A spring with a k value of 350 and a mass of 5 grams is compressed and released, converting all EPE into GPE. It rises up to a height of 4.37 meters before stopping, assuming no energy is lost to friction.
The potential energy stored in a spring is given by the formula:
[tex]EPE = 1/2 \times k \times x^2[/tex]
where k is the spring constant and x is the displacement of the spring from its equilibrium position. In this case, the spring is compressed by 3.5 cm or 0.035 meters, so the potential energy stored in the spring is:
[tex]EPE = 1/2 \times 350 \times 0.035^2 = 0.214 J[/tex]
When the spring is released, all of this potential energy is converted into gravitational potential energy (GPE) as the spring rises up in the air. The formula for GPE is:
[tex]GPE = m \times g \times h[/tex]
where m is the mass of the object, g is the acceleration due to gravity, and h is the height above the starting position.
Substituting the values given in the problem, we get:
[tex]0.214 J = 0.005 \;kg \times 9.81 \;m/s^2 \times h[/tex]
Solving for h, we get:
[tex]h = 0.214 J / (0.005 \;kg \times 9.81 \;m/s^2) = 4.37 m[/tex]
Therefore, the spring will rise up to a height of 4.37 meters before coming to a stop, assuming no energy is lost to friction.
In summary, by using the formulas for potential energy and gravitational potential energy, we can calculate the height that a spring will reach when launched into the air.
We found that the spring with a k value of 350 and a mass of 5 grams, when compressed 3.5 cm and released, will rise up to a height of 4.37 meters if all EPE is converted into GPE and no energy is lost to friction.
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Which branch of science is more interesting for you? Write any two points about your interest. What scopes do you expect in the corresponding branches of science?
Answer:
My most interesting branch of science is psychology the study of the human mind branches out into so many different fields and effects everything even how we science
Explanation:
HYSICS What mass of lead has the volume as 1 600 kg of alcohol? the values of densities given in table2.7)
Explanation:
Solution:
Density of alcohol = 600kg/m³
In g/cm³ = 600/1000
= 0.60 g/cm³
What affects the thermal conductivity of earth materials? (Ex: Water, Soil, Sand, Air, etc.)
The factors that affect the thermal conductivity of earth materials include porosity, density, mineral composition, moisture content, etc.
Factors affecting thermal conductivity of earth materialsThe thermal conductivity of earth materials depends on several factors, including:
Porosity: The thermal conductivity of earth materials increases with decreasing porosity. Moisture content: The thermal conductivity of earth materials increases with increasing moisture content. Mineral composition: The thermal conductivity of earth materials depends on the relative abundance of different minerals present.Density: The thermal conductivity of earth materials increases with increasing density. Temperature: The thermal conductivity of earth materials generally increases with increasing temperature. Structure: The thermal conductivity of earth materials can also be influenced by their structure, such as the arrangement of particles or the presence of fractures or voids.More on thermal conductivity can be found here: https://brainly.com/question/7643131
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A friend wants to know whether her wedding ring is made of pure gold or of a mixture of gold and silver.
a)Describe an investigation to answer her question.
b)Explain what is likely to be the most significant source of error in your answer.
The density of gold is 19. 3g/cm and the density of silver is 10. 5g/cm
The investigation provides a useful method for determining the composition of a wedding ring, but caution should be taken in interpreting the results due to potential sources of error.
a) To investigate whether the wedding ring is made of pure gold or a mixture of gold and silver, we can use the density of the ring as a clue. Firstly, we need to weigh the ring using a scale with high precision. Then, we can calculate the volume of the ring by measuring its dimensions and using the formula for the volume of a cylinder (V=πr²h). Once we have the weight and volume of the ring, we can calculate its density by dividing the weight by the volume. If the density of the ring is close to the density of pure gold (19.3g/cm³), then the ring is likely to be made of pure gold. However, if the density of the ring is lower than that of pure gold, it may indicate that the ring is made of a mixture of gold and silver.
b) The most significant source of error in our investigation is that the ring may contain other metals or impurities that affect its density. Additionally, the precision of the scale and measurements of the ring's dimensions can also affect the accuracy of our calculations. Therefore, we need to use high-precision instruments and repeat our measurements several times to ensure the accuracy of our results.
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If you had 3. 8 x 10^22 J of energy and you had a machine that could turn all of that energy into mass, what would be your mass in kg?
If you had 3.8 x 10^22 J of energy and a machine that could turn all of that energy into mass, your mass would be approximately 4.23 x 10^5 kg.
To find the mass, we will use the mass-energy equivalence formula, which is represented by the famous equation E=mc^2. Here, E is the energy, m is the mass, and c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s).
Step 1: Given energy, E = 3.8 x 10^22 J
Step 2: Speed of light, c = 3.00 x 10^8 m/s
Step 3: Rearrange the equation E=mc^2 to solve for mass: m = E / c^2
Step 4: Plug the given energy and speed of light into the equation: m = (3.8 x 10^22 J) / (3.00 x 10^8 m/s)^2
Step 5: Calculate the mass: m = (3.8 x 10^22 J) / (9 x 10^16 m^2/s^2) = 4.23 x 10^5 kg
So, if you were able to convert all 3.8 x 10^22 J of energy into mass, the resulting mass would be approximately 4.23 x 10^5 kg.
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Describe the energy changes as a pendulum swings if the pendulum has a mass of 50g and is lifted so that has a GPE of 0. 1j calculate a,its increase in height
b,the velocity of the bob as it pass through the bottom of the swing (assume no energy losses
The increase in height of the pendulum is: approximately 2.04 cm, and the velocity of the bob as it passes through the bottom of the swing is approximately 0.894 m/s.
a) To calculate the increase in height, we can use the formula for GPE: GPE = mgh, where m is the mass (50g or 0.05kg), g is the gravitational acceleration (approximately 9.81 m/s^2), and h is the height.
Given that the GPE is 0.1 J, we can rearrange the formula to solve for h:
h = GPE / (mg).
Plugging in the values, we get h = 0.1 / (0.05 * 9.81) ≈ 0.0204 m or 2.04 cm.
b) As the pendulum swings, its GPE is converted to KE at the bottom of the swing. We can use the conservation of energy principle, which states that the total energy (GPE + KE) remains constant. Since the GPE at the top of the swing equals the KE at the bottom,
we can use the formula for KE to find the velocity of the bob:
KE = 0.5 * m * v^2, where m is the mass (0.05kg) and v is the velocity.
We know that the GPE is 0.1 J, so we can set this equal to the KE and solve for v: 0.1 = 0.5 * 0.05 * v^2. Rearranging and solving for v, we get v ≈ 0.894 m/s.
In summary, the increase in height of the pendulum is approximately 2.04 cm, and the velocity of the bob as it passes through the bottom of the swing is approximately 0.894 m/s.
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complete question:
Describe the energy changes as a pendulum swings if the pendulum has a mass of 50g and is lifted so that has a GPE of 0. 1 calculate
a. its increase in height
b. the velocity of the bob as it pass through the bottom of the swing
Which of the following would be the best way to find experimental evidence of the different types of materials that condensed as a function of distance from the sun during the period of accretion in the solar nebula?.
The best way to find experimental evidence of the different types of materials that condensed as a function of distance from the sun during the period of accretion in the solar nebula is through astronomical observations.
By observing the composition of planets and asteroids at different distances from the sun, scientists can determine the types of materials that condensed as a function of distance. For example, the inner planets are composed of denser materials than the outer planets, indicating that different materials condensed at different distances from the sun.
Additionally, by studying meteorites and comets, which are believed to be left over from the formation of the solar system, scientists can gain insight into the composition of materials that condensed at various distances from the sun. Finally, using spectroscopy to analyze the composition of dust in interstellar clouds can provide evidence of the types of materials that condensed at different distances from the sun in the solar nebula.
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The force responsible for normal expiration is supplied by the:.
The force responsible for normal expiration is supplied by the elastic recoil of the lungs and chest wall. During inhalation, the diaphragm and intercostal muscles contract, causing the chest cavity to expand and the lungs to fill with air.
When the muscles relax, the chest cavity and lungs recoil back to their resting positions, expelling air out of the lungs. The elastic recoil of the lungs and chest wall generates the force needed for normal expiration.
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How long does it take to shut down a nuclear reactor?.
Shutting down a nuclear reactor can take anywhere from a few minutes to several hours, depending on the type of reactor and the circumstances surrounding the shutdown.
In a normal shutdown, it typically takes a few hours to fully cool down the reactor and bring it to a safe, stable state.
However, in an emergency situation such as a reactor malfunction or natural disaster, the shutdown process may need to be accelerated to prevent a catastrophic event.
In such cases, emergency cooling systems and other safety measures may be employed to shut down the reactor as quickly as possible.
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In 1992, residents of Arkansas consumed, on average, 11. 4 L of gasoline per
vehicle per day. If this amount of gasoline burns completely in a pure combustion
reaction, it will release 4. 3 * 10% J of energy. Suppose this amount of energy is
transferred by heat from a quantity of gas confined in a very large cylinder. The
cylinder, however, is equipped with a piston, and shortly after the energy is
transferred by heat from the cylinder, work is done on the gas. The magnitude of
the energy transferred by work is equal to one-third the magnitude of the
energy transferred by heat. If the initial internal energy of the gas is 1. 00 x 10°J,
what is the final internal energy of the gas?
The final internal energy of the gas is 1.07 x [tex]10^{10[/tex] J.
What is Energy?
Energy is a fundamental physical quantity that refers to the ability of a system to do work or produce heat. It is a scalar quantity that has many different forms, including kinetic energy, potential energy, thermal energy, electromagnetic energy, and more.
The energy released by the combustion of 11.4 L of gasoline per vehicle per day is given as 4.3 x [tex]10^{7[/tex] J. Let's assume that this energy is transferred by heat to the gas in the cylinder. The energy transferred by work is one-third of this, which is 4.3 x [tex]10^{7[/tex] J / 3 = 1.43 x [tex]10^{7[/tex]J.
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
In this case, the heat added to the system is 4.3 x [tex]10^{7[/tex] J, and the work done by the system is -1.43 x [tex]10^{7[/tex] J (since work done on the gas is negative). Therefore, the change in internal energy is:
ΔU = 4.3 x [tex]10^{7[/tex]J - (-1.43 x [tex]10^{7[/tex] J) = 5.73 x [tex]10^{7[/tex] J
Since the initial internal energy of the gas is 1.00 x [tex]10^{10[/tex] J, the final internal energy is:
Uf = Ui + ΔU = 1.00 x [tex]10^{10[/tex] J + 5.73 x [tex]10^{7[/tex] J = 1.07 x [tex]10^{10[/tex] J
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Which part of the scapula articulates with the clavicle?.
The part of the scapula that articulates with the clavicle is called the acromion process. The acromion process is a bony projection located at the lateral end of the scapula, and it forms a joint called the acromioclavicular joint (AC joint) with the medial end of the clavicle. This joint allows for movement and stability between the scapula and the clavicle, contributing to the overall mobility of the shoulder.
In addition to the acromion process, there is another part of the scapula that articulates with the clavicle. It is called the lateral end of the clavicle. The lateral end of the clavicle forms a joint called the sternoclavicular joint with the medial end of the clavicle. This joint connects the clavicle to the sternum and allows for movement and stability of the shoulder girdle.
To summarize, the scapula articulates with the clavicle at two different joints: the acromioclavicular joint (AC joint) formed by the acromion process of the scapula and the medial end of the clavicle, and the sternoclavicular joint formed by the lateral end of the clavicle and the sternum. These joints play a crucial role in shoulder movement and stability.
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What is the relationship between distance and magnetic force?
As you increase the distance between the magnet and the paper clip, does the magnetic force increase or decrease?
a. As distance increases, magnetic force increases.
b. As distance increases, magnetic force decreases.
c. As distance increases, magnetic force stays the same
Answer:
b. As distance increases, magnetic force decreases.
Explanation:
The correct answer is b. As distance increases, the magnetic force decreases. Magnetic force obeys an inverse square law with distance. This means that the force is inversely proportional to the distance squared. For example, if the distance between two magnets is doubled, the magnetic force between them will fall to a quarter of the initial value.
If five equal resistors dissipate a total of 10 W in a series circuit, how much power does each resistor dissipate
The power dissipated by each resistor in a series circuit can be calculated by dividing the total power dissipated by the number of resistors in the circuit.
In this case, since there are five equal resistors, we can divide the total power dissipated (10 W) by the number of resistors (5) to find the power dissipated by each resistor. Therefore, each resistor dissipates 2 W of power (d).
It is important to note that in a series circuit, the current flowing through each resistor is the same, and the voltage across each resistor is proportional to its resistance. Therefore, the power dissipated by each resistor is also proportional to its resistance. In other words, the resistor with higher resistance will dissipate more power compared to the one with lower resistance.
Understanding how to calculate the power dissipated by each resistor in a series circuit is essential in designing and troubleshooting electrical circuits, as it helps in determining the power rating and specifications of the resistors needed for a specific application.
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If the 50-kg crate starts from rest and achieves a velocity of v = 4 m/s
when it travels a distance of 5 m to the right, determine the magnitude of
force P acting on the crate. The coefficient of kinetic friction between the
crate and the ground is μk = 0. 3
Answer:
given m = 50 kg u = 0 m/s v = 4m/s force = P theta = 30 deg
Explanation:
What type of reaction is being shown in this energy diagram?
Energy
Reactants
to
Activation
Energy
ħ₁.
Products
Time
Answer: thermodynamics energy
Narrower
Write True if the statement is correct and change the underlined word/s if it is wrong.
1.
Gravity is a contact force that acts between two separate objects.
2 Gravity is the force exerted by the farth which is uivalent to the mass of an object.
1. False.
Gravity is a non-contact force that acts between two objects with mass, even if they are not in physical contact with each other.
2. False.
Gravity is the force exerted by the Earth (or any other massive body) on an object with mass.
The weight of an object is the measure of the force of gravity acting on it, and it is equivalent to the mass of the object times the acceleration due to gravity.
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Doug places a toy car at the top of the first hill and releases it. the car stops at point x. which change to the model would allow the toy car to travel over all three hills?
a.add a loop after the tallest hill in order to maximize the kinetic energy of the car.
b.order the three hills from shortest to tallest so that the potential energy builds up according to the height of each hill.
c.order the three hills from tallest to shortest to provide the potential energy needed for the car to make it over each hill.
In order for the toy car to travel over all three hills, one of the changes that could be made to the model is to order the hills from tallest to shortest.
This is because when the car is released from the top of the first hill, it has potential energy due to its height.
As it travels down the hill, the potential energy is converted to kinetic energy, which is the energy of motion.
In order to make it up the next hill, the car needs to have enough potential energy to overcome the force of gravity pulling it back down.
By ordering the hills from tallest to shortest, the car will build up potential energy as it goes up each hill, allowing it to make it over the subsequent hills.
Adding a loop after the tallest hill may not necessarily maximize the kinetic energy of the car. While the loop may provide a brief increase in kinetic energy due to the car's acceleration,
it also introduces friction and air resistance that can slow the car down. In addition, the loop may not provide enough potential energy for the car to make it up the subsequent hills.
Ordering the hills from shortest to tallest may not provide enough potential energy for the car to make it over all three hills.
While the car may build up speed going down the shorter hills, it may not have enough potential energy to make it up the taller hills, resulting in it stalling out at point x again.
Therefore, ordering the hills from tallest to shortest is the best change to make to the model to ensure the car can travel over all three hills.
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How do astronomers create three-dimensional maps of the universe?.
Techniques that are often combined to create more detailed and accurate maps of the universe. The resulting maps provide valuable insights into the evolution, structure, and properties of the universe.
Astronomers create three-dimensional maps of the universe using various techniques, including:
1. Redshift surveys: Astronomers measure the redshift of galaxies to determine their distance and velocity. The redshift is caused by the expansion of the universe, which stretches the wavelength of light from distant objects. By measuring the redshift of many galaxies, astronomers can create a three-dimensional map of the large-scale structure of the universe.
2. Cosmic microwave background radiation (CMB) surveys: The CMB is the oldest light in the universe, and it provides a snapshot of the early universe when it was only 380,000 years old. Astronomers use specialized telescopes to measure the temperature and polarization of the CMB to study the structure and history of the universe.
3. Gravitational lensing: Massive objects like galaxies and clusters of galaxies can bend and distort the light from more distant objects behind them, creating a magnifying effect. By studying the distortions in the light, astronomers can map the distribution of dark matter, which is invisible but exerts a gravitational force.
4. Galaxy surveys: Astronomers can also create three-dimensional maps of the universe by cataloging the positions and properties of large numbers of galaxies. By studying the distribution of galaxies, astronomers can infer the large-scale structure of the universe and the distribution of dark matter.
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Armatures are wound to provide high voltage, high current, or some specific combination of voltage and current. which type of winding provides moderate voltage and moderate current
The type of winding that provides moderate voltage and moderate current is called "lap winding." A lap winding connects each armature conductor to the adjacent conductor in a path that runs parallel to the field poles, resulting in multiple parallel paths and a moderate voltage output.
Lap windings are commonly used in direct current (DC) motors and generators, as they provide a balance between high voltage and high current, making them suitable for a range of applications.
The winding is constructed by arranging the armature conductors in concentric circles around the armature core, and then connecting the conductors end-to-end in a continuous loop.
In a lap winding, the number of parallel paths is equal to the number of field poles. This means that a four-pole motor or generator will have four parallel paths, while a six-pole machine will have six parallel paths. The number of parallel paths determines the output voltage and current of the machine, with more parallel paths producing higher output.
In summary, lap winding is a type of armature winding that provides moderate voltage and moderate current, making it suitable for a range of applications. It is constructed by connecting armature conductors in a continuous loop in multiple parallel paths that produce a balanced output.
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the sun is a star in the milky way galaxy. when viewed from the side, the galaxy looks like a disk that is approximately 100,000 light- years in diameter (a light-year is the distance light travels in one year) and about 1000 light-years thick (figure p25.8). what is the diameter and thickness of the milky way in meters? in kilometers? in miles?
Answer:
1,000,000,000,000,000,000 km (about 100,000 light years or about 30 kpc)
Explanation:
A 30 kg block with velocity 50 m/s is encountering a constant 8 N friction force. What is the momentum of the block after 15 seconds?
The momentum of a 30 kg block with an initial velocity of 50 m/s encountering a constant 8 N friction force and traveling for 15 seconds is 1680 kg m/s.
The initial momentum of the block is given by:
p = mv = (30 kg) x (50 m/s) = 1500 kg m/s
The net force acting on the block is given by the force of friction:
[tex]F_{net} = F_{friction} = 8 N[/tex]
Using Newton's second law, we can find the acceleration of the block:
[tex]F_{net} = ma[/tex]
8 N = (30 kg) a
[tex]a = 8/30 m/s^2[/tex]
Using the equation for displacement with constant acceleration, we can find the distance traveled by the block during the 15 seconds:
[tex]d = vt + 1/2 at^2[/tex]
[tex]d = (50 m/s)(15 s) + 1/2 (8/30 m/s^2)(15 s)^2[/tex]
d = 750 m + 450 m = 1200 m
Finally, using the equation for final velocity with constant acceleration, we can find the final velocity of the block:
[tex]v_{f^2} = v_{i^2} + 2ad[/tex]
[tex]v_{f^2} = (50 m/s)^2 + 2(8/30 m/s^2)(1200 m)[/tex]
[tex]v_{f^2} = 2500 \;m^2/s^2 + 640 \;m^2/s^2 = 3140\; m^2/s^2[/tex]
[tex]v_f[/tex] = 56.0 m/s
Therefore, the momentum of the block after 15 seconds is:
p = mv = (30 kg)(56.0 m/s) = 1680 kg m/s
In summary, the momentum of a 30 kg block with an initial velocity of 50 m/s encountering a constant 8 N friction force and traveling for 15 seconds is 1680 kg m/s.
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A person walks 5. 0 kilometers north, then 5. 0 kilometers east. His displacement is closest to:.
The person's displacement is closest to 7.1 kilometers.
To find the displacement of the person, we can use the Pythagorean theorem.
The person walks 5.0 km north and 5.0 km east. This creates a right triangle with sides of length 5.0 km and 5.0 km.
Using the Pythagorean theorem, we can find the length of the hypotenuse, which is the displacement of the person:
displacement = √(5.0 km)^2 + (5.0 km)^2
displacement = √(25 km^2 + 25 km^2)
displacement = √50 km^2
displacement = 7.1 km (rounded to one decimal place)
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as you get older it, it will become harder to eat whatever you want and maintain a healthy weight. this is because your basel metabolic rate, or BMR, ______ as your age.
This is because your basal metabolic rate, or BMR, decreases as you age.
What is BMR ?
Your body burns calories at rest to maintain essential bodily processes like breathing, circulation and cell growth and repair which is referred to as BMR.
Age-related changes in body composition including an increase in body fat and a loss of muscular mass can result in a reduction in BMR.
Therefore, To maintain a healthy weight and overall health as you age, it is crucial to pay attention to your food and physical activity levels. Maintaining a healthy BMR and avoiding weight gain can be achieved by eating a well-balanced diet with sensible portion sizes and exercising frequently.
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2. A girl on her bicycle rides in a direction opposite of her dad, who is driving away in his car at 33. 4 m/s. The girl’s speed is 8. 54 m/s as she rings the bell on her bike. If her dad hears a 714 Hz ringing sound, what is the frequency of the girl’s bell?
The frequency of the girl's bell heard by her dad is approximately 772 Hz.
1. This problem involves the Doppler effect, which describes how the frequency of a sound wave changes when the source of the sound is moving relative to an observer.
When the source is moving towards the observer, the frequency appears higher, and when the source is moving away from the observer, the frequency appears lower.
We can use the following equation to calculate the frequency of the sound wave heard by the dad:
f' = f(v + vd) / (v - vs)
where f is the frequency of the sound wave emitted by the girl, v is the speed of sound in air, vd is the speed of the dad's car (33.4 m/s), and vs is the speed of the girl on her bicycle (8.54 m/s). f' is the frequency heard by the dad.
Substituting the given values, we get:
f' = f(v + vd) / (v - vs)
f' = 714 Hz * (343 m/s + 33.4 m/s) / (343 m/s - 8.54 m/s)
f' = 772 Hz
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Prior knowledge question (do this before using the gizmo. )a boy rolls an old car tire down a hill. it goes pretty fast, but he wants the tire to go even faster. so, the boy climbs inside and rolls down the hill inside the tire. assuming there are no crashes, how do you think the speed of the tire with the boy inside will compare to the speed of the empty tire
The speed of the tire with the boy inside will likely be slower than the speed of the empty tire. This is because the added weight of the boy will increase the tire's mass and therefore, its inertia.
The increased inertia will require more force to accelerate the tire to the same speed as the empty tire. Additionally, the added friction between the boy and the inside of the tire may also slow down the tire's speed.
To further illustrate this concept, one can use the formula for kinetic energy, which is 1/2 times mass times velocity squared. As the mass of the tire increases with the boy inside, the kinetic energy required to reach a certain speed will also increase.
Therefore, the tire with the boy inside will require more kinetic energy to reach the same speed as the empty tire. Overall, the added weight and friction of the boy inside the tire will likely result in a slower speed for the tire compared to when it is empty.
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The basics of _________ fusion in the Sun are detailed in the following important summary (i. E. , understand this material). Normally, protons repel each other because their charges are similar, and by analogy consider trying bring together the N of a magnet with the N of another magnet. To overcome that electromagnetic repulsion one needs to smash the protons at a very high speed, and then nuclear fusion can occur. That high speed is not achieved in daily life, thankfully, but in the cores of stars where the temperature is high. Temperature is a proxy for the speed of particles, and as an example consider if it is cold in the room the particles are moving slowly. The temperature is high in the cores of stars because there is the sizable mass of all the overlaying layers exerting a pressure on the core, and causing the temperature to rise, and hence the speed of the protons. By analogy, consider when diving from the top of the pool to the bottom of the pool, and where one begins to feel the pressure exerted by all the overlaying layers of water
Answer:
The basics of proton-proton fusion in the Sun are detailed in the following important summary:
Normally, protons repel each other because their charges are similar. This is similar to trying to bring together the north pole of a magnet with the north pole of another magnet.
To overcome that electromagnetic repulsion, one needs to smash the protons at a very high speed. This is similar to how two magnets can be brought together if they are moving very fast.
That high speed is not achieved in daily life, thankfully, but in the cores of stars where the temperature is high.
Temperature is a proxy for the speed of particles. For example, if it is cold in a room, the particles are moving slowly.
The temperature is high in the cores of stars because there is the sizable mass of all the overlaying layers exerting a pressure on the core. This pressure causes the temperature to rise, and hence the speed of the protons.
By analogy, consider when diving from the top of the pool to the bottom of the pool. As you descend, you begin to feel the pressure exerted by all the overlaying layers of water.
In the core of the Sun, the temperature is about 15 million degrees Celsius. This is hot enough for the protons to move at very high speeds. When two protons collide at high speed, they can fuse together to form a helium nucleus. This process releases a large amount of energy, which is what powers the Sun.
The proton-proton fusion reaction is a complex process, but it is essential for the Sun to shine. Without this reaction, the Sun would eventually cool and collapse.
An iron Cub has each 15cm long at 20c. What will be :
1 the new surface of a face weather temperature rise to 80c
2 the volume of the same final temperature
a) The new surface area of one face will be 225.162 cm^2.
b) The volume of the iron cube at the final temperature of 80°C will be 3382.29 cm^3.
The thermal expansion of a solid material can be determined using the coefficient of linear expansion, which is a material property that relates the change in length to the change in temperature. For iron, the coefficient of linear expansion is approximately 1.2 x 10^-5 /°C.
a) To find the new surface area of a face when the temperature rises from 20°C to 80°C, we can use the formula:
ΔA = A_0 * α * ΔT
where ΔA is the change in surface area, A_0 is the initial surface area, α is the coefficient of linear expansion, and ΔT is the change in temperature.
For a cube with each side 15 cm long, the initial surface area of one face is 15 cm x 15 cm = 225 cm^2. The change in temperature is 80°C - 20°C = 60°C. Substituting these values and the coefficient of linear expansion for iron, we get:
ΔA = 225 cm^2 * 1.2 x 10^-5 /°C * 60°C = 0.162 cm^2
Therefore, the new surface area of one face will be 225 cm^2 + 0.162 cm^2 = 225.162 cm^2.
b) To find the volume of the iron cube at the final temperature of 80°C, we can use the formula:
ΔV = V₁ * β * ΔT
where ΔV is the change in volume, V₁ is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature.
For a cube with each side 15 cm long, the initial volume is 15 cm x 15 cm x 15 cm = 3375 cm^3. The coefficient of volume expansion for iron is approximately three times the coefficient of linear expansion, so we can use β = 3α.
Substituting these values and the change in temperature, we get:
ΔV = 3375 cm^3 * 3 * 1.2 x 10^-5 /°C * 60°C = 7.29 cm^3
Therefore, the volume of the iron cube at the final temperature of 80°C will be 3375 cm^3 + 7.29 cm^3 = 3382.29 cm^3.
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You do 25 J of work in pushing a crate up a ramp. If the output work from the
inclined plane is 10 J, then what is the efficiency of the inclined plane?
The efficiency of the inclined plane is 40%.
The efficiency of the inclined plane can be calculated by dividing the output work by the input work and multiplying by 100% to get a percentage.
Efficiency = (Output work / Input work) x 100%
In this case, the input work is 25 J and the output work is 10 J.
Efficiency = (10 J / 25 J) x 100%
Efficiency = 0.4 x 100%
Efficiency = 40%
Therefore, the efficiency of the inclined plane is 40%.
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Determine the force acting downwards on a mass of 1500 g suspended on a string. (14. 72 N)
The Force acting downwards on the mass = 14.72N
To determine the force acting downwards on a mass of 1500 g suspended on a string, you'll need to use the formula for gravitational force: F = m * g, where F is the force, m is the mass in kilograms, and g is the acceleration due to gravity (approximately 9.81 m/s²).
First, convert the mass from grams to kilograms: 1500 g = 1.5 kg.
Next, plug the values into the formula: F = 1.5 kg * 9.81 m/s² ≈ 14.72 N.
So, the force acting downwards on the mass is approximately 14.72 N.
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The speed of light in a certain medium is 2. 2 × 108 m/s. What is the index of refraction of this medium?
The index of refraction of this medium is 1.36. The index of refraction (n) of a medium is the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v): n = c/v
Given the speed of light in the medium as 2.2 × 10^8 m/s, we can calculate the index of refraction as: n = c/v = (3.0 × 10^8 m/s) / (2.2 × 10^8 m/s) = 1.36
Therefore, the index of refraction of this medium is 1.36. This indicates that light travels slower in this medium compared to a vacuum and is bent when it enters the medium at an angle, a phenomenon called refraction.
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