An aircraft flying in a north easterly direction alters it's course by turning through one whole number 2 over 3 right angle to the right of it's path. what is it's new course​

The postulate or theorem that can be used to prove that ΔABC ≅ ΔDCB is the "Side-Side-Side (SSS) theorem".

Hence, the correct option is A.

Since in both triangles ΔABC and ΔDCB, we have

Therefore, by SSS theorem, we can conclude that ΔABC ≅ ΔDCB.

Hence, the correct option is A.

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The area of the wrapping paper would be = 72.5in².

To calculate the area of the wrapping paper, the figure is first divided into two leading to the formation of a triangle and a rectangle.

For the triangle, the formula use to calculate it's area is given as follows;

Area = 1/2 base × height

base = 15-10 = 5 in

height = 9-4 = 5 in

area = 1/2×5 × 5

= 25/2 = 12.5 in²

Area of a rectangle = length× width

width = 4 in

length = 15 in

area = 4×15 = 60in²

Therefore the area of the wrapping paper = 12.5+60 = 72.5in²

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The temperature in Buenos Aires can be modeled using the equation T(t) = 5 sin(2π(t - 182.5)/365) + 27, where t is the number of days since January 1.

To model the temperature in Buenos Aires using a trigonometric function, we can use the sine function.

First, we need to find the amplitude, period, phase shift, and vertical shift.

Putting it all together, the equation for the temperature in Buenos Aires as a function of time is:

T(t) = 5 sin(2π(t - 182.5)/365) + 27

Where t is the number of days since January 1 and T(t) is the temperature in degrees Celsius.

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The maximum height the golf ball reached before landing back on the ground is 3.75 yards.

To find the maximum height the golf ball reached before landing back on the ground, we need to find the vertex of the quadratic function[tex]h(t) = -0.6t^2 + 3t.[/tex] The vertex of a quadratic function in the form of[tex]f(x) = ax^2 + bx + c[/tex] is given by the formula x = -b/(2a).

In this case, a = -0.6 and b = 3. Plugging these values into the formula:

t = -3 / (2 * -0.6) = 3 / 1.2 = 2.5

Now that we have the time at which the ball reaches its maximum height, we can plug this value back into the height function to find the maximum height:

[tex]h(2.5) = -0.6(2.5)^2 + 3(2.5) = -0.6(6.25) + 7.5 = -3.75 + 7.5 = 3.75[/tex]

So, the maximum height the golf ball reached before landing back on the ground is 3.75 yards.

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Using the seven square tiles numbered 2, 3, 4, 5, 6, 7, and 8, we can make 1260 different 4-digit numbers.

To create a 4-digit number using these seven square tiles, we have to consider the following:

- The first digit cannot be 2 because then the number would only have three digits.
- We can choose any of the remaining six tiles for the first digit, which means there are 6 choices.
- We can choose any of the seven tiles for the second digit, which means there are 7 choices.
- We can choose any of the remaining six tiles for the third digit, which means there are 6 choices.
- We can choose any of the remaining five tiles for the fourth digit, which means there are 5 choices.

Therefore, the total number of 4-digit numbers we can make is:

6 x 7 x 6 x 5 = 1260

So, using the seven square tiles numbered 2, 3, 4, 5, 6, 7, and 8, we can make 1260 different 4-digit numbers.

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The probability of selecting a caramel chocolate both times is approximately 0.103.

The events of selecting a caramel chocolate on each pick are dependent since the probability of the second pick depends on the outcome of the first pick.

First, we need to calculate the probability of selecting a caramel chocolate on the first pick, which is 10/30 or 1/3. After eating the first chocolate, there will be 29 chocolates left in the box, and 9 of them will be caramel-filled. So, the probability of selecting a caramel chocolate on the second pick, given that the first pick was a caramel chocolate and it was eaten, is 9/29.

To find the probability of selecting a caramel chocolate both times, we need to multiply the probabilities of the two events together, since they are independent:

P(caramel and caramel) = P(caramel on first pick) * P(caramel on second pick | first pick was caramel)

= (1/3) * (9/29)

= 0.103 or 0.1034 rounded to four decimal places.

Therefore, the probability of selecting a caramel chocolate both times is approximately 0.103.

The events of selecting a caramel chocolate on the first pick and selecting a caramel chocolate on the second pick are dependent events since the probability of selecting a caramel chocolate on the second pick changes based on what was selected on the first pick.

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The function that is increasing and has a domain of (1, infinity) is A. F(x) = log(x - 1) + 2.


To determine the increasing function with the specified domain, let's analyze each option:

A. F(x) = log(x - 1) + 2
This function is increasing because the logarithm of a positive number is always increasing. The domain is (1, infinity), which matches the requirement.

B. F(x) = -log(x - 2) + 1
This function is decreasing because the negative sign in front of the logarithm inverts the increase. The domain is (2, infinity), which does not match the requirement.

C. F(x) = -log(x - 1) + 2
This function is also decreasing because of the negative sign in front of the logarithm. The domain is (1, infinity), which matches the requirement, but the function is not increasing.

D. F(x) = log(x - 2) + 1
This function is increasing because the logarithm of a positive number is always increasing. However, the domain is (2, infinity), which does not match the requirement.

The function that is increasing and has a domain of (1, infinity) is A. F(x) = log(x - 1) + 2.

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The width of the gravel pathway is 7 meters.

The length of the rectangular garden is 50m and the width is 13m. Let's assume the width of the gravel pathway to be w meters.

The length of the rectangular garden including the two widths of the pathway would be 50+2w meters, and the width including the two widths of the pathway would be 13+2w meters.

The area of the rectangular garden including the pathway is the product of the length and the width:

(50+2w)(13+2w)

We can now set up an equation using the area of the garden and the amount of gravel available:

(50+2w)(13+2w) - 50*13 = 80

Simplifying this equation gives:

4w^2 + 126w - 3196 = 0

This is a quadratic equation that we can solve for w using the quadratic formula:

w = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 4, b = 126, and c = -3196.

Plugging in these values and solving for w gives:

w = 7 or w = -22.75

Since the width of the pathway cannot be negative, the only valid solution is w = 7.

Therefore, the width of the gravel pathway is 7 meters.

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Answer:

Step-by-step explanation:

To solve the triangle, we can use the law of sines and the fact that the sum of the angles in a triangle is 180 degrees.

First, we can find angle A by using the fact that the sum of the angles in a triangle is 180 degrees:

A = 180 - B - C

A = 180 - 92 - 16

A = 72 degrees

Next, we can use the law of sines to find side a:

a/sin(A) = c/sin(C)

a/sin(72) = 32/sin(16)

a = (32*sin(72))/sin(16)

a ≈ 89.4

Finally, we can use the fact that the sum of the angles in a triangle is 180 degrees to find angle B:

B = 180 - A - C

B = 180 - 72 - 16

B = 92 degrees

Therefore, the triangle has angle B = 92 degrees, angle A = 72 degrees, and side a ≈ 89.4.

The probability is 0.125

There are a total of 2 × 2 x 2 = 8 possibilities of one plate, one cup, and one bowl that Kyra can select if she has two plates, two cups, and two bowls.

We need to figure out how many combinations fit this requirement because we are interested in the likelihood that all three objects are blue. There are 2 × 2 x 2 = 8 potential color combinations if we assume that each item can be either blue or not blue.

There is only one of these eight color pairings in which all three components are blue. P(all three are blue) = 1/8 = 0.125 is the likelihood that Kyra will select one blue plate, one blue cup, and one blue bowl.

So, the probability is 0.125.

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The value for each symbol is: Heart - 9, Spade - 3, Club - 6, Diamond - 8.

To solve the puzzle and find the value for each symbol, we can use the given information.

First, we observe that the sum of each row is provided on the side of the table. Therefore, we can use this information to find the value for each symbol.

Let's assign variables to each symbol: heart (H), spade (S), club (C), and diamond (D).

From the first row, we have H + S + C = 28.

From the second row, we have H + D = 24.

From the third row, we have H + S + C + D = 36.

We can solve this system of equations to find the value for each symbol. By substituting the values, we can deduce that heart (H) is equal to 10, spade (S) is equal to 7, club (C) is equal to 11, and diamond (D) is equal to 14.

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The expression that represents a strategy for estimating the farm's output for 2015 is 1.153w, where w is the farm's wheat output in 2013.

Let w be the farm's wheat output in 2013. We know that the output increased by 9.8% from 2013 to 2014, so the output in 2014 can be estimated as:

w + 0.098w = 1.098w

This expression represents a strategy for estimating the farm's output for 2014.

Similarly, the output in 2015 can be estimated as:

(1.098w) + 0.051(1.098w) = (1 + 0.051)(1.098w)

Simplifying this expression, we get:

1.153w

Therefore, the expression that represents a strategy for estimating the farm's wheat output for 2015 is:

1.153w

where w is the farm's wheat output in 2013 (i.e., 19.8 tons).

So we can estimate the farm's wheat output in 2015 as:

1.153(19.8) = 22.82 tons (rounded to two decimal places)

Note that this is only an estimate, based on the assumption that the percentage increases from 2013 to 2014 and from 2014 to 2015 will continue to hold in the future.

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The angle between u and v is approximately 104.66 degrees. To find the angle between two vectors u and v, we can use the dot product formula:

cos(theta) = (u · v) / (||u|| ||v||)

where ||u|| and ||v|| are the magnitudes of u and v, respectively.

First, let's compute the dot product of u and v:

u · v = [tex](4)(5) + (3)(-12) = 20 - 36 = -16[/tex]

Next, we need to find the magnitudes of u and v:

[tex]||u||[/tex] = sqrt([tex]4^2[/tex] + [tex]3^2[/tex]) = 5

[tex]||v||[/tex] = sqrt([tex]5^2[/tex] + (-12[tex])^2[/tex]) = 13

Now we can substitute these values into the formula for cos(theta):

cos(theta) = [tex](-16) / (5 * 13) = -0.246[/tex]

To find the angle theta, we take the inverse cosine of cos(theta):

theta = [tex]cos^-1[/tex](-0.246) = 104.66 degrees

Therefore, the angle between u and v is approximately 104.66 degrees.

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Chaz builds a connection between points on circle Q and points on circle P by carrying out these two translations while maintaining the size and shape of the circles.

Chaz may apply two translations sequentially to map circle Q onto circle P, demonstrating that they are comparable following a similarity transformation followed by a rigid transformation.

The center of circle Q can first be translated to the center of circle P by Chaz. The two circles' centers will match thanks to this translation.

After that, Chaz can do another translation to line up a point on circle Q's circumference with a similar point on circle P's circumference. The matching points on the circles are aligned as a result of this translation.

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The Mean Value Theorem can be used to prove that the square root of 6a+31 lies between two values, where one value is equal to the function evaluated at a divided by the square root of 6, and the other value is equal to the function evaluated at a plus one divided by the square root of 6.

Let f(x) = √(6x + 31) and choose any value of a such that a > -31/6.

By the Mean Value Theorem, there exists some c in (a, a+1) such that:

f(a+1) - f(a) = f'(c)

where f'(c) is the derivative of f(x) evaluated at c.

We have:

f'(x) = 3/√(6x+31)

Thus, we can write:

f(a+1) - f(a) = (3/√(6c+31)) * (a+1 - a)

Simplifying, we get:

f(a+1) - f(a) = 3/√(6c+31)

Since a < c < a+1, we have:

a < c

√(6a+31) < √(6c+31)

√(6a+31) < (3/√(6c+31)) * √(6c+31)

√(6a+31) < f(a+1) - f(a)

Therefore, we can write:

f(a) < √(6a+31) < f(a+1)

f(a) = √(6a + 31)/√6

f(a+1) = √(6(a+1) + 31)/√6

Substituting these values, we get:

(√(6a + 31))/√6 < √(6a+31) < (√(6(a+1) + 31))/√6

Simplifying, we get:

√(6a + 31)/√6 < √(6a+31) < √(6a + 37)/√6

Hence, we have shown that the square root of 6a+31 lies between two values, where one value is equal to the function evaluated at a divided by the square root of 6, and the other value is equal to the function evaluated at a plus one divided by the square root of 6.

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Using  trignometric functions the shorter side AD has length a ≈ 25.75 cm and the longer side AB has length b ≈ 34.25 cm.

In the given scenario, we have a rectangle with sides AD and AB. The length of AD is represented as 'a' and is approximately 25.75 cm, while the length of AB is denoted as 'b' and is approximately 34.25 cm. The diagonal AC of the rectangle has a length of 42.3 cm and forms an angle of 53° with AD.

To find the lengths of sides a and b, we can utilize trigonometric functions, specifically cosine and sine. Since we have the length of the diagonal AC and the angle it forms with AD, we can set up the following equations:

cos(53°) = a/42.3

sin(53°) = b/42.3

By rearranging the equations, we can solve for a and b:

a = 42.3 * cos(53°) ≈ 25.75 cm

b = 42.3 * sin(53°) ≈ 34.25 cm

By substituting the given values into the equations, we can determine that the length of AD (a) is approximately 25.75 cm, and the length of AB (b) is approximately 34.25 cm.

These calculations allow us to find the side lengths of the rectangle based on the given information about the diagonal length and angle. Understanding trigonometric relationships enables us to solve geometric problems involving angles, sides, and diagonals in various shapes and configurations.

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For this above box plot prompt, the answer are given below.

Part A

From the box plots, we can see that the Red Team has the least variability and spread of times, followed by the Blue Team and then the Green Team.

The Red Team's box is the smallest, indicating that their times are more tightly clustered together.

Blue Team:

Q1: 75

Q2: 82

Q3: 87

IQR: 12

Upper fence: Q3 + 1.5IQR = 87 + 1.512 = 105

There are no outliers

Green Team:

Q1: 70

Q2: 75

Q3: 80

IQR: 10

Upper fence: Q3 + 1.5IQR = 80 + 1.510 = 95

There is one outlier at 90

Red Team:

Q1: 80

Q2: 83

Q3: 87

IQR: 7

Upper fence: Q3 + 1.5IQR = 87 + 1.57 = 98.5

There are no outliers

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The cube root of the given function is [tex]x=2\sqrt[3]{2}[/tex].

The given function is x³=16.

Here, the given function can be written as

[tex]x=\sqrt[3]{16}[/tex]

[tex]x=\sqrt[3]{2\times2\times2\times2}[/tex]

[tex]x=\sqrt[3]{2^3\times2}[/tex]

[tex]x=2\sqrt[3]{2}[/tex]

Therefore, the cube root of the given function is [tex]x=2\sqrt[3]{2}[/tex].

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"Your question is incomplete, probably the complete question/missing part is:"

How do you solve the cube root function of x³=16.

Answer:

Step-by-step explanation:

5p-40

a. y/x = 40/1, 76/2, 112/3, 148/4 does not represent a proportional relationship. . y/x = 48/2, 96/3, 144/4, 192/5 does not represent a proportional relationship. c. y/x = 18/1, 54/3, 90/5, 126/7  represents a proportional relationship.

A proportional relationship means that the ratio of y to x is constant throughout the table. Let's check each table:

a. y/x = 40/1, 76/2, 112/3, 148/4

If we simplify the fractions, we get y/x = 40, 38, 37.33, 37. This is not a constant ratio, so this table does not represent a proportional relationship.

b. y/x = 48/2, 96/3, 144/4, 192/5

If we simplify the fractions, we get y/x = 24, 32, 36, 38.4. This is not a constant ratio, so this table does not represent a proportional relationship.

c. y/x = 18/1, 54/3, 90/5, 126/7

If we simplify the fractions, we get y/x = 18, 18, 18, 18. This is a constant ratio, so this table represents a proportional relationship.

d. y/x = 24/1, 21/2, 18/3, 15/4

If we simplify the fractions, we get y/x = 24, 10.5, 6, 3.75. This is not a constant ratio, so this table does not represent a proportional relationship.

Therefore, the table that represents a proportional relationship is c. y/x = 18/1, 54/3, 90/5, 126/7.

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To find the cat's final position, we need to add up all the vectors representing the cat's movements.

The cat first travels along the vector −1, 2.

Next, the cat chases the ball along the vector 2, 6 − , which we can write as (2, 6) − (0, 1) = (2, 5).

Then, the cat darts after the ball 1.5 times along the vector 4, 3, which we can write as 1.5(4, 3) = (6, 4.5).

Finally, the cat's position after catching the ball is the sum of all these vectors:

(-1, 2) + (2, 5) + (6, 4.5) = (7, 11.5)

Therefore, the vector describing the cat's final position is (7, 11.5).

Answer is 9.5 tons of cement

Anne's Road Paving Company initially mixed 16 1/4 tons of cement. They used 6 3/4 tons for paving a street downtown. To find the remaining amount of cement, subtract the used amount from the initial amount:

16 1/4 - 6 3/4 = 15 1/4 - 5 3/4 = 9 1/2 tons.

So, they had 9 1/2 tons of cement left.

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The revenue of the chairs sold as per given R(x) = 0.004x³ -0.04x² +0.6x for different conditions are,

The current daily revenue is $2646.

Increase in revenue for 92 chairs sold every day is $185.16

Marginal revenue is $90.6 per lawn chair for 92 chairs sold every day.

Estimated revenue for R(91), R(92) and R(93) is equal to $2555.4 , $2464.8, and $2374.2 respectively.

Daily revenue from sale of x chairs is,

R(x) = 0.004x³ -0.04x² +0.6x

The current daily revenue can be found by evaluating the function at x = 90,

R(90) = 0.004(90)³ - 0.04(90)² + 0.6(90)

        = 2916 - 324 + 54

        = $2646

Increase in revenue,

⇒ difference between the revenue from selling 92 lawn chairs and the revenue from selling 90 lawn chairs,

R(92) - R(90)

= [0.004(92)³ - 0.04(92)² + 0.6(92)] - [0.004(90)³ - 0.04(90)² + 0.6(90)]

= 3114.752 -338.56 + 55.2 - 2646

= 2831.16 - 2646

= $185.16

Revenue would increase by$185.16 if 92 lawn chairs were sold each day.

The marginal revenue is the derivative of the revenue function,

R'(x) = 0.012x² - 0.08x + 0.6

Marginal revenue when 90 lawn chairs are sold daily,

we can evaluate the derivative at x = 90,

R'(90) = 0.012(90)² - 0.08(90) + 0.6

          = $90.6

When 90 lawn chairs are sold daily, the marginal revenue is $90.6 per lawn chair.

Use the answer from above part to estimate the revenue from selling 91, 92, and 93 lawn chairs daily.

Assume that the marginal revenue is approximately constant in a small interval around 90,

Use the linear approximation,

R(91) ≈ R(90) + R'(90)(1)

       = $2646 + $90.6

       = $2555.4

R(92) ≈ R(90) + R'(90)(2)

        = $2646 + 2($90.6)

        = $2464.8

R(93) ≈ R(90) + R'(90)(3)

         = $2646 + 3($90.6)

         = $2374.2

If 91, 92, and 93 lawn chairs were sold daily,

The estimated daily revenue would be $2555.4 , $2464.8, and $2374.2 respectively.

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The above question is incomplete, I answer the question in general according to my knowledge:

Pierce Manufacturing determines that the daily revenue, in dollars, from the sale of x town chairs is

R(x) = 0.004x³ -0.04x² +0.6x .

Currently, Pierce sells 90 lawn chairs daily.

a) What is the current daily revenue?

b) How much would revenue increase if 92 lawn chairs were sold each day?

c) What is the marginal revenue when 90 lawn chairs are sold daily

d) Use the answer from part (c) to estimate R(91), R(92) and R(93)

The total amount Babcar and Arutro paid in the Burger Beast Restaurant is $ 34.56.

Total bill = $36

Discount coupon = 20 %

The price paid after the discount coupon = 36 - (20% of 36 )

Price paid = 36 - (36 × 20/100)

The price paid = 36 - 7.2

Price paid = 28.8

The tip paid is 20 % the discounted price

The tip paid = 20% of 28.8

The tip paid = 28.8 × 20/100

The tip paid = 5.76

The total price paid = price paid after discount coupon + Tip paid

The total price paid = 28.8 + 5.76

The total price paid = 34.56

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The conclusion should be made using the Alpha = 0. 05 significance level is because the P-value is greater than Alpha = 0.05, there is not convincing evidence that greater than 75% of puppies are house-trained by the time they are 6 months old. The correct answer is B.

The given null hypothesis is that 75% of puppies are house-trained by the time they are 6 months old. The alternative hypothesis is that greater than 75% of puppies are house-trained by the time they are 6 months old.

The test statistic is a z-score, which is calculated by subtracting the hypothesized proportion (0.75) from the sample proportion (42/50 = 0.84), dividing by the standard error of the sample proportion, and then standardizing with respect to the standard normal distribution. The resulting z-score is 1.47.

The P-value is the probability of observing a test statistic as extreme or more extreme than the calculated z-score, assuming the null hypothesis is true. A P-value of 0.708 means that there is a 70.8% chance of observing a sample proportion as extreme or more extreme than 0.84, assuming that 75% of puppies are house-trained by the time they are 6 months old.

Since the P-value is greater than the significance level (alpha) of 0.05, we fail to reject the null hypothesis. In other words, there is not convincing evidence to suggest that greater than 75% of puppies are house-trained by the time they are 6 months old.

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Answer:

x>3

Step-by-step explanation:

i assume you're solving for x so,

1) rearrange terms,

5x+4>19

2)subtract 4 from both sides

5x+4-4>19-4

3) Simplify

5x>15

4) divide both sides by 5, because they are same factor

\frac{5x}{5} > \frac{15}{5}

5) Finally, the answer is

x>3

The amount each of them pays when their electricity bill is $110, $165, and $352 respectively, in the ratio 2:4:5, are:

1) $20, $40, $50

2) $30, $60, $75

3) $64, $128, $160

To find out how much each of them pays, we'll use the given ratio of 2:4:5 and divide the total bill among them accordingly.

Total bill: $110

The total ratio is 2+4+5=11.

Greg's share: (2/11) * $110 = $20

Harry's share: (4/11) * $110 = $40

Ian's share: (5/11) * $110 = $50

Therefore, Greg pays $20, Harry pays $40, and Ian pays $50.

Total bill: $165

The total ratio is still 2+4+5=11.

Greg's share: (2/11) * $165 = $30

Harry's share: (4/11) * $165 = $60

Ian's share: (5/11) * $165 = $75

Therefore, Greg pays $30, Harry pays $60, and Ian pays $75.

Total bill: $352

The total ratio remains the same: 2+4+5=11.

Greg's share: (2/11) * $352 = $64

Harry's share: (4/11) * $352 = $128

Ian's share: (5/11) * $352 = $160

Therefore, Greg pays $64, Harry pays $128, and Ian pays $160.

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The probability that a randomly selected balloon animal is green and shaped like a dog is 0.231.

The probability is found using the data table given below:

Purple and giraffe = 3; Purple and dog =  3; Green and giraffe = 4; Green and dog = 3

Out of the total number of balloon animals made, the number of green dog balloon animals is 3.

The probability of randomly selecting a green dog balloon animal is found using the formula:

Probability = 3 / (3 + 3 + 4 + 3) = 3/13

Probability = 0.231

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Let's call the initial number of bacteria in the petri dish as $N_0 = 100$. After 12 hours, the number of bacteria triples, which means there are now $3N_0$ bacteria. After another 12 hours, the number of bacteria triples again, which means there are now $3(3N_0) = 9N_0$ bacteria.

We can see a pattern here that after every 12 hours, the number of bacteria is multiplied by 3. Let's calculate the number of bacteria after 1 hour:

$\sf\implies\:N_1 = N_0 \times 3^{1/12}$

After simplifying:

$\sf\implies\:N_1 = 100 \times 3^{1/12}$

Using a calculator, we can find that $\sf\:3^{1/12} \approx 1.1548$. Therefore:

$\sf\implies\:N_1 \approx{\boxed{115.48}}$

So the equivalent hourly rate at which the number of bacteria is increasing is approximately 15.48% per hour.

In general, if the number of bacteria triples every $t$ hours, the equivalent hourly rate can be calculated as:

$\sf\implies\:r = 3^{1/t} - 1$

where $r$ is the hourly rate expressed as a decimal.

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Answer:

The equation of a circle with center (a,b) and radius r is given by:

(x - a)² + (y - b)² = r²

Comparing this to the equation x² + y² = 12², we can see that the center of the circle is (0,0) and the radius is 12. Therefore, the radius of the circle is 12 units.