve your desired rate of return.

First, divide 4 percent by 100 to get 0.04. Second, add 1 to 0.04 to get 1.04. Third, raise 1.04 to the sixth power to get 1.2653. Lastly, divide the face value of $1,000 by 1.2653 to find that the price to pay for the zero-coupon bond is $790,32.

Graph the equation y=−4x+3 by plotting points.

Answers

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

y=4x+3

The winery sold 81 cases of wine this week. If twice
as many red cases were sold than white. how many
white cases were sold this week?​

Answers

Answer:

21 cases

Step-by-step explanation:

red cases=2x.    white cases=x

2x+x=81

3x=81

x=21 cases

f(x)=−4x−9 when x=−5.

Answers

Answer:

11

Step-by-step explanation:

x=-5

-4(-5)-9

=20-9

=11

Hope this helps, and marking me as a brainliest would help me too;)

Answer:

11

Step-by-step explanation:

We just have to plug in -5 for x and when we do so we get f(-5) = -4 * (-5) - 9 = 20 - 9 = 11.

What is the slope of the line described by the equation below?
y - 5 = -3(x - 17)

O A. -5
OB. 5
O c. -3
D. 3

Answers

Answer:

C) -3

Step-by-step explanation:

We are given the following equation:

[tex]y-5=-3(x-17)[/tex]

And we want to determine its slope.

Note that this is in point-slope form. Recall that in point-slope form, we have:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope and (x₁, y₁) is an ordered pair.

From the equation, we can see that the value in front of the parentheses will be the slope of the line.

The value in front of the parentheses of our given equation is -3.

In conclusion, the slope of the line described by the equation is -3.

Hence, our answer is C.  

The circumference of C is 72cm. What is the length of AB (the minor arc)

Answers

Answer:

Step-by-step explanation:

Can you please include a image?

Thanks!!!

The heights of three trees are 0.41m, 2.10m and 3.52m. Find their average height

Answers

Answer:

2.01m; 0.41m + 2.10m + 3.52m = 6.03 6.03/3= 2.01

Step-by-step explanation:

0.41m + 2.10m + 3.52m = 6.03 6.03/3= 2.01

The average height of the three trees is 2.01 meters.

Given that,

The heights of the three trees are 0.41m, 2.10m and 3.52m.

To find the average height of the three trees,

Use the formula for calculating the mean

Add up their heights and then divide by the total number of trees.

So, we have:

Average height = (0.41 m + 2.10 m + 3.52 m) ÷ 3

We can simplify this expression:

Average height = 6.03 m ÷ 3

Average height = 2.01 m

Therefore, the average height of the three trees is 2.01 meters.

To know more about average visit:-

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Which sequence of transformations on preimage Triangle ABC will NOT produce the image A’B’C’

Answers

Answer:

b

Step-by-step explanation:

You may assume the conditions for regression inference are satisfied. A grass seed company conducts a study to determine the relationship between the density of seeds planted (in pounds per 500 sq ft) and the quality of the resulting lawn. Eight similar plots of land are selected and each is planted with a particular density of seed. One month later the quality of each lawn is rated on a scale of 0 to 100. The sample data are given below.
Seed Density Lawn Quality
1 30
1 40
2 40
3 40
3 50
3 65
4 50
5 50
At the 1% level of significance, is there evidence of an association between seed density and lawn quality?
a) yes
b) no

Answers

Answer:

b) no

Step-by-step explanation:

The regression analysis is a statistical technique which is used for forecasting. It determines the relationship between two variables. It determines the relationship of two or more dependent and independent variables. It is widely used in stats to find trend in the data. It helps to predict the values of dependent and independent variables. In the given question, the relationship is determined to identify the relationship between density of seed planted and quality of lawn. The significance level is 1% which means strength of evidence is not strong enough to support the test.

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