Answer:
Acceleration
Explanation:
The choice from the given option which is not a force is acceleration.
Acceleration is defined as the rate of change of velocity of a body with time;
Acceleration = [tex]\frac{change in velocity}{time}[/tex]
Force is a pull or push on a body. The product of mass and acceleration is force.
Thrust is a form of forceGravity is a force acting on bodies with masses. Friction is a force that opposes motion,A projectile is shot a cliff of 20m high, at an angle of 60o with respect to the horizontal, and it lands on the ground 8 seconds later. Find: a) the initial speed ? b) the speed of the projectile after 4 s c) the horizontal range d)the maximum height it reached e) what was the speed of the projectile when it landed on the ground?
Answer:
a) The initial speed of the projectile is approximately 42.410 meters per second.
b) The speed of the projectile after 4 seconds is approximately 21.352 meters per second.
c) The horizontal range of the projectile is 169.64 meters.
d) The maximum height of the projectile is 68.775 meters.
e) The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.
Explanation:
According to the statement, the projects shows a parabolic motion, which consists in the combination of horizontal uniform motion and vertical uniformly accelerated motion due to gravity. This motion is represented by the following equations of motion:
[tex]x = x_{o} + v_{o}\cdot t\cdot \cos \theta[/tex] (1)
[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \theta + \frac{1}{2}\cdot g\cdot t^{2}[/tex] (2)
Where:
[tex]x_{o}[/tex], [tex]x[/tex] - Initial and current horizontal position, measured in meters.
[tex]y_{o}[/tex], [tex]y[/tex] - Initial and current vertical position, measured in meters.
[tex]\theta[/tex] - Launch angle, measured in sexagesimal angle.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]t[/tex] - Time, measured in second.
a) By using (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]y = 0\,m[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then initial speed of the projectile is:
[tex]v_{o}\cdot t \cdot \sin \theta = y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2}[/tex]
[tex]v_{o} = \frac{y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2} }{t\cdot \sin \theta}[/tex]
[tex]v_{o} = \frac{0\,m-20\,m-\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)^{2} }{(8\,s)\cdot \sin 60^{\circ}}[/tex]
[tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex]
The initial speed of the projectile is approximately 42.410 meters per second.
b) The vertical component of the velocity of the projectile is determine by differentiating (2) in time and substitute all known values:
[tex]v_{y} = v_{o}\cdot \sin \theta +g\cdot t[/tex] (3)
([tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 4\,s[/tex])
[tex]v_{y} = -2.5\,\frac{m}{s}[/tex]
The horizontal component of the velocity of the projectile is:
[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]
[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]
And the speed of the projectile is determined by Pythagorean Theorem:
[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]
[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-2.5\,\frac{m}{s} \right)^{2}}[/tex]
[tex]v \approx 21.352\,\frac{m}{s}[/tex]
The speed of the projectile after 4 seconds is approximately 21.352 meters per second.
c) By (1) we find the horizontal range of the projectile:
([tex]x_{o} = 0\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 8\,s[/tex])
[tex]x = 0\,m + \left(42.410\,\frac{m}{s} \right)\cdot (8\,s)\cdot \cos 60^{\circ}[/tex]
[tex]x = 169.64\,m[/tex]
The horizontal range of the projectile is 169.64 meters.
d) The projectile reaches its maximum height when velocity is zero. By (3) and knowing that [tex]v_{y} = 0\,\frac{m}{s}[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the time associated with maximum height is:
[tex]0\,\frac{m}{s} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot t[/tex]
[tex]t = 3.745\,s[/tex]
And by (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 3.745\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the maximum height reached by the projectile is:
[tex]y = 20\,m + \left(42.410\,\frac{m}{s} \right)\cdot (3.745\,s)\cdot \sin 60^{\circ}+\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (3.745\,s)^{2}[/tex]
[tex]y = 68.775\,m[/tex]
The maximum height of the projectile is 68.775 meters.
e) If we know that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the components of the speed are, respectively:
[tex]v_{y} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)[/tex]
[tex]v_{y} = -41.728\,\frac{m}{s}[/tex]
[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]
[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]
And the speed of the projectile is determined by Pythagorean Theorem:
[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]
[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-41.728\,\frac{m}{s} \right)^{2}}[/tex]
[tex]v \approx 46.807\,\frac{m}{s}[/tex]
The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.
Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?
Answer:
The displacement of Sudhir is 0.781 km.
Explanation:
Given;
initial distance, d₁ = 0.4 km = 400 m, N60.0°W
final distance, d₂ = 0.5 km
Make a sketch of Sudhir motion to form a right angled triangle;
(Check image uploaded).
Apply cosine rule to determine d "displacement"
d² = 500² + 400² - (2 x 500 x 400 x cos 120)
d² = 410,000 - (400,000 x -0.5)
d² = 410,000 - (-200,000)
d² = 410,000 + 200,000
d² = 610,000
d = √610000
d = 781.03 m
d = 0.781 km
Therefore, the displacement of Sudhir is 0.781 km.
An airplane is flying at an elevation of 6 miles on a flight path that will take it directly over a radar tracking station. Let S represent the distance between the radar station and the plane. If S is decreasing at a rate of 400 mph when S is 10 miles, what is the velocity of the plane
Answer:
[tex]-500\ \text{mph}[/tex]
Explanation:
h = Height at which the plane is flying = 6 miles
S = Distance between plane and radar = 10 miles
[tex]\dfrac{dS}{dt}[/tex] = Rate at which S is decreasing = -400 mph
Distance between S and and the elevation of the plane
[tex]b=\sqrt{S^2-h^2}=\sqrt{10^2-6^2}\\\Rightarrow b=8[/tex]
From Pythagoras theorem we get
[tex]S^2=b^2+h^2[/tex]
Differentiating with respect to time we get
[tex]2S\dfrac{dS}{dt}=2b\dfrac{db}{dt}+2h\dfrac{dh}{dt}\\\Rightarrow S\dfrac{dS}{dt}=b\dfrac{db}{dt}+h\dfrac{dh}{dt}\\\Rightarrow 10\times -400=8\times \dfrac{db}{dt}+0\\\Rightarrow \dfrac{db}{dt}=\dfrac{10\times -400}{8}\\\Rightarrow \dfrac{db}{dt}=-500\ \text{mph}[/tex]
Velocity of the plane is [tex]-500\ \text{mph}[/tex].
If the distance between the radar station and the plane is decreasing at the given rate, the velocity of the plane is -500mph
Given the data in the question;
Elevation; [tex]x = 6miles[/tex]Distance between the radar station and the plane; [tex]S = 10miles[/tex]Since "S" is decreasing at a rate of 400 mph; [tex]\frac{ds}{dt} = -400mph[/tex]As illustrated in the diagram below, we determine the value of "y"
Using Pythagorean theorem:
[tex]S^2 = x^2 + y^2[/tex]------------Let this be Equation 1
We substitute in our value
[tex]y = \sqrt{(10miles)^2- (6miles)^2} \\\\y = \sqrt{100mi^2- 36mi^2}\\\\y = \sqrt{64mi^2}\\\\y = 8miles[/tex]
Now, we determine velocity of the plane i.e the change in distance in horizontal direction ([tex]\frac{dy}{dt}[/tex])
Lets differentiate Equation 1 with respect to time t
[tex]2S\frac{ds}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]------ Let this be Equation 2
Since, the plane is not landing, [tex]\frac{dx}{dt} =0[/tex]
We substitute our values into Equation 2 and find [tex]\frac{dy}{dt}[/tex]
[tex][2*10mi*(-400mph) ] = [2*6mi*0] + [2*8mi * \frac{dy}{dt}]\\\\-8000m^2ph = 0 + 16miles * \frac{dy}{dt}\\\\\frac{dy}{dt} = \frac{-8000m^2ph}{16miles}\\\\\frac{dy}{dt} = -500mph[/tex]
Therefore, if the distance between the radar station and the plane is decreasing at the given rate, the velocity of the plane is -500mph
Learn more: https://brainly.com/question/18187424
True or false? When a change of state starts to occur, the energy supplied changes the temperature but not the internal energy.
Answer:
True
Explanation:
This heat energy allows the change of state to happen, and the temperature remains constant during the process. The amount of energy required to change the state of a substance depends upon the mass and characteristics of that substance. The energy required to change the state of a material is known as the latent heat. During a change of phase the temperature does not change, but the internal energy does. The internal energy is the sum of the kinetic energy of the molecules and the chemical potential energy of the molecules.
A 40 kg boy is moving upwards in a lift with an acceleration of 2 m /s ^2 what would be the weight felt by him if measuured in a scale
Answer:
40×（9.8+2）＝432n
Explanation:
9.8m/s^2 is acceleration of gravity
Answer with explanation!!!
Answer:
The light enters the box along the normal to the side of the box or perpendicularly to the box's surface
Therefore, the light is expected to travel straight through the box
However, when a rectangular glass prism is placed inside the box, the light can then be refracted to pass through the box in the given path as shown
Light bends towards the normal when passing from a less dense medium to a denser medium with larger refractive index and vice versa
Therefore, when the glass prism with a larger refractive index than air is inclined with the top part further away from the incident beam and the bottom part closer to the incident beam as shown, the refracted ray through the box will be shifted downwards as shown in the drawing created with Microsoft Visio
Explanation:
[tex]Refractive \ index, n = \dfrac{sin(i)}{sin(r)}[/tex]
Where;
i = The angle between the incidence light and the normal line
r = The angle between the refracted light and the normal line
n = The refractive index
When n > 1 is large, we have, ∠i > ∠r and the light is bent towards the normal when moving from a less dense medium to a denser medium and vice versa.
11. A non-contact force that exists between objects with mass is called
In the reaction 2H, + O, → H,0, what coeficient should be placed in front of H,0 to balance the reaction?
Which of the following statements would be best described as an expression of an attitude that is low in accessibility and high in ambivalence?
A.
Frank: “I eat a banana for breakfast everyday. I’ve loved them since I was little.”
B.
Judy: “I really dislike bananas. I don’t know why. I just always have.”
C.
Ralph: “I’m not sure about bananas. I’d have to think about it.”
D.
Fiona: “I am a huge banana fan. I don’t know why. I just like them.”
Answer:
The answer is C. Ralph: “I’m not sure about bananas. I’d have to think about it.”
Explanation:
I did the practice.
Answer:
C.) Ralph: "I'm not sure about bananas. I'd have to think about it."
Explanation:
Just took the practice
Two vector have equal magnitude and their resultant also have the same magnitude, what is the angle between the two vectors?
Answer:
The angle between the two vectors is 60°
Explanation:
Let A and B represent the two vectors, we have;
[tex]\left | A \right | = \left | B \right | = \left | A + B\right |= \left | R\right |[/tex]
Let [tex]\left | A \right |[/tex] = a, [tex]\left | B\right |[/tex] = b, and [tex]\left | R\right |[/tex] = c
We have by cosine rule
c² = a² + b² - 2 × a × b × cos(C)
Where, the angle "C", is the angle between the resultant of the two vectors, a and b and facing the resultant [tex]\left | R\right |[/tex]
Given that, a = b = c, we have;
a² = a² + a² - 2 × a × a × cos(C)
a² = 2·a² - 2 × a² × cos(C)
2 × a² × cos(C) = 2·a² - a²
cos(C) = a²/(2·a²) = 1/2
Therefore, angle ∠C = arccosine(1/2) = 60°
The angle between the two vectors = ∠C = 60°.
A boy throws rocks with an initial velocity of 12m/s [down] from a 20 m bridge into a river. Consider the river to be at a height of 0 m. Draw a velocity-time and position-time graph. Use up as position and ignore air resistance.
Answer:
Please find attached the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel
Explanation:
The given parameters are;
The initial velocity with which the boy throws the rock, u = 12 m/s
The direction in which he throws the rock = Down
The height from which the rock was thrown, h = 20 m
The height at which the river is located = 0 m
The kinematic equation of motion, of the rock can be given as follows;
h = u·t + 1/2·g·t²
Where;
t = The time of motion of the rock
g = The acceleration due to gravity = 9.8 m/s²
h = The height from which the rock is thrown = 20 m
Substituting the known values into given equation, we get;
20 = 12·t + 1/2·9.8·t² = 12·t + 4.9·t²
4.9·t² + 12·t - 20 = 0
t = (-12 ± √(12² - 4×4.9×(-20)))/(2 × 4.9) = (-12 ± √(242))/(9.8)
t ≈ -3.587 seconds or t ≈ 1.138 seconds
Attached please find the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel.
what would be the importance of a topographic map in a rescue situation?
Answer:
Topographic maps give the user the ability to view a three-dimensional landscape on a two-dimensional map. One who is able to read a topo map can identify the elevation and location of valleys, peaks, ridges, and other land features.
Explanation:hope this helps
a horizental force of 310n exerted on 2.0kg ball as it rotates ( at arm's length) uniformly in horizental circle of radius 0.0.90m calculate the speed of the ball
Answer:
v=11.8m/s
Explanation:
speed of the ball
Force=mass*centripetal acceleration
Centripetal acceleration= V2/r
F=M*V2/r
Data
F=310N
M=2.0kg
r=0.90m
v=?
310N=(2.0kg)*V2/0.90m
cross multiply
279Nm=(2.0kg)V2
V2= 279Nm/2.0kg
V2=139.5Nm/kg
apply square root both sides
√V2=√139.5
V=11.8m/s
a horizontal force of 50 Newtons acts on a body of mass 3kg placed on a rough horizontal surface, giving it an acceleration of 8m/s2
Explanation:
Fnet = ma = (3kg)(8m/s²) = 24N.
50N - 24N = 26N.
Hence the frictional force is 26N.
A bicyclist travels 4.5 km west, then travels 6.7 km at an angle 27.0 degrees South of West. What is the magnitude of the bicyclist's total displacement?
Answer:
10.90km
Explanation:
Magnitude of the total displacement is expressed using the equation
d = √dx²+dy²
dx is the horizontal component of the displacement
dy is the vertical component of the displacement
dy = -6.7sin27°
dy = -6.7(0.4539)
dy = -3.042
For the horizontal component of the displacement
dx = -4.5 - 6.7cos27
dx = -4.5 -5.9697
dx = -10.4697
Get the magnitude of the bicyclist's total displacement
Recall that: d = √dx²+dy²
d = √(-3.042)²+(-10.4697)²
d = √9.2538+109.6146
d = √118.8684
d = 10.90km
Hence the magnitude of the bicyclist's total displacement is 10.90km
The bicyclist magnitude of displacement is equal to 9.62m
Resolution of VectorsTo find the resultant magnitude of the bicyclist total displacement, we have to find the x and y component.
For the first direction, the components are
[tex]x_1 = -4.5i[/tex]
sine we don't have any vertical displacement, the y-component is equal to zero.
for the second direction,
[tex]x_2 = -6.7sin27i\\y_2= 6.7cos27j[/tex]
The resultant x and y component are;
[tex]R_x = -4.5i + (-6.7sin27i)\\R_x = -7.54i[/tex][tex]R_y = 0 + 6.7cos27= 5.97j[/tex]Let's find the magnitude of displacement
[tex]R = \sqrt{R_x^2 + R_x^2}\\R = \sqrt{(-7.54)^2 + (5.97)^2 }\\\\R = 9.62m[/tex]
The bicyclist magnitude of displacement is equal to 9.62m
Learn more on resolution of vectors here;
https://brainly.in/question/3543542
When a 65 kg skydiver jumps from a plane, her speed steadily increases until air
resistance provides a force that balances the force due to free fall. How fast is the
skydiver falling if her kinetic energy at the moment is 704 x 10- J?
Correct value of kinetic energy is 704 × 10³ J
Answer:
v = 147.18 m/s
Explanation:
At any point/moment during the fall, the sky diver will possess kinetic energy with the formula;
KE = ½mv²
Where;
m is mass
v is velocity
We are given;
m = 65 kg
KE = 704 × 10³ J
Thus;
704 × 10³ = ½ × 65 × v²
v² = (2 × 704 × 10³)/65
v² = 21661.53846153846
v = √21661.53846
v = 147.18 m/s
what is a volt as applied in physics
Answer:
The answer is below
Explanation:
Volt in physics is a term that is used to describe the unit of both electrical potential difference and electromotive force. In other words, it is a unit of measuring the voltage between two points. It is represented as "V".
The formula for Voltage is V=IR
Where V= Voltage, I = Current and R = Resistance.
State Ohms law o derive relation between
Vel and R Draw the graph between
vanda
Answer:
Explanation:
V = I*R
V/R = I
How does wheel and axel work
Once the object is moving, the force of friction opposes the force exerted on the object. The wheel and axle makes this easier by reducing the friction involved in moving an object.
Hope it helps!
Answer:
The wheel and axle work by reducing the effect of friction on an object, thereby creating a mechanical advantage.
when required to be returned to the issuing activity upon the individual's transfer, clothing loaned to an individual by a navy activity is referred to by what term?
Answer:
Organizational clothing.
Explanation:
An organizational clothing can be defined as the standard field uniform of the U.S Navy that is being loaned to a person (officer) by a naval activity and as such must be returned to the naval activity as soon as the person is transferred.
Basically, an organizational clothing is generally considered to be the property of the U.S Navy and should be sent to the regional or area naval coordinator.
Hence, when required to be returned to the issuing activity upon the individual's transfer, clothing loaned to an individual by a navy activity is referred to as organizational clothing.
are fossil fuels a renewable energy source because they are formed from living things
Answer:
Fossil fuels are non-renewable . They took a very long time to form and we are using them up faster than they can be replaced - once they have all been used up, they cannot be replaced.
A girl runs at a speed of 3.9 m/s off a high dive and hit the water 1.8 s later.
a. How high was the diving board?
b. How far horizontally was she from the board when she hit the water?
c. If she had just dropped off the board, would her time to drop to the water been longer, shorter or the same?
Answer:
(a) the height of the diving board is 22.896 m
(b) the horizontal distance traveled by the girl is 7.02 m
(c) if she had just drop off the board, her time to drop to the water would have been longer.
Explanation:
Given;
initial speed of the girl, u = 3.9 m/s
time to hit the water, t = 1.8 s
(a) the height of the diving board is calculated as;
h = ut + ¹/₂gt²
h = (3.9 x 1.8) + ¹/₂ x 9.8 x 1.8²
h = 7.02 + 15.876
h = 22.896 m
(b) the horizontal distance traveled by the girl is calculated as;
X = ut
X = 3.9 x 1.8
X = 7.02 m
(c) if she just drop off the board, then the initial speed will be zero;
h = ut + ¹/₂gt²
h = 0 + ¹/₂gt²
2h = gt²
[tex]t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \ \times\ 22.896 }{9.8} }\\\\t = 2.16 \ s[/tex]
Thus, if she had just dropped off the board, her time to drop to the water would have been longer.
An airplane traveling from Atlanta to New York travels 1,395 km in 2.5 h. What is the plane’s average speed?
A. 0.00179 km/h
B. 3,487.5 km/h
C. 1,259 km/h
D. 558 km/h
What exercise will strengthen your legs?
Biking
Stretching
Lifting a box
Playing catch
Answer:
biking
Explanation:
To make the Bike move you peddle with your legs.
Total Internal Reflection
Each critical angle of the prisms is 42°.How the direction of light to reflect ?
Answer: The light beam will not diffract out of the prism.
Explanation: The angle the light is entering the prism is greater than the critical angle therefore total internal reflection will occur. Hope this helps :)
Does the reaction above satisfy the law of conservation of matter? Use details to support your work.
2H₂O₂=H₂+O₂
Answer:
No, the amount of matter of the reactants is not equal to the amount of matter of the products.
Explanation:
According to the conservation of matter the amount of matter of the reactants is equal to the amount of matter of the products. The given reaction is
[tex]2H_2O_2=H_2+O_2[/tex]
In the reactant side there are [tex]2\times 2=4[/tex] molecules of hydrogen and [tex]2\times 2=4[/tex] molecules of oxygen.
In the product side there are 2 molecules of both hydgrogen and oxygen. So the reaction does not satisfy the law of conservation of mass.
The balanced reaction would be
[tex]2H_2O_2=2H_2+2O_2[/tex].
A tilt a whirl at an amusement park has a radius of 8 m and it completes 1
revolution every 4 seconds. A passenger on board has a mass of 63 kg.
What is the velocity of the passenger?
Answer: 12.56 m/s
Explanation:
The velocity of something that is doing a circular motion can be written as:
v = R*w
Where:
v is the velocity.
R is the radius, in this case, we know that it is 8m.
w is the angular velocity, we know that:
w = 2*pi*f
where:
pi = 3.14
f = frequency, this is equal to the inverse of the period, and we know that the period is 4 seconds.
then:
f = 1/4s
w = 2*3.14*(1/4s)
Then the velocity will be:
v = 8m*2*3.14*(1/4s) = 12.56 m/s
The velocity is 12.56 meters per second, and the mass of the passenger does not mater for this particular calculation.
Calculate the gravitational force acting on a 16.8kg monkey flying through the air on Earth. Fg = mg , g = 9.8
Given that,
Mass of the monkey, m = 16.8 kg
The acceleration due to gravity on the Earth, g = 9.8 m/s²
To find,
The gravitational force acting on the monkey.
Solution,
Gravitational force acting on the monkey is equal to its weight. It is given by :
W = mg
Putting all the values,
W = 16.8 kg × 9.8 m/s²
= 164.64 N
Hence, the gravitational force acting on the monkey is 164.64 N.
Water in its solid state has a specific heat of 2.093 J/g°C. Water in its liquid state has a specific heat of 4.186 J/g°C. Which statement best relates the difference in specific heats?
More hydrogen bonds must be broken between water molecules in the liquid state than in the solid state for a given increase in temperature.
Hydrogen bonds between water molecules are stronger in the liquid state than in the solid state.
For a given amount of energy, the temperature of solid water changes less than an equal mass of liquid water.
The hydrogen bonds between water molecules are more cohesive in the liquid state than in the solid state.
Answer:
D: The hydrogen bonds between water molecules are more cohesive in the liquid state than in the solid state.
Explanation:
If we assume that there is no phase change due to heating, we know that the temperature change will be proportional to the mass heated, being the proportionality constant that is a quantity which depends on the material, and also represents the resistance of the material to cause a change in the temperature and is called specific heat.
Now, if we are to assume that the mass is the same for the three phases, and that the amount of heat supplied is also the same, the phase with the highest specific heat will therefore possess the lowest temperature change.
At a lower temperature, the hydrogen bonds will be more cohesive than at higher temperatures.
We are told that in it's solid state, it has a specific heat capacity of 2.093 J/g°C while in its liquid state, it has a specific heat capacity of 4.186 J/g°C.
Thus, the hydrogen bonds between water molecules in the liquid state will be less cohesive than in its solid state.
Answer: D
Explanation:
HELP ME ASAP PLEASE!!Which natural phenomenon can trigger a landslide?
O intense rain or an earthquake
O light breezes or a flowing stream
O heavy snow or continuous sunlight
O icy conditions or ground surface melting
Answer:
O Intense rain or an earthquake
Explanation:
Landslides can be initiated in slopes already on the verge of movement by rainfall, snowmelt, changes in water level, stream erosion, changes in ground water, earthquakes, volcanic activity, disturbance by human activities, or any combination of these factors.
Intense rain or an earthquake can trigger a landslide.
Landslide is a natural phenomenon in which a mass of rock and/or earth moves down a slope. An earthquake is a major geologic hazard that shakes the Earth and thus can induce a landslide.Intense rain can also induce a landslide because humidity on the ground also leads to disturbances in the natural stability of the slope.In conclusion, intense rain or an earthquake can trigger a landslide.
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