A student who is 5ft tall and cast a shadow 8ft long.at the Same time a flag shadow is 24ft long.how long is the flag?

Answer:

25p^2 + 4 + 20p

Step-by-step explanation:

(5p + 2)^2 = (5p)^2 + (2)^2 + 2 × 5p × 2

= 25p^2 + 4 + 20p

Answer:

Step-by-step explanation:

The minute hand of a clock overtakes the hour hand at intervalsof M minutes of correct time. The clock gains or loses in a day by=(720/11−M)(60×24/M) minutes.

Here M = 64. The clock gains or losses in a day by

=(720/11−M)(60×24/M)=(720/11−64)(60×24/64)

=16/11(60×3/8)=2/11(60×3)=360/11=32(8/11) minutes.

Answer:

0.09

0.55

Step-by-step explanation:

to write least to greatest firstly, start comparing both number

so the answer will be=0.09,0.55

it least to greatest or in assending order.

Answer:

0.8185 or 81.85%

Step-by-step explanation:

The mean length (μ) of an adult foot is 11 and the standard deviation (σ) is 1.5.

The z score is a measure in statistic used to determine the amount of standard deviation by which the raw score (x) is above or below the mean. If the raw score is above the mean, the z score is positive  and if the raw score is below the mean the z sore is negative. It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

To calculate the probability that a randomly selected male will have a foot length between 8 and 12.5 inches, we first calculate the z score for 8 inches and then for 12.5 inches.

For 8 inches:

[tex]z=\frac{x-\mu}{\sigma}=\frac{8-11}{1.5}=-2[/tex]

For 12.5 inches:

[tex]z=\frac{x-\mu}{\sigma}=\frac{12.5-11}{1.5}=1[/tex]

From the normal distribution table, The probability that a randomly selected male will have a foot length between 8 and 12.5 inches = P(8 < x < 12.5) = P(-2 < z < 1) = P(z < 1)  - P(z < -2) = 0.8413 - 0.0228 = 0.8185 = 81.85%

Answer:

19.5 km

Step-by-step explanation:

the actual distance between Harry and the Sea view:

if 24 km is 5 cm on map

24*4/5= 19.5 km

Answer:

$24 will be the cost of tennis racquet with weight 25 oz.

Step-by-step explanation:

Given that Price of racquet is inversely proportional to its weight.

i.e.

[tex]Price \propto \dfrac{1}{Weight}[/tex]

We can replace the proportional sign with a constant of proportionality.

[tex]Price = \dfrac{C}{Weight}[/tex]

Where C is a constant named as constant of proportionality.

Given that cost of 20 oz. racquet is $30.00

Putting both the values :

[tex]30 = \dfrac{C}{20}\\\Rightarrow C = 600[/tex]

So, the equation becomes:

[tex]Price = \dfrac{600}{Weight}[/tex]

Now, we have to find the price of 25 oz. racquet.

Putting Weight = 25 oz and finding Price:

[tex]Price = \dfrac{600}{25}\\\Rightarrow Price = \$24[/tex]

So, $24 will be the cost of tennis racquet with weight 25 oz.

4/25

Step-by-step explanation:

16/100, 8/50, 4/25

Answer:

Step-by-step explanation:

Area of shaded region it is area of hexagon minus area of circle.

A regular hexagon is comprised of six equilateral triangles (of the same sides).

So its area:  [tex]A_1=6\cdot\dfrac{S^2\sqrt3}{4}=\dfrac{3S^2\sqrt3}2[/tex]     {S = side of the triangle}

Height (H) of such a triangle is equal to radius (R) of a circle inscribed in the hexagon:

[tex]R = H = \dfrac{S\sqrt3}{2}[/tex]

Area of shaded region:

[tex]A=A_1-A_\circ=\dfrac{3S^2\sqrt3}2-\pi R^2=\dfrac{6S^2\sqrt3}4-\pi\left(\dfrac{S\sqrt3}2\right)^2=\dfrac{S^2(6\sqrt3-3\pi)}4[/tex]

S = 6 cm

so:

[tex]A=\dfrac{6^2(6\sqrt3-3\pi)}4=\dfrac{36(6\sqrt3-3\pi)}4=9(6\sqrt3-3\pi)=27(2\sqrt3-\pi)\ cm^2\\\\A=27(2\sqrt3-\pi)\ cm^2\approx8.71\ cm^2[/tex]

Answer:

The answer is 45 inches².

Step-by-step explanation:

First, you have to find the area of each triangle:

[tex]area = \frac{1}{2} \times base \times height[/tex]

[tex]let \: base = 3 \\ let \: height = 6[/tex]

[tex]area = \frac{1}{2} \times 3 \times 6[/tex]

[tex]area = \frac{1}{2} \times 18[/tex]

[tex]area = 9 \: \: {inches}^{2} [/tex]

Assuming that the formula for surface area of pyramid is Surface area = base area(area of square) × 4(area of triangle):

[tex]base \: area = 3 \times 3 = 9[/tex]

[tex]area \: of \: triangle = 9[/tex]

[tex]s.a = 9 + 4(9)[/tex]

[tex]s.a = 9 + 36[/tex]

[tex]s.a = 45 \: \: {inches}^{2} [/tex]

Answer:

A

Step-by-step explanation:

Answer:

For the first one, answer is dilation of 2

Step-by-step explanation:

you see the coordinates for triangle A'B'C' are all doubled the coordinates of triangle ABC

Answer:

The width is 23.5 ft and the length is 47 ft

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

141 = 2(l+w)

The length is twice the width

l = 2w

141 = 2 ( 2w+w)

141 = 2( 3w)

141 = 6w

Divide each side by 6

141/6 = 6w/6

23.5 = w

l = 2w = 2(23.5) = 47

The width is 23.5 ft and the length is 47 ft

Answer:

[tex]\boxed{Width = 23.5 \ feet}[/tex]

[tex]\boxed{Length = 47 \ feet}[/tex]

Step-by-step explanation:

Let Length be l and Width be w

Perimeter = 2(Length) + 2(Width)

Condition # 1:

2l+2w = P

=> 2 l + 2 w = 141

Condition # 2:

=> l = 2w

Putting the second equation in the first one

=> 2(2w)+2w = 141

=> 4w + 2w = 141

=> 6w = 141

Dividing both sides by 6

=> Width = 23.5 feet

Given that

=> l = 2w

=> l = 2(23.5)

=> Length = 47 feet

Answer:

x = 56 degrees

y = 62 degrees

Step-by-step explanation:

Given TS || PR

x = 56    ................. corresponding angles TS, PR parallel sides of trapezium.

VSK = x ...................... correspoinding angles given TU || SV

y = 118 - VSK          .......... given VSR = 118

= 118 - 56

= 62

Answer:

The coordinates are;

For reflection over the x-axis

A'(-8, 2)

B'(-4, 3)

C'(-2, 8)

D'(-10, 6)

For reflection over the y-axis;

A''(8, 2)

B''(4, 3)

C''(2, 8)

D''(10, 6)

Step-by-step explanation:

When a point (x, y) is reflected over the x, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (x, -y)

Therefore, for the points A, B, C, D we have;

Pre-image A(-8, -2), Image A'(-8, 2)

Pre-image B(-4, -3), Image B'(-4, 3)

Pre-image C(-2, -8), Image C'(-2, 8)

Pre-image D(-10, -6), Image D'(-10, 6)

When a point (x, y) is reflected over the y, axis, we have;

Coordinates of the pre-image = (x, y)

Coordinates of the image after reflection = (-x, y)

Therefore, for the points A', B', C', D' we have;

Pre-image A'(-8, 2), Image A''(8, 2)

Pre-image B'(-4, 3), Image B''(4, 3)

Pre-image C'(-2, 8), Image C''(2, 8)

Pre-image D'(-10, 6), Image D''(10, 6).

Answer:

233.37

Step-by-step explanation:

so between each gondola is 20.95 so you will multiply it by 35 not 36 (because between the first you go round and come back to the same first you started so no space between first and last) then get circumference as 733.25 using

[tex]c = \pi \: d[/tex]

you get diameter

Answer:

b. Contains four right angles.

Step-by-step explanation:

A parallelogram has two pairs of opposite sides that are both congruent and parallel, as does a rectangle.

A parallelogram usually does NOT have four right angles, but a rectangle does. b Contains four right angles is the difference between a parallelogram and a rectangle.

The diagonals of a parallelogram bisect each other, and so do the rectangle's diagonals.

The opposite angles of parallelograms are congruent, and all four angles of a rectangle are congruent, so this is a similar aspect of both a parallelogram and a rectangle.

Hope this helps!

Answer:

Part 1: 359,007 ft³

Part 2: 216 times smaller

Part 3: 21600%

Step-by-step explanation:

Part 1:

The parameters for the tank are;

The radius of the tank = 70 feet

The volume of a sphere = 4/3·π·r³

Therefore, the volume of a quarter sphere = 1/4×The volume of a sphere

The volume of a quarter sphere = 1/4×4/3·π·r³ = π·r³/3

Plugging in the value for the radius gives

Volume = π×70³/3 = 114,333.33×3.14 = 359,006.7≈ 359,007 ft³.

Part 2:

The dimension of the scale model  = 1/6 × Actual dimension

Therefore, we have the radius of the sphere of the scale model = 1/6 × 70

Which gives;

The radius of the sphere of the scale model = 35/3 = 11.67 feet

The volume of the scale model = π·r³/3 = (3.14×11.67³)/3 = 1662.07 ≈ 1662 ft³

The number of times smaller the scale model is than the actual volume = (Actual volume)/(Scale model) = (359,007 ft³)/(1662 ft³) = 216 times

The number of times smaller the scale model is than the actual volume =  216 times = (1/Scale of model)³ = (1/(1/6))³ = 6³.

Part 3:

The percentage of the mock-up, x, to the volume of the actual tank is given as follows

x/100 ×  1662  = 359,007

∴ x = 216 × 100 = 21600%

The percentage of the mock-up, to the volume of the actual tank is 21600%.

Answer:

Part 1: 359,007 ft³

Part 2: 216 times smaller

Part 3: 21600%

Step-by-step explanation:

Part 1:

The parameters for the tank are;

The radius of the tank = 70 feet

The volume of a sphere = 4/3·π·r³

Therefore, the volume of a quarter sphere = 1/4×The volume of a sphere

The volume of a quarter sphere = 1/4×4/3·π·r³ = π·r³/3

Plugging in the value for the radius gives

Volume = π×70³/3 = 114,333.33×3.14 = 359,006.7≈ 359,007 ft³.

Part 2:

The dimension of the scale model  = 1/6 × Actual dimension

Therefore, we have the radius of the sphere of the scale model = 1/6 × 70

Which gives;

The radius of the sphere of the scale model = 35/3 = 11.67 feet

The volume of the scale model = π·r³/3 = (3.14×11.67³)/3 = 1662.07 ≈ 1662 ft³

The number of times smaller the scale model is than the actual volume = (Actual volume)/(Scale model) = (359,007 ft³)/(1662 ft³) = 216 times

The number of times smaller the scale model is than the actual volume =  216 times = (1/Scale of model)³ = (1/(1/6))³ = 6³.

Part 3:

The percentage of the mock-up, x, to the volume of the actual tank is given as follows

x/100 ×  1662  = 359,007

∴ x = 216 × 100 = 21600%

The percentage of the mock-up, to the volume of the actual tank is 21600%.

Answer:

0

Step-by-step explanation:

Answer: it's C. 0

Also Happy early Christmas

Answer:

These are two equilateral triangles and all the sides of an equilateral triangle are equal. The question even says so so that's the answer, all the sides of the equilateral triangles are equal so all the sides equate to each other

Answer:

ABC≅DEF

x = 2

CB = 3

FE = 4

y = 5

ED = 6

FD = 7

AB = 8

AC = 9

In triangle ABC=

Side AC= 9 cm

Side CB= 3 cm

Area= [tex]\frac{1}{2}[/tex]×[tex]b[/tex]×[tex]h[/tex]

        =13.5 cm^2

In triangle DEF=

Side FE= 4 cm

Side FD= 7 cm

Area= [tex]\frac{1}{2}[/tex]×[tex]b[/tex]×[tex]h[/tex]

        =14 cm^2

Answer:

if it takes 4 people for 2 days

4+4= 8

so it would only take 8 people for 1 day

Answer:

1 day

Step-by-step explanation:

4 people = 2 days

→ Work out how long 1 person takes

4 people = 2 days

( ÷ 4 )            ( × 4 )

1 person = 8 days

→ Work out how long 8 people can do it

1 person = 8 days

( × 8 )            ( ÷ 8 )

8 people = 1 day

Answer:

what expressions?

Step-by-step explanation:

Answer:

i need help this too

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given,

x = 5

Now, let's find the value of C

[tex]c = 3x - 2[/tex]

plug the value of x

[tex] = 3 \times 5 - 2[/tex]

Multiply the numbers

[tex] = 15 - 2[/tex]

Calculate the difference

[tex] = 13[/tex]

Hope this helps..

Best regards!!

Answer:

You havent showed us the pattern

Answer:

The height of the rider as a function of time is [tex]h(t) = 15 + 82.5\cdot (1-\cos 0.168t) \,[ft][/tex], where time is measured in seconds.

Step-by-step explanation:

Given that Ferris wheel rotates at constant rate and rider begins at the bottom of the wheel, the height of the rider as a function of time is modelled after this expression:

[tex]h(t) = h_{bottom} + (1-\cos \omega t)\cdot r_{w}[/tex]

Where:

[tex]h_{bottom}[/tex] - Height of the bottom with respect to ground, measured in feet.

[tex]\omega[/tex] - Angular speed of the ferris wheel, measured in radians per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]r_{w}[/tex] - Radius of the Ferris wheel, measured in feet.

The angular speed of the ferris wheel, measured in radians per second, is obtained from the following expression:

[tex]\omega = \frac{\pi}{30}\cdot \dot n[/tex]

Where:

[tex]\dot n[/tex] - Angular speed of the ferris wheel, measured in revolutions per minute.

If [tex]\dot n = 1.6\,rpm[/tex], then:

[tex]\omega = \frac{\pi}{30}\cdot (1.6\,rpm)[/tex]

[tex]\omega \approx 0.168\,\frac{rad}{s}[/tex]

Now, given that [tex]h_{bottom} = 15\,ft[/tex], [tex]r_{w} = 82.5\,ft[/tex] and [tex]\omega \approx 0.168\,\frac{rad}{s}[/tex], the height of the rider as a function of time is:

[tex]h(t) = 15 + 82.5\cdot (1-\cos 0.168t) \,[ft][/tex]

Explanation:

The flat horizontal portion S is where the distance (y) does not increase or decrease. So Ted is stationary during this time frame.

In terms of speed, we would say speed = distance/time = (change in y)/(change in x). Note how this is the slope.

Rise = 0 because the horizontal line does not go up or down. The run is any positive number, though convention usually has Run = 1. Therefore, slope = rise/run = 0/1 = 0. All flat horizontal lines have a slope of 0 to indicate no upward or downward movement.

Answer:

Step-by-step explanation:

–3(6 – 2x) ≥ 4x + 12

Expand the terms in the bracket

We have

- 18 + 6x ≥ 4x + 12

Group like terms

that's

6x - 4x ≥ 12 + 18

2x ≥ 30

Divide both sides by 2

x ≥ 15

Hope this helps you

Step-by-step explanation:

no worries

if u multiply by a negative number the sign changes

so it can -18 + 6x <= 4x + 12

take x to one side and others to other side

6x - 4x <= 18 + 12

2x <= 30

x<= 15

so solutions can be from ....-2,-1,0,1,2,3....

Answer:

(3,2)

Step-by-step explanation:

Just took the test

Answer:

20

Step-by-step explanation:

20 + (75% × 20) =

20 + 75% × 20 =

(1 + 75%) × 20 =

(100% + 75%) × 20 =

175% × 20 =

175 ÷ 100 × 20 =

175 × 20 ÷ 100 =

3,500 ÷ 100 =

35;

Answer:

x = 3

y = -2

Step-by-step explanation:

x + 2y + 1 = 0

2x - 3y - 12 = 0

Multiply first equation by -2.

-2x + -4y + -2 = 0

2x - 3y - 12 = 0

Add equations.

0x + -7y - 14 = 0

Solve for y.

-7y = 14

y =-2

Put y as -2 in the first equation and solve for x.

x+2(-2)+1=0

x + -4 + 1 = 0

x = 0 + 4 - 1

x = 3

Answer:

[tex]\boxed{x = 3, y = -2}[/tex]

Step-by-step explanation:

[tex]x+2y +1 = 0[/tex]

=> [tex]x+2y = -1[/tex] -------------------(1)

[tex]2x-3y-12 = 0[/tex]

=> [tex]2x-3y = 12[/tex] -------------------(2)

Multiplying (1) by 2

=> [tex]2(x+2y) = 2(-1)[/tex]

=> [tex]2x+4y = -2[/tex] ------------------(3)

Subtracting (3) from (2)

=> [tex]2x-3y+2x-4y = 12+2[/tex]

=> -3y-4y = 14

=> -7y = 14

Dividing both sides by -7

=> y = -2

Now, Put y = -2 in Eq (1)

=> x+2(-2)+1 = 0

=> x -4+1 = 0

=> x - 3= 0

Adding 1 to both sides

=> x = 3