A star is observed to have a temperature of 3000 k and a luminosity of 105. what is the color of the star? what group does the star belong to?

Answer:

Approximately [tex]1.79 \times 10^{5}\; {\rm N \cdot m^{-1}}[/tex], assuming friction between the vehicle and the ground is negligible.

Explanation:

Let [tex]m[/tex] denote the mass of the vehicle. Let [tex]v[/tex] denote the initial velocity of the vehicle. Let [tex]k[/tex] denote the spring constant (needs to be found.) Let [tex]x[/tex] denote the maximum displacement of the spring.

Convert velocity of the vehicle to standard units (meters per second):

[tex]\begin{aligned}v &= 20.8\; {\rm km \cdot h^{-1}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \\ &\approx 1.908\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].

Initial kinetic energy ([tex]{\rm KE}[/tex]) of the vehicle:

[tex]\begin{aligned}\frac{1}{2}\, m \, v^{2}\end{aligned}[/tex].

When the vehicle is brought to a rest, the elastic potential energy ([tex]\text{EPE}[/tex]) stored in the spring would be:

[tex]\displaystyle \frac{1}{2}\, k\, x^{2}[/tex].

By the conservation of energy, if the friction between the vehicle and the ground is negligible, the initial [tex]\text{KE}[/tex] of the vehicle should be equal to the [tex]{\rm EPE}[/tex] of the vehicle. In other words:

[tex]\begin{aligned}\frac{1}{2}\, m \, v^{2} &= \frac{1}{2}\, k\, x^{2}\end{aligned}[/tex].

Rearrange this equation to find an expression for [tex]k[/tex], the spring constant:

[tex]\begin{aligned}k &= \frac{m\, v }{x^{2}}\end{aligned}[/tex].

Substitute in the given values [tex]m = 1508\; {\rm kg}[/tex], [tex]v \approx 1.908\; {\rm m\cdot s^{-1}}[/tex], and [tex]x = 6.87\; {\rm m}[/tex]:

[tex]\begin{aligned}k &= \frac{m\, v }{x^{2}} \\ &\approx \frac{1508\; {\rm kg} \times 1.908\; {\rm m\cdot s^{-1}}}{(6.87\; {\rm m})^{2}} \\ &\approx 1.79 \times 10^{5}\; {\rm kg \cdot m \cdot s^{-2} \cdot m^{-3}}\\ &\approx 1.79 \times 10^{5}\; {\rm N \cdot m^{-1}}\end{aligned}[/tex]

Answer:

torques must balance for equilibrium

counterclockwise = clockwise

1.5 X = 4 * 20

x = 80 N-m / 1.5 m = 53 N

(D) is correct

Answer:

Etiquette determines which behaviors are polite and impolite among players and team. It is a code of polite conduct according to social norms and efficiency. Etiquette as a societal rule is formed to enhance positive human relation when interacting and can reduce conflicts in the society. A person who is aware of the etiquette in a given situation will be more confident, comfortable and competent thus making even those around him or her at ease.

Answer:

3904 Meters

Explanation:

F = ma

work = F * d

89.1 (9.8)* d        = 815000/.23906                                                                                                     conversion factor  1 j = .23906 cal

d = 3904 meters

Answer:

n Hz

Explanation:

I think I'm Sry if it is wrong.

The charge would be in equilibrium so there would be no charge in the body of the conductor.

Answer:

(b) there cannot be any charge in the body of the conductor

Answer:

B

Explanation:

Note the line that there is no charges anywhere else outside means the charge is placed in equilibrium position.

Hence there cannot be any charge in the body of conductor

Answer:

Explanation:

Remark

The answer is in the formula

E = I * R

Solution

Let the resistance = R

I = 12/R

If we increase the resistance by 20% then we get

R1 = R + (20/100) * R

R1 = R + 1/5 * R

R1 = 6 R/5

What happens to I when you do this

I = 12/(6/5 R)       Effectively you need to treat 6/5 as a reciprocal

I = 12 * 5/6 * R

I = 10 / R

What does this tell you? Since the Resistance has a base value of R, when increased by 20%, the numerator of the fraction is reduced to 10 from 12. In other words the current  is now smaller when R goes up.

When an object in simple harmonic motion is at its maximum displacement, its acceleration is also at a maximum.

Reason: The speed is zero when the simple harmonic motion is at its maximum displacement, however, the acceleration is the rate of change of velocity. The velocity reverses the direction at that point therefore its rate of change is maximum at that moment. thus the acceleration is at its maximum at this point

Hope that helps!

Answer:

true

Explanation:

i did the test

We can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is moving.

These are small organs located in the inner ear. They serve a very important function in our everyday life. These otolith organs are responsible for the detection of movement and provide us with a sense of spatial orientation. They accomplish this by stimulating very small, hair-like cells with a specialized fluid.

Therefore, we can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is accelerating or decelerating.

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Answer:

virtual, upright, smaller

Explanation:

yes

The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

E = mgh

Divide both side by mg

h = E / mg

h = 428706.6 / (73.9 × 9.8)

h = 591.95 m

Divide by 1000 to express in km

h = 591.95 / 1000

h = 0.59 Km

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When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called a Neutron star.

Stars are present in the galaxy that have the ability to generate their own light. They are both quite hot and very huge.

They are largely formed of hydrogen, with a trace of helium thrown in for good measure.

The sun is also a star, and its energy and light play an important part in the survival of all kinds of life on Earth.

When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called a Neutron star.

Hence the correct answer is a neutron star.

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Answer:

मार्क ASL brainlisessjd

Answer:

The answer for cos(30°) is 0.87

Explanation:

w = v/r

= 15/ 45 = 1/3 rads-¹

a = w²r

= 1/9 • 45 = 5 ms-²

F = mv²/r

= 1200• 15• 15/45

= 6000N

The car, when rounding the curve, is pulled towards the center by the friction between it's wheels and the road.

Answer:

i dont know but ill update you

Answer:

increases   increases   decreases

Explanation:

For an object falling from a height

Answer:

11.98 N

Explanation:

Normal force =   mg =  2.03 * 9.81

coeff of static friction must be overcome for the book to begin moving

       .602 = F / (2.03 * 9.81)   = 11.98  N

Answer:

intellectual disabilities

Founded in 1968 by Eunice Kennedy Shriver, Special Olympics provides people with intellectual disabilities continuing opportunities to realize their potential, develop physical fitness, demonstrate courage and experience joy and friendship.

Explanation:

Answer:

mechanical

Explanation:

the energy is carried by water <3 hope this helped

Answer:

[tex]F_{k} = 9854N[/tex] Opposite to the motion of the car.

Explanation:

Please find the detailed solution below

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

Answer:

8.16 seconds, enjoy physics

A 1,500kg boulder falls off a 120m tall cliff on a planet that has a surface gravitational field of magnitude 3. 6 N/kg. Assume that the planet has no atmosphere, it would take 8.16 seconds for the boulder to strike the ground

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

where u and v are the initial and final velocity respectively

S is the total distance covered by the object

a is the acceleration of the object

As given in the problem a 1,500kg boulder falls off a 120m tall cliff on a planet that has a surface gravitational field of magnitude 3. 6 N/kg. Assume that the planet has no atmosphere

S = 120m, the initial velocity of the boulder is zero

u = 0

g = 3.6 m/s²

S = ut + 1/2at²

u= 0m/s , a= 3.6 m/s² and t = ? seconds

120  = 0×t + 0.5×3.6×t²

t² = 120 /(3.6×0.5)

t² = 66.667

t = 8.16 seconds

Thus, it would take 8.16 seconds for the boulder to strike the ground

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In the early 20th century, the average luminosity in Cepheid variable stars was related to: the period of time it takes to vary.

A cosmic distance can be defined as an accurate and precise measurement of the distance to celestial or astronomical objects such as:

In the early 20th century, a discoery of the average luminosity in Cepheid variable stars was related by astronomers to the period of time it takes to vary and this helped tremendously in the measurement of cosmic distances.

Read more on cosmic distance here: https://brainly.com/question/23428619

Answer:

1.66 x 10^-6 m

Explanation:

Answer:

2.5 kg - m/s

Explanation:

Momentum = m * v = .5 * 5 = 2.5  kg-m/s

The equation is not balance because the law of conservation of mass is not being followed.

The hydrogen and chlorine atoms have different numbers of atoms in the reactants and products which is not balance on both sides i.e. reactant and products.

So we can conclude that the equation is not balance because the law of conservation of mass is not being followed.

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Answer:(a) With our choice for the zero level for potential energy of the car-Earth system when the car is at point B ,

          U

B

​

=0

When the car is at point A, the potential energy of the car-Earth system is given by

          U

A

​

=mgy

where y is the vertical height above zero level. With 135ft=41.1m, this height is found as:

y=(41.1m)sin40.0

0

=26.4m

Thus,

U

A

​

=(1000kg)(9.80m/s

2

)(26.4m)=2.59∗10

5

J

The change in potential energy of the car-Earth system as the car moves from A to B is

U

B

​

−U

A

​

=0−2.59∗10

5

J=−2.59∗10

5

J

(b) With our choice of the zero configuration for the potential energy of the car-Earth system when the car is at point A, we have U

A

​

=0. The potential energy of the system when the car is at point B is given by U

B

​

=mgy, where y is the vertical distance of point B below point A. In part (a), we found the magnitude of this distance to be 26.5m. Because this distance is now below the zero reference level, it is a negative number.

Thus,