The pH of the solution containing 44.5 mol HCl and 38.9 mol NaOH is 2.087.
pH is generally the measure of how acidic or basic a substance or solution is on a scale of 1 to 14. Basically, on the pH scale, a pH value of 7 is neutral, which means the solution is neither acidic nor basic and a pH value of less than 7 means the solution is more acidic, and a pH value of more than 7 means the solution is more basic.
Moles of H⁺ = 44.5
Moles of OH⁻ = 38.9
Now,
H⁺ + OH⁻ → H₂O
Moles of H⁺ left = 44.5 - 38.9 = 5.6
Volume = 684 L
[H⁺] = n/V = 5.6 / 684 = 0.0082 M
pH = - log [H⁺] = - log 0.0082 = 2.087
Hence, the pH of the solution containing 44.5 mol HCl and 38.9 mol NaOH is 2.087.
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determine the total mass of 1 pentanol that will dissolve in 110 grams of water to produce a saturated solution
To determine the total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution, we need to use the concept of solubility and molar mass. What is solubility? Solubility refers to the ability of a solute to dissolve in a solvent. It is measured in units of grams per 100 grams of solvent at a specific temperature.
A solution is said to be saturated if it contains the maximum amount of solute that can dissolve in the solvent at a specific temperature. The solubility of a solute depends on factors such as temperature, pressure, and the nature of the solvent and solute. What is molar mass? Molar mass refers to the mass of one mole of a substance. It is measured in units of grams per mole. The molar mass of a compound can be calculated by adding the atomic masses of the elements in the compound. Explanation: Given data: Mass of water = 110 grams To determine: Total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution Solution: Firstly, let's find out the solubility of 1-pentanol in water. According to the solubility chart, the solubility of 1-pentanol in water at 25°C is 22.5 g/100 ml (or 22.5 g/110 g).So, we can say that 22.5 g of 1-pentanol can dissolve in 100 g of water to produce a saturated solution at 25°C.Now, we can use the proportionality method to calculate the total mass of 1-pentanol that will dissolve in 110 g of water.22.5 g of 1-pentanol dissolves in 100 g of water. So, x grams of 1-pentanol will dissolve in 110 g of water. x = (22.5 × 110) / 100x = 24.75 g Therefore, the total mass of 1-pentanol that will dissolve in 110 g of water to produce a saturated solution is 24.75 grams.
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PLEASE HELP
- Methods of electrical charging
- Classification of elements based on electric conductivity.
- Share at least one example of each element of conductivity
- Please include key points (about 3) and very briefly share your experience about this activity.
Electricity can be charged via a variety of techniques, such as frictional charging, contact charging, and induction charging.
What kind of material exhibits electrical conductivity?For conducting electricity, metals like copper, iron, gold, aluminium, and silver work best. Via the electrodes in a standardised aqueous solution at a specific temperature, the electrical conductivity of a substance is measured.
How can you determine whether an element is a metal or a non-metal using electrical conductivity?A substance is a metal if it conducts electricity and has a basic oxide. A non-metal is an element whose oxide is acidic but not electrically conducting.
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which type of molecule is the final product of gene expression?
In the former area, we have seen that the eventual outcome of certain qualities is an RNA molecule itself, like those present in the snRNPs and in ribosomes.
In the former area, we have seen that the eventual outcome of certain qualities is an RNA molecule itself, like those present in the snRNPs and in ribosomes. Nonetheless, most qualities in a cell produce mRNA molecules that act as go-betweens on the pathway to proteins. In this part, we look at how the cell changes over the data conveyed in an mRNA molecule into a protein molecule. This accomplishment of interpretation previously pulled into the consideration of scientists in the last part of the 1950s, when it was acted like the "coding issue": how is the data in direct succession of nucleotides in RNA converted into the straight grouping of a synthetically very unique arrangement of subunits — the amino acids in proteins? This interesting inquiry invigorated extraordinary energy among researchers at that point.
There was a cryptogram set up commonly that, after multiple billion years of development, could, at last, be tackled by one of the results of advancement — individuals. What's more, without a doubt, not just has the code been broken bit by bit, but in the year 2000 the intricate hardware by which cells read this code — the ribosome — was at last uncovered in nuclear detail.
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what is the electrophile that reacts with benzene in the nitration of benzene by a mixture of nitric and sulfuric acid?
The electrophile that reacts with benzene in the nitration of benzene by a mixture of nitric and sulfuric acid is the nitronium ion (NO2+). Electrophiles are atoms or molecules that are electron deficient or have an unfilled valence shell, making them attractive to electrons.
Electrophiles will attack nucleophiles, which have a free pair of electrons in their outermost orbital, resulting in a chemical reaction. Nitration of benzene is the reaction of benzene with a mixture of nitric acid and sulfuric acid to produce nitrobenzene as the major product. The reaction involves the substitution of a hydrogen atom on the benzene ring by a nitro group (-NO2).The electrophile that is formed by the mixture of nitric acid and sulfuric acid is the nitronium ion (NO2+).
The nitronium ion is highly reactive and will attack the benzene ring, leading to the formation of nitrobenzene. The reaction is as follows:
Benzene + Nitric Acid + Sulfuric Acid → Nitrobenzene + Water.
The mechanism of the reaction involves the formation of an intermediate arenium ion, which is stabilized by resonance. The intermediate is attacked by the nitronium ion, leading to the formation of the final product.The nitration of benzene is an important reaction in organic chemistry, as it is used to synthesize a wide range of organic compounds such as explosives, dyes, and pharmaceuticals.
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10.
Given the following reaction
Ca(s) + 2HCl(aq) → CaCl2(aq) + H2(g)
If 1.00 g of Ca reacts with 1.00 g HCI and 1.21 g CaCl2 are produced, what is the theoretical yield, the percent
yield and the limiting reactant?
a. 2.77 g, 43.7%, Ca limiting
b. 2.77 g, 79.5%, HCI limiting
c. 1.52 g, 43.7%, Ca limiting
d. 1.52 g, 79.5% HCI limiting
e. 2.77g, 54.9%, Ca limiting
f. 1.52 g, 54.9%, HCI limiting
The given reaction is calcium, solid, plus 2 h c, l gives c a c l, 2 plus hydrogen. Here we can write 1 mole of calcium, reacting with 2 moles of h, c l ...
Given the following reaction Ca(s) + 2HCl(aq) → CaCl2(aq) + H2(g) If 1.00 g of Ca reacts with 1.00 g HCI and 1.21 g CaCl2 are produced,
a student releases a balloon filled with 0.13 moles of he into the air. as the balloon rises, the temperature of the helium decreases and the balloon expands. if the helium in the balloon started at 3.0l and 298k, what is the overall change in entropy after the he has cooled to 291k and expanded to 3.5l?
The overall change in entropy for the process is approximately -0.251 J/K.
Steps
The change in entropy can be calculated using the formula:
ΔS = nCp ln(T2/T1) + nR ln(V2/V1)
where:
n = 0.13 moles (number of moles of helium in the balloon)
Cp = 5/2R (specific heat capacity of helium gas at constant pressure)
R = 8.314 J/(mol*K) (gas constant)
T1 = 298 K (initial temperature of the helium gas)
T2 = 291 K (final temperature of the helium gas)
V1 = 3.0 L (initial volume of the balloon)
V2 = 3.5 L (final volume of the balloon)
Plugging in the values, we get:
ΔS = (0.13 mol * 5/2 * 8.314 J/(molK)) ln(291 K/298 K) + (0.13 mol * 8.314 J/(molK)) ln(3.5 L/3.0 L)
ΔS = -0.296 J/K + 0.045 J/K
ΔS = -0.251 J/K
Therefore, the overall change in entropy for the process is approximately -0.251 J/K.
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Indicate the dostance that corresponds to the bond length of the N2 molecule by placing an X on the horizontal axis
To indicate the distance that corresponds to the bond length of the N₂ molecule, we need to know the bond length of the N₂ molecule. The bond length of a molecule refers to the distance between the nuclei of two bonded atoms.
The bond length of N₂ is approximately 109.76 picometers (pm). Therefore, to indicate the bond length of N₂ on the horizontal axis, we can place an X at 109.76 pm.
It's important to note that bond lengths can vary slightly depending on the specific conditions of a given experiment or calculation. However, the bond length of N₂ at standard conditions is well established, and 109.76 pm is a commonly accepted value.
Knowing the bond length of a molecule is important in understanding the nature of the chemical bond between two atoms. The bond length is related to the strength of the bond, with shorter bond lengths indicating stronger bonds. The bond length of N₂ , for example, is relatively short, indicating a strong bond between the two nitrogen atoms.
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cu(oh)2(s) will not dissolve when the following reagent is added to it: select one: a. 6m hno3 b. 6m nh3 c. 6m hcl d. 6m naoh
When the reagent is put to 6M HCl, Cu(OH)2(s) will not dissolve it.
What exactly are reagents?A material or molecule that is introduced to a system in order to bring about a chemical reaction or is added to assess whether a reaction has happened or not is referred to as a reagent in the study of chemistry. A similar response is performed to verify the presence of a different chemical.
What does a pharmacy reagent mean?A Reagent is described as a "substance or compound that is introduced to a system in order to bring about a chemical reaction or is added to test if a reaction happens". The existence of another drug is confirmed by a similar response.
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