The initial speed of the proton that is projected in the positive x direction into a region of a uniform electric field is 2.84×〖10〗^6 m/s
The equation of motions expresses the speed of an object with initial velocity u, final velocity v, and distance s, as;
v^2= u^2+2 a.s
Making u the subject of the formula,
u^2= -2 a.s
Given that:
a=5.76×〖10〗^13 m/s^2
s =7.00cm or 0.07m
Inserting values,
u^2= -2 ×(-5.76×〖10〗^13 m/s^2)×0.07m
u^2=8.06×〖10〗^12 m^2/s^2
Therefore,
u= √8.06×〖10〗^12 m^2/s^2
u=2.84×〖10〗^6 m/s
Therefore, the initial speed of the proton is 2.84×〖10〗^6 m/s
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how long will it take the bird to cover a ground distance of 550 km from north to south? (note that even on cloudy nights, many birds can navigate using the earth's magnetic field to fix the north-south direction.)
The direction of the bird's velocity can be adjusted so that the wind and the resulting bird velocity will both be in the southerly direction.
(a) The bird should fly at an angle of roughly South 23.58° East if it wants to move directly southward in relation to the earth.
(b) The bird would need around 5.46 hours to fly 500 kilometres from North to South.
The components of the velocity are v(x) and v(y).
The magnitude of the velocity of the bird is 100 km/h
The orientation of the bird corresponds to that of North and South.
The magnitude of the velocity of the wind is 40 km/h
East-west is the direction of the wind.
(a) The component vector of the two velocities are;
The velocity of the bird, v(y) = -100(j)
The velocity of wind, v(x) = 40(i)
If the bird has a component of velocity to accommodate the wind velocity, the direction of its movement will be southerly.
Let θ be the angle of the direction of the bird relative to the negative x-axis, therefore:
-100(j) × cos(θ) = -40·i
θ = cos⁻¹(40/100)
θ ≈ 66.42° in the third quadrat, given that both the y, and x, values are negative.
In the South-West direction, the angle is:
90 - 66.42 ≈ 23.58°
Therefore, to fly directly southward relative to the ground, the bird should fly in the direction of south 23.58° east.
(b) The following is given as the component of the bird's southerly velocity when traveling in the new direction:
v(s) = 100 × sin(θ)
Hence,
Southward velocity, v(s) = 100 × sin(66.42°)
The time t it takes to travel 500 km, is given as:
d = v(s)t
500 = 100 × sin(66.42°)(t)
t = 5.46 hrs
The bird would need 5.46 hours to fly 500 kilometres from North to South.
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The complete question is mentioned below:
Canada geese migrate essentially along a north–south direction for well over a thousand kilometres in some cases, traveling at speeds up to about 100 km/h. If one goose is flying at 100 km/h relative to the air but a 40-km/h wind is blowing from west to east,
(a) at what angle relative to the north–south direction should this bird head to travel directly southward relative to the ground?
(b) How long will it take the goose to cover a ground distance of 500 km from north to south? (Even on cloudy nights, many birds can navigate by using the earth’s magnetic field to fix the north–south direction.)
An electron has a speed of 0.750 c .(b) What If? Find the speed of a proton that has the same momentum as the electron.
By relativistic momentum, the proton speed is 1.93 x 10⁵ m/s.
We need to know about relativistic momentum to solve this problem. The rest energy of the object can be determined by
P = m₀ . v/ √(1 - v²/c²)
where P is relativistic momentum, m₀ is rest mass, c is speed of light (3 x 10⁸ m/s) and v is speed of object.
From the question above, we know that :
mp = 1.6 x 10¯²⁷ kg
me = 9.1 x 10¯³¹ kg
c = 3 x 10⁸ m/s
ve = 0.75c
Find the relativistic momentum of electron
P = me . ve/ √(1 - ve²/c²)
P = 9.1 x 10¯³¹ . 0.75c / √(1 - (0.75c)²/c²)
P = 2.0475 x 10¯²² / 0.66
P = 3.1 x 10¯²² kg.m/s
Find the speed of proton
P = mp . vp/ √(1 - vp²/c²)
3.1 x 10¯²² = 1.6 x 10¯²⁷ . vp / √(1 - vp²/c²)
vp = 193892.05 x √(1 - vp²/c²)
squared
vp² = 3.76 x10¹⁰ - 3.76 x10¹⁰vp²/c²
(1 + 3.76 x10¹⁰/c²) vp² = 3.76 x10¹⁰
(1.0) vp² = 3.76 x10¹⁰
vp = √(3.76 x10¹⁰)
vp = 1.93 x 10⁵ m/s
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a man jogs at a speed of 1.5 m/s. his dog waits 2.5 s and then takes off running at a speed of 3.3 m/s to catch the man. how far will they have each traveled when the dog catches up with the man?
By the velocity, they will travel 6.875 m and the dog catches the man at 2.08s.
We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as
v = s / t
where v is velocity, s is distance and t is the time interval.
From the question above, we know that.
v man = 1.5 m/s
v dog = 3.3 m/s
to = 2.5s
Determine the distance traveled by man when the dog waits
so = vman . to
so = 1.5 x 2.5 = 3.75 m
Find the man's total distance
total distance = distance after dog run + distance when the dog waits
total distance = vman . t + 3.75
We know that the total distance by man's will be caught by the dog, Thus
total distance = vman . t + 3.75
v dog . t = 1.5t + 3.75
3.3t = 1.5t + 3.75
1.8t = 3.75
t = 2.08 s
Find total distance
total distance = vdog . t
total distance = 3.3 x 2.08
total distance = 6.875 m
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2x²-y if x =3 and y = 8
Answer:
10
Explanation:
2*3^2-8
2*9-8
18-8
10
A student looks up an element on the periodic table. The table says that the atomic number of the element is 12 and the mass number of the element is 40. What information do these two numbers convey about the element? a The element has 40 protons and 12 neutrons b The element has 12 protons and 12 neutrons c The element has 12 protons and has 28 neutrons d The element has 28 protons and 40 neutrons
If the table says that the atomic number of the element is 12 and the mass number of the element is 40, then the element has 12 protons and 28 neutrons, therefore the correct answer is option C.
What is atomic mass?It is the sum of the mass of all the protons as well as the neutrons that are present inside the nucleus.
The addition of protons and neutrons represents the mass number of any element.
The mass number of any element is the sum of the number of protons and the number of neutrons, therefore the correct answer is option C.
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Tech A says that pushing on the brake pedal stops the vehicle by converting chemical energy into thermal
energy. Tech B says that brake pedal pressure is transmitted to the brakes hydraulically. Who is correct?
Tech B is correct. The brake pedal pressure is transmitted to the brakes hydraulically.
How does brake pedal stop a vehicle?The energy of the pads clamping against the rotors and brake shoes pushing against drums generates friction and heat.
This heat-friction, along with friction generated between the tire and road surface, slows rotor and axle rotation and ultimately brings the car to a stop.
Thus, Tech B is correct. The brake pedal pressure is transmitted to the brakes hydraulically.
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a wheel with a radius of 45.0 cm rolls without slipping along a horizontal floor (fig. 3-37). at time t 1 the dot p painted on the rim of the wheel is at the point of contact between the wheel and the floor. at a later time t 2 the wheels has rolled through one-half of a revolution. what are (a) the magnitude and (b) the angle (relative to the floor) of the displacement of p?
The magnitude is 167.6cm and the angle (relative to the floor) of the displacement of p is 32.5 degree.
What is displacement ?
A displacement is a vector in geometry and mechanics that has a length equal to the shortest distance between a point P's initial and final positions. It calculates the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement.
A point's ultimate location in relation to its original position, or a displacement, can also be defined as a relative position. The instantaneous velocity of an object is the rate at which the displacement changes as a function of time when studying motions of objects throughout time.
Explanation:
a)
height = 2*r =2*45 cm = 90 cm
y = 1/2 * circumference
=1/2 * 2*pi*r
= pi*r
= pi*45
= 141.4 cm
displacement =sqrt ( height^2 + y^2)
= sqrt (90^2 + 141.4^2)
= 167.6 cm
Answer: 167.6 cm
b)
angle ,x = atan (height/y)
= atan (90/141.4)
= 32.5 degree
Answer: 32.5 degree
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An object of known mass that can be used to establish uncertainty in measurements made with a balance is best described as a.
Answer:
standard
Explanation:
we sometimes use weights of known mass to balance with an object of unknown mass to determine that objects weight.
A wire carrying a current I is bent into the shape of an equilateral triangle of side L. (b) At a point halfway between the center and any vertex, is the field stronger or weaker than at the center? Give a qualitative argument for your answer.
At a point halfway between the center and any vertex, the field is stronger.
An equilateral triangle with side L is formed by the bend of a wire carrying a current I.
The magnetic field created by a straight wire is given as:
[tex]B = \frac{ \mu_{0} I}{2 \pi a}[/tex]
The cosines of the complementary angles are identical to the sines of the angles that appear in that equation.
For the distance "a" from the wire to the field point,
We obtain:
[tex]tan{~}30^{\circ} = \frac{a}{L/2}\\a = 0.2887L[/tex]
We have one whole side of the triangle that generates a magnetic field at the center of the triangle is [tex](\frac{ \mu_{0} I(1.732)}{4 \pi a} )[/tex].
Now, the near side of a triangle will be at a geometrically equivalent location and will be half as far from point P(b).
Then the field at P(b) is:
[tex](\frac{ \mu_{0} I(1.732)}{4 \pi a} )= \frac{2 \mu_{0} I (1.732)}{4 \pi a}[/tex]
A P(b) field is created by the two half-sides that are cross-hatched which is:
[tex]2(\frac{2 \mu_{0} I(1.732)}{4 \pi a} )= \frac{4 \mu_{0} I (1.732)}{4 \pi (0.2887L)}=\frac{6 \mu_{0} I}{ \pi L}[/tex]
We already have evidence that the field at P(b) is stronger because the remaining triangle will contribute a little bit more field in the same direction.
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Please identify what is the force indicated at the “X” and what would happen if “X” is greater than the pushing force in the diagram? Make sure to include (Quote and define the force at “X”)
Answer:
X is frictional force
Explanation:
when X is greater than pushing force,the object won't move
The correct answer for the nature of force at "X" is frictional force.
What is friction force?
Friction or frictional force is the force that acts when two surface comes in contact with each other. When a body A is resting upon a body B, The force that helps the body to maintain the equilibrium position is static friction.
Kinetic friction slows down a moving object, when their is relative motion between two objects. It always acts in apposite direction to the force applied.
It is denoted by [tex]F[/tex].
The formula to calculate static friction is [tex]F = \mu N[/tex]
[tex]\mu_s =[/tex] Co-efficient of static friction
[tex]\mu_k =[/tex] Co-efficient of Kinematic friction.
The Force indicated at "X" is "Kinetic friction", It will slow down the moving object.
When "X" is greater than the moving object, the object will stop moving and will remain at rest.
The Force Indicated at "X" is Frictional force.
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to find the masses of both stars in a binary system, you must find the of each star, the of the orbit, and the average between the stars.
To find the masses of both stars in a binary system, you must find the velocity of each star, the period of the orbit, and the average distance between the stars.
The displacement covered by an object in the unit of time is called velocity.
The formula of velocity is v = d/t and its dimensions are LT-1.
A unit of time in which a particle or object passes through a point to complete its one cycle is called a period. It is related to time.
The time-period is denoted by T and the formula is T = 2 π√ l / g.
In physics, distance is a vector quantity without any direction. It can be calculated as distance = speed x time i.e. d = v.t
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A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpendicular to the proton's velocity. It leaves the field-filled region with velocity -20.0j Mm/s. Determine(b) the radius of curvature of the proton's path while in the field.
The radius of curvature of the proton's path while in the field is [tex]66.67[/tex] × [tex]10^{-2}[/tex].
b) Let R = radius curvature of protons path. Then,
relation b/w B, R, and v is: -
[tex]B = mv/eR\\R=mv/eB[/tex]
[tex]R=\frac{1.6*10^{-27} * 20*10^{6}}{1.6*10^{-19}*0.3 }[/tex]
[tex]R =66.67[/tex]× [tex]10^{-2}[/tex]
Hence, the radius of curvature of the proton's path while in the field is [tex]66.67[/tex] × [tex]10^{-2}[/tex].
What do you mean by Magnetic field?The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things.
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PLEASE HELP ME!
as your friend skateboards down a hill, you measure their velocity at 1.0-second intervals. you record the following data: (0.0 s, 0.0m/s), (1.0 s, 2.3 m/s), (2.0 s, 4.6 m/s). Determine your friends acceleration.
Answer:
Explanation:
it should be 3.2 m/s^2
The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.
What is acceleration?Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
A moving object can occasionally alter its velocity by the same amount every second. The data table above depicts an item altering its velocity by 10 m/s every second, as was described in the paragraph above. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration.
Therefore, The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.
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A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
What is the gravitational force on the box?
The gravitational force on the box is 580N.
How to illustrate the information?It should be noted that the gravitational force acts perpendicularly downwards and the normal force of the box is perpendicular to the slanting ramp. This force we are given 538 N.
The gravitational force is the component of this 538 N.
In this case, Cos22° = 538/Y
Where
y = the gravitational force.
Cos22° = 538/Y
Y× Cos22° = 538
Y = 538/Cos22°
= 580.25
Therefore, the gravitational force on the box is 580N.
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A fireworks shell is accelerated from rest to a velocity of 65.0 m/s over a distance of 0.250 m. (a) How long did the acceleration last? (b) Calculate the acceleration.
The acceleration lasts 0.0077 seconds and is equivalent to 8450 m/s².
The rate at which an object's position changes with respect to time is defined as velocity.
Because it consist of both magnitude and direction, it is a vector quantity. Speed is a scalar quantity that represents the magnitude of velocity. The SI unit of velocity and speed is m/s.
Acceleration is the measure of how quickly a velocity varies over time. It is also a vector quantity. A negative sign of acceleration indicates that the velocity of the body is decreasing with time.
Given in the question
Initial speed = u = 0 m/s ( as the firework starts from rest)
Final velocity = v = 65 m/s
Distance traveled = 0.25 m
B) Acceleration
Using the third equation of motion,
[tex]v^{2} -u^{2} =2as[/tex]
Put in the value, we get
(65)² - (0)² = 2a(0.250)
0.5a = 4225
a = 8450 m/s²
As a result, fireworks accelerate at 8450 m/s².
A) Time the acceleration lasts
Acceleration is calculated as (Final Velocity - Initial Velocity)/Time.
Put in the values, we get
8450 = 65/time
Time = 65/8450
Time = 0.0077 seconds
Hence, the acceleration lasts for 0.0077 seconds and is 8450 m/s².
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Balboa Park in San Diego has an outdoor organ. When the air temperature increases, the fundamental frequency of one of the organ pipes (a) stays the same, (b) goes down, (c) goes up, or (d) is impossible to determine.
(c) The fundamental frequency of one of the organ pipes will go up or increase.
When pressured air is forced into an organ pipe, it echoes at a particular pitch, generating the sound of the pipe organ. Each pipe has been adjusted to a particular pitch on the musical scale.
An outdoor pipe organ is a type of musical instrument used to perform music. It sounds quite serene and produces some calming tones.
The organ pipe produces the sound of the outdoor organ. The wavelength of the sound is also dependent on the length of the pipe. The fundamental frequency of one of the organ pipes will grow as the speed of the sound increases as the ambient air temperature rises.
The correct option is (c).
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Rank the magnitudes of the following magnetic fields from largest to smallest, noting any cases of equality. (a) the field 2cm away from a long, straight wire carrying a current of 3 A (b) the field at the center of a flat, compact, circular coil, 2cm in radius, with 10 turns, carrying a current of 0.3 A (c) the field at the center of a solenoid 2 cm in radius and 200 cm long, with 1000 turns, carrying a current of 0.3A (d) the field at the center of a long, straight, metal bar, 2 cm in radius, carrying a current of 300 A (e) a field of 1 mT
Magnitude of the magnetic fields from largest to smallest is,
[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]
We know that,
[tex]Permeability\;of\;free\;space,\;\mu_{0} = 4 \times \pi \times 10^{-7}\;H/m\\[/tex]
[tex]l=length[/tex]
[tex]I=current[/tex]
(a)
[tex]Radial\;distance,\;r = 2\;cm=0.02\;m[/tex]
[tex]Current,\;I = 3\;A[/tex]
We know that, Magnetic equation,
[tex]B_{a} =\frac{\mu_{0} \times I}{2\times \pi\times r}[/tex]
Substitute the known values in the above magnetic field equation,
[tex]B_{a}=\frac{4 \times \pi \times 10^{-7} \times 3}{2\times \pi\times 0.02}[/tex]
By solving the equation, we get
[tex]B_{a}=3 \times 10^{-5}\;T[/tex]
(b)
[tex]Radius\;of\;the\;coil,\;r = 0.02\;m[/tex]
[tex]Number\;of\;turns,\;N = 10[/tex]
[tex]Current,\;I = 0.3\;A[/tex]
We know that, Magnetic equation,
[tex]B_{b} =\frac{\mu_{0} \times N \times I}{2\times r}[/tex]
Substitute the known values in the above magnetic field equation,
[tex]B_{b}=\frac{4 \times \pi \times 10^{-7} \times 10 \times 0.3}{2 \times 0.02}[/tex]
By solving the equation, we get
[tex]B_{b}=9.425 \times 10^{-5}\;T[/tex]
(C)
[tex]Length\;of\;the\;solenoid,\;l = 2\;m[/tex]
[tex]Number\;of\;turns,\;N = 1000[/tex]
[tex]Current,\;I = 0.3\;A[/tex]
We know that, Magnetic equation,
[tex]B_{c} =\frac{\mu_{0} \times N \times I}{l}[/tex]
Substitute the known values in the above magnetic field equation,
[tex]B_{c}=\frac{4 \times \pi \times 10^{-7} \times 1000 \times 0.3}{2}[/tex]
By solving the equation, we get
[tex]B_{c}=18.85 \times 10^{-5}\;T[/tex]
(d)
[tex]Current\;through\;the\;bar,\;I = 300\;A[/tex]
At the center of the conductor if we consider an Amperian loop of zero radius, no current will be enclosed by this loop.
Hence, At the center of the conductor magnetic field will be zero
[tex]B_{d}=0[/tex]
(e)
[tex]1 mT=1 \times 10^{-3}[/tex]
Therefore,
[tex]B_{e}=1 \times 10^{-3}\;T[/tex]
Therefore, Magnitude of the magnetic fields from largest to smallest is,
[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]
What is permeability?When placed inside a magnetic field, a material's permeability—which is defined as the number of magnetic lines of force that may pass through a specific surface—allows magnetic flux to pass through it.
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please help meeeeeeeee
when an object that is moving slows down, which action must be occurring? unbalanced forces unbalanced forces frictional force frictional force gravity gravity balanced forces balanced forces
When a moving thing slows down, gravity action must be taking place on the object.
What is gravity?
Every item is subject to the gravitational pull of the earth, which pulls everything in the atmosphere toward the planet's surface.
Since there is no gravity nor a vacuum in space, the only reason the item is traveling is due to the attraction of the earth's gravitational field.
Therefore, when an item slows down while in motion, gravitational force must be at work. The moon's gravitational pull causes ocean tides, and on Earth, gravity gives weight to physical objects. Additionally, gravity is a key factor in a variety of biological processes, such as gravitropism, which controls plant development, and the fluid movement in multicellular organisms.
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A driver travels northbound on a highway at a speed of 25.0v m/s. A police car, traveling southbound at a speed of 40.0 m/s , approaches with its siren producing sound at a frequency of 2500 Hz. . (b) What frequency does the driver detect after the police car passes him?
The frequency that the driver detects after the police car passes him is 2.08 kHz.
What do you mean by the frequency?The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 per hour if it takes 1/100 of an hour. Frequency is typically expressed in hertz units, which were created in honor of German physicist Heinrich Rudolf Hertz in the 19th century. The frequency, abbreviated as Hz, refers to the number of waves that move across a space in a second. An "A" note on a violin string, for instance, vibrates at roughly 440 Hz (440 vibrations per second).
frequency = 1/T
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A rock is initially launched from ground level vertically reaching its highest point 4.2 seconds after being launched. Calculate the initial velocity of the rock, to the nearest 100th, as the rock is launched. Calculate the maximum height of the rock to the nearest 10th.
The initial velocity with which the rock was launched is 41.16 m/s and the maximum height achieved by the rock is 86.4 m.
State three equations of motion.The three equations of motion are -
v = u + at
S = ut + 1/2 at²
v² - u² = 2aS
Given is a rock launched from ground vertically upwards reaching its highest point after 4.2 s of being launched. Therefore, we can write -
Time taken to achieve maximum height [t] = 4.2 sec
Acceleration [a] = - 9.8 m/s²
Assume that the initial velocity is u.
Therefore - at maximum height S[max], t = 4.2 s
Now, at maximum height, final velocity (v) will be zero.
From the first equation of motion -
v = u + at
0 = u - gt
u = gt
u = 9.8 x 4.2
u = 41.16 m/s
The initial velocity of rock was 41.16 m/s.
The maximum height achieved by the rock -
S[max] = ut + 1/2 at²
S[max] = 41.16 x 4.2 - 0.5 x 9.8 x 4.2 x 4.2 = 172.87 - 86.44 = 86.4 m
Therefore, the initial velocity with which the rock was launched is 41.16 m/s and the maximum height achieved by the rock is 86.4 m.
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drag each tile to the correct box. identify the type of scientific knowledge represented by each statement. law theory hypothesis if a certain piece of metal is cooled, it will conduct electricity better. arrowright the amount of electric current that passes through a conductor is directly proportional to the voltage and is described by the formula v
If a certain piece of metal is cooled, it will conduct electricity better, this statement is theory whereas, the amount of electric current that passes through a conductor is directly proportional to the voltage is known as law.
What is hypothesis, theory and law?A hypothesis is a statement that may be true or false. A theory is a well-supported explanation of observations or data. A scientific law is a statement that explains the relationship between variables. Hypothesis is a statement that is given before performing an experiment. It can be true or false after we perform an experiment. When a number of experiments can be performed and the hypothesis comes out true then theory is evolved. When the statement is verified after performing large number of experiments, it becomes a law.
So we can conclude that if a certain piece of metal is cooled, it will conduct electricity better, this statement is theory whereas, the amount of electric current that passes through a conductor is directly proportional to the voltage is known as law.
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Air (a diatomic ideal gas) at 27.0°C and atmospheric pressure is drawn into a bicycle pump (see the chapteropening photo on page 599 ) that has a cylinder with an inner diameter of 2.50 cm and length 50.0 cm . The downstroke adiabatically compresses the air, which reaches a gauge pressure of 8.00×10⁵ Pa before entering the tire. We wish to investigate the temperature increase of the pump.(g) What is the volume of steel in this 4.00-cm length?
The volume of the 4.00 cm length of the, 1.85 mm thick cylinder pump, that comes to thermal equilibrium with the air is approximately 6.24 cm³.
Which formula can be used to find the volume of the cylindrical pump?Parameters of the question found in a similar question found online are as follows;
Thickness of the steel cylinder, t = 1.85 mm
Length of steel cylinder that comes to thermal equilibrium with the air, l = 4.00 cm
Given parameters;
Inner diameter of the cylinder, d = 2.50–cm
Length of the cylinder = 50.0–cm
Required; Volume of the steel in the 4.00–cm length
Solution;
1.85 mm = 0.185 cm
Volume of the cylinder, V, is found as follows;
V = π•(D² - d²)/4 × l
Where;
D = The outer diameter of the cylindrical pump
d = The inner diameter
l = Length of the cylinder
Therefore;
D = d + 2•t
Which gives;
D = 2.5 + 2 × 0.185 = 2.87
V = (π•(2.87² - 2.5²)/4) × 4 ≈ 6.24
Therefore;
The volume of steel in the 4.00 cm length is 6.24 cm³Learn more about finding the volume of regular shapes here:
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what helps differentiate between the sound of a fire truck, an ambulance and an 18 wheeler? imbre form dynamics sound
Dynamics sound helps differentiate between the sound of a fire truck, an ambulance and an 18-wheeler.
What is dynamics sound?Elements allude to the din or delicateness of music. Elements offer a method for showing articulation in printed music. They help to drive the profound substance of music through volume and force. Elements can likewise be shown at the large-scale level for a piece of music in general. This may be just a single time toward the beginning, or a few times all through in the event that the din changes during various segments. Static elements are melodic directions that advise us to play the music at a specific volume that doesn't change. As such, don't get stronger or calmer, play each note at a similar volume as the final remaining one.
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a molecule in the air is moving at a speed 459 m/s. how many meters would the molecule move during 7.00 ms (milliseconds) if you didn’t collide with any other molecules?
The molecule in the air that is moving at a speed 459 m/s during a time of 7.00 ms (milliseconds) if it didn’t collide with any other molecules would move a distance of: 3.213 m
The formula and procedure we will use to solve this exercise is:
x = v * t
Where:
x = distancet = timev = velocityInformation about the problem:
v = 459 m/st = 7.00 msx=?By converting the time units from (ms) to (s) we have:
t = 7.00 ms * 1 s/1000 ms
t = 0.007 s
Applying the distance formula we have that:
x = v * t
x= 459 m/s * 0.007 s
x = 3.213 m
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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A tennis ball with a speed of 23.7 m/s is
moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 15.2865 m/s.
If the ball is in contact with the wall for
0.0145 s, what is the average acceleration of
the ball while it is in contact with the wall?
Take “toward the wall” to be the positive
direction.
Answer in units of m/s
The average acceleration of the ball while it is in contact with the wall is 1634.48 m/s²
Speed of the ball, v = 23.7 m/s
Contact timing of the ball with the wall, t = 0.0145 s
Since, average acceleration of the ball while it is in contact with the wall is being asked, so we can neglect the rebound speed.
So according to the First Equation of Motion which relates the velocity, acceleration and time i.e.
v = u +at
u = 0 as the initial velocity of the ball is zero
v = at
a = [tex]\frac{v}{t}[/tex]
a = [tex]\frac{23.7}{0.0145}[/tex]
a = 1634.48 m/s²
The average acceleration of the ball while it is in contact with the wall will be 1634.48 m/s²
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an elevator is being lifted up an elevator shaft at a constant speed by a steel cable. all frictional effects are negligible. in this situation, forces on the elevator are such that:: *
An elevator is being lifted up an elevator shaft at a constant speed by a steel cable. All frictional effects are negligible. In this situation, forces on the elevator are such that the upward force of the cable is equal to the downward force of gravity.
As per Newton's 2nd regulation F = ma, acceleration needs a force proportional to mass. So when the elevator is accelerating upwards, it has to not handiest oppose gravity however provides greater pressure for the upward acceleration. This calls for an expanded ordinary force
Friction is the pressure resisting the relative motion of strong surfaces, fluid layers, and cloth factors sliding against each other. There are several types of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.
The gravitational force is a pressure that draws any gadgets with mass. We call the gravitational pressure attractive as it usually attempts to pull masses collectively, it in no way pushes them apart. In fact, each item, which includes you, is pulling on each other object in the entire universe.
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ind the frequency at which gain is maximized for the forced damped harmonic oscillator with equation
the frequency at which gain is maximized for the forced damped harmonic oscillator is ωr .when 0<b<2mω
ωr is the frequency at which gain is maximum.
oscillator is a device that work on the principle of oscillation.
harmonic oscillator - It is a periodic rotation about the main position. That shifts to and fro.
Damped harmonic oscillator - It is a vibrating system for amplitude of vibration decreases over a time.
equation of damped harmonic oscillator.
[tex]\frac{d^{2}x}{dt^{2}} +2k\frac{dx}{dt} + \omega^{2} x = 0[/tex]
ω is the angular frequency
k is resistance coefficient
when 0<b<2mω
ωr is the frequency at which gain is maximum.
the frequency at which gain is maximized for the forced damped harmonic oscillator is ωr
The question is incomplete.
ind the frequency at which gain is maximized for the forced damped harmonic oscillator with equation
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point charges of 10.8 nc and 51.9 nc are placed 0.500 m apart. what is the electric field halfway between them? indicate direction by a positive or a negative value. keep in mind that a positive vector is one directed to the right and a negative vector is one directed to the left. your answer should be a positive or a negative number with two decimal places, do not include the unit. hint: 1 nc
Net electric field in middle of two charge is equal to 7,318.4 NC⁻.
Electric field at a point by an point electric charge is given by:
E=KQ/r²
where,
E is electric field
K is an constant with value 9×10⁹
Q is point electric charge
r is the distance at which E is desired
for 10.8 nC
electric field at +0.25 m is as
E=+155.2NC⁻
for 51.9nC
electric field at -0.25 m is as
E= - 7473.6NC⁻
therefore net electric field in middle of two charge
=(+155.2- 7473.6)
= -7318.4NC⁻
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An ion rocket engine produces 1 newton of thrust. What acceleration can it give to a space probe with a mass of 1000kg?.
The ion rocket engine give an acceleration to the space probe of: 0.001 m/s²
To solve this exercise, the formula and procedure to be applied is:
F = m * a
Where:
m = massF = Forcea = accelerationInformation about the problem:
F= 1 N1 N = kg * m/s²m = 1000kga= ?Applying the force formula and isolating the acceleration, we get:
F = m * a
a = F/m
a = 1 N /1000kg
a = 1 kg * m/s² / 1000kg
a = 0.001 m/s²
What is force?It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.
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