AC and BD are perpendicular bisectors of each other. Find the perimeter of ADB.

A. 60
B. 52
C. 30
D. 50

The expression that can be used to find the perimeter of the rectangle is 62 centimeters 2(5x−2)+2(3x+1).

The perimeter of the rectangle is equal to the 2 times sum of the length and width of the rectangle.

Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper.

The expression that can be used to find the perimeter of the rectangle is given by;

[tex]\rm Perimeter \ of \ rectangle = 2 (length +width)\\\\\rm Perimeter \ of \ rectangle = 2 (5x-2+3x+1)\\\\ \rm Perimeter \ of \ rectangle = 2 (7x-1)\\\\ \rm Perimeter \ of \ rectangle = 16x-2\\\\When , x\ =\ 4\\\\ \rm Perimeter \ of \ rectangle = 14x-2\ = 16(4)-2\ =\ 64-2\ =\ 62\\[/tex]

Hence, the expression that can be used to find the perimeter of the rectangle is 62 centimeters 2(5x−2)+2(3x+1).

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Answer:

The answer is (A.)

Step-by-step explanation:

Answer: A on edge 22

Step-by-step explanation:

Answer:

9/13

Step-by-step explanation:

Total = 9 + 4

= 13

Probability: 9/13

[tex]\\ \rm\Rrightarrow (-3\dfrac{1}{3})^2[/tex]

[tex]\\ \rm\Rrightarrow (\dfrac{-10}{3})^2[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{(-10)^2}{3^2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{100}{9}[/tex]

[tex]\\ \rm\Rrightarrow 11\dfrac{1}{9}[/tex]

Answer:

100/9 (or) 11 1/9

Step-by-step explanation:

Q) (-3 1/3)² = ?

→ (-3 1/3)²

→ (-10/3)²

→ 100/9

→ [ 11 1/9 ]

Hence, the solution is 11 1/9.

Answer:

21sqrt(6)

Step-by-step explanation:

Hope it helps......

Answer:

Lateral surface area=perimeter×Height

Total surface area=Perimeter (p)×Height(h)+2×Area of cross section

The only true statement that compares the two functions is:

B: The solution to f(x)=g(x) is 1

Here we have the functions:

f(x) = |x - 3| + 1

g(x) = 2x + 1

First, let's find the solution for:

f(x) = g(x)

|x - 3| + 1 = 2x + 1

|x - 3| = 2x

Notice that we have two options, x = 3:

|3 - 3| = 2*3

0 = 6  (x = 3 is not a solution)

And x = 1:

|1 - 3| = 2*1

2 = 2  (x = 1 is a solution).

Now to get the y-value where the graphs intersect, we just evaluate one of the functions in the solution we found above;

f(1) = |1 - 3| + 1  = 2 + 1 = 3

The graphs intersect when y = 3.

Then we conclude that the only true statement is:

B: The solution to f(x)=g(x) is 1

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Answer:

X.

10, 20, 30, 40, 50, 60

Add them:

10 + 20 + 30 + 40 + 50 + 60

= 210

Then divide that sum by the many numbers there are, and there are 6 numbers in which we added.

210 ÷ 6

= 35, the mean for this is 35.

F.

4, 5, 6, 2, 3, 5

Add them:

4 + 5 + 6 + 2 + 3 + 5

= 25

Then divide that sum by the many numbers there are, and there are 6 numbers in which we added.

25 ÷ 6

= 4.1666..., the mean for this is 4.17.

We are given the function to differentiate:

[tex]{\quad \qquad \sf \rightarrow y=x^{e^x}}[/tex]

Do take natural log on both sides, then we will be having

[tex]{:\implies \quad \sf ln(y)=ln(x^{e^{x}})}[/tex]

[tex]{:\implies \quad \sf ln(y)=e^{x}ln(x)\quad \qquad \{\because ln(a^b)=bln(a)\}}[/tex]

Now, differentiate both sides by using so called chain rule and the product rule

[tex]{:\implies \quad \sf \dfrac{1}{y}\dfrac{dy}{dx}=e^{x}ln(x)+\dfrac{e^x}{x}}[/tex]

[tex]{:\implies \quad \boxed{\bf{\dfrac{dy}{dx}=x^{e^x}\bigg\{\dfrac{e^x}{x}+ln(x)e^{x}\bigg\}}}}[/tex]

Hence, Option B) is correct

Product rule of differentiation:

Where, u and v are functions of x

Answer:

- 43

Step-by-step explanation:

f ( x ) = - 2x² + 2x - 3

To find : f ( 5 )

f ( 5 ) = f ( x )

Here,

x = 5

f ( 5 ) = - 2x² + 2x - 3

        = - 2 ( 5 )² + 2 ( 5 ) - 3

        = - 2 ( 25 ) + 10 - 3

        = - 50 + 7

f ( 5 ) = - 43

Answer:

-43

Step-by-step explanation:

oon edge

mark me brain

Interest be I

Total:-

The volume of the post = volume of rectangular prism - volume of cylindrical hole = 3,223.0 cm³.

Volume = (l)(w)(h)

Volume = πr²h

Volume of the post = volume of rectangular prism - volume of cylindrical hole

= (l)(w)(h) - πr²h

= (10)(12)(30) - π(2²)(30)

Volume of the post = 3,223.0 cm³

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The expressions are equivalent.

[tex] \sqrt{ \frac{2x}{9} } = \frac{ \sqrt{2x} }{ \sqrt{9} } = \frac{ \sqrt{2x} }{3} = \frac{1}{3} \sqrt{2x} \\ [/tex]

Answer:

Around 295m

Step-by-step explanation:

Answer:

295.44 m to the neaest hundredth

Step-by-step explanation:

A line drawn from the kite  perpendicular to the ground forms 2 right triangles. Let this  line be x m.

Also let y be the distance from Allison to the bottom of the line.

Consider 'Alison' triangle

cos 70 = y/150

y = 51.303 m

sin 70 = x/150

x = 150 sin 70 = 140.954 m

Consider 'Marcs' triangle

tan 30 = x / (AM - y)

tan 30 = 140.954 / (AM - 51.303)

AM - 51.303 =  140.954/tan 30

AM =  140.954/tan 30 + 51.303

AM = 295.442  m

Answer:

B

Step-by-step explanation:

please mark brainliest

Answer:

Question 16: 44 inches

Question 18: 10, 24, 26

Step-by-step explanation:

Question 16:

Pythagoras Theorem: c^2 = a^2 + b^2, where c is the hypotenuse and the longest side.

125^2 = 117^2 + b^2

15,625 = 13,689 + b^2

15,625 - 13689 = b^2

1936 = b^2

√1936 = b

44 = b

Question 18:

Pythagoras Theorem: c^2 = a^2 + b^2, where c is the hypotenuse and the longest side. You have to try all the possibilities. The ones that match are the lengths.

The answers are 10, 24, 26

c^2 = a^2 + b^2

26^2 = 10^2 + 24^2

676 = 100 + 576

676 = 676

Answer:

[tex]\bf Area= 90\;in[/tex]

Step-by-step explanation:

Area of ABCD = L * W

[tex]\bf 6\times 12[/tex]

[tex]\bf 72 \;in^2[/tex]

Area of EFGC:- L * W

[tex]\bf 6 \times 3[/tex]

[tex]\bf 18\; in^2[/tex]

Now, the area of the combind rectangles:-

ABCD + EFGC

[tex]\bf 72+18[/tex]

[tex]\boxed{\bf 90\; in}[/tex]

Answer:

x < 16

Step-by-step explanation:

∣x−7∣ < 9

x < 9 + 7

x < 16

Answer:

7x < 9

Step-by-step explanation:

because the absolute value of -7 is 7 and 7 + x = 7x.

I belive the correct answer would be A because if M and N are the signatures it would make sense to add them. Multiply the signatures by the days, and you have your self an equation. So because we added the first two... Nikkis's petition is still the same so we would have to add hers to M again leaving you with the equation of A.

Hope this helps :)

Answer:

4 sets

Step-by-step explanation:

16 + 17 + 18 = 51

17 + 18 + 19 = 54

18 + 19 + 20 = 57

19 + 20 +21 = 60

Volume of cylinder,=πr²h

(22÷7)×5²×3

3.14×25×3

235.5

Answer :

235.5 units³

Answer:

D

Step-by-step explanation:

for 20 pounds of grass seed, we need 356 pounds of fertilizer

20 pounds of grass seed : 356 pounds of fertilizer

divide both sides by 20 to get 1 pound of grass seed on one side, as we want to figure out the corresponding amount of fertilizer for 1 pound of grass seed

20 pounds of grass seed/20 : 356 pounds of fertilizer/20

1 pound of grass seed: 17.8 pounds of fertilizer

Answer:

x = 16

Step-by-step explanation:

3√x = x - 4

Raise the equation to the second power.

(3√x)² = (x - 4)²

9x = x² - 8x + 16

Rewrite the equation with the values on the left.

-x² + 17x - 16 = 0

x² - 17x + 16 = 0

Factor.

(x - 16)(x - 1) = 0

Set each part equal to 0.

x - 16 = 0

x = 16

x - 1 = 0

x = 1

Your solutions are 16 and 1, but it doesn't end there. Both of these may not satisfy the original equation, so plug them back in.

3√x = x - 4

3√16 = 16 - 4

3(4) = 12

12 = 2

16 is a solution.

3√x = x - 4

3√1 = 1 - 4

3(1) = -3

3 ≠ -3

1 is NOT a solution.

Answer:

c. 4,250.00

Step-by-step explanation:

The initial deposit amount is $4,250.00.

A quick and easy method of calculating the interest charge on a loan is called a Simple interest.

Given that,

The worth of an investment is $6774.50

The time period is 22 years.

The rate of interest is 2.7%.

Now, Based on the above information, the calculation is as follows:

We know that;

SI = P x r x t

SI = P x 2.7% x 22

SI = 0.594P

Now,

Investment worth = P  + SI

= P + 0.594P

= 1.594P  

So, we get;

1.594P  = 6774.50

P  = $4,250  

Therefore, we can conclude that the initial deposit amount is,

⇒ $4,250.00

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#SPJ5

So, before solving further, let's recall that, a deck of card have 52 cards, with 26 black cards, and 26 red cards, out of which, let's first consider red cards,so 13 of 26 are heart, and the other 13 out of 26 is diamond, now let's consider the black cards, so 13 of 26 black cards are spades and the other 13 out of 26 black cards are clubs, every type have an ace card, and 9 cards numbering from 2-10 and three face cards naming, queen, king and Jack. And the probability of any event is defined as the ratio of no. of favourable outcomes to Total no. of possible outcomes, so let's stary solving all the parts one by one :

7) [tex]{:\implies \quad \sf P(Red\:\:card)=\dfrac{26}{52}}[/tex]

[tex]{:\implies \quad \boxed{\bf{P(Red\:\:card)=\dfrac12}}}[/tex]

8) [tex]{:\implies \quad \sf P(Jack\:\:of\:\:diamonds)=\dfrac{1}{52}}[/tex]

[tex]{:\implies \quad \boxed{\bf{P(Jack\:\:of\:\:diamonds)=\dfrac{1}{52}}}}[/tex]

9) [tex]{:\implies \quad \sf P(Ace)=\dfrac{4}{52}}[/tex]

[tex]{:\implies \quad \boxed{\bf{P(Ace)=\dfrac{1}{13}}}}[/tex]

10) [tex]{:\implies \quad \sf P(A\:\:black\:\:10)=\dfrac{2}{52}}[/tex]

[tex]{:\implies \quad \boxed{\bf{P(A\:\:black\:\:10)=\dfrac{1}{26}}}}[/tex]

11) [tex]{:\implies \quad \sf P(A\:\:heart)=\dfrac{13}{52}}[/tex]

[tex]{:\implies \quad \boxed{\bf{P(A\:\:heart)=\dfrac14}}}[/tex]

12) [tex]{:\implies \quad \sf P(Not\:\:a\:\:club)=\dfrac{39}{52}}[/tex]

[tex]{:\implies \quad \boxed{\bf{P(Not\:\:a\:\:club)=\dfrac34}}}[/tex]

Answer:

32.24

Step-by-step explanation:

To get the height, use Pythagoras theorem on the smaller triangle

8^2=2^2+x^2

x^2=64-4

x=√60=2√15.

then for the base use P.T for the bigger triangle

10^2=y^2+√60^2

y^2=100-60

y=√40=2√10

1/2×(2√10+2)×2√15

=32.24

Answer:

$1.95 for 5kg

Step-by-step explanation:

0.96 x2 is 1.92 and not even 5kg so if you get 5kg worth of the 0.96$ per kg then it will be more expensive.

So $1.95 for 5kg is the better deal.

Answer:

Volume of prism = Area of base× height

= l×b×h

=4.8×23×0.9

= 99.36 m³

All options are incorrect : )

Answer:

The answer is B

Step-by-step explanation:

Im 3 weeks late lol sorry. I took the quiz.