Answer:$207.48
Step-by-step explanation:You need to find how much gallons he would need so you divide 2,093 by 23 and you get 91. After that you multiply it by $2.28, The price per gallon and you get 207.48.
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 155 m above the ground. Suppose opening altitude actually has a normal distribution with mean value 155 and standard deviation 30 m. Equipment damage will occur if the parachute opens at an altitude of less than 100 m. What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes
Answer:
the probability that one parachute of the five parachute is damaged is 0.156
Step-by-step explanation:
From the given information;
Let consider X to be the altitude above the ground that a parachute opens
Then; we can posit that the probability that the parachute is damaged is:
P(X ≤ 100 )
Given that the population mean μ = 155
the standard deviation σ = 30
Then;
[tex]P(X \leq 100 ) = ( \dfrac{X- \mu}{\sigma} \leq \dfrac{100- \mu}{\sigma})[/tex]
[tex]P(X \leq 100 ) = ( \dfrac{X- 155}{30} \leq \dfrac{100- 155}{30})[/tex]
[tex]P(X \leq 100 ) = (Z \leq \dfrac{- 55}{30})[/tex]
[tex]P(X \leq 100 ) = (Z \leq -1.8333)[/tex]
[tex]P(X \leq 100 ) = \Phi( -1.8333)[/tex]
From standard normal tables
[tex]P(X \leq 100 ) = 0.0334[/tex]
Hence; the probability of the given parachute damaged is 0.0334
Let consider Q to be the dropped parachute
Given that the number of parachute be n= 5
The probability that the parachute opens in each trail be p = 0.0334
Now; the random variable Q follows the binomial distribution with parameters n= 5 and p = 0.0334
The probability mass function is:
Q [tex]\sim[/tex] B(5, 0.0334)
Similarly; the event that one parachute is damaged is :
Q ≥ 1
P( Q ≥ 1 ) = 1 - P( Q < 1 )
P( Q ≥ 1 ) = 1 - P( Y = 0 )
P( Q ≥ 1 ) = 1 - b(0;5; 0.0334 )
P( Q ≥ 1 ) = [tex]1 -(^5_0)* (0.0334)^0*(1-0.0334)^5[/tex]
P( Q ≥ 1 ) = [tex]1 -( \dfrac{5!}{(5-0)!}) * (0.0334)^0*(1-0.0334)^5[/tex]
P( Q ≥ 1 ) = 1 - 0.8437891838
P( Q ≥ 1 ) = 0.1562108162
P( Q ≥ 1 ) [tex]\approx[/tex] 0.156
Therefore; the probability that one parachute of the five parachute is damaged is 0.156
When a force of 36 Newtons is applied to springs S1 and S2, the displacement of the springs is 6 centimeters and 9 cm, respectively. What is the difference between the spring constants of the two springs?
Answer:
200 N/m
Step-by-step explanation:
Rearranging the formula F = kx, you find that k = F/x. For the first spring,
F = 36 N and x = 0.06 m (6 cm). So the spring constant, F/x, is 36N/0.06m = 600 N/m
For the second spring, F = 36 N and x = 0.09 m. F/x = 36N/0.09m = 400 N/m
The difference between these values is 200 N/m, and that's the answer.
Which graph represents the solution to this inequality?
Answer:
D
Step-by-step explanation:
1/3(9x + 27) > x + 33
3x + 9 > x + 33
2x > 24
x > 12
> means open circle
Answer:
The answer is D
Step-by-step explanation:
I took the plato test!
A study of the annual population of butterflies in a county park shows the population, B(t), can be represented by the function B(t)=137(1.085)t, where the t represents the number of years since the study started. Based on the function, what is the growth rate?
Answer:
The growth rate is of 0.085 = 8.5% a year.
Step-by-step explanation:
General growth equation:
[tex]B(t) = B(0)(1+r)^{t}[/tex]
In which B(t) is the population of butterflies after t years, B(0) is the initial population and r is the growth rate, as a decimal.
We have:
[tex]B(t)=137(1.085)^{t}[/tex]
Comparing to the general equation, we have that:
[tex]B(0) = 137, 1 + r = 1.085[/tex]
Growh rate:
1 + r = 1.085
r = 1.085 - 1
r = 0.085
The growth rate is of 0.085 = 8.5% a year.
Solve the equation for the indicated variable. C=680x/h^2 for x
Answer:
C h^2 / 680 = x
Step-by-step explanation:
C=680x/h^2
Multiply each side by h^2
C h^2=680x/h^2 * h^2
C h^2=680x
Divide each side by 680
C h^2 / 680=680x/680
C h^2 / 680 = x
What is the point-slope form of a line that has a slope of One-half and passes through point (–7, 2)? 2 minus y = one-half (7 minus x) 7 minus y = one-half (negative 2 minus x) y minus 7 = one-half (X minus 2) y minus 2 = one-half (x minus (negative 7))
Answer: y-2=1/2(x-(-7)) or y-2=1/2(x+7)
Step-by-step explanation:
The point-slope formula is y-y₁=m(x-x₁). Since we are given the point and the slope, we can directly plug them into where it is appropriate. The slope is 1/2. Slope is represented by m. We would plug in 1/2 into m. The point is (x₁,y₁). That format matches (-7,2).
y-2=1/2(x-(-7))
y-2=1/2(x+7)
Answer:
D.
Step-by-step explanation:
Suppose that 10 fair coins are tossed. Find the numbers of ways of obtaining exactly 1 heads. Round the answer to the nearest whole number
Answer: 10
Step-by-step explanation:
Given : Total number of coins tossed = 10
Possible outcomes to toss a coin = Head or tail
Number of possible outcomes = [tex]2^{10}=1024[/tex]
Number of ways of obtaining exactly 1 heads = [tex]{10}C_1=\dfrac{10!}{1!9!}[/tex] [using combinations [tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex] ]
=10
Hence, the numbers of ways of obtaining exactly 1 heads= 10
Find the four terms of the sequence given by the following expression
Answer:
47, 40, 33, 26 are the first four terms of the sequence.
Step-by-step explanation:
Expression representing the sequence is,
[tex]a_n=46-7(n-1)[/tex]
where n = number of term in the sequence
For n = 1,
[tex]a_1=47-7(1-1)[/tex]
= 47
For n = 2,
[tex]a_2=47-7(2-1)[/tex]
= 47 - 7
= 40
For n = 3,
[tex]a_3[/tex] = 47 - 7(3 -1)
= 47 - 14
= 33
For n = 4,
[tex]a_4=47-7(4-1)[/tex]
= 47 - 21
= 26
Therefore, first four terms of the sequence are 47, 40, 33 and 26.
Use a power reduction identity to simplify 8cos4 x .
Answer:
[tex]8cos^4}x = (3 + 4cos2x + cos4x)[/tex]
Step-by-step explanation:
Using the power reduction identity, we have that:
[tex]cos^{2}x = \frac{1}{2}(1 + cos2x)\\ \\cos^{4}x = (cos^{2}x)^2 = (\frac{1}{2}(1 + cos2x))^2\\\\cos^{4}x = \frac{1}{4} (1 + 2cos2x + cos^{2}2x)\\[/tex]
From the first line:
[tex]cos^{2}2x = \frac{1}{2}(1 + cos4x)[/tex]
Therefore:
[tex]cos^{4}x = \frac{1}{4} (1 + 2cos2x + \frac{1}{2}(1 + cos4x))\\\\cos^4}x = \frac{1}{4} (1 + 2cos2x + \frac{1}{2} + \frac{1}{2} cos4x)\\\\cos^4}x = \frac{1}{4} (\frac{3}{2} + 2cos2x + \frac{1}{2} cos4x)\\\\=> 8cos^4}x = 8 * \frac{1}{4} (\frac{3}{2} + 2cos2x + \frac{1}{2} cos4x)\\\\8cos^4}x = 2 * (\frac{3}{2} + 2cos2x + \frac{1}{2} cos4x)\\\\8cos^4}x = (3 + 4cos2x + cos4x)[/tex]
Answer:
Step-by-step explanation:
What number must you add to complete the square? x^2+6x=15 A.6 B.12 C.9 D.3
Answer:
C. 9
Step-by-step explanation:
To find the number we add to complete the square, we do (b/2)², or take b (which is 6), divide by 2 (which gives us 3), then square the result (which gives us 9):
6/2 = 3
3² = 9
Answer: 9
Step-by-step explanation: To complete the square, we need a number to create a perfect square trinomial on the left side of the equation.
So the question is, what is that number?
Well it comes from a formula.
The number that we will need to complete the square will always
come from half the coefficient of the middle term squared.
In this case, that's half of 6 which is 3, squared, which is 9.
So we add 9 to both sides of the equation.
This will now allow the left side of the equation to factor.
Write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3
To write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3
Let n be the number, then -3 < n ≤3 .
On number line we mark open circle at -3 (since it has a strictly less than sign) and a closed circle at 3 (since it has a less than and equal to sign) .
To the required inequality that shows all the numbers greater than (−3) but less than or equal to 3 : -3 < n ≤3 and the number line is represented below.
Please help me out with these questions, ❤️☢️⬅️⬅️☣️⬅️✖️❌❎❎❎❌️️ℹ️⚫▫️▫️▫️
Hi there! Thanks for your questions ;)
The answers are quite easily, go through the steps below so that you can catch it up yourself!!
a)= [tex]\rm{sin (x) = \dfrac{9}{20}}[/tex]
= [tex]\rm{0.45}[/tex]
= [tex]\rm{x = arcsin(0.45)}[/tex]
= [tex]\rm{26.74 \: degrees}[/tex](b) here, h is height.= [tex]\rm{h = 20 \times cos(x)}[/tex]
= [tex]\rm{20 \times cos(26.74)}[/tex]
= [tex]\rm{ 17.86 \: m}[/tex]Hope it is helpful!
there are three oranges in 200g of bag . if the weight of them with bag is 1.4kg. find the weight of an orange.i want full methods
the bag is 200g
total weight with oranges is 1400g
deduct the bags weight from total weight
1400 - 200
1200g
this is the weight of the three oranges
so each orange would be
1200 ÷ 3
400g
The attendance for a week at a local theatre is normally distributed, with a mean of 4000 and a standard deviation of 500. What percentage of the attendance figures would be less than 3500? What percentage of the attendance figures would be greater than 5000? what percentage of the attendance figures would be between 3700 and 4300 each week?
ok its 45.15% trust me
Answer:
Step-by-step explanation:
This curve alone does not give exact percentages with the exception of P(z=0) = .50 or 50%
A Pictorial where 'some' of the % have been added for helps more...
However, most often one needs to use a table, calculator, or an Excel function ect to find exact Percentage,
P(x > 4000) = P(z = 0) = .50 or 50 % |using above pictorial
Using Calculator etc: Here, am using the Excel NORMSDIST function to find the Percentages:
P(z=3/5 - z=-3/5) = .7257 - .2742 =.4515 or 45.15%
A 24 inch wire is cut in two and shaped into a square and a regular octagon . What is the minimum possible sum of the two areas?
Answer:
A(t) = 41,47 in²
Step-by-step explanation:
Let´s call "x" the cut of point to get to pieces of wire, we make a square from x and the regular octagon will be shaped with 24-x
Then Area of the square A(s) = x²
Area of the octagon is A(o) = 1/2*p*length of apothem (d)
p = ( 24 - x )
length of apothem (d) :
The side of the octagon is equal to ( 24 - x ) / 8 half the side is
( 24 - x ) / 16
tan α = ( 24- x ) 16 / d since ∡s in octagon are 360 / 8 = 45°
α ( ∡ between apothem and one of the interiors ∡ of the octagon )half of 45 is α = 22,5°
tanα = 0,41
d = (24 - x ) / 16*0,41 d = ( 24 - x ) / 6,56
Then
A(t) = A(s) + A(o)
A(t) = x² + (1/2)* ( 24 - x ) ( 24 - x ) / 6,56
Note A(t) = A(x)
A(x) = x² + (1/2) * (24 - x )²/ 6,56
A(x) = x² + ( 1/ 2*6,56) * ( (24)² -48*x + x² )
Taking derivatives on both sides of the equation
A´(x) = 2*x + ( 1/13,12)* ( - 48 + 2x )
A´(x) = 2*x - 48/ 13,12 + 2*x
A´(x) = 4*x - 3,66
A´(x) = 0 4x = 3,66 x = 0,91 in and d =( 24 - x ) / 6,56
d = ( 24 - 0,91 ) / 6,56 d = 3,52
Then A(s) = (0,91)² A(s) = 0,83 in²
A(o) = 1/2 * ( 24 - 0,91 )* 3,52
A(o) = 40,63 in²
A(t) = 40,63 + 0,83
A(t) = 41,47 in²
Daddy's annual salary is $42603.00. If he gets the same salary
each month and a monthly travelling allowance of $1250.00,
what is his monthly earning?
Answer:
$4800.25
Step-by-step explanation:
$42603 is a yearly salary.
There are 12 months in 1 year.
Monthly salary:
$42603/12 = $3550.25
Monthly travelling allowance: $1250
Total amount earned in 1 month:
$3550.25 + $1250 = $4800.25
Safegate Foods, Inc., is redesigning the checkout lanes in its supermarkets throughout the country and is considering two designs. Tests on customer checkout times conducted at two stores where the two new systems have been installed result in the following summary of the data.
System System B
n1=120 n2=100
x1=4.1 minutes x2=3.4 minutes
σ1=2.2minutes σ2= 1.5 minutes
Test at the 0.05 level of significance to determinewhether the population mean checkout times of the two newsystems differ. Which system is preferred?
Answer:
We conclude that the population means checkout times of the two new systems differ.
Step-by-step explanation:
We are given the result in the following summary of the data;
System System B
n1=120 n2=100
x1=4.1 min x2=3.4 min
σ1=2.2 min σ2= 1.5 min
Let [tex]\mu_1[/tex] = population mean checkout time of the first new system
[tex]\mu_2[/tex] = population mean checkout time of the second new system
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1=\mu_2[/tex] {means that the population mean checkout times of the two new systems are equal}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1\neq \mu_2[/tex] {means that the population mean checkout times of the two new systems differ}
The test statistics that will be used here is Two-sample z-test statistics because we know about population standard deviations;
T.S. = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1} + \frac{\sigma_2^{2} }{n_2}} }[/tex] ~ N(0,1)
where, [tex]\bar X_1[/tex] = sample mean checkout time of the first new systems = 4.1 min
[tex]\bar X_2[/tex] = sample mean checkout time of the second new systems = 3.4 min
[tex]\sigma_1[/tex] = population standard deviation of the first new systems = 2.2 min
[tex]\sigma_2[/tex] = population standard deviation of the second new systems = 1.5 min
[tex]n_1[/tex] = sample of the first new systems = 120
[tex]n_2[/tex] = sample of the second new systems = 100
So, the test statistics = [tex]\frac{(4.1-3.4)-(0)}{\sqrt{\frac{2.2^{2} }{120} + \frac{1.5^{2} }{100}} }[/tex]
= 2.792
The value of z-test statistics is 2.792.
Now, at 0.05 level of significance, the z table gives a critical value of -1.96 and 1.96 for the two-tailed test.
Since the value of our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the population mean checkout times of the two new systems differ.
The graph of a linear function is given below. What is the zero of the function?
Answer:
Option (D)
Step-by-step explanation:
Zero of any function is defined by the x-value of the function when y = 0.
Let the equation of the line given in the graph is,
y = mx + b
where m = slope of the line
b = y-intercept of the line
Slope of a line passing through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is defined by the formula,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
If the passes through (0, -3) and (-2, 0)
m = [tex]\frac{-3-0}{0+2}[/tex]
m = [tex]-\frac{3}{2}[/tex]
Fro the graph,
y-intercept 'b' = -3
Therefore, equation of the line is,
[tex]y=-\frac{3}{2}x-3[/tex]
For y = 0,
[tex]0=-\frac{3}{2}x-3[/tex]
[tex]\frac{3}{2}x=-3[/tex]
x = -2
Therefore, option (D) will be the answer.
Answer:
d- -2
Step-by-step explanation:
Please help! I’ll mark you as brainliest if correct
Answer:
You need to add 150 mL of 65% alcohol solution.
Step-by-step explanation:
You have 300 mL of 20% solution.
300 mL of 20% alcohol solution has 20% * 300 mL of alcohol.
You have 65% solution.
Let the volume of 65% solution you add be x.
In 65% solution, 65% of the volume is alcohol, so the amount of alcohol in x amount of 65% solution is 65% * x.
You want 35% solution.
The total amount of 35% solution you will make is 300 mL + x. The amount of alcohol in that amount of solution is 35% * (x + 300).
Equation of alcohol content:
20% * 300 + 65% * x = 35% * (x + 300)
60 + 0.65x = 0.35x + 105
0.3x = 45
x = 150
Answer: You need to add 150 mL of 65% alcohol solution.
Simplify and leave in radical form.
Answer:
[tex]\sqrt[4]{xy^3}[/tex].
Step-by-step explanation:
[tex]\sqrt[8]{x^2y^6}[/tex]
= [tex]x^{\frac{2}{8} } y^{\frac{6}{8}}[/tex]
= [tex]x^{\frac{1}{4} } y^{\frac{3}{4}}[/tex]
= [tex]\sqrt[4]{xy^3}[/tex].
Hope this helps!
Find c and round to the nearest tenth
Answer:
[tex] c = 15.5 [/tex]
Step-by-step explanation:
Using the Law of Cosines, c² = a² + b² - 2ab*cos(C), let's find c.
Where,
a = 15 ft
b = 20 ft
C = 50°
Thus:
[tex] c^2 = 15^2 + 20^2 - 2*15*20*cos(50) [/tex]
[tex] c^2 = 625 - 600*0.6429 [/tex]
[tex] c^2 = 625 - 600*0.6429 [/tex]
[tex] c^2 = 625 - 385.74 [/tex]
[tex] c^2 = 239.26 [/tex]
[tex] c = \sqrt{239.26} [/tex]
[tex] c = 15.5 [/tex] (nearest tenth)
Answer:
c sorry gotta get points.
Step-by-step explanation:
Find the midpoint of the segment between the points (17,−11) and (−14,−16)
Answer:
(1.5, -13.5)
Step-by-step explanation:
Midpoint Formula: [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]
Simply plug in our coordinates into the formula:
x = (17 - 14)/2
x = 3/2
y = (-11 - 16)/2
y = -27/2
Answer:
(-1.5, -13.5)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinates and divide by 2
( 17+-14)/2 = 3/2 =1.5
To find the y coordinate of the midpoint, add the x coordinates and divide by 2
( -11+-16)/2 = -27/2= - 13.5
What is the value of Sine theta in the diagram below?
Answer:
C) 24/25
Step-by-step explanation:
did the quiz and got it right
The value of the sine theta in the first quadrant in the diagram given is [tex]\mathbf{\dfrac{24}{25}}[/tex]
What is the trigonometric function in the first quadrant?The explanation of the trigonometric functions (i.e cosine, sine, tangent) in respect of point coordinates on the unit circle informs us of the signs and meanings of the trigonometric functions for each of the four(4) quadrants, depending on the signs of the x, as well as, y coordinates in each quadrant.
In the first quadrant;
cos(θ) > 0, sin(θ) > 0 andtan(θ) > 0Thus, we have a positive x and y-axis.
Taking the forms x and y, i.e. (x, y) = (cos θ, sin θ)
The value of sine theta in [tex]\mathbf{(\dfrac{7}{25}, \dfrac{24}{25} ) = \dfrac{24}{25} }[/tex]
Learn more about Trigonometric functions here:
https://brainly.com/question/24349828
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here is the picture pls answer another for my lil friend lol
Answer:
Hey there!
The perimeter can be expressed as 140+140+68[tex]\pi[/tex]
This is equal to 493.52 m
Hope this helps :)
solve the nonlinear system of equations. State the number of solutions.
Answer:
Step-by-step explanation:
Hello,
Question 15
We can search x such that:
[tex]x^2-4x+4=2x-5\\\\\text{*** subtract 2x-5 from both sides ***}\\ \\x^2-4x-2x+4+5=0\\ \\\text{*** simplify ***}\\ \\x^2-6x+9=0 \\ \\\text{*** we can notice a perfect square ***}\\ \\x^2 -2\cdot x \cdot 3 + 3^2=(x-3)^2=0\\\\\text{*** taking the root ***}\\\\x-3=0\\\\\large \boxed{\sf \ \ x=3 \ \ }[/tex]
There is 1 solution.
Question 16
Again, we search x such that:
[tex]x^2-8x+15=2x-6\\\\\text{*** subtract 2x-6 from both sides ***}\\\\x^2-8x-2x+15+6=0\\\\\text{*** simplify ***}\\\\x^2-10x+21=0 \\ \\\text{*** we are looking for two roots where the sum is 10 and the product is 21 = 7 x 3 ***} \\\\x^2-7x-3x+21=x(x-7)-3(x-7)=(x-3)(x-7)=0\\\\\large \boxed{\sf \ \ x= 3 \ or \ x =7 \ \ }[/tex]There are two solutions.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Let a and b be real numbers where a=/b=/c=/0 which of the following functions could represent the graph below?
Answer: The second option; y = (x - a)^2*(x-b)^4
Step-by-step explanation:
Ok, we have that a and b are real numbers different than zero.
In the graph, we can see that the line touches the x-axis in two values. Now, if we would have an equation like:
y = x*(x - a)^3*(x - b)^3
then when x = 0 we would have:
y = 0*(0-a)^3*(0-b)^3 = 0
But in the graph, we can see that when x = 0, the value of y is different than zero, so we can discard options 1 and 3.
So the remaining options are:
y = (x - a)^2*(x-b)^4
y = (x - a)^5*(x - b)
Now, another thing you can see in the graph is that it is always positive.
Particularly the second option allows negative values for y because it has odd powers, then we can also discard this option.
(For example, if x > a and x < b we would have a negative value for y)
Then the only remaining option is y = (x - a)^2*(x-b)^4
Answer:
B.y = (x - a)^2*(x-b)^4
Step-by-step explanation:
EDGE 2020 Brainliest please
If f(x)=x-9 and g(x)=-6x-3 which statement is true
Answer:
-1 is not in the domain of (f o g)(x)
Step-by-step explanation:
f(x) = sqrt(x - 9)
g(x) = -6x - 3
(f o g)(x) = f(g(x)) = sqrt(g(x) - 9)
(f o g)(x) = sqrt(-6x - 3 - 9)
(f o g)(x) = sqrt(-6x - 12)
Let x = -1:
(f o g)(-1) = sqrt(-6(-1) - 12)
(f o g)(-1) = sqrt(6 - 12)
(f o g)(-1) = sqrt(-6)
Since sqrt(-6) is not a real number, -1 is not in the domain of (f o g)(x).
calculate the value of angle A to one decimal place. Picture Attached
Answer:
[tex] A = 50.7 [/tex] (to nearest tenth)
Step-by-step explanation:
Use the Law of Cosines to find the value of angle A as follows:
[tex] cos(A) = \frac{b^2 + c^2 - a^2}{2*b*c} [/tex]
Where,
a = 7 in
b = 5 in
c = 9 in
Plug in the values into the formula
[tex] cos(A) = \frac{5^2 + 9^2 - 7^2}{2*5*9} [/tex]
[tex] cos(A) = \frac{57}{90} [/tex]
[tex] cos(A) = 0.6333 [/tex]
[tex] A = cos^{-1}(0.6333) [/tex]
[tex] A = 50.7 [/tex] (to nearest tenth)
Judith is planning a birthday party at her house. she has 36 slices of pizza and 24 Capri Suns. What is the maximum number of people she can have at the party so that each person gets the same number of slices of pizza and the same number of Capri Suns? show all work
She can either have 24 people since there are more slices of pizza there will be extras
Which system of equations represent the matrix shown below?
1 2 -1| 8
-1 0 3| 15
1 -2 4| 18
A. x + 2y + z =8
x + y + 3z =15
x + 2y + 4z =18
B. x + 2y + z =8
x + 3z =15
x + 2y + 4z =18
C. x + 2y - z =8
-x + y + 3z =15
x - 2y + 4z =18
D. x + 2y - z =8
-x + 3z =15
x - 2y + 4z =18
Answer:
the solution to the problem is D