Answer:
W = 0
Explanation:
As the satellite moves in a circle the force is perpendicular to the path, therefore the work that is defined by
W = F. r = f r cos θ
Since the force and the radius are perpendicular, the angle θ = 90º and the cosine 90 = 0, therefore there is no work for the circular motion.
W = 0
Two students are standing next to one another. One student has a mass of 79.0 kg, and the other has a mass of 93.5 kg. If they are standing so that their centers of mass are a distance of 1.12 m apart, what is the force of the gravitational attraction between them?
A. 4.40 * 10^-7 N
B. 3.93 * 10^-7 N
C. 1.29 * 10^-6 N
D. 8.77 * 10^-6 N
Answer:
[tex]F=3.93\times 10^{-7}\ N[/tex]
Explanation:
Mass of student 1, m₁ = 79 kg
Mass of student 2, m₂ = 93.5 kg
The students are 1.12 m apart, d = 1.12 m
We need to find the force of the gravitational attraction between them. The force of gravitational force is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{79\times 93.5}{(1.12)^2}\\\\=3.93\times 10^{-7}\ N[/tex]
So, the force of gravitational attraction between them is [tex]3.93\times 10^{-7}\ N[/tex]. Hence, the correct option is (B).
A girl uses paper-clips to balance a toy bird on her finger. What effect does it have on the centre of mass?
An object has a mass of 19 kg. Attached to the end of a spring, if the spring constant is 486 N/m, what is the maximum frequency?
Answer:
The frequency [tex]f = 0.8048 \ Hz[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m = 19 \ kg[/tex]
The spring constant is [tex]k = 486 \ N/ m[/tex]
Generally the maximum frequency is mathematically represented as
[tex]f = \frac{1}{2 \pi } * \sqrt{ \frac{k}{m } }[/tex]
=> [tex]f = \frac{1}{2 * 3.142 } * \sqrt{ \frac{486}{ 19 } }[/tex]
=> [tex]f = 0.8048 \ Hz[/tex]
A series RC circuit contains two resistors and two capacitors. The resistors are 39 ohms and 56 ohms. The capacitors have capacitive reactances of 80 ohms and 40 ohms. When calculating the circuit values, the total resistance used is:_______
a. 215 ohms
b. 95 ohms
c. 25 ohms
d. 120 ohms
Answer:
The correct option is b
Explanation:
From the question we are told that
The resistance of the first resistor is [tex]R_1 = 39 \ \Omega[/tex]
The resistance of the second resistor is [tex]R_2 = 56 \ \Omega[/tex]
The capacitive reactance of the first capacitor is [tex]jX_{c_1 } = 80 \ \Omega[/tex]
The capacitive reactance of the first capacitor is [tex]jX_{c_2 } = 40 \ \Omega[/tex]
Generally given that the resistors are connected in parallel , their equivalent resistance is
[tex]R_e = R_1 +R_2[/tex]
=> [tex]R_e = 39 + 56[/tex]
=> [tex]R_e = 95 \ \Omega[/tex]
Generally given that the capacitors are connected in parallel , their equivalent capacitive reactance is
[tex]jX_e = jX_{c_1} + jX_{c_2}[/tex]
=> [tex]jX_e = 80 + 40[/tex]
=> [tex]jX_e = 120[/tex]
Hence the impedance of the circuit is
[tex]Z = R_e - jX_e[/tex]
=> [tex]Z = 95 - j120[/tex]
Generally from the impedance equation , the total used resistance is
[tex]R_e = 95 \ \Omega[/tex]
If the net work done on a particle is zero, which of the following statements must be true?
A. The speed is unchanged.
B. The velocity is zero.
C. The velocity is unchanged.
D. More information is needed.
E. The velocity is decreased.
Answer:
A. The speed is unchanged.
Explanation:
In the case when the work is to be done on a particle i.e. zero so the change made in KE of the particle would be zero. This represent the work energy theroem. But when the KE remains same or does not change so it should be the same and the particle speed would also the same
Therefore as per the given statement, the first option is correct
And rest of the options are wrong
High above the town of Whoville there lived a Grinch and his dog Max. The Grinch being antisocial has never gone to school so needs your help with some physics concepts.
a) Start by stating Newton's Three Laws of Motion
b) While watching the Who's skate on Who lake, the Grinch notices that when Sue Who is spinning as she pulls in her arms she spins faster. Explain why this happens to the Grinch.
c) The Grinch notices that as time progresses his cave gets messier. Explain why this occurs.
Answer:
a) Newton proposed three laws to explain the motion of things.
b) bodies are in motion the kinetic moment is preserved,
c) entropy
Explanation:
In this exercise you are asked to explain various concepts of physics
a) Newton proposed three laws to explain the motion of things.
* The first law or inertia states that a body in an inertial system (without acceleration) remains stationary or with constant velocity if the sum of the forces is zero
* The second law states that the force (interaction) is proportional to the masses and the acceleration of the bodies
F = m a
* The third law or action and reaction, says that the forces always go in pairs, that is, if a body interacts with a body 2, and body 2 will also interact with body 1, with the same force but with the opposite direction, each force is applied to a body
b) when bodies are in motion the kinetic moment
L = I w
it is preserved, if it does not interact with the outside.
The quantity I called the moment of inertia is I = m r²
In this case
in the initial instant with outstretched arms
L = I₀ w₀
in the final moment. By shrinking your arms
[tex]L_{f}[/tex] = I_{f} w_{f}
as the body does not interact with another
L₀ = L_{f}
I₀ w₀ = I_{f} w_{f}
w_{f} = [tex]\frac{I_{o} }{I_{f} }[/tex] w₀
we substitute
w_{f} = \frac{r_{o} }{r_{f} }^2 w₀
as the distance of the arms extended is greater than when they are retracted (r₀> [tex]r_{f}[/tex]), the final angle speed increases
c) This is an application of the concept of entropy that establishes that disorder is the most probable state of a system, which is why the cave increases its disorder or entropy over time since by not fixing things, they are increasingly dispersed
What kind of force is the force of gravity?
Answer:
Its a Universal Force
Explanation:
Activity: Lab safety and Equipment Puzzle
Answer:
number 2 down is: safetygoggles
Explanation:
no space
Lab safety personal protective equipment should always be put on when in the lab, and lab equipment are what scientists for lab work
The words for the lab safety and lab equipment puzzle are:
1. Test tube rack
2. Splash goggles
3. Fire extinguisher
4. Balance scale
5. Closed heel
6. Deluge shower
7. Waft
8. Pipette
9. Proctor
10. Meter stick
11. Bunsen burner
12. Cleanup
13. Beaker tongs
14. Measuring cylinder
15. Funnel
16. Trash bin
17. Hot plate
18. Beaker
19. Lab apron
20. Fire blanket
Learn more about lab equipment here:
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A 20-kg object sitting at rest is struck elastically in a head-on collision with a 10-kg object initially moving at 3.0 m/s. Find the final velocity
Answer:
1 m/s
Explanation:
Using law of conservation of momentum
m1v1 + m2v2 = (m1 + m2)vf , where
m1 = mass of object at rest, 20 kg
v1 = initial velocity of object at rest, 0 m/s
vf = final velocity of the bodies
m2 = mass of object in motion, 10 kg
v2 = initial velocity of object in motion, 3 m/s
On substituting, we have
(20 * 0) + (10 * 3) = (20 + 10) vf
0 + 30 = 30 vf
vf = 30 / 30
vf = 1 m/s
Therefore, the velocity of the bodies after hitting each other is 1 m/s
An object of mass 6 kg. is resting on a horizontal surface. A horizontal force
of 15 N is constantly applied on the object. The object moves a distance of
100m in 10 seconds.
(a) How much work does the applied force do?
(b) What is the kinetic energy of the block after 10 seconds?
(c) What is the magnitude and direction of the frictional force (if there is
any)?
(d) How much energy is lost during motion?
Answer:
a) The work done by the applied force is 1500 joules.
b) The kinetic energy of the block after 10 seconds is 1200 joules.
c) The magnitude of the force of friction is 3 newtons and its direction is against motion.
d) 300 joules of energy are lost during motion.
Explanation:
a) Since the object has a constant mass, on which a constant horizontal force is exerted. The work done by the force ([tex]W[/tex]), measured in joules, is defined by the following expression:
[tex]W = F\cdot \Delta x[/tex] (1)
Where:
[tex]F[/tex] - Force, measured in newtons.
[tex]\Delta x[/tex] - Distance, measured in meters.
If we know that [tex]F = 15\,N[/tex] and [tex]\Delta x = 100\,m[/tex], then the work done by the force exerted on the object is:
[tex]W = (15\,N)\cdot (100\,m)[/tex]
[tex]W = 1500\,J[/tex]
The work done by the applied force is 1500 joules.
b) At first we need to calculate the net acceleration of the object ([tex]a[/tex]), measured in meters per square second. By assuming a constant acceleration, we use the following kinematic formula:
[tex]\Delta x = v_{o}\cdot t +\frac{1}{2}\cdot a\cdot t^{2}[/tex] (2)
Where [tex]v_{o}[/tex] is the initial velocity of the object, measured in meters per second.
We clear the acceleration within the equation above:
[tex]\frac{1}{2}\cdot a \cdot t^{2} = \Delta x-v_{o}\cdot t[/tex]
[tex]a = \frac{2\cdot (\Delta x - v_{o}\cdot t)}{t^{2}}[/tex]
If we know that [tex]\Delta x = 100\,m[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex] and [tex]t = 10\,s[/tex], then the net acceleration experimented by the object is:
[tex]a = \frac{2\cdot \left[100\,m-\left(0\,\frac{m}{s} \right)\cdot (10\,s)\right]}{(10\,s)^{2}}[/tex]
[tex]a = 2\,\frac{m}{s^{2}}[/tex]
By the 2nd Newton's Law, we construct the following equation of equilibrium under the consideration of a friction force acting against the motion of the object:
[tex]\Sigma F = F - f = m\cdot a[/tex] (3)
Where:
[tex]F[/tex] - External force exerted on the object, measured in newtons.
[tex]f[/tex] - Kinetic friction force, measured in newtons.
If we know that [tex]F = 15\,N[/tex], [tex]m = 6\,kg[/tex] and [tex]a = 2\,\frac{m}{s^{2}}[/tex], the kinetic friction force is:
[tex]f = F-m\cdot a[/tex]
[tex]f = 15\,N-(6\,kg)\cdot \left(2\,\frac{m}{s^{2}} \right)[/tex]
[tex]f = 3\,N[/tex]
The work done by friction ([tex]W'[/tex]), measured in joules, is:
[tex]W' = f\cdot \Delta x[/tex] (4)
[tex]W' = (3\,N) \cdot (100\,m)[/tex]
[tex]W' = 300\,J[/tex]
And the net work experimented by the object is:
[tex]\Delta W = 1500\,J - 300\,J[/tex]
[tex]\Delta W = 1200\,J[/tex]
By the Work-Energy Theorem we understand that change in translational kinetic energy ([tex]\Delta K[/tex]), measured in joules, is equal to the change in net work. That is:
[tex]\Delta K = \Delta W[/tex] (5)
If we know that [tex]\Delta W = 1200\,J[/tex], then the change in translational kinetic energy is:
[tex]\Delta K = 1200\,J[/tex]
The kinetic energy of the block after 10 seconds is 1200 joules.
c) The magnitude of the force of friction is 3 newtons and its direction is against motion.
d) The energy lost by the object is equal to the work done by the force of friction. Therefore, 300 joules of energy are lost during motion.
Jack and Rob try to move the new couch. Jack pulls with 30N of force and Rob pushes with 25 N of force.
Net Force = (your answer)
Body Diagram or Explanation = (your answer)
Answer:
Fr = 55 [N]
Explanation:
We must perform a free body diagram to understand the forces acting on the couch. In the attached image we see the force that Jack exerts just like that of Rob acting in the same direction.
We must perform a summation of force on the X-axis, to determine the resulting force.
∑Fx = Fr
Fr = 30 + 25
Fr = 55 [N]
What is the motion of the object?
F = 90 N
F3 = 60 N
F = 20 N
F2 = 90 N
Constant speed to the left
Accelerating to the left
Accelerating to the right
Constant speed to the right
Answer:
Thus, the object is accelerating to the left
Explanation:
The Net Force
The net force is the result of adding all the forces as vectors acting on a body.
[tex]\vec F=\vec F_1+\vec F_2+...+\vec F_n[/tex]
Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.
Second Newton's law gives the relation between the net force and the acceleration of the body:
[tex]\vec F = m.\vec a[/tex]
We can see the acceleration is a vector with the same direction as the net force.
The diagram shows two vertical forces and two horizontal forces.
The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.
The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N
Thus, the object is accelerating to the left
Calculate the force between charges of 55 × 108 C and 1 × 107C if they are 5
cm apart.?
First:
5 cm = 0,05 m
Now, the formula:
F = k * (qq') / r²
Replacing:
F = 9x10⁹ * (55x10⁸ * 1x10⁷) / 0,05²
F = 9x10⁹ * (5,5x10¹⁶ / 2,5x10⁻³)
F = 9x10⁹ * 2,2x10¹⁹
F = 1,98x10²⁹
The force between the charges is 1,98x10²⁹ Newtons.
Please HElp!!
Name five conductors and insulators
Answer:
Conductors- copper, aluminum, gold, and silver.
Insulators- glass, air, plastic, rubber, and wood.
Explanation:
Answer: 5 conductors are copper, aluminum, gold, iron, and silver and 5 insulators are glass, air, plastic, rubber, and wood.
why reverberation doesn't occur in well furnished room?
Answer:
It is because the room is occupied with stuffs.
Explanation:
In a well furnished room there are things
like bed, cupboard, wardrobe and other stuffs, So they act as absorbing materials.
They absorb sound and do not give a chance to resounds.
Vin Diesel jumps out of a plane. Gravity pulls on him with 184N of force and his parachute pushes him up with 82 N of force.
Net Force = (your answer)
Body Diagram or Explanation = (your answer)
Answer:
Fr = 102[N]
Explanation:
We must perform a free body diagram to understand the forces acting on Vin Diesel. In the attached image we see the forces related to his weight and the air resistance force.
We must analyze the forces in the Y axis, we see that we have the force of the air opposing the fall of Vin Diesel, in this way this force is negative since it opposes the movement, the fall.
∑Fy = 0
[tex]F_{weight}-F_{air}=F_{r}\\F_{r}= 184-82\\F_{r}=102[N][/tex]
A truck covers 40.0 m in 9.50 s while uniformly slowing down to a final velocity of 2.75 m/s.
a. Find its original speed.
b. Find its acceleration.
Explanation:
Given that,
Distance covered, d = 40 m
Time, t = 9.5 s
Final velocity, v = 2.75 m/s
(a) Let u be the original speed of the truck. We can find it using first equation of motion.
[tex]v=u+at\\\\2.75=u+2.75\times 9.5\\\\2.75-26.125=u\\\\u=-23.375\ m/s[/tex]
(b) Acceleration = rate of change of velocity
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{2.75-(-23.375)}{9.5}\\\\=2.75\ m/s^2[/tex]
So, the original speed is -23.375 and acceleration is 2.75 m/s².
number 8 please i need help asap
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
what is the velocity of a point on the edge of the wheel?
A. 6.15 m/s
B. 5.39 m/s
C. 5.84 m/s
D. 6.20 m/s
Answer:
The correct answer is B)
Explanation:
When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel. So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.
The formula for calculating the velocity of a point on the edge of the wheel is given as
[tex]V_{r}[/tex] = 2π r / T
Where
π is Pi which mathematically is approximately 3.14159
T is period of time
Vr is Velocity of the point on the edge of the wheel
The answer is left in Meters/Seconds so we will work with our information as is given in the question.
Vr = (2 x 3.14159 x 1.94m)/2.26
Vr = 12.1893692/2.26
Vr = 5.39352619469
Which is approximately 5.39
Cheers!
If velocity, time and force were chosen as basic quantities, find the
dimensions of mass and energy.
Answer:
The Dimension of mass is [F T v⁻¹] and Dimension of energy is [F T v]
Explanation:
(i) We know that,
Force = mass × acceleration
= mass × velocity/time
⇒ mass = force × time ÷ velocity
or. [mass] = [force] [time] ÷ [velocity]
= [F] [T] ÷ [v]
∴ [mass] = [F T v⁻¹]
(ii) Dimensions of energy are same as the dimensions of kinetic energy
∴ Energy = [ ½mv²] = [m] [v]²
= [F T v⁻¹] [v]²
Energy = [F T v]
Thus, The Dimension of mass is [F T v⁻¹] and Dimension of energy is [F T v]
-TheUnknownScientist
Explanation:
fvt-1 = mass
ftv = energy
A ball is hit with a paddle, causing it to travel straight upward. It takes 2.90 s for the ball to reach its maximum height after being hit. Treat upward as the positive direction.
(a) What is the ball's initial velocity (in m/s), just after it is hit? _____ m/s upward
(b) What height (in m) does it reach above the level where it was hit? _____ m
Answer:
A. 28.42 m/s
B. 41.21 m
Explanation:
From the question given above, the following data were obtained:
Time (t) to reach the maximum height = 2.90 s
Initial velocity (u) =?
Maximum height (h) =?
A. Determination of the initial velocity of the ball.
Time (t) to reach the maximum height = 2.90 s
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
v = u – gt (since the ball is going against gravity)
0 = u – (9.8 × 2.9)
0 = u – 28.42
Collect like terms
0 + 28.42 = u
u = 28.42 m/s
Thus, the initial velocity of the ball is 28.42 m/s
B. Determination of the maximum height reached by the ball.
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) = 28.42 m/s
Maximum height (h) =?
v² = u² – 2gh (since the ball is going against gravity)
0² = 28.42² – (2 × 9.8 × h)
0 = 807.6964 – 19.6h
Collect like terms
0 – 807.6964 = – 19.6h
– 807.6964 = – 19.6h
Divide both side by – 19.6
h = – 807.6964 / – 19.6
h = 41.21 m
Thus, the maximum height reached by the ball is 41.21 m
A 0.55-kg particle has a speed of 5.0 m/s at point A and kinetic energy of 7.6 J at point B.
a. What is its kinetic energy at A?
b. What is its speed at point B?
c. What is the total work done on the particle as it moves from A to B?
Answer:
(a) The kinetic energy at A is 6.875 J.
(b) The speed at point B is 5.26 m/s.
(c) The total work done on the particle as it moves from A to B is 0.725 J.
Explanation:
Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and at rest, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless a change in speed occurs or the body returns to its state of rest by applying a force.
Kinetic energy is represented by the following formula:
Ec = ½ *m*v²
Where Ec is kinetic energy, which is measured in Joules (J), m is mass measured in kilograms (kg), and v is velocity measured in meters over seconds (m/s).
(a) In this case, you know:
m= 0.55 kgv= 5 m/sReplacing:
Ec = ½ *0.55 kg*(5 m/s)²
and solving you get:
Ec= 6.875 J
The kinetic energy at A is 6.875 J.
(b) In this case, you know:
Ec= 7.6 Jm= 0.55 kgReplacing:
7.6 J = ½ *0.55 kg*v²
and solving you get:
[tex]v=\sqrt{\frac{7.6 J}{\frac{1}{2}*0.55 kg } }[/tex]
v= 5.26 m/s
The speed at point B is 5.26 m/s.
(c) The total work done on the particle as it moves from A to B is the difference between the work done at the end point (point B) and the work done at the start point (point A). Considering that work is equal to kinetic energy, then:
Work= Ec at point B - Ec al point A= 7.6 J - 6.875 J
Work= 0.725 J
The total work done on the particle as it moves from A to B is 0.725 J.
why was bowling one of the first racially integrated sports
Answer:
bowling was one of the first racially integrated sports because bowling alleys were primarily located in urban areas. Racial integration was inevitable since it was promoted by US Armed Forces during 1940s and its image as sport for the common man made it a choice of activity for Americans!!
Explanation:
A force Fof 40000 lbf is applied to rod AC the negative Y-direction. The rod is 1000 inches tall. A Force P of 25 lbf is applied in the negative Z- direction at point E, and a force R of 75 ibf is applied in the negative Z-direction at point F. Rod AC has a diameter of 1 inch from A to ca diameter of 15 inches from 3 tic, and all fillet radii are 0.25 in. The rod is made of 1020 CD steel, and has a Sy of 135 ksi, a Sur of 150 ksi, and an ef = 0.15. Determine the effective stress at point B
Answer:
The answer is "effective stress at point B is 7382 ksi "
Explanation:
Calculating the value of Compressive Axial Stress:
[tex]\to \sigma y =\frac{F}{A} = \frac{4 F}{( p d ^2 )} = \frac{(4 x ( - 40000 \ lbf))}{[ p \times (1 \ in)^2 ]} = - 50.9 \ ksi \\[/tex]
Calculating Shear Transverse:
[tex]\to \frac{4v}{ 3 A} = \frac{4 (75 \ lbf + 25 \ lbf)}{ \frac{3 ( lni)^2}{4}}[/tex]
[tex]= \frac{4 (100 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\ = \frac{400 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\= 0.17 \ ksi[/tex]
[tex]= R \times 200 \ in - P \times 100 \ in = 12500 \ lbf \times\ in[/tex]
[tex]\to \sigma' =[ s y^2 +3( t \times y^2 + t yz^2 )] \times \frac{1}{2}\\\\[/tex]
[tex]= [ (-50.9)^2 +3((63.7)^2 +(0.17)^2 )] \times \frac{1}{2}\\\\=[2590.81+ 3(4057.69)+0.0289]\times \frac{1}{2}\\\\=[2590.81+12,173.07+0.0289] \times \frac{1}{2}\\\\=14763.9089\times \frac{1}{2}\\\\ = 7381.95445 \ ksi\\\\ = 7382 \ ksi[/tex]
What will happen to the wavelength of light uf the frequency is doubled?What will happen to the wavelength of light uf the frequency is doubled?
Answer:
if the frequency is double, the wavelength is only half as long
Explanation:
Considering the definition of wavelength, frequency and propagation speed, if the wavelength is doubled, the frequency is reduced by half.
In a periodic wave the wavelength (λ) is the physical distance between two points from which the wave repeats itself. That is, the wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
The frequency (f) is a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).
The wavelength and its frequency are related from the speed at which the wave travels. The propagation speed (v) is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement. So, the speed expression is:
v=λ×f
This indicates that the higher the frequency, the shorter the wavelength and the lower the frequency, the longer the wavelength.
All electromagnetic waves propagate in a vacuum at a constant speed of 300,000,000 m/s, the speed of light. Then, since an inversely proportional relationship is established between the frequency and the wavelength, if the wavelength is doubled, the frequency is reduced by half.
In summary, if the wavelength is doubled, the frequency is reduced by half.
Learn more:
brainly.com/question/2232652?referrer=searchResults brainly.com/question/7321084?referrer=searchResults brainly.com/question/14946166?referrer=searchResultswhat is general relativity
Explanation:
General relativity is a theory of space and time. ... The central idea of general relativity is that space and time are two aspects of spacetime. Spacetime is curved when there is matter, energy, and momentum resulting in what we perceive as gravity. The links between these forces are shown in the Einstein field equations.
According to the Law of Conservation of Energy, why does the first hill on a roller coaster always have to be the tallest of all the other hills?
A 12-inch ruler rests on your right index finger at the 6-inch mark.
Required:
a. What forces are present?
b. Write the first and second equations of equilibrium fully and show that both conditions are satisfied.
Answer:
Explanation:
Let the right index finger be the pivot, the balanced ruler is shown in the diagram attached to this answer.
a. The forces present are:
i. The weight of the ruler, W, which acts upwards at the point of pivot.
ii. The reaction, R, of the right index finger on the ruler which acts upwards.
b. According to the principle of equilibrium, the total forces acting upwards must be equal to the total forces acting downwards.
So that,
R = W ................. 1
ii. The sum of clockwise moment must be equal to the sum of anticlockwise moment.
Since the ruler is balanced at the mid-point (6 inch), then;
R x 0 = w x 0 = 0 ............... 2
This implies that no moment is experienced by the ruler balanced on the right index finger. Therefore, the ruler is said to be in a state of equilibrium.
A weight of 1400 pounds is suspended from two cables as shown in the figure. What is the tension in the left cable? _________ pounds (Round to one decimal place as needed).
Answer:
Following are the solution to this question:
Explanation:
Law:
[tex]\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}[/tex]
[tex]= 180^{\circ}- 75^{\circ}\\\\= 105^{\circ}[/tex]
[tex]\to \frac{T_{L}}{\sin (90+50)}= \frac{T_{R}}{\sin (25+90)}=\frac{1400}{\sin (105)}[/tex]
[tex]\to T_L=931.65 \ pounds \\\\ \to T_R=1313.59 \ pounds \\\\[/tex]
Who’s has bigger cross sectional area capillaries or aorta?
Answer:
Even though the cross-sectional area of each capillary is extremely small compared to that of the large aorta, the total cross-sectional area of all the capillaries added together is about 1,300 times greater than the cross-sectional area of the aorta because there are so many capillaries
Explanation: