It will take the quarter 0.151 seconds to reach the ground.
Given the following data:
Height = 1.45 metersInitial velocity = 10.32 m/sWe know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find how much time it will take the quarter to reach the ground, we would use the second equation of motion.
Mathematically, the second equation of motion is given by the formula;
[tex]S = ut + \frac{1}{2} at^2[/tex]
Where:
S is the height or distance covered. u is the initial velocity. a is the acceleration. t is the time measured in seconds.Substituting the values into the formula, we have;
[tex]1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0[/tex]
The standard form of a quadratic equation is:
[tex]ax^2 + bx + c = 0[/tex]
a = 4.9, b = 10.32 and c = 1.45
We would solve the above quadratic equation by using the quadratic equation formula;
[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]
Substituting the values, we have;
[tex]t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}[/tex]
Time, t = 0.151 seconds.
Therefore, it will take the quarter 0.151 seconds to reach the ground.
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During a demonstration of Newton’s laws of motion, a student used the setup shown in Figure 1. The student flicked the index card with a fingertip, and the coin fell straight down into a plastic cup as shown in Figure 2.
A: A falling body accelerates at a constant speed.
B: The motion of an object is constantly changing due to magnetic forces.
C: The force friction causes an object in motion to move faster.
D: An object remains at rest, or at a constant speed, an unbalanced force acts on it.
Answer:
D. An object remains at rest, or at a constant speed, an unbalanced force acts on it.The coin was at rest until the card was removed, so it tended to remain in the same location. Once the card was gone, the unbalanced force of gravity caused the coin to fall.
I hope this helped!+*♡
4. A person who walks one block north, one block east, one block south,
and one block west has a DISPLACEMENT of... (include magnitude and
direction) *
Answer:
Displacement should be 0
Explanation:
Pleaseeeeeee, help me, I need youuuu!!!!!!
David put a plant in a black box as shown. The box also had a black lid to cover the front. David only opened the box to add water to the plant. The plant stayed in the box for 10 days. When David took the plant out of the box on the tenth day, the plant was dead. Why did the plant dead only after ten days in the box?
Answer:
the plant died because of lack of sunlight
Explanation:
A plant gets its food from the photosynthesis process, which combines CO₂ and H₂0 into carbohydrates, the two substances are in the box, but for this they need energy from sunlight.
CO₂ + H₂O + Sunlight /chlorophyll → (CH₂0)ₙ + O₂
the extra oxygen is released into the atmosphere.
Therefore the plant died because of lack of sunlight
Help hurry help pls it’s timed
I think it's the yellow one
3. A warehouse employee is pushing a 30.0 kg desk across a floor at a
constant speed of 0.50 m/s. How much work must the employee do on
the desk to change the speed to 1.00 m/s?
Answer: The employee must do 11.2308 Joules of work
Explanation:
Work done = force × distance
But
Force = ma(mass x acceleration due to gravity)
F = 30×9.8
F = 294N
Also distance moved can be found using the equation
v² = u² +2gS
1.00 ² = 0.50²+2(9.8)S
1 =0.25+19.6S
1-0.25 =19.6S
0.75=19.6S
S=0.75/19.6
S = 0.0382m
Work done = force × distance = FS
Work done = 294 N X 0.0382m
Workdone =11.2308Nm = 11.2308 Joules
Work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.
What is work done?Work done is the force applied on a body to move it over a distance. Work done by a body can be given as,
[tex]W=Fd[/tex]
Here (F) is the magnitude of force and (d) is the distance traveled.
From the second law of motion, the force is product of mass time acceleration. Thus the above formula can be given as,
[tex]W=(ma)d[/tex]
For the gravitational acceleration, it can be written as,
[tex]W=(mg)d\\W=mgd[/tex]
The constant speed by which, the warehouse employee is pushing the desk across a floor is 0.50 m/s and the the final speed of the desk is 1 m/s.
Thus, the distance traveled by it can be find out using the third law of motion as,
[tex]v^2-u^2=2gd\\1^2-0.25^2=2\times9.8\times d\\d=0.0382\rm m[/tex]
As the mass of the desk is 30 kg and the distance moved is 0.382 meters. Thus, put the values in the above formula as,
[tex]W=30\times9.81\times0.0382\\W\cong11.3\rm J[/tex]
Thus the work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.
Learn more about the work done here;
https://brainly.com/question/25573309
Continue taking reading until the water starts to be boil
Answer:
pogggs
Explanation:
how animal, plant, and bacterial cells are similar and how they are different from one another
During construction, a crane lifts a 2,000-newton weight to the top of a 50-meter-tall building. How much power must the crane have to perform this task in 5 seconds? Use commas where appropriate and round to the nearest tenth.
watts:
kilowatts:
horsepower:
Answer:
Work is defined as force thru a distance: W = F * S
Power is defined as Work per unit time P = W / t
So we an write: P = F * S / t = 2000 N * 50 m / 5 s = 20,000 N-m/s
Since a Joule/sec is equivalent to a Watt
The power required is 20,000 Watts or 20 Kw
Also, you can convert to Hp since 1 Hp = 746 Watts
What effect does the Sun have on the ocean tides?
A.
The Sun does not have an effect on the ocean tides because it is
too far away.
B. The Sun warms the water, causing it to rise.
C. The gravitational pull of the Sun causes spring and neap tides.
D.the gravitational pull of the sun gravity is more powerful then the moons
Answer:
B
Explanation:
When the sun, moon, and Earth are in alignment at the time of the new or full moon, the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides both commonly called spring tides.
PLEASE help its timed..
Which statement describes how a machine can help make work easier?
A)It can put out more force than the input force by decreasing the distance over which force is applied.
B) It can increase the amount of work performed if the output force is in the same direction as the input force.
C) It can apply a greater output force over a greater distance compared to the input force and distance.
D) It can increase the distance over which output force acts by applying less output force than input force.
Answer:
D
Explanation:
by increasing the distance through which force is applied, by changing the direction of force applied or by multiplying force of speed of the energy applied
Describe the movement of air masses and the weather conditions at front 3. What type of front is it?
Answer:
Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).
Warm Front. ...
Stationary Front. ...
Occluded Front.
Answer:
Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.
Explanation:PLATO
Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows through them. Draw a circuit diagram showing the correct connections of the three resistors, a cell of 2.5V, an ammeter and a voltmeter across R3. Calculate the potential difference across R3.
Answer
Explanation:
As the three resistors are connected in series, the expression to be used for the
calculation of RT equivalent resistance
is:
RT = R1 + R2 + R3
We replace the data of the statement in the previous expression and it remains:
5 10 15 RT + R1 + R2 + R3 + +
We perform the mathematical operations that lead us to the result we are looking for:
RT - 30Ω
Forces at a Distance
Use Equation: e-r/T
If the distance between the two foci in an orbit is 4 AU, and the length of the major axis is 9 AU, what is the eccentricity of the orbit?
O 0.888
O 0.222
O 2.25
O 0.444
True
False
PLEASE HELP
Answer:
False
Explanation:
10 is not the same as -10 but if -10 is the absolute value they would be the same
Give me brainllest
A commercial jet liner takes off with an average acceleration of 3 g. How long does it take to reach the end of its runway which is 1524 meters away?
Answer:
The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Explanation:
Given;
average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²
distance traveled by the commercial Jet liner, s = 1542 m
The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;
s = ut + ¹/₂at²
where;
u is the initial velocity of the commercial Jet liner = 0
s = 0 + ¹/₂at²
s = ¹/₂at²
2s = at²
[tex]t = \sqrt{\frac{2s}{a} } \\\\t = \sqrt{\frac{2 \times 1524}{29.4} } \\\\t = 10.18 \ s[/tex]
Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
don't give links or anything besides an answer to this problem
When sound waves move through a medium, in what direction do the particles in the medium move?
The particles always move side to side.
The particles always move up and down.
The particles always move in the same direction as the wave.
The particles always move perpendicular to the direction of the wave.
Answer:
I think its the last one
Explanation:
The particles always move perpendicular to the direction of the wave.
A hot-air balloon with a mass of 400 kilograms moves across the sky with 3,200 joules of kinetic energy. The velocity of the balloon is meters/second.
Answer:
4 m/s
Explanation:
KE =
Velocity of balloon will be 4 m/s.
!! Hope It Helps !!
what forces are being used when walking a dog and how ?
What is important when it comes to winning
Answer:
satisfaction, enjoyment and fair play
Answer:
It is important to be a good sport, and even if you do not win still be happy about being able to participate, and congratulate the person that did win.
Explanation:
Hope this helped Bye!
A family took a trip in a car traveling East from Greensboro to Wilmington, NC. Use the Graph to answer the questions below.
1: Calculate the average speed of the trip.
2: What was the average velocity of the car?
Note: Please don't put weird stuff or completely off-topic stuff, I really need help for this homework! Thanks!
Answer:
1). Average speed = 1.5 m per second
2). Average velocity = 1.5 m per second
Explanation:
1). Since, speed is a scalar quantity
Therefore, average speed of the trip = [tex]\frac{\text{Total distance covered}}{\text{Total time taken}}[/tex]
From the graph attached,
Total distance covered = 10 + 10 + 20 + 0 + 20 + 30
= 90 meters
Total time taken = 60 seconds
Average speed = [tex]\frac{90}{60}[/tex]
= 1.5 meter per second
2). Velocity is a vector quantity.
Therefore, average velocity = [tex]\frac{\triangle d}{\triangle t}[/tex]
= [tex]\frac{d_{60}-d_0}{60-0}[/tex]
= [tex]\frac{90-0}{60-0}[/tex]
= 1.5 meter per second
The world's longest continuous mountain ridge is under the ocean.
True
False
Please hurry!!!
Answer:
True
Explanation:
Un cuerpo lleva una velocidad de 122k por hora y de golpe frena reduciendo su velocidad a 50km por hora en un instante de tiempo de 4,5 segundos y la fuerza de frenado es de 1200n, ¿cual será su masa?
Answer:
La masa del objeto es 270.027 kilogramos.
Explanation:
Asumamos que el cuerpo decelera a tasa constante, entonces podemos calcularlo por medio de la siguiente ecuación cinemática:
[tex]a = \frac{v-v_{o}}{t}[/tex] (1)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial, en metros por segundo.
[tex]v[/tex] - Velocidad final, en metros por segundo.
[tex]t[/tex] - Tiempo, en segundos.
[tex]a[/tex] - Deceleración, en metros per segundo al cuadrado.
Si sabemos que [tex]v_{o} = 33.889\,\frac{m}{s}[/tex], [tex]v = 13.889\,\frac{m}{s}[/tex] y [tex]t = 4.5\,s[/tex], entonces la deceleración experimentada por el cuerpo es:
[tex]a = \frac{v-v_{o}}{t}[/tex]
[tex]a = -4.444\,\frac{m}{s^{2}}[/tex]
Por las Leyes de Newton, tenemos que la masa del cuerpo se calcula a partir de la siguiente expresión:
[tex]m = \frac{F}{a}[/tex] (2)
Donde:
[tex]m[/tex] - Masa, en kilogramos.
[tex]F[/tex] - Fuerza de frenado, en newtons.
Si sabemos que [tex]F = -1200\,N[/tex] y [tex]a = -4.444\,\frac{m}{s^{2}}[/tex], entonces la masa del cuerpo es:
[tex]m = \frac{F}{a}[/tex]
[tex]m = 270.027\,kg[/tex]
La masa del objeto es 270.027 kilogramos.
Earth is protected from meteorites by... (please help T-T 10 points)
a. the Moon
b. the atmosphere
c. other planets
d. the Sun
g The ant has traveled 10 cm horizontally and 6 cm vertically from its starting point on a twig with a slope of 0.5. If this is the only information the ant has, what function best approximates the geometry of the twig at the point the ant is on? b) The ant can use its model of the environment to plan its movements. In particular, it wants its next step to take it no higher than 0.1 cm above its current location. How far can the ant travel horizontally and still accomplish this?
Answer:
a) a right triangle, b) x = 0.167 m
Explanation:
a) It is asked to find which geometry figure describes the movement of the ant.
Let's use trigonometry with the angles measured in radians
tan θ = y / x
tan θ = 6/10
θ = tan⁻¹ 0.6
θ = 0.54 rad
this value is equal to the upward slope therefore the geometric body that describes the movement is a right triangle
b) it is asked to find the horizontal displacement for a vertical displacement of y = 0.1 cm x = y / tan tea
x = 0.1 / tan 0.54
x = 0.1668 m
x = 0.167 m
Please help with this!! I need help asap!
NO LINKS!!!
Write as if you are teaching someone about lunar phases!
Write one paragraph about lunar phases, act as if you are teaching a person about these lunar phases.
THANK YOU SOOOO MUCH IF YOU CAN ACTUALLY HELP ME!!
Answer:
so a A lunar phase is an angle of the moon to the earth so it appears differently every day. The moon goes through 8 major phases. A new moon is when the moon cannot be seen because we are looking at the unlit half of the Moon. The new moon phase occurs when the Moon is directly between the Earth and Sun. A solar eclipse can only happen at new moon.
Explanation:
hope this helps
11. A sensitive thermometer is one which
A. Is sensitive to heat
B. has large bore
C. can record big changes in temperature
D. can record small changes in temperature
Answer:
A. ls sensitive to heat
this is correct answer
I hope it's helpful for you.......
4. Given that the specific heat of copper is 385J/kg/K and if 81.2J of heat is applied to 17.8g of copper by how much will the temperature of the copper increase?
Answer:
11.85 k
Explanation:
11.85 k
No Links!!!!!!!!!!!!!!!!!!!!!!!!!! Can you guys help me with this? Please :)
Answer:
C and True :)
Explanation:
Hope you got it right!
Which choice Not a direct risk of eating a diet too high in sugar? 1 diabetes 2 weight gain 3 tooth decay 4 weight loss
Answer:
4 weight loss
Explanation: