A teacher bought a packet of 17 batteries. Each calculator uses 3 batteries. How many calculators can the teacher fill with batteries? *

Answer:

The correct option is (A). The first equation is for sample​ data; the second equation is for a population.

Step-by-step explanation:

According to the scenario, the following would be represented as a sample and the population

Y with caret = b0 + b1x = sample

and

y = b0 + b1x =  population

It is because if we considered the population than the expected value would be nearest and there is no need to determine the b0 and b1 value again. But in the case of the sample, the reestimation of the values would be determined again and again

Therefore the correct option is A.

The vertices of the image are R'(x, y) = (- 1, - 7), S'(x, y) = (4, - 7), T'(x, y) = (4, - 5) and V'(x, y) = (- 1, - 3).

In this question we know the locations of the four vertices of the trapezoid RSTV and we need to determine the coordinates of its image by using a reflection formula about an axis parallel to the y-axis, whose formula is described below:

P'(x, y) = P(x, y) - 2 · [P(x, y) - (p, k)]    

Where:

Now we proceed to find the coordinates of the images:

R'(x, y) = (- 1, 1) - 2 · [(- 1, 1) - (- 1, - 3)]

R'(x, y) = (- 1, 1) - 2 · (0, 4)

R'(x, y) = (- 1, 1) + (0, - 8)

R'(x, y) = (- 1, - 7)

S'(x, y) = (4, 1) - 2 · [(4, 1) - (4, - 3)]

S'(x, y) = (4, 1) - 2 · (0, 4)

S'(x, y) = (4, 1) + (0, - 8)

S'(x, y) = (4, - 7)

T'(x, y) = (4, - 1) - 2 · [(4, - 1) - (4, - 3)]

T'(x, y) = (4, - 1) - 2 · (0, 2)

T'(x, y) = (4, - 1) + (0, - 4)

T'(x, y) = (4, - 5)

V'(x, y) = (- 1, - 3) - 2 · [(- 1, - 3) - (- 1, - 3)]

V'(x, y) = (- 1, - 3) - 2 · (0, 0)

V'(x, y) = (- 1, - 3)

The vertices of the image are R'(x, y) = (- 1, - 7), S'(x, y) = (4, - 7), T'(x, y) = (4, - 5) and V'(x, y) = (- 1, - 3).

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Answer:

D

Step-by-step explanation:

Samuel pays 59.99 for the 450 minutes but when he goes over he pays 0.25 for each minute he goes over. The same thing for Monica

The correct option is D

Given that,

Based on the above information, the equation is as follows:

y = 59.99 + 0.25x

y = 64.99 + 0.10x

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Answer:

the graph that starts at (0,1) and has a rise/run of 1/3

Step-by-step explanation:

The increased percent and decreased percent of an item are not equal.

What is Percent formula?

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

Now,

Let the original price of an item = $100

After increased by $10,

Increased percent of an item = 10 * 10/100 = 10%

The new cost of an item = $100 + $10 = $110

After decreased by $10,

Decreased percent of an item = 10 * 10/110 = 9.1%

So, The increased percent and decreased percent of an item are not equal.

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Answer:

f= 3

Step-by-step explanation:

-12 = 4f-24

+24. +24

----------------

12 = 4f

/4. /4

-----------

f= 3

Answer:

3

Step-by-step explanation:

-12 = 4(f - 6)

-12/4 = (4(f - 6))/4

-3 = f - 6

-3 + 6 = f - 6 + 6

3 = f

Answer:

why the hell you got blobs in your bed?

Step-by-step explanation:

Answer:

[tex]\dfrac{2}{3}[/tex]

Step-by-step explanation:

Given that:

The number of observations is:

6, 10, 12

If we are to use a simple  random sampling without replacement, then we will have:

(6,10)  (6,12)  (10,12)

Here;

the sample size n = 2

The population size N = 3

For (6,10) ; The sample mean = [tex]\dfrac{6+10}{2}[/tex]

= [tex]\dfrac{16}{2}[/tex]

= 8

For (6,12) ; The sample mean = [tex]\dfrac{6+12}{2}[/tex]

= [tex]\dfrac{18}{2}[/tex]

= 9

For (10, 12) ; The sample mean = [tex]\dfrac{10+12}{2}[/tex]

= [tex]\dfrac{22}{2}[/tex]

= 11

The probability distribution of sample mean(x) is:

X           8           9          11

P(X=x)    [tex]\dfrac{1}{3}[/tex]          [tex]\dfrac{1}{3}[/tex]           [tex]\dfrac{1}{3}[/tex]

Thus, the probability that the sample mean  is larger than 8 is:

P(X> 8) = P(X = 9) + P(X + 11)

P(X> 8) = [tex]\dfrac{1}{3}+\dfrac{1}{3}[/tex]

P(X > 8) = [tex]\dfrac{1+1}{3}[/tex]

P(X> 8) = [tex]\dfrac{2}{3}[/tex]

Answer:

c. C

Step-by-step explanation:

byy byyy..........

This portion of the graph is completely flat, and has a slope of 0. The slope is the rate of change. Any horizontal line has a slope of 0 (we can use the slope formula to prove this). The term 'constant" means "it does not change".

In contrast, sections A, B, and D are all increasing sections because they go uphill as we move from left to right. The slopes of each line segment are positive.

Answer:

Yes, the given figure are similar but not congruent. All the edges are making angles of 90°.

Answer:

647$ USD

Step-by-step explanation:

You add 4% of each sale to eachother and to the 375. goodluck!

Answer:

7171

Step-by-step explanation:

i added it all up and thats what i got hope this helps and if right can i have brainlyest.

You will find it easiest if you write the integral in the form.

∫??∫??13 ,∫??∫??1r3drdθ ,that is, with θ on the "outside" integral. Looking at your diagram, the minimum θ value in the region of integration is =0θ=0, which occurs along the x axis. The maximum θ value occurs at the point (1,1)(1,1), giving =/4θ=π/4. So we have∫/40∫??13 .∫0π/4∫??1r3drdθ .For any fixed θ value, the values of r in the region go from the vertical line =1x=1 to the semicircle. At =1x=1 we have =secr=sec⁡θ as you have noted. The easiest way to get the maximum r value is to draw a line from the origin at angle θ until it hits the semicircle, and a line from there to (2,0)(2,0). Then you can see in the diagram a right-angled triangle (because the angle in a semicircle is a right angle) with hypotenuse 22, and so we get max=2cosrmax=2cos⁡θ. So the integral is∫/40∫2cossec13 .∫0π/4∫sec⁡θ2cos⁡θ1r3drdθ .For sketching the graph,=2−2‾‾‾‾‾‾‾√⇒2−2+2=0⇒(−1)2+2=1 ,y=2x−x2⇒x2−2x+y2=0⇒(x−1)2+y2=1 ,and not forgetting that ≥0y≥0.

The value of x that will make each of the parallelogram the given type is:

11. x = 6.5

12. x = 3

A parallelogram is any quadrilateral whose opposite sides are parallel and equal to each other.

Examples of a parallelogram include:

11. The diagonals of a square intersect at right angles, therefore:

13x + 5.5 = 90

13x = 90 - 5.5

13x = 84.5

x = 84.5/13

x = 6.5

12. The four sides of a rhombus are equal in length, therefore:

14 - x = 2x + 5

14 - 5 = 2x + x

9 = 3x

9/3 = x

x = 3

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Answer:

[tex]\frac{10a + 6}{-a^2 + 1}[/tex] is undefined at a = 1

Step-by-step explanation:

Required

Which is undefined at a = 1

An expression is undefined when its denonimator equals 0.

So, we have to test the denominator of each.

(A): 7a + 7

This gives:

[tex]= 7(1) + 7[/tex]

[tex]= 7 + 7[/tex]

[tex]= 14[/tex]

(B): 5a - 10

This gives:

[tex]= 5(1) - 10[/tex]

[tex]= 5- 10[/tex]

[tex]= -5[/tex]

(C) -a² + 1

This gives

[tex]-(1^2) + 1[/tex]

[tex]= -1 + 1[/tex]

[tex]=0[/tex]

(D) 3a²

This gives:

[tex]= 3(1)^2[/tex]

[tex]= 3 * 1[/tex]

[tex]= 3[/tex]

Notice that only (C) equals 0.

Hence:

[tex]\frac{10a + 6}{-a^2 + 1}[/tex] is undefined at a = 1

Answer:

C

Step-by-step explanation:

75,437

hope this helps

Answer:

I believe its hyperbola

Answer:

ellipse

Step-by-step explanation:

just got it right on edg ^u^

Answer:

12 and 24

Step-by-step explanation:

[tex]{ \tt{x = 2y - - - - (a)}} \\ { \tt{x + y = 36 - - - (b)}}[/tex]

Perform for eqn (b):

[tex]{ \tt{2y +y = 36}} \\ { \tt{3y = 36}} \\ { \tt{y = 12}}[/tex]

For x:

[tex]{ \tt{x = 2y}} \\ { \tt{x = 2 \times 12}} \\ { \tt{x = 24}}[/tex]

==========================================================

Explanation:

The mean of all ten numbers is 22.

This tells us the sum of those ten numbers is 10*22 = 220

Recall that

mean = (sum of items)/(number of items)

We take this process in reverse to find the sum.

In other words:

sum = (mean)*(number of items)

--------------

Now remove the elements {8,12,21,23} to get a new sum of:

220-8-12-21-23 = 156

Divide that smaller sum over 6 since removing 4 elements leaves us with 10-4 = 6 left over.

new mean = (new smaller sum)/(number of items)

new mean = (156)/(6)

new mean = 26

Answer:

B. [tex] \frac{60 hours}{1} \times \frac{1 day}{24 hours} [/tex]

Step-by-step explanation:

Converting 60 hours to days:

24 hours = 1 day

60 hours = x day

Cross multiply

[tex] 24 hours \times x = 60 hours \times 1 day [/tex]

Divide both sides by 24 hours

[tex] x = \frac{60 hours \times 1 day}{24 hours} [/tex]

Thus,

[tex] \frac{60 hours \times 1 day}{24 hours} = \frac{60 hours}{1} \times \frac{1 day}{24 hours} [/tex]

The expression that shows how to convert 60 hours to days is:

[tex] \frac{60 hours}{1} \times \frac{1 day}{24 hours} [/tex]

Answer:

The daily rate that maximizes the revenue is $40 and the maximum revenue is $9600

Step-by-step explanation:

Given

[tex]Rooms = 240[/tex]

[tex]Price= \$40[/tex]

[tex]Increment = \$2[/tex]

First, we calculate the revenue.

[tex]Revenue (r) = Price (p) * Number\ of\ Rooms(n)[/tex]

[tex]r = p*n[/tex]

Let x be the change in rate.

i.e.

For every 2x increment in price (p) i.e. p + 2x

There will be 4 fewer rooms (n) i.e. n - 4x

So, the revenue is updated as:

[tex]r = (p + 2x) * (n - 4x)[/tex]

[tex]Price = 40[/tex]

So:

[tex]r = (40 + 2x) * (n - 4x)[/tex]

[tex]Rooms = 240[/tex]

So:

[tex]r = (40 + 2x) * (240 - 4x)[/tex]

Expand

[tex]r = 40 * 240 - 40 * 4x + 2x * 240 - 2x*4x[/tex]

[tex]r = 9600 - 160x + 480x - 8x^2[/tex]

Reorder

[tex]r = -8x^2 - 160x + 480x + 9600[/tex]

[tex]r = -8x^2 +320x + 9600[/tex]

The maximum of a function is calculated as:

[tex]Max = -\frac{b}{2a}[/tex]

In: [tex]r = -8x^2 +320x + 9600[/tex]

[tex]a = -8[/tex]   [tex]b = 320[/tex]    [tex]c = 9600[/tex]

So:

[tex]Max = -\frac{b}{2a}[/tex]

[tex]Max = -\frac{320}{-8}[/tex]

[tex]Max = \frac{320}{8}[/tex]

[tex]Max = 40[/tex]

To get the maximum revenue;

Substitute 40 for x in [tex]r = -8x^2 +320x + 9600[/tex]

[tex]r = -8(40)^2 + 320 * 40 + 9600[/tex]

[tex]r = 9600[/tex]

The daily rate that maximizes the revenue is $40 and the maximum revenue is $9600

You should put a lot of the 26% as it is necessary

The simplified trigonometric expression is given as follows:

[tex]-sin{\theta}\tan{\theta}(1 - \csc{\theta})[/tex]

The expression is given by:

[tex]\frac{\cos{\theta}}{1 + \csc{\theta}} \times \frac{1 - \csc{\theta}}{1 - \csc{\theta}}[/tex]

Applying the subtraction of perfect squares at the denominator, we have that the expression is given by:

[tex]\frac{\cos{\theta}(1 - \csc{\theta})}{1 - \csc^2{\theta}}[/tex]

Applying an identity, we have that:

[tex]1 - \csc^2{\theta} = -\cot^2{\theta}[/tex]

Hence the expression is:

[tex]-\frac{\cos{\theta}(1 - \csc{\theta})}{\cot^2{\theta}}[/tex]

cot = cos/sin, hence:

[tex]-\frac{sin^2{\theta}(1 - \csc{\theta})}{\cos{\theta}}[/tex]

tan = sin/cos, hence the simplified expression is:

[tex]-sin{\theta}\tan{\theta}(1 - \csc{\theta})[/tex]

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Answer:

its d

Step-by-step explanation: