Answer:
44%
Explanation:
The average power of a wave is directly proportional to the square of the frequency.
P ∝ ω²
Writing a proportion:
P₁ / P₀ = ω₁² / ω₀²
P₁ / P₀ = (1.2 ω₀)² / ω₀²
P₁ / P₀ = 1.44
P₁ = 1.44 P₀
The power increases by 44%.
Select the correct answer.
According to the Universal Law of Gravitation, every object attracts every other object in the universe. Why can’t you feel the force of attraction between you and Mars?
A.
There is no force of attraction between you and Mars.
B.
Your mass is too low.
C.
Mars is a larger planet than Earth.
D.
Mars is a long distance away.
Answer:
D. Mars is a long distance away
A body is thrown vertically upwards, remaining 4s in the air. Calculate the maximum height that the body reaches.
Answer:
20 m
Explanation:
Given:
v = 0 m/s
a = -10 m/s²
t = 4 s / 2 = 2 s
Find: Δy
Δy = vt − ½ at²
Δy = (0 m/s) (2 s) − ½ (-10 m/s²) (2 s)²
Δy = 20 m
What is the angle of deviation in a plane mirror at normal incidence?
Answer:
The deviation of a mirror is equal to twice the angle of incidence.The total angle between the straight-line path and the reflected ray is twice the angle of incidence. This is called the deviation of the light and measures the angle at which the light has strayed from its initial straight-line path.
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PLEASE MARK IT THE BRAINLIEST!
It a process or act of natural growth.
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the acceleration of the wagon?
Explanation:
F = ma
2 N = (10 kg) a
a = 0.2 m/s²
A catapult is usedto fire an object into the air describe the energy transfers when the catapult is released and stretched
Explanation:
potential energy ===> kinetic energy
when an object is stretched there will be a stored energy in it enough to react to the upcoming change
that is the potential energy
similar to a stretched elastic band
kinetic energy is the energy on a moving object
*If a kinetic energy takes place there must gave been a potential energy before*
A catapult is used to fire an object into the air, the potential energy transfers as the elastic potential energy and to the kinetic energy when the catapult is released and stretched.
What is the energy conversion taken place in Catapult?The potential energy is associated with bodies that are above a reference point, at that reference point the value of potential energy is taken as zero. For example, if an object with a mass M is in a tower that is 140 meters high, its potential energy is defined as the product of the mass of the object by gravity and by the height at which the object is measured from the reference point.
Ep =mgh
When talking about elastic objects such as springs or elastic fibers, it is usually understood that there is an elastic potential energy associated with the constant of the spring. This can be calculated using the following equation:
U ela = 1/2×k×(Dx)²
where:
k = elastic constant of the elastic material [N/m]
Dx = distance stretched or compressed of the elastic material [m]
U = elastic energy [Joules]
So, there are difference between the elastic potential energy and the potential energy.
In a catapult, Initially, energy is stored in the form of potential energy which is later converted into kinetic energy. Potential energy can be stored in the form of elastic potential energy in the case of elastic. It suddenly releases the energy to propel the object into the air.
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Formulating a Hypothesis: Part II
Now you will focus on a second hypothesis. This
hypothesis can be very similar to the first, but this time
you want to focus only on the second variable in
question, speed. What could be a hypothesis that would
illustrate the relationship between speed and kinetic
energy? Use the format of "if.. then... because..." when
writing your hypothesis.
If we have a ball rolling its speed could determine the amount of
kinetic energy in it while in movement
Explanation:
The kinetic energy of an object is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex]
m is mass of the object
v is the speed of the object
It is clear from the above relation that the kinetic energy of the object is directly proportional to the product of mass and velocity.
The hypothesis can be :
If the speed of the object increased then its kinetic energy increase because kinetic energy is directly proportional to ist speed.
The kinetic energy of an object is given by :
m is mass of the object
v is the speed of the object
It is clear from the above relation that the kinetic energy of the object is directly proportional to the product of mass and velocity.
The hypothesis can be :
If the speed of the object increased then its kinetic energy increase because kinetic energy is directly proportional to its speed.
Which statement best describes the difference between how lenses and
mirrors interact with light?
A. Lenses bring light to a point; mirrors do not.
B. Lenses form images by reflecting light; mirrors do not.
C. Lenses spread light apart; mirrors do not.
D. Lenses form images by refracting light; mirrors do not.
Answer:D
Explanation:
Apex
A projectile is fired from a height of 80 M above sea level, horizontally with a speed of 360 M / S, calculate: The time it takes for the projectile to reach the water. The Horizontal scope. The height that remains to descend after 2 seconds of being launched.
Answer:
(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.
Explanation:
The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:
[tex]x = x_{o}+v_{o,x} \cdot t[/tex]
[tex]y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex]
Where:
[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial horizontal and vertical position of the projectile, measured in meters.
[tex]v_{o,x}[/tex], [tex]v_{o,y}[/tex] - Initial horizontal and vertical speed of the projectile, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]x[/tex], [tex]y[/tex] - Current horizontal and vertical position of the projectile, measured in meters.
Given that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 80\,m[/tex], [tex]v_{o,x} = 360\,\frac{m}{s}[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the kinematic equations are, respectively:
[tex]x = 360\cdot t[/tex]
[tex]y = 80-4.094\cdot t^{2}[/tex]
(a) If [tex]y = 0\,m[/tex], the time taken for the projectile to reach the water is:
[tex]80 - 4.094\cdot t^{2} = 0[/tex]
[tex]t = \sqrt{\frac{80}{4.094} }\,s[/tex]
[tex]t \approx 4.420\,s[/tex]
The projectile takes approximately 4.420 seconds to reach the water.
(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If [tex]t \approx 4.420\,s[/tex], the horizontal scope of the projectile is:
[tex]x = 360\cdot (4.420)[/tex]
[tex]x = 1591.2\,m[/tex]
The horizontal scope of the projectile is 1591.2 meters.
(c) If [tex]t = 2\,s[/tex], the height that remains to descend is:
[tex]y = 80-4.094\cdot (2)^{2}[/tex]
[tex]y = 63.624\,m[/tex]
The remaining height to descend after 2 seconds of being launched is 63.624 meters.
when vector contains distance and direction it also known as
When vector contain distance and direction it is also known as displacement .
a solid weighs 20gf in air and 18 gf in water.Find the specific gravity of the solid. Please show your work.
Answer: It is given that A body weighs 20gf in air and 18. 0gf in water. Hence, the answer X-3 = 7.
analyze this physics mystery and be marked brainliest
Answer:
The two middle chains are for suspension of the glass surface, while the fours chains at all corners prevents tilting
Explanation:
From the picture, the the frame bearing the glass surface is suspended by the two metal chains at the middle,
While the balance to avoid tilting to either directions is maintained by the four chains at all corners.
How do you find time with current and charge
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Current Electricity .
Since we know that, Current is Charge per unit time.
so we get as,
Q = I*t
here, Q = charge, I = current, t = time.
For the electric circuit given below, calculate: 3 (i) the equivalent resistance of the circuit, (ii) the total current drawn from the battery and (iii) the voltage across 7Ω resistor.
Answer:
1)31/3Ω
2)18/31A
3)4.06V
Explanation:
According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below
1/R= 1/R1 + 1/R2
But we know R1= 5 Ω and R2= 10 Ω
1/R= 1/5 + 1/10
R= 10/3 Ω
=3.33 Ω
Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then
Req = 10/3 +7
Req= 31/3 Ω
Therefore, equivalent resistance = 31/3 Ω
According to ohms law we know that V= IR
Then I= V/R
Where I= current
R= resistance
V= voltage
I= 6/(31/3)
I= 18/31A
We can now calculate the voltage accross the resistor which is
V=(18/31)× 7
V=4.06V
Therefore, the voltage accross the 7 ohm resistor is 4.06V
CHECK THE FIQURE AT THE ATTACHMENT
A scientist is studying the effects of sunlight on rose bushes. Which of the
following is a testable question about this topic?
Answer:
Does more sunlight make rose bushes grow taller?
Explanation:
When conducting a research, the researcher usually poses research questions in order to confirm or disprove the research hypothesis. A research question addresses the key issues and questions that the research project is intended to answer. Good research questions always aim at improving the body of knowledge on the selected topic of the research. Research questions must be narrowed down to specific details of the topic. They must also be testable, they must not be vague.
If I am studying the effect of sunlight on rose bushes, then the question, 'does more sunlight make rose bushes grow taller?' Is apt to the research because it can be tested by exposing various thorn bush plants to varying degrees of sunlight and recording my observation.
Answer:
If rose bushes receive more hours of sunlight each day, they will grow taller.
Explanation:
I just answered it on Apex, and they like to switch up how they word things sometimes.
A uniform metre rod of 5 metre length is suspended horizontally by two strings P and Q.Pis attached 0.8 metre from one end and Q is attached 2 metre from the other end.Given that the weight of the rod is 110N. Calculate the tension in each string
Answer:
The tension in string P is 25 N, while that of Q is 85 N.
Explanation:
Considering the conditions for equilibrium,
i. Total upward force = Total downward force
[tex]T_{P}[/tex] + [tex]T_{Q}[/tex] = 110 N
ii. Taking moment about P,
clockwise moment = anticlockwise moment
110 × (2.5 - 0.8) = [tex]T_{Q}[/tex] × (3 - 0.8)
110 × 1.7 = [tex]T_{Q}[/tex] × 2.2
187 = 2.2[tex]T_{Q}[/tex]
[tex]T_{Q}[/tex] = [tex]\frac{187}{2.2}[/tex]
[tex]T_{Q}[/tex] = 85 N
From the first condition,
[tex]T_{P}[/tex] + [tex]T_{Q}[/tex] = 110 N
[tex]T_{P}[/tex] + 85 N = 110 N
[tex]T_{P}[/tex] = 110 - 85
[tex]T_{P}[/tex] 25 N
Therefore, the tension in string P is 25 N while that of Q is 85 N.
Indicate the direction of heat flow in each scenario. Scenario A: Scenario B: Scenario C: Scenario D:
Answer:
Scenario A: toward object 1
Scenario B: toward object 2
Scenario C: toward object 1
Scenario D: toward object 1
Explanation:
The heat transfer will take place for different cases are as follow
A: From skin to lotion
B: From lasagna to plate
C: Lava to ocean water
D: From sidewalk to egg
What is heat transfer?Heat always flows from a higher temperature body to a low-temperature body. Heat transfer, any or all of several kinds of phenomena, is considered a mechanism, that conveys energy and entropy from one location to another.
The specific mechanisms are usually referred to as convection, thermal radiation, and conduction (see thermal conduction).
Conduction involves the transfer of energy and entropy between adjacent molecules, usually a slow process.
Convection involves the movement of heated fluid, such as air, usually a fairly rapid process.
Radiation refers to the transmission of energy as electromagnetic radiation from its emission at a heated surface to its absorption on another surface, a process requiring no medium to convey the energy
The heat transfer will take place for different cases are as follow
A: From skin to lotion
B: From lasagna to plate
C: Lava to ocean water
D: From sidewalk to egg
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Janaki Temple and Pashupatinath Temple are increasing our pride how
Answer:
Janaki temple and Pashupatinath Temple are found in Nepal. These structures are religious and they increase the pride of the country through tourism. These temples are important in the country and are mostly visited by tourists.
This also helps to bring in income for the country and also helps by attracting many visitors and a corresponding development of its tourism industry.
A 500 kg car starts with a force of 1000 N
1) Calculate the acceleration with which the car starts.
2) Determine the speed of the car 15 seconds after starting if we know what part of the rest
Answer:
2 m/s²
30 m/s
Explanation:
1) F = ma
1000 N = (500 kg) a
a = 2 m/s²
2) Given:
v₀ = 0 m/s
a = 2 m/s²
t = 15 s
Find: v
v = at + v₀
v = (2 m/s²) (15 s) + 0 m/s
v = 30 m/s
Part E Now convert the time from seconds to years. This value is the approximate age of the universe. Write the age in scientific notation. Use the conversion, 1 year = 3.154 × 107 seconds.
Explanation:
The age of the universe is 13.8 billion years.
We know that,
1 billion years = 10⁹ years
So,
[tex]13.8\ \text{billion years}=13.8\times 10^9\ \text{years}[/tex]
We need to convert the age of the universe to the scientific notation.
Since, [tex]1\ \text{year}=3.154\times 10^7\ s[/tex]
So,
[tex]13.8\times 10^9\ \text{years}=13.8\times 10^9\times 3.154 \times 10^7\\\\=4.35\times 10^{17}\ s[/tex]
So, the age of the universe is [tex]4.35\times 10^{17}\ s[/tex].
Answer:
So the universe is approximately 1.34 x 10^10 years old
Explanation:
Edmentum
explain relative velocity.
Answer:
The relative velocity of an object A with respect to another object B.
Explanation:
The relative velocity of an object A with respect to another object B is the velocity that object A would appear to have to an observer situated on object B moving along with it.
identify the motion when a car is moving with constant speed along a curve
Answer:
Uniform circular motion
Explanation:
When a car is moving with constant speed along a curve, it will said to have uniform circular motion. The speed of the car remains constant in this case. But its velocity keeps on changing. The velocity can be calculated by drawing the tangent on the circle. Hence, the motion of the car is uniform circular motion.
Answer:
Uniform motion
Explanation:
The motion when a car is moving with constant speed along a curve is an example of uniform motion.
A car moving at constant speed covers equal distances in equal intervals of time. The average speed remains the same in uniform motion.
The curve defines the path of the motion and the speed remains constant.
Law of conservation
of momentum
Answer:
Explanation:
Law of conservation of momentum is applied in solving collision problem. When two body collides, their momentum after collision can be determined using the law.
The law States that the sum of momentum of two bodies before collision is equal to the sum of their momentum after collision. Before collision, both bodies moves with a different velocity while during some cases, the bodies moves with a common velocity after collision.
Whether they move with or without the same velocity depends on the type of collision that exists between them after the collision. After collision, some object sticks together and move with a common velocity while some doesn't.
If the bodies sticks together after collision, the type of collision that occur is inelastic (energy is not conserved) and if they splits after collision, the type of collision that occur is an elastic collision (energy is conserved).
Let m1 and m2 be the masses of the bodies
u1 and u2 be their velocities before collision
v1 and v2 be their velocities after collision.
According to the law;
m1u1 + m2u2 = m1v1 + m2v2
Note that momentum = mass × velocity of the body.
If three cars, each of mass 1000 kg , occupy the NE, SE, and SW corners, determine the coordinates of the CM of the loaded ferryboat relative to the center of the raft. Take the origin to be at the CM of the raft.
Answer:
Using X = sum( x's * mass)/sum( masses)
= [(0)*(6400)+ (-9.5*1000) + (9.5)*(1000) + (9.5)*(1000)]/(6400+1000+1000+1000)
= 1.01 m
Y = sum( y's * mass)/sum( masses)
= [(0)*(6400) + (9.5)*(1000) +(-9.5)*(1000) + (-9.5)*(1000)]/ (6400+1000+1000+1000)
= -1.01 m
2. A solid sphere and a solid cylinder, both uniform and of the same mass and radius, roll without slipping at the same forward speed. It is correct to say that the total kinetic energy of the solid sphere is A) more than the total kinetic energy of the cylinder. B) less than the total kinetic energy of the cylinder. C) equal to the total kinetic energy of the cylinder.
Find the speed of the mobile after 4 seconds
Answer:
27 m/s
Explanation:
V_final = v_initial + a*t
V_final = 15 + 3 * 4
V_final = 27 m/s
HELP me pleaseeee somebody
an object is placed 30cm from a mirror of focal length 15 cm the object is 7.5cm tall. where is the image located? how tall is the image??
Explanation:
It is given that,
Object distance from the mirror, u = -30 cm
Focal length of the mirror, f = +15 cm
Size of the object, h = 7.5 cm
We need to find the image distance and the size of the image.
Mirror's formula, [tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]
v is image distance
[tex]\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(15)}-\dfrac{1}{(-30)}\\\\v=10\ cm[/tex]
Let h' is the size of the image. So,
[tex]\dfrac{h'}{h}=\dfrac{-v}{u}\\\\h'=\dfrac{-vh}{u}\\\\h'=\dfrac{-10\times 7.5}{-30}\\\\h'=2.5\ cm[/tex]
So, the image is located at a distance of 10 cm and the size of the image is 2.5 cm.
Calculate the speed of a car that travels 355km in 15 hours , a good answer please
Answer:
23.67 km / hr
Explanation:
car travels 355 km (d)
duration = 15 hrs (t)
average speed formula = v = d / t
v = 355 km / 15 hr
v = 23.67 km / hr
Explanation:
Hello, there!!!
Here, your question is asking about the speed and the given are:
distance (s)= 355km
time (t) = 15hrs.
speed (v)=?
now,
we have the formula:
v= s/t
or, v = 335km /15 hrs.
Therefore, the speed of car was 23.67km/hr.
Hope it helps..
how to find volume of a cuboid in cm3
Answer:
we have to use formula of volume to find volume of a cuboid. ( i.e v = l ×b ×h)
Explanation:
here, let your length of cuboid be x cm, breadth be y cm and height be z cm .
now, formula to find volume of cuboid = length ×
breadth × height.
so, v( volume)= l (length)× b (breadth)× h (height)
or, v= x cm × y cm × z cm
therefore, volume is xyz cm^3..... answer.
hope it helps..
Answer: length times width times height
Explanation:
On January 22, 1943, in Spearfish, South Dakota, the temperature rose from −4.00°F to 45.0°F over the course of two minutes (the current world record for the fastest recorded temperature change). By how much did the temperature change on the Celsius scale?
Answer:
The change on the Celsius scale is 27.22 °C.
Explanation:
The conversion of Fahrenheit to Celsius is the following:
[tex]T = \frac{5}{9}(^{\circ} F - 32)[/tex]
So, we need to convert T₁ and T₂ from °F to °C:
[tex]T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C[/tex]
[tex]T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C[/tex]
Hence, the change on the Celsius scale is:
[tex] \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C [/tex]
Therefore, the change on the Celsius scale is 27.22 °C.
I hope it helps you!