Answer:
v_r = 3.4 cm / s , v_t = 84.82 cm / s
Explanation:
The speed of the insect has two components, one radial and the other tangential,
The radial component is the speed with which the insect moves with respect to the plate
v_r = 3.4 cm / s
The tangential component is given by
v = w r
Let's reduce the angular velocity to the SI system
w = 45 rpm (2π rad / 1 rev) (1 min / 60 s) = 4.712 rav / s
let's calculate
v = 4.712 18
v_t = 84.82 cm / s
What is Newton's First Law of Motion? (2 points)
A For every action there is an equal and opposite reaction.
B An object in motion or at rest will stay that way unless acted on by an unbalanced force.
C The smaller the mass of an object, the greater the acceleration of that object when a force is applied.
D Every force is said to be unbalanced when the force acting against it is less.
Answer:
B
Explanation:
B is Newton's first law of motion, I got this in class and that was the right answer.
Good Luck!
Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now imagine that a dielectric slab with dielectric constant 2.6 is inserted a length 4.4 cm into the capacitor. The slab has the same width as the plates. The capacitor is completely filled with dielectric material down to a length of 4.4 cm. A battery is connected to the plates so that they are at a constant potential 0.8 V while the dielectric is inserted.
Required:
What is the ratio of the new potential energy to the potential energy before the insertion of the dielectric?
Answer:
The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58
Explanation:
Given that,
Length of plates = 8 cm
Width = 5.52 cm
Distance = 1.99 cm
Dielectric constant = 2.6
Length = 4.4 cm
Potential = 0.8 V
We need to calculate the initial capacitance
Using formula of capacitance
[tex]C=\dfrac{\epsilon_{0}A}{d}[/tex]
Put the value into the formula
[tex]C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}[/tex]
[tex]C=1.96\times10^{-12}[/tex]
We need to calculate the final capacitance
Using formula of capacitance
[tex]C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}[/tex]
Put the value into the formula
[tex]C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}[/tex]
[tex]C'=3.37\times10^{-12}[/tex]
We need to calculate the ratio of the new potential energy to the potential energy before the insertion of the dielectric
Using formula of energy
[tex]\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}[/tex]
Put the value into the formula
[tex]\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}[/tex]
[tex]\dfrac{E}{E'}=0.58[/tex]
Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58
A thick conducting spherical shell, with inner radius R1 and outer radius R2, is in electrostatic equilibrium. The area inside and outside the spherical shell is vacuum. The net charge on the spherical shell is Q. Note: for parts (a)-(c), describe the direction of the electric field assuming that Q is positive.
(a) Find the electric field outside the shell, at a distance d > R2 from the center of the shell.
(b) Find the electric field in the shell material, at a distance d from the center of the shell where R1 < d < R2.
(c) Find the electric field at a distance d < R1 from the center of the shell, i.e. in the empty space inside the shell.
(d) How much charge is on the inner surface of the conducting shell
Answer:
a) E = k Q / r² , k = 1 / 4πε₀, b) E=0, C) E=0, d) Q=0
Explanation:
To find the electric field in this exercise let's use Gauss's law
Ф = ∫ E. dA = [tex]q_{int}[/tex] /ε₀
Let's use a sphere as a Gaussian surface, in this case the field lines and the radii of the spheres are parallel so the scalar product is reduced to the algebraic product, let's carry out the integral
E A = q_{int} /ε₀
The area of a sphere is
A = 4π r²
we substitute
E (4π r²) =q_{int} /ε₀
a) The field is requested outside the spherical shell
d> R₂
in this case the charge inside the Gaussian surface is
q_{int} = Q
E = Q / (4π r²) ε₀
E = k Q / r²
k = 1 / 4πε₀
b) In the second case, the field inside the spherical casing is requested.
As the surface is metallic, the charge is located on the surface of it, the electrons repel each other. So the charge inside is zero
q_{int} = 0
E = 0
c) The field in the interior region of the shell, all the charge is external, therefore the internal charge is zero
q_{int} = 0
E = 0
d) as the shell is conductive, the electrons can move freely, which is why it moves as far away as possible between them, this means that everything is located as close as possible to the outer surface of the conductor. Consequently, THERE ARE NO ELECTRONS ON THE INTERNAL SURFACE
Q_internal =0
What best describes the dropping height of a ball that bounced back up to a height of 45 centimeters?
Less than 45 centimeters, as the ball transforms some of its thermal energy into potential energy
Greater than 45 centimeters, as the ball transforms some of its thermal energy into potential energy
Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy
Greater than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy
Answer:C:Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy
Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy.
Although the initial energy (potential energy is preserved), the energy of deformation as the ball strikes a surface creates energy dissipation in the form of frictional heat and audible sound energy.
Every time the ball bounces, its height will be less than its previous height.
Explanation:
Answer:
C is incorrect I got it wrong on my test don't go with C
Explanation:
What is the acceleration of a 1,125 kg truck with a net force of 8,268 N?
Answer:
The answer is 7.35 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
where
f is the force
m is the mass
From the question
f = 8268 N
m = 1125 kg
We have
[tex]a = \frac{8268}{1125} \\ =7.3493 3333...[/tex]
We have the final answer as
7.35 m/s²Hope this helps you
Which of the following statements must be true?
a. The velocity and acceleration are in the direction of the resultant force.
b. The velocity could be in any direction, but the acceleration is in the direction of the resultant force.
c. The velocity and acceleration could be in any direction.
d. None of these choices.
Answer:
your answer is B. The velocity could be in any direction, but the acceleration is in the direction of the resultant force
SYW A force of 175 N is needed to keep a stationary engine of weight 640 N on wooden skids from
sliding on a wooden floor. What is the mass of the engine?
Select one:
Answer:
phle follow karo yrr tab hee bat u ga
Answer:
no
Explanation:
ok
A car transports its passengers between 3 buildings. It moves from the first building to the second building, 4.76km away, in a direction 37° north of east. It then moves from second building to the third building in a direction 69° west of north. Finally, it returns to the first building, sailing in a direction 28° east of south. Calculate the distance between (a) the second and third buildings and (b) the first and third buildings.
Answer:
1) a = 6.14 km
2) b = 4.69 km
Explanation:
Let the first building be A, second building be B and third building be C.
Now, bearing of A = 4.76 km in a direction 37° north of east
Bearing of B = 69° west of north
Bearing of C = 28° east of south
Thus if this 3 points form a triangle, we will have the following angles;
Angle at point A = 28 + (90 - 37) = 81°
Angle at point B = 28 + (90 - 69) = 49°
Angle at point C = 180 - (81 + 49) = 50°
Now, the distance between second and third building is "a" which is represented by BC in the triangle attached while the given distance of 4.76 represents side AB. Thus;
Using sine rule, we can find "a".
a/sin 81 = 4.76/sin 50
a = 6.14 km
B) distance between first and third building is AB in the triangle depicted by "b".
Similar to the first problem, we will use sine rule again.
b/sin49 = 4.76/sin 50
b = 4.69 km
Two vectors are given by a = 8.6i + 5.1 j and b = 931 + 9.5.
Find
(a). [a xb]
(b). a.b ,
(c) a + b . b , and
(d) the component of a along the direction of b.
Answer:
Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong):
a) a×b = 34.27k
b) a·b = 128.43
c) (a + b)·b = 305.17
d) The component of a along the direction of b = 9.66
Explanation:
Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong) we can proceed as follows:
a) The vectorial product, a×b is:
[tex] a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k [/tex]
b) The escalar product a·b is:
[tex] a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43 [/tex]
c) Asumming (a + b)·b instead a+b·b we have:
[tex](a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17[/tex]
d) The component of a along the direction of b is:
[tex] a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66 [/tex]
I hope it helps you!
True or False: When analyzing surface forces, the pressure always acts away from the control volume. g
ANSWERED: Which action will cause the induced current to decrease or remain constant?
*zoom in answer to remove computer lines*
Answer:
Reversing the polarity of the magnet
Explanation:
The action that will cause the induced current to decrease or remain constant is "reversing the polarity of the magnet"
To reverse the polarity, a battery and coil of copper can be used. Reversing the polarity of the magnet will also cause the induced current to reverse in direction. The polarity of the magnet actually determines the direction of the electromagnetic force.
A coconut falls from a height of 18m to the ground. What is the velocity at which the coconut hits the ground?
[Given g = 10m/s]
Answer:
v=18.97 m/s
Explanation:
the equation for the above question is v²=u²+2as
A driver translation a speed of 115km/hr received a text message on his mobile phone how far is he ,in kilometers,20s later from when he received the text message?
Answer:
S=d/t.
distance is= speed multiplied by the time
D= 115 multiplied by 20
the answer is 2300km
Driver is approximately 0.63888 kilometers away from where he received the text message after 20 seconds.
To determine the distance the driver travels 20 seconds after receiving the text message, we need to calculate the distance covered during that time interval.
First, we convert the driver's speed from km/h to m/s for consistent units. The conversion factor is 1 km/h = 0.27778 m/s.
Driver's speed = 115 km/h × 0.27778 m/s = 31.944 m/s
Next, we use the formula for distance traveled:
Distance = Speed × Time
Distance = 31.944 m/s × 20 s = 638.88 meters
Therefore, the driver will be 638.88 meters away from the point where he received the text message after 20 seconds.
To convert this distance to kilometers, we divide by 1000:
Distance = 638.88 m ÷ 1000 = 0.63888 km
So, the driver is approximately 0.63888 kilometers away from where he received the text message after 20 seconds.
To know more about distance traveled, here
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ANSWET ASAP
Which term is the rate at which work is done?
energy
power
joules
force
Answer:
power
Explanation:
Answer:
power
Explanation:
You made a peanut butter and jelly sandwich for lunch and ate it. What did your actions cause?
A. Caused a physical change when digesting the food
B. Caused a physical change when chewing the sandwich.
C. Caused a chemical change to the peanut butter and jelly.
O D. Performed a chemical reaction by mixing the peanut butter and jelly together.
Answer:
C
Explanation:
Chemical energy is in the food you eat and It fuels your body
Answer: B
Explanation:
When you chew it, you're changing the physical state it's in.
How much kinetic energy does a 1 kg ball
traveling at 5 m/s have?
Answer:
Okay, first off, the formula for Kinetic Energy is:
KE = 1/2(m)(v)^2
m = mass
v = velcoity (m/s)
Using this formula, we can then calculate the kinetic energy in each scenario:
1) KE = 1/2(100)(5)^2 = 1,250 J
2) KE = 1/2(1000)(5)^2 = 12,500 J
3) KE = 1/2(10)(5)^2 = 125 J
4) KE = 1/2(100)(5)^2 = 1,250 J
The number of waves in a given time period is called the ________________ .
Answer:
frequency.
......... i need more characters so
A uniform electric field has magnitude E and is directed in the negative x direction. The potential difference between point a (at x = 0.60 m) and point b (at x = 0.90 m) is 240 V.
Required:
a. Which point, a or b, is at the higher potential?
b. Calculate the value of £.
c. A negative point charge q = —0.200 μC is moved from 5 to a. Calculate the work done on the point charge by the electric field.
Answer:
a)
b is at higher potential
b)
E = 800 V/m
c)
W = -48.0 μ J
Explanation:
Given:
electric field has magnitude E and is directed in the negative x direction
potential difference between point a (at x = 0.60 m) and point b (at x = 0.90 m) = 240 V
a)
Direction of the electric field is in the negative x direction so it is away from the positive charge and the more distance away from direction, the lesser the potential gets. So b is at the higher potential.
b)
When the magnitude of electric field is constant then the potential difference between two points in the field is given by:
Vab = Ed
where
Vab is the potential difference between two points a and b in the field
E is electric field magnitude
d is the distance between two points
Compute distance between two points a and b
d = 0.90 - 0.60
d = 0.30
d = 0.3 m
Since potential difference between two points in the field is given which is 240 V
Compute E:
The above formula becomes:
Vab = Ed
E = Vab/d
= 240/0.3
E = 800 V/m
c)
The negative charge moved from the higher potential to low so work done on the point charge by electric field is negative.
W = Fd
Electric field = E = F/q
where
E is electric field magnitude
F is electric force on q
q is point charge magnitude
The charge q is either positive or negative and when charge is positive the directions of E and F are same otherwise opposite in case of negative charge.
So to calculate the work done on the point charge by the electric field:
E = F/q
F = Eq
so
W = Fd = Eqd
Now putting the values:
E = 800 V/m
q = - 0.200 μC
d = 0.3 m
W = Eqd
W = 800 * - 0.200 * 0.3
W = 800 * - 0.2 * 10⁻⁶ * 0.3
W = - 48 * 10⁻⁶
W = - 4.8 * 10⁻⁵ J
W = -48.0 μJ
a. The point which is at a higher potential is point a.
b. The magnitude (E) of the uniform electric field is equal to 800 V/m.
c. The work done on the point charge by the electric field is equal to -48 microjoules.
Given the following data:
Point a (at x) = 0.60 meterPoint b (at x) = 0.90 meterPotential difference = 240 Volts.Point charge = -0.200 uC = [tex]0.200 \times 10^{-6}\;C[/tex]a. Since the uniform electric field with a magnitude (E) is directed in the negative x direction, the point at a higher potential is point a because the electric field is not close to the positive charge and it is further away from point b by 0.90 meter. Also, the potential difference of an electric field is inversely proportional to the square of the distance from a point charge.
b. To calculate the magnitude (E) of the uniform electric field:
At a constant potential difference, the magnitude (E) of this electric field is given by the formula:
[tex]V_{ab} = Ed[/tex]
Where:
V_{ab} is the potential difference between point a and b.E is the magnitude the electric field.d is the distance between point a and b.First of all, we would determine the distance (d).
[tex]d = d_b - d_a\\\\d = 0.90 -0.60[/tex]
Distance, d = 0.30 meter.
Substituting the given parameters into the formula, we have;
[tex]240 = 0.3E\\\\E=\frac{240}{0.3}[/tex]
E = 800 V/m
c. To calculate the work done on the point charge by the electric field:
Mathematically, the work done on a point charge in an electric field is given by the formula:
[tex]W = Fd = Eqd\\\\W = 800 \times (-0.200 \times 10^{-6}) \times 0.3\\\\W = -240 \times 0.200 \times 10^{-6}\\\\W = -48\times 10^{-6}\;Joules[/tex]
Note: 1 microjoules = [tex]1\times 10^{-6}[/tex] Joules
Work done = -48 microjoules.
Read more on an electric field here: https://brainly.com/question/23153766
An object is made from a material that is hard, shiny, and can be hammered into thin sheets. Which of these is another likely property of the material?
Answer:
Good conductor of heat
Explanation:
Because metals are shiny, ductile, malleable, sonorous, good conductors of heat and electricity and have high melting and boiling points
Answer: mine is different so im sorry im here for points
Explanation:
Tell whether the statement below is a scalar or a vector
Answer:
1. Scalar
2.Vector
3. Scalar
4. Vector
5.Scalar
6.Scalar
7.Vector
8.Vector
9.Scalar
10.Scalar
11.Scalar
12. Vector
13.Scalar
Explanation:
Scalar refers to magnitude, and Vectors include magnitude with directions.
Luis wants to compare the density of three solid objects that are different shapes and sizes. What information does he need to make the comparison?
Answer:
u need to make sure that comparison is = to shapes and then find the shapes sizes and add them
Explain why moving a heavy box on a wheeled cart is easier than pushing it across the floor
Answer:
because pushing it the mass is sitting steal when pushing the mass and no choice but to move
Which statement describes oneScientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below.
A purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals.
What experimental evidence led to the development of this atomic model from the one before it? feature of Rutherford’s model of the atom?
Answer:
el continuo movimiento
Explanation:
Can someone please help, ty!!
(Will mark brainliest)
Answer:
graph
noun
a diagram representing a system of connections or interrelations among two or more things by a number of distinctive dots, lines, bars, etc.
Mathematics.
a series of points, discrete or continuous, as in forming a curve or surface, each of which represents a value of a given function.
Also called linear graph . a network of lines connecting points.
a written symbol for an idea, a sound, or a linguistic expression.
verb (used with object)
Mathematics. to draw (a curve) as representing a given function.
to represent by means of a graph.
Explanation:
that is what i found
You are a member of a geological team in Central Africa. Your team comes upon a wide river that is flowing east. You must determine the width of the river and the current speed (the speed of the water relative to the earth). You have a small boat with an outboard motor. By measuring the time it takes to cross a pond where the water isn’t flowing, you have calibrated the throttle settings to the speed of the boat in still water. You set the throttle so that the speed of the boat relative to the river is a constant 6.00 m/s. Traveling due north across the river, you reach the opposite bank in 20.1s. For the return trip, you change the throttle setting so that the speed of the boat relative to the water is 9.00 m/s. You travel due south from one bank to the other and cross the river in 11.2 s.
Required:
a. How wide is the river, and what is the current speed?
b. With the throttle set so that the speed of the boat relative to the water is 6.00 m/s, what is the shortest time in which you could cross the river, and where on the far bank would you land?
Answer:
(a). The width of the river is 90.5 m.
The current speed of the river is 3.96 m.
(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.
Explanation:
Given that,
Constant speed = 6.00 m/s
Time = 20.1 sec
Speed = 9.00 m/s
Time = 11.2 sec
We need to write a equation for to travel due north across the river,
Using equation for north
[tex]v^2-c^2=\dfrac{w^2}{t^2}[/tex]
Put the value in the equation
[tex]6.00^2-c^2=\dfrac{w^2}{(20.1)^2}[/tex]
[tex] 36-c^2=\dfrac{w^2}{404.01}[/tex]....(I)
We need to write a equation for to travel due south across the river,
Using equation for south
[tex]v^2-c^2=\dfrac{w^2}{t^2}[/tex]
Put the value in the equation
[tex]9.00^2-c^2=\dfrac{w^2}{(11.2)^2}[/tex]
[tex] 81-c^2=\dfrac{w^2}{125.44}[/tex]....(II)
(a). We need to calculate the wide of the river
Using equation (I) and (II)
[tex]45=\dfrac{w^2}{125.44}-\dfrac{w^2}{404.01}[/tex]
[tex]45=w^2(0.00549)[/tex]
[tex]w^2=\dfrac{45}{0.00549}[/tex]
[tex]w=\sqrt{\dfrac{45}{0.00549}}[/tex]
[tex]w=90.5[/tex]
We need to calculate the current speed
Using equation (I)
[tex]36-c^2=\dfrac{(90.5)^2}{(20.1)^2}[/tex]
[tex]36-c^2=20.27[/tex]
[tex]c^2=20.27-36[/tex]
[tex]c=\sqrt{15.73}[/tex]
[tex]c=3.96\ m/s[/tex]
(b). We need to calculate the shortest time
Using formula of time
[tex]t=\dfrac{d}{v}[/tex]
[tex]t=\dfrac{90.5}{6}[/tex]
[tex]t=15.0\ sec[/tex]
We need to calculate the distance
Using formula of distance
[tex]d=vt[/tex]
[tex]d=3.96\times15.0[/tex]
[tex]d=59.4\ m[/tex]
Hence, (a). The width of the river is 90.5 m.
The current speed of the river is 3.96 m.
(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.
I don’t know what this is
1) How many people can be on a basketball team?
2) How many people can be on the court at a time?
3) List the dimensions of the court listed in the video (Length and Width)
4) How many points does a freethrow count for?
5) How many seconds does a team get to shoot the ball before a shot clock violation?
Answer:
it can be up to 15 ppl
ur team can be on a court
width
28 I believe
less then 10 seonds
Consider this situation: A person stands at rest on the floor.
Identify the forces that act upon the person.
Answer:
Explanation:
Gravity and normal
Answer:
Gravity and Normal
Why should I not choose you?
Answer:
bc I'm ugly
Explanation:
i just answer a random thing bc I know is not from school
Answer:
you shouldn't, if u were to choose me then you would be making a huge mistake since choosing me would go against why you shouldn't choose me.
It is the final seconds of an ice hockey game between the Flyers and the Bruins. The Bruins are down by 1 point. With 20 s left in the game, the Bruins pull the goalie and have him play as a forward in an attempt to tie the game. The Flyers successfully defend their goal for 9 s. With only 1.25 s remaining on the game clock, a Flyer shoots the puck on the ice past the skates and sticks of the other players and toward the Bruins' goal. The puck is 37 m from the goal when it leaves the stick with an initial horizontal velocity of 30 m/s. The shot is perfectly directed toward the empty goal, but the ice slows the puck down at a constant rate of 0.50 m/s2 as it slides toward the goal. None of the Bruins can stop the puck before it reaches the goal.
A. Where is the puck when the game clock reaches zero and the horn sounds to end the game?
B) Do the flyers win the game by 1 or 2 points?
Answer:
A
[tex]k = 0.11 \ m [/tex] beyond the goal post
B
Given that the goal was score against the Bruins it then means that the Flyer won the game with 2 points
Explanation:
From the question we are told that
The amount of time left in the game is [tex]t = 20 \ s[/tex]
The amount of time the goal was defended is [tex]t_1 = 9 \ s[/tex]
The time remaining when the shot was made is [tex]t_2 = 1.25 \ s[/tex]
The distance of the pluck from the goal is [tex]d = 37 \ m[/tex]
The initial velocity of the pluck is [tex]u = 30 \ m/s[/tex]
The acceleration of the pluck is [tex]a = -0.50 \ m/s^2[/tex]
Generally the distance travel at the remaining time is mathematically represented as
[tex]D = u * t _2 + \frac{1}{2}* a* t_2[/tex]
[tex]D = 30 * 1.25 - \frac{1}{2}* 0.50* 1.25^2[/tex]
[tex]D = 37.11 \ m [/tex]
So the position of the pluck when the game clock reaches zero is
[tex]k = D - d[/tex]
=> [tex]k = 37.11 - 37[/tex]
=> [tex]k = 0.11 \ m [/tex] beyond the goal post
Given that the goal was score against the Bruins it then means that the Flyer won the game with 2 points