The supplied tuning fork has a frequency of 262Hz.
A recurring event's frequency is measured by how many times it occurs in a unit of time. To emphasize distinctions with spatial and angular frequencies, respectively, it is also sometimes referred to as ordinary frequency or temporal frequency.
Additionally, it is claimed that when it is played on a mandolin, four beats can be heard every second.
Together, the beats produced by a vibrating mandolin string and tuning fork are referred to as beat frequencies.
Frequency of beat= Frequency of tuning fork + Frequency of mandolin string
Given that a tuning fork's frequency is 262 Hz
String frequency equals 4 beats per second (4Hz).
Therefore, Frequency of beat = 262Hz +4 Hz = 266Hz
Hence, the correct answer for the given question is option (D) 266Hz
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When two mechanical waves interact and their crests line up, they create constructive interference. True or False?
Pls do these for me asap
Answer:
Look below!
Explanation:
1) Observation
2) Hypothesis
3) Results
4) Experiment
5) Problem
6) Conclusion
7) Inference
M A particle with positive charge q = 3.20 ×10⁻¹⁹C moves with a velocity →v = (2i + 3j - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (b) What angle does the force vector make with the positive x axis?
The Magnitude of force on the charged particle is -
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
We have a positively charged particle that moves through a region where both a uniform magnetic field and a uniform electric field exist.
What is Lorentz Force?The force exerted on a charged particle (q) moving with velocity (v) through an Electric field (E) and Magnetic field (B) is called Lorentz force.
Mathematically -
|F| = qE + qv x B
According to the question, we have -
q = 3.20 × 10⁻¹⁹C
v = (2i + 3j - k) m/s
B = (2i + 4j + k) T
E = (4i - j - 2k) V
Now, using the formula to calculate Lorentz force -
F = q(4i - j - 2k) + q(2i + 3j - k) x (2i + 4j + k)
F = q(4i - j - 2k) + (2qi + 3qj - qk) x ((2i + 4j + k)
F = q(4i - j - 2k) + 0
F = q(4i - j - 2k)
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
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Question 17 (2 points)
A delivery man is told to go 60 miles per hour north to make his delivery on time. These instructions describe the delivery man's (2 points)
a
speed
velocity
ОБ
OC
Od magnitude
acceleration
The correct answer is velocity.
The vector measure of level and direction of motion is known as velocity. The speed at which an object goes in one direction is known as its velocity. Speed may be used to calculate both the speed of the car traveling north on the major highway and the speed of the rocket bursting in space. As you may expect, the vector velocity's scalar size (total value) corresponds to the movement's speed. Speed is the initial exit of a place in terms of time when it comes to computations. A straightforward formula that incorporates measurement, distance, and time can be used to determine speed.
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A representation of a chemical reaction that uses symbols to show the relationship between the reactants and the products is called a __________. a. symbolic statement b. chemical equation c. mole ratio d. chemical proportion
Answer:
B. chemical equation.
Explanation:
This explained to be a short method of representing different symbols and structures that are seen to make up a chemical reaction. It is known to have been formulated by a French chemist Jean Beguin. In a course of writing a chemical reaction, its reaction is seen to show a starting compound which is been written on the left hand side of the said equation while the product is written by the right hand side and are separated in different directions by an arrow. When this is done, charges on this equation that is balanced is also written on each side of the equation.
Which form of heat transfer transfers both matter(particles) and energy?
Conduction
Convection
Radiation
None of these
as you walk to the grocery store you walk 800m north, 600m east and 200m south at a speed of 1m/s. what is your velocity?
According to the question as you walk to the grocery store you walk 800m north, 600m east, and 200m south at a speed of 1m/s. Then your velocity will be ( V = 0.5m/sec )
Velocity is the directional pace of an object in movement as an indication of its price of alternate in function as located from a specific body of reference and as measured by a particular widespread of time.
To find the velocity follow the following steps:
Displacement of 800m north, 600m east, and 200m south from the Cartesian coordination is given as 600[tex]\sqrt{2}[/tex]
Velocity = displacement / time
Therefore time = distance / speed
Time = 800 + 600 + 200 / 1
Time = 1600s
Therefore velocity = 600[tex]\sqrt{2}[/tex] / 1600
Velocity = 0.5m/sec
A Cartesian coordinate gadget in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates, which are the signed distances to the factor from constant perpendicular oriented strains, measured in the equal unit of duration.
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julie drives 100 mimi to grandmother's house. on the way to grandmother's, julie drives half the distance at 34.0 mphmph and half the distance at 66.0 mphmph . on her return trip, she drives half the time at 34.0 mphmph and half the time at 66.0 mphmph .
The average speed is r=50 mph
What is speed?Teenagers, young adults, and others use the stimulant medication known as "speed" to feel more focused and alert, and occasionally to get euphoric. Several types of speed are also used by some people to suppress their appetite. Different speed types include: Amphetamines (used to treat ADHD, narcolepsy, and depression)
In essence, an object's speed indicates how quickly it is moving. Its velocity reveals how quickly it is moving in a specific direction. In your daily life, you utilize speed measures, but in physics, velocity measurements are more frequently used.
distance=rate*time
total distance=rate*total time
to Grandmother's...
50=34*t
50/34=t
t=25/17 hours for the first 50 miles
50=66*t
50/66=t
t=25/33 hours for the second 50 miles
total distance=50+50=100 miles
total time=25/17+25/33
total time=(825/561)+(425/561)=1250/561 hours
total distance=rate*total time
100=r*(1250/561)
r=(100)(561/1250)
r=56,100/1250
r=5610/125
r=1122/25
r=44.88 mph is the average speed (rounded it is 44.9 mph)
Note: If you are familiar with the simplified form of the harmonic mean you can solve the problem that way. If not, that's okay. You can look it up if you like.
(2*34*66)/(34+66)=4488/100=44.88 again
from Grandmother's house...
because the times are the same you simply add the 2 rates and divide by 2
(34+66)/2=100/2=50 mph is the average speed
d=r*t
100=34*t+66*t (the times are the same, t)
100=100*t
t=1 hour traveling at 34 mph and 1 hour traveling at 66 mph for a total of 2 hours traveling
d=r*t
100=r*2
r=100/2
r=50 mph is the average speed
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HELPPP!!! During a soccer game, a player kicks the winning goal. When is work being done by the player?
A) when the ball flies through the air
B) when the player moves toward the ball
C) when the player’s foot is in contact with the ball
D) when the player’s foot continues to move after touching the ball
Answer:
when the player’s foot is in contact with the ball
Explanation:
QC Two waves simultaneously present on a long string have a phase difference π between them so that a standing wave formed from their combination is described by
y(x,t) = 2Asin( kx + π/2 ) cos( ωt - π/2) (a) Despite the presence of the phase angle π, is it still true that the nodes are one-half wavelength apart? Explain.
The equation of motion of the standing wave, y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2), indicates that it is still true that the nodes are one half the wavelength apart
Therefore;
It is still true that the nodes are one half the wavelength apart What are the nature of standing wave?The equation describing the standing wave formed by the two waves is y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2)
A standing wave is formed when two waves that have equal amplitude and frequency and moving in opposite directions, are combined.
A standing wave can be formed by a wave and its reflection, resulting in a wave where there is no propagation of particles beyond the vibration region.
The fundamental frequency of a standing wave consists of two nodes and an antinode.
The wavelength is the distance between two peaks of one wave, such that two nodes are formed within the span of a wavelength, which makes the distance between nodes being half the wavelength of the wave.
Therefore;
It is still true that the nodes are one half the wavelength apart.
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A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops at a time of 0.5 seconds. What is the force on the car?
Answer:
The force = F = -40000 N
Explanation:
Mass m = 1000 kg speed v₁ = 20 m/s speed v₂ = 0 m/s t = 0.5We know that,
Calculating the acceleration
using the formula
a = (v₂ - v₁) / t
= 0 - 20 / 0.5
= -20 / 0.5
= -40 ms⁻²
Thus, acceleration (deceleration) = a = -40 ms⁻²
Note: negative sign gives us an idea the car is slowing down after a collision with the barrier, thus acceleration and velocity are in opposite direction.
We know that
F = ma
= 1000 × -40
= -40000 N
Thus, the force = F = -40000 N
A box moves 5m horizontally when force F=10N is applied at an angle 0=30°.
What is the work done?
please help and show your work if you can
Answer:
43.3J
Explanation:
Given parameters:
Force = 10N
Distance = 5m
Angle = 30°
Unknown:
Work done = ?
Solution:
Work done is the force applied to move a body through a particular distance;
Work done = Force x distance cos Ф
Now insert the parameters and solve;
Work done = 10 x 5 cos 30 = 43.3J
What change would occur if Earth's rate of rotation significantly increased?
a. The day would be longer.
b. The day would be shorter.
c. The year would be longer.
d. The year would be shorter.
Answer:the answer is B The day would be Shorter .
Explanation:its correct I got it right hope this help .
The change that would occur if Earth's rate of rotation significantly increased is that the day would be shorter. The correct option is b.
What is Earth's rotation?The rotation or spin of the Earth is the rotation of the planet Earth around its own axis, as well as changes in the orientation of the rotation axis in space. Earth rotates counterclockwise as seen from the northern polar star Polaris.
Earth rotates because the sun attracts the earth and thus pulls it towards it, and because the earth's revolution around the sun causes it to move away from the sun in the direction of the tangent, causing a rotational force (torque) to act on the earth, causing it to rotate.
The Earth rotates once every 24 hours in relation to the Sun, but once every 23 hours, 56 minutes, and 4 seconds in relation to other distant stars. Because the Earth's rotation slows slightly over time, a day used to be shorter.
Thus, the correct option is b.
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A plane flew for 2 hours at 467 mph and 5 hours at 536 mph how far did the plane fly in miles?
Answer:
3614
Explanation:
A flywheel has a radius of 20. 0cm.What is the speed of a point on the edge of
the flywheel if it experiences a centripetal acceleration of 900.0cm/s 2 ?
Given that,
The radius of a flywheel, r = 20 cm = 0.2 m
The centripetal acceleration experienced on the edge of the flywheel = 900 cm/s² = 9 m/s²
To find,
The speed of a point on the edge.
Solution,
The formula for the centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{9\times 0.2} \\\\=1.34\ m/s[/tex]
Hence, the required speed is 1.34 m/s
The speed of a point on the edge of the flywheel is 134.16cm/s
The formula for calculating the centripetal acceleration of the flywheel is expressed as:
[tex]a=\frac{v^2}{r}[/tex]
where;
v is the speed of the flywheel
r is the radius of the wheel
Given the following parameters
r = 20.0cm
a = 900cm/s²
Substituting the given parameters into the formula above;
[tex]900=\frac{v^2}{20}\\v^2=900\times 20\\v^2=18,000\\v=\sqrt{18,000}\\v= 134.16cm/s[/tex]
Hence the speed of a point on the edge of the flywheel is 134.16cm/s
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Two short people are trying to get a 50 kg box moving across the floor. One is quite tall, and the other is quite short, so they can't use the same rope. The shorter person pulls on the rope so it is exactly horizontal to the floor, and uses a force of 170N. The taller person has to hold their rope at a 45 degree angle to the horizontal, and pulls with a force of 200N. What is the acceleration assuming the coefficient of friction is 0.3.
in a slap shot, a hockey player accelerates the puck from a velocity of 5 m/s to 30 m/s in the same direction. if the puck moves over a distance of 10 m during this process, what was the acceleration? group of answer choices
The acceleration of the puck is 43.75 m/s².
The velocity of an object or particle in uniform motion is defined as the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.
The player's puck accelerates from a velocity of 5 m/s to 30 m/s in the same direction.
The player's puck covers a distance of 10 m during that process.
Therefore,
The initial velocity of the puck is u = 5 m/s
The final velocity of the puck is v = 30 m/s
The distance covered during the period is s = 10 m
Using the equation of motion,
v² - u² = 2as
(30)² - (5)² = 2 × a × 10
900 - 25 = 20 × a
875 = 20 × a
a = 875/20
a = 43.75 m/s²
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A runner exerts a force of 234 Newtons against the ground while using 1100 Watts of power. How long does it take them to run a distance of 30.0 m?
Answer:
30 seconds
Explanation:
A football goalkeeper moves across her goal in a straight line. Her motion is shown on the following graph of horizontal position xxx vs. time ttt. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. What is the average speed of the goalkeeper between the times t=4\text{ s}t=4 st, equals, 4, start text, space, s, end text and t=12\text{ s}t=12 st, equals, 12, start text, space, s, end text? Choose 1 answer: Choose 1 answer: (Choice A) A -0.25\,\dfrac{\text m}{\text s}−0.25 s m minus, 0, point, 25, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice B) B 0.50\,\dfrac{\text m}{\text s}0.50 s m 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice C) C -0.50\,\dfrac{\text m}{\text s}−0.50 s m minus, 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice D) D 0.25\,\dfrac{\text m}{\text s}0.25 s m
Answer:
0.25 m/s
Explanation:
Acceleration cannot be negative.
A girl throws a ball vertically upwards. It takes a time of 3.20 s to return to her hand.
Assume air resistance is negligible.
What is the initial speed with which the ball is thrown?
Answer: 15.68ms
Explanation:
From the question, we are informed that it takes a time of 3.20s for the ball to return to her hand.
Then, the time thst will be taken by the ball to reach maximum height will be 1.6s
Let the initial speed be represented by v.
Therefore,
Vf = v - gt
where,
g = 9.8
t = 1.6
Vf = v - gt
0 = v - (9.8 × 1.6)
0 = v - 15.68
v = 15.68ms
=v−gt
⟹0=v−9.8×1.6
⟹v=15.68ms
A 0.50-kilogram frog is at rest on a rock next to a pond. The frog leaps pushing off of the rock with an acceleration of 5.0 m/s2. What is the magnitude of the net force exerted on the frog as it leaps? a)2.5 N b)1.5 N c)1.0 N d)2.0 N
Given that,
Mass of a frog, m = 0.5 kg
The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².
To find,
The magnitude of the net force exerted on the frog as it leaps.
Solution,
Let the net force exerted on the frog is given by the formula as follows :
F = ma
Putting the values of m and a to find F as follows :
F = 0.5 kg × 5 m/s²
F = 2.5 N
So, the magnitude of net force is 2.5 N.
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
Given the data in the question;
Mass of frog; [tex]m = 0.5kg[/tex]Acceleration; [tex]a = 5.0m/s^2[/tex]Force Exerted; [tex]F = ?[/tex]
To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:
[tex]F = m * a[/tex]
Where m is mass and a is acceleration
We substitute our given values into the equation
[tex]F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N[/tex]
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
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ANSWER THIS FOR BRAINY CROWN B) ITS SO EASY!
Answer:
300
Explanation:
What is the name of the process that plants use to remove carbon dioxide from the atmosphere?
transpiration
photosynthesis
respiration
decomposition
Answer:
Photosynthesis
Explanation:
It removes carbon naturally.
Answer:
photosynthesis
Explanation:
A forklift was used to lift a 750 kg. oil drum 18 m straight up into the air to store on a shelf. If it does it in 28 seconds, Calculate the work and power exerted by the forklift.
W= J
P= watts
Explanation:
Given parameters:
Mass of forklift = 750kg
Height of lift = 18m
Time taken = 28s
Unknown:
Work done = ?
Power = ?
Solution;
The work done by the forklift is given as:
Work done = mass x acceleration due to gravity x height
Work done = 750 x 9.8 x 18 = 132300J
Power is the rate at which work is done;
Power = [tex]\frac{work done }{time}[/tex]
Insert the parameters and solve;
Power = [tex]\frac{132300}{28}[/tex] = 4725W
1.10 You bring a negatively charged rubber rod close to a grounded
conductor without touching it. Then you disconnect the ground. What is the
sign of the charge on the conductor after you remove the charged rod?
a) negative
b) positive
d) cannot be determined from the
information given
c) no charge
The conductor after disconnected from the ground is positively charged after you remove the rubber rod.
Electrostatic induction is the change in a material's electric charge under the influence of another nearby object that has electric charge. For Electrostatic induction to occur a charged particle is held close (without touching it ) to a uncharged material that is grounded .
So, when the negatively charged rubber rod is brought closer to the grounded conductor which is neutral, a positive charge is induced on the conductor's side which is closer to the rubber rod and a negative charge on the other side which is close to the ground. So the negative charge starts escaping through ground. As it is disconnected from the ground, the conductor becomes positively charged.
Therefore, the conductor is positively charged after you remove the rubber rod.
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Two parallel wires separated by 4.00cm repel each other with a force per unit length of 2.00×10⁻⁴ N/m . The current in one wire is 5.00 A. (c) What would happen if the direction of one current were reversed and doubled?
When the direction of one current is reversed and doubled, the force will be doubled.
The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.
With a distance of 4.00 cm between them, two parallel wires repel one another with a force of 2.00 × 10⁻⁴ N/m. One wire is carrying 5.00 A of current.
I₁ = 5 A
d = 4 cm
F = 2 × 10⁻⁴ N/m
We have, [tex]\frac{F}{L}=\frac{\mu_{0} I_{1}I_{2}}{L}[/tex]
Now, we know the force is directly proportional to the product of the current, and the direction of one current is reversed and doubled.
The force of interaction would become attractive and its magnitude would double as a result of switching the directions of either of the currents and doubling their size.
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What part of an experiment contains the data tables and graphs
?
Answer: Review your data. ...
Calculate an average for the different trials of your experiment, if appropriate.
Make sure to clearly label all tables and graphs. ...
Place your independent variable on the x-axis of your graph and the dependent variable on the y-axis.
Hope this helps!!
Explain how a musical instrument such as a piano may be tuned by using the phenomenon of beats.
Hence , musical instrument such as a piano may be tuned by using the phenomenon of beats.
Suppose 2 sound waves of various frequencies reach your ear. the 2 waves can interfere with one another leading to constructive and damaging interference. This may lead to the sound being instead soft and loud, that we have a tendency to decision beats. The beat frequency is that the distinction between the frequency of the 2 sound waves.A musician typically uses the development of beat frequency to tune their piano. They pluck one string of the piano and faucet a implement at the same time. If the 2 sound sources turn out completely different beats, their frequencies will not be identical, and that they are aforementioned to be out of tune. The musician can modify the string's tension and repeatedly repeat the above mentioned method till the beats cannot be distinguished, that means the frequencies are identical. they're aforementioned to be in tune.
This methodology can work a lot of expeditiously for associate degree instrument entirely out of tune as a result of it'll be easier to differentiate the beats of the instruments and also the implement.
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a car accelerates from rest to 90 kilometre per hour in 10 seconds what is its acceleration in metre per second squared
Answer:2.5 m/s2
Explanation:
Acceleration =v2-v1 ÷ t2-t1 convert 90 km/h to m/s = 90×5/18 = 25 m/s , 25÷10 = 2.5
If the total charge inside a closed surface is known but. the distribution of the charge is unspecified, can you use Gauss's law to find the electric field? Explain.
No, Gauss’s law of charge distribution in electric field only applies to specified charge distribution. Hence, it cannot be used to find the electric field if the total charge inside a closed surface is known but. the distribution of the charge is unspecified
The electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field. Another interpretation of Gauss' rule holds that the net flow of an electric field across a particular surface divided by the contained charge should equal a constant. Gauss' law is only applicable to continuous charge distribution. In such instance, we may calculate the total electric field across the surface. However, we cannot use Gauss' law to calculate the electric field of charge with an uncertain distribution.
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