An ant travels 33cm in walking completely around the edges of a rectangle. If the rectangle is twice as long as it is wide, how long is the shortest side?

Answer:11

Step-by-step explanation:Vertically opposite angles are the same.
Alternate(Z)angles are the same.Therefore we have an angle of 143 vertically opposite to the equation.143-55=88
88/8=11

a) The probability of selecting two even numbered balls before odd numbered balls is 1/6.

b) The probability of not selecting balls in size order is 22/24 or 11/12.


a) There are 4! (24) ways to arrange the four balls. There are 2! ways (2) to arrange the even balls and 2! ways (2) to arrange the odd balls, so there are 2x2=4 favorable ways (2,4,1,3 and 4,2,1,3). The probability is 4/24, which simplifies to 1/6.

b) There are only 2 ways to select balls in size order (1,2,3,4 and 4,3,2,1). Subtracting these from the total arrangements (24-2) results in 22 non-size ordered selections. The probability is 22/24, which simplifies to 11/12.

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the integral by reversing the order of integration. the result will be F(β) - F(α), which is the integral evaluated after reversing the order of integration.

First, let's rewrite your integral more clearly:

∫∫ R 7x dy dx, where R is the region of integration.

To reverse the order of integration, we first need to determine the limits of integration for R in terms of x and y. Let's assume the current limits are a to b for x and c(y) to d(y) for y.

Now, we need to express these limits in terms of y and x. Let's denote the new limits as α to β for y and γ(x) to δ(x) for x.

After finding the new limits, we can rewrite the integral as:

∫∫ R 7x dx dy

Now, evaluate the integral by integrating first with respect to x and then with respect to y:

1. Integrate 7x with respect to x: (7/2)x^2 + C₁(x)
2. Apply the limits of integration for x: [(7/2)δ(x)^2 + C₁(δ(x))] - [(7/2)γ(x)^2 + C₁(γ(x))]
3. Integrate the result with respect to y: ∫[α, β] [(7/2)(δ(y)^2 - γ(y)^2)] dy
4. Apply the limits of integration for y: F(β) - F(α)

The final result will be F(β) - F(α), which is the integral evaluated after reversing the order of integration.

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The calculated value of the actual area of the playground is 5625π

From the question, we have the following parameters that can be used in our computation:

A scale drawing of a playground had a scale of 15

This means that

Scale factor = 15/1

Evaluate

Scale factor = 15

The actual area of the park in meters squared is calculated as

Area = Area of scale * Scale factor²

Substitute the known values in the above equation, so, we have the following representation

Area = Area of scale * 15²

Using the area of circle, we have

Area = π5² * 15²

Evaluate

Area = 5625π

Hence, the actual area is 5625π

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Answer:

Jack now makes $10.45

Step-by-step explanation:

First, we need to find 10% of 9.50. To do that we must divide 9.50 by 10 or simply move the decimal one place to the left to get 0.95. 0.95 is 10% of 9.50. Now we must ADD 0.95 to 9.50 because Jack is getting a 10% raise.  0.95 + 9.50 = 10.45. Therefore Jack makes $10.45 per hour at his job.

Answer:

5*5*3

5²*3

Step-by-step explanation:

Assuming that we have to find prime factorization of 75:

75 = 25 * 3

75 = 5*5*3

The volume of the cube-shaped speaker is 42.875 cubic inches. The volume of the package is 68 cubic inches. Subtracting the volume of the speaker from the volume of the package gives the empty space remaining, which is 25.125 cubic inches.

The volume of the cube-shaped speaker is given by V₁ = (edge length)³ = 3.5³ = 42.875 cubic inches.

The volume of the square prism-shaped package is given by V₂ = (base area) x (height) = 16 x 4.25 = 68 cubic inches.

Therefore, the empty space remaining in the package after the speaker is placed in it is V₂ - V₁ = 68 - 42.875 = 25.125 cubic inches.

So, the empty space remaining in the package is 25.125 cubic inches.

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The expression that represents the area of the parking lot is (5 - 7) * (3 + 4).

The length of the parking lot can be represented as (5 - 7), which simplifies to -2. The width of the parking lot can be represented as (3 + 4), which simplifies to 7. To find the area of a rectangle, we multiply the length by the width.

Therefore, the expression that represents the area of the parking lot is (-2) * 7. Multiplying -2 by 7 gives us -14. So, the area of the parking lot is -14 square units.

However, it is important to note that negative areas do not have practical meaning in this context, as areas are typically positive values. Therefore, the area of the parking lot would be considered 14 square units.

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The interquartile range (IQR) of the given data set is 4.

Interquartile range (IQR) is a measure of variability in a data set that measures the spread of the middle 50% of the data. It is calculated as the difference between the third quartile (Q3) and the first quartile (Q1).

To find the interquartile range (IQR), we first need to find the median of the data set.

The median is the middle value of the dataset when the data is arranged in order. In this case, the data set is already in order, so the median is the middle value or the average of the two middle values:

Median = (26 + 28) / 2 = 27

Now, we need to find the first quartile (Q1) and the third quartile (Q3) of the data set.

Q1 is the median of the lower half of the data set, and Q3 is the median of the upper half of the data set.

Lower half: 22, 24, 26

Upper half: 28, 30

Q1 = median of the lower half = (24 + 26) / 2 = 25

Q3 = median of the upper half = (28 + 30) / 2 = 29

Now we can find the IQR:

IQR = Q3 - Q1 = 29 - 25 = 4

Therefore, the interquartile range (IQR) of the given data set is 4.

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With the masses, the value of a and b will be 6 and 5.

The value of m is 6.

The mass of an African elephant is 6,125,000 grams, or about 6 x 10⁶grams. Thus, b = 6.

The mass of a silverback gorilla is 185,000 grams, or about 1.85 x 10⁵grams. Thus, c = 5.

We are told that the mass of the African elephant is about 10 times the mass of the silverback gorilla, where m is an integer.

Let's write this as an equation:

6 x 10ⁿ = 10(1.85 x 10⁵)

Simplifying this equation, we get:

6 x 10ⁿ = 1.85 x 10⁶

10ⁿ = 3.08 x 10⁵

Taking the logarithm (base 10) of both sides, we get:

m = log(3.08 x 10)

Using a calculator, we find that:

m ≈ 5.49

Since m must be an integer, we round up to the nearest integer and get:

m = 6.

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Meena would have to pay a total of $57 for her family if she were to buy 3 snacks for everybody to share.

Meena would have to pay a total of $42 + 5xx for her family if she bought xx snacks for everybody to share.

To calculate the total money Meena would have to pay for her family, including movie tickets and snacks, we'll first look at the scenario with 3 snacks to share.

1. Calculate the cost of movie tickets: Meena + 2 kids = 3 tickets at $14 each.
  3 tickets * $14 = $42

2. Calculate the cost of 3 snacks at $5 each.
  3 snacks * $5 = $15

3. Add the cost of movie tickets and snacks.
  $42 + $15 = $57

Meena would have to pay a total of $57 for her family if she were to buy 3 snacks for everybody to share.

For the scenario where she buys xx snacks:

1. Calculate the cost of movie tickets (same as before):
  3 tickets * $14 = $42

2. Calculate the cost of xx snacks at $5 each.
  xx snacks * $5 = 5xx

3. Add the cost of movie tickets and snacks.
  $42 + 5xx = $42 + 5xx

Meena would have to pay a total of $42 + 5xx for her family if she bought xx snacks for everybody to share.

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The value of measure of angle WPN is,

⇒ m ∠WPN = 108°

We have to given that;

Parallel lines EN, BH, and RK, with transversal PW are shown.

And, m ∠ BMV = 108° and m ∠KVS = 72°

Now, We get by definition of vertically opposite angle;

m ∠ BMV = m ∠PWN = 108°

Hence, By definition of alternate angle we get;

⇒ m ∠PWN = m ∠WPN = 108°

Thus, The value of measure of angle WPN is,

⇒ m ∠WPN = 108°

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The average price of a gallon of milk in the following years, using the exponential growth function, are:

a) 2018 = $2.90

  2021 = $3.55

b) Based on the exponential growth function, the cost of milk is inflating at 7% per year.

c) Based on the percentage of inflation, the predicted price of a gallon of milk in 2025 is $4.66.

An exponential growth function is a mathematical equation that describes the relationship between two variables (dependent and independent).

Under the function, there is a constant ratio of growth with the number of years between the initial value and the desired value as the exponent.

The given function for the price of average gallon of milk from 2008 to 2021 is 3.55 = 2.90 (1 + x)³.

Average price of milk in 2018 = $2.90

Average price of milk in 2021 = $3.55

Change in the average price of milk = $0.65 ($3.55 - $2.90)

The percentage change from 2018 to 2021 = 22.41% ($0.65 ÷ $2.90 x 100)

The cost of milk is inflating annually at (1 + x)^3

x = 7%

Cost of milk in 2025 = y

Number of years from 2018 to 2025 = 7 years

y = 2.90 (1 + 0.07)⁷

y = 2.90 (1.07)⁷

y = $4.66

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Step-by-step explanation:

First you need to do of bracket

(8+2)

=10

Second you need to do of exponential sign ^

10^3=1000(note this sign is also called cube)

Now,

1000-6

=994

Answer:

994

Step-by-step explanation:

We need to use order of operations to solve this problem.

( 8 + 2 ) ^ 3 - 6

According to PEMDAS, Parenthesis must be resolved first.

So we get:

10 ^ 3 - 6

Secondly, PEMDAS states that Exponents go next

1000 - 6

Finally, we only have one operation left, subtraction, so we can go ahead and do that.

994 is your answer.

I put a lot of thought and effort into my answers, so a brainliest would be much appreciated!

Service fee for the over the counter deposit of R700: R10.50

Service fee for the ATM withdrawal of R500: R11.50

To determine the service fee that Tilly will incur for the given transactions,

Over the Counter Deposit of R700:

Tilly is depositing R700, the fee will be:

Fee = R3.50 + (R1.00 per R100) x (R700 / R100)

= R3.50 + R7.00

= R10.50

Therefore, the service fee for the over the counter deposit of R700 is R10.50.

ATM Withdrawal of R500:

The fee for an ATM withdrawal at own bank is calculated as R6.50 + R1.00 per R100.

Since Tilly is withdrawing R500, the fee will be:

Fee = R6.50 + (R1.00 per R100) x (R500 / R100)

= R6.50 + R5.00

= R11.50

Therefore, the service fee for the ATM withdrawal of R500 is R11.50.

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The company's profits for each month from March through May were $658.33.

How to find the company profits for the months of March through May?

To solve the problem, we need to use the information given and set up an equation. Let's call the profits for the months of March through May "P" (since they are the same for each month).

The company's total profits for the year can be calculated by adding up the profits for each month:

January profit + February profit + March profit + April profit + May profit = total profit

Plugging in the numbers we know:

-$4,758 + $3,642 + 3P + 3P + 3P = -$1,275

Simplifying the equation:

9P = $5,925

Dividing both sides by 9:

P = $658.33

So the company's profits for each month from March through May were $658.33.

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The sample regression equation for salary and education is Salaryˆ= 32.67 + 4.46Education. For each additional year of education, an individual's salary is predicted to increase by $4,460. Predicted salary for 7 years of education is $63,845.

Using the provided data, we can calculate the sample regression equation for the model  Salary = β0 + β1Education + ε by using linear regression. The result is Salaryˆ= 32.67 + 4.46Education.

The coefficient for Education is 4.46, which means that as Education increases by 1 year, an individual’s annual salary is predicted to increase by $4,460.

To find the predicted salary for an individual who completed 7 years of higher education, we substitute Education = 7 into the regression equation: Salaryˆ= 32.67 + 4.46(7) = $63,845. Therefore, the predicted salary for an individual who completed 7 years of higher education is $63,845.

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(a) The empirical probability that the next person favors rock music is approximately 0.226.
b) The empirical probability that the next person favors country music is approximately 0.258.
c) The empirical probability that the next person favors something other than rock, country, or classical music is approximately 0.387.

a) To determine the empirical probability that the next person entering the store favors rock music, you need to divide the number of people who chose rock (14) by the total number of people surveyed (62).
Empirical Probability (Rock) = Number of Rock Fans / Total Surveyed = 14 / 62 ≈ 0.226
b) To determine the empirical probability that the next person entering the store favors country music, you need to divide the number of people who chose country (16) by the total number of people surveyed (62).
Empirical Probability (Country) = Number of Country Fans / Total Surveyed = 16 / 62 ≈ 0.258
c) To determine the empirical probability that the next person entering the store favors something other than rock, country, or classical music, you need to divide the number of people who chose something other (24) by the total number of people surveyed (62).
Empirical Probability (Other) = Number of Other Fans / Total Surveyed = 24 / 62 ≈ 0.387
In summary:
a) The empirical probability that the next person favors rock music is approximately 0.226.
b) The empirical probability that the next person favors country music is approximately 0.258.
c) The empirical probability that the next person favors something other than rock, country, or classical music is approximately 0.387.

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We want to use properties to write expressions for the length of the other sides of the square.

Remember that the length of all the sides in a square is the same, so we only need to rewrite the above expression in two different ways.

First, we can use the distribute property in the first term:

[tex]\sf 6\times(3x + 8) + 32 + 12\times x[/tex]

[tex]\sf = 6\times3x + 6\times8 + 32 +12\times x[/tex]

[tex]= \sf 18\times x + 48 + 32 + 12\times x[/tex]

So this can be the length of one of the sides.

Now we can keep simplifying the above equation:

[tex]= \sf 18\times x + 48 + 32 + 12\times x[/tex]

To do it, we can use the distributive and associative property in the next way:

[tex]\sf 18\times x + 48 + 32 + 12\times x[/tex]

[tex]= \sf 18\times x + 12\times x + 48 + 32[/tex]

[tex]= \sf (18\times x + 12\times x) + (48 + 32)[/tex]

[tex]= \sf (18 + 12)\times x + 80[/tex]

[tex]= \sf 30\times x + 80[/tex]

This can be the expression to the other side.

a) The number of cities that had only a professional sports team can be found by subtracting the number of cities that had a professional sports team and a symphony, the number of cities that had a professional sports team and a children's museum, and the number of cities that had all three activities from the total number of cities:

33 - (9 + 6 + 3) = 15 cities had only a professional sports team.

b) The number of cities that had a professional sports team and a symphony, but not a children's museum can be found by subtracting the number of cities that had all three activities from the number of cities that had a professional sports team and a symphony:

9 - 3 = 6 cities had a professional sports team and a symphony, but not a children's museum.

c) The number of cities that had a professional sports team or a symphony can be found by adding the number of cities that had a professional sports team, the number of cities that had a symphony, and then subtracting the number of cities that had both:

17 + 15 - 9 + 14 - 6 + 3 = 34 cities had a professional sports team or a symphony.

d) The number of cities that had a professional sports team or a symphony, but not a children's museum can be found by subtracting the number of cities that had all three activities from the answer to part c:

34 - 3 = 31 cities had a professional sports team or a symphony, but not a children's museum.

e) The number of cities that had exactly two of the activities can be found by adding up the number of cities that had a professional sports team and a symphony, the number of cities that had a professional sports team and a children's museum, and the number of cities that had a symphony and a children's museum, and then subtracting twice the number of cities that had all three activities:

9 + 6 + 6 - 2(3) = 15 cities had exactly two of the activities.

Natalie will have earned a total of $488.97 in interest by March 2025.

To solve this problem, we can use the formula for compound interest:

A = [tex]P(1 + r/n)^(nt)[/tex]

where A is the total amount, P is the principal amount, r is the annual interest rate as a decimal, n is the number of times the interest is compounded per year, and t is the time in years.

First, let's find out how much money Natalie will have in her first account after 5 years:

P = $800

r = 4.8% per year = 0.048

n = 12 (compounded monthly)

t = 5 years

A = [tex]800(1 + 0.048/12)^(12*5)[/tex]

A = $995.08

So after 5 years, Natalie will have $995.08 in her first account.

Next, let's find out how much money Natalie will have in her second account:

P = $995.08

r = 6% per year = 0.06

n = 2 (compounded semiannually)

t = 5 years

A = [tex]995.08(1 + 0.06/2)^(2*5)[/tex]

A = $1,288.97

So after reinvesting her money in the second account, Natalie will have $1,288.97 after 5 years.

Finally, let's calculate the total interest earned:

Total interest = A - P

Total interest = $1,288.97 - $800

Total interest = $488.97

Therefore, Natalie will have earned a total of $488.97 in interest by March 2025.

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The solution to the equation is m = 0.

What is an algebraic expression?

An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations. It may also include exponents and/or roots. Algebraic expressions are used to represent quantities and relationships between quantities in mathematical situations, often in the context of problem-solving.

To solve the equation:

(-3m^ {5}) (-2m^ {4}) = (-6m^ {9})

We can simplify the left side of the equation by multiplying the terms:

(-3m^ {5}) (-2m^ {4}) = (6m^ {9})

Now we have:

6m^ {9} = (-6m^ {9})

To solve for m, we can divide both sides by 6m^ {9}:

m^ {9} = -m^ {9}

Since the powers of m on both sides are equal, we can simplify to:

2m^ {9} =0

Dividing both sides by 2, we get:

m^ {9} =0

Taking the ninth root of both sides, we get:

m = 0

Therefore, the solution to the equation is m = 0.

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Complete Question:

Simplify the expression: $(-3m^ {5}) (-2m^ {4}) $.

The probability that the selected person is a teaching assistant or a female is 29.

What is the probability?

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Here, we have

Given: The physics department of a college has 10 male professors, 7 female professors, 13 male teaching assistants, and 9 female teaching assistants.

We have to find the probability that the selected person is a teaching assistant or a female.

N(A OR B) = N(A) + N(B) - N(A AND B)

N(teaching assistant) = 13 + 9 = 22

N(females) = 7 + 9 = 16

N(teaching assistant and female) = 9

N(teaching assistant OR female) = N(teaching assistant) + N(females) - N(teaching assistant AND female)

N(teaching assistant OR female) = 22 + 16 - 9

N(teaching assistant OR female) =  29

Hence, the probability that the selected person is a teaching assistant or a female is 29.

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Answer:

[tex]32 \div 4 = 8[/tex]

Answer: 32 divided by 4 =8

Step-by-step explanation:

The predicted populations of rabbits in the warren in 2008 and 2022 are 2909 and 9933, respectively.

To predict the population of rabbits in the warren in 2008 and 2022, we can use the formula for exponential growth:
P(t) = P₀ (1 + r)ᵗ

Where P(t) is the population at time t, P₀ is the initial population, r is the growth rate, and t is the time elapsed.

For this problem, we know that P₀ = 1500, r = 0.07 (since the growth rate is 7%), and we want to find P(8) and P(22) (since we're predicting the population in 2008 and 2022, respectively).

Using the formula, we get:
[tex]P(8) = 1500( 1 + 0.07)^{8}  = 2909[/tex]

So we can predict that there will be about 2909 rabbits in the warren in 2008.

To find P(22), we simply plug in t = 22:
[tex]P(22) = 1500 (1 + 0.07)^{22}  = 9933[/tex]

So we can predict that there will be about 9933 rabbits in the warren in 2022.

Therefore, the predicted populations of rabbits in the warren in 2008 and 2022 are 2909 and 9933, respectively.

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Answer:

[tex]x&=\dfrac{1}{2}\pi +2\pi n,\;\; \dfrac{3}{2}\pi + 2 \pi n[/tex]

Step-by-step explanation:

Given equation:

[tex]\sin(2x)\sin(x)+\cos(x)=0[/tex]

Rewrite sin(2x) using the trigonometric identity sin(2x) = 2sin(x)cos(x):

[tex]\implies 2\sin(x)\cos(x)\sin(x)+\cos(x)=0[/tex]

[tex]\implies 2\sin^2(x)\cos(x)+\cos(x)=0[/tex]

Factor out cos(x):

[tex]\implies \cos(x)\left[2\sin^2(x)+1\right]=0[/tex]

Applying the zero-product property:

[tex]\textsf{Equation 1:}\quad\cos(x)=0[/tex]

[tex]\textsf{Equation 2:}\quad2\sin^2(x)+1=0[/tex]

Solve each part separately.

[tex]\underline{\sf Equation \; 1}[/tex]

[tex]\begin{aligned}\cos(x)&=0\\x&=\arccos(0)\\x&=\dfrac{1}{2}\pi +2\pi n,\;\; \dfrac{3}{2}\pi + 2 \pi n\end{aligned}[/tex]

[tex]\underline{\sf Equation \; 2}[/tex]

[tex]\begin{aligned}2\sin^2(x)+1&=0\\\sin^2(x)&=-\dfrac{1}{2}\;\;\;\;\;\;\leftarrow\;\textsf{No solution}\end{aligned}[/tex]

Therefore, the solutions of the equation in radians are:

[tex]\boxed{x&=\dfrac{1}{2}\pi +2\pi n,\;\; \dfrac{3}{2}\pi + 2 \pi n}[/tex]

If Larry went to Home Depot and buck 32 ft.² The amount the treated plywood cost in the regular plywood in dollars per foot is: -$1.80 per foot

Treated plywood cost per square foot:

50 / 32

= $1.5625 per square foot

Regular plywood cost per square foot:

64 / 40

= -$1.60 per square foot

Difference in cost per square foot

1.5625 - 1.60

= -$0.0375 per square foot

Difference in cost per foot is:

(-$0.0375 / 0.0208)

≈ $1.80 per foot

Therefore based on the above calculation it  treated plywood costs $1.80 less per foot than the regular plywood.

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The capacity of one glass is 36/37 liters.

Let's begin by representing the capacity of one jug as "J" and the capacity of one glass as "G". From the first piece of information, we know that:

J = 6G

This means that the capacity of one jug is equal to 6 times the capacity of one glass.

Next, we are given that 36 liters of water is needed to fill 3 jugs and 19 glasses. We can use this information to form an equation in terms of J and G.

The total capacity of 3 jugs is 3J and the total capacity of 19 glasses is 19G. Therefore, we can say:

3J + 19G = 36

Now we can substitute J with 6G (from the first equation) and simplify:

3(6G) + 19G = 36

18G + 19G = 36

37G = 36

G = 36/37

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The measure of angle M is 20°.

To solve the problem, we need to find the measure of angle M, given the information about Circle K with center O, diameter US, angle MRU = 50°, and angle MUT = 30°.

Step 1: Determine the relationship between angles MRU and MUT.
Since MRU and MUT are both inscribed angles in Circle K, they share the same intercepted arc, which is arc MU.

Step 2: Calculate the measure of arc MU.
The measure of an intercepted arc is twice the measure of the inscribed angle. Since angle MRU = 50°, the measure of arc MU will be 2 * 50° = 100°.

Step 3: Find the measure of angle M.
We know that angle MUT = 30°, and the measure of an intercepted arc is twice the measure of the inscribed angle. Therefore, the measure of arc MT = 2 * 30° = 60°. Now, since arc MU = 100°, we can determine the measure of arc MS (arc MS = arc MU - arc MT) which is 100° - 60° = 40°.

Step 4: Calculate the measure of angle M.
Finally, the measure of angle M can be found using the intercepted arc MS. Since the measure of an intercepted arc is twice the measure of the inscribed angle, angle M = 1/2 * arc MS = 1/2 * 40° = 20°.

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As per the probability, the expected demand for bananas per week is 182.5 pounds.

To model this problem, we can use decision analysis, which involves identifying the possible outcomes, assigning probabilities to each outcome, and calculating the expected value of each decision.

In this case, the possible outcomes are the demand for bananas, which can be 100, 150, 200, or 250 pounds per week. The probabilities of each demand level are given as 0.20, 0.25, 0.35, and 0.20, respectively.

Let X denote the demand for bananas in pounds. Then, the expected demand for bananas, denoted as E(X), can be calculated as follows:

E(X) = 100(0.20) + 150(0.25) + 200(0.35) + 250(0.20) = 182.5

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