Complete question :
a store specializing in mountain bikes is to open in one of two malls if the first mall is selected the store anticipates a yearly profit of $825,000 if successful a yearly loss of 275,000 otherwise the probability of success is 1/2 if the second mall is selected it is an estimated that the yearly profit will be 550,000 if successful otherwise the annual loss will be 165,000 the probability of success at the second mall is three Fourth (3/4).
What is the expected profit of thesecond mall?
Answer:
$453,750
Step-by-step explanation:
Given the following :
First mall:
Profit if successful = $825,000
Loss if otherwise = $275000
Probability of success = 1/2
Second mall:
Profit if successful = $550,000
Loss if otherwise = $165,000
Probability of success = 3/4
Expected profit of second mall:
If probability of profit ' P(profit)' = 3/4
Then,
Probability of loss P(loss) = 1 - P(profit)
P(loss) = 1 - 3/4 = 1/4
Expected profit:
[P(profit) * profit] + [P(loss) * loss])
(0.75 * $550,000) + (0.25 * (-$165,000))
$412,500 - $41,250 = $453,750
Assume that there is a 6% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive? b. If copies of all your computer data are stored on independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive? four a. With two hard disk drives, the probability that catastrophe can be avoided is . (Round to four decimal places as needed.) b. With four hard disk drives, the probability that catastrophe can be avoided is . (Round to six decimal places as needed.)
Answer: 0.9964
Step-by-step explanation:
Consider,
P (disk failure) = 0.06
q = 0.06
p = 1- q
p = 1- 0.06,
p = 0.94
Step 2
Whereas p represents the probability that a disk does not fail. (i.e. working entire year).
a)
Step 3
a)
n = 2,
let x be a random variable for number...
Continuation in the attached document
The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4178 miles, with a variance of 124,609. If he is correct, what is the probability that the mean of a sample of 40 cars would be less than 4265 miles? Round your answer to four decimal places.
Answer:
P(X' < 4265) = 0.9418
Step-by-step explanation:
Due to the fact that the population is normal, the distribution of the sample mean of 40 cars is;
X' = (x1 + x2 + x3....... + x40)/40
We are given;
Normal mean;μ = 4178 miles
Variance = 124,609
Standard deviation; σ = √variance = √124609 = 353
Formula for standard error of mean = σ/√n = 353/√40 = 55.814
So from the formula;
z = (x - μ)/(σ/√n)
So for P(X' < 4265) we have;
z-value of P(X' < 4265) = (4265 - 4178)/55.814 ≈ 1.56
From the z-table attached, we have for P(z < 1.56) = 0.94179
Approximating to 4 decimal places gives 0.9418
People start waiting in line for the release of the newest cell phone at 5\text{ a.m.}5 a.m.5, start text, space, a, point, m, point, end text The equation above gives the number of people, PPP, in line between the hours, hhh, of 6\text{ a.m.}6 a.m.6, start text, space, a, point, m, point, end text and 11\text{ a.m.}11 a.m.11, start text, space, a, point, m, point, end text, when the doors open. Assume that 6\text{ a.m.}6 a.m.6, start text, space, a, point, m, point, end text is when time h = 1h=1h, equals, 1. What does the 232323 mean in the equation above?
Answer:
There are 23 people in line at 6:00 A.M
Step-by-step explanation:
When you plug in h=1, we get 23 people
h corresponds with the time 6:00 am, as a result there are 23 people in line
The equation represents how many people will come as the hour increases.
23 represents the initial amount of people in line.
(got this from Khan academy too:))
Which point is a solution to y<=3x-4?
Answer:
(3, 1)
Step-by-step explanation:
Plug-in points and see which one works. (x, y). <= means less than or equal to.
Answer:
D. (3,1) is the correct answer
Step-by-step explanation: Just graph this question on a graph, and you will find that (3,1) is in the shaded region, which means it is part of the solution
Three generous friends, each with some cash, redistribute their money as follows: Ami gives enough money to Jan and Toy to double the amount that each has. Jan then gives enough to Ami and Toy to double their amounts. Finally, Toy gives Ami and Jan enough to double their amounts. If Toy has $36 when they begin and $36 when they end, what is the total amount that all three friends have?
Answer:
$252
Step-by-step explanation:
This is quite a neat question, with no fixed equation. Given that each person gives the other two enough money to double their cash, if Toy had 36 dollars beginning, and 36 at the end - presumably the cash of each person, ( their starting and original ) should be the same as well. Respectively each should be a multiple of 36 dollars.
Jan's " give away " = Ami + 36, Jan - 108, Toy + 72
Toy's " give away " = Ami + 72, Jan + 36, Toy - 108
Therefore, we can conclude that Ami = 144 at the start, presuming he gave away 108 dollars, with a remaining 36. Jan, having 144 dollars ( after having his 72 dollars doubled by Ami ) gives 36 to Ami to double his amount, and 72 to double Toy's doubled amount, remaining with 36 dollars. Now Ami has 72 dollars, Jan has 36, and Toy has 144. Then, Toy double's Ami and Jan's amount, giving away 72 and 36 dollars, remaining with 36 dollars himself. Therefore, Ami has 144 dollars, Jan has 72 dollars, and Toy has 36 dollars both at the beginning and end.
144 + 72 + 36 = 252 dollars ( in total )
Answer:
answer is 252
Step-by-step explanation:
Good luck :)
Which is the simplified form of m Superscript negative 8 p Superscript 0? StartFraction 1 Over m Superscript 8 Baseline p EndFraction StartFraction 1 Over m Superscript 8 EndFraction StartFraction p over m Superscript 8 EndFraction m Superscript 8 PLS HELPP
Answer:
Correct Option is : StartFraction 1 Over m Superscript 8 EndFraction
Step-by-step explanation:
=> [tex]m^{-8} p^0[/tex]
According to law of exponents [tex]a^0 = 1[/tex]
=> [tex]m^{-8} (1)[/tex]
Using Law of exponents [tex]a^{-m} = \frac{1}{a^m}[/tex]
=> [tex]\frac{1}{m^8}[/tex]
The simplified form of [tex]m^{-8}p^0[/tex] is [tex]\frac{1}{m^8}[/tex].
The question is not well formatted the question might be as follows:
Which is the simplified form of [tex]m^{-8}p^0[/tex]?
[tex]\frac{1}{m^8p}[/tex][tex]\frac{1}{m^8}[/tex][tex]\frac{p}{m^8}[/tex]m⁸What are exponents?Exponents are numbers that say how many times a number is to be multiplied. For example, 2⁸ means 2 is multiplied 8 times.
How to solve the problem?[tex]m^{-8}p^0[/tex] = [tex]m^{-8}[/tex] since, p⁰=1.
⇒[tex]m^{-8}[/tex] = [tex]\frac{1}{m^8}[/tex] .
Hence, the simplified form of [tex]m^{-8}p^0[/tex] is [tex]\frac{1}{m^8}[/tex].
To learn more about simplified forms visit- https://brainly.com/question/13242938?referrer=searchResults
#SPJ2
The function f is defined as follows.
f(x) =4x²+6
If the graph of f is translated vertically upward by 4 units, It becomes the graph of a function g.
Find the expression for g(x).
Answer:
g ( x ) = 4x^2 + 10
Step-by-step explanation:
Solution:-
The translation of a function f ( x ) in the cartesian coordinate domain can be done by following the given guidelines:
Translation guidelines
Horizontal shifts
Right : f ( x ) -> f ( x - a )Left : f ( x ) - > f ( x + a )
Vertical shifts
Up : f ( x ) -> f ( x ) + bDown : f ( x ) - > f ( x ) - bGeneral shift ( Horizontal and Vertical shift )
f ( x ) - > f ( x ± a ) ± b
We are given a function f ( x ) which is to be translated vertically upward 4 units. We will use the guidelines for Vertical shifts, where in this case the magnitude of b = 4.
f ( x ) = 4x^2 + 6
f ( x ) - > f ( x ) + b
g ( x ) = f ( x ) + 4
g ( x ) = 4x^2 + 6 + 4
g ( x ) = 4x^2 + 10 ... Answer
Marie is saving money for home repairs. So far, she has saved $1,558. She needs at least $2,158 for the repairs. She plans to
add $60 per week to her current savings until she can afford the repairs.
In this activity, you will algebraically model and solve an inequality based on this situation and interpret the solutions within
realistic guidelines
Part A
Question
Given the situation, which inequality models the number of additional weeks Marie needs to continue saving to afford the
home repairs?
Select the correct answer.
1,558 + 60x 22,158
60x + 1,558 5 2,158
1,558 - 60x s 2,158
2,158 - 60x 2 1,558
Answer:
Inequality: [tex]1558 + 60 x \geq 2158[/tex]
Number of Weeks: [tex]x \geq 10[/tex]
Step-by-step explanation:
Given
[tex]Initial\ Savings = \$1558[/tex]
[tex]Amount\ Needed = \$2158[/tex]
[tex]Additional\ Savings = \$60\ weekly[/tex]
Required
Represent this using an inequality
Represent the number of weeks as x;
This implies that, She'll save $60 * x in x weeks
Her total savings after x weeks would be
[tex]Initial\ Savings + 60 * x[/tex]
From the question, we understand that she needs at least 2158;
Mathematically, this can be represented as (greater than or equal to 2158)
[tex]\geq 2158[/tex]
Bringing the two expressions together;
[tex]Initial\ Savings + 60 * x \geq 2158[/tex]
Substitute 1558 for Initial Savings
[tex]1558 + 60 * x \geq 2158[/tex]
[tex]1558 + 60 x \geq 2158[/tex]
Hence, the inequality that represents the situation is [tex]1558 + 60 x \geq 2158[/tex]
Solving further for x (number of weeks)
[tex]1558 + 60 x \geq 2158[/tex]
Subtract 1558 from both sides
[tex]1558- 1558 + 60 x \geq 2158 - 1558[/tex]
[tex]60x \geq 600[/tex]
Divide both sides by 60
[tex]\frac{60x}{60} \geq \frac{600}{60}[/tex]
[tex]x \geq 10[/tex]
This means that she needs to save $60 for at least 10 weeks
Answer:
Its the first one
Step-by-step explanation:
I just did it lol
prove that 1/3 root2 is irrational
Step-by-step explanation:
Let us assume that 1/2+root 3 is rational . So 1/2+root 3 = a/b where a and b are irrationals. since rhs is a rational number root 3 should be also rational .
In order to sustain itself in its cold habitat, a Siberian tiger requires 25 pounds of meat per day.
How much meat would seven Siberian tigers need for the month of April?
Select one:
a. 750 pounds
b. 175 pounds
c. 5425 pounds
d. 5250 pounds
Answer:
d. 5250 pounds
Step-by-step explanation:
25 lbs per day
There are 30 days in april
25 lbs/ day * 30 days
1 tiger would eat 750 lbs
There are 7 tigers
7 * 750 =5250 lbs
Answer:
D. 5250 pounds
Step-by-step explanation:
What you need to do is multiply 25 pounds by 30 because there are 30 days in the month of April.
25 x 30 = 750
Then multiply that amount by seven because there are 7 tigers.
750 x 7 = 5250
For the functions f(x)=4x+5 and g(x)=6x+4,find (f•g)(0)and (g•f)(0)
Answer:
Step-by-step explanation:
f(x)=4x+5
g(x)=6x+4,
first: (f*g)=(4x+5) (6x+4)=24x²+46x+20
next:(f*g)(0)=((g*f)=24x²+46x+20=20
Hi,
f°g means : apply first g then f . so calculate "g" and then use result as "x" in f.
g°f means : you apply first f then g
so : f°g = 4 (g (x)) +5
4 (6x+4) +5 = 24x+16+5 = 24x+21
What is the correlation coefficient for the data in the table?
–0.57
–0.28
0.28
0.57
Answer: i believe it’s 0.28, but tbh i’m on a unit test so i can’t see what’s wrong and what’s right. good luck!
Step-by-step explanation:
Answer:
c- 0.28
Step-by-step explanation:
If (x+1) is the factor of polynomial p(x) = ax²+x+1, then find a.
Answer:
a = 0
Step-by-step explanation:
p(x) = ax²+x+1
Let x+1 = 0 => x = -1
Putting in the above polynomial
=> p(-1) = a(-1)^2+(-1)+1
By Remainder Theorem, Remainder will be zero
=> 0 = a(1) -1+1
=> 0 = a
OR
=> a = 0
Answer:
a = 1Step-by-step explanation:
Factors are what we can multiply to get the number.
x² + x + 1
Factor the polynomial.
x(x+1) + 1
ax² + x = x(x + 1)
ax² + x = x² + x
[tex]a=\frac{x^2 +x}{x^2 +x}[/tex]
a = 1
Please answer this correctly without making mistakes I want expert genius or ace people to answer this correctly
Answer:
45.5 km
Step-by-step explanation:
18.3 km + 27.2 km = 45.5 km or 45 km and 500 m
Answer:
45.5km
Step-by-step explanation:
The distance between the locksmith and the furniture=18.3km
The distance between the furniture and the hotel=27.2km
S(locksmith)+S(furniture)=S(hotel)
18.3km+27.2km=45.5km
Hope this helps ;) ❤❤❤
Let me know if there is an error in my answer.
A right triangle has legs with lengths equal to 10 inches and 9x inches. Its hypotenuse measures (x + 10) inches. What is the approximate value of the hypotenuse? 10 inches 10.25 inches 20.25 inches 81 inches
Answer:
10.25 inchesStep-by-step explanation:
Given,
Perpendicular ( p ) = 9x
Base ( b ) = 10
Hypotenuse ( h ) = x + 10
Now, let's find the value of x
Using Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
Plug the values
[tex] {(x + 10)}^{2} = {(9x)}^{2} + {(10)}^{2} [/tex]
Using [tex] {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} [/tex] , expand the expression
[tex] {x}^{2} + 20x + 100 = {(9x)}^{2} + {10}^{2} [/tex]
To raise a product to a power , raise each factor to that power
[tex] {x}^{2} + 20x + 100 = 81 {x}^{2} + {10}^{2} [/tex]
Evaluate the power
[tex] {x}^{2} + 20x + 100 = 81 {x}^{2} + 100[/tex]
Cancel equal terms on both sides of the equation
[tex] {x}^{2} + 20x = 81 {x}^{2} [/tex]
Move x² to R.H.S and change its sign
[tex]20x = 81 {x}^{2} - {x}^{2} [/tex]
Calculate
[tex]20x = 80 {x}^{2} [/tex]
Swap both sides of the equation and cancel both on both sides
[tex]80x = 20[/tex]
Divide both sides of the equation by 80
[tex] \frac{80x}{80} = \frac{20}{80} [/tex]
Calculate
[tex]x = \frac{20}{80} [/tex]
Reduce the numbers with 20
[tex]x = \frac{1}{4} [/tex]
The value of X is [tex] \frac{1}{4} [/tex]
Now, let's replace the value of x to find the approximate value of hypotenuse
Hypotenuse = [tex] \frac{1}{4} + 10[/tex]
Write all numerators above the common denominator
[tex] \frac{1 + 40}{4} [/tex]
Add the numbers
[tex] \frac{41}{4} [/tex]
[tex] = 10.25[/tex] inches
Hope this helps..
best regards!!
Answer:
10.25
Step-by-step explanation:
because I said so ya skoozie
the product of two consequtive integers is 72 the equation x(x+1)=72 represents the situation, where x represents the smaller integer, which equation can be factor and solve for the smaller integer?
Answer:
x² + x - 72 = 0 can be factored into (x - 8)(x + 9) = 0 to find your answer.
Step-by-step explanation:
Step 1: Distribute x
x² + x = 72
Step 2: Move 72 over
x² + x - 72 = 0
Step 3: Factor
(x - 8)(x + 9) = 0
Step 4: Find roots
x - 8 = 0
x = 8
x + 9 = 0
x = -9
Answer:
x² + x - 72 = 0 ⇒ (x - 8)(x + 9) = 0
Step-by-step explanation:
Let the first consecutive integer be x.
Let the second consecutive integer be x+1.
The product of the two consecutive integers is 72.
x(x + 1) = 72
x² + x = 72
Subtracting 72 from both sides.
x² + x - 72 = 0
Factor left side of the equation.
(x - 8)(x + 9) = 0
Set factors equal to 0.
x - 8 = 0
x = 8
x + 9 = 0
x = -9
8 and -9 are not consecutive integers.
Try 8 and 9 to check.
x = 8
x + 1 = 9
x(x+1) = 72
8(9) = 72
72 = 72
True!
The two consecutive integers are 8 and 9.
Which ordered pair is a solution to the system of linear equations? 2x + 3y= 6 –3x + 5y = 10
Answer:
(0,2)
Step-by-step explanation:
solve by addition/elimination
2x + 3y= 6
–3x + 5y = 10
multiply first equation by 3 and second one by 2 to eliminate x)
6x+9y=18
-6x+10y=20 (add the two equations)
6x+9y-6x+10y=38
19y=38
y=38/19=2
2x+3y=6
2x=6-6
x=0
Answer:
a
Step-by-step explanation:
The four-member math team at Pecanridge Middle School is chosen from the math club, which has three girls and five boys. How many different teams made up of two girls and two boys could be chosen?
Answer:
[tex]Total\ Selection = 30\ ways[/tex]
Step-by-step explanation:
Given
Girls = 3
Boys = 5
Required
How many ways can 2 boys and girls be chosen?
The keyword in the question is chosen;
This implies combination and will be calculated as thus;
[tex]Selection =\ ^nC_r = \frac{n!}{(n-r)!r!}[/tex]
For Boys;
n = 5 and r = 2
[tex]Selection =\ ^5C_2[/tex]
[tex]Selection = \frac{5!}{(5-2)!2!}[/tex]
[tex]Selection = \frac{5!}{3!2!}[/tex]
[tex]Selection = \frac{5 * 4 * 3!}{3!*2 * 1}[/tex]
[tex]Selection = \frac{20}{2}[/tex]
[tex]Selection = 10[/tex]
For Girls;
n = 3 and r = 2
[tex]Selection =\ ^3C_2[/tex]
[tex]Selection = \frac{3!}{(3-2)!2!}[/tex]
[tex]Selection = \frac{3!}{1!2!}[/tex]
[tex]Selection = \frac{3 * 2!}{1 *2!}[/tex]
[tex]Selection = \frac{3}{1}[/tex]
[tex]Selection = 3[/tex]
Total Selection is calculated as thus;
[tex]Total\ Selection = Boys\ Selection * Girls\ Selection[/tex]
[tex]Total\ Selection = 10 * 3[/tex]
[tex]Total\ Selection = 30\ ways[/tex]
Jamie's dog eats 3/4 pound of dog food each day. How many pounds of dog
food does Jamie's dog eat in 4 days?
Answer:
The dog will eat 3 lbs
Step-by-step explanation:
Take the amount eaten per day and multiply by the number of days
3/4 * 4 = 3
The dog will eat 3 lbs
Answer:
3 pounds
Step-by-step explanation:
Multiply the amount of dog food per day with the number of days.
[tex]\frac{3}{4} \times 4[/tex]
[tex]\frac{12}{4} =3[/tex]
In 4 days, Jamie's dog will eat 3 pounds of dog food.
A college graduate is curious about the proportion of graduates who have loan debt 20 years after graduating. Let the proportion of graduates who have loan debt 20 years after graduating be p. If the college graduate wishes to know if the proportion of graduates who have loan debt 20 years after graduating is less than 18%, what are the null and alternative hypotheses?
Answer: Null Hypothesis [tex]H_{0}[/tex]: p = 0.18
Alternative Hypothesis [tex]H_{a}[/tex]: p < 0.18
Step-by-step explanation: When doing an experiment, first define the hypotheses you want to test. These hypotheses are Null Hypothesis and Alternative Hypothesis
Null Hypothesis is a general assumption and discloses that there is no relationship between the conditions under consideration. It is the hypothesis the researcher is trying to disprove. It is denoted by the symbol [tex]H_{0}[/tex].
For the college graduate curiosity, the hypothesis the graduate is trying to disprove is that the proportion of students who have loan debt after 20 years of graduation is 18%. Then, Null Hypothesis is [tex]H_{0}[/tex]: p = 0.18
Alternative Hypothesis is the a statement describing a relationship between the collected data. It is what researches try to prove and the results are observations of real causes. It is denoted by the symbol [tex]H_{a}[/tex].
For the graduate study, the alternative is that the proportion is less tahn 18% or 0.18. Then, Alternative Hypothesis: [tex]H_{a}[/tex]: p < 0.18
The Orchard Cafe has found that about 15% of the diners who make reservations don't show up. If 77 reservations have been made, how many diners can be expected to show up? Find the standard deviation of this distribution
Answer:
65 dinners are expected to show up
The standard deviation of the distribution is 3.13
Step-by-step explanation:
Given
Proportion = 15%
Population = 77
Required
Expected Number that'll show up
Standard Deviation
If 15% won't show up; then
100% - 15% = 85% will show up
Expected Number, E(x) of Dinner is calculated as thus;
[tex]E(x) = np[/tex]
Where [tex]p = 85\%[/tex] (calculated above)
and [tex]n = 77[/tex]
Convert p to decimal
[tex]p = 0.85[/tex]
So;
[tex]E(x) = 0.85 * 77[/tex]
[tex]E(x) = 65.45[/tex]
[tex]E(x) = 65[/tex]
65 dinners are expected to show up
Calculating Standard Deviation, SD
Standard Deviation is calculated as;
[tex]SD = \sqrt{np(1-p)}[/tex]
Substitute 0.85 for p and 77 for n
[tex]SD = \sqrt{77 * 0.85 * (1-0.85)}[/tex]
[tex]SD = \sqrt{77 * 0.85 * 0.15}[/tex]
[tex]SD = \sqrt{9.8175}[/tex]
[tex]SD = 3.13328900678[/tex]
[tex]SD = 3.13[/tex] (Approximated)
The standard deviation of the distribution is 3.13
The equation 6x2 - 132 +5 -0 has solutions of the form
NVD
M
(A) Use the quadratic formula to solve this equation and find the appropriate integer values of N.M and D. Do not worry about simplifying the VD yet in this part of the problem.
N = ]:D
M
(B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: -5/2-3/4
Preview
Answer:
(A)
[tex]N = -b = -(-13) = 13\\\\[/tex]
[tex]D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49[/tex]
[tex]M = 2a = 2(6) = 12[/tex]
(B)
[tex]$ x = (\frac{5}{3} , \: \frac{1}{2}) $[/tex]
Step-by-step explanation:
The given equation is
[tex]6x^2 - 13x + 5 = 0[/tex]
The solution is of the form as given by
[tex]$x=\frac{N\pm\sqrt{D}}{M}$[/tex]
(A) Use the quadratic formula to solve this equation and find the appropriate integer values of N, M and D. Do not worry about simplifying the VD yet in this part of the problem.
The quadratic formula is given by
[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]
The equations of N, M and D are
[tex]N = -b[/tex]
[tex]D =b^2 -4ac[/tex]
[tex]M = 2a[/tex]
The values of a, b and c are
[tex]a = 6 \\\\b = -13 \\\\c = 5[/tex]
So,
[tex]N = -b = -(-13) = 13\\\\[/tex]
[tex]D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49[/tex]
[tex]M = 2a = 2(6) = 12[/tex]
(B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: -5/2-3/4
N = 13
D = 49
M = 12
[tex]$x=\frac{13\pm\sqrt{49}}{12}$[/tex]
[tex]$x=\frac{13\pm7}{12}$[/tex]
[tex]$ x=\frac{13+7}{12} $[/tex] and [tex]$ x=\frac{13-7}{12} $[/tex]
[tex]$ x=\frac{20}{12} $[/tex] and [tex]$ x=\frac{6}{12} $[/tex]
[tex]$ x=\frac{5}{3} $[/tex] and [tex]$ x=\frac{1}{2} $[/tex]
[tex]$ x = (\frac{5}{3} , \: \frac{1}{2}) $[/tex]
Hershel had 100 baseball cards that he labeled from 1-100. He started with number
one and marked every 5th card with an X, every 7th card with an O and every 10th
card with a V. What number card will be the first to have all 3 marks (XOV)?
Answer:
Hey there!
This question is basically asking for the least common multiple, or LCM of the three numbers.
If it is a multiple of 10, it has to be a multiple of 5. Thus, the only thing we need to do now, is find the LCM of 10 and 7, which is 70.
Thus, your answer is 70.
Hope this helps :)
Answer:
I think it is 70.
Step-by-step explanation:
I think that is the Lowest common Multiple of 5, 7 and 10:
10 = 2*5
7 = 7
5 = 5
So the LCM is 2 * 5 * 7 = 70.
Find the midpoint of AC.
B (0, a)
C (a, a)
A(0, 0) D (a,0)
Answer:
[tex]\huge\boxed{\bigg(\dfrac{a}{2};\ \dfrac{a}{2}\bigg)}[/tex]
Step-by-step explanation:
The formula of a midpoint:
[tex]M\bigg(\dfrac{x+1+x+2}{2};\ \dfrac{y_1+y_2}{2}\bigg)[/tex]
We have the points
[tex]A(0;\ 0)\to x_1=0;\ y_1=0\\\\C(a;\ a)\to x_2=a;\ y_2=a[/tex]
Substitute:
[tex]\dfrac{x_1+x_2}{2}=\dfrac{0+a}{2}=\dfrac{a}{2}\\\\\dfrac{y_1+y_2}{2}=\dfrac{0+a}{2}=\dfrac{a}{2}[/tex]
Answer:
The answer is (a/2,a/2)
Step-by-step explanation:
Fill in 2 then a
In conclusion (a/2,a/2)
16. Find the equation of a parabola with a focus at (3,1) and a directrix at y = 3.
A) y = 1∕4(x – 3)^2 + 3
B) y = –1∕4 (x – 3)^2 + 3
C) y = –1∕4 (x – 3)^2 + 2
D) y = 1∕4(x – 3)^2 + 2
Answer:
C
Step-by-step explanation:
Any point (x, y) on the parabola is equidistant from the focus and the directrix.
Using the distance formula
[tex]\sqrt{(x-3)^2+(y-1)^2}[/tex] = | y - 3 | ← square both sides
(x - 3)² + (y - 1)² = (y - 3)² ← expand the y- factors
(x - 3)² + y² - 2y + 1 = y² - 6y + 9 ← subtract y² - 2y + 1 from both sides
(x - 3)² = - 4y + 8 ( subtract 8 from both sides )
(x - 3)² - 8 = - 4y ( divide both sides by - 4 )
- [tex]\frac{1}{4}[/tex] (x - 3)² + 2 = y, that is
y = - [tex]\frac{1}{4}[/tex] (x - 3)² + 2 → C
Answer:
Step-by-step explanation:
C) y = –1∕4 (x – 3)^2 + 2
2. Write as a complex number.
Answer:
Your answer is correct ✔️
Step-by-step explanation:
Hope this is correct and helpful
HAVE A GOOD DAY!
Answer:
2√3 + 3i is the answer
Step-by-step explanation:
please help answer this!!!
Answer:
49) [tex]12\,b^4[/tex]
50) [tex]200\,x^6[/tex]
Step-by-step explanation:
Use the properties of exponent to reduce this expressions:
a) [tex]3\,b\,*\,4 \,b^3=(3\,*\,4)\,(b\,*\,b^3)=12\,b^{(1+3)}=12\,b^4[/tex]
b) [tex]5\,x^2\,*\,8\,x\,5\,*\,x^3=(5\,*\,8\,*\,5)\,(x^2\,*\,x\,*\,x^3)=200\,x^{(2+1+3)}= 200\,x^6[/tex]
A sample of radioactive material disintegrates from 6 to 4 grams in 100 days. After how many days will just 3 grams remain?
Answer:
150 days
Step-by-step explanation:
6-4=2
100/2=50
50*3=150
The number of days for the radioactive material to disintegrate to 3 grams is 173.077 days.
The rate of disintegration varies directly proportional to the quantity of the material.
As such, we can say:
[tex]\mathbf{=\dfrac{dN}{dt}\ \alpha \ N}[/tex]
[tex]\mathbf{\implies \dfrac{dN}{N}\ = k dt}[/tex]
Taking the integral form;
[tex]\mathbf{\implies \int \dfrac{dN}{N}\ =\int k dt}[/tex]
[tex]\mathbf{\implies In N =kt+ C---- (1)}[/tex]
When t = 0, N = 6 grams
In(6) = C
∴
When t = 100, N = 4 grams
In (4) = 100k + In6
100 k = 1n (4) - In(6)
[tex]\mathbf{100 k = In (\dfrac{4}{6})}[/tex]
[tex]\mathbf{k = \dfrac{1}{100} In(\dfrac{4}{6})}[/tex]
∴
From equation (1):
[tex]\mathbf{In N = \dfrac{t}{100} In(\dfrac{4}{6})+ In 6}[/tex]
when,
n = 3 grams; we have:[tex]\mathbf{In (3) = \dfrac{t}{100} In(\dfrac{4}{6})+ In 6}[/tex]
[tex]\mathbf{\implies \dfrac{t}{100} In(\dfrac{4}{6}) = In \dfrac{ 3}{ 6}}[/tex]
[tex]\mathbf{t = 100\times \Big ( \dfrac{In (\dfrac{ 3}{ 6})}{ In(\dfrac{4}{6}) }\Big) }[/tex]
[tex]\mathbf{t = 100\times \Big ( \dfrac{0.69314}{ 0.40048}\Big) }[/tex]
t = 173.077 days
Therefore, the number of days for the radioactive material to disintegrate to 3 grams is 173.077 days.
Learn more about radioactive materials here:
https://brainly.com/question/24339152?referrer=searchResults
In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years. Assuming that life expectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and 2000,what will life expectancy be for women in 2100? Assuming the life expectancy between 2000 and 2100 will increase by the same percentage as it did between 1900 and 2000, the life expectancy for women will be —— years
Answer:
49145 years
Step-by-step explanation:
In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years.
Assuming that life expectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and 2000,what will life expectancy be for women in 2100?
In 10 years, the expectancy increased by 85/45 = 17/9
between 2000 and 2100, it will increas by 10 time 10 years, so expected expectancy is [tex]85*(\frac{85}{45})^{10} = 49145[/tex] years
The life expectancy for women will be 49145 years when It will increase by ten times between 2000 and 2100.
What is an exponential function?An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.
It is a relation of the form y = aˣ in mathematics, where x is the independent variable
In one country, women's life expectancy was 45 years in 1990 and 85 years in 2000.
Assuming that life expectancy grows by the same proportion between 2000 and 2100 as it did between 1900 and 2000, we have to determine the life would expectancy for women in 2100
Over a ten-year period, life expectancy rose by 85/45 = 17/9.
It will increase by ten times between 2000 and 2100, therefore the anticipated life expectancy will be
⇒ 85×(85/45)¹⁰
⇒ 85×(1.88)¹⁰
⇒ 49145 years
Hence, the life expectancy for women will be 49145 years
Learn more about exponential function here:
brainly.com/question/11487261
#SPJ2
f(n)=4n-3 find the 15th term of the sequence defined by the explicit rule
Answer:
57
Step-by-step explanation:
f(15)=4(15)-3
f(15)=60-3
f(15)=57
Hope that helps, tell me if you need more help
Answer:
57
Step-by-step explanation:
If you plug 15 into the equation, you get f(15)=4(15)-3
60-3
57
:)