A teacher asked three different students to write the conditions that would result in a triangle. Which of the following students listed conditions that would result in more than one triangle?

John threw the javelin 3 standard deviations below the mean

An equation is an expression that shows how numbers and variables using mathematical operators.

The z score shows by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given that John threw 106 feet. The average throw was 130 ft. The standard deviation was 8 feet. Hence:

z = (106 - 130) / 8

z = -3

John threw 3 standard deviations below the mean

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Sine and cosine are both equivalent to x/y, depending on the angle of the point on the circle.

To find two trigonometric functions equivalent to the ratio x/y, we can use the unit circle. Let's assume that x and y are the coordinates of a point on the circle, where x represents the horizontal displacement, and y represents the vertical displacement.

From this, we can find that the sine of the angle that x and y make with the x-axis is y, and the cosine of that angle is x. Therefore, the two trigonometric functions equivalent to the ratio x/y are sine and cosine.

We can write this as sin(angle) = y/y and cos(angle) = x/y. It's important to note that the value of the angle depends on the position of the point on the unit circle.

So, sine and cosine are both equivalent to x/y, depending on the angle of the point on the circle.

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The probability P(2 or fewer) is 0.678.

To find the probability of 2 or fewer successes in a binomial experiment with 10 trials and a success probability of 0.2, we can use the binomial probability formula:

P(2 or fewer) = P(0) + P(1) + P(2)

where P(0), P(1), and P(2) represent the probabilities of getting 0, 1, or 2 successes, respectively.

P(0) = (10 choose 0) * 0.2^0 * 0.8^10 = 0.1074
P(1) = (10 choose 1) * 0.2^1 * 0.8^9 = 0.2684
P(2) = (10 choose 2) * 0.2^2 * 0.8^8 = 0.3020

Therefore,

P(2 or fewer) = 0.1074 + 0.2684 + 0.3020 = 0.6778

Rounded to at least three decimal places, the probability P(2 or fewer) is 0.678.

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The dilation is (x, y) → (2x, 2y). So, the correct answer is D).

Let the coordinates of point C be (x, y). Then, the distance from the origin to point C is given by the distance formula

OC = √(x² + y²)

The corresponding side lengths are

CG = 16 - x

CD = √((x - 0)² + (y - 0)²)

The scale factor is the ratio of corresponding side lengths

CG/CD = 2

Therefore,

16 - x = 2*√(x² + y²)

Solving for y, we get

y = √(13x² - 64x + 256)

If we assume that point G corresponds to point C, then the center of dilation is the origin and the rule that represents the dilation is

(x, y) → (2x, 2y)

Therefore, the answer is

(x, y) → (2x, 2y)

So, the correct answer is D).

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--The given question is incomplete, the complete question is given

" Quadrilateral ABCD is dilated about the origin into quadrilateral EFGH so that point G is located at (16,8). scale factor is 2.

Which rule represents the dilation?

Select one

(x, y) → (18x, 18y)

(x, y) → (x+8, y+4)

(x, y) → (12x, 12y)

(x, y) → (2x, 2y) "--

Answer:107

Step-by-step explanation:8*17-29=107 so our answer is 107

Answer:

40%

Step-by-step explanation:

[tex] \frac{48}{120} \times 100 = 40[/tex]

Answer:

40%

Step-by-step explanation:

To find out what percentage of 2 hours is 48 minutes, we need to first convert both values to the same unit of time, such as minutes.

2 hours is equal to 120 minutes (2 x 60).

So, the fraction of 2 hours that is represented by 48 minutes is:

48/120

Simplifying this fraction by dividing both the numerator and denominator by 12, we get:

4/10

Multiplying the numerator and denominator by 10 to convert this fraction into a percentage, we get:

40%

Therefore, 48 minutes is 40% of 2 hours.

The conversion is given as follows:

123 pounds per mile = 0.01 ounces per cm.

The conversion is obtained applying the proportions in the context of the problem.

There are 16 ounces in 1 pound, hence the number of ounces in 123 pounds is given as follows:

123 x 16 = 1968 ounces.

There are 5,280 feet in 1 mile, 12 inches in one feet and 2.54 cm in one inch, hence the number of cm is given as follows:

5280 x 12 x 2.54 = 160934.4 cm.

Hence the rate is given as follows:

1968/160934.4 = 0.01 ounces per cm.

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The circumference of the circle is 6.28 kilometers if the diameter of the circle is 2 kilometers and assuming the value of π is 3.14 kilometers.

The diameter of the circle = 2 kilometers

The circumference of a circle is calculated by using the formula,

C = π *d

where,

C = circumference of a circle

d = diameter of the circle

π = Constant value = 3. 14 Km

Substituting the above-given values into the equation, we get:

C = π*d

C = 3.14 x 2 km

C = 6.28 km

Therefore, we can conclude that the circumference of the circle is 6.28 kilometers.

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This is a binomial probability problem, where the number of trials (n) is 15, the probability of success (p) is 0.75, and we want to find the probability of at least 12 successes.

We can use the binomial probability formula to calculate this:

P(X >= 12) = 1 - P(X < 12)

P(X < 12) = sum[k=0 to 11] (n choose k) * p^k * (1-p)^(n-k)

where n choose k is the binomial coefficient, which represents the number of ways to choose k items out of n.

Using a calculator or statistical software, we can calculate:

P(X < 12) = sum[k=0 to 11] (15 choose k) * 0.75^k * 0.25^(15-k) = 0.0278 (rounded to four decimal places)

Therefore,

P(X >= 12) = 1 - P(X < 12) = 1 - 0.0278 = 0.9722

So the probability that the football player will kick at least 12 field goals in the next 15 tries is approximately 0.9722, or about 97.22%

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a) To express ∂z/∂u and ∂z/∂v as functions of u and v, we first need to express z directly in terms of u and v. We are given that:

z = tan^-1(x/y)

And that:

x = ucosv
y = usinv

Substituting these expressions for x and y into the equation for z, we get:

z = tan^-1((ucosv)/(usinv))
z = tan^-1(cotv)

Now we can use the chain rule to find ∂z/∂u and ∂z/∂v:

∂z/∂u = ∂z/∂cotv * ∂cotv/∂u
∂z/∂v = ∂z/∂cotv * ∂cotv/∂v

To find ∂cotv/∂u and ∂cotv/∂v, we use the quotient rule:

∂cotv/∂u = -cosv/u^2
∂cotv/∂v = -csc^2v

Substituting these into the chain rule expressions, we get:

∂z/∂u = (-cosv/u^2) * (1/(1+cot^2v))
∂z/∂v = (-csc^2v) * (1/(1+cot^2v))

Simplifying these expressions using trig identities, we get:

∂z/∂u = (-cosv/u^2) * (1/(1+(cosv/usinv)^2))
∂z/∂v = (-1/sinv^2) * (1/(1+(cosv/usinv)^2))

b) To evaluate ∂z/∂u and ∂z/∂v at (u,v) = (1.3, pi/6), we simply plug in these values into the expressions we derived in part (a):

∂z/∂u = (-cos(pi/6)/(1.3)^2) * (1/(1+(cos(pi/6)/(1.3*sin(pi/6)))^2))
∂z/∂v = (-1/sin(pi/6)^2) * (1/(1+(cos(pi/6)/(1.3*sin(pi/6)))^2))

Simplifying these expressions using trig functions, we get:

∂z/∂u = (-sqrt(3)/1.69^2) * (1/(1+(sqrt(3)/1.3)^2))
∂z/∂v = (-4) * (1/(1+(sqrt(3)/1.3)^2))

Plugging in the values and evaluating, we get:

∂z/∂u ≈ -0.5167
∂z/∂v ≈ -1.5045
To answer this question, we'll first express z directly in terms of u and v, and then apply the chain rule to find the partial derivatives ∂z/∂u and ∂z/∂v.

Given:
z = tan^(-1)(x/y)
x = u*cos(v)
y = u*sin(v)

First, let's express z in terms of u and v:
z = tan^(-1)((u*cos(v))/(u*sin(v)))

Now, we can simplify the expression:
z = tan^(-1)(cot(v))

Next, we'll find the partial derivatives using the chain rule:

a) ∂z/∂u:
Since z doesn't have a direct dependence on u, we have:
∂z/∂u = 0

b) ∂z/∂v:
∂z/∂v = -csc^2(v)

Now let's evaluate the partial derivatives at the given point (u,v) = (1.3, π/6):

∂z/∂u(1.3, π/6) = 0
∂z/∂v(1.3, π/6) = -csc^2(π/6) = -4

So, the partial derivatives at the given point are:
∂z/∂u = 0 and ∂z/∂v = -4.

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The probability of the spinner not landing on red and then landing on red is 7/64.

The probability chance that the spinner will not land on red then land on red is calculated as follows;

The probability of the spinner not landing on red is 1 - 1/8 = 7/8.

To find the probability that the spinner will not land on red and then land on red, we multiply the probabilities:

(7/8) x (1/8) = 7/64

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Yes, there is reason to doubt the randomness of the jury selection based on the information provided.

Given data:

Out of the 20 potential jurors, 8 were African American and 12 were white. The probability of randomly selecting an African American juror from the pool of potential jurors would ideally be 8/20, which simplifies to 2/5 or 40%. However, the actual jury selected had only 1 African American member out of 6 jurors, which is significantly lower than the expected 40% if the selection were truly random.

This deviation from the expected probability raises questions about the randomness of the selection process. The observed outcome appears to be disproportionately skewed against the representation of African American jurors. While random variations can occur, the extent of the deviation in this case warrants further investigation into the jury selection process to determine if there were any biases or factors influencing the outcome.

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the formula for ak, we can set up a system of linear equations using the given values for ao, aj, and Ak+1.

Let x = ak-1 and y = ak. Then we have:

2 = a0 = x
4 = a1 = y
Ak+1 = 10ak-1 + 9ak

Substituting x and y, we get:

Ak+1 = 10(2) + 9(4) = 56

So we have the system of equations:

x = 2
y = 4
y = 10x + 9y

Rewriting the third equation, we get:

-10x + y = 0

Adding the first two equations, we get:

x + y = 6

Solving this system of equations, we get:

x = 2
y = 4

Therefore, ak = 4 for all k > 0.

To find lim kak, we can use the formula for ak:

lim kak = lim 4 = 4

So the limit of ak as k approaches infinity is 4.
To find the formula for a_k using linear algebra, we can first form a system of linear equations using the given recurrence relation:

a_(k+1) = 10a_(k-1) + 9a_k

Since we know a_0 = 2 and a_1 = 4, we can start by finding a_2:

a_2 = 10a_0 + 9a_1 = 10(2) + 9(4) = 20 + 36 = 56

Next, we can find a_3 using a_1 and a_2:

a_3 = 10a_1 + 9a_2 = 10(4) + 9(56) = 40 + 504 = 544

Now, we can represent this system of linear equations in matrix form:

[ [ 1  0 ]   [ a_0 ]   [  2 ]
 [ 0  1 ] * [ a_1 ] = [  4 ]
 [ 10 9 ] * [ a_2 ] = [ 56 ]  
 [ 10 9 ] * [ a_3 ] = [ 544 ] ]

We can then use methods of linear algebra such as Gaussian elimination, Cramer's rule, or matrix inversion to solve the system and find a_k.

However, this particular system does not provide a direct formula for a_k. Moreover, as the given information doesn't suggest a converging series, we cannot determine the limit as k approaches infinity (lim k→∞ a_k).

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Answer: $108,972

Step-by-step explanation:

To find the current value of Lawrence's condominium, we need to calculate the 8% increase in value over the past 2 years.

First, find the increase in value:

$100,900 * 0.08 = $8,072

Next, add this increase to the original price:

$100,900 + $8,072 = $108,972

So, the current value of Lawrence's condominium is $108,972.

Evaluating an exponential function A(x) = 160*(1.03)ˣ we can see that in 30 years she will have:

$388.36

We know that the initial investment is 160, and the rate per year is 3%.

Then after x years, the value is given by the exponential function.

A(x) = 160*(1.03)ˣ

The amount of money in the account after 30 years is what we get if we evaluate the equation in x = 30, then we will get:

A(30) = 160*(1.03)³⁰

A(30) = 388.36

In 30 years she will have a total amount of 388.36 dollars.

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Possible options for z could be:

1) z = -6

2) z = -7

These are two possible options for z that satisfy the given inequality.

Given that the opposite of z is greater than 5, we can write this as an inequality:

-z > 5

To find the possible options for z, we can follow these steps:

Step 1: Multiply both sides of the inequality by -1 to solve for z. Remember to flip the inequality sign when multiplying by a negative number:

z < -5

Step 2: Choose two values for z that satisfy the inequality z < -5.

Possible options for z could be:

1) z = -6
2) z = -7

These are two possible options for z that satisfy the given inequality.

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Since G is a cyclic group of order m, there exists an element g in G such that the subgroup generated by g contains all elements of G. We denote this subgroup by <g>. The order of <g> is equal to the order of g, which is a divisor of m. Hence, there exists an integer k such that m = kg.

Now, consider the element [tex]g^{(k/d)[/tex]. Since ([tex]g^k[/tex]) generates G and d is a divisor of k, ([tex]g^k/d[/tex]) is an element of <g>. Therefore, the subgroup generated by [tex]g^{(k/d)[/tex] is a subgroup of <g> with order d.

To show that this subgroup has order d, suppose that there exists an integer r such that [tex](g^{(k/d)})^r[/tex] = [tex]g^{(kr/d)[/tex] = e, where e is the identity element of G. This means that kr/d is an integer multiple of k, which implies that r is a multiple of d. Thus, the order of [tex]g^{(k/d)[/tex] is d, and the subgroup generated by [tex]g^{(k/d)[/tex] has order d.

Therefore, we have shown that if G is a cyclic group of order m and d | m, then G must have a subgroup of order d, which is generated by an element of the form [tex]g^{(k/d)[/tex], where g is a generator of G and m = kg.

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a = 5

b = 4

c= 0

Therefore, the equation for graph C is Y = a ^b + c

Y = 5 ^4 + 0

A graph is described as a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.

Graphs are a popular tool for graphically illuminating data relationships. A graph serves the purpose of presenting data that are either too numerous or complex to be properly described in the text while taking up less room.

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The gradient of line A and B are 4 and - 2 respectively.

The gradient or slope of a line is a the change in the dependent variable with respect to the change in the independent variable.

Therefore, let's find the gradient of line a and b as follows:

(2, -1)(3, 3)

Gradient  of line A = 3 + 1 / 3 - 2

Gradient  of line A = 4 / 1

Gradient  of line A = 4

Therefore,

(0, 1)(1, -1)

Gradient  of line B = -1 - 1 / 1 - 0

Gradient  of line B =  - 2 / 1

Gradient  of line B = - 2

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The nearest tenth how many miles is alshleys house from Bridget house is  AB = √[(xB-xA)² + (yB-yA)²]

The nearest tenth how many miles is Ashley’s house from carlys house is AC = √[(xC-xA)² + (yC-yA)²]

The distances from Ashley's house to both Bridget's house and Carly's house, we can compare them and see which one is shorter.

To find the distance between Ashley's house and Bridget's house, we need to know the coordinates of both locations. Let's say Ashley's house is located at point A, and Bridget's house is located at point B. We can use the distance formula to find the distance between A and B:

distance AB = √[(xB-xA)² + (yB-yA)²]

Here, xA and yA represent the coordinates of Ashley's house, and xB and yB represent the coordinates of Bridget's house. The formula calculates the square root of the sum of the squares of the differences between the x-coordinates and y-coordinates of the two points.

To find the distance between Ashley's house and Carly's house, we again need to know the coordinates of both locations. Let's say Ashley's house is located at point A, and Carly's house is located at point C. We can use the same distance formula as before:

distance AC = √[(xC-xA)² + (yC-yA)²]

Here, xC and yC represent the coordinates of Carly's house. Plug in the values and calculate the distance to the nearest tenth of a mile.

To determine whose house Ashley lives closest to, we need to calculate the distances from Ashley's house to both Bridget's house and Carly's house. Whichever house has the shorter distance will be the closer one.

To find the difference between the two distances, we can subtract the smaller distance from the larger distance.

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Answer:

17.1

Step-by-step explanation:

a. FA5.6₁₆ = 15x16² + 10x16 + 5 + 6/16 = 4005.375₁₀

b. 725.38₁₀ remains the same in decimal form

c. 3F4.8₁₆ = 3x16² + 15x16 + 4 + 8/16 = 1012.5₁₀

d. 73.25₈ = 7x8 + 3 + 2/8 = 59.3125₁₀

e. FF.F0₁₆ = 15x16 + 15 + 15/16 + 0/256 = 255.9375₁₀

Decimal form is a way of representing numbers using the base 10 number system. In this system, there are 10 digits from 0 to 9 that are used to represent all possible numbers. Each digit in a decimal number has a place value that is determined by its position. The rightmost digit represents units, the next digit to the left represents tens, and so on, with each successive digit representing higher powers of 10.

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Answer:

f(-2) = 9

Step-by-step explanation:

f(x) = -3x + 3                       Solve for f(-2)

f(-2) = -3(-2) + 3

f(-2) = 6 + 3

f(-2) = 9

To find the population at any given term n, continue to apply the recursive rule.
Pₙ = Pₙ₋₁ + 50
Using this recursive rule and the initial population, you can find the population at any given term n.

We are given a population growth model with a recursive rule and an initial population. Let's break down the information and find the population at any given term n.

Recursive rule: Pₙ = Pₙ₋₁ + 50
Initial population: P₀ = 30

Now let's find the population at any term n, using the recursive rule:

Step 1: Determine the base case, which is the initial population.
P₀ = 30

Step 2: Apply the recursive rule to find the next few terms.
P₁ = P₀ + 50 = 30 + 50 = 80
P₂ = P₁ + 50 = 80 + 50 = 130
P₃ = P₂ + 50 = 130 + 50 = 180

Step 3: To find the population at any given term n, continue to apply the recursive rule.
Pₙ = Pₙ₋₁ + 50

Using this recursive rule and the initial population, you can find the population at any given term n.

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The perimeter and area of the shape is 18cm² and 12cm respectively.

The perimeter of a shape is the total measurement of all the edges of a shape. Area is defined as the total space taken up by a flat (2-D) surface or shape of an object.

The perimeter of the shape = 4+4+5+5 = 8 +10

= 18cm.

The area of the shape is = b×h

the base = 4cm and height is 3cm

A = 4× 3

= 12cm²

therefore the perimeter and the area of the shape is 18cm² and 12cm² respectively.

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The most appropriate domain for Spencer's table would be D. all whole numbers.

To explain this, let's first understand the terms involved. In this context, the domain refers to the set of possible input values (x) for the function, which in this case, represents the number of people attending the school basketball game.

Option A, all integers, includes negative numbers, which are not suitable as you cannot have a negative number of people. Option B, all rational numbers, comprises fractions, which are also not applicable because you cannot have a fraction of a person attending the game. Option C, all real numbers, consists of all numbers including irrational numbers like π, which are not relevant in this context as well.

Option D, all whole numbers, represents the most suitable domain as it includes all non-negative integers (0, 1, 2, 3, ...). This set accurately represents the possible number of people attending the game, since you can have zero or a whole number of people attending but not negative or fractional values.

Therefore, Spencer should use whole numbers as the domain for his table to relate the number of people (x) to the money made from ticket sales (y).

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