A student places a transparent semicircular block on a sheet of paper and draws

around the block. She directs a ray of light at the centre of the flat edge of the block.

Figure 1 shows the path of the ray through the block.

Figure 1

incident ray

centre of the flat

edge of the block

transparent

semicircular block

emergent ray \ sheet of paper

[foya}(4] State why the emergent ray does not change direction as it leaves the block.

[1 mark]

Answers

Answer 1

The emergent ray does not change direction as it leaves the block because it is traveling perpendicular to the flat surface of the semicircular block.

What is an emergent ray?

An emergent ray is described to be a refracted beam that originates from a medium or channel after refraction.

It is known that when light passes from one medium to another at a particular angle, it changes direction due to refraction, which is caused by a change in the speed of light as it travels through different media.

If light passes through a flat surface at a perpendicular angle, there is no change in speed or direction, so the emergent ray travels in a straight line without bending or changing direction.

But in this scenario, the incident ray is directed towards the center of the flat edge of the block, it enters the block perpendicular to the flat surface and emerges from the block at the same angle and direction as the incident ray, without any refraction or change in direction.

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Related Questions

oppositely charged parallel plates are separated by 5.04 mm. a potential difference of 600 v exists between the plates. (a) what is the magnitude of the electric field between the plates? n/c (b) what is the magnitude of the force on an electron between the plates? n (c) how much work must be done on the electron to move it to the negative plate if it is initially positioned 2.84 mm from the positive plate?

Answers

The magnitude of the electric field between the plates is  [tex]1.19 \times 10^5 \ N/C[/tex], magnitude of the force on an electron between the plates is [tex]1.9 \times 10^{-14} N[/tex] and work done on the electron to move it to the negative plate is [tex]4.2 \times 10^{-17}\  J[/tex].

(a) The magnitude of the electric field between the plates can be calculated using the formula:

[tex]E = V/d[/tex]

where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates.

Substituting the given values, we get:

[tex]E = 600 \ V / 5.04 \times 10^{-3} m = 1.19 \times 10^5 \ N/C[/tex]

Therefore, the magnitude of the electric field between the plates is [tex]1.19 \times 10^5 \ N/C[/tex].

(b) The magnitude of the force on an electron between the plates can be calculated using the formula:

F = qE

where F is the force, q is the charge of the electron ([tex]-1.6 \times 10^{-19} C[/tex]), and E is the electric field.

Substituting the given values, we get:

[tex]F = (-1.6 \times 10^{-19} C) \times (1.19 \times 10^5 \ N/C) = -1.9 \times 10^{-14}\  N[/tex]

Therefore, the magnitude of the force on an electron between the plates is [tex]1.9 \times 10^{-14} N[/tex].

(c) The work done on the electron to move it to the negative plate can be calculated using the formula:

W = qV

where W is the work done, q is the charge of the electron ([tex]-1.6 \times 10^{-19} C[/tex]), and V is the potential difference between the plates.

First, we need to calculate the electric potential at the initial position of the electron using the formula:

V = Ed

where E is the electric field and d is the distance between the electron and the positive plate.

Substituting the given values, we get:

[tex]V = (1.19 \times 10^5 N/C) \times (2.84 \times 10^{-3} m) = 338 \ V[/tex]

Therefore, the electric potential at the initial position of the electron is 338 V.

Substituting the given values, we get:

[tex]W = (-1.6 \times 10^{-19}\ C) \times (600\ V - 338\ V) = -4.2 \times 10^{-17}\  J[/tex]

Therefore, the work done on the electron to move it to the negative plate is [tex]4.2 \times 10^{-17}\  J[/tex]. Note that the negative sign indicates that the work is done by the electric field (i.e. the electron loses potential energy).

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a 1.24 kg bowling trophy is held at arm's length, a distance of 0.505 m from the shoulder joint. what torque does the trophy exert about the shoulder if the arm is horizontal?

Answers

A 1.24 kg bowling trophy is held at arm's length, a distance of 0.505 m from the shoulder joint. 6.14 Nm torque does the trophy exert about the shoulder if the arm is horizontal

To calculate the torque exerted by the 1.24 kg bowling trophy held at arm's length (0.505 m) from the shoulder joint when the arm is horizontal, you need to follow these steps:
Determine the force exerted by the trophy.
Since the trophy has a mass of 1.24 kg

The force exerted by the trophy due to gravity can be calculated using the equation:

F = m x g

where F is the force,

m is the mass, and

g is the acceleration due to gravity (approximately 9.81 m/[tex]s^2[/tex]).
F = 1.24 kg x 9.81 m/[tex]s^2[/tex] ≈ 12.16 N (Newtons)
Calculate the torque.
Torque (τ) is the rotational force that causes an object to rotate about an axis or pivot point. In this case, the axis is the shoulder joint.

The torque can be calculated using the equation:

τ = r x F x sin(θ)

where τ is the torque,

r is the distance from the axis to the point of force application (0.505 m),

F is the force exerted by the trophy (12.16 N), and

θ is the angle between the force vector and the distance vector.
Since the arm is held horizontally, the force exerted by the trophy is acting vertically downward, which means the angle θ between the force and distance vectors is 90 degrees.

The sine of 90 degrees is 1, so the equation simplifies to:

τ = r x F.
τ = 0.505 m x 12.16 N ≈ 6.14 Nm (Newton meters)

So, the torque exerted by the 1.24 kg bowling trophy about the shoulder joint when the arm is held horizontally at a distance of 0.505 m is approximately 6.14 Nm.
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Suppose you are on a cart, initially at rest, which rides on a frictionless horizontal track. If you throw a ball off the cart towards the left, will the cart be put into motion?
Yes, and it moves to the right.
Yes, and it moves to the left.
No, it remains in place

Answers

Answer:

Yes, and it moves to the right.

Explanation:

When you throw a ball from a cart which is initially at rest on a frictionless horizontal track towards the left, the cart will move towards the right in accordance with the law of conservation of momentum.

Newton's third law?

Force is a push or pull acting on an object resulting in its interaction with another object. Force is a result of an interaction.

Force can be classified into two categories: contact force such as frictional force and non-contact force such as gravitational force.

According to Newton, when two bodies interact, they exert force on each other, and these forces are known as action and reaction pairs ,which is explained in Newton’s third law of motion.

As the ball goes towards the left, it gains a leftward momentum, and by Newton's third law of motion, the cart gains a rightward momentum, there by moving towards the right, as shown in the diagram below: [text] \boxed{  \text{Cart} \to \leftarrow \text{Ball}  }[/tex]

Therefore, the correct option is 'Yes, and it moves to the right.'

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A block of wood has a density of 0. 6 g/cm3 and a volume of 1. 2 cm3. What is the mass of the block of wood?

Answers

The block of timber weighs 0.72 grams in total.

The density of a material is defined as the mass of the material per unit volume. In this case, the density of the block of wood is given as 0.6 g/cm³, and the volume of the block is 1.2 cm³. To find the mass of the block, we can use the formula:

Mass = Density × Volume

Substituting the given values, we get:

Mass = 0.6 g/cm³ × 1.2 cm³

Simplifying the expression, we get:

Mass = 0.72 g

Therefore, the mass of the block of wood is 0.72 grams.

It is important to note that the units used in this calculation are consistent - the density is given in grams per cubic centimeter, and the volume is given in cubic centimeters. This ensures that the final answer for the mass is in grams, which is the appropriate unit for measuring the mass of a small object like a block of wood.

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the strength of the magnetic field at the center of two concentric current loops is zero. the smaller loop has a radius of 0.0390 m and a current of 12.0 a. the larger current loop carries a current of 27.0 a. what is the radius of the larger loop?

Answers

The strength of the magnetic field at the center of two concentric current loops is zero. The smaller loop has a radius of 0.0390 m and a current of 12.0 A. The larger current loop carries a current of 27.0 A, thus the radius of the larger loop should be 0.08775 m

What is the radius of the larger loop? Formula to calculate magnetic field on the axis of a circular current loop that is at a distance x from the center of the loop is given by the equation below.

B = [tex]\frac{\mu_oI}{2R}[/tex]

Here, B is the magnetic field on the axis of a circular current loop that is at a distance x from the center of the loop.

μ₀ is the permeability of free space.

I is the current in the loop,

R is the radius of the loop

In the case of a smaller loop, the magnetic field at its center is [tex] B_1 [/tex] and the magnetic field generated by the larger loop at the center of the smaller loop is [tex] B_2 [/tex].

Then [tex]B_1- B_2=0[/tex]

[tex]\frac{\mu_o}{2}[\frac{I_1}{R_1}-\frac{I_2}{R_2}]=0[/tex]

where [tex] I_1 [/tex] [tex] I_2 [/tex] are the currents in smaller and larger loops respectively.

[tex] R_1 [/tex] [tex] R_2 [/tex] are the radius of  smaller and larger loops respectively.

[tex]\frac{I_1}{R_1} = \frac{I_2}{R_2}\\R_2= \frac{I_2\times R_1}{I_1}\\R_2=0.08775 m.[/tex]

Therefore, the radius of the larger loop is 0.08775 m.

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a cat, also of weight 45.8 n , falls asleep on top of block a. if block b is now set into downward motion, what is its acceleration magnitude?

Answers

The acceleration magnitude of block B when a cat of weight 45.8 N falls asleep on top of block A is 9.8 m/s².

Let the mass of block A be m₁ and its weight be W₁.

Let the mass of block B be m₂ and its weight be W₂.

The total mass that is resting on Block B is given by the equation:

m₁ + m₂ = 45.8/9.8

Where 9.8 m/s² is the acceleration due to gravity.

The net force acting on the block B is given by:

F = (m₁ + m₂)g

Where g is the acceleration due to gravity = 9.8 m/s²

The force exerted by block A on block B is given by:

F = m₁g

Therefore the net force on Block B is given by:

Fnet = (m₁ + m₂)g - m₁g

Fnet = m₂g

The acceleration of Block B is given by the equation:

Fnet = m₂a

Therefore, a = Fnet/m₂

We have, Fnet = m₂g

Therefore, a = g

Therefore, The acceleration of block B is equal to the acceleration due to gravity, g which is 9.8 m/s². Hence, the magnitude of its acceleration is 9.8 m/s².

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a copper cable has a current of 1200 a running through it. there is a potential difference of 0.016 v between two points on the cable that are 0.24 m apart. calculate the radius of the cable

Answers

The radius of the copper cable is 0.107 mm.

The formula to calculate the radius of the cable is given by;

r=ρl/πV

Where, r is the radius of the cable

ρ is the resistivity of the copper

l is the length of the cable

V is the potential difference between two points on the cable.

The potential difference between two points on the cable is given by;

V=IR

Where, I is the current running through the cable

R is the resistance of the cable.

To determine the radius of the copper cable, we need to calculate its resistance first.

Resistance of the cable can be calculated as;

R=V/IR

Substitute the values given in the equation

R=0.016/(1200 A)=1.33x10^-5 Ω

Now, we can use this resistance value and resistivity of copper to calculate the radius of the cable.

The resistivity of copper is 1.72x10^-8 Ω.m.

So, r=ρl/π

[tex]V_r = 1.72x10^-^8 Ω.

m ×0.24 m/π ×1.33x10^-^5 Ω

r=0.000107 m = 0.107 mm[/tex]

So, the radius of the copper cable is 0.107 mm.

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15 Joules of work was done to move a 4C charged particle in an electric field of 3N/C. How far was the particle moved in the electric field?

Giving out BRAINLIEST. PLEASE help.

Answers

The formula for an electric field's work is as follows: The particle was pushed 1.25 metres in the electric field as a result of W = qEd.

When a charge is transferred in an electric field, does work get done?

When a charge is transported in an electric field, work is done. A positively charged particle, such a proton, would accelerate in the direction of the arrows if it were placed in an electric field.

W = qEd

Rearranging the formula to solve for d:

d = W/(qE)

Substituting the given values:

[tex]d = 15 J / (4 C * 3 N/C)[/tex]

d = 1.25 meters

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if pulley b is removed from the system, what is the ratio of the original value of the force with two pulleys to the new value of the force with one pulley?

Answers

If pulley b is removed from the system, the ratio of the original value of the force with two pulleys to the new value of the force with one pulley is 2:1.

A pulley is a wheel with a groove for a rope or a belt to run over. Pulleys are commonly used to lift heavy loads. When the rope is looped around a pulley, it changes the direction of the force that must be exerted to lift the load. When you need to lift a load that is too heavy to lift alone, you can use a pulley system to reduce the amount of force required to lift the load.One of the most useful mechanical devices is a pulley system.

Pulleys are simple machines that can make it easier to lift heavy objects by changing the direction of the force required to lift them. Pulleys work by changing the direction of the applied force, making it easier to lift the load. The weight of the load is distributed over the multiple ropes of a pulley system so that the force required to lift the load is spread out over the multiple ropes, reducing the amount of force required to lift it.

*Complete question: If a pulley b is removed from a system, what is the ratio of the original value of the force with two pulleys to the new value of the force with one pulley?

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A block of copper with a mass of 0.94 kg has 24,600 J of thermal energy removed from it. How much does its temperature change?

Answers

The amount of thermal energy required to change the temperature of a substance is proportional to its mass and its specific heat capacity. The specific heat capacity of copper is 0.385 J/g°C.

To find the change in temperature, we can use the following formula:

ΔT = Q / (m * c)

where ΔT is the change in temperature, Q is the amount of thermal energy removed, m is the mass of the copper block, and c is the specific heat capacity of copper.

Substituting the given values, we get:

ΔT = 24,600 J / (0.94 kg * 0.385 J/g°C)

ΔT = 65.42°C

Therefore, the temperature of the copper block would decrease by approximately 65.42°C when 24,600 J of thermal energy is removed from it.

which particales discrib elements that are non meatal gases

Answers

Answer: Group 0 contains non-metal elements placed in the vertical column on the far right of the periodic table.

Explanation:

The elements in group 0 are called the noble gases. They exist as single atoms.

It is estimated that the human brain has a power requirement of 40W. How much energy does it use in an hour?

Answers

Explanation:

P=40w

T=1hrs

=1×60=60

Now,

P2=40×60=2400

Hence, in a hour, the brain uses 2400w

Which step of the water cycle is the most important

Answers

Answer: evaporation.

Explanation: It soaks up moisture from soil in a garden for example, as well as the biggest oceans and lakes. The water level will decrease as it is exposed to the heat of the sun. (rewrite in your own words)

a truck with 0.347-m-radius tires travels at 26.4 m/s. what is the angular velocity of the rotating tires in radians per second

Answers

The angular velocity of the rotating tires is 76.27 rad/s.

The angular velocity, ω, of a rotating object is the rate at which it rotates around a chosen center point,

ω = Δθ / Δt (angular displacement over time).

A truck with 0.347-m-radius tires travels at 26.4 m/s. We need to determine the angular velocity of the rotating tires in radians per second. The equation that relates speed and angular velocity is

v = ωr

where,ω = angular velocityv = linear velocity, r = radius of the tire. The angular velocity is given by the equation

ω = v / r

Substitute the given values into the formula;

ω = 26.4 m/s / 0.347 mω = 76.27 rad/s

Hence, the angular velocity of the rotating tires in radians per second of a truck with 0.347-m-radius tires that travels at 26.4 m/s is 76.27 rad/s.

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An elastic cord that is 4.21 m long has a mass of 0.0204 kg. What tension must be applied to the cord to make the wavelength of a 112 Hz wave 1.135 m?

Answers

77.4 N of tension must be applied to the rope in order to create a 112 Hz wave's wavelength 1.135 m.

What is the meaning of wavelength?

The distance that separates the crests and troughs of the light wave is known as the wavelength of light. With the Greek letter lambda (λ), it is identified. As a result, wavelength refers to the separation between one wave's peak or dip and the following wave.

The wave equation may be used to connect the cord's tension to the wave's wavelength and frequency:

v = fλ

where,

v denotes the wave's speed

The frequency is f, and

The wavelength is  λ

The elastic cord's elastic wave's velocity is provided by:

v = √(T/μ)

where,

T is the cord's tension, and

μ is the cord's linear mass density,

This is the mass per unit length:

μ = m/L

where m is the cord's mass and

Its length is L.

When we solve for the tension T using these formulas in the wave equation, we obtain:

T = μv² = μ(fλ)²

Inputting the values provided yields:

μ = m/L = 0.0204 kg / 4.21 m = 0.00484 kg/m

v = √(T/μ) --> v² = T/μ

λ = v/f --> v = λ*f

T = μv² = μ(fλ)²

= (0.00484 kg/m)*(1.135 m * 112 Hz)²

= 77.4 N

Hence, 77.4 N of tension must be applied to the rope in order to create a 112 Hz wave's wavelength 1.135 m.

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in the future, a pair of astronauts are sent on a mission to the planet mercury. they watch the sun set one mercurian evening and decide they will go exploring in opposite directions and meet again the next time the sun is setting in the spot where they started. how long will they have to wait for the next sunset at that spot?

Answers

Answer:

On Mercury, a day (the time it takes for the planet to complete one full rotation on its axis) is 59 Earth days long. Additionally, Mercury's orbit around the sun is much faster than Earth's, so its year (the time it takes to orbit the sun once) is only 88 Earth days long.

Since the astronauts are waiting for the next sunset at the same spot, they are essentially waiting for Mercury to complete one full rotation on its axis. So they will have to wait for one Mercury day, which is 59 Earth days long.

Since the year on Mercury is shorter than its day, the planet rotates on its axis three times for every two orbits around the sun. This means that there are approximately 1.5 Mercury days in each Mercury year.

Therefore, the astronauts will have to wait for approximately 39.3 Earth days (59 Earth days/Mercury day * 1.5 Mercury days/Mercury year) for the next sunset at the same spot.

Explanation:

Mercury takes approximately 59 Earth days to complete one full rotation on its axis. This means that from one sunrise to the next, it takes approximately 59 Earth days. This is because a day on any planet is defined as the time it takes for the planet to make one full rotation on its axis.

Mercury takes approximately 88 Earth days to complete one orbit around the sun. This means that from one sunrise to the next, it takes approximately 88 Earth days. This is because a year on any planet is defined as the time it takes for the planet to make one full orbit around the sun.

However, since Mercury rotates on its axis three times for every two orbits around the sun, it means that it takes 1.5 Mercury days to complete one full orbit around the sun. This is because in the time it takes Mercury to orbit the sun once, it rotates on its axis three times.

So, if the astronauts wait for one Mercury day (i.e. one full rotation of the planet on its axis), they will have to wait for approximately 59 Earth days.

But since it takes 1.5 Mercury days to complete one orbit around the sun, the planet will have to rotate approximately 1.5 times before the same spot faces the sun again. This means that the astronauts will have to wait for approximately 1.5 Mercury days or 1.5 x 59 Earth days = 88.5 Earth days for the same spot to face the sun again.

Therefore, the astronauts will have to wait for approximately 88.5 Earth days - 59 Earth days (for one Mercury day) = 29.5 Earth days for the next sunset at the same spot. Rounding up, this is approximately 39.3 Earth days.

there is an increase in precipitation over an ocean. how is the salinity of the seawater affected?

Answers

The increase in precipitation over an ocean leads to a decrease in the salinity of seawater.

An increase in precipitation over an ocean can result in a decrease in the salinity of the seawater. This is because the added freshwater from precipitation can dilute the seawater, lowering its salt concentration.

Additionally, increased precipitation can lead to increased runoff from land, which can carry freshwater and other dissolved substances into the ocean, further reducing the salinity of the seawater. However, the extent to which the salinity is affected will depend on various factors such as the rate and amount of precipitation, ocean currents, and evaporation rates.

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. a small cart on a 0.5 m long frictionless track moves with a speed of 0.75 m/s. bumpers at either end of the track reverse the cart with no loss of speed. find the period and frequency of the motion

Answers

The period and frequency of the motion is 1.33 second and 0.75 Hz respectively.

To solve this problem, we will use the formula for the period of simple harmonic motion. The period is the time taken for the object to complete one full oscillation. In this case, the object is the small cart on the frictionless track. We can use the following formula to calculate the period of the cart:

T=2L/v

where T is the period of the motion, L is the length of the track, and v is the speed of the cart.

In this case, L = 0.5 m and v = 0.75 m/s. Thus,

T=2(0.5 m)/(0.75 m/s)

T=1.33 s

The period of the motion is 1.33 seconds.

To find the frequency of the motion, we use the formula:

f=1/T

T=1.33 s

f=1/1.33

f=0.75 Hz

The frequency of the motion is 0.75 Hz.

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if the aimless wanderer goes into a circular orbit 40,000 km k m above the surface of mongo, how many hours will it take the ship to complete one orbit?

Answers

If the aimless wanderer goes into a circular orbit 40,000 km above the surface of Mongo, it will take the ship approximately  11.81 hours to complete one orbit.

What is an orbit?

An orbit is a curved path followed by a celestial object around a star, planet, or moon, such as the path of the earth around the sun. Gravity keeps the object in orbit around the star or planet. An orbit can be circular or elliptical. Satellites, planets, moons, and asteroids all follow orbits around stars or planets.

How to find the time taken by the aimless wanderer to complete one orbit?

The time required for the aimless wanderer to complete one orbit can be calculated by using the formula,
T = 2π√(a^3/GM)
Where:
a = altitude of orbit above the surface of the planet (radius of planet + altitude)
G = gravitational constant (6.67430 × 10^-11 N m^2/kg^2)
M = mass of the planet

First, we need to calculate the radius of the planet (R) based on the altitude of the orbit:
R = altitude of orbit + radius of planet
R = 40,000 km + radius of planet

We don't know the radius of the planet, so we can't calculate R directly. However, we can assume that the altitude of the orbit is small compared to the radius of the planet, which means we can approximate R as:
R ≈ 2 × altitude of orbit
R ≈ 2 × 40,000 km
R ≈ 80,000 km

Now that we have an approximation for the radius of the planet, we can calculate the period of the orbit:
T = 2π√(a^3/GM)
T = 2π√((R + altitude of orbit)^3/GM)
T = 2π√(((80,000 km + 40,000 km)^3)/(6.67430 × 10^-11 N m^2/kg^2 × M))

We don't know the mass of the planet, so we can't calculate T directly. However, we can make a simplifying assumption that the mass of the planet is much greater than the mass of the spacecraft, which means that the period of the orbit is only weakly dependent on the mass of the planet. Therefore, we can use the mass of Earth as an approximation for the mass of Mongo:
T ≈ 2π√(((80,000 km + 40,000 km)^3)/(6.67430 × 10^-11 N m^2/kg^2 × 5.9722 × 10^24 kg))
T ≈ 11.81 hours

Therefore, the spacecraft will take approximately 11.81 hours to complete one orbit of Mongo at an altitude of 40,000 km above its surface.

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define the critical temperature for a superconducting material. explain in words any method for measuring the critical temperature in a superconductor.

Answers

The critical temperature of a superconducting material is defined as the temperature below which a material exhibits zero electrical resistance and becomes a superconductor. This phenomenon is only observed in certain materials at very low temperatures, typically near absolute zero.


There are several methods for measuring the critical temperature in a super conductor, including resistivity measurements, magnetometry, and specific heat measurements. One of the most common methods is resistivity measurements, which involves measuring the electrical resistance of a sample as a function of temperature. At the critical temperature, the resistance of the material drops abruptly to zero, indicating the transition to a superconducting state.
Another method for measuring the critical temperature is magnetometry, which involves measuring the magnetic properties of the material as a function of temperature. Superconductors typically exhibit perfect diamagnetism, meaning they expel any applied magnetic fields from their interior. The critical temperature can be determined by measuring the temperature at which the material transitions from a magnetically susceptible state to a diamagnetic state.
Finally, specific heat measurements can also be used to measure the critical temperature in a superconductor. Specific heat is the amount of energy required to raise the temperature of a material by a certain amount, and it changes abruptly at the critical temperature. By measuring the specific heat of a material as a function of temperature, the critical temperature can be determined by identifying the temperature at which the specific heat jumps.
In conclusion, the critical temperature is the temperature at which a material exhibits zero electrical resistance and becomes a superconductor. Several methods can be used to measure the critical temperature in a superconductor, including resistivity measurements, magnetometry, and specific heat measurements.

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calculate the time required for a spacecraft launched into a paraboliv trajectory at a perigee altitude of 200 km to leave the earth's sphere of influence

Answers

The time required for a spacecraft launched into a paraboliv trajectory at a perigee altitude of 200 km to leave the earth's sphere of influence is 7.77 days.

Thus, The terms apogee and perigee describe the separation between the Earth and the moon. The distance from the earth at apogee is the greatest.

The moon appears larger around perigee, which is when it is closest to the earth. Without anything to compare it against, the moon appears to be the same size when viewed from the ground. But the size disparity may actually be pretty substantial.

The tides on Earth are impacted by the moon's apogee and perigee. The moon has less gravitational attraction when it is at apogee, the distance from Earth at when it is closest to the moon.

Thus, The time required for a spacecraft launched into a paraboliv trajectory at a perigee altitude of 200 km to leave the earth's sphere of influence is 7.77 days.

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a star's apparent magnitude is a measure of how bright it apppears to us if it is at its actual distane true false

Answers

Answer:

true

Explanation:

The apparent brightness of a star is how much energy is coming from the star per square meter per second, as measured on Earth. The further away the star is, the smaller the probability that a given photon emitted by the star will eventually hit Earth. Or said a quantitative form: all else being the same, the apparent brightness of a star is proportional the the inverse square of its distance.

Calculate the potential energy, kinetic energy, mechanical energy, velocity, and height of the skater at the various locations

Answers

It is challenging to provide a precise response to this query without knowing the skater's exact whereabouts. I can, however, give a general explanation of how potential energy, kinetic energy, mechanical energy, velocity, and height are related.

the formula for potential energy What are mechanical energy and kinetic energy?

Kinetic energy (K.E.) plus potential energy equals mechanical energy (M.E. (P.E.)Kinetic Energy (K.E.) is equal to (1/2)mv.Potential Energy (P.E.) is defined as mgh.

How do you calculate potential energy using height and speed?

The force acting on the two objects affects the potential energy formula. The formula for gravitational force is P.E. = mgh, where g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and m is the mass in kilogrammes.

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why will a rainbow never have a black stripe? group of answer choices black is not a color on the color spectrum. in direct sunlight, the color back will not appear. dark color spectrum rainbows only appear at night. if there is a black layer, it is no longer called a rainbow. previousnext

Answers

Option 1. A rainbow will never have a black stripe because black is not a color on the color spectrum.

A rainbow is an optical and meteorological phenomenon that occurs when light is refracted or dispersed through water droplets present in the Earth's atmosphere, leading to a spectrum of light appearing in the sky. Rainbows are caused by sunlight being refracted and reflected by water droplets in the atmosphere. A rainbow spans a continuous spectrum of colors, ranging from red on the outside to violet on the inside.

The color spectrum refers to the full range of colors that can be seen by the human eye. The visible spectrum, also known as the color spectrum or the optical spectrum, is a portion of the electromagnetic spectrum that can be seen by the human eye. The spectrum of visible light can be separated into various colors that, when combined, form white light. This is due to the fact that visible light is made up of different colors of light.

Sunlight is a type of electromagnetic radiation that comes from the sun. Sunlight is composed of photons that travel through space until they reach Earth's atmosphere. Sunlight appears white to the human eye, but it is actually made up of various colors of light, as seen in a rainbow. The sun emits light at various wavelengths, which can be separated by a prism to reveal the colors in the spectrum.

Black is not a color in the visible light spectrum, and therefore cannot be found in a rainbow. The colors that appear in a rainbow are a result of the sun's light being refracted and reflected by water droplets in the atmosphere. The colors in a rainbow always appear in the same order and do not include black. Therefore, it is concluded that a rainbow will never have a black stripe because black is not a color on the color spectrum.

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A 2.0kg object is dropped from a height of 10m.
Calculate the speed of the object after it has fallen 5.0m, assuming there is no air resistance.
Give your answer to 2 significant figures.
g=9.8 N/kg.

Answers

The speed of the object after falling 5.0 m would be 5.4 m/s.

Energy conservation problem

We can solve this problem using the law of conservation of energy, which states that the total energy of a system is constant. At the top of the drop, the object has potential energy equal to its mass times the acceleration due to gravity times its height above the ground:

Ep = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the drop.

At any point during the fall, the object has kinetic energy equal to one half its mass times its speed squared:

Ek = (1/2)mv^2

where v is the speed of the object.

Since there is no air resistance, the total energy of the system is conserved, so the initial potential energy at the top of the drop (Ep = mgh) is converted entirely into kinetic energy (Ek = (1/2)mv^2) as the object falls.

When the object has fallen 5.0 m, its potential energy is:

Ep = mgh = (2.0 kg)(9.8 N/kg)(5.0 m) = 98 J

The kinetic energy of the object at this point is equal to its initial potential energy minus the potential energy it still has at that point:

Ek = Ep - mghEk = 98 J - (2.0 kg)(9.8 N/kg)(5.0 m) = 58 J

Setting the kinetic energy equation equal to the expression for Ek above and solving for v gives:

Ek = (1/2)mv^2v = sqrt(2Ek/m)v = sqrt(2(58 J)/(2.0 kg))v = 5.4 m/s

Therefore, the object's speed after falling 5.0 m is 5.4 m/s, rounded to 2 significant figures.

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A small block is sent through point A with a speed of 6.2 m/s. Its path is without friction until it reaches the section of length L = 14 m, where the coefficient of kinetic friction is 0.71. The indicated heights are h1 = 5.3 m and h2 = 2.9 m. What are the speeds of the block at (a) point B and (b) point C? (c) Does the block reach point D? (d) If so, what is its speed there; if not, how far through the section of friction does it travel?

Answers

As a result, the speed at point B is 11.93 M/S. a) The potential energy shift from point A to point B equals the kinetic energy at point B. (b) The block doesn't really achieve point D .

because the kinetic energy at point C is equivalent to the change in potential energy from point A towards point C, which results in a speed of 9.246 m/s at point C.

d) The friction force energy from the block's kinetic energy at point C causes it to move 6.14 meters, which is much less than 14 meters. The power an entity receives as the result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it.

We must put forth effort in order to apply significant force. Once the job is finished, the energy returns towards the item, which then moves at a new, steady velocity.

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what are the x and y components of the acceleration a 2.0 kg object on which the forces below are acting?

Answers

By applying Newton's second law of motion the value of x component is 1 m/s^2 and the y component has the value of 0 m/s^2.

In contrast to the first law of motion, the second law of motion deals with the behaviour of objects when all external factors are in equilibrium.The second rule of motion, which is more quantitative, is frequently applied to determine what occurs when a force is present.
According to Newton's second rule, an object's acceleration is determined by its mass and the total force that is operating on it.The mass of the body has an inverse relationship with acceleration, which is exactly proportionate to the total force exerted on the body. This implies that as the force exerted on an object increases, so does the object's motion. Similar to how an object's motion decreases as its mass increases, so does its mass.
By applying Newton's second law of motion:-

for x component:

4N - 2N = 2a

2= 2a and a = 1 m/s^2.

for y component:

3N-(2N+1N)= 2a

a= 0m/s^2.

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According to the Big Bang theory, how many forces - and which ones - operated in the universe during the GUT era?
A. 2 forces: gravity and a single force that later became the strong, weak, and electromagnetic forces
B. 3 forces: gravity, the strong force, and the electroweak force
C. 2 forces: the strong force and the electroweak force
D. 1 force that represented the unification of all four forces that operate today

Answers

The answer is:
B. 3 forces: gravity, the strong force, and the electroweak force

if you analyze the light from a low density object (such as a cloud of interstellar gas), which type of spectrum do you see?

Answers

If you analyze the light from a low-density object such as a cloud of interstellar gas, you will see an emission spectrum.

What is emission spectrum?

An emission spectrum is a light spectrum created by the emission of light by a substance when it is exposed to high-frequency radiation. Each element has a unique line spectrum or emission spectrum, which can be used to detect the element.

An emission spectrum's line spectrum can be used to identify an element and distinguish it from other elements. It shows what color of light a substance emits when heated. The color of the lines on the emission spectrum is determined by the element that emitted the light. Each chemical element has a unique line spectrum, allowing astronomers to identify the elements in stars and other celestial objects.

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what would cause an atom to have a high electronegativity value?

Answers

Answer:

As the number of protons in the nucleus increases, the electronegativity or attraction will increase. Therefore electronegativity increases from left to right in a row in the periodic table

Explanation:

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