A rock dropped off a bridge takes 5 seconds to hit the water. Which of the following best represents the rock's speed just before impact?

Answers

Answer 1

The rock's speed just before impact is 49 m/s and it will be the maximum speed of the rock.

What is the rock's speed before the impact?

The velocity of the rock before the impact is the final velocity of the rock and it depends on the initial velocity of the rock, time of motion and acceleration due to gravity.

The speed of the rock before the impact is calculated as follows;

v = u + at

where;

v is the final velocity of the rocku is the initial velocity of the rockt is the time of motiong is acceleration due to gravity

Substitute the given parameters and solve for the final velocity.

v = 0 + 9.8 m/s² x 5 s

v = 49 m/s

Thus, the rock's speed just before impact is 49 m/s and it will be the maximum speed of the rock.

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Related Questions

A green laser pointer emits light with a wavelength of 532 nm. What is the frequency of this radiation, in hz?.

Answers

The frequency of electromagnetic waves is 5.64 x 10¹⁴ Hz.

We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as

c = λ . f

where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.

From the question above, we know that

λ = 532 x 10¯⁹ m

By substituting the given parameter, we can calculate the frequency of green laser pointer

c = λ . f

f = c / λ

f = 3 x 10⁸ / 532x10¯⁹

f = 5.64 x 10¹⁴ Hz

Hence, the frequency is 5.64 x 10¹⁴ Hz.

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1. What coefficients would balance the following equation?
_Al + _02 →_Al2O3
2A1 + 302 +1A1,03
2A1+ 302 → 2A1203
3A1 + 302 + 2A1003
4A1 + 302 → 2A1203

Answers

Answer:

D. 4Al + 3O2 → 2Al2O3

Explanation:

Chemical reactions involves the chemical combination of two or more substances called REACTANTS to yield other substances called PRODUCTS. However, in accordance with the LAW OF CONSERVATION OF MASS, the amount of reactants must be equal to that of the products.

To accomplish this, the reaction must be BALANCED. A balanced equation is an equation in which the number of atoms of each element in the reactant side equals the number of atoms in the product side. In this reaction involving Aluminum and Oxygen to give Aluminum oxide as follows:

Al + 02 → Al2O3

A coefficient is used to balance the number of atoms on both sides of the equation as follows:

4Al + 3O2 → 2Al2O3

Answer:

here for points

3u3784y297y4ui3t7

Explanation:

An object of known mass that can be used to establish uncertainty in measurements made with a balance is best described as a.

Answers

According to the graphic, the weighing balance has a hundredth-place level of uncertainty.

What is a balance?

The characteristic of matter that gauges its resistance to acceleration in physics. An object's mass can be thought of as a rough count of its atoms.

Any tool that measures an object's mass or weight is referred to as a balance. Every laboratory needs balance as an essential tool.

In the hundredth position, there is uncertainty. There are always three significant figures for a mass that is between 1 gram and 9 grams when it is measured on this balance.

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A sound wave has a velocity of 350 meters/second and a frequency of 430 hertz. what is its wavelength? a. 0.01 meters b. 0.60 meters c. 0.81 meters d. 0.08 meters

Answers

The wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.

The relation between velocity(v), frequency(f) and wavelength(lambda) of a sound wave is given by the following formula,

V = (f)(λ)                                                 equation1

We are given that , v = 350 meters/second

f = 430 hertz

By putting the above values in the equation1 , we will get

350 = 430 x (λ)

350/430 = λ

λ = 0.81 meters

Thus, the wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.

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How do sound waves travel?

Sound waves radiate outward from a central point.

Sound moves randomly in different directions.

Sound causes the air near it to vibrate inwards.

Sound transforms waves into different frequencies.
please give right answer!

Answers

Answer:

Sound waves move by vibrating objects and these objects vibrate other surrounding objects, carrying the sound along. The further away from the original source of a sound you are, the waves lessen until they don't have the strength to vibrate any other particles.

Explanation:

broglie wavelength of a 231 gg baseball with a speed of 34.0 m/sm/s ? express your answer in meters.

Answers

The broglie wavelength is 9.27 x 10¯³⁵ meter.

We need to know about de Broglie's wavelength to solve this problem. Broglie's wave equation is the following :

λ = h / (m.v)

where λ is the wavelength, h is Max Planck constant 6.62x10⁻³⁴ J.s, m is the mass and v is velocity.

From the question above, we know that:

m = 231 gram = 0.231 kg

v = 34 m/s

By substituting the parameter, we get :

λ = h / (m.v)

λ = 6.62x10⁻³⁴ / (0.21 x 34)

λ = 9.27 x 10¯³⁵ m

Hence, the broglie wavelength is 9.27 x 10¯³⁵ meter.

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Ou
A truck starts from rest and accelerates uniformly over a time of 5.5 seconds for a
distance of 130 m. Determine the acceleration (in m/s^2) of the truck.
Please submit your answer with 2 decimal places!

Answers

Answer:

8.6m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 5.5s

Distance  = 130m

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use one of the appropriate motion equations:

       S  = Ut  + [tex]\frac{1}{2}[/tex] at²

S is the distance

U is the initial velocity

t is the time taken

a  is the unknown acceleration

t is time taken

    Since U = 0m/s

      S  =  [tex]\frac{1}{2}[/tex] at²

     130 =  [tex]\frac{1}{2}[/tex]  x a x 5.5²  

     130  = 15.13a

         a  = 8.6m/s²

What unite do scientists use to measure force

A) Newton
B) grams
C) meters
D) meters per second per second

Answers

They use Newton to measure force

calculate the displacement and velocity of a ball 0.50 seconds after it is thrown straight up with an initial velocity of 15.0 m/s. take the point of release to be an initial height of zero.

Answers

Answer:

The ball will have a displacement of 0.5*15.0=7.5m after 0.5 seconds. The velocity of the ball will be 15.0 m/s, since it is not acted on by any forces except gravity (which acts in the direction opposite of the velocity).

Explanation:

We know this is the answer because, according to the kinematic equation:

v^2=u^2+2*a*d

0=15.0^2+2*(-9.8)*d

d=-7.5m

If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?

Answers

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 200kg

Force on car  = 500N

Unknown:

Acceleration of the car  = ?

Solution:

According to Newton's second law of motion:

      Force  = mass x acceleration

Insert the given parameters and find the acceleration;

         500  = 200 x acceleration

           acceleration = 2.5m/s²

Explanation:

F = ma

500N = 200 × a

200a. = 500N

a. =. 2.5m/s²

PLEASE GIVE BRAINLIEST.

You are playing catch in the front yard and your sister throws a football at you, then your neighbor throws a baseball at
you at the same speed.
Which ball has the greater momentum?

Answers

i believe the baseball is the answer

100 POINTS PHYSICS PLEASE HELP

1: Let’s say you drop a 100 kg ball from the top of the stairs and by the
time it reaches the ground it has a velocity of 40 m/s. How much kinetic
energy would it have?

2: If a 63.5 kg person climbs a hill that is 1500 m and stands at the top
looking over the edge, what is their potential energy at that point?

3: If that 63.5 kg person went parachuting, jumped out of an airplane, and
reached a velocity of 80 m/s before opening their parachute, how much
kinetic energy would they have?

4: Look at the formula for potential energy. Why would that 63.5 kg person
have more energy if they walked up a 1500 m hill than if they walked 1500
m on a flat surface?

Answers

Answer:

1: The Ball Has 80,000 J

2: Their Potential Energy Is 934,083 J At That Point

3: They Would Have 203,200 Kinetic Energy

4: The Person Would Have More Potential Energy GoingUp A 1500 M Hill Rather Than Walking 1500 M On A Flat Surface Because When You Walk Up Something You Have More Potential Energy Then When You Walk On Flat Ground

Reason:

1: 100kg x 40 m/s = 80,000

2: 63.5 x 1500 M = 934,083

3: 63.5 x 80 M/s = 203,200

A bicyclist pedaling up a hill is this a form of kinetic energy or potential energy?

Answers

Answer:

Kinetic

Explanation:

Its a moving action

When a bicyclist is pedaling up a hill, it is a form of potential energy. The correct option is option potential energy.

An object's position or configuration in relation to other things might provide it potential energy. The potential energy in this situation is gravitational potential energy.

Because they are being lifted against gravity as they ascend the hill, the cyclist gains gravitational potential energy. The potential energy of the cyclist increases as they ascend.

The potential energy will be transformed into kinetic energy once the cyclist begins pedaling or moving downward.

As a result of their increased height above the ground, cyclists are building up potential energy as they bike up a hill. They gain speed as they cycle downhill, transforming that potential energy into kinetic energy.

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A nonconducting ring of radius R is uniformly charged with a total positive charge q. The ring rotates at a constant angular speed \omega about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic field on the axis of the ring a distance 1/2 R from its center?

Answers

The magnitude of the magnetic field on the axis of the ring (1/2)R from its center is [tex]\frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R }[/tex].

The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.

The radius of the nonconducting ring is R.

The ring is uniformly charged q.

The ring rotates at a speed of ω.

The distance between the ring and its center is x = (1/2)R.

The magnetic field on a current loop's axis is given as follows:

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]

Now, [tex]I=\frac{q}{2 \pi /\omega}[/tex]

The magnetic field's strength at x = R/2 is:

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{R}{2} )^{2}+R^{2})^{\frac{3}{2}} }[/tex]

[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{5}{4} )R^{2})^{\frac{3}{2}} }[/tex]

[tex]B = \frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R}[/tex]

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Newton's first law of motion: Objects in motion will stay in motion and objects at rest will stay at rest, unless acted on by
a. friction
b. acceleration
c. unbalanced force
d. contact force​

Answers

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia

The effect of gravity on a falling object can be modeled by a ball dropped
from different heights. What is a limitation of this model?
O A. Not all objects bounce, even though balls do.
B. Friction with air also affects the fall of the object.
C. Some balls float in water, while others sink.
O
D. The ball can be dropped from varying heights.

Answers

Answer:

B. Friction with air also affects the fall of the object.

Explanation:

The limitation of this experimental design is that friction with air also affects the fall of the object.

Therefore, it is difficult to measure effect of gravity on falling objects. Air resistance cause friction in the movement of an object falling. Frictional force resists the motion of an object subject to free fall.

Therefore, the experiment will be biased due to the influence of the frictional force.

estimate how long it would take one person to mow a football field using an ordinary home lawn mower. suppose that the mower moves with a 1- km/h speed, has a 0.5- m width, and a field is 360 ft long and 160 ft wide. 1 m

Answers

The calculated time taken is 10.7 hours

Given that our speed is 1 km/h and our width is 0.5 m, we can mow a path that is 0.5 m wide and 1000 m long in an hour, covering a total area of 1000 m * 0.5 m = 500 m2/hr.

Let's now determine the size of that football field.

5350.692864 m2 is equal to 360 ft / 3.281 ft/m plus 160 ft / 3.281 ft/m.

To determine how many hours it will take, divide that area by the 500 m2 that was previously determined.

500 m2/hour / 5350.692864 m2

= 10.70138573 hr

In other words, moving the football field would take around 10.7 hours.

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what are two conditions of equilibrium? write them in word​

Answers

In order for a system to be in equilibrium , two conditions must be met. Net force must be 0.

Question 6 (3 points)
(03.01 MC)
The fossils found in the different layers of Earth are listed below.
Top layer: Fossil A
Bottom layer: Fossil B
Second layer from top: Fossil C
Third layer from top: Fossil D
Which fossil is the oldest? (3 points)
Oa
Fossil A
Fossil B
Fossil C
Fos
d

Answers

i’m pretty sure it’s c

Answer:

fossil c

Explanation:

a ball is thrown upward at 25 m/s from the ground. what is the average velocity and average speed of the ball after 5 seconds?​

Answers


When the ball reaches the highest point, its velocity will be zero. So final velocity is v=0m/s
Here, the time to reach highest point is equal to time to hit ground from highest point.
Consider upward motion, the acceleration of the ball is a=−g=−9.8m/s
2
(minus for motion opposite to gravity)
If t be the required time.
Using v=u+at,
0=25+(−9.8)t
⟹ t=2.5s
Thus the ball hits the ground after 2.5 seconds after reaching its highest point.

Help! How do you find the Eccentricity??

Answers

Explanation:

The formula to determine the eccentricity of an ellipse is the distance between foci divided by the length of the major axis

which statement correctly line graph
a. the x-axis is on the left side of the graph
b. the responding variable is on the y-axis
c. the line graph has 3 axes
d. the manipulated variable is not shown

Answers

Answer:

A.

Explanation:

The X-Axis is always on the left side.

What is a physical change ?
A. Burning wood
B. Rusting metal
C. Cooking a egg
D. Freezing water
Answer : Freezing water !

Answers

The answer is D but Ig you already knew that

the density of aluminum is 2.70 g/cm3. express this value in units of kilogram per cubic meter and pounds per cubic foot.

Answers

The density of aluminum in units of kilogram per cubic meter is 2700kg/m³

The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³

unit conversion - conversion of one unit to another unit of measurement of same quantity by using multiplication/division.

the density of aluminum is 2.70 g/cm3.(given)

1 kg = 1000g

1m = 100cm

density of aluminum in kg/m³ is :

2.7×10⁻³kg/10⁻⁶m³

2700kg/m³

density of aluminum in  lb/ft³ (ponds per cubic foot) is :

1g = 0.2204lb

1cm = 0.328ft

= 2.7×0.02204/(0.328)³

1.686lb/ft³

The density of aluminum in units of kilogram per cubic meter is 2700kg/m³

The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³

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Scientists study how the continents move. Why might scientists use a model
to show this movement?
O A. It is too slow to observe directly.
O B. It is too fast to observe directly.
O C. It is too dangerous to observe directly.
O D. It is too complex to observe directly.

Answers

Answer: A

Explanation: continents move very slowly, about one inch per year

Answer:

A

Explanation:

it takes thousands of years to see the continents progress in it's movement. by the time we see progress of how they are moving you'd have been dead for 50000 years XD

Two carts connected by a 0.25 m spring hit a wall, compressing the spring to 0.1 m. The spring constant k is 100 N m . What is the elastic potential energy stored from the spring's compression?

Answers

Given that,

Initial position of the spring, x₁ = 0.25 m

Final position of the spring, x₂ = 0.1 m

The spring constant of the spring, k = 100 N/m

To find,

The elastic potential energy stored from the spring's compression.

Solution,

The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :

[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]

So, the required energy is 2.62 J.

Answer:

1.125 J

Explanation:

The correct answer is 1.125 J

Will mark brainliest

Answers

Answer:

v = u +at

Explanation:

The equation that relates the final velocity and the average acceleration is written as follows :

v = u +at

Where

v is final velocity

u is initial velocity

a is acceleration

t is time

This equation is valid when the motion is with constant acceleration.

What is the answer please help me!

Answers

Answer:

The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground

Explanation:

We know that the earth's center attracts everything towards its center with an acceleration of 9.8 m/s² so it simply means that the change in velocity must occur to produce acceleration. When the ball comes towards the earth, its speed  continuously increases and it is at maximum level when it is about to hit the ground so this is the point where gravitational force is maximum.

I hope this helps ^_^

Which of the following actions is an example of an improvement in human capital?
A
Michelle applies for a job as a mechanical engineer at Honeywell.
B.
Marcus hires three workers for his thriving electrical business.
C.
Hawk Builders of Phoenix builds two new hospitals.
D.
Frank's Furniture trains all of its employees to use computers.

Answers

Answer: D

Explanation:

Frank’s Furniture trains all of its employees to use computers is an example of an improvement in human capital.

A 1000 kg car moves with a constant speed 20.0 m/s
around a flat circular track of radius 30.0 m. What is the
centripetal acceleration of the car?

Answers

Answer:

13.33 m/s^2

Explanation:

Velocity^2 then divide that by the radius

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