A research group is interested in gauging perceptions about costs of textbooks among college students. They use an alphabetized list of students in state universities and use technology to generate a randomly shuffled list of students. They then select students to contact from this list until they have succeeded in contacting 175 students. What is the population parameter of interest

Answer: A

Step-by-step explanation:

26/400 = x/56,000

6.5% of the products are defective so you can just use that information to find the total defective.

.065 x 56,000 = 3,640

Answer:

3,640

Step-by-step explanation:

First find the percent of products that were defective out of 400.

26 ÷ 400 = 0.065 or 6.5%

Then find 6.5% of 56,000.

56,000 × .065 = 3640

Answer:

-4 5/12

Step-by-step explanation:

-23/3 + (-11/2) + 35/4

Find a common denominator (12).

-92/12 + (-66/12) + 105/12

Reform the equation to have this as a single fraction.

(-92 + (-66) + 105)/12

Subtract 66 from -92 to get -158.

(-158 + 105)/12

Add 105 to -158 to get -53.

-53/12

Convert into a mixed number by dividing by 12.

-4 5/12 (Choice A) is your answer.

Answer:

A

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

They are the same dimensions

Answer:

I think its true because there both the same shape and dimension

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

Learn more about length of the arc of a curve here:

https://brainly.com/question/14319881

Answer:

1a. 3y = 18

1b. y + 7 = 18

1c. 2y + 4 = 18

Step-by-step explanation:

In each case, let's take the red boxes to be constant why the the green boxes represents the variable, y.

Thus,

1a. There are only 3 green boxes which gives us 18, therefore, the equation that expresses this would be:

3y = 18

1b. We have 7 red boxes which represents the constant, 7.

We also have 1 green box which represents the variable, y. Therefore, the equation that expresses this would be:

y + 7 = 18

1c. We have 4 red boxes = 4

We have 2 green boxes = 2y

Therefore, we would have:

2y + 4 = 18

Answer:

8 divided by 1/4 = 2

12 divided by 1/4 = 3

more cows were put in the barn

Step-by-step explanation:

8 horses 1/4= 2

12 horses 1/4= 3

Answer:

all you have to do is graph i dont see what i can help you with im

sorry

Step-by-step explanation:

Answer:

x = 12

y = 12√3

Step-by-step explanation:

Answer:

= 9x−7

Step-by-step explanation:

=(2)(3x)+(2)(−5)+3x+3

=6x+−10+3x+3

Combine Like Terms:

=6x+−10+3x+3

=(6x+3x)+(−10+3)

=9x+−7

Answer:

he has already ran 35 miles

turn 70% into a decimal .70 than multiply that by 50 and you get 35

perimeter = 72 cm

width = x

length = x+8

perimeter of rect. = 2(l+b)

2(x+x+8) = 72

2(2x+8) = 72

4x + 16 = 72

4x = 56

x = 56|4

x= 14

hence width is 14 so ,length will

14+ 8 = 22

hope it helps and your day will full of happiness

NoAnswer:

Step-by-step explanation:

Answer:

So I think its either 75 or 3

Step-by-step explanation:

for 80% of 15 its 3. 20% is fifteen. 20 times 5 is 100 so I did 15 times 5 to get the answer 75. I hope this helps!

Given :

Sum of all angles in a triangle = 180°

Which means :

[tex] = \tt61 + 15x - 1 = 180[/tex]

[tex] =\tt 61 - 1 + 15x = 180[/tex]

[tex] =\tt 60 + 15x = 180[/tex]

[tex] = \tt15x = 180 - 60[/tex]

[tex] =\tt 15x = 120[/tex]

[tex] = \tt \: x = \frac{120}{15} [/tex]

[tex] =\tt x = 18[/tex]

Measure of angle 15x-1 :

[tex] = \tt15 \times 8 - 1[/tex]

[tex] =\tt120 - 1[/tex]

[tex] =\tt 119[/tex]

Thus, the measure of angle 15x-1 = 119°

Let us place 8 in the place of x to see if we have found out the correct measure of the angles :

[tex] = \tt40 + 21 + 119 = 180[/tex]

[tex] = \tt61 + 119 = 180[/tex]

[tex] =\tt 180 = 180[/tex]

Since the measures of all the angle sum up to form 180°, we can conclude that we have found out the correct measure of each of the angles.

Therefore, the value of x = 8

[tex]\boxed{\color{plum}\bold{x = 8}}[/tex]

Answer:

5) $82

6) 300

Step-by-step explanation:

If y=x is your linear regression equation, and if x = temperature and y = $ of ice cream sales, then...

5) x = 82, and given that y=x, then y = $82

6) y = $300, and given that y=x, then x = 300

This doesn't really require algebraic calculation, so I wonder if the linear regression equation obtained from the scatter plot is correct.

Answer:

false

Step-by-step explanation:

I assume this is a true/false question.

The answer would be 'false'.

For 3 segments to make a triangle, each single side must be LESS than the sum of the other two.

Here, that is not the case. The '10' side is not less than 3+7.

Answer:

35

Step-by-step explanation:

Hope this helps

==========================================================

Explanation:

There are currently 8,427 trees. Triple this value to get 3*8427 = 25,281

Add this result onto the previous number of trees to get 25,281+8,427 = 33,708

-----------

An alternative approach:

if we started off with x number of trees, and then added on three times as much, then we add on 3x more trees. This gets us x+3x = 4x trees total.

In this case, x = 8427, so that leads to 4*x = 4*8427 = 33,708

Answer:

See below.

Step-by-step explanation:

I've never seen one asked quite this way, but I think I have it figured out.

The objective here is to get the right answer for each square. The answer is either the one next to the 'x', which means you put an 'x' in the tic-tac-toe square or the answer is the one next to the 'O', which means you put an 'O' in the tic-tac-toe square.

I will number them boxes 1-3 on the top row, 4-6 for the next, and 7-9 for the bottom row.

Box 1: In a fraction, you subtract the bottom exponent from the top exponent, so the proper exponent is 10 - 2 = 8. That is an O for g^8.

Box 2: A power raised to a power - multiply the exponents. 2*6=12. That is an X for m^12 for box 2.

Box 3: for multiplying the same base, you add the exponents. 4+5=9. That gives us y^9, which is a X for box 3.

Box 4: j is a factor four times, so that is j^4. That puts an O in Box 4.

Box 5: In a fraction, you subtract the bottom exponent from the top exponent, so we get -2 - (-6) = -2 + 6 = 4. The correct expression is h^4, so we have an X for box 5.

Box 6: A power to a power, you multiply the exponents so the first part becomes m^8. Now we have m^8 * m^5. For multiplying the same base, you add the exponents. 8+5=13. That gives us m^13, which puts an O in box 6.

Box 7: The top is a power to a power so we multiply the exponents. 4*5=20. The top is b^20.

On the bottom, for multiplying the same base, you add the exponents. 2+3=5, so the bottom is b^5.

Now we have a fraction, (b^20)/(b^5). In a fraction, you subtract the bottom exponent from the top exponent, so we have 20 - 5 = 15, and thus b^15. That gives us an X for box 7.

Box 8: A fraction IS a division, so we do divisons and fractions the same way. The p^3 on the left is the top (numerator) and the p^2 part is the bottom (denominator). So 3-2=1. But P^1 is just P, so we have an O for box 8.

Box 9: For the numerator, it is a power to a power so we multiply the exponents and get k^12.

For the denominator, we are multiplying the same base, so you add the exponents. 7 + (-5) = 2, and we get k^2 for the denominator

Now we have the fraction of k^12 OVER k^2.  In a fraction, you subtract the bottom exponent from the top exponent. 12-2=10. We get k^10, giving us an X for box 9.

So here is what we get for tic-tac-toe.

0   X   X

O   X   0

X   O   X

We get 3 in a row in boxes 3, 5, and 7. The exponents in those problems are 9, 4, and 15 respectively. The product of thse 3 numbers is 540.

This was a LOT of steps, so I encourage you to check every little multiplication and addition I did.

Hope this helps.

Answer:

576 cm²

Step-by-step explanation:

10x15=150

10x15=150

12x15=180

1/2x8x12=48

1/2x8x12=48

150+150+180+48+48=576

Answer: positive force → balanced force → negative force

Step-by-step explanation: I just did it

Answer:

A

Step-by-step explanation:

edg

Answer:

=12r2+5

Step-by-step explanation:

3² + (12r2) - 16 / 4

9+12r2+−4

Combine like terms

(12r2)+(9+−4)

12r2+5

Answer:

Step-by-step explanation:

65

Answer:

[tex](-6,\, -5)[/tex] is outside the circle of radius of [tex]12[/tex] centered at [tex](3,\, 3)[/tex].

Step-by-step explanation:

Let [tex]J[/tex] and [tex]r[/tex] denote the center and the radius of this circle, respectively. Let [tex]F[/tex] be a point in the plane.

Let [tex]d(J,\, F)[/tex] denote the Euclidean distance between point [tex]J[/tex] and point [tex]F[/tex].

In other words, if [tex]J[/tex] is at [tex](x_j,\, y_j)[/tex] while [tex]F[/tex] is at [tex](x_f,\, y_f)[/tex], then [tex]\displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}[/tex].

Point [tex]F[/tex] would be inside this circle if [tex]d(J,\, F) < r[/tex]. (In other words, the distance between [tex]F\![/tex] and the center of this circle is smaller than the radius of this circle.)

Point [tex]F[/tex] would be on this circle if [tex]d(J,\, F) = r[/tex]. (In other words, the distance between [tex]F\![/tex] and the center of this circle is exactly equal to the radius of this circle.)

Point [tex]F[/tex] would be outside this circle if [tex]d(J,\, F) > r[/tex]. (In other words, the distance between [tex]F\![/tex] and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between [tex]J[/tex] and [tex]F[/tex]:

[tex]\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145} \end{aligned}[/tex].

On the other hand, notice that the radius of this circle, [tex]r = 12 = \sqrt{144}[/tex], is smaller than [tex]d(J,\, F)[/tex]. Therefore, point [tex]F[/tex] would be outside this circle.

Answer:

outside the circle

Step-by-step explanation:

khan

Answer:

14

Step-by-step explanation:

x = -14

and

y = - x

so you put the -14 instead of x

y = --14

y = +14