A reversible steady-state device receives a flow of 1 kg/s air at 400 K, 450 kPa and the air leaves at 600 K, 100 kPa. Heat transfer of 900 kW is added from a 1000 K reservoir, 50 kW is rejected at 350 K, and some heat transfer takes place at 500 K. Find the heat transferred at 500 K and the rate of work produced.

Answer:

Tools.

Explanation:

The Occupational Safety and Health Administration (OSHA) is a federal agency saddled with the responsibility of assuring and ensuring safe and healthy working conditions for employees by setting and enforcing standards, providing education, trainings and assistance to various organizations.

According to the Occupational Safety and Health Administration (OSHA), trainings on the adoption and application of safety precautions (tools) such as wearing a personal protective equipment e.g masks (respirators), ear plugs, safety boots, gloves, helmet, etc. are very important and are essentially to be used by employees (workers) while working in a hazard prone environment or industries. Therefore, all employers of labor are required to provide tools and ensure that their employees properly use those tools, as well as abide by other safety precautions and standards.

Hence, training is a way for employers to provide tools to enable employees to protect themselves and others from injuries.

Answer:

A Lengths

Explanation:

you make a model to show an object too large to test and too expensive to test

Answer:

a. lengths.

Explanation:

The scale can be said to be a representation of the model as regards the prototype. The prototype is the machine. Using a 1:20 scale tells us that the model is 1/20 times the magnitude of the length of this machine. So if the length of the side of the machine = 20m then we would have the length of the model as 1. (1/20x20 = 1)

Therefore the scale is the length and option a is correct

This question is incomplete, the complete question is;

A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle.

Determine the velocity of the flowing water jet if the blade is assumed to be frictionless.

Answer: the velocity of the flowing water jet is 32.55 m/s  assuming the blade is frictionless

Explanation:

Given that;

Force Ft = 1040 N

diameter d = 2.5 cm = 0.025 m

we know that; force acting on Hemispherical plate is;

Ft = 2δav²

where

a is area = π/4(0.025)²

δ is density of water = 1000 kg/m³

v is velocity = ?

now we substitute

1040 = 2 × 1000 × (π/4(0.025)²) × v²

1040 =  0.9817v²

v² = 1040 / 0.9817

v² = 1059.3867

v = √1059.3867

v = 32.5482 ≈ 32.55 m/s

Therefore the velocity of the flowing water jet is 32.55 m/s  assuming the blade is frictionless

Answer:

i know this one well hypotheticly what if i where to say it was 0 b

Answer:

A sketch is included to show interior designs using a technique called sectioning.

Explanation:

Complete question is;

Lucy works for a company that manufactures liquid dyes for fabric. She currently wants to mix up some 23%-concentrated teal dye. She has 16 gallons of 15%-concentrated teal dye, as well as plenty of 25%-concentrated teal dye. How many gallons of the 25%-concentrated teal dye will Lucy need to add to the 15%-concentrated teal dye to make a batch with a concentration of 23%?

Answer:

64 gallons

Explanation:

We are given;

Quantity of 15%-concentrated teal dye = 16 gallons

Let the number of gallons of 25%-concentrated teal dye needed to add to make the batch with a concentration of 23% be represented as x.

Thus;

(15% × 16) + (25%)x = 23%(16 + x)

Multiply each term by 100 to give;

(15 × 16) + 25x = 23(16 + x)

240 + 25x = 368 + 23x

Rearranging, we have;

25x - 23x = 368 - 240

2x = 128

x = 128/2

x = 64

Answer:

The Load Voltage is 0.7 v

the corresponding voltage is - 3.098 dB

the corresponding current gain is 78.48 dB

the corresponding POWER gain is 37.7 bB

Explanation:

Given the diagram;

in the circuit of 1 MΩ and 200 KΩ are in  series

also 20  Ω and 100 Ω are in series;

so

V₀ = [ (1V×1MΩ)/(1MΩ+200KΩ)] × [ (1V×100Ω)/(100Ω+20Ω)]

V₀ = 0.7 v

The Load Voltage is 0.7 v

Now considering the formula to find Voltage Gain

A_v = V₀ / V_i

we substitute

A_v = 0.7 / 1

A_v = 0.7 V/V

to convert to dB

A_v (dB) = 20logA_v

= 20log0.7

= - 3.098 dB

the corresponding voltage is - 3.098 dB

To determine the current gain

A_i = V₀/100Ω × 1.2MΩ/V_i

= 0.7/100Ω × 1.2MΩ/1

= 8400 A/A

to convert to dB

A_I (dB) = 20logA_I

= 20log8400

= 78.48 dB

the corresponding current gain is 78.48 dB

To determine the power gain

P_G = V₀²/100Ω × 1.2MΩ/V_i²

= 0.49/100Ω × 1.2MΩ/1

= 5880 W/W

to convert to dB

P_G (dB) = 10logP_G

= 10log5880

= 37.7 bB

the corresponding POWER gain is 37.7 bB

Answer:

Answered below.

Explanation:

A) Both spheroidite & tempered martensite possess sphere - like cementite particles within their microstructure known as a ferrite matrix. However, the difference is that these particles are much larger for spheroidite than tempered.

B) Tempered martensite is much harder and stronger than spheroidite primarily because there is much more ferrite - cementite phase boundary area for its sphere - like cementite particles.

This is because the greater the boundary area, the more the hardness.

Answer:

The correct option is;

c.  the exergy of the tank can be anything between zero to P₀·V

Explanation:

The given parameters are;

The volume of the tank = V

The pressure in the tank = 0 Pascal

The pressure of the surrounding = P₀

The temperature of the surrounding = T₀

Exergy is a measure of the amount of a given energy which a system posses that is extractable to provide useful work. It is possible work that brings about equilibrium. It is the potential the system has to bring about change

The exergy balance equation  is given as follows;

[tex]X_2 - X_1 = \int\limits^2_1 {} \, \delta Q \left (1 - \dfrac{T_0}{T} \right ) - [W - P_0 \cdot (V_2 - V_1)]- X_{destroyed}[/tex]

Where;

X₂ - X₁ is the difference between the two exergies

Therefore, the exergy of the system with regards to the environment is the work received from the environment which at is equal to done on the system by the surrounding which by equilibrium for an empty tank with 0 pressure is equal to the product of the pressure of the surrounding and the volume of the empty tank or P₀ × V less the work, exergy destroyed, while taking into consideration the change in heat of the system

Therefore, the exergy of the tank can be anything between zero to P₀·V.

Answer:

R=v/i.... So V=R*i=10*1.7=17 volt

Answer:

Ve = Vcc/10

Explanation:

The rule of thumb that is used for emitter voltage while designing this is

Ve = Vcc / 10

Answer: c.An accumulator is not used in a system with a receiver/dryer

Explanation:

In a refrigeration system, a condenser is used to transfer heat and this occurs from the refrigerant to the air or water.

Then, the refrigerant then condenses to liquid when the hear has been transferred.

We should note that the condenser is normally mounted in front of the radiator. The receiver/dryer is a storage tank for the liquid refrigerant from the condenser.

The statement that an accumulator is not used in a system with a receiver/dryer is not true. This is because, the accumulator gives protection to the compressor which helps to prevent the failure of the compressor.

Therefore, the answer is C.

Explanation:

R = √(A²+B²–2ABCos(x°))

x⁰ = 180–135

x° = 45°

R = √(350²+180²–2(350(180))Cos(45)))

R = 256.524

F=m*a

F=80*20

F =1600 ans"

Answer: basically we are asked to find it's force and the formula that helps us to find force is Force= Mass× Acceleration

so let's put out the given and what we need to find

GIVEN. Solution

F=m.a

Mass= 1300. F=1300kg×20m/s

speed (Acceleration)=20m/2. F=26000Kg.m/s

Force=? F=26000N

N stands for Newton and the reason that it comes Newton is because it is the SI-unit of Force and the result of kg×m/s.

Answer:

2

Explanation:

Answer:

11/8

Explanation:

7/8+4/8=11/8 if you want it on a ruler you need to go online and type fraction to decimal converter and put in 11/8 into a decimal

Answer:

I am pretty confident it is the Employer!

Explanation:

They have the responsibility to provide a safe workplace that is free from serious hazards, according to the General Duty Clause of the OSH Act (OSHA Standards)

I hope this helped you!! :D

Answer:

Employers

Explanation:

OSHA requires employers to: Provide working conditions that are free of known dangers. Keep floors in work areas in a clean and, so far as possible, a dry condition. Select and provide required personal protective equipment at no cost to workers.

Answer:

The work of the turbine is done at the expense of the enthalpy of the fluid.

Explanation:

Ideally speaking, a turbine is a steady-state devices that has no heat interactions and generates works at the expense of enthalpy. By the First Law of Thermodynamic, we have the following definition for steady-state conditions: (all energy components are measured in joules)

[tex]E_{in} - E_{out} + E_{gen} = 0[/tex] (1)

Where:

[tex]E_{in}[/tex] - Inlet energy.

[tex]E_{out}[/tex] - Outlet energy.

[tex]E_{gen}[/tex] - Generated energy.

Generated energy is associated with endothermic and exothermic chemical reactions and fission processes in radioactive elements and isotopes. Since fluids used in turbines are usually inert, the generated energy is zero and each remaining componets of the expression are defined:

[tex]E_{in} = U_{g,in}+K_{in}+H_{in}[/tex] (2)

[tex]E_{out} = U_{g,out}+K_{out}+H_{out}+W_{out}[/tex] (3)

Where:

[tex]U_{g,in}[/tex], [tex]U_{g,out}[/tex] - Inlet and outlet gravitational potential energies.

[tex]K_{in}[/tex], [tex]K_{out}[/tex] - Inlet and outlet translational kinetic energies.

[tex]H_{in}[/tex], [tex]H_{out}[/tex] - Inlet and outlet enthalpies.

[tex]W_{out}[/tex] - Energy generated by the turbine.

Usually, turbines at steady state does not report significant changes in translational and gravitational potential energies and (2) and (3) can be reduced into this form:

[tex]E_{in} = H_{in}[/tex] (2b)

[tex]E_{out} = H_{out}+W_{out}[/tex] (3b)

And we find the following equation of work by substituting on (1):

[tex]W_{out} = H_{in}-H_{out}[/tex] (4)

In a nutshell, the work of the turbine is done at the expense of the enthalpy of the fluid.

Answer:

Each wattmeter measures a line-to-line voltage between two of the three power supply lines. In this configuration, the total power, watts is accurately measured by the algebraic sum of the two wattmeter values. Pt = P1 + P2. This holds true if the system is balanced or unbalanced.

Answer:

thats a really cool design or whatever you got there.

Explanation:

niceeeeeeee :)

Answer:

d

Explanation:

it measures things so i think that is the answer

Answer:

it would be d

Explanation:

i hope this helps

Answer:

The answer is "F".

Hope this helped!

Answer: the answer is B and D

Explanation:

Answer:

The answer is "Option C".

Explanation:

The creep depends on temperature and stress whenever the temperature rise, for failure generosity, its core symptoms can be increased between about 0,5 and 0,7 TM in k (melting point of temperature). It is indeed a metal puncturing type, typically at high temperatures with stresses below the yields of a metal.

Explanation:

Creep occurs by constant stress at temperatures over 0.5 TM in K.

Creep is a phenomenon in which a material or an object is elongated over a time period under constant temperature and stress for a long period of time. For example, a belt used for a year or so, is elongated.

The correct temperature is 125°C

Answer:

A) M_a1 = 0.5

B) T2 = 232.17 K

C) V2 = 611 m/s

D) m' = 187 kg/s

Explanation:

We are given;

Pressure; P1 = 250 kPa

Temperature; T1 = 125°C = 398 K

Speed; v1 = 200 m/s

Area; A2 = 0.25 m²

M_a2 = 2

A) Formula for M_a1 is given by;

M_a1 = v/a1

Where;

v is speed

a1 = √kRT

k is specific heat capacity ratio of air = 1.4

R is a gas constant with a value of R = 287 J/kg·K

T is temperature

Thus;

M_a1 = 200/√(1.4 × 287 × 398)

M_a1 = 200/399.895

M_a1 = 0.5

B) To find T2, let's first find the Stagnation pressure T0

Thus;

T0/T1 = 1 + ((k - 1)/2) × (M_a1)²

T0 = T1(1 + ((k - 1)/2) × (M_a1)²)

T0 = 398(1 + ((1.4 - 1)/2) × (0.5)²)

T0 = 398(1 + (0.2 × 0.5²))

T0 = 398 × 1.05

T0 = 417.9 K

Now,similarly;

T0/T2 = 1 + ((k - 1)/2) × (M_a2)²

T2 = T0/[(1 + ((k - 1)/2) × (M_a2)²)]

T2 = 417.9/(1 + (0.2 × 2²))

T2 = 417.9/1.8

T2 = 232.17 K

C) V2 is gotten from the formula;

T0 = T2 + (V2)²/(2C_p)

Cp of air = 1005 J/Kg.K

Thus;

V2 = √(2C_p)[T0 - T2]

V2 = √((2 × 1005) × (417.9 - 232.17))

V2 =√373317.3

V2 = 611 m/s

D) mass flow is given by the formula;

m' = ρA2•V2

Where;

ρ is Density of air with an average value of 1.225 kg/m³

m' = 1.225 × 0.25 × 611

m' = 187 kg/s

Answer:

v₀ = 2.68 m/s.

[tex]v_{B}[/tex] = 3.33 m/s

d = 1.61 m

Explanation:

Searching on the internet I found the picture of the answer in which the height between point A and point B is equal to 0.2 m.

To determine the value of v₀ we need to use the following equation:

[tex] v_{f} = v_{0} - gt [/tex]

Taking the initial vertical velocity ([tex]v_{0_{y}}[/tex]) as [tex]v_{A_{y}}[/tex] and the final vertical velocity ([tex]v_{f_{y}}[/tex]) as [tex]v_{B_{y}}[/tex] we have:

[tex]v_{B_{y}} = v_{A_{y}} - gt[/tex]  

We can express the time (t) in terms of the velocities of A and B:

[tex] t = \frac{v_{A_{y}} - v_{B_{y}}}{g} [/tex]    (1)

Now, we can use the equation:

[tex]y_{f} = y_{0} + v_{A_{y}}t - \frac{1}{2}gt^{2}[/tex]   (2)

By entering equation (1) into equation (2):

[tex]y_{f} = y_{0} + v_{A_{y}}*(\frac{v_{A_{y}} - v_{B_{y}}}{g}) - \frac{1}{2}g(\frac{v_{A_{y}} - v_{B_{y}}}{g})^{2}[/tex]      (3)

Since [tex]v_{A_{x}} = v_{B_{x}} [/tex] because there is no acceleration in the horizontal movement, we have:

[tex] v_{A}sin(15) = v_{B}sin(12) [/tex]

[tex] v_{A} = \frac{v_{B}sin(12)}{sin(15)} [/tex]    (4)

Taking:

[tex]y_{f}[/tex] = 0

[tex]y_{0}[/tex] = 0.2 m

g = 9.81 m/s²

[tex]v_{A_{y}} = v_{A}cos(15)[/tex]

[tex]v_{B_{y}} = v_{B}cos(12)[/tex]

Entering the above values and equation (4) into equation (3) we have:

[tex] -0.4 m*9.81 m/s^{2} = (\frac{v_{B}sin(12)cos(15)}{sin(15)})^{2} - (v_{B}cos(12))^{2} [/tex]  

By solving the above quadratic equation:

[tex]v_{B} = 3.33 m/s [/tex]

Hence, the velocity of the ball [tex]v_{B}[/tex] is 3.33 m/s.

Now, we can find [tex]v_{A}[/tex] by using equation (4):

[tex]v_{A} = \frac{v_{B}sin(12)}{sin(15)} = \frac{3.33 m/s*sin(12)}{sin(15)} = 2.68 m/s [/tex]

Then, the value of v₀ of the ball is 2.68 m/s.

Finally, to find the distance between point A and point B we need to calculate the time by using equation (1):

[tex]t = \frac{v_{A_{y}} - (-v_{B_{y}})}{g} = \frac{v_{A_{y}} + v_{B_{y}}}{g}[/tex]

The minus sign in [tex]v_{B_{y}}[/tex] is because the vertical component of the vector is negative.

[tex] t = \frac{v_{A_{y}} + v_{B_{y}}}{g} = \frac{2.68 m/s*cos(15) + 3.33 m/s*cos(12)}{9.81 m/s^{2}} = 0.60 s [/tex]

Now, the distance is:

[tex] x = v_{0}*t = 2.68 m/s*0.60 s = 1.61 m [/tex]

I hope it helps you!            

Answer:

O 2 no cap 192882822882282

Answer:

B.) Identify the need, create a concept, provide

Explanation:

edge

Answer:

A) б1 = 28 ksi and  б2 = -6.02 ksi

B) 1.25

Explanation:

Given data :

Torsional stress = 13 ksi

Alternating bending stress = 22ksi

A) determine yielding factor of safety  according to the distortion energy theory

б1,2 = [tex]\frac{22}{2}[/tex] ± √(22/2)² + 13²

       = 11  ± 17

therefore б1 = 28 ksi  hence б2 = -6.02 ksi

B) determine the fatigue factor of safety  

with properties ;  Se = 35ksi, Sy = 60 ksi, Sut = 85 ksi

( б1 - б2 )²  + ( б2 - б3 )² + ( б3 - б1 )²  ≤  2 ( Sy / FOS ) ²

( 28 + 6.02 ) ² + ( 6.02 - 0 )² + ( 0 - 28 )² ≤  2 ( 60 / FOS ) ²

solving for FOS = 1.9

Next we can determine FOS with the use of Goodman criterion

бm / Sut  + бa / Se  =  1 / FOS

= 0 / 85 + 28/35 = 1 / FOS

making FOS the subject of the equation ; hence  FOS = 1.25