Answer:
1) 1/2 + 1/4 = 2/4 + 1/4 = 3/4
2) To add these fractions, you need to find a common denominator. The smallest common multiple of 7 and 9 is 63, so we can write:
3/7 * 9/9 + 2/9 * 7/7 = 27/63 + 14/63 = 41/63
3) To add these fractions, you need to find a common denominator. The smallest common multiple of 5 and 15 is 15, so we can write:
3/5 * 3/3 + 1/15 * 1/1 = 9/15 + 1/15 = 10/15
But we can simplify this fraction by dividing both the numerator and denominator by 5:
10/15 = 2/3
4) To add these fractions, you need to find a common denominator. The smallest common multiple of 9 and 8 is 72, so we can write:
1/9 * 8/8 + 7/8 * 9/9 = 8/72 + 63/72 = 71/72
5) To add these fractions, you need to find a common denominator. The smallest common multiple of 7 and 21 is 21, so we can write:
6/7 * 3/3 + 2/21 * 1/1 = 18/21 + 2/21 = 20/21
6) To add these fractions, we need to find a common denominator first. The smallest number that both 6 and 10 divide into is 30. So, we convert 4/6 to 20/30 by multiplying both the numerator and denominator by 5, and we convert 2/10 to 3/15 by multiplying both the numerator and denominator by 3. Now we have:
20/30 + 3/15 = (20x1 + 3x2)/(30x2) = 23/60
Therefore, 4/6 + 2/10 = 23/60.
7) To add these fractions, we need to find a common denominator first. The smallest number that both 11 and 22 divide into is 22. So, we convert 1/11 to 2/22 by multiplying both the numerator and denominator by 2, and we convert 3/22 to 3/22 (it is already in terms of 22). Now we have:
2/22 + 3/22 = (2 + 3)/22 = 5/22
Therefore, 1/11 + 3/22 = 5/22.
8) To add these fractions, we need to find a common denominator first. The smallest number that both 4 and 20 divide into is 20. So, we convert 1/4 to 5/20 by multiplying both the numerator and denominator by 5, and we convert 8/20 to 8/20 (it is already in terms of 20). Now we have:
5/20 + 8/20 = (5 + 8)/20 = 13/20
Therefore, 1/4 + 8/20 = 13/20.
9) To add these fractions, we need to find a common denominator first. The smallest number that both 7 and 9 divide into is 63. So, we convert 4/7 to 24/63 by multiplying both the numerator and denominator by 3, and we convert 2/9 to 14/63 by multiplying both the numerator and denominator by 7. Now we have:
24/63 + 14/63 = (24 + 14)/63 = 38/63
Therefore, 4/7 + 2/9 = 38/63.
10) To add these fractions, we need to find a common denominator first. The smallest number that both 10 and 30 divide into is 30. So, we convert 6/7 to 18/30 by multiplying both the numerator and denominator by 3, and we convert 2/30 to 1/15 by multiplying both the numerator and denominator by 15. Now we have:
18/30 + 1/15 = (18x1 + 1x2)/(30x2) = 37/30
Therefore, 6/7 + 2/21 = 37/30.
24. Anna, Berta, Charlie, David and Elisa baked biscuits at the weekend. Anna baked 24, Berta
25, Charlie 26, David 27 and Elisa 28 biscuits. By the end of the weekend one of the children had
twice as many, one 3 times, one 4 times, one 5 times and one 6 times as many biscuits as on
Saturday. Who baked the most biscuits on Saturday?
(A) Anna (8) Berta (C) Charlie (D) David (E) Elisa
At the end of the weekend, Elisa had the most biscuits (168). So, the answer is (E) Elisa baked the most biscuits on Saturday.
To determine who baked the most biscuits on Saturday, we need to calculate how many biscuits each child had at the end of the weekend.
Anna had 24 biscuits, Berta had 25, Charlie had 26, David had 27, and Elisa had 28.
Let's start with the child who had twice as many biscuits as on Saturday. We can divide their total number of biscuits by 2 to get the number they had on Saturday.
If we try this calculation for each child, we find that only Elisa's total number of biscuits (28) is evenly divisible by 2. Therefore, Elisa must be the child who had twice as many biscuits as on Saturday, meaning she had 14 biscuits on Saturday.
We can use a similar process to determine how many biscuits each child had on Saturday:
- The child who had three times as many biscuits as on Saturday must have had a total of 42 biscuits, which means they had 14 biscuits on Saturday.
- The child who had four times as many biscuits as on Saturday must have had a total of 56 biscuits, which means they had 14 biscuits on Saturday.
- The child who had five times as many biscuits as on Saturday must have had a total of 70 biscuits, which means they had 14 biscuits on Saturday.
- The child who had six times as many biscuits as on Saturday must have had a total of 84 biscuits, which means they had 14 biscuits on Saturday.
Now we can add up the number of biscuits each child had on Saturday:
- Anna had 24 biscuits.
- Berta had 25 biscuits.
- Charlie had 26 biscuits.
- David had 27 biscuits.
- Elisa had 14 biscuits.
Therefore, David baked the most biscuits on Saturday with 27.
To determine who baked the most biscuits on Saturday, we need to consider the information given about the multiplication factors (twice, 3 times, 4 times, 5 times, and 6 times) and the initial number of biscuits baked by each child.
1. Anna baked 24 biscuits.
2. Berta baked 25 biscuits.
3. Charlie baked 26 biscuits.
4. David baked 27 biscuits.
5. Elisa baked 28 biscuits.
Now, let's apply the multiplication factors and see which child had the most biscuits at the end of the weekend:
1. Anna: 24 x 2 = 48
2. Berta: 25 x 3 = 75
3. Charlie: 26 x 4 = 104
4. David: 27 x 5 = 135
5. Elisa: 28 x 6 = 168
At the end of the weekend, Elisa had the most biscuits (168). So, the answer is (E) Elisa baked the most biscuits on Saturday.
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If the coordinates of two points are P (-2, 3) and Q (-3, 5), then find (abscissa of P) – (abscissa of Q)
The difference between the abscissa of P and Q is 1.
The abscissa of a point is its x-coordinate, or horizontal distance from the origin (usually measured along the x-axis).
In the given problem, the abscissa of point P is -2, which means it is located 2 units to the left of the origin on the x-axis. The abscissa of point Q is -3, which means it is located 3 units to the left of the origin on the x-axis.
To find the difference between the abscissas of P and Q, we simply subtract the abscissa of Q from the abscissa of P:
(abscissa of P) - (abscissa of Q) = (-2) - (-3) = -2 + 3 = 1
Therefore, the difference between the abscissas of P and Q is 1 unit.
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Question 7 Determine the way in which the line (x, y, z) = (2, -3, 0] + k[-1, 3, -1) intersects the plane [x, y, 2] = [4, -15, -8] + s[1, -3, 1] + t[2, 3, 1), if at all. [2T/2A] , - No text entered -
The line intersects the plane at the point (-4, 15, -6).
How to find the intersection of line in given plane?The line (x, y, z) = (2, -3, 0) + k(-1, 3, -1) can be expressed parametrically as:
x = 2 - k
y = -3 + 3k
z = k
The plane [x, y, 2] = [4, -15, -8] + s[1, -3, 1] + t[2, 3, 1) can be expressed in scalar form as:
x + y - 2z = 14 + s - 2t
To find the intersection of the line and the plane, we can substitute the parametric equations of the line into the scalar equation of the plane:
(2 - k) + (-3 + 3k) - 2k = 14 + s - 2t
Simplifying this equation, we get:
-4k + 3 = 14 + s - 2t
We can also express the line and plane equations in vector form:
Line: r = (2, -3, 0) + k(-1, 3, -1) = (2-k, -3+3k, k)
Plane: r = (4, -15, -8) + s(1, -3, 1) + t(2, 3, 1) = (4+s+2t, -15-3s+3t, -8+s+t)
To find the intersection of the line and the plane, we need to find the values of k, s, and t that satisfy both equations simultaneously. We can do this by equating the vector forms of the line and plane and solving for k, s, and t:
2 - k = 4 + s + 2t
-3 + 3k = -15 - 3s + 3t
k = -8 - s - t
Substituting k into the first equation, we get:
2 + 8 + s + t = 4 + s + 2t
Simplifying this equation, we get:
t = 4
Substituting t = 4 and k = -8 - s - t into the second equation, we get:
-3 + 3(-8 - s - 4) = -15 - 3s + 3(4)
Simplifying this equation, we get:
s = -2
Substituting t = 4 and s = -2 into the first equation, we get:
k = 8 - s - t = 8 + 2 - 4 = 6
Therefore, the line intersects the plane at the point (x, y, z) = (2, -3, 0) + 6(-1, 3, -1) = (-4, 15, -6).
So the line intersects the plane at the point (-4, 15, -6).
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please help me answer this (can give brainliest)
a) The graph of the given lines is as attached
b) The area of the enclosed triangle is: 8 square units
How to graph linear equations?The general form of expression of linear equations in slope intercept form is expressed as:
y = mx + c
where:
m is slope
c is y-intercept
We are given the equations as:
y = x + 5
y = 5
x = 4
The graph of these three linear equations is as shown in the attached file
2) The area of the given triangle enclosed by the three lines is gotten from the formula:
A = ¹/₂ * b * h
where:
A is area
b is base
h is height
Thus:
A = ¹/₂ * 4 * 4
A = 8 square units
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Solid metal support poles in the form of right cylinders are made out of metal with a
density of 6.3 g/cm³. This metal can be purchased for $0.30 per kilogram. Calculate
the cost of a utility pole with a diameter of 42 cm and a height of 740 cm. Round your
answer to the nearest cent. (Note: the diagram is not drawn to scale)
Answer:Therefore, the cost of a utility pole with a diameter of 42 cm and a height of 740 cm is approximately $1957.43.
Step-by-step explanation:First, we need to calculate the volume of the cylinder-shaped utility pole:
The radius of the pole is half the diameter, so it's 42 cm / 2 = 21 cm.
The height of the pole is 740 cm.
The volume of a cylinder is given by the formula V = πr²h, where π is approximately 3.14, r is the radius, and h is the height.
Substituting the values we have, we get V = 3.14 x 21² x 740 = 1,034,462.4 cm³.
Now we can calculate the mass of the pole:
The density of the metal is 6.3 g/cm³, which means that 1 cm³ of the metal has a mass of 6.3 g.
The volume of the pole is 1,034,462.4 cm³, so its mass is 6.3 x 1,034,462.4 = 6,524,772.72 g.
Next, we convert the mass to kilograms and calculate the cost:
1 kg is equal to 1000 g, so the mass of the pole in kilograms is 6,524,772.72 g / 1000 = 6524.77 kg.
The cost of the metal is $0.30 per kilogram, so the cost of the pole is 6524.77 kg x $0.30/kg = $1957.43.
how much soda do you need if you buy 20 bags of 4 bags of hot chips and 3 bottles of soda.
If each bag of hot chips requires around 500 ml of soda to drink with, then 46,000 ml of soda would be needed to buy 20 bags of 4 bags of hot chips and 3 bottles of soda.
To determine how much soda is needed if you buy 20 bags of 4 bags of hot chips and 3 bottles of soda, we need to know the volume of each bottle of soda.
Assuming each bottle of soda contains 2 liters of soda, the total volume of soda needed can be calculated as follows:
One bag of hot chips contains 4 bags of chips.So, 20 bags of hot chips contain 20 x 4 = 80 bags of chips.Each bag of chips may require around 500 ml of soda to drink with.Therefore, the total soda needed for all bags of chips is 80 x 500 ml = 40,000 ml.Three bottles of soda are also purchased, which contain a total of 3 x 2000 ml = 6000 ml.The total soda needed is the sum of the soda needed for the chips and the soda purchased, which is 40,000 ml + 6000 ml = 46,000 ml.To know more about volume, refer to the link below:
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There are 4 times as many chickens as ducks, there are 72 more chickens than ducks how many chickens and ducks are there
c = number of chickens
d = number of ducks
c = 4d because there are 4 times as many chickens as ducks
c = d+72 because there are 72 more chickens
4d = d+72 after using substitution
4d-d = 72
3d = 72
d = 72/3
d = 24
c = 4d = 4*24 = 96 ...or... c = d+72 = 24+72 = 96
Answer: There are 96 chickens and 24 ducksA boy cycles 5km from his home to school and 8km from his home to the market. The chief's camp is closer to the boys home than the market but further than the school. Write a compound inequality to show the distance from the boys home to the chief's camp.
A compound inequality to show the distance from the boys home to the chief's camp is 5 < d < 8
How to explain the inequalityThe distance from the boy's home to the school is 5km.
The distance from the boy's home to the market is 8km.
The chief's camp is closer to the boy's home than the market, but further than the school
The chief's camp is closer to the boy's home than the market, so the distance from the boy's home to the chief's camp is less than 8km.
Putting these together, we can write a compound inequality to show the possible distances d from the boy's home to the chief's camp:
distance from home to school < distance < home to maket
5 < d < 8
The inequality is 5 < d < 8.
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HELP
The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater maximum value, and provide the ordered pair.
Function 1
graph of function f of x equals negative x squared plus 8 multiplied by x minus 15
Function 2
f(x) = −x2 + 2x − 15
Function 1 has the larger maximum at (4, 1).
Function 1 has the larger maximum at (1, 4).
Function 2 has the larger maximum at (−14, 1).
Function 2 has the larger maximum at (1, −14).
The correct statement regarding the maximum values of the quadratic functions is given as follows:
Function 1 has the larger maximum at (4, 1).
How to obtain the maximum values?The standard definition of a quadratic function is given as follows:
y = ax² + bx + c.
The x-coordinate of the vertex of a quadratic function is given as follows:
x = -b/2a.
Hence, for each function, the x-coordinate of the vertex is given as follows:
Function 1: x = -8/-2 = 4.Function 2: x = -2/-2 = 1.Each function has a negative leading coefficient, hence the vertex represents a maximum value, and the y-coordinate is given as follows:
Function 1: f(4) = -(4)² + 8(4) - 15 = 1.Function 2: f(1) = -(1)² + 2(1) - 15 = -14.1 > -14, hence the correct statement is given as follows:
Function 1 has the larger maximum at (4, 1).
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Question content area top Part 1 Point B has coordinates (3,2). The x-coordinate of point A is −9. The distance between point A and point B is 15 units. What are the possible coordinates of point A
The possible coordinates of point A are (-9, -7) and (-9, 11).
What are coordinates?Coordinates refers to a set of numbers that are used to identify the position of a point in a space, usually defined by an x-axis, y-axis, and in sometimes a z-axis.
Let the y-coordinate of point A be y. Then the coordinates of point A are (-9, y).
Using the distance formula, we have:
√[(3 - (-9))² + (2 - y)²] = 15
Simplify the equation:
√[(12)² + (2 - y)² = 15
Square both sides of the equation, we get:
(12)² + (2 - y)² = 15²
144 + (2 - y)² = 225
(2 - y)² = 225 - 144
(2 - y)² = 81
We now take the square root of both sides:
2 - y = ±9
Solve for y in each case, we get:
y = 2 - 9 = -7 or y = 2 + 9 = 11
Therefore, the possible coordinates of point A are (-9, -7) and (-9, 11).
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Raymond wants to know the costs of buying different numbers of songs for his mp3 player. The cost of each song is the same.
To determine the cost of buying different numbers of songs for his mp3 player, Raymond needs to know the cost of a single song and the total number of songs he wants to buy, as well as consider bulk purchasing options like buying an album.
Assuming the cost of a single song is $1, if Raymond wants to buy 10 songs, the cost would be 10 x $1 = $10. Similarly, if Raymond wants to buy 20 songs, the cost would be 20 x $1 = $20. In general, the cost of buying n songs would be n x $1.
If the cost of a single song is not $1, then Raymond would need to adjust his calculations accordingly. For example, if the cost of a single song is $0.99, then the cost of buying 10 songs would be 10 x $0.99 = $9.90, and the cost of buying 20 songs would be 20 x $0.99 = $19.80.
Raymond could also consider purchasing songs in bulk, such as by buying an album, which typically offers a discounted price compared to purchasing individual songs. In this case, the cost of buying different numbers of songs would depend on the number of songs in the album and the cost of the album.
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Complete Question:
Raymond wants to know the costs of buying different numbers of songs for his MP3 player. The cost of each song is the same.
• Let s represent the possible number of songs Raymond could buy.
• Let d represent the amount of money, in dollars, Raymond would need to buy the songs.
Fill in the table for all missing values of s and d.
Number of songs, s
Amount of money ($), d
2
2.58
5.16
7
11
21.93
andy can run 20 miles in 6 hours. how much miles can he run in 1 hour.
I see that this is a rate of change time of problem
If andy can run 20 miles in 6 hours, than our goal is to find out how much he runs in a hour
So, we just have to divide 20 by 6.
It's sorta hard to explain
Questions?
Anyhow, the answer is around 3.3 miles per hour
Answer:
3.33 miles
Step-by-step explanation:
We Know
Andy can run 20 miles in 6 hours.
How many miles can he run in 1 hour?
We Take
20 / 6 ≈ 3.33 miles
So, Andy can run about 3.33 miles in 1 hour.
In a nuclear disaster, there are multiple dangerous radioactive isotopes that can be detected. If 91.9% of a particular isotope emitted during a disaster was still present 6 years after the disaster, find the continuous compound rate of decay of this isotope
The decay of isotope at compound rate is approximately 0.0140.
To find the continuous compound rate of decay of this isotope, we can use the following formula:
Nₜ = N₀e^(-λᵗ)
Where:
Nₜ is the amount of the isotope present after time t (years),
N₀ is the initial amount of the isotope,
λ is the continuous compound rate of decay, and
t is the time in years.
In this case, 91.9% of the isotope is still present 6 years after the disaster,
so Nₜ = 0.919 * N₀, and t = 6 years.
We want to find λ, the continuous compound rate of decay.
We can rewrite the formula as follows:
0.919 * N₀ = N₀ * e^(-λ * 6)
Divide both sides by N₀:
0.919 = e^(-λ * 6)
Now, take the natural logarithm (ln) of both sides:
ln(0.919) = -λ * 6
Divide by -6 to solve for λ:
λ = ln(0.919) / (-6)
Calculate the value:
λ ≈ 0.0140
So, the continuous compound rate of decay of this particular radioactive isotope is approximately 0.0140.
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What is -3x - 2x -5 = -7
Step-by-step explanation:
-3x - 2x - 5 = -7
-5x - 5 = -7
-5x = -7 + 5
-5x = -2
x = 2/5
#CMIIWThe am between two number exceeds their gm by 2 and the gm exceed the hm by 1.8 find the number
The unknown number x = (6.1 ± sqrt(6.
How to find the unknown numberLet's call the two numbers x and y.
We are given:
AM (Arithmetic Mean) between x and y exceeds their GM (Geometric Mean) by 2:
(x + y)/2 - sqrt(xy) = 2
GM between x and y exceeds their HM (Harmonic Mean) by 1.8:
sqrt(xy) - 2xy/(x+y) = 1.8
We can solve for one variable in terms of the other from the second equation and substitute into the first equation to solve for the remaining variable. Let's solve for y in terms of x from the second equation:
sqrt(xy) - 2xy/(x+y) = 1.8
sqrt(xy)(x+y) - 2xy = 1.8(x+y)
sqrt(xy)x + sqrt(xy)y - 2xy = 1.8x + 1.8y
sqrt(xy)(x+y-1.8) = 0.2x + 0.8y
x+y-1.8 = (0.2/0.8)sqrt(xy)(x+y-1.8)
x+y-1.8 = 0.25sqrt(xy)(x+y-1.8)
4x + 4y - 7.2 = sqrt(xy)(x+y)
Now we can substitute this expression for sqrt(xy)(x+y) into the first equation and solve for x:
(x + y)/2 - sqrt(xy) = 2
(x + y)/2 - (4x + 4y - 7.2)/4 = 2
2(x + y) - (4x + 4y - 7.2) = 8
12.2 = 2x + 2y
6.1 = x + y
Now we can substitute x + y = 6.1 into the expression we derived for sqrt(xy)(x+y) to solve for sqrt(xy):
4x + 4y - 7.2 = sqrt(xy)(x+y)
4x + 4y - 7.2 = sqrt(xy)(6.1)
sqrt(xy) = (4x + 4y - 7.2)/6.1
Finally, we can substitute both x + y = 6.1 and sqrt(xy) = (4x + 4y - 7.2)/6.1 into the equation sqrt(xy) - 2xy/(x+y) = 1.8 and solve for y:
sqrt(xy) - 2xy/(x+y) = 1.8
(4x + 4y - 7.2)/6.1 - 2xy/6.1 = 1.8
4x + 4y - 7.2 - 12.2xy = 11.38
4x + 4y - 11.38 = 12.2xy
4x + 4(6.1 - x) - 11.38 = 12.2xy (substituting x + y = 6.1)
xy = 4.08
Now we know that xy = 4.08, and we can use this to solve for x and y:
y = 6.1 - x
xy = 4.08
x(6.1 - x) = 4.08
6.1x - x^2 = 4.08
x^2 - 6.1x + 4.08 = 0
We can solve for x using the quadratic formula:
x = (6.1 ± sqrt(6.
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To the nearest cubic centimeter, what is the volume of the regular hexagonal prism?
a hexagonal prism has a height of 7 centimeters and a base with a side length of 3 centimeters. a line segment of length 2.6 centimeters connects a point at the center of the base to the midpoint of one of its sides, forming a right angle.
the volume of the regular hexagonal prism is about ___ cm3
Rounded to the nearest cubic centimeter, the volume of the regular hexagonal prism is approximately 82 [tex]cm^3.[/tex]
To calculate the volume of the regular hexagonal prism, we need to find the area of the base and multiply it by the height.
The base of the prism is a regular hexagon with side length 3 centimeters. The formula for the area of a regular hexagon is:
[tex]Area = (3√3/2) * (side length)^2.[/tex]
Substituting the given side length of 3 centimeters:
[tex]Area = (3√3/2) * 3^2[/tex]
= (3√3/2) * 9
= (27√3/2).
Now, let's calculate the volume by multiplying the base area by the height:
Volume = Area * height
= (27√3/2) * 7
≈ 81.729[tex]cm^3[/tex].
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What is the quotient of 223 + 3x2 + 5x – 4 divided by 22 +2+1?
Pls I need help
The quotient is -58x2 + 131x - 234 with a remainder of -5898.To solve this problem, we need to use long division. The dividend is 223 + 3x2 + 5x - 4 and the divisor is 22 + 2 + 1, which simplifies to 25.
We start by dividing 2 into 22, which gives us 11. We then write 11 above the 2 and multiply it by 25, which gives us 275. We subtract 275 from 223, which gives us -52. We bring down the 3, which gives us -523. We then repeat the process by dividing 2 into 52, which gives us 26. We write 26 above the 5 and multiply it by 25, which gives us 650. We subtract 650 from -523, which gives us -1173. We bring down the 1, which gives us -11731. We divide 2 into 117, which gives us 58.
We write 58 above the x and multiply it by 25, which gives us 1450. We subtract 1450 from -1173, which gives us -2623. We bring down the -4, which gives us -26234. We divide 2 into 262, which gives us 131. We write 131 above the 5 and multiply it by 25, which gives us 3275. We subtract 3275 from -2623, which gives us -5898. Therefore, the quotient is -58x2 + 131x - 234 with a remainder of -5898.
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The number of bacteria in a certain colony doubles every 5 days. At the same rate, how long will the colony need to triple in number?
The colony will need to triple in number after about 7.58 days.
How to find the number of bacteria in a certain colony?Since the number of bacteria doubles every 5 days, we can write the relationship between the number of bacteria and time as an exponential function:
N(t) = N0 x 2^(t/5)
where N0 is the initial number of bacteria and t is the time in days.
To find out how long it will take for the colony to triple in number, we need to solve the equation:
N(t) = 3N0
Substituting the expression for N(t) from above, we get:
N0 x 2^(t/5) = 3N0
Dividing both sides by N0, we get:
2^(t/5) = 3
Taking the logarithm of both sides (with base 2) gives:
t/5 = log2(3)
Multiplying both sides by 5, we get:
t = 5 x log2(3)
Using a calculator or a computer program to evaluate the logarithm, we get:
t ≈ 7.58
Therefore, the colony will need to triple in number after about 7.58 days.
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I need help with this and I need it in 30 minutes please
The missing value in the frequency table from the electronics manufacturers would be 150.
How to find the frequency ?The class interval of the battery life is in fives which means that between 25 and 30, the shaded region on the histogram would represent 28 ≤ x < 30.
Looking at the y axis, we can tell that the class interval is 50 thanks to the 120 achieved by 15 ≤ x < 20. This then means that as 28 ≤ x < 30 is sitting on the third y interval, we know that it has a value of 150.
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find the coordinates of p so that p partitions the segment of AB in the ratio 7 to 2 if A( -5,4) and B( -8,-2)
The coordinates of p so that p partitions the segment of AB in the ratio 7 to 2 if A( -5,4) and B( -8,-2) is P(x, y) = [-22/3, -2/3].
How to determine the coordinates of point P?In this scenario, line ratio would be used to determine the coordinates of the point P on the directed line segment that partitions the segment into a ratio of 1 to 4.
In Mathematics and Geometry, line ratio can be used to determine the coordinates of P and this is modeled by this mathematical equation:
P(x, y) = [(mx₂ + nx₁)/(m + n)], [(my₂ + ny₁)/(m + n)]
By substituting the given parameters into the formula for line ratio, we have;
P(x, y) = [(mx₂ + nx₁)/(m + n)], [(my₂ + ny₁)/(m + n)]
P(x, y) = [(7(-8) + 2(-5))/(7 + 2)], [(7(-2) + 2(4))/(7 + 2)]
P(x, y) = [(-56 - 10)/(9)], [(-14 + 8)/9]
P(x, y) = [-66/9], [(-6)/(9)]
P(x, y) = [-22/3, -2/3]
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The table gives a set of outcomes and their probabilities. Let a be the event "the outcome is a divisor of 4". Let b be the event "the outcome is prime". Find p(a|b)
The probability that the outcome is a divisor of 4 given that it is prime is 0.125, or 12.5%.
Since we are given the probabilities of different outcomes, we can use the definition of conditional probability to find p(a|b), which represents the probability that the outcome is a divisor of 4 given that it is prime.
The formula for conditional probability is:
p(a|b) = p(a ∩ b) / p(b)
where p(a ∩ b) represents the probability of both events happening simultaneously.
Looking at the table of outcomes and their probabilities, we can see that there are four prime numbers: 2, 3, 5, and 7. Of these, only 2 is a divisor of 4.
Therefore, p(a ∩ b) is the probability that the outcome is 2, which is 0.1.
The probability of the outcome being prime is the sum of the probabilities of the four prime outcomes, which is:
p(b) = 0.1 + 0.2 + 0.3 + 0.2 = 0.8
Substituting these values into the formula for conditional probability, we get:
p(a|b) = p(a ∩ b) / p(b) = 0.1 / 0.8 = 0.125
Therefore, the probability that the outcome is a divisor of 4 given that it is prime is 0.125, or 12.5%.
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a professor gives his students 6 essay questions to prepare for an exam. only 4 of the questions will actually appear on the exam. how many different exams are possible?
The different possible exams for the 6 essay questions from which only 4 appear is equal to 15.
n is the total number of items in the set = 6 essay questions
r is the number of items we want to choose = 4 questions
Using combinations,
which is a way of counting the number of ways to choose a certain number of items from a larger set without regard to order.
Choose 4 out of the 6 essay questions, without regard to the order in which they appear on the exam.
Use the formula for combinations,
C(n, r) = n! / (r! × (n - r)!)
Plugging in the values, we get,
⇒C(6, 4) = 6! / (4! × (6 - 4)!)
⇒C(6, 4) = 6! / (4! ×2!)
⇒C(6, 4) = (6 × 5 × 4 × 3) / (4 × 3 × 2 × 1)
⇒C(6, 4) = 15
Therefore, there are 15 different exams possible, each consisting of 4 out of the 6 essay questions provided by the professor.
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50 POINTS: In terms of the number of marked mountain goats, what is the relative frequency for male goats, female goats, adult goats, and baby goats? Write your answers as simplified fractions.
Male 71
Female 93
Adult 103
Baby 61
To calculate the relative frequency for each category, divide the number of marked mountain goats in each category by the total number of marked mountain goats.
Total marked mountain goats = 71 (male) + 93 (female) = 164
Total marked mountain goats = 103 (adult) + 61 (baby) = 164
Relative frequency for male goats = Male goats / Total marked mountain goats = 71/164
Relative frequency for female goats = Female goats / Total marked mountain goats = 93/164
Relative frequency for adult goats = Adult goats / Total marked mountain goats = 103/164
Relative frequency for baby goats = Baby goats / Total marked mountain goats = 61/164
Your answer:
Relative frequency for male goats = 71/164
Relative frequency for female goats = 93/164
Relative frequency for adult goats = 103/164
Relative frequency for baby goats = 61/164
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Brooke bought a condominium for $413,600. She made a 9% down payment and financed the remaining amount using a 25-year fixed-rate mortgage at 5. 2%. The monthly payment is $2,244. Brooke will pay for one discount point, a 0. 75% origination fee, the brokerage fee, state documentary taxes on the deed and the mortgage, and the intangible tax. • Discount points equal 1% of the mortgage amount. Documentary stamp tax on deed is $0. 70 per $100 or portion thereof. • Documentary stamp tax on mortgage is $0. 35 per $100 or portion thereof. • Mortgage broker fee is $175 plus 5% of the mortgage amount. • Intangible tax is 0. 2% of the mortgage amount. What is the total amount of the principal, interest, down payment, and fees described for Brooke's condominium? (4 points) $743,687. 00 $807,569. 73 $481,369. 73 $740,969. 73
The total amount of the principal, interest, down payment, and fees described for Brooke's condominium is $1,154,091.59
Find out the total amount of the principal and interest down payment, and fees?The first step is to calculate the mortgage amount, which is the purchase price minus the down payment:
Mortgage amount = $413,600 - 9% of $413,600 = $376,576
Next, we need to calculate the total cost of the fees and charges:
Discount points = 1% of $376,576 = $3,766
Origination fee = 0.75% of $376,576 = $2,823.42
Documentary stamp tax on deed = $0.70 per $100 or portion thereof, so for $413,600 it would be:
$0.70 * ($413,600 / $100) = $2,895.20
Documentary stamp tax on mortgage = $0.35 per $100 or portion thereof, so for $376,576 it would be:
$0.35 * ($376,576 / $100) = $1,318.02
Brokerage fee = $175 + 5% of $376,576 = $19411.8
Intangible tax = 0.2% of $376,576 = $753.15
Now we can calculate the total cost of the principal and interest payments over the life of the mortgage. We'll use a mortgage calculator to do this, based on the mortgage amount, interest rate, and term:
Total mortgage payments = $2,244 * 12 months * 25 years = $673,200
Finally, we can add up all of these amounts to get the total cost of the principal, interest, down payment, and fees:
Total cost = Purchase price + Down payment + Mortgage payments + Discount points + Origination fee + Documentary stamp tax on deed + Documentary stamp tax on mortgage + Brokerage fee + Intangible tax
Total cost = $413,600 + $37,224 + $673,200 + $3,766 + $2,823.42 + $2,895.20 + $1,318.02 + $19,411.80 + $753.15
Total cost = $1,154,091.59
Therefore, we got a total cost of $1,154,091.59
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PLEASE HELP
Which inequality is true?
A number line going from negative 3 to positive 3 in increments of 1.
One-fourth less-than negative 1 and StartFraction 2 Over 4 EndFraction
Negative 2 and three-fourths less-than negative 1 and one-half
Negative 2 and one-fourth greater-than negative 1 and one-fourth
Negative three-fourths greater-than 1 and three-fourths
The inequality that is true is Negative 2 and three-fourths less-than negative 1 and one-half.
How to find the true inequality ?The first inequality from the number line can be shown to be :
( 1 / 4 ) < - 1 1 / 2
This is not possible as a negative cannot be larger than a positive.
The second inequality is:
- 2. 75 < - 1. 5
This is true as larger negative numbers are lower than smaller negative numbers.
The third inequality is:
- 2. 25 > - 1. 25
This is not possible for the reason explained.
In conclusion, option B is correct.
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MARKING BRAINLEIST IF CORRECT PLS ANSWER ASAP
Answer:
7.6 cm
Step-by-step explanation:
[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]
[tex]a^{2}[/tex] + [tex]6.5^{2}[/tex] = [tex]10^{2}[/tex]
[tex]a^{2}[/tex] + 42.25 = 100 Subtract 42.25 from both sides
[tex]a^{2}[/tex] = 57.57
[tex]\sqrt{\a^{a} }[/tex] = [tex]\sqrt{57.57}[/tex]
a ≈ 7.6
Helping in the name of Jesus.
Answer:
7.6 cm
Step-by-step explanation:
a^2+ b^2=c^2
a^2+6.5^2=10^2
a^2+42.25=100 subtract 42.25 from both sides
a^2=57.57
a=√57.57
a=7.6 cm
To conduct a science experiment, it is required to decrease the temperature from 36 c at the rate of 4 c every hour. what will be the temperature 10 hours after the process begins?
To conduct the science experiment, the temperature needs to be decreased from 36°C at a rate of 4°C every hour.
So, after 1 hour, the temperature will be 36°C - 4°C = 32°C. After 2 hours, the temperature will be 32°C - 4°C = 28°C. Continuing this pattern, after 10 hours, the temperature will be 36°C - (4°C x 10) = 36°C - 40°C = -4°C.
However, this temperature is below freezing and unlikely to be accurate for a science experiment.
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The volume of a cone is 45.3 cubic cm. B=40 Find the height.
The height of the cone is 3.4cm
What is volume of cone?A cone is a shape formed by using a set of line segments or the lines which connects a common point, called the apex or vertex.
The volume of a cone is expressed as;
V = 1/3 πr²h
where πr² = base area. therefore the volume can be written as;
V = 1/3 base area × height
base area = 49cm²
height = 45.3 cm³
45 = 1/3 ×40h
135 = 40h
h = 135/40
h = 3.4cm
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Chris bought 5 tacos and 2 burritos for $13. 25.
Brett bought 3 tacos and 2 burritos for $10. 75.
The price of one taco is $
The price of one burrito is $
If Chris bought 5 tacos and 2 burritos for $13. 25 and Brett bought 3 tacos and 2 burritos for $10. 75, the price of one taco is $1.25, and the price of one burrito is $3.50.
Let the price of one taco be T and the price of one burrito be B. We have the following equations:
5T + 2B = $13.25
3T + 2B = $10.75
To find the prices of the taco and the burrito, we can use the system of equations. First, subtract the second equation from the first equation:
(5T + 2B) - (3T + 2B) = $13.25 - $10.75
2T = $2.50
Now, divide by 2 to find the price of one taco:
T = $1.25
Next, plug the value of T back into one of the equations (let's use the second equation):
3($1.25) + 2B = $10.75
$3.75 + 2B = $10.75
Now, subtract $3.75 from both sides:
2B = $7.00
Finally, divide by 2 to find the price of one burrito:
B = $3.50
So, the price of one taco is $1.25, and the price of one burrito is $3.50.
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When angela and walker first started working for the supermarket, their weekly salaries totaled $550. now during the last 25 years walker has seen his weekly salary triple angela has seen her weekly salary become four times larger. together their weekly salaries now total $2000. write an algebraic equation for the problem. how much did they each make 25 years ago?
Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.
Let's assign variables to represent Angela and Walker's salaries 25 years ago. Let A be Angela's salary 25 years ago and W be Walker's salary 25 years ago.
Using the information given in the problem, we can set up two equations:
A + W = 550 (their total salary 25 years ago)
4A + 3W = 2000 (their total current salary)
To solve for A and W, we can use substitution or elimination. Let's use substitution.
From the first equation, we can rearrange to solve for A:
A = 550 - W
Substitute this into the second equation:
4(550 - W) + 3W = 2000
Distribute the 4:
2200 - 4W + 3W = 2000
Simplify:
W = 800
Now that we know Walker's salary 25 years ago was $800, we can plug that into the first equation to solve for Angela's salary:
A + 800 = 550
A = -250
Uh oh, a negative salary doesn't make sense in this context. We made a mistake somewhere.
Let's go back to our original equations and try elimination instead:
A + W = 550
4A + 3W = 2000
Multiplying the first equation by 4, we get:
4A + 4W = 2200
Subtracting the second equation from this, we get:
W = 200
Now we can plug this into either equation to solve for A:
A + 200 = 550
A = 350
So Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.
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