A tray of lasagna comes out of the oven at 200°F and is placed on a table


where the surrounding room temperature is 70°F. The temperature T (in °F) of


the lasagna is given by the function (0) -e(486753-1) +70, 0 s t, where tis time


(in hours) after taking the lasagna out of the oven. What is the rate of change


in the temperature of the lasagna exactly 2 hours after taking it out of the


oven?

The scale factor from A to B is 5 / 4.

The value of t in the diagram is 5.6 cm.

Scale factor is the ratio between corresponding measurements of an object and a representation of that object.

Therefore, let's find the scale factor from the shape A to the shape B as follows:

5 / 4 = 15 / 12

Therefore, the scale factor is 5 / 4.

Hence, let's find the value of t in the diagram as follows:

Therefore, using the proportionality,

7 / t = 5 / 4

cross multiply

28 = 5t

divide both sides by 5

t = 28 / 5

t = 5.6 cm

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Answer:

2*Ab    Or AC

Step-by-step explanation:

No detail in question

Answer:

423.9

Step-by-step explanation:

To solve this problem you need to use the formula for surface area. This formula can either be used with the radius or the diameter. I prefer using diameter because it is easier to remember and it is easier to calculate. The formula writes as follows: [tex]SA=d\pi h+d\pi ^{2}\\\\[/tex]. To use this formula all we have to do is insert the values into the formula and solve.

[tex]SA=d\pi h+d\pi ^{2}\\\\SA=(9)\pi(6)+\pi(9) ^{2}\\\\SA=54\pi+81\pi\\\\SA=54\pi+81\pi\\\\SA=135\pi\\\\SA=423.9[/tex]

423.9 is our answer.

To find the effective interest rate that Hannah is being offered, we need to take into account the compounding period, which is daily in this case. The effective annual interest rate (EAR) can be calculated using the formula:

EAR = (1 + APR/n)^n - 1

where APR is the annual percentage rate, and n is the number of compounding periods per year.

For the first 30 days, Hannah is offered a 0% APR, so the EAR for this period is simply 0.

After 30 days, Hannah is offered a 12.22% APR compounded daily, which means that there are 365 compounding periods per year. Therefore, the EAR for this period can be calculated as follows:

EAR = (1 + 0.1222/365)^365 - 1

   ≈ 0.1267

So the effective interest rate that Hannah is being offered is approximately 12.67%.

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The missing side length of the rectangle is 7.75 inches when x is equal to 3. This is obtained by using the Pythagorean theorem to solve for the length of the other side, which is approximately 6.3 inches.

Using the Pythagorean theorem, we can find the missing side length of the rectangle

a² + b² = c²

where c is the length of the diagonal and a and b are the lengths of the sides.

Plugging in the values given, we get

(2x)² + b² = (8x)²

4x² + b² = 64x²

b² = 60x²

b = √(60x²) = √(60)x

When x = 3, the missing side length is

b = √(60)(3) = 7.75 in. (rounded to the nearest tenth of an inch)

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--The given question is incomplete, the complete question is given

"Find an equivalent expression for the missing side length of the rectangle.

then find the missing side length when x = 3. round to the nearest tenth of an inch.

8x in. is a diagonal of rectangle

2x in. is one side of rectangle

? in. is other side at base "--

(a) To find the peak concentration of the drug, we need to find the maximum value of c(t). Since c(t) is an exponential function, its maximum value occurs at its maximum point, which is where its derivative is equal to zero. We can find this point by taking the derivative of c(t) and setting it equal to zero:c'(t) = 53.2e^{-0.26} - 13.832te^{-0.26} = 0Solving for t, we get t = 3.870 hours. Therefore, the peak concentration of the drug is c(3.870) = 109.2 ng/ml.(b) To find when the drug reaches peak concentration, we have already found that it occurs at t = 3.870 hours. Therefore, the drug reaches peak concentration 3.870 hours after it is administered.

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The peak concentration of the drug is approximately 42.83 ng/ml, and it occurs around 3.85 hours after the drug is administered.

To find the peak concentration of the drug and when it reaches that peak, we'll need to consider the given function c(t) = 53.2te^(-0.26t), where t is the time in hours.

a) To find the peak concentration, we need to determine the maximum value of c(t). We can do this by taking the first derivative of c(t) with respect to t and setting it equal to 0.

c'(t) = 53.2(-0.26)e^(-0.26t) + 53.2e^(-0.26t) = 0

Now, solve for t:

t ≈ 3.85 hours

b) Plug the value of t back into the c(t) function to find the peak concentration:

c(3.85) = 53.2(3.85)e^(-0.26(3.85)) ≈ 42.83 ng/ml

So, the peak concentration of the drug is approximately 42.83 ng/ml, and it occurs around 3.85 hours after the drug is administered.

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To find the annual rate at which the car depreciated, we need to use the formula for exponential decay:

A(t) = P(1 - r)^t

where A(t) is the current value of the car after t years, P is the initial value of the car, and r is the annual rate of depreciation.

We know that P = $15,500 and A(t) = $8,400, so we can plug in these values to solve for r:

$8,400 = $15,500(1 - r)^t

Divide both sides by $15,500:

0.54 = (1 - r)^t

Take the logarithm of both sides:

log(0.54) = t*log(1 - r)

Solve for r:

log(0.54)/t = log(1 - r)

1 - r = 10^(log(0.54)/t)

r = 1 - 10^(log(0.54)/t)

Plugging in t = 7 (since the car has depreciated for 7 years), we get:

r = 1 - 10^(log(0.54)/7) ≈ 9.35%

Therefore, the car depreciated at an annual rate of approximately 9.35%.

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Answer:

Step-by-step explanation:

To prove that lines a and b are parallel lines cut by transversal f, we need to show that the alternate interior angles are congruent. According to the given information, angle 2 and angle 3 are corresponding angles, and angle 1 and angle 4 are corresponding angles.

Therefore, the set of equations that is enough information to prove that lines a and b are parallel lines cut by transversal f is:

angle 2 = angle 3 (corresponding angles)

angle 1 = angle 4 (corresponding angles)

The test statistic for the hypothesis about a consumer activist decides to test the authenticity of the claim is t = 1.38.

In a hypothesis test, a test statistic—a random variable—is computed from sample data. To decide whether to reject the null hypothesis, you can utilise test statistics. Your results are compared to what would be anticipated under the null hypothesis by the test statistic. The p-value is computed using the test statistic.

A test statistic gauges how closely a sample of data agrees with the null hypothesis. Its observed value fluctuates arbitrarily from one random sample to another. When choosing whether to reject the null hypothesis, a test statistic includes information about the data that is important to consider. The null distribution is the sample distribution of the test statistic for the null hypothesis.

Sample size, n = 20

Sample mean, x = 14.8 pounds

Sample standard deviation, s = 2.6

The null hypothesis is,

[tex]H_o[/tex]: μ ≤ 14

The alternative hypothesis is,

[tex]H_a[/tex] : μ > 14

t-test statistic is defined as:

[tex]t = \frac{x - \mu}{\frac{s}{\sqrt{n} } }[/tex]

[tex]= \frac{14.8 - 14}{\frac{2.6}{\sqrt{20} } }[/tex]

= [tex]\frac{0.8}{0.581}[/tex]

= 1.377

t = 1.38.

Therefore, the test statistic for the hypothesis is 1.38.

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Complete question"

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than 14 pounds. A consumer activist decides to test the authenticity of the claim. She follows the progress of 20 women who recently joined the weight-reduction program. She calculates the mean weight loss of these participants as 14.8 pounds with a standard deviation of 2.6 pounds. The test statistic for this hypothesis would be Multiple Choice -1.38 1.38 1.70 -1.70 O O

From the calculation, you are 100 m away from the plateau.

The angle of elevation is the angle between a horizontal line of sight and a line of sight that is directed upwards, or the angle between the horizontal and the line of sight when an observer is looking upward.

We know that;

Angle of elevation = 35°

Height of the Plateau = 70 m

Thus;

Tan 35 =70/x

x = Your distance from the plateau.

x = 70/Tan 35

x = 100m

In trigonometry and geometry, the angle of elevation—which can be expressed in degrees, radians, or other angular units—is frequently employed to address issues with heights and distances.

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The value of the tangent segment b is 20.15.

The secant-tangent power theorem, also known as the tangent-secant theorem, states that if a tangent and a secant are drawn from a common external point to a circle, then the product of the length of the secant segment and its external part is equal to the square of the length of the tangent segment.

It is expressed as:

( tangent segment )² = External part of the secant segment + Secant segment.

From the diagram:

Tangent segment = WX = b

External part of the secant segment = YX = 14

Secant segment = ZX = 15 + 14 = 29

Plug these values into the above formula and solve for b.

( tangent segment )² = External part of the secant segment + Secant segment.

b² = 14 × 29

b² = 406

b = √406

b = 20.15

Therefore, the value of b is 20.15.

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The Lagrange error bound for the fourth-degree Taylor polynomial of [tex]e^x[/tex] about 0 for 0 ≤ x ≤ 0.9 is approximately 0.000129.

To find the Lagrange error bound for the fourth-degree Taylor polynomial of [tex]e^x[/tex] about 0, we need to find the maximum value of the fifth derivative of [tex]e^x[/tex] on the interval [0, 0.9].

Since the nth derivative of [tex]e^x[/tex] is [tex]e^x[/tex] for all n, the fifth derivative is also [tex]e^x[/tex]. To find the maximum value of[tex]e^x[/tex]on the interval [0, 0.9].

We evaluate [tex]e^x[/tex] at the endpoints and at the critical point x = 0.45, which is the midpoint of the interval:

[tex]e^0[/tex] = 1

[tex]e^0.9[/tex]≈ 2.4596

[tex]e^0.45[/tex] ≈ 1.5684

The maximum value of [tex]e^x[/tex] on the interval [0, 0.9] is approximately 2.4596.

The Lagrange error bound for the fourth-degree Taylor polynomial of [tex]e^x[/tex] about 0 is given by:

E₄(x) ≤ (M/5!)[tex]|x-0|^5[/tex]

where M is the maximum value of the fifth derivative of [tex]e^x[/tex] on the interval [0, 0.9].

So, we have:

E₄(x) ≤ (2.4596/5!) [tex]|x|^5[/tex] for 0 ≤ x ≤ 0.9

Substituting x = 0.9 into this inequality, we get:

E₄(0.9) ≤ (2.4596/5!)[tex](0.9)^5[/tex] ≈ 0.000129

Therefore, the Lagrange error bound for the fourth-degree Taylor polynomial of [tex]e^x[/tex] about 0 for 0 ≤ x ≤ 0.9 is approximately 0.000129.

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Mariah cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

A triathlon is  described as an endurance multisport race consisting of swimming, cycling, and running over various distances.

The coordinates are given as follows:

Suppose that we have two points,  and . The distance between them is given by:

distance = √(x2 - x1)² + (y2-y1)²

We substitute in the equation

Hence the distance between her house and the library is:

D = 8.6 miles.

She cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

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The math fact that 4 x 6 = 24 helps Matt remember that 6 x 4 = 24, and Sadie arrived at the answer 10 for 6 + 4 by incorrectly adding the numbers in reverse order.

Matt knows that 6 x 4 = 24. This helps him remember that 4 x 6 and 6 x 4 are both equal to 24.

The math fact that Matt can remember based on 4 x 6 = 24 is that multiplication is commutative. This means that the order of the numbers being multiplied doesn't affect the result. So, if 4 multiplied by 6 equals 24, it also implies that 6 multiplied by 4 would give the same result of 24.

Sadie arrived at the answer 10 for 6 + 4 by mistakenly swapping the order of the numbers and performing the addition incorrectly. The correct sum for 6 + 4 is indeed 10. Sadie's error demonstrates the importance of following the correct order of operations, where addition should be performed after ensuring the numbers are in the correct order.

As for Sadie's answer of 6 + 4 = 10, it is not directly related to the multiplication fact that Matt knows.

It is possible that Sadie used a different math fact or strategy to arrive at that answer.

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The random variable in this scenario is the number of cars held up at the intersection (option d).

The data provided in the table shows the number of cars held up at the intersection during specific time intervals, ranging from 12:00 p.m. to 9:00 p.m. Based on this information, it is clear that the random variable in this scenario is the number of cars held up at the intersection.

To put it in mathematical terms, let X be the random variable representing the number of cars held up at the intersection during a specific time interval. The data provided in the table represents a sample of X, with each time interval being a different observation. The values of X can range from 0 to 25, with 17 being the threshold for intervention by a traffic officer.

Therefore, the answer to the question is d. the number of cars held up at the intersection. It is important to note that this random variable is discrete, as it takes on specific integer values.

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The answer is  (3.25, 2.75)

To find point B, we can use the fact that AB and BC form a 1:3 ratio. Let's start by finding the coordinates of point B.

First, we need to find the distance between A and C. We can use the distance formula for this:

[tex]d = \sqrt{ ((x2 - x1)^2 + (y2 - y1)^2)[/tex]

where  [tex](x1, y1) = (4, 2)[/tex]  and [tex](x2, y2) = (1, 5)[/tex]

[tex]d = \sqrt{((1 - 4)^2 + (5 - 2)^2)} = \sqrt{(9 + 9)} = \sqrt{(18)}[/tex]

Next, we need to find the distance between A and B, which we'll call x, and the distance between B and C, which we'll call 3x (since AB and BC are in a 1:3 ratio).

Using the distance formula for AB:

[tex]x = \sqrt{\\((x2 - x1)^2 + (y2 - y1)^2)[/tex]

where [tex](x1, y1) = (4, 2)[/tex] and [tex](x2, y2) = (Bx, By)[/tex]

[tex]x = \sqrt{((Bx - 4)^2 + (By - 2)^2)[/tex]

Using the distance formula for BC:

[tex]3x = \sqrt{((x2 - x1)^2 + (y2 - y1)^2)[/tex]

where [tex](x1, y1) = (1, 5)[/tex] and [tex](x2, y2) = (Bx, By)[/tex]

[tex]3x = \sqrt{((Bx - 1)^2 + (By - 5)^2)[/tex]

Now we can set up an equation using the fact that AB and BC are in a 1:3 ratio:

[tex]x / 3x = 1 / 4[/tex]

Simplifying this equation, we get:

[tex]4x = 3(AB)[/tex]

[tex]4x = 3\sqrt{((Bx - 4)^2 + (By - 2)^2)[/tex]

And

[tex]9x = \sqrt{((Bx - 1)^2 + (By - 5)^2)[/tex]

Now we have two equations and two unknowns (Bx and By). We can solve for Bx in the first equation and substitute into the second equation:

[tex]Bx = (3\sqrt{((Bx - 4)^2 + (By - 2)^2))} / 4[/tex]

[tex]9x = \sqrt{((Bx - 1)^2 + (By - 5)^2)[/tex]

[tex]81((Bx - 4)^2 + (By - 2)^2) / 16 = (Bx - 1)^2 + (By - 5)^2[/tex]

Expanding the squares and simplifying, we get:

[tex]81Bx^2 - 648Bx + 1245 = 16Bx^2 - 32Bx + 266[/tex]

[tex]65Bx^2 - 616Bx + 979 = 0[/tex]

Using the quadratic formula, we get:

[tex]Bx = (616 ± \sqrt{(616^2 - 4(65)(979)))} / (2(65))[/tex]

[tex]Bx = (616 ± \sqrt{(223456))} / 130[/tex]

[tex]Bx = 3.25[/tex] or [tex]Bx = 10.2[/tex]

We can eliminate the solution Bx ≈ 10.2 because it is outside the segment AC. Therefore, the solution is:

B = (3.25, 2.75)

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To add one number to each column of the table and make it show a function, we need the specific table or information about the columns to provide a precise answer.

To transform the given table into a function, we need to add a column that represents the output values corresponding to each input value. A function relates each input value to a unique output value.

Here is an example of how the table could be modified to represent a function:

Input (x) Output (y)

1             3

2               5

3             7

4            9

In this modified table, the output values (y) are obtained by adding 2 to each input value (x). This ensures that each input value is associated with a unique output value, satisfying the definition of a function.

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The probability of selecting an M&M that is not red is 11/15.To find the probability of selecting an M&M that is not red, we need to first find the total number of M&Ms in the bag,

It is the sum of the number of M&Ms of each color: 4 + 8 + 6 + 12 = 30.

Next, we need to find the number of M&Ms that are not red, which is the sum of the number of M&Ms of all other colors: 4 + 6 + 12 = 22.

Therefore, the probability of selecting an M&M that is not red is 22/30, which can be simplified by dividing both the numerator and the denominator by 2:

22/30 = 11/15

So the probability of selecting an M&M that is not red is 11/15.

In other words, there is an 11/15 chance that the selected M&M will be blue, orange, or green, and a 4/15 chance that it will be red.It is important to note that this assumes that each M&M is equally likely to be selected, and that the bag is well-mixed so that each M&M has an equal chance of being chosen.

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Using mathematical operations, each box of a dozen donuts should cost $3.40.

The basic mathematical operations used to determine the cost of a dozen donuts include multiplication and addition.

Firstly, the total cost of 12 donuts is computed by multiplication, while the total cost of the donuts per box (including the cost of the box) is obtained by addition.

1 dozen = 12 donuts

The cost unit of a donut = $0.27

The total cost of donuts = $3.24 ($0.27 x 12)

The cost per square foot of cardboard = $0.16

The total cost of a dozen donuts and the box = $3.40 ($3.24 + $0.16)

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Answer:is 230

Step-by-step explanation:

230 i hoped i helped

The triangle has two sides with equal lengths (AB and AC) and one side with a different length (BC). This makes it an isosceles triangle.

Triangle ABC has vertices A(0,0), B(0,3), and C(3,0).

To determine the type of triangle, we can find the lengths of the sides using the distance formula:

AB = sqrt((0-0)^2 + (3-0)^2) = sqrt(0 + 9) = 3

BC = sqrt((3-0)^2 + (0-3)^2) = sqrt(9 + 9) = sqrt(18) = 3√2

AC = sqrt((3-0)^2 + (0-0)^2) = sqrt(9 + 0) = 3

The triangle has two sides with equal lengths (AB and AC) and one side with a different length (BC). This makes it an isosceles triangle.

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Answer:

The radius of the basketball is 20 cm.

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr^3, where V is the volume and r is the radius.

We are given that the volume of the basketball is 11488.2 cm, so we can set up the equation:

Simplifying, we get:

Dividing both sides by (4/3)π, we get:

Taking the cube root of both sides, we get:

Rounding to the nearest whole number, the radius of the basketball is 20 cm.

The inequalities for which the ordered pair (-1,-9) is a solution are a and b

From the question, we have the following parameters that can be used in our computation:

The inequality expression y> -5/4x-3 and the list of options

To determine the ordered pairs of the inequality expression, we set x = -1 and then calculate the value of y

Using the above as a guide, we have the following:

y > -5/4(-1) -3

Evauate

y > -1.75 -- this is false because -9 < -1.75

For the list of options, we have

Graph (a) True

Graph (b) True

Hence, the inequalities for which the ordered pair (-1,-9) is a solution are a and b

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The value of x and y is 11 and 4 respectively

A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also sometimes called inscribed quadrilateral.

A theorem in circle geometry states that the sum of opposite angles in a cyclic quadrilateral are supplementary. i.e they sum up to give 180.

10x + 16y+6 = 180

10x+16y = 174... eqn1

4+18y +10x-6 = 180

18y +10x = 182... eqn2

subtract equation 1 from 2

2y = 8

y = 8/2 = 4

Subtitle 4 for y in equation 1

10x+ 16(4)= 174

10x= 174-64

10x = 110

x= 110/10

x = 11

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The length of BC rounded to 3 significant figures is 6.98.

Since ∠cab = 90°, we can use the Pythagorean Theorem to find the length of AB.

Let's call BC = x, then we have:

sin(65°) = AB/BC

AB = sin(65°) * BC

In right triangle ABC, we have:

AB^2 + BC^2 = AC^2

(sin(65°) * BC)^2 + BC^2 = 8.9^2

Solving for BC, we get:

BC = 8.9 / sqrt(sin^2(65°) + 1)

BC ≈ 6.98

Therefore, the length of BC rounded to 3 significant figures is 6.98.

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The cone will hold approximately 198 cubic inches of water. The correct answer is option B.

To find how much water a cone with a diameter of 6 inches and a height of 21 inches will hold, we need to calculate the volume of the cone. We can use the formula for the volume of a cone: V = (1/3)πr^2h, where V is the volume, r is the radius, and h is the height.

1. Since the diameter is 6 inches, the radius (r) is half of that: r = 6/2 = 3 inches.

2. The height (h) is given as 21 inches.

3. Use 3.14 for π.

Now, plug the values into the formula:

V = (1/3) * 3.14 * (3^2) * 21

4. Calculate the square of the radius: 3^2 = 9

5. Multiply the values: (1/3) * 3.14 * 9 * 21 ≈ 197.64

6. Round the answer to the nearest whole number: 198 cubic inches.

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The human heart beats approximately 4.1975 x 10⁸ times in one year and it expressed in scientific notation.

According to the question, the average human heart beats 1.15 x 10⁵ times a day. We need to find out how many times the heart beats in one year, which is 3.65 x 10² days.

To calculate the total number of heartbeats in one year, we can multiply the number of heartbeats in a day by the number of days in a year. Therefore, we have:

Total number of heartbeats in one year = 1.15 x 10⁵ beats/day x 3.65 x 10² days/year

= (1.15 x 3.65) x (10⁵ x 10²) beats/year

= 4.1975 x 10⁸ beats/year

This number may seem large, but it is necessary for the heart to pump blood throughout the body to keep us alive and healthy.

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If An oil globe made of hand-blown glass of a diameter of 22.6. Therefore, the volume of the oil globe is approximately 5704.8 cm^3.

The volume of a spherical object can be calculated using the formula:

V = (4/3)πr^3

where V is the volume, π is the mathematical constant pi (approximately equal to 3.14159), and r is the radius of the sphere.

In this case, we are given the diameter of the oil globe, which is 22.6. The radius is half of the diameter, so we can calculate the radius as:

r = d/2 = 22.6/2 = 11.3 cm

Substituting this value of radius in the formula for the volume of a sphere, we get:

V = (4/3)π(11.3)^3

V = 5704.8 cm^3 (rounded to one decimal place)

Therefore, the volume of the oil globe is approximately 5704.8 cm^3.

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