A truck is moving north word at a constant speed the momentum of the car is

Answer:

[tex]Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\[/tex]

Given that,

Force in right side = 50 N

Force in left side = 110 N

To find,

The resultant and direction of force.

Solution,

Let the net force F is acting on the rope. Also, we can assume that right side is positive and left side is negative.

F = 50+(-110)

= -60 N

So, the magnitude of the resultant force acting on the rope is 60 N and it acts in left side.

Answer:

132 N

Explanation:

Given that a  1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

From Newton 2nd law of motion,

Change in momentum = impulse.

Change in momentum = m( V - U )

Substitute all the parameters into the formula

Change in momentum = 1.1 ( 4.5 - 1.5 )

Change in momentum = 1.1 × 3

Change in momentum = 3.3 kgm/s

Impulse = Ft

That is,

Ft = 3.3

Substitute time t into the formula above

F × 0.025 = 3.3

F = 3.3 / 0.025

F = 132 N

Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.

Answer:

Speed of the approaching train = 15.45 m/s

Explanation:

Given:

Frequency F0 = 220 Hz

Beat frequency F1 = 10.0 Hz

Find:

Speed of the approaching train

Computation:

Approaching frequency F2 = 220 + 10.0 Hz

Approaching frequency F2 = 230 Hz

Doppler shift;

F = [(v+v0)/(v-vS)]F0

230 = [(340+v0)/(340-0)]220

V0 = 15.45 m/s

Speed of the approaching train = 15.45 m/s

Answer:

It increases the time it takes for the person to stop.

Explanation:

Answer:

C: It increases the time it takes for the person to stop.

Explanation:

on edge! hope this helps!!~ o(〃＾▽＾〃)o

Answer:

1425kgm/s

Explanation:

Given parameters:

Mass  = 95kg

Velocity  = 15m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion it posses;

  Momentum  = mass x velocity

Insert the parameters and solve;

 Momentum  = 95 x 15  = 1425kgm/s

Answer:

sure I will helpy you iru

F=nmv

where;

n=no. of bullets = 1

m=mass of bullets=2g *10^-3

V=velocity of bullets200m/sec

F=1

loss in Kinetic energy=gain in heat energy

1/2MV^2=MS∆t

let M council M

=1/2V^2=S∆t

M=2g

K.E=MV^2/2

=(2*10^-3)(200)^2/2

2 councils 2

2*10^-3*4*10/2

K.E=40Js

H=mv∆t

(40/4.2)

40Js=40/4.2=mc∆t

40/4.2=2*0.03*∆t

=158.73°C

Answer:

0.000314 Am²

6.049*10^-7 T

Explanation:

A

From the definitions of magnetic dipole moment, we can establish that

= , where

= the magnetic dipole moment in itself

= Current, 100 A

= Area, πr² (r = diameter divided by 2). Converting to m², we have 0.000001 m²

On solving, we have

= ,

= 100 * 3.14 * 0.000001

= 0.000314 Am²

B

= (0)/4 * 2 / ³, where

(0) = constant of permeability = 1.256*10^-6

z = 4.7 cm = 0.047 m

B = 1.256*10^-6 / 4*3.142 * [2 * 0.000314/0.047³]

B = 1*10^-7 * 0.000628/1.038*10^-4

B = 1*10^-7 * 6.049

B = 6.049*10^-7 T

Complete question:

Please find the image uploaded for the diagram.

Answer:

The magnitude of the current is 6 A, in the direction of Q to P.

Explanation:

Given;

length of the wire, l = 0.25 m

magnetic field strength, B = 40 mT = 0.04 T

Magnitude of the magnetic force, F = 60 mN = 0.06 N

The magnitude of the current in the conductor is given as;

F = BIL

Where;

I is the current induced in the conductor

I = F / BL

I = (0.06) / (0.04 x 0.25)

I = 6 A

Th current will move in direction of Q to P

Answer:

The magnitude of the final velocity of the water balloon is 84.3 m/s.

Explanation:

To calculate the velocity of the water balloon when it strikes the ground we need to use the next equation:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]

Where:

[tex]v_{f}[/tex]: is the final velocity =?

[tex]v_{0}[/tex]: is the initial velocity = 2 m/s

g: is the gravity = 9.81 m/s²

h: is the height = 4.5 m

By entering the above values into equation (1) we have:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (2 m/s)^{2} - 2*9.81 m/s^{2}*4.5 m = -84.3 m/s [/tex]

The minus sign is because the direction of the velocity vector is in the negative vertical axis.  

Therefore, the magnitude of the final velocity of the water balloon is 84.3 m/s.

I hope it helps you!

On heating a lead bar, its volume increases, density decreases and its mass remains constant.

According to Ideal gas equation,

pV = nRT

ρ = m / V

V = Volume

T = Temperature

ρ = Density

m = Mass

Based on Ideal gas equation, Volume is directly proportional to Temperature. As temperature increases, volume also increases. Based on density formula, Volume is indirectly proportional to Density. As Volume increases density decreases.  

In any reaction, the mass is always conserved. Because, mass is the amount of matter present in a substance. During a reaction, atoms are neither created nor destroyed, just rearranged. So the mass always remains constant.  

Therefore, if a lead bar was heated to 120°C, its volume increases, density decreases and its mass remains constant.

To know more about Ideal gas equation

https://brainly.com/question/15379358

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Answer:

Seventy-Five Metres

Explanation:

You can solve this simply by multiplying 15 m/s by 5 seconds

[tex]15 \frac{m}{s} * 5s\\=75\frac{ms}{s}\\= 75m[/tex]

A) the forces are acting in the same direction.. B) Together, forces are acting in opposite directions

Answer:

A) 80 N

B) 20 N

Explanation:

A) If the forces acting are in the same direction, then the net force will be a sum of both so many faces..

Thus;

ΣF = 50 + 30

ΣF = 80 N

B) If the forces are acting in the in opposite directions with the larger force pointing in the positive y-axis then, the net force is;

ΣF = 50 - 30

ΣF = 20 N

The correct answer is a = 539.68 m/[tex]s^2[/tex]

A push or pull that one thing applies to another is known as force. An object is considered to exert a force when it accelerates through space because acceleration is the rate at which an item's speed changes. The second law of motion of Newton explains this concept.

The equation F=ma, where "F" stands for force, "m" for mass, and "a" for acceleration, illustrates the link between force and acceleration.

Force applied = F = 3.40 N

The bullet's weight = m = 6.30 g = 0.0063 kg

The bullet's rate of acceleration can be expressed as = a = F/m

a = 3.40 / 0.0063

a = 539.68 m/[tex]s^2[/tex]

To learn more about acceleration refer the link:

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Answer:

48,2 m/s²

Explanation:

We're gonna use the Centripetal Acceleration formula: v² / r but before that, we got to know the velocity, that is not shown clearly to us, so....

To know the velocity let's calculate the distance that the ball traveled

The circumference of a circle formula is:

2piR

2 . 3,14 . 7,1 | That is equal to 44,588 m

We know that the ball traveled this distance 3,9 times, so...

44,588 . 3,9 = 173,8932 m

Ok, now we have the distance, just need to know the time, that is 9.4 seconds.

Velocity = Distance / Time

V = 173,8932 / 9,4

V = 18,5 (approximate)

So...

We are back to the first formula:

Ca = v² / r

Ca = 18,5² / 7.1

Ca = 48,2 m/s² (approximate)

I hope it is correct, hahaha.

Answer:

28.3 m/s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Maximum height (H) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

Thus, we can obtain the minimum velocity cannon ball by using the following formula:

H = u²Sine² θ / 2g

10 = u² × (Sine 30)² / 2× 10

10 = u² × (0.5)² / 20

10 = u² × 0.25 / 20

10 = u² × 0.0125

Divide both side by 0.0125

u² = 10/ 0.0125

u² = 800

Take the square root of both side

u = √800

u = 28.3 m/s

Therefore, the minimum speed of the cannon ball is 28.3 m/s

Answer:

5.14m/s

Explanation:

First we need to get the Maximum height reached by the rocket;

H = u²sin² theta/2g

H = 25²sin² 40/2(9.8)

H = 625(0.5878)/19.6

H = 18.74m

Get the velocity after 1.5secs

Using the equation of motion

H = ut + 1/2gt²

18.74 = u(1.5)+1/2(9.8)(1.5)²

18.74 = 1.5u + 4.9(2.25)

18.74 = 1.5u + 11.025

1.5u = 18.74 - 11.025

1.5u = 7.715

u = 7.715/1.5

u = 5.14m/s

Hence the velocity after 1.5secs is 5.14m/s

Given that,

A whale dives at an angle of 24 degrees to the horizontal surface of the water.

The whale continues in a straight line 145 m.

To find,

The horizontal and vertical components of the displacement of the whale.

Solution,

The horizontal component of displacement is :

[tex]d_x=d\cos\theta\\\\=145\times \cos(24)\\\\=132.46\ m[/tex]

The vertical component of displacement is :

[tex]d_y=d\sin\theta\\\\=145\times \sin(24)\\\\=58.97\ m[/tex]

Answer: D

Explanation:

Answer: the external agent must do work equal to -1.3 × 10⁻⁸ J

Explanation:

Given that;

Mass M1 = 7.0 kg

r = 3.0/2 m = 1.5 m

Mass M2 = 21 kg

we know that G = 6.67 × 10⁻¹¹ N.m²/kg²

work done by an external agent W = -2GM2M1 / r

so we substitute

W = (-2 × 6.67 × 10⁻¹¹ × 21 × 7) / 1.5

W = -1.96098 × 10⁻⁸ / 1.5

W = -1.3 × 10⁻⁸ J

Therefore the external agent must do work equal to -1.3 × 10⁻⁸ J

Answer:

Explanation:

The Net Force

The net force is defined as the sum of all the forces acting on a body at a certain moment.

Recall some basic concepts and equations to solve the problem.

If no external forces are applied in the vertical direction, the weight of the object and the normal force have the same magnitude and point to opposite directions.

The friction force is defined as:

[tex]Fr_k=\mu_k N[/tex]

[tex]Fr_s=\mu_s N[/tex]

Where the subindices k and s are referred as to the kinetic and static friction forces respectively.

The condition for the object to move is that the applied force is greater than the friction force.

The crate of oranges has a mass of 30 Kg, thus its weight is:

W = m.g = 30 * 9.8 = 294 N

The normal force is:

N = W = 294 N

The kinetic friction is calculated as:

[tex]Fr_k=0.52* 294[/tex]

[tex]Fr_k=152.88\ N[/tex]

The static friction is calculated as:

[tex]Fr_s=0.62* 294[/tex]

[tex]Fr_s=182.28\ N[/tex]

The applied force is 200 N and it's greater than both the kinetic and the static friction forces, thus the crate is definitely moving at a certain positive acceleration.

Answer:

c

Explanation:

Answer:

C

Explanation:

got it right on edge

Answer:

jrirnr tn

Explanation:

and then we was just wondering what we should be talking to about to see how you are

Answer:

T = 692.42 N

Explanation:

Given that,

Mass of hammer, m = 8.71 kg

Length of the chain to which an athlete whirls the hammer, r = 1.5 m

The angular sped of the hammer, [tex]\omega=1.16\ rev/s=7.28\ rad/s[/tex]

We need to find the tension in the chain. The tension acting in the chain is balanced by the required centripetal force. It is given by the formula as follows :

[tex]F=m\omega^2r\\\\=8.71\times (7.28)^2\times 1.5\\\\=692.42\ N[/tex]

So, the tension in the chain is 692.42 N.

Answer:

Slowing down

Explanation:

Carlos is travelling to the right as indicated by his velocity, so his velocity is +5m/s. He is also accelerating to the left which is the opposite direction to his velocity so his acceleration is -1.2m/s2 to the right.

Since his acceleration is negative relative to his velocity and direction of motion, his speed is decreasing and he is slowing down.

Hope this helped!