A rectangular garden is to be twice as long as it is wide. If 360 yards of fencing, including the gate, will completely enclose the garden, what will be the length of the garden, in yards

Area=50m^2

Let side be a

[tex]\\ \rm\Rrightarrow Area=a^2[/tex]

[tex]\\ \rm\Rrightarrow a^2=50[/tex]

[tex]\\ \rm\Rrightarrow a=\sqrt{50}[/tex]

[tex]\\ \rm\Rrightarrow a=7.1m[/tex]

Answer:

[tex]\displaystyle 5\sqrt{2}\:m.[/tex]

Step-by-step explanation:

Sinse squares are equal in length all around, this formula applies:

[tex]\displaystyle s^2 = A → \sqrt{50} = \sqrt{s^2} \\ \\ 5\sqrt{2} = s[/tex]

Therefore, the length of the playground is [tex]\displaystyle 5\sqrt{2}[/tex] metres.

* Just in case you could not figure out how to find the square root of fifty, here is how using perfect squares:

[tex]\displaystyle \sqrt{50} → \sqrt{2 \times 25} \\ \\ 5\sqrt{2}[/tex]

Sinse we are dealing with measurements, we only want the NON-NEGATIVE root.

I am joyous to assist you at any time.

Answer:

Hope it helped

Step-by-step explanation:

The restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

An inverse function or an anti function is defined as a function, which can reverse into another function.

Now the given quadtratic function is,

f(x) = x² + 2

Now vertex of the given quadratic function is (0,2)

Thus the range of the function is [2,∞)

If we restrict the domain of this function to either (-∞,0} or [0.∞), it will become one to one function.

Now the inverse function is given as,

y = x² + 2

Upon interchanging x and y, we get:

x = y² + 2

⇒ y² = x - 2

or, y = ±[tex]\sqrt{x-2}[/tex]

Hence, the inverse function would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

Thus, the restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

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Answer:

40% increase

Step-by-step explanation:

c = final value - initial value

     ------------------------------------

                initial value

112 - 80 = 32

32 / 80 = 0.4

0.4 = 40%

Answer:

<CAB =30°

Step-by-step explanation:

<DAB=80°

<DAC=50°

<DAB=<DAC+<CAB

<CAB=<DAB-<DAC

=80°-50°

=30°

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

Answer:

8

Step-by-step explanation:

The function u given me is

[tex] \tan( \frac{\pi}{4} (x - \frac{\pi}{3} ) )[/tex]

The period of a function is represented by

[tex] \frac{2\pi}{ |b| } [/tex]

where b is the coefficient of the x variable.

The coefficient is pi/4 so

[tex] \frac{2\pi}{ \frac{\pi}{4} } = 8[/tex]

8 is the answer.

Answer: 4 units

Step-by-step explanation:

(f–g)(x)= (3x-13) – (2x²–4x–5)= –2x²+7x-8

(f–h)(x)= (3x-13) – ( 4^x –7) = 3x – 4^x–6

(f+g)(x)= (3x-13) + (2x²–4x–5) = 2x²–x – 18

I hope I helped you^_^

Answer:

Step-by-step explanation:

[tex] \frac{3}{5} xy \: \times ( - 25 {x}^{2} y)[/tex]

[tex] = \frac{3}{5} \times ( - 25) \times x \times {x}^{2} \times y \times y[/tex]

[tex] = - 15 \times {x}^{3} \times {y}^{2} [/tex]

[tex] = - 15 {x}^{3} {y}^{2} (ans)[/tex]

Answer: $4.50

Step-by-step explanation:

48-21=27

27 divided by 6= 4.50

Therefore each case costs 4.50

Answer:

$4.50

Step-by-step explanation:

48 - 21

27

divide by 6

4.50

Answer:

true

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

137+143=280

280/7= 40

Answer:

Division/dividing/divide

Step-by-step explanation:

If Justin has 280 baseball cards, and if each page will only hold 7 cards per page, then by dividing 280 by 7 (280÷7) would equal to 40 pages.

Answer:

40+x+5 = 3x +15

2x= 30

x=15

Their present ages are 15 and 55

Answer:

Get all the terms with x on the left. Get all the terms without x on the right. Simplify by adding and subtracting the terms without x and adding and subtracting the terms with x. Finally divide to get the value of x.

Step-by-step explanation:

6x+6 =- 5+3x+17

6x+6 -6 =- 5+3x+17 -6

6x = 5+3x+11

6x = 3x + 16

6x - 3x = 3x + 16 -3x

3x = 16

3x / 3 = 16 / 3

x = 15/3 + 1/3

x = 5 1/3

x = 5.33333...

Answer:

Below.

Step-by-step explanation:

The GCF of 9 , 27 and 45 = 9.

GCF of the d terms is d^2.

So the GCF of the whole expression is 9d^2.

Factors are 9d^2( 1 - 3d^3 + 5d)

Answer:

position of objects in space

for example: up, down, in front, behind, between, left, right.

motion of objects in space

for example: Stars, planets, moons.

Answer:

x = 17°

m∠MKL = 116°

m∠JKL = 159°

Step-by-step explanation:

JKM = 43

MKL = 8x - 20

JKL = 10x - 11

Since JKL is the whole angle, JKM + MKL = JKL

43 + 8x - 20 = 10x - 11

Add 20 to both sides:

43 + 8x = 10x + 9

Subtract 8x from both sides:

43 = 2x + 9

Subtract 9 from both sides:

34 = 2x

x = 17°

MKL = 8(17) - 20

MKL = 116°

JKL = 10(17) - 11

JKL = 159°

And to check 159 - 116 = 43

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

I think its c I hope I'm right

Answer:

[tex]{ \underline{ \sf{6y = x + 1 }}}[/tex]

Step-by-step explanation:

[tex]y = mx + c[/tex]

m is slope

c is y intercept.

at x-intercept, y = 0

[tex]0 =( \frac{1}{6} \times - 1 )+ c \\ \\ c = \frac{1}{6} [/tex]

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of the given line is 6y=x+1.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

Given that the slope of the equation of the line is 1/6, while the x-intercept is at -1. Therefore, if we substitute the coordinate of the intercept and the slope in the equation in the general equation of the line. We will see,

y = mx + c

0 = (1/6)(-1) + c

0 = -1/6 + c

c = 1/6

Now, the equation of the line can be written as,

y = (1/6)x + (1/6)

y = (x/6) + (1/6)

y = (x+1)/6

6y = x + 1

Hence, the equation of the given line is 6y=x+1.

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Hi ;-)

[tex]y-4=3\\\\y=3+4\\\\\boxed{y=7}[/tex]

Answer:  7  

.....7-4=3

The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex]  is

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

From the Question we are told that

Vector [tex]\vec b = <9, 0, 0>[/tex]

Vector [tex]\vec a = <4, -5, 0>[/tex]

Generally in the orthogonal decomposition of b to a we have

[tex]\vec b=\vec b"+\vec b'[/tex]

Where

[tex]\vec b"=(\frac{\vec b*\vec a}{\vec *\vec a})*\vec a[/tex]

[tex]\vec b"=(\frac{ <9, 0, 0>*<4, -5, 0>}{<4, -5, 0>*<4, -5, 0>})*<4, -5, 0>[/tex]

[tex]\vec b"=<\frac{4}{5},\frac{-8}{5},0>[/tex]

Therefore

[tex]b'= \vec b- \vec b"\\\\b'=<4,0,0>-<\frac{4}{5},\frac{-8}{5},0>[/tex]

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

in Conclusion

The orthogonal decomposition of vector [tex]\vec b = <9, 0, 0>[/tex] with respect to vector [tex]\vec a = <4, -5, 0>[/tex]  is

[tex]b'=<\frac{16}{5},\frac{8}{5},0>[/tex]

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Answer:

Step-by-step explanation:

[tex]U=\{(x,y)\ \zeta\ y=|x+1| \ and\ x \in \{-2,-1,0,1,2\}\ \}\\\\\begin{array}{|c|c|}x&y\\---&---\\-2&2\\-1&0\\0&2\\1 & 4\\2&6\\---&---\\\end{array}\\\\U=\{(-2,2),(-1,0),(0,2),(1,4),(2,6)\}\\[/tex]

Answer:

2 / (-2,2)

Step-by-step explanation:

Answer:

Step-by-step explanation:

In x², here the 2 is exponent while x is base.

Answer:

an exponent

Step-by-step explanation:

hope it helps:)

Answer:

600

Step-by-step explanation:

since 1m=1000mm

Answer:

If the exponent is 0 the answer is 224/y^2

Step-by-step explanation:

Answer:

[tex] \sqrt{2.2.3.3.5} [/tex]

[tex]\sqrt{2.2.3.3.5}[/tex] is equivalent to [tex]\sqrt{180}[/tex]. Correct option is 1. First, we look for perfect square factors within 180. We can factor 180 as follows: [tex]\(180 = 2^2 \times 3^2 \times 5\)[/tex]

Next, we can group the perfect square factors together:

[tex]\(180 = (2 \times 3)^2 \times 5\)[/tex]

Since we are taking the square root of 180, we can rewrite it as the square root of its perfect square factors multiplied by the remaining non-perfect square factor:[tex]\(\sqrt{180} = \sqrt{(2 \times 3)^2 \times 5}\)[/tex]

The square root of a perfect square is just the value of the number itself:

[tex]\(\sqrt{180} = 2 \times 3 \times \sqrt{5}\)[/tex]

Finally, we can simplify the expression by multiplying the numbers outside the square root [tex]\(\sqrt{180} = 6\sqrt{5}\)[/tex]

So, the expression [tex]\(6\sqrt{5}\)[/tex] is equivalent to [tex]\(\sqrt{180}\)[/tex], and it represents the positive square root of 180 with any perfect square factors taken outside the square root sign.

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Answer:

1/23

Step-by-step explanation:

5/23 - 4/23 would be 1/23. When the denominators of the fractions are the same, you can just subtract the numerators.

Assuming 120 is a base 10 numeral, then

120 = 100 + 20 = 4×5² + 4×5¹

so you have

120₁₀ = 440₅