A stone is dropped into a deep well and is heard to hit the water 5 s after being dropped. Determine the depth of the well.

Answer:

You have a displacement of 5 units to the right.

Explanation:

First you go three to the right which lands on the 3 mark. Then you move it 4 to the left which substracts 4, landing the object at -1. Finally you move 6 to the right, and you finish at marker 5. Since displacement is not total distance but just final distance from the start point directly to end point, it is only a displacement of 5.

Answer:

I think it would be +5

Explanation:

I looked on a number line and started at 0.

I then moved the object 3 units to the right and got 3.

I then moved the object 4 units the the left and got -1.

I then moved the object 6 units to the right and my final answer was positive 5. (+5 or just 5)

I hope I was right and helped

Answer:

54.5 kmph

Explanation:

From work-kinetic energy principles, work done by friction on both pavement and gravel shoulder = kinetic energy change of vehicle

ΔK = W = -(f₁d₁ + f₂d₂) where f₁ = frictional force due to pavement = μ₁mg where μ₁ = coefficient of friction of pavement = 0.35, m = mass of vehicle and g = acceleration due to gravity = 9.8 m/s² and d₁ = distance moved by vehicle across pavement = 30 m and

f₂ = frictional force due to gravel shoulder = μ₂mg where μ₂ = coefficient of friction of pavement = 0.50, m = mass of vehicle and g = acceleration due to gravity = 9.8 m/s² and d₂ = distance moved by vehicle across gravel shoulder = 60 m

ΔK = 1/2m(v₁² - v₀²) where v₀ = initial velocity of vehicle, v₁ = final velocity of vehicle = 20 kmph = 20 × 1000/3600 = 5.56 m/s and m = mass of vehicle

So,

ΔK = -(f₁d₁ + f₂d₂)

1/2m(v₁² - v₀²) = -(μ₁mgd₁ + μ₂mgd₂)

1/2(v₁² - v₀²) = -(μ₁gd₁ + μ₂gd₂)

v₁² - v₀² = -2g(μ₁d₁ + μ₂d₂)

v₀² = v₁² + 2g(μ₁d₁ + μ₂d₂)

v₀ = √[v₁² + 2g(μ₁d₁ + μ₂d₂)]

substituting the values of the variables into the equation, we have

v₀ = √[(5.56 m/s)² + 2 × 9.8 m/s²(0.35 × 30 m + 0.5 × 60 m]

v₀ = √[30.91 (m/s)² + 4.9 m/s²(10.5 m + 30 m]

v₀ = √[30.91 (m/s)² + 4.9 m/s²(40.5 m]

v₀ = √[30.91 (m/s)² + 198.45 (m/s)²]

v₀ = √[229.36 (m/s)²

v₀ = 15.14 m/s

v₀ = 15.14 × 3600/1000

v₀ = 54.5 kmph

So, the initial speed of the vehicle is 54.5 kmph

Answer:

1) the correct answer is b and d

2) For force b its direction is vertical up

   for the force d its direction is vertical down

3) the correct answers are: a, c and d

4) Force a is vertical down , force c is vertical up and force d is vertical down

5) the correct answer which is b

Explanation:

In this exercise it is asked to identify the forces, fundamentally on the free there are the forces of gravity and the support force of the hand, with these facts we answer the questions

1) the correct answer is b and d

the hand acts on the book with a contact force and the Earth acts on the book with the force of gravity.

2) For force b its direction is vertical up

   for the force d its direction is vertical down

3) The forces on the hand are the weight of the book. The force of gravity due to the mass of the hand. As the hand is in balance, there must be a force applied by the arm to keep the hand in position; assuming the hand is in the air, if the hand is resting on the floor the force of the floor on the hand can perform this function

therefore the correct answers are: a, c and d

4) Force a is vertical down

    force c is vertical up

   force d is vertical down

5) The action and reaction forces are forces of equal magnitude, each applied to one of the bodies, we have

* the force of the hand on the free and its reaction the force of the book on the hand

* The force of the Earth on the book and the hand, giving the weight of each one and the relationship is the force of the book and the hand on the Earth

the correct answer which is b

Answer:

allows for efficient transport of materials

Explanation:

Living cells relatively have a small size, so small that a microscope is needed to see their structure. However, this small size is for their benefitting as it increases their surface area to volume ratio (SA:V).

A large surface area to volume ratio (SA:V) enables easy movement of molecules to and fro the cell membrane via the process of DIFFUSION. Therefore, having a small size allows for efficient transport of materials needed in the cell.

Answer:

C

Explanation:

From the question we are told that a vector on the x and y plane face their negative axis

Generally  in the x and y plane thr negative y axis is made to face down opposite the positive y axis

Whilst the negative x axis faces the left which is also alternate to the positive x axis

Generally A vector pointing towards the x and y negative axis fro  the origin (0) will definitely be in the third quadrant

Answer:

(a) 98 N

(b) 158 N

(c) 38 N

Explanation:

When the acceleration is 0 m/s², the net force on the mass is 0 N. Therefore, the tension force is equal to the weight force due to Newton's Second Law:

Since the tension in the cable and the weight of the mass are equal to each other, we can solve for the weight force of the mass by using:

Since T = w, we can say that T = 98 N.  

Let's set the upwards direction to be positive and the downwards direction to be negative. We can use Newton's Second Law to solve for the tension in the cable if the acceleration is 6 m/s² upward:

Plug the known values into the equation and solve for T.

The tension in the cable if the acceleration is +6 m/s² is 158 N.

The process is the same, but this time acceleration is -6 m/s².

Plug known values into the equation and solve for T.

The tension in the cable if the acceleration is -6 m/s² is 38 N.

Answer:

A. Time and space are relative.

B. The speed of light in a vacuum is constant for all observers.

D. Physical laws change based on an observer's motion.

E. Physical laws remain constant regardless of an observer's motion.

Explanation:

The statements that explain the special theory of relativity are a),b) and e) respectively.

The special theory of relativity, developed by Albert Einstein, is based on the idea that the laws of physics are the same for all observers who are moving uniformly relative to each other. This means that there is no "absolute" or "preferred" frame of reference in the universe. Instead, all frames of reference are equally valid, and any observer can use their own frame of reference to describe physical phenomena.

One consequence of this idea is that time and space are relative. This means that the measurements of time and distance depend on the observer's frame of reference. For example, if two observers are moving relative to each other, they will measure different lengths and times for the same event. This effect is known as time dilation and length contraction.

Finally, the special theory of relativity applies only to objects with constant velocity. It does not apply to accelerating objects, which require the more general theory of relativity. The special theory of relativity is a fundamental theory in modern physics, and it has important implications for our understanding of space, time, and the nature of reality.

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The correct question is :

Which statements explain the special theory of relativity? Check all that apply.

a) Time and space are relative.

b) The speed of light in a vacuum is constant for all observers.

c) Physical laws change based on an observer's motion.

d) Physical laws remain constant regardless of an observer's motion.  

e) The special theory of relativity applies to objects with constant velocity.

f) The special theory of relativity applies to accelerating objects.

Sphere A travels a horizontal distance of (10 m/s) t after time t, while sphere B travels a distance of (5 m/s) t. So sphere B lands on the floor some point between the table's edge and the point X (A).

Answer:

The second graph, B

Explanation

Answer:

I belive it is the thickness of the wire

Explanation:

There are no other answers and I searched it up and it seems that it is the thickness of the wire.

A current is induced in a wire by moving the wire through a magnetic field. A factor that affects the direction of the current is  the direction in which the wire moves.

Magnetic field is the region of space where an object experiences the magnetic force towards a magnetic material.

The direction of flow of electric current in a current carrying conductor wire depends on many factors. The direction of the wire moves in or out and current will flow towards the direction of a given wire.

Hence, a factor that affects the direction of the current is in the direction in which the wire moves.

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Answer:

1 µC

Explanation:

From the question given above, the following data were obtained:

Electric field intensity (E) = 9000 N/C

Distance (r) = 1 m

Charge (Q) =?

NOTE: Electric force constant (K) = 9×10⁹ Nm²C¯²

The magnitude of the point charge can be obtained as follow:

E = KQ/r²

9000 = 9×10⁹ × Q / 1²

9000 = 9×10⁹ × Q

Divide both side by 9×10⁹

Q = 9000 / 9×10⁹

Q = 1×10¯⁶ C

Recall:

1 micro charge (µC) = 1×10¯⁶ C

Hence, the magnitude of the point charge is 1 µC

Answer:

Explanation:

The magnitude of the point charge is expressed as;

V = kQ/r

k is the coulombs constant = 9.0×10^9 N⋅m²/C²

V is the electric field = 9000N/C

Q is the charge

r is the distance = 1.00m

Get the required charge

Substitute the given parameters into the formula;

9000 = 9.0×10^9Q/1.0

9000 = 9.0×10^9Q

Q = 9000/9.0×10^9

Q = 9.0×10^3/9.0×10^9

Q = 9.0/9.0×10^(3-9)

Q = 1.0×10^6C

Q = 1ηC

hence the magnitude of the point charge is 1ηC

Answer:

The total power is  [tex]P = 6.665 *10^{4} \ W[/tex]        

Explanation:

From the question we are told that

     The distance is  [tex]r = 10 \ km = 1000 \ m[/tex]

      The amplitude of the electric field is   [tex]E = 0.20 \ volt/meter[/tex]

Generally the average intensity of the electromagnetic field from the radio transmitter is mathematically represented  as

           [tex]I = \frac{E^2}{ 2 \mu_o * c }[/tex]

Here c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

         [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4\pi *10^{-7} \ N/A^2[/tex]

So

           [tex]I = \frac{0.2^2}{ 2 * 4\pi *10^{-7} * 3.0*10^{8} }[/tex]      

=>        [tex]I = 5.307 *10^{-5} \ W/m^2[/tex]

Generally this intensity can also be mathematically represented as

               [tex]I = \frac{P }{ 4 \pi r^2 }[/tex]

=>           [tex]P = I ( 4 \pi r^2 )[/tex]        

=>           [tex]P = 5.307 *10^{-5} ( 4 * 3.142 * 1000^2 )[/tex]        

=>           [tex]P = 6.665 *10^{4} \ W[/tex]        

The total power emitted by the radio transmitter is [tex]6.67\times 10^4 \ W[/tex].

The given parameters;

The intensity of the radio wave from the transmitter is calculated as follows;

[tex]I = \frac{E^2}{2\mu_0 c} \\\\I = \frac{0.2^2 }{2\times 4\pi \times 10^{-7} \times 3\times 10^8} \\\\I = 5.305 \times 10^{-5} \ W/m^2[/tex]

The total power emitted by the radio transmitter is calculated as follows;

[tex]I = \frac{P}{A} \\\\P = IA\\\\P = I \times 4\pi r^2\\\\P = (5.305\times 10^{-5} )\times 4\pi \times (10,000)^2\\\\P = 6.67\times 10^{4} \ W[/tex]

Thus, the total power emitted by the radio transmitter is [tex]6.67\times 10^4 \ W[/tex].

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Answer: Depends on the context.

Explanation: While simply throwing a football won’t breach the sound barrier, a specialized jet can breach it easily. It all just depends on your definition of an object. Hope this helps!

Answer:

  C)  There will be no change in the balance

Explanation:

Before and after the cork is placed, the masses in each pan are the same. There will be no change in the balance.

Answer:

20m

Explanation:

The two tens cancel each other out, as they are in opposite directions. Now we only care about the 20m, which if we have no 10's, will end up 20m away.

The distance covered by man is 40 m and the displacement is 20 m towards the east.

The distance can be defined as the measurement of the total ground covered by an object during its motion. It is a scalar quantity.

The displacement can be defined as the measurement of the shortest path over the ground is covered by an object during its motion. It is a vector quantity.

Given that a man starts walking towards the north and covered 10 m. he turns east and walks for 20 m then turns right and walks for 10 m. The attachment shows the total ground area covered by the man.

The total distance covered by the man is given below.

[tex]D = 10 + 20 + 10[/tex]

[tex]D = 40 \;\rm m[/tex]

The displacement of the man is the difference between its final position and initial position.

[tex]d = 20 - 0[/tex]

[tex]d = 20 \;\rm m[/tex]

Hence we can conclude that the distance covered by man is 40 m and the displacement is 20 m towards the east.

To know more about distance and displacement, follow the link given below.

Answer:

W = 0

Explanation:

As the satellite moves in a circle the force is perpendicular to the path, therefore the work that is defined by

      W = F. r = f r cos θ

Since the force and the radius are perpendicular, the angle θ = 90º and the cosine 90 = 0, therefore there is no work for the circular motion.

W = 0

Answer:

As you know, the denser objects have more weight per unit of volume, this will mean that the force that pulls down these objects is a bit larger.

This will mean that the denser objects will always go to the bottom.

This clearly implies that the red liquid, the one with one of the smaller densities, can not be at the bottom.

There are some cases where a liquid with a small density may become a lot denser as the temperature or pressure changes, and in a case like that, we could see the red liquid at the bottom, but for this case, there is no mention of changes in the temperature nor in the pressure, so this can be discarded.

The only thing that makes sense is that the red part at the bottom is the base of the tube, and has nothing to do with the red liquid.

Answer:

a)   α = 0.0334 rad / s² ,  b) w = 2.14  rad/s see that the angular velocity doubles.

Explanation:

This is a magular kinematics exercise

Let's reduce the magnitudes to the SI system

   w = 0.17 rev /s (2π rad / 1rev) = 1.07 rad / s

a) as part of rest its initial velocity is zero w or = 0

        w = w₀ + α t

        α = [tex]\frac{\omega -\omega_{o} }{t}[/tex]

        α = [tex]\frac{1.07-0}{32}[/tex]

         α = 0.0334 rad / s²

b) If we double the angular relation what will be the final velocity

       w = w₀ + (2α) t

       w = 0 + 2 0.0334 32

       w = 2.14  rad/s

We see that the angular velocity doubles.

Answer:

if the angular momentum is constant, the skater is closer, going faster.  

  w₂ = r₁² / r₂² w₁

Explanation:

For the skaters to perform in the turn in l, the angular number of the same must be equal, so we stammer the concept of conservation of angular momentum

             L₁ = L₂

the angular momentum is

           L = I w

we substitute

             I₁ w₁ = I₂ w₂

             w₂ = [tex]\frac{I_{1} }{I_{2} }[/tex] w₁

if we consider the skater as a particle, his moment of inertia is

             I = m r²

we substitute

              w₂ = r₁² / r₂² w₁

therefore, if the angular momentum is constant, the skater is closer, going faster.

Answer:

66.6N

Explanation:

Step one;

given data

the mass of the lamp = 200N

we are told that it is suspended by 3 cables.

Now we know that the weight will be distributed equally on the cables

Step two:

so, let the tension in each cable be T

T+T+T= 200

3T=200

T=200/3

T=66.6N

The tenion on each cable is 66.6N

Answer:

getc+d

Explanation:

gger

Answer:

The value is  [tex]F = 1.568 *10^{-9} \ N[/tex]

Explanation:

From the question we are told that

     The mass  of the first lead sphere is [tex]m = 1.60 \ kg[/tex]

      The mass of the second lead sphere is  [tex]M = 16 \ g = 0.016 \ kg[/tex]

      The separation between masses is  [tex]r = 3.30 \ cm = 0.033 \ m[/tex]

Generally the gravitational force between each sphere is mathematically represented as

          [tex]F = \frac{G * m * M }{r^2 }[/tex]

Here G is the gravitational constant with value  [tex]G = 6.67 *10^{-11 } \ m^3 \cdot kg^{-1} \cdot s^{-2}[/tex]

         [tex]F = \frac{6.67 *10^{-11 } * 1.60 * 0.016 }{0.033^2 }[/tex]

=>       [tex]F = 1.568 *10^{-9} \ N[/tex]

Answer:

D. There are fewer younger adults than older adults.

Explanation:

Failed the assignment but got this answer correct.

Answer:

D is correct

Explanation:

Answer:

Low-temperature blackbody

Explanation:

There are 3 types of blackbody temperatures.

Low-temperature blackbody

High temperature extended area blackbody

High-temperature cavity blackbody

A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.

Answer:

at the highest point the velocity and acceleration are perpendicular but when projectile starts to move are said to be parallel to one another

Explanation:

the clear explanation is shown above.

Answer:

a) 113N

b) 0.37

Explanation:

a) Using the Newton's second law:

\sum Fx =ma

Since the crate doesn't move (static), acceleration will be zero. The equation will become:

\sum Fx = 0

\sumFx = Fm - Ff = 0.

Fm is the applied force

Ff is the frictional force

Since Fm - Ff = 0

Fm = Ff

This means that the applied force is equal to the force of friction if the crate is static.

Since applied force is 113N, hence the magnitude of the static friction force will also be 113N

b) Using the formula

Ff = nR

n is the coefficient of friction

R is the reaction = mg

R = 31.2 × 9.8

R = 305.76N

From the formula

n = Ff/R

n = 113/305.76

n = 0.37

Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37

Answer:

I believe C

Explanation:

i never learned this sorry

Answer:

agree  eager  eagre  ragee

Explanation:

hope this help

Answer:

C. Oxygen

Explanation:

Oxygen is the 8th element.

Answer:

While there is no text here are some climate conditions you could go off of, tropical, dry, temperate, cold, and polar, hope this helps you with whatever your trying to do

Explanation: