The true statement about Amy's weekly income is that her net income is less than $120 (option c).
To find out the true statement about Amy's weekly income, we need to calculate her gross income first.
Step 1: Multiply the hours worked per week by the hourly wage.
Amy works 15 hours a week and earns $8 an hour, so:
15 hours * $8/hour = $120
Now we have her gross income, which is $120.
Comparing the gross income to the statements given:
a) Her net income is more than $120: False, as net income is usually less than gross income due to deductions (taxes, social security, etc.).
b) Her gross income is less than $120: False, as we calculated her gross income to be exactly $120.
c) Her net income is less than $120: True since net income is generally less than the gross income due to deductions.
d) Her gross income is more than $120: False, as her gross income is exactly $120.
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-3 3/7 times 5 5/6 ........
Answer:
the answer for this problem would be -20
Answer:
-20
Step-by-step explanation:
The easiest way to do it is to change -3 3/7 and 5 5/6 into improper fractions. To do that, let’s take -3 3/7 for example. You would add the numerator by the whole number, and then multiply the denominator by the whole number. Getting you -24/7, the other number would be 35/6 then you multiply the two getting you -840/42, which it turned back into a proper fraction by dividing the two numbers, you would get -20. Hope this helps!
please help.................................
Answer:
plugging in those values you get 40+(81/9)=40+9=49.
A company estimates that 0. 5% of their products will fail after the original warranty period but within 2 years of the purchase, with a replacement cost of $500. 0. If they offer a 2 year extended warranty for $33. 00, what is the company's expected value of each warranty sold? Please format your answer using a dollar sign and two decimal points for the cents. For example, if the expected value was 50, please enter it as $50. 0
The expected value of each warranty sold is $2.47.
The expected value of each warranty sold can be calculated by subtracting the cost of the warranty from the expected value of the potential savings on replacement costs.
Let's assume that the company sells 1000 warranties. Then, the expected number of products that will fail within 2 years is:
0.5% of 1000 = 0.005 x 1000 = 5
The expected cost of replacing these products is:
5 x $500 = $2500
Therefore, the expected value of the warranty is:
($2500 - $33 x 1000) / 1000 = $2.47
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Can u please help me solve this and explain how you got it please.
8xsquared-2-5x=8
Find the x
Using quadratic formula, the value of x in the quadratic equation are 1.47 and -0.85
What is the value of x?To find the value of x, we can either use quadratic formula or factorization method.
8x² - 2 - 5x = 8
Let's rewrite the equation properly
8x² - 5x - 2 - 8 = 0
8x² - 5x - 10 = 0
a = 8, b = -5, c = -10
Using quadratic formula;
-b ±[√b² - 4ac / 2a]
-(-5) ±[√(-5)² - 4(8)(-10) / 2(8)]
x = 5+ √345 / 16 or x = 5 - √345 / 16
x = 1.47 or x = -0.85
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Write the coordinates of the vertices after a rotation 180° clockwise around the origin.
Answer:
it will be P'(y,-x) since it is clockwise direction and I anti clockwise the formula to find the coordinates will be (-y,x)
A man is sitting at a park bench 92 feet away from an office building. The medical examiner and other
investigators have determined that the bullet entered the man's head at an angle of 26° and at about 3. 7 feet
off the ground. If the man was shot from the office building, about how high off of the ground was the shooter
located?
The shooter was located approximately 36.15 feet off the ground.
How high was the shooter located?We can use trigonometry to solve for the height of the shooter.
First, we need to find the horizontal distance from the shooter to the man on the park bench. We can use the angle of 26° and the distance of 92 feet to calculate this distance:
horizontal distance = 92 feet * cos(26°)
horizontal distance = 82.33 feet
Next, we can use the height of 3.7 feet and the horizontal distance of 82.33 feet to find the height of the shooter:
tan(26°) = height difference / horizontal distance
height difference = horizontal distance * tan(26°)
height difference = 82.33 feet * tan(26°)
height difference = 36.15 feet
Therefore, the shooter was located approximately 36.15 feet off the ground.
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The second number is five more than the first number. The sum of three times the first and double the second number is 30. Find the numbers.
Answer:
x = 4 and y = 9
Step-by-step explanation:
Let x and y be the two numbers. Also,
Let the first number be x and the second number be y.
Converting the word expressions to an equation we get:
y = x + 5
3x + 2y = 30
Only thing left is to substitute y = x + 5 into the second equation
3x + 2y = 30
3x + 2(x + 5) = 30 (substituting y as x + 5)
3x + 2x + 10 = 30 (multiplying by both x and 5)
5x = 30 - 10 (collecting like terms to one side)
5x = 20
[tex]\frac{5x}{5} = \frac{20}{5}[/tex] (divide both sides by 5 to get the value of x)
x = 4
Now that we know the value of x, we can find y.
y = x + 5
y = 4 + 5
y = 9
If you want to make sure your answer is correct, substitute x and y into the equation.
3x + 2y = 30
3(4) + 2(9) = 30
12 + 18 = 30
30 = 30
Construct a 95% confidence interval for the true average monthly salary earned by all employees of People Plus Pty, if it was found that the average monthly salary earned by a sample of 19 employees of the company was R18 500, with a standard deviation of R1 750. Interpret your answer
We can be 95% confident that the true average monthly salary earned by all employees of People Plus Pty is between R16 234.49 and R20 765.51. This means if created for several samples of the same size taken from the population, would contain the actual population mean.
To construct a 95% confidence interval for the true average monthly salary earned by all employees of People Plus Pty, we can use the following formula:
CI = x ± t(α/2, n-1) * (s/√n)
where:
x = sample mean = R18 500
s = sample standard deviation = R1 750
n = sample size = 19
t(α/2, n-1) = t-score at α/2 and n-1 degrees of freedom
Using a t-table or calculator with 18 degrees of freedom (n-1), we can find the t-score at α/2 = 0.025 to be 2.101.
Plugging in the values, we get:
CI = 18500 ± 2.101 * (1750/√19)
= (16234.49, 20765.51)
Therefore, we can be 95% confident that the true average monthly salary earned by all employees of People Plus Pty is between R16 234.49 and R20 765.51.
This means that if we were to take multiple samples of the same size from the population and construct 95% confidence intervals for each sample mean, about 95% of those intervals would contain the true population mean.
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Simon is filling a cylindrical water dispenser that has a radius of 7 inches and a height of 20 inches. Which of these is the best estimate of the volume of this water dispenser?
A 140 in
b 2,940 in
c 840 in
d 11,769 in
PLEASE ANSWER FAST
The best estimate of the volume of this cylindrical water dispenser is 2940 in³. The correct option is b.
To estimate the volume of the cylindrical water dispenser, we can use the formula for the volume of a cylinder, which is given by V = πr²h, where V is the volume, π is a mathematical constant approximately equal to 3.14, r is the radius, and h is the height.
Given that the radius of the water dispenser is 7 inches and the height is 20 inches, we can substitute these values into the formula:
V = π(7²)(20)
V = π(49)(20)
V ≈ 3.14 × 49 × 20
V ≈ 3.14 × 980
V ≈ 3075.2 in³
From the given options, the closest estimate to the calculated volume of approximately 3075.2 in³ is option B: 2940 in³. While it is not an exact match, it is the closest estimate among the options provided.
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A person stands on level ground 60 m from the nearest point of a cylindrical tank of radius length 20 m. Calculate:
a- the circumference of the tank
b the percentage of the circumference that is visible to the person
The circumference of the tank is is 125.66m and the percentage of the circumference that is visible to the person is 10.24%.
a) To calculate the circumference of the cylindrical tank, using the formula C = 2πr, where C is the circumference and r is the radius of the tank. In this case, r = 20 m, so:
C = 2π(20 m) ≈ 125.66 m
b) To determine the percentage of the circumference visible to the person, we first need to calculate the angle (in degrees) that subtends the visible arc. This can be done using the inverse tangent function:
angle = atan(opposite/adjacent) = atan(20 m/60 m)
angle ≈ 18.43°
Since the visible arc is symmetrical on both sides, the total angle of the visible arc is twice the calculated angle:
total angle ≈ 36.86°
Now, calculate the percentage of the circumference that is visible by dividing the total angle by 360° and multiplying by 100%:
percentage = (36.86°/360°) × 100% ≈ 10.24%
So, the visible percentage of the circumference to the person is approximately 10.24%.
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HELP
Fran has been assigned the task of determining the
probability of drawing 3 spades from a standard deck of
52 cards. Recall there are 4 suits (diamonds, hearts, spades,
and clubs) of 13 cards each, in a deck. Each card is drawn
one at a time and held until the remaining cards of the hand
are drawn.
How many ways are there to draw the first card?
o 13
O 52
04
01
52
How many ways to draw?There are 52 ways to draw the first card from a standard deck of 52 cards. Each card in the deck is distinct, so there are 52 different possibilities for the first card.
The deck consists of 4 suits (diamonds, hearts, spades, and clubs) with 13 cards in each suit. Therefore, there are 13 cards of the spades suit. Since each card is equally likely to be drawn, the probability of drawing a spade as the first card is 13/52 or 1/4.
This is because out of the 52 possible cards, 13 of them are spades. So, regardless of the specific spade that is drawn, there are 13 ways to draw a spade as the first card.
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(0,1),(5,2),(2,-3),(-3,-3),(-5,3) range and domain
The domain of the set of points {(0,1),(5,2),(2,-3),(-3,-3),(-5,3)} is {0, 5, 2, -3, -5}, and the range is {-3, 1, 2, 3}.
What is the range and domain of the relation?Given the relations in the question:
(0,1), (5,2), (2,-3), (-3,-3), (-5,3)
To determine the domain and range of a set of points, we need to look at the x-coordinates of the points to determine the domain, and the y-coordinates of the points to determine the range.
{(0,1),(5,2),(2,-3),(-3,-3),(-5,3)}
The x-coordinates of these points are: 0, 5, 2, -3, and -5.
Therefore, the domain of this set of points is:
Domain = {0, 5, 2, -3, -5}
The y-coordinates of these points are: 1, 2, -3, and 3.
Therefore, the range of this set of points is:
Range = {-3, 1, 2, 3}
Therefore, the domain is {0, 5, 2, -3, -5}, and the range is {-3, 1, 2, 3}.
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11. The function f(t) = 40 sin (π/45 t) +48 models the height in feet of one car od a Ferris wheel called the Colossus, where t is the time in seconds. Each of the functions below models the motion of a different Ferris wheel. Which Ferris wheel has the same diameter as The Colossus?
a. g(t) = 40 cos (π/45 t) +50
b. h(t) = 39 cos (π/60 t) + 49
c. j(t) = 39 sin (π/45 t) + 48
d. k(t) = 39 sin (π/45 t) + 49
Ferris wheel has the same diameter as The Colossus is g(t) = 40 cos (π/45 t) +50. So, correct option is A.
To determine which of the given functions represents a Ferris wheel with the same diameter as The Colossus, we need to use the fact that the diameter of a Ferris wheel is equal to the amplitude of the sinusoidal function that models its height.
The amplitude of the function f(t) = 40 sin (π/45 t) +48 is 40, so the diameter of The Colossus is 40 feet. We need to find the function that also has an amplitude of 40.
Looking at the given answer choices, we see that function g(t) has an amplitude of 40 cos (π/45 t) +50, which is equal to 40. This means that the Ferris wheel represented by function g(t) has a diameter of 40 feet, the same as The Colossus.
Functions h(t), j(t), and k(t) all have amplitudes that are less than 40, so they represent Ferris wheels with smaller diameters than The Colossus.
Therefore, the answer is A.
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4h(x)=x−4h, left parenthesis, x, right parenthesis, equals, x, minus, 4
what is the domain of h?h?
The given equation is 4h(x) = x - 4.
To find the domain of h(x), we need to determine the set of all possible input values for x that will result in a valid output value for h(x).
Since there are no restrictions on the input values for x in the given equation, the domain of h(x) is all real numbers.
Your answer: The domain of h(x) is all real numbers.
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The domain of the function 4h(x) = x - 4 is all real numbers, because there's no value of x that can make the equation undefined. It's represented as (-∞, ∞).
Explanation:In the function 4h(x) = x - 4, the variable x is an independent variable and it can take any real number as value. Therefore, the domain of this function refers to the set of all possible x-values. In other words, the domain of this function is all real numbers.
A function's domain is essentially the set of all values that can be plugged into the function without causing problems such as division by zero or taking the square root of a negative number. In the given equation, there's nothing that would limit the possible values of x.
Therefore, the domain of h(x) in this case is all real numbers, symbolically represented as (-∞, ∞).
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5 dived by 465 long divsion 6th grade
Answer: 5 divided by 465 is 0.010752688172
465 divided by 5 is 93
Step-by-step explanation:
Which of the following groups listed below is a subset of the whole numbers?
Rational Numbers
Real Numbers
Natural Numbers
Irrational Numbers
Integers
The group of natural numbers is a subset of the whole numbers.
What is Whole number ?
Whole numbers are a set of numbers that includes all positive integers (1, 2, 3, ...) and zero (0). They do not include negative numbers or fractions. Whole numbers are often used to count objects or represent quantities that cannot be divided into smaller parts.
Out of the given options, the group of natural numbers is the only one that is a subset of whole numbers. The other options - Rational numbers, Real numbers, Irrational numbers, and Integers - are not subsets of the whole numbers.
Rational numbers include fractions and decimal numbers, which can be expressed as a ratio of two integers, including non-whole numbers.
Real numbers include all rational and irrational numbers, including non-whole numbers. Irrational numbers are non-repeating, non-terminating decimals that cannot be expressed as a fraction. Integers include both positive and negative whole numbers, as well as zero.
The subset of whole numbers is called natural numbers.
Therefore, the group of natural numbers is a subset of the whole numbers.
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The Huns migrated to the West in groups. There were three sections of the migration: the front, the middle, and the back. There were 3 groups of 5 people leading in the front and the same amount of groups and people at the back of the migration. In the middle of the pack, we have 9 groups of 9 people each. Write an expression and solve for the total number of Huns that migrated to the West. Use exponents in your expression.
The total number of Huns that migrated to the West is 111.
How to calculate the total number of Huns?To find the total number of Huns that migrated to the West, we can use the expression:
Total number of Huns = Number of groups x Number of people per group
For the front and back sections, there were 3 groups of 5 people each, so the total number of Huns in each section is:
3 x 5 = 15
For the middle section, there were 9 groups of 9 people each, so the total number of Huns in the middle section is:
9 x 9 = 81
To find the total number of Huns that migrated to the West, we add up the number of Huns in each section:
15 + 81 + 15 = 111
Therefore, the total number of Huns that migrated to the West is 111.
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Megha bikes 20km north, 30km east, 20 km south and then 30 km west and then stopped. What is her displacement
Megha's total movement involves biking 20km north, 30km east, 20km south, and 30km west, resulting in a displacement of zero as she ends up back at her starting point.
Given that,
Megha bikes 20km north.
Megha then bikes 30km east.
After that, Megha bikes 20km south.
Lastly, Megha bikes 30km west.
Megha stops after completing the above movements.
Megha's displacement can be calculated by finding the straight-line distance between her starting point and ending point.
In this case,
She initially bikes 20km north, then 30km east, followed by 20km south, and finally 30km west.
Let's break it down:
The north and south distances cancel each other out, as she ends up back at her starting point vertically.
The east and west distances also cancel each other out, as she ends up back at her starting point horizontally.
Hence,
Megha's displacement is zero. She has returned to her original position.
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The temperature on skylar’s thermometer last night was −3°f. this morning it was colder. what could be the temperature on her thermometer this morning?−5°f−1°f0°f2°f
The only option left is −5°F, which is colder than −3°F and thus could be the temperature on her thermometer this morning.
The temperature on Skylar's thermometer is measured using a scale that indicates the degree of hotness or coldness of the atmosphere. In this case, we know that the temperature on her thermometer last night was −3°F. The negative sign indicates that the temperature was below the freezing point of water.
We are asked to determine what the temperature could be on her thermometer this morning. Since we are told that the temperature is colder than −3°F, we can eliminate 0°F and 2°F as possible options, as they are warmer than −3°F.
Similarly, −1°F is only slightly colder than −3°F, so it is unlikely to be the temperature on Skylar's thermometer this morning. Therefore, the only option left is −5°F, which is colder than −3°F and thus could be the temperature on her thermometer this morning.
It is important to note that temperature can have a significant impact on our daily lives. Extreme cold temperatures can cause frostbite, hypothermia, and other health hazards, while hot temperatures can lead to dehydration, heat exhaustion, and heat stroke. It is important to dress appropriately and take necessary precautions when the temperature is too low or too high.
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Keilantra was given a large box of 24 chocolates for her birthday. If she eats exactly 3 chocolates each day, how many chocolates would Keilantra have remaining 6 days after her birthday?
Answer: 6 chocolates
Step-by-step explanation:
Keilantra had 24 chocolates to begin with, and she ate six lots of three. so the first step is 6 x 3 = 18. Now that we know how many chocolates Keilantra ate, we need to figure out how many chocolates she has left. So we take our product (18) and we subtract it from the total (24). So we end up with 24 - 18 = 6.
please show all work so i can better understand. Thank you!
- 2. Find all values of x where f '(x) = 0 for f(x) = arcsin(e2x – 2x).
The only value of x where f'(x) = 0 is x = 0.
Let's find all values of x where the derivative of f(x) = [tex]arcsin(e^(2x) – 2x)[/tex] is equal to 0.
Step 1: Find the derivative f'(x) using the chain rule.
For this, we'll need to differentiate [tex]arcsin(u)[/tex] with respect to u, which is [tex](1/√(1-u^2))[/tex], and then multiply by the derivative of u [tex](e^(2x) – 2x)[/tex]with respect to x. So, f'(x) = [tex](1/√(1-(e^(2x) – 2x)^2)) * d(e^(2x) – 2x)/dx[/tex]
Step 2: Find the derivative of e^(2x) – 2x with respect to x. Using the chain rule and the derivative of [tex]e^u: d(e^(2x) – 2x)/dx = 2e^(2x) – 2[/tex]
Step 3: Combine the derivatives. f'(x) =[tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2)[/tex]
Step 4: Set f'(x) equal to 0 and solve for x. [tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2) = 0[/tex]
Since the first part of the product [tex](1/√(1-(e^(2x) – 2x)^2))[/tex] is never 0, we can focus on the second part: [tex]2e^(2x) – 2 = 0[/tex]
Step 5: Solve for x. [tex]2e^(2x) = 2 e^(2x) = 1[/tex]
The only way this is true is when 2x = 0, since [tex]e^0 = 1: 2x = 0 x = 0[/tex]
So, the only value of x where f'(x) = 0 is x = 0.
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Why are rectangles relatable to factors
Rectangles are relatable to factors because of their areas and perimeter equations
Why are rectangles relatable to factorsFrom the question, we have the following parameters that can be used in our computation:
Explaining why rectangles are relatable to factors
Rectangles are relatable to factors because of the following reasons
Perimeter = 2 * (Length + width)
Area = Length * width
This means that in calculating the areas and the perimeters of a rectangles, we make use of arithmetic expressions
These arithmetic expressions, when expanded form terms and factors of expression
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Ray and Kelsey are working to graph a third-degree polynomial function that represents the first pattern in the coaster plan. Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only. Is there a way for the both of them to be correct? Explain your answer.
Kelsey has a list of possible functions. Pick one of the g(x) functions below and then describe to Kelsey the key features of g(x), including the end behavior, y-intercept, and zeros.
g(x) = (x + 2)(x − 1)(x − 2)
g(x) = (x + 3)(x + 2)(x − 3)
g(x) = (x + 2)(x − 2)(x − 3)
g(x) = (x + 5)(x + 2)(x − 5)
g(x) = (x + 7)(x + 1)(x − 1)
For the g(x) functions provided, here are their key features:
g(x) = (x + 2)(x − 1)(x − 2)
End behavior: As x approaches negative or positive infinity, g(x) approaches positive infinity.
Y-intercept: g(0) = -4
Zeros: x = -2, 1, 2
How to explain the functionRay and Kelsey could both be accurate, all depending on the stated third-degree polynomial function.
It is conceivable for a third-degree polynomial to present up to three zeros, thus corroborating Kelsey's point that the function can have up to three intersection points with the x-axis maximum. Moreover, it can even occur that this function possesses a repeatable zero, causing a fourth interception.
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A company responsible for making gumballs found that their gumballs had an average diameter of 2. 21 cm and a standard deviation of 0. 01 cm. What is the percentage of gumballs that are within standard deviations of the mean?
Percentage of gumballs that are within standard deviations of the mean is 68% and have a diameter between 2.20 cm and 2.22 cm.
To find the percentage of gumballs that are within one standard deviation of the mean, we need to use the empirical rule, also known as the 68-95-99.7 rule. According to this rule, for a normal distribution:
Approximately 68% of the data falls within one standard deviation of the mean.Approximately 95% of the data falls within two standard deviations of the mean.Approximately 99.7% of the data falls within three standard deviations of the mean.Here we want to find the percentage of gumballs that are within one standard deviation of the mean. So we can use the first part of the empirical rule and say that approximately 68% of the gumballs have a diameter between:
Mean - Standard deviation = 2.21 - 0.01 = 2.20 cm and Mean + Standard deviation = 2.21 + 0.01 = 2.22 cm
Therefore, approximately 68% of the gumballs have a diameter between 2.20 cm and 2.22 cm.
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There are 5 children running in a relay race. in a relay race, each person runs part of the race. the next runner starts where the previous runner stops. each runner runs the same distance. in this relay race, each child runs of a mile, then stops so the next , a runner can continue. plot the point on the number line that represents the location where the fourth child will stop running.
The location where the fourth child will stop running in the relay race is 4/5 of the way.
To determine the location where the fourth child will stop running in the relay race, we need to find out the total distance covered by the first four children.
Since each child runs 1/5 of a mile, we can find the total distance for the first four children by multiplying their individual distances.
Total distance = (Number of children) * (Distance run by each child)
Total distance = 4 * (1/5)
Now, let's multiply:
Total distance = 4/5
So, the fourth child will stop running at a location 4/5 of a mile from the starting point. To plot this point on a number line, locate the point between 0 and 1 that is 4/5 of the way. This point represents the location where the fourth child will stop running in the relay race.
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Find the critical points c for the function / and apply the Second Derivative Test (if possible) to determine whether each of
these points corresponds to a local maximum (mar) or minimum (Gmin).
/(x) = 7x° In(3x) (* > 0)
(Use symbolic notation and fractions where needed. Give your answer in the form of a comma separated list, if necessary. Enter
DNE if there are no critical points.)
Cmin=
Cmax=
The critical points of f(x) are x = 0 and x = e^(-1/2) / 3, and x = e^(-1/2) / 3 corresponds to a local minimum of f(x). Cmin = e^(-1/2) / 3 and Cmax = 0.
Taking the derivative of f(x) with respect to x using the product rule and the chain rule, we get:
f'(x) = 14x ln(3x) + 7x
Setting f'(x) equal to zero and solving for x, we get:
14x ln(3x) + 7x = 0
Factor out x:
7x(2ln(3x) + 1) = 0
So either x = 0 or 2ln(3x) + 1 = 0.
If x = 0, then f'(x) = 0 and x is a critical point.
If 2ln(3x) + 1 = 0, then ln(3x) = -1/2 and 3x = e^(-1/2). Solving for x, we get:
x = e^(-1/2) / 3
So e^(-1/2) / 3 is also a critical point.
Now we need to apply the second derivative test to determine whether these critical points correspond to a local minimum or maximum.
Taking the second derivative of f(x), we get:
f''(x) = 14 ln(3x) + 21
For x = 0, we have:
f''(0) = 14 ln(0) + 21
The natural logarithm of zero is undefined, so the second derivative does not exist at x = 0. Therefore, we cannot apply the second derivative test at x = 0.
For x = e^(-1/2) / 3, we have:
f''(e^(-1/2) / 3) = 14 ln(1/e^(1/2)) + 21
= -14/2 + 21
= 7/2
Since the second derivative is positive at this point, we can conclude that x = e^(-1/2) / 3 is a local minimum of f(x).
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Please help I need this done NOW!
The volume of the different shapes have been calculated in the space below
How to find volumeVolume of rectangular prism = lwh
where we define the variables as :
l = length
w = width
h = height
then when we multiply, we will have
= 4 x 10 x 6
= 240
Volume of triangular pyramid = 1 / 3 b x h
where b = base
h = height
1 / 3 x 1.5 x 2
= 1
Volume of rectangular pyramid = lwh / 3
= 7.5 x 4.5 x 5 / 3
= 56.25
Volume of triangular prism= 1/2 x b x h x l
= 1/2 x 3 x 8.5 x 7
= 89.25
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Directions: Give the next three terms in each sequence. Write a rule to describe each sequence.
1. 5, 25, 125, 625, ___________, __________, _____________ .
Rule:
2. 12, 24, 48, 96, ___________, ___________, ______________ .
Rule:
3. 85, 80, 75, 70, __________, ___________, _______________ .
Rule:
4. 3, 5, 7, 9, 11, ___________, ___________, _______________ .
Rule:
5. 12, 13, 15, 16, 18, ________, ____________, _____________ .
Rule
Answer:
1. 5,25,125,625,3125, 15625,78125
Rule: We multiply each term of the sequence by 5.
2.12, 24, 48, 96, 192, 384, 768
Rule: We multiply each term of the sequence by 2.
3. 85, 80, 75, 70, 65, 60, 55
Rule:subtract 5 from each term of the sequence
4.3;5,7,9,11,13,15
Rule: Add 2 to every term in the sequence
5.12, 13,15,16,18,19,21,22
Rule: We first add 1 to the previoys term then add 2 to the new term of the sequence and so on.
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The average price of milk in 2018 was 6.45 dollars per gallon.
The average price of milk in 2021 was 189.95 dollars per gallon.
How to calculate the priceThe given function is: Price = 3.55 + 2.90(1 + x)³
In order to find the average price of milk in 2018, we need to set x = 0:
Price in 2018 = 3.55 + 2.90(1 + 0)³ = 3.55 + 2.90(1) = 6.45 dollars per gallon
Price in 2021 = 3.55 + 2.90(1 + 3)³ = 3.55 + 2.90(64) = 189.95 dollars per gallon
Hence, the average price of milk in 2021 was 189.95 dollars per gallon.
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Question
What is the scale factor for the similar figures below?
The value of the scale factor for the similar figures is 1/2
What is the scale factor for the similar figures?From the question, we have the following parameters that can be used in our computation:
The similar figures
The corresponsing sides of the similar figures are
Original = 8
New = 4
Using the above as a guide, we have the following:
Scale factor = New /Original
substitute the known values in the above equation, so, we have the following representation
Scale factor = 4/8
Evaluate
Scale factor = 1/2
Hence, the scale factor for the similar figures is 1/2
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