A scientist added bacteria and a nutrient medium that could support the growth of the bacteria to a sterilized petri dish. No other materials were added. The graph models the growth of the bacteria over time.

Answer:

e. The reaction is spontaneous at low temperatures.

Explanation:

The reaction 2Mg(s) + O2(g) → 2MgO(s)  is an exothermic reaction. Let us recall that in an exothermic reaction, heat and light are given out and ΔH is negative (less than zero).

In an exothermic reaction increase in temperature shifts the equilibrium position towards the left and more reactants are produced. However, decrease in temperature shifts the equilibrium position towards the right and more products are obtained.

Also, since the reaction is exothermic, then given that; ΔG = ΔH - TΔS, ΔH is negative for an exothermic reaction and ΔG must be negative for a reaction to be spontaneous. Hence, at low temperature, the value of ΔH - TΔS remains negative (less than zero) hence the reaction is spontaneous.

Hence, Being an exothermic reaction, the process is spontaneous at low temperatures.

Answer:

all of the above

Explanation:

The Law of Conservation of Mass states that matter is neither created nor destroyed. It also states that in a chemical reaction, the total mass of the reactants equals the total mass of the products.

The Law of Conservation of Matter states that matter can change form through physical and chemical changes but matter is conserved. The same amount exists before and after the change. Matter is not created or destroyed.

So the answer will be all of the above.

Hope that helps.

Answer:

flammability, toxicity, acidity, reactivity , and heat of combustion.

Explanation:

Answer:

Its the banana one

Explanation:

Answer:d8

Explanation:

Answer:

Liquid helium

Explanation:

Liquid helium is known to be the coldest element in the world.

It has a ridiculous boiling point of -452 degrees

It is considered the only element on earth that does not freeze to become solid. normally, it is usually in a form of cryogenic fluid or superfluid.

Hence, the coldest element is known as LIQUID HELIUM

Answer:

b. NAD+

Explanation:

Aldehydes are oxidized to carboxylic acids in the presence of strong oxidizing agents.

In a biochemical system, the same oxidation reaction occurs by the help of the enzyme alcohol dehydrogenase and NAD+ which is a biological oxidizing agent.

NAD+ is an effective biological oxidizing agent that accepts electrons from molecules and change to its reduced form NADH, which is an effective biological reducing agent that donates electrons. Electron transfer processes are the main functions of NAD+.

16.2 g of Water are formed

Answer:

because it starts to fall apart and it eventually just disappears like for example putting a bleach tablet it water it will take day to desolve but it desolves any way though.

Answer: My answer is in the explanation

Explanation:

Physical and mechanical characteristics of iceberg ice were studied from samples collected near the shores of eastern Newfoundland. Although the physical characteristics show considerable diversity, iceberg ice has some common features and is generally porous, lacks significant concentrations of dissolved materials, contains internal cracks and has an irregular interlocking grain structure.

Answer:

Explanation:

Strong electrolytes completely ionize when dissolved, and no neutral molecules are formed in solution. Since NaCl is an ionic solid (s), which consists of cations Na+ and anions Cl−, no molecules of NaCl are present in NaCl solid or NaCl solution. The ionization is said to be complete.

Answer:

K3PO4(s) ----- 3K+(aq) + PO43–(aq)

Explanation:

edge 2021

Answer:

Following are the solution to the given points:

Explanation:

Oxalic acid volume [tex]= 25.00 \ mL = 0.0250 \ litres[/tex]  

KMnO4 volume [tex]= 12.70 \ ml = 0.0127 \ litres[/tex]

KMnO4 molarity [tex]= 0.0206\ M = 0.0206 \ \frac{mol}{l}[/tex]

In point a:

Its pink presence after full intake of oxalic acid with attachment to KMnO4 is suggested by the end-point of the process due to the small abundance of KMnO4, As just a self predictor, KMnO4 is used.

In point b:

[tex]H_2C_2O_4[/tex] molecules mole ratio to [tex]MnO_4^-[/tex] ions:  

The equilibrium for both the oxalic acid and KMnO4 reaction is suggested:

[tex]6H+ (aq) + 2MnO_4- (aq) + 5H_2C_2O_4 (aq) \rightarrow 10CO_2 (g) + 8H_2O (l) + 2Mn_2+ (aq)[/tex]

The reaction of 5 mol of oxalic acid is 2 mol [tex]MnO_4^-[/tex] ions  

[tex]H_2C_2O_4[/tex]: molecules mole proportion to [tex]MnO_4^-[/tex] ions:  

[tex]5 H_2C_2O_4[/tex]: : [tex]2MnO_4^-[/tex]

In point c:

The Moles of [tex]MnO_4^-[/tex] ions reacted with the [tex]H_2C_2O_4[/tex]:

The molar mass of the solution is the number of solute moles in each volume of water  

[tex]Molarity =\frac{moles}{Volume}\\\\Moles \ of\ KMnO_4 = Molarity \times volume[/tex]

Moles with ions reacted to mol with both the amount of : supplied.

In point d:

[tex]H_2C_2O_4[/tex] moles in the sample present:  

[tex]H_2C_2O_4[/tex] moles = moles [tex]MnO_4^-[/tex] ions [tex]\times[/tex] mole ratio  

[tex]H_2C_2O_4[/tex] moles in the sample = [tex]2.6162 \times 10^{-4}\ mol \times (\frac{5}{2})[/tex]

[tex]H_2C_2O_4[/tex] molecules = [tex]6,5405\times 10^{-4}[/tex] mol are present in the sample

In point e:

Oxalic acid molarity = [tex]\frac{mole}{volume}[/tex]  

                                  [tex]=\frac{ 6.54 \times 10^{-4} mol}{0.025\ L} \\\\ = 0.0260 \ M[/tex]

In point f:

Oxalic acid level by mass in the solution:  

Oxalic acid mass calculation:  

Oxalic acid molar weight = 90.0349 [tex]\frac{g}{mol}[/tex].  

Oxalic acid mass per liter = oxalic acid moles per liter [tex]\times[/tex] molar mass

                                          [tex]= 0.0260 \frac{mol}{L} \times 90.0349 \frac{g}{mol}\\\\= 2.3409 \frac{g}{L}\\\\ = 2.3409 \frac{g}{1000 \ mL}\\\\= 0.2409 \frac{g}{100 \ mL}[/tex]

When Oxalic acid solution density[tex]= 1.00 \ \frac{g}{mL}[/tex]  

Mass oxalic acid percentage = [tex]0.2409 \%[/tex]

Oxalic acid mass proportion [tex]= 0.24\% \ \frac{W}{v} \ \ Mass[/tex]

Answer:

i have no clue

Explanation:

i have no clue

Answer:

The answer is "[tex]2.73 \times 10^3 \ K[/tex] ".

Explanation:

Please find the complete question in the attachment.

The Formula for Ideal gas:

[tex]\to PV = nRT \\\\[/tex]

          [tex]= ( \frac{m}{M})RT[/tex]

[tex]\to Density\ \rho = \frac{m}{V} = \frac{PM}{RT}[/tex]

[tex]\to P= pressure\\\\\to V = volume\\\\ \to n = moles\ of \ gas \\\\\to R = molar \ gas \ constant\\\\ \to T = temperature\\\\ \to m = mass \\\\ \to M = molar \ mass[/tex]

[tex]\to P(Ar) = P(He) = 1.00 atm\\\\\to T(Ar) = ?\\\\ T(He) = 273.2 \ K\\\\\to M(Ar) = 39.948 \ \frac{g}{mol}\\\\ \to M(He) = 4.0026 \ \frac{g}{mol}\\\\\to \rho(Ar) = \rho(He)\\\\\bold{Formula: } \\\\ \to \frac{P(Ar)M(Ar)}{RT(Ar)} = \frac{P(He)M(He)}{RT(He)}\\\\\to \frac{1.00 \times 39.948}{(0.08206 \times T(Ar))} = \frac{1.00 \times 4.0026}{(0.08206 \times 273.2)}\\\\ \to T(Ar) = 2.73 \times 10^3 \ K[/tex]

Answer:

Immunity

Explanation:

Answer:

8.77 grams

Explanation:

Explanation:

The reaction expression is given as:

           2H₂  +   O₂    →    2H₂O

The limiting reactant is the reactant in short short supply in the given reaction.

To find the limiting reactant we use the number of moles.

    Mass of H₂  = 5g

    Mass of O₂   = 10g

  Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

       Molar mass of H₂   = 2(1) = 2g/mol

       Molar mass of O₂  = 2(16)  = 32g/mol

Number of moles  H₂ = [tex]\frac{2}{5}[/tex]   = 0.4mole

Number of moles O₂ = [tex]\frac{10}{32}[/tex]   = 0.3mole

   From the balanced reaction equation:

           2 mole of H₂ reacts with 1 mole of O₂

          0.4 mole of H₂ reacts with  0.2 mole of O₂

But we are given 0.3 moles of O₂, so the limiting reactant is H₂ because oxygen gas is in excess

The limiting reactant when 5.00g of H₂ and 10.00g of O₂ react is Oxygen (O₂)

From the question,

We are to determine the limiting reactant

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

2H₂ + O₂ → 2H₂O

This means 2 moles of H₂ reacts with 1 mole of O₂ to produce 2 moles of H₂O

Now, we will determine the number of moles of each reactant present

Mass = 5.00 g

Molar mass = 2.0 g/mol

Using the formula,

[tex]Number\ of \ moles = \frac{Mass}{Molar\ mass}[/tex]

Number of moles of H₂ = [tex]\frac{5.00}{2.0}[/tex]

Number of moles of H₂ = 2.50 moles

Mass = 10.00 g

Molar mass = 32.0 g/mol

Then,

Number of moles of O₂ = [tex]\frac{10.00}{32.0}[/tex]

Number of moles of O₂ = 0.3125 mole

Now,
Since 2 moles of H₂ reacts with 1 mole of O₂

Then,

0.625 moles of H₂ reacts with 0.3125 mole of O₂

This means part of the H₂ reacts with all of the O₂. Since all the O₂ reacted, then O₂ is the limiting reactant.

Hence, the limiting reactant when 5.00g of H₂ and 10.00g of O₂ react is Oxygen (O₂).

Learn more on Stoichiometry here: https://brainly.com/question/17199947

Answer:

because he would've not known properly about it!

Answer:

a) Photosynthesis - chemical change

b) dissolving sugar in water -physical change

c) burning of coal- chemical change

d) melting of wax- Physcial change

e) beating of aluminum to make Almunium foil-Physical change

f) digestion of food- chemical change

Answer

false

Explanation:

sorry I tbought i put false I hope I helped ....

The answer is false! All matters do not look the same, even if it had a visible look the answer would be false!

Why is the answer false?

There is lots of matters, Like liquids:

(Water, Juice, Milk, etc.)

All Water, Juice, & Milk looks different, Maybe SOME look the same, but the question is saying "All", Most of all questions is wrong.

Therefore the answer is false!

Learn more about matter on www.Bing/LearnMore/Subject="Matter%20Learning"/Search.com

Need more of my help? Put #AJQ in your questions and I will come fast!

Answer: Its A or D                                                        

wish i had an actual answer sorry..  

The correct answer should be A

Answer:

1. 1.21mol

2.8.5kg

Explanation:

the number of moles and grams of gas in the sample

Answer:

light, temperature, water, humidity, and nutrition.

Answer:

Water is water.

Explanation:

Water is a colorless and odorless substance found all over Earth. Water is made up of billions of molecules. ... Water on our planet flows as liquid in rivers, streams, and oceans; is solid as ice at the North and South Poles; and is gas (vapor) in the atmosphere. Water is also underground and inside plants and animals

Answer:

Settling and decanting is a method to reduce turbidity by letting the water sit for 2-24 hours so that the particulates settle to the bottom of the container. The clear water is then decanted off the top into a second container.

Explanation:

Settling and decanting is a method to reduce turbidity by letting the water sit for 2-24 hours so that the particulates settle to the bottom of the container. The clear water is then decanted off the top into a second container.

Answer:

3. 2.00 L of air at 100°C has twice the pressure of the same 2.00 L of air at  50°C

Explanation:

1)  doubling the pressure of a gas doubles its volume

This is incorrect because by increasing the pressure volume is going to be decreased.

2)  2.00 L of air at 227°C has twice the pressure of the same 2.00 L of air at  23°C

This is also incorrect because 2 L air at 227 °C will have the pressure more than twice time as compared to the 2L air at 23°C.

3. 2.00 L of air at 100°C has twice the pressure of the same 2.00 L of air at  50°C

This is correct;

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

thus, by increasing the temperature pressure is also goes to increase in the same ratio.

4. halving the pressure of a gas halves its volume

This is incorrect because halving the pressure of gas increasing its volume.

Explanation:

Options A and B have wrong reasons because to feed on producers means that it is a primary consumer.

Option C is wrong because organism X only feeds on cornstalks.

Organism Y does feed on the grasshopper, which feeds on the cornstalks. It is a secondary consumer.

Hence Option D is correct.

hope this will help you mate! :)

shadow

Answer:

At equilibrium, the forward and backward reaction rates are equal.

The forward reaction rate would decrease if [tex]\rm O_2[/tex] is removed from the mixture. The reason is that collisions between [tex]\rm SO_2[/tex] molecules and [tex]\rm O_2\![/tex] molecules would become less frequent.

The reaction would not be at equilibrium for a while after [tex]\rm O_2[/tex] was taken out of the mixture.

Explanation:

Neither the forward reaction nor the backward reaction would stop when this reversible reaction is at an equilibrium. Rather, the rate of these two reactions would become equal.

Whenever the forward reaction adds one mole of [tex]\rm SO_3\, (g)[/tex] to the system, the backward reaction would have broken down the same amount of [tex]\rm SO_3\, (g)\![/tex]. So is the case for [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex].

Therefore, the concentration of each species would stay the same. There would be no macroscopic change to the mixture when it is at an an equilibrium.

In the collision theory, an elementary reaction between two reactants particles takes place whenever two reactant particles collide with the correct orientation and a sufficient amount of energy.

Assume that [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex] molecules are the two particles that collide in the forward reaction. Because the collision has to be sufficiently energetic to yield [tex]\rm SO_3\, (g)[/tex], only a fraction of the reactions will be fruitful.

Assume that [tex]\rm O_2\, (g)[/tex] molecules were taken out while keeping the temperature of the mixture stays unchanged. The likelihood that a collision would be fruitful should stay mostly the same.

Because fewer [tex]\!\rm O_2\, (g)[/tex] molecules would be present in the mixture, there would be fewer collisions (fruitful or not) between [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)\![/tex] molecules in unit time. Even if the percentage of fruitful collisions stays the same, there would fewer fruitful collisions in unit time. It would thus appear that the forward reaction has become slower.

The backward reaction rate is likely going to stay the same right after [tex]\rm O_2\, (g)[/tex] was taken out of the mixture without changing the temperature or pressure.

The forward and backward reaction rates used to be the same. However, right after the change, the forward reaction would become slower while the backward reaction would proceed at the same rate. Thus, the forward reaction would become slower than the backward reaction in response to the change.

Therefore, this reaction would not be at equilibrium immediately after the change.

As more and more [tex]\rm SO_3\, (g)[/tex] gets converted to [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex], the backward reaction would slow down while the forward reaction would pick up speed. The mixture would once again achieve equilibrium when the two reaction rates become equal again.