5604000gallon =21239160 liters
What is Minimum Threshold Frequency?
Explanation:
Threshold frequency: Threshold frequency is the minimum frequency of the incident radiation below which photoelectric emission is not possible irrespective of the intensity of the incident radiation. ... Emitted electrons are called photoelectrons.
Hope this helps you dear :)
Good morning!
5.36 liters of nitrogen gas are at STP. What would be the new volume if we increased the moles from 3.5 moles to 6.0 moles?
Answer:
[tex]V_2=9.20L[/tex]
Explanation:
Hello there!
In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:
[tex]\frac{V_2}{n_2}= \frac{V_1}{n_1}[/tex]
In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:
[tex]V_2= \frac{V_1n_2}{n_1} \\\\V_2=\frac{5.36L*6.0mol}{3.5mol}\\\\V_2=9.20L[/tex]
Best regards!
PlEASE HELP! 40!
A radioactive form of sodium pertechnetate is used as a brain-scanning agent in medicine. Quantitative analysis of a sample with a mass of 0.8961 g found 0.1114 g of sodium and 0.4749 g of technetium. The remainder was oxygen. Determine the empirical formula.
Answer:
moles Na = 0.1114 g / 22.9898 g/mol=0.004846
moles Tc = 0.4562g /98.9063 g/mol=0.004612
mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g
moles O = 0.3285 g/ 15.999 g/mol=0.02053
divide by the smallest
0.02053/ 0.004612 =4.45 => O
0.004846/ 0.004612 = 1.0 => Tc
to get whole numbers multiply by 2
Na2Tc2O 9
Explanation:
Hope it right hope it helps
Question 2
The volume of a gas-filled balloon is 20.0 L at 60 atm pressure. What volume in liters will the balloon have at 30 atm?
Question 3
8.00 L of gas at standard temperature and pressure (STP) is compressed to 3 L. What is the new pressure of the gas in atm?
Question 4
If a tennis ball has a pressure of 200 atm at a temperature of 27oC, what pressure in atm will the tennis ball have if the temperature of the gas increased to 77oC?
Question 5
Exactly 5.00 L of air at -23oC is warmed to 27o What is the new volume in liters if the pressure remains constant?
Question 6
The temperature inside my refrigerator is about 40 If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon in liters when it is fully cooled by my refrigerator?
Question 7
Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs, what is the new volume of the gas in liters?
Question 8
Today, I forgot my soda in the trunk of my car. The initial pressure is 3 atm and it was a cool morning, at 15o By the afternoon, however, the temperature rose to 25oC. What is the pressure in atm inside the can?
please help me, im failing all my classes and really need some help with this. if i could give more than 100 i would
These questions all involve special cases of the ideal gas law, namely Boyle's, Charles', and Gay-Lussac's Laws. The ideal gas law relates together the absolute pressure (P), volume (V), the absolute temperature (T), and number of moles (n) of a gas by the following:
PV = nRT
where R is the universal gas constant.
The special cases of the ideal gas law are obtained by holding constant all but two of the variables of a gas.
Boyle's Law relates the pressure and volume of a given mass of gas at a constant temperature: PV = k or P₁V₁ = P₂V₂.
Charles' Law relates the volume and temperature of a given mass of gas at a constant pressure: V/T = k or V₁/T₁ = V₂/T₂.
Gay-Lussac's Law relates the pressure and temperature of a given mass of gas at a constant volume: P/T = k or P₁/T₁ = P₂/T₂.
Depending on what we're given and instructed to find in each question, we can figure out which law to use.
---
Question 2:
We are given the volume of a gas at some pressure, and we're to find the new volume of the gas at a different pressure. Here, we use Boyle's Law: P₁V₁ = P₂V₂ where P₁ = 60 atm, V₁ = 20.0 L, and P₂ = 30 atm. We want to find V₂, which we can determine by rearranging the equation into the form V₂ = P₁V₁/P₂. Note that pressure and volume are inversely related according to Boyle's Law; since we're decreasing the pressure, the new volume of the gas should be greater than the initial volume of 20.0 L.
V₂ = (60 atm)(20.0 L)/(30.0 atm) = 40.0 L.
So, at 30 atm, the balloon will have a volume of 40.0 L.
---
Question 3:
This is another Boyle's Law question. The standard pressure (our initial pressure) is 1 atm. Here, we are decreasing the volume of the gas, and we want to find the new pressure; the pressure of the gas should thus increase proportionally (the pressure will be greater than 1 atm). Rearranging Boyle's Law to solve for P₂, we get P₂ = P₁V₁/V₂.
P₂ = (1 atm)(8.00 L)/(3 L) = 2.67 atm.
So, the new pressure of the gas is 2.67 atm (or 3 atm if we're considering V₂ to comprise one significant figure).
---
Question 4:
Here, we are increasing the temperature of a gas at a known pressure, and we want to determine what the new pressure will be. This is a Gay-Lussac's Law question; from the law, we see that pressure and temperature are directly proportional. Since we're increasing the temperature of the gas, we should expect the pressure of the gas to be greater than the initial 200 atm. Gay-Lussac's Law rearranged to solve for P₂ gives us P₂ = P₁T₂/T₁. When working with gas laws, temperatures must be in Kelvin (°C + 273.15 = K). So, T₁ = 300.15 K, T₂ = 350.15 K, and P₁ = 200 atm.
P₂ = (200 atm)(350.15 K)/(300.15 K) = 233 atm.
So, if the temperature is increased from 27 to 77 °C, the pressure of the gas in the tennis ball will be 233 atm. Here, it's ambiguous how many sig figs to use; if we use one sig fig per P₁, then our P₂ would equal P₁, which I think would be an absurd for a question to ask for. I would stick with either 233 atm or 230 atm (following the two sig figs of the temperatures), or you may go with however you've been instructed.
---
Question 5:
This is a Charles' Law question; we're looking for the new volume of a gas when the temperature of the gas is increased. As was the case in Gay-Lussac's Law, the two parameters in Charles' Law—volume and temperature—are directly proportional. Since the temperature of the gas is increased, we should expect the new volume of the gas to also increase (V₂ will be greater than 5.00 L). Temperatures should be in Kelvin.
V₂ = V₁T₂/T₁ = (5.00 L)(300.15 K)/(250.15 K) = 5.99 L.
---
Question 6:
Another Charles' Law question. As with question 5, we want to find the new volume of the gas after a change in temperature. This time, the final temperature is lower than the initial temperature, so we should expect that V₂ will be less than the initial 0.5 L. Again, temperatures in Kelvin.
V₂ = V₁T₂/T₁ = (0.5 L)(313.15 K)/(493.15 K) = 0.317 L.
So, the volume of the balloon when it is fully cooled by your refrigerator will be 0.317 L.
---
Question 7:
This is yet another Charles' Law question, and, again, we are solving for V₂ after a change in temperature. Since the final temperature is greater than the initial temperature, V₂ should be greater than 2.2 L. Again, the temperatures should be in Kelvin.
V₂ = V₁T₂/T₁ = (2.2 L)(653.15 K)/(453.15 K) = 3.17 L.
The new volume of the gas is 3.17 L ≈ 3.2 L (two sig figs).
---
Question 8:
We return to Gay-Lussac's Law here; pressure and temperature are directly proportional, and the temperature of the gas is increased. Thus, P₂ should be greater than 3 atm. Again, remember that temperatures must be in Kelvin.
P₂ = P₁T₂/T₁ = (3 atm)(298.15 K)/(288.15 K) = 3.1 atm.
So, the pressure inside the can after the temperature rise is 3.1 atm. Not a big increase, but an increase nonetheless.
what happened to the sound as vibration of an object increase in strength
Answer:
A.The sound becomes louder.
And
C.The sound waves get further.
Explanation:
Louder the sound it will travel long.
Why are half-reactions used in redox reactions?
Answer:
Because a redox reaction holds for both oxidation and reduction.
One half equation is of oxidation and the other is of reduction.
When these two half equations are combined, we get an overall equation of the redox reaction.
C3H8, + 5O2
+ 5O2,3CO2 + 4H20
If 2.50 moles of C3H8react, how many moles of H20 are produced?
Answer:
[tex]from \: the \: equation \\ 1 \: moles \: of \: propane \: produce \: 4 \: moles \: of \: water \\ 2.50 \:moles \: of \: propane \: will \: produce \: ( \frac{(2.50 \times 4)}{1} ) \: moles \\ = 10 \: moles \: of \: water[/tex]
3.A binary mixture consisting of 50.7 mol % n-butane (1) and the balance iso-butane (2) enters a flash chamber operating at 9.6 bar and 344 K. Use the truncated virial equation of state (equation 3.36 in the textbook) to estimate the composition of the vapor and liquid phases leaving the flash chamber.
If the temperatures were raised slowly under the same conditions, would ice made from fresh water or sea water melt first? Which would boil first? Which of these would allow the temperature of an ice cream maker to drop below 0°C? Which requires colder temperatures to freeze, unsalted roads or salted roads? Which requires more heat to boil, pure water or a sugar solution used for making candy?
Answer:
1.sea water 2.fresh water 3. Salt and ice
4.salted roads 5. Sugar solution used for making candy
Explanation:
Because Truck
Answer:
salted roads
sugar something
pure water
Explanation:
trust me bro
How many mL of 0.100M Ca(OH) are needed to titrate 20.0mL of 0.300M H2SO4
Answer:
60.0 mL
Explanation:
Using CAVA = CBVB
CA = 0.300M
VA = 20.0 mL
CB = 0.100M
VB = ?
VB = CAVA
CB
VB = 0.300 * 20/ 0.100
VB = 60.0 mL
a freshwater stream flows into the ocean as shown in the diagram which statement correctly describes how the stream affects these salinity of the ocean
A- salinity increases because the stream adds salt to the ocean.
B- salinity decreases because the stream adds freshwater to the ocean
C- salinity increases because of stream adds freshwater to the ocean
D- salinity Remains the Same because the stream adds freshwater to the ocean
Calculate how many grams of sodium acetate you expected to make from your starting amount of sodium bicarbonate (0.5g). This is your theoretical yield.
Equation: NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2
What is a renewable resource on Earth?
minerals
coal
wind
petroleum
Answer:
Wind
Explanation:
Wind turbines make energy by the movement of the natural force on earth called 'wind' and renewable resources are resources that can be made from natural and environment-safe objects or things (e.g. Water, Geothermal Heat, The Sun, and Wind)
100.00 mL of 0.15 M nitrous acid (HNO2) are titrated with a 0.15 M NaOH solution. (a) Calculate the pH for the initial solution. (b) Calculate the pH for the point at which 80.0 mL of the base has been added. (c) Calculate the pH for the equivalence point. (d) Calculate the pH for the point at which 105 mL of the base has been added.
Answer:
a. pH = 2.04
b. pH = 3.85
c. pH = 8.06
d. pH = 11.56
Explanation:
The nitrous acid is a weak acid (Ka = 5.6x10⁻⁴) that reacts with NaOH as follows:
HNO₂ + NaOH → NaNO₂(aq) + H₂O(l)
a. At the beginning there is just a solution of 0.12M HNO₂. As Ka is:
Ka = [H⁺] [NO₂⁻] / [HNO₂]
Where [H⁺] and [NO₂⁻] ions comes from the same equilibrium ([H⁺] = [NO₂⁻] = X):
5.6x10⁻⁴ = X² / 0.15M
8.4x10⁻⁵ = X²
X = [H⁺] = 9.165x10⁻³M
As pH = -log [H⁺]
pH = 2.04b. At this point we have HNO₂ and NaNO₂ (The weak acid and the conjugate base), a buffer. The pH of a buffer is obtained using H-H equation:
pH = pKa + log [NaNO₂] / [HNO₂]
Where pH is the pH of the buffer,
pKa is -log Ka = 3.25
And [NaNO₂] [HNO₂] could be taken as the moles of each compound.
The initial moles of HNO₂ are:
0.100L * (0.15mol / L) = 0.015moles
The moles of base added are:
0.0800L * (0.15mol / L) = 0.012moles
The moles of base added = Moles of NaNO₂ produced = 0.012moles.
And the moles of HNO₂ that remains are:
0.015moles - 0.012moles = 0.003moles
Replacing in H-H equation:
pH = 3.25 + log [0.012moles] / [0.003moles]
pH = 3.85c. At equivalence point all HNO2 reacts producing NaNO₂. The volume added of NaOH must be 100mL. That means the concentration of the NaNO₂ is:
0.15M / 2 = 0.075M
The NaNO₂ is in equilibrium with water as follows:
NaNO₂(aq) + H₂O(l) ⇄ HNO₂(aq) + OH⁻(aq) + Na⁺
The equilibrium constant, kb, is:
Kb = Kw/Ka = 1x10⁻¹⁴ / 5.6x10⁻⁴ = 1.79x10⁻¹¹ = [OH⁻] [HNO₂] / [NaNO₂]
Where [OH⁻] = [HNO₂] = x
[NaNO₂] = 0.075M
1.79x10⁻¹¹ = [X] [X] / [0.075M]
1.34x10⁻¹² = X²
X = 1.16x10⁻⁶M = [OH⁻]
pOH = -log [OH-] = 5.94
pH = 14-pOH
pH = 8.06d. At this point, 5mL of NaOH are added in excess, the moles are:
5mL = 5x10⁻³L * (0.15mol / L) =7.5x10⁻⁴moles NaOH
In 100mL + 105mL = 205mL = 0.205L. [NaOH] = 7.5x10⁻⁴moles NaOH / 0.205L =
3.66x10⁻³M = [OH⁻]
pOH = 2.44
pH = 14 - pOH
pH = 11.56Help please I’ll mark as brainiliest
Answer:
B B
W BW BW
W BW BW
Explanation:
Hope this helps
Muscles and bones work together when muscles move bones through contracting and
relaxing.
A.true
B.false
I think it's true.
Explanation:
Muscles move bones through contracting and relaxing
Five identical test tubes are each filled from the following five copper (11) sulfate stock solutions. Which of the following test tubes would appear the lightest blue?
a) Stock solution made form 0.200 moles of CuSO4 dissolved to a total volume of 400 ml
b) Stock solution made form 0.150 moles of CuSO4 dissolved to a total volume of 300 mL
C)Stock solution made form 0.250 moles of CuSO4 dissolved to a total volume of 500 ml
d) Stock solution made form 0.175 moles of CuSO4 dissolved to a total volume of 400 ml
e) Stock solution made form 0.125 moles of CuSO4 dissolved to a total volume of 300 ml
Answer:
deez cutz
Explanation:
did i get it right
what type of chart is used to help organize study and predict genetic inheritance?
Answer:
Its a punnet square
Explanation:
Balance the single replacement chemical reaction.
Explanation:
B) 3CuCl2+2AL..….2AlCl3+3Cu
hope it helps.
Balanced Equation:
3CuCl₂ + 2Al = 2AlCl₃ + 3Cu
Groups of organs that work together to complete a series of takes are called..
A: Skeletal System
B: Organ System
C: Muscular System
What is the most likely effect of people logging a forest faster than it can grow back?
The forest will eventually disappear and no longer provide any resources.
The forest will eventually reach a smaller population size and remain at that size.
The forest will gradually grow faster to keep up with increased demand.
The forest will keep its current population size and continue to provide resources.
Answer:
D
Explanation:
A growing body of scientific evidence shows that the felling of tropical forests creates optimal conditions for the spread of mosquito-borne scourges, including malaria and dengue. Primates and other animals are also spreading disease from cleared forests to people.
10) Is the chemical equation balanced?
2 Al + Fe2O3
2Fe + Al2O3
Answer: Yes , the equation is balanced.
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The given chemical equation is:
[tex]2Al+Fe_2O_3\rightarrow 2Fe+Al_2O_3[/tex]
As the number of atoms on reactant side is equal to the number of atoms on product side, the equation is balanced.
How did the different trait help the one cactus survive and reproduce?
Answer:
The trait of the other cactus stopped it from being able to reproduce and survive.
Which of the following is the correct definition for electronegativity?
А. The amount of energy to attract or bond electrons
В. The amount of energy required to remove an electron
C. Half the distance between the nuclei of two bonded atoms
D. All of the above correctly explain electronegativity
Answer:
[tex]\color{Blue}\huge\boxed{Question} [/tex]
Which of the following is the correct definition for electronegativity[tex]\color{Blue}\huge\boxed{Answer} [/tex]
А. The amount of energy to attract or bond electronsWhat is the total number of atoms in ammonium hydroxide?
I will give Brainliest! :)
Answer:Ammonia is a compound that contains one nitrogen atom and three hydrogen atoms. Ordinarily having a characteristic of a pungent and gaseous compound.
Elemet: Hydrogen, Symbol: H, # of Atoms:5
Elemet:Nitrogen, Symbol: N, # of Atoms:1
Elemet:Oxygen, Symbol: O, #of Atoms:1
Explanation:
The number of atoms presennt in one mole of ammonium hydroxide is 6.02 * 10^23 atoms.
What is the mole?The mole refers to the amount of a substance that can be used as a reference. According to Avogadro, one mole of a substance contains 6.02 * 10^23 atoms, molecules, ions etc.
In that case, we can say that the number of atoms presennt in one mole of ammonium hydroxide is 6.02 * 10^23 atoms.
Learn more about mole: https://brainly.com/question/3393755?
What needs to be taken into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution?
The more concentrated the buffer solution, the greater its buffer capacity.
What is an acid?An acid is any substance that in water solution tastes sour, changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions.
The more concentrated the buffer solution, the greater its buffer capacity.
If the buffer capacity is 10 times larger, then the buffer solution can absorb 10 times more strong acid or base before undergoing a significant change in pH.
Hence, we need to take this into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution.
Learn more about acid here:
https://brainly.com/question/3700851
#SPJ2
How many atoms are in 20.4 g of beryllium
Using table 3, predict the molecular geometry of the following molecules:
a. The central atom bonded to four substituent atoms and having no lone pair.
b. The central atom bonded to three substituent atoms and having one lone pair.
c. The central atom bonded to two substituent atoms ảnd having
one lone pair.
d. The central atom bonded to two substituent atoms and having no lone pair.
Answer:
see explanations
Explanation:
a. The central atom bonded to four substituent atoms and having no lone pair.
This is an AX₄ geometry => tetrahedron
b. The central atom bonded to three substituent atoms and having one lone pair.
This is an AX₃E geometry => pyramidal
c. The central atom bonded to two substituent atoms ảnd having
one lone pair.
This is an AX₂E geometry => bent angular
d. The central atom bonded to two substituent atoms and having no lone pair.
This is an AX₂ geometry => linear
_______________________________
Based upon the VSEPR Theory there are 6 parent geometry configurations and associated derived geometries.
Parent geometries => Derivatives => Examples
linear => AX₂ (BeCl₂) trigonal planer => AX₃ (BH₃) => AX₂E (Bent) (:SnCl₂)tetrahedral => AX₄ (CH₄) => pyrimidal AX₃E (NH₃) => Bent AX₂E₂ (H₂O)trigonal bipyrimidal => AX₅ (PCl₅) => seesaw AX₄E (:SF₄) => T-shaped AX₃E₂ (ClF₃ (T-shaped) => linear AX₂E₃ (XeF₂)octahedral => AX₆ (SF₆) => sqr pyramid AX₅E (IF₅) => sqr planar AX₄E₂ (XeF₄) pentagonal bipyrimidal => AX₇ (ClF₇)For graphic images of each geometry do an internet search for 'molecular geometry'.
811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of the metal is 0.534 J/g*C. oC
Answer:
16 °C
Explanation:
Step 1: Given data
Provided heat (Q): 811.68 JMass of the metal (m): 95 gSpecific heat capacity of the metal (c): 0.534 J/g.°CStep 2: Calculate the temperature change (ΔT) experienced by the metal
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C
Plz answer the first two questions and maybe the third. I will give brainliest.
Answer:
1. 24.45 moles
2. 437.90 grams
Bonus :
0.75 grams
Explanation:
Hope it was helpful ;)