Answer:
28.4
Explanation:
for those on acellus
The acceleration of the puck is the rate of change in velocity of the puck. The acceleration is obtained as 9.06 m/s².
What is acceleration?Acceleration of an object is its rate of change in velocity. It is a vector quantity, thus, having both magnitude and direction.
The velocity components is given
2.35 m/s in direction of 22° and 6.42 m/s in a direction of 50°.
Thus, initial velocity u = 2.35 cos 22 = 2.17 m/s
final velocity V = 6.42 cos 50 = 4.12 m/s
Hence, the change in velocity = V - U
= 4.12 - 2.17 = 1.95 m/s.
The time change is given ΔT = 0.215 s.
ΔV = 1.95 m/s
Thus, acceleration = ΔV / ΔT
= 1.95 m/s / 0.215 s
= 9.06 m/s².
Therefore, the acceleration of the puck is 9.06 m/s².
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We gonna make the girls dance
I ain't lookin' for enemies
But I ain't playin' n*ce
The way you testing me and look me in the eyes
Want some of my own candy
I love to see you try
Ain't nothing real about the way you look tonight
Answer:
Definition: poem
Explanation:
If a 5 n force is pushing upward on an object what force would need to be applied to create a net force of zero?
Answer:
the foce aplied to make the net force be 0 is 5n force pushing downward on the object becasue it will cancel it out
Explanation:
Sasha lifts a couch 8.2 meters from the ground floor of her house to the attic. If the couch has a mass of 120 kg, what is the gravitational potential energy gained by the couch? Estimate g as 9.81 m/s^2.
Answer:
9653.04 joules
Explanation:
H= 8.2 m
M= 120 kg
G= 9.81 m/s^2
P.E= ?
P.E = MGH
P.E = 120 x 9.81 x 8.2
P.E = 9653.04 joules
What equation do I use?
Answer:
I think it's the 3rd one
If someone tells u somethin else, go for it cause im not 100% sure...
What is an institutional review board? Select one: a. The people who control the qualifications of psychology professors at colleges and universities b. The committee who oversees the ethical treatment of college students. c. The committee who insures ethical treatment of research participants d. An unknown group of Avengers
Answer: The correct option is C (The committee who insures ethical treatment of research participants)
Explanation:
The institute Review Board ( IRB) is a committee that reviews research that involves human beings and approves it once it's of ethical standard. This committee is usually made up of scholars that arefrom various departments who are mandated to review proposals to ensure that they comply with ethical guidelines and write a summary of proposed risks to subjects.
The primary importance of institute Review board is to protect the rights and welfare of human research subjects and to ensure that appropriate steps are taken to protect the rights and welfare of humans participating as subjects in the research, both in advance and by periodic review,
Question 7 of 10
Which three statements describe electromagnetic waves?
A. They can transfer energy through a vacuum.
I B. They vibrate parallel to the direction in which the wave travels.
O C. They vibrate in two directions that are perpendicular to each
other.
D. They radiate outward in all directions.
Answer:
A. They can transfer energy through a vacuum
C. They vibrate in two directions that are perpendicular to each other
D. They radiate outward in all directions
Explanation:
A statement (A), a statement (C), and a statement (D) are correct because electromagnetic waves can only transfer energy through the vacuum.
What is an electromagnetic wave?The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.
The correct statements are:
They can transfer energy through a vacuum.They vibrate in two directions that are perpendicular to each other.They radiate outward in all directions.Thus, a statement (A), a statement (C), and a statement (D) are correct because electromagnetic waves can only transfer energy through the vacuum.
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A piece of wood 400N in weight and 50cm X 30cm X 20cm in size lies on 50cm X 20cm face. Calculate the pressure exerted by it.
Answer:
P = 4000 [Pa]
Explanation:
Pressure is defined as the relationship between Force and the area where the body rests.
The support area is equal to:
[tex]A=50*20=1000[cm^{2} ][/tex]
But we must convert from square centimeters to square meters.
[tex]1000[cm^{2}]*\frac{1^{2}m^{2} }{100^{2}m^{2} }=0.1[m^{2} ][/tex]
And the pressure is:
[tex]P=\frac{F}{A} \\P=400/0.1\\P=4000[N/m^{2} ]or 4000[Pa][/tex]
18)
Swimmers speed along the river (downstream) is 20km/hr
and can swim Cupstream) at 8km lhr. calculate the
velocity of the stream and the swimmer's possible
speed in still water,
Answer:
The speed of the stream is 6 km/h and the speed of the swimmers in still water is 14 Km/h
Explanation:
Relative Speeds
When swimming downstream, the velocity (speed, really) of the stream (Vs) and the speed of the swimmers (Vm) are collaborative. When swimming upstream the speed of the stream subtracts to the speed of the swimmers, thus:
Vm + Vs = 20
Vm - Vs = 8
Adding both equations:
2Vm = 28
Vm = 28/2 = 14
From the first equation:
Vs = 20 - Vm = 20 - 14 = 6
The speed of the stream is 6 km/h and the speed of the swimmers in still water is 14 Km/h
A cheap effective and simple way to help body recover is to get adequate amounts of. ?
A cheap effective and simple way to help the body recover is to get adequate amounts of sleep, as our body need rest to reduce the tiredness and physical as well as mental stress in our human system.
What is exercise?Exercise is the activity that includes the physical movements of the body and results in fitness, wellness, and healthiness of the person to protect and lower the risks of getting diseases. It allows the person to maintain a healthy weight.
Getting enough sleep is an easy, affordable technique to aid in the body's recovery. Resting our bodies helps our minds and bodies recuperate from fatigue and physical and emotional stress.
Thus, an adequate amount of sleep is one of the effective ways to help the body recover.
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PLEASE HELP ASAP ILL GIVE U BRAINLIEST
An object is pulled to the left by a force of 100 N and to the right by a force of
80N. What is the net force acting on the object?
Answer: 20 N
Explanation: Net force is the sum of all forces acting on an object. For example, in a tag of war, when one team is pulling the tag with a force of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).
If an area has high air pressure and low humidity, what type of weather will it most likely have?
Answer:
c
Explanation:
Calculate the momentum of a 5 kg ball in free fall at 20 m/s. Show your work.
Answer:
100kgm/s
Step by step solution:
mass(m) = 5kg
Initial velocity (u) = 0
i.e u = 0 for free fall
Final velocity (v) = 20m/s
Momentum = m(v - u)
= 5(20 - 0)
= 5(20) = 100kgm/s.
Answer:
[tex]\boxed {\boxed {\sf 100 \ kg*m/s}}[/tex]
Explanation:
Momentum can be found using the following formula.
[tex]p=mv[/tex]
where p is the momentum, m is the mass, and v is the velocity.
1. Define Variables
The mass is 5 kilograms and the velocity is 20 meters per second.
[tex]m= 5 \ kg \\v= 20 \ m/s[/tex]
2. Calculate Momentum
Substitute the values into the formula.
[tex]p= 5 \ kg * 20 \ m/s[/tex]
Multiply.
[tex]p= 100 \ kg*m/s[/tex]
The momentum of the ball is 100 kilograms meters per second.
A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it exert on the track
Answer:
[tex]46620\ \text{N}[/tex]
Explanation:
m = Mass of roller coaster = 2000 kg
r = Radius of loop = 24 m
v = Velocity of roller coaster = 18 m/s
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Normal force at the point will be
[tex]N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}[/tex]
The force exerted on the track is [tex]46620\ \text{N}[/tex].
Two cylinders A&B at the same temperature contains the same quantity of the same kind of gas. Cylinder A has three times the volume of cylinder B. What can you conclude about the pressure the gases exert
Answer:
pressure in cylinder A must be one third of pressure in cylinder B
Explanation:
We are told that the temperature and quantity of the gases in the 2 cylinders are same.
Thus, number of moles and temperature will be the same for both cylinders.
To this effect we will use the formula for ideal gas equation which is;
PV = nRT
Where;
P is prrssure
V is volume
n is number of moles
T is temperature
R is gas constant
We are told that Cylinder A has three times the volume of cylinder .
Thus;
V_a = 3V_b
For cylinder A;
Pressure = P_a
Volume = 3V_b
Number of moles = n
Thus;
P_a × 3V_b = nRT
For cylinder B;
Pressure = P_b
Volume = V_b
Number of moles = n
Thus,
P_b × V_b = nRT
Combining the equations for both cylinders, we have;
P_a × 3V_b = P_b × V_b
V_b will cancel out to give;
3P_a = P_b
Divide both sides by 3 to get;
P_a = ⅓P_b
Thus, pressure in cylinder A must be one third of pressure in cylinder B
A 10 g bullet accelerates to 400 m/s after being fired from a gun with a mass of 2.0 kg.
(i) What is the momentum of the bullet?
(ii) What is the momentum of the gun?
(iii) What is the velocity of the recoiling gun?
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, and can be calculated by means of the following expression.
[tex]P=m*v[/tex]
where:
P = Momentum [kg*m/s]
m = mass = 10 [g] = 0.01 [kg]
v = velocity = 400 [m/s]
i)
[tex]P=0.01*400\\P=4[kg*m/s][/tex]
ii)
The momentum of the gun is equal to zero, because it does not move before being fired, the weapon only moves after having fired the weapon.
[tex]P_{gun}=0[/tex]
iii)
Since the momentum is conserved before and after the shot, the same momentum given to the bullet is equal to the momentum received by the gun.
[tex]P=m*v_{recoil}[/tex]
[tex]v_{recoil}=P/m\\v_{recoil}= 4/2\\v_{recoil}=2[m/s][/tex]
The acceleration due to gravity is zero at the
Answer:
the center of the earth
A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13kg-m/s directed 55 degrees to the left of its initial direction as shown below. What is the momentum (magnitude and direction) of the pin's resultant velocity?
Answer:
[tex]14.98\ \text{kg m/s}[/tex]
[tex]45.26^{\circ}[/tex]
Explanation:
[tex]P_1[/tex] = Initial momentum of the pin = 13 kg m/s
[tex]P_i[/tex] = Initial momentum of the ball = 18 kg m/s
[tex]P_2[/tex] = Momentum of the ball after hit
[tex]55^{\circ}[/tex] = Angle ball makes with the horizontal after hitting the pin
[tex]\theta[/tex] = Angle the pin makes with the horizotal after getting hit by the ball
Momentum in the x direction
[tex]P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}[/tex]
Momentum in the y direction
[tex]P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}[/tex]
[tex](P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}[/tex]
The pin's resultant velocity is [tex]14.98\ \text{kg m/s}[/tex]
[tex]P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}[/tex]
The pin's resultant direction is [tex]45.26^{\circ}[/tex] below the horizontal or to the right.
The megnitude and the direction of the resultant velocity of the pin willl be 14.98 Kgm/sec and 45.26° below the horizontal or to the right.
What is momentum?The momentum is defined as the product of mass and the velocity of the body. It is denoted by the letter P. It occurs due to the applied force. Its unit is Kg m/s².
The given data in the problem is;
P₁ is the initial momentum of the pin = 13 kg m/s
[tex]\rm p_i[/tex] is the initial momentum of the ball = 18 kg m/s
P₂ is the momentum of the ball after hit
[tex]\rm \theta[/tex] is the angle the pin makes with the horizotal after getting hit by the ball
Momentum in x direction;
[tex]\rm P_i= P_1 cos \theta + P_2 cos \theta \\\\ P_2cos \theta = P_i -P_i cos 55^0 \\\\ P_2cos \theta = 10.54 \ Kgm/s[/tex]
Momentum in y direction;
[tex]\rm P_i sin\theta = P_2 sin\theta \\\\ P_2 sin\theta =13 sin 15^0 \\\\ P_2 sin\theta =10.64 \ kgm/sec[/tex]
[tex](P_2 cos \theta )^2 + (P_2 sin \theta)^2 = P_2^2 \\\\ \rm P_2 = \sqrt{(10.54)^} +(10.64)^2[/tex]
[tex]\rm P_2 = 14.98 \ kgm/sec[/tex]
The direction of the resulatnt velocity is find as;
[tex]P_2 sin\theta = 10.64 \\\\ \theta = sin^{-1 } \frac{10.64}{14.98} \\\\ \theta=45.26^0[/tex]
Hence the megnitude and the direction of the resultant velocity of the pin willl be 14.98 Kgm/sec and 45.26° below the horizontal or to the right.
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pLS ANSWER FAST WILL MARK BRAINLIEST
In position A
The mirror has to be observed in the ray reflected from the mirror.
Since the the angle of reflection is equal to the angle of incidence, the reflected ray must be in equal path as the incident ray.
That phenomenon is only in diagram A
Nuclear power plants produce a waste product of cesium-137, which has a half-life of 30 years. How long would it take for the cesium to decay to 1/8 of its original amount?
90 years
120 years
30 years
60 years
Why is it an advantage to the beef
producer that beef cattle are foragers?
A. The cattle can graze for grain to eat.
B. It reduces labor as long as there is a good supply of
grasses.
C. The beef will grow much faster with an abundance of
food.
D. It helps to make the herd more fertile.
what is meaning of forages
It reduces labor as long as there is a good supply of grasses. Therefore, option B is correct.
What are the advantages of beef production?Ruminants are unique animals that are classified as such. This indicates that their stomach has four distinct components and is particularly built. The several compartments aid in the digestion of the lignin and cellulose found in the plants they consume. The energy can be converted by cattle in a way that is not possible for humans.
Numerous additional by-products from cattle are also available to us. These include sections of the cow that are utilized to create goods for the house, body, food, and industry. Other than beef, byproducts are goods with added value that come from cattle.
The claim that land for beef cattle may be used for other crops for human use is one that is frequently made. This is not totally accurate, though, as beef cattle live a large portion of their lives on forage-based systems. If not utilized for grazing, forages are often cultivated on land that is unsuitable for other high-value crops and would be regarded as a land of marginal use.
Thus, option B is correct.
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In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the string. Question 1 options: 5 cm 10 cm 15 cm 20 cm
Answer:
5 cm
Explanation:
Engineers were planning to install decorative columns made of marble, of density 2560kg/m cubed, in front of a building. The columns were 2.72m tall and of radius 45 cm
a) Calculate the mass of column
ii) Calculate the pressure exerted by each column on the ground
iii) Engineers found out that the ground beneath the columns would not withstand the pressure calculated in c(ii). Suggest 1 possible change to each column, the engineers do , to solve this problem
Answer:
See the answers below.
Explanation:
We must apply the definition of density which is the ratio of mass to volume.
[tex]Ro=m/v[/tex]
where:
Ro = density = 2560 [kg/m³]
m = mass [kg]
v = volume [m³]
With the column height data and column radius we can calculate the volume, since it resembles the volume of a cylinder. In this way the volume of a cylinder is defined by the following expression.
[tex]V=\pi *r^{2}*h[/tex]
where:
r = radius = 45 [cm] = 0.45 [m]
h = height = 2.72 [m]
[tex]V = \pi *(0.45)^{2}*2.72 \\V = 1.73 [m^{3} ][/tex]
a)
The mass can be calculated as follows.
[tex]m=Ro*V\\m=2560*1.73\\m= 4428.8 [kg][/tex]
ii)
Pressure is defined as the relationship of force over an area.
The area can be calculated with the radius of the cylinder.
[tex]A=\pi *r^{2}\\A = \pi *(0.45)^{2}\\A = 0.636 [m^{2} ][/tex]
Therefore
[tex]P=F/A\\where:\\F=m*g\\F=4428.8*9.81\\F=43446.53[N][/tex]
[tex]P=43446.53/0.636\\P=68312.15[Pa]\\P=68.31[kPa][/tex]
iii)
If the pressure is very large we must analyze the pressure equation again.
[tex]P=\frac{F}{A}[/tex]
We can see that the pressure depends on the strength (weight) and the area of the column. In this way if we increase the value of the area (denominator) we see that the pressure decreases.
If the new Radius is 50 [cm] = 0.5 [m]
[tex]A=\pi *(0.5)^{2}\\A = 0.785 [m^{2} ][/tex]
Now we can calculate again the pressure.
[tex]P=43446.53/0.785\\P=55317.84[Pa]=55.32[kPa][/tex]
We can see the reduction in pressure.
how does area affect pressure?
Answer:
???????????????? Tell me also
Answer:
Area is inversely proportional to pressure.
Explanation:
✍ Lesser the area, higher the pressure.
✍ More the area, lower the pressure.
Thank You
If you liked the answer then, plzz.. mark as BRAINLIEST...An airplane flying at 57 m/s releases a crate of supplies that lands 821 m from where it was released. How high was the plane flying?
1020 m
14.4 m
71 m
5910 m
Answer:1020
Explanation:
Why are we unable to work long without food
Answer:
Without food your not able to produce energy thats why you cannot work so long
a communication satellite is stationed in an orbit high abovr the earth. which of the follwoing will not be exhibeted by communication satellites.
a) rotational motion and periodic motion
b) periodic motion and circular motion
c) rotational motion and rectilinear motion
d) periodic motion and oscillatory motion
i) A and B
ii) B and C
iii) A only
iv) D only
Pls help
Answer:
i think ii)
B and c
i'm note sure though
Two sound waves, from two different sources with the same frequency, 540 Hz, travel in the same direction at 330 m s . The sources are in phase. What is the phase difference of the waves at a point that is 4.40 m from one source and 4.00 m from the other?
Answer:
The value is [tex]\Delta \phi = 4.12 \ rad[/tex]
Explanation:
From the question we are told that
The frequency of each sound is [tex]f_1 = f_2 = f = 540 \ Hz[/tex]
The speed of the sounds is [tex]v = 330 \ m/s[/tex]
The distance of the first source from the point considered is [tex]a = 4.40 \ m[/tex]
The distance of the second source from the point considered is [tex]b = 4.00 \ m[/tex]
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
[tex]\phi_a = 2 \pi [\frac{a}{\lambda} + ft][/tex]
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
[tex]\phi_b = 2 \pi [\frac{b}{\lambda} + ft][/tex]
Here b is the distance o f the first wave from the considered point
Gnerally the phase diffencence is mathematically represented as
[tex]\Delta \phi= \phi_a - \phi_b = 2 \pi [\frac{ a}{\lambda} + ft ] - 2 \pi [\frac{b}{\lambda} + ft ][/tex]
=> [tex]\Delta \phi = \frac{2\pi [ a - b]}{ \lambda }[/tex]
Gnerally the wavelength is mathematically represented as
[tex]\lambda = \frac{v}{f}[/tex]
=> [tex]\lambda = \frac{330}{540}[/tex]
=> [tex]\lambda = 0.611 \ m[/tex]
=> [tex]\Delta \phi = \frac{2* 3.142 [ 4.40 - 4.0 ]}{ 0.611 }[/tex]
=> [tex]\Delta \phi = 4.12 \ rad[/tex]
A student walks the hallway for 25 m stops to talk and continues down the hallway another 10 m what is the distance and displacement
Answer:
Distance = displacement = 35m
Explanation:
The distance of the student is how far he has gone.
Distance = 25m + 10m
Distance = 35m
Displacement is the distance specified in specific direction. Since the student walk in the sane direction, thence the displacement is also 35m
A 15.0-kg block is dragged over a rough, horizontal surface by a 70.0-N force acting at 20.0° above the horizontal. The block is displaced 5.00 m, and the coefficient of kinetic friction is 0.300. Find the work done on the block by a) The 70-N force, b) The normal force, and c) The gravitational force. D) What is the increase in internal energy of the block-surface system due to friction? E) Find the total change in the block's kinetic energy.
Answer:
Explanation:
from the question we are told that
Load [tex]L=15kg[/tex]
Force[tex]F=70N[/tex]
Angle of inclination [tex]=20.0 degres[/tex]
Displacement [tex]m=5 meters[/tex]
coefficient of kinetic friction [tex]\alpha =0.300[/tex]
Before Freddy lands on the skateboard it has a certain momentum. After landing, the skateboards momentum
Answer:
remains the same
Explanation:
Momentum refers to the quantity of motion of a body. When any body of mass moves, it possess momentum. Numerically,
Momentum = mass x velocity
i.e. momentum is the product of the mass x velocity
Momentum of a body is always conserved.
In the context, the skateboard has certain momentum before Freddy lands on it. After Freddy lands, the momentum of skateboard remains the same, there is no change in the momentum.
This is because, here the momentum is conserved. After Freddy lands on the skateboard, the total mass on the skateboard increases and so the velocity decreases making the momentum same before the landing.