The time interval over which the proton is projected in the positive x direction into a region of a uniform electric field comes at rest is 4.93×〖10〗^(-8) s as it travel 7.00cm
Using the initial velocity and acceleration gotten from the linked questions where;
u=-2.84×〖10〗^6 m/s
a=5.76×〖10〗^13 m/s^2
Using the equation of velocity as;
v=u+a.t
0=u+a.t
Therefore, time t;
t=(-u)/a
t=(-2.84×〖10〗^6 m/s)/(5.76×〖10〗^13 m/s^2 )
t=4.93×〖10〗^(-8) s
Thus, the time interval for the proton to come to rest is 49.3ns. #SPJ4
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The most soaring vocal melody is in Johann Sebastian Bach's Mass in B Minor. In one section, the basses, tenors, altos, and sopranos carry the melody from a low D to a high
A. In concert pitch, these notes are now assigned frequencies of 146.8Hz and 880.0 Hz . Find the wavelengths ofFind the pressure amplitudes of (d) the final note.
The Wavelength and pressure amplitude of the final note is 0.39 m and 0.255 Pa respectively.
What do you mean by the pressure amplitude?The minuscule pressure difference between compressions and rarefactions in a sound wave is what the human ear uses to function. Pressure amplitude refers to the size of these pressure variations. Generally speaking, a sound appears louder the larger the pressure amplitude it has. Even for very loud sounds, these pressure changes are negligible in comparison to ambient pressure. A jet plane at 30 yards, for example, has pressure changes of just a few hundred Pascals, or less than one-hundredth of atmospheric pressure, which is loud enough to cause damage to human ears (which is roughly 100,000 Pa). The pressure amplitudes of the quietest noises that people can hear are approximately one billionth of the atmospheric pressure.
x=Asin (w [ t-K])+ b
Given:
Initial frequency, [tex]f_{initial} = 146.8\;Hz[/tex]
Final frequency, [tex]f_{final} = 880\;Hz[/tex]
Sound level, [tex]\beta=79\;dB[/tex]
We know that,
Speed of the sound, [tex]v=343\;m/s[/tex]
Density of air, [tex]\rho=1.2\;kg/m^{3}[/tex]
Wavelength, [tex]\lambda=\frac{v}{f}[/tex]
Wavelength of final note is,
[tex]\lambda=\frac{v}{f_{final}}[/tex]
Substitute the known values in the above equation,
[tex]\lambda=\frac{343}{880}}[/tex]
[tex]\lambda=0.39\;m[/tex]
[tex]\beta=10\times log(\frac{I}{I_{0}} )[/tex]
We know that, [tex]I_{o}=1 \times 10^{-12}\;W/m^{2}[/tex]
[tex]79=10\times log(\frac{I}{1 \times 10^{-12}} )[/tex]
By solving the above equation, We get,
[tex]I=7.9\times 10^{-5} W/m^{2}[/tex]
Pressure amplitude of the final note is,
[tex]I = \frac{(\triangle p)^{2} }{2 \times \rho \times v}[/tex]
[tex](\triangle p)^{2} = I \times2 \times \rho \times v[/tex]
[tex]\triangle p = \sqrt{I \times2 \times \rho \times v}[/tex]
Substitute the known values in the above equation,
[tex]\triangle p = \sqrt{7.9 \times 10^{-5} \times2 \times 1.2 \times 343}[/tex]
By solving the above equation, We get,
[tex]\triangle p = 0.255\;Pa[/tex]
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The velocity of a 48.0 g shell leaving a 2.95 kg rifle is 391. m/s. What is the recoil velocity of the rifle?
Hi there!
[tex]\large\boxed{ -6.36m/s}[/tex]
Use the equation:
[tex]v_{2} = -\frac{m_{1}}{m_{2}} v_{1}[/tex]
Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:
v2 = ?
m1 = 0.048 kg (converted)
m2 = 2.95
v1 = 391
[tex]v_{2} = -\frac{0.048}{2.95} *391[/tex]
[tex]v_{2} = -6.36m/s[/tex]
A 450 N trunk rests on a 30 degree inclined plane. What is the force acting down the
plane (parallel force)?
Answer: What is the force acting down the plane?
• Opp= hyp (sinq)= 450(sin30)= 225 N
• What is the force acting perpendicular to the plane?
• adj= hyp (cosq)= 450(cos30)= 390 N
Explanation:
If it took you 12 seconds to walk 36 meters, what is your velocity?
a
3 m/s
12 m/s
с
432 m/s
d
36 m/s
HEN
Answer:
3 m/s
Explanation:
rbsbdvebzvsvehdhdbd
Your speed is (36m)/(12sec).
That's 3 m/s. (Choice-A)
There's not enough information to determine your velocity.
ILL GIVE BRAINLIEST IF UR CORRECT
Answer:
B is the answer.
Explanation:
you are arguing over a cell phone while trailing an unmarked police car by 26.0 m; both your car and the police car are traveling at 110 km/h. your argument diverts your attention from the police car for 2.0 s (long enough for you to look at the phone and yell,"i won't do that!"). at the beginning of that 2.0 s, the police officer begins braking suddenly at 5.00 m/s2. suppose that you take another 0.500 s to realize your danger and begin braking
The speed of the car when you hit the police car is 26.154 m/s.
The speed of the car's v = 110km/h = 30.56 m/s
The total time travel will also include the reaction time:
t = 2 + 0.4 = 2.4 s
For police,
The acceleration, a = - 5 m/s²
The distance traveled is:
[tex]S(p) = vt + (\frac{1}{2} ) \times at^{2}[/tex]
[tex]S(p) = 30.56 \times 2.4 + \frac{1}{2} \times (-5) \times (-2.4)^{2}[/tex]
S(p) = 58.93 m
Now, the original gap between the car was 25 m.
Therefore, the final gap = (25 − 73.33 + 58.93) m = 10.6 m
As a result, let's say that at time t₀, the distance between the cars is 10.6 meters.
The speed of the police car at t₀ will be:
v(p) = (30.56 − 5 × 2.4) = 18.56m/s.
Now, the collision occurs at a time t when S = S(p)
We pick your position's coordinates to be S = 0 and the police car's position to be S(p) = 10.6m at time t₀ .
Therefore,
[tex]S(p) - 10.6 = 18.56(t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}[/tex]
S(p) = 10.6 + 18.56t − 2.5t²
And,
[tex]S = 30.56 (t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}[/tex]
When the distances are equal.
S = S(p)
30.56 (t - t₀) - (1/2)(5)(t - t₀)² = 10.6 + 18.56t − 2.5t²
t = 0.883 sec
So, the speed of your car during the collision will be:
v = 30.56 - 5(0.883) = 26.154 m/s
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The complete is mentioned below:
You are arguing over a cell phone while trailing an unmarked police car by 25m; both your car and the police car are traveling at 110km/h. Your argument diverts your attention from the police car for 2.0s (long enough for you to look at the phone and yell, “I won’t do that!”). At the beginning of that 2.0s, the police officer begins braking suddenly at 5.0m/s². What is the separation between the two cars when your attention finally returns? Suppose that you take another 0.40s to realize your danger and begin braking. If you too brake at 5.0m/s², what is your speed when you hit the police car?
Science: Please help due in 5 minutes...
Answer:
fossil fuels are petroleum and natural gas. Well Fossils are mineralized remains of ancient plants and animals
approximately 72 billion liters of milk are produced each year in the united states, from 8 million cows. on average, a single cow consumes 13,500 kg of corn feed each year. it requires 40 mj to produce a kilogram of corn feed, which contains 20 mj of energy. there are 15 mj of energy in a single liter of milk.
The energy efficiency of growing corn converted to milk is 50 percent corn efficiency produce 50 percent milk efficiency
Given data
annual milk production = 72 billion liters from 8 million cows
annual milk production = 72 billion liters / 8 million cows
annual milk production = 9000 liters / cow per annum
On average, a single cow consumes 13,500 kg of corn feed each year
40 MJ to produce a kilogram of corn feed, which contains 20 MJ of energy
15 MJ of energy in a single liter of milk
How to solve for energy efficiency of growing corn and converting it to milkEnergy efficiency of corn = energy output / energy input * 100
energy output = 20MJ
energy output = 40MJ
Energy efficiency of corn = 20 / 40 * 100
Energy efficiency of corn = 50 %
Energy efficiency of milk = energy output / energy input * 100
energy output = 13,500 * 20 = 270 000
energy output = 9000 * 15 = 135 000
Energy efficiency of milk = 135 000 / 270 000 * 100
Energy efficiency of milk = 50 %
Therefore 50 percent corn efficiency produce 50 percent milk efficiency
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complete question
Approximately 72 billion liters of milk are produced each year in the United States, from 8 million cows. On average, a single cow consumes 13,500 kg of corn feed each year. It requires 40 MJ to produce a kilogram of corn feed, which contains 20 MJ of energy. There are 15 MJ of energy in a single liter of milk.
1. Calculate the energy efficiency of growing corn and converting it to milk
Why does precipitation
occur when warm air rises?
Answer:
the warm air rises, cools and condenses to form clouds
Question 21 of 25
Calculate the capacitance of a system that stores 6.5 x 10-10 C of charge at
Q
50.0 V. Use C =
AV
A. 7.7 * 1010 F
B. 3.1 x 107 F
C. 1.3 x 10-11 F
D. 3.2 x 10-8 F
SUBMIT
Answer:
C. 1.3 x 10-11 F
I took the test and got this correct, hope this helps
Explanation:
(1) astronomers have inherited many useful concepts from antiquity. (2) for example, ancient mathematicians invented angles and a system of angular measure that is still used to denote the positions and apparent sizes of objects in the sky. (3) when we locate stars, we don’t need to know their distances from earth (which are all different). (4) all we need to know is the angle from one star to another in the sky, a property that remains fixed over our lifetimes. (neil f. comins and william j. kaufmann iii, discovering the universe) sentence 2 can best be described as a
The reading of the given passage on astronomy gives;
Sentence (2) is the major supporting detailHow can the parts of the passage be identified?Sentence (1) is the main idea or background statement with regards to astronomy, with regards to the sources of concepts being used in astronomy. It conveys the subject matter of passage.
Sentence (2) gives more light to the statement of sentence (1). It gives the supporting details of the concepts astronomers inherited from antiquity, by outlining them; (angles and angular measure system used locate stellar objects), while sentence (4) gives a little information with regards to the use of angular system.
Therefore;
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Use the law of conservation of energy (assume no friction nor air resistance) to determine the kinetic and potential energy at the various marked positions along the roller coaster track below: KE= ME PER KE PE=20 000J KE=25 000J PE= mgh PE=_ KE= KE KE=OJ PE-7 500J PE=5 000J PE- D Ε. Voc KE=/m 12 KE- PEN KE=_ PE=__ KE=40 000J PE=OJ What is the total mechanical energy of the roller coaster throughout the ride? Explain how you determined ME.
Answer:
Part A
1) At the starting point, we have;
PE = 40,000 J
2) PE = 0 J, KE = 40,000 J
3) KE = 20,000 J
4) PE = 15,000 J
5) KE = 32,500 J
6) KE = 40,000 J, PE = 0 J
7) KE = 35,000 J
8) KE = 40,000 J, PE = 0 J
Part B
The total Mechanical Energy = ME = 40,000 J
At the final point, we have;
ME = KE + PE = 40,000 J + 0 J = 40,000 J
Explanation:
Part A
By the law of conservation of energy, we have;
ME = PE + KE
Where;
ME = The total Mechanical Energy of the system
PE = The Potential Energy of the system
KE = The Kinetic Energy of the system
Where there is no friction, we have;
At the final stage, KE = 40,000 J. PE = 0 J
Therefore, ME = PE + KE = 40,000 J + 0 J = 40,000 J
1) At the starting point, we have;
KE = 0 J, therefore, PE = ME - KE = 40,000 J - 0 J = 40,000 J
2) At the bottom of the roller coaster, at the same level the PE is taken as PE = 0 J at the final stage, we have;
PE = 0 J, therefore, KE = ME - PE = 40,000 J - 0 J = 40,000 J
3) Where PE = 20,000 J, KE = ME - PE = 40,000 J - 20,000 J = 20,000 J
4) Where KE = 25,000 J, PE = ME - KE = 40,000 J - 25,000 J = 15,000 J
5) Where PE = 7,500 J, KE = ME - PE = 40,000 J - 7,500 J = 32,500 J
6) At the bottom KE = 40,000 J, PE = 0 J
7) Where PE = 5,000 J, KE = ME - PE = 40,000 J - 5,000 J = 35,000 J
8) KE = 40,000 J, PE = 0 J
Part B
The given that there is no friction nor air resistance, the total Mechanical Energy, ME, is constant and equal to the sum of the Potential Energy, PE and the Kinetic Energy, KE, as follows;
ME = KE + PE
At the final point, we have;
ME = 40,000 J + 0 J = 40,000 J
The total Mechanical Energy = ME = 40,000 J
Enter an expression in the box to Write the equation of the line perpendicular to y=-3x-1 that passes through the point (3,4).
Y = ?
Answer: -3x+13
Explanation:
The slope of the line that passes through the point (3,4) is 1/3. Then , the intercept of the perpendicular line is 3 . Then, the equation of the line is y = 1/3x + 3.
What are coordinates ?Coordinates are numbers which describes the position of a shape, curve or line. The coordinates are written in terms of x and y axis values. A line or curve passing through certain points can be represented by an equation.
For a straight line the equation is y = mx + c
where m is the slope of the line and c be the intercept on y- axis.
For two perpendicular lines, the slope will be opposite inverse of each other.
The slope of the line y = -3x + 1 is -3. Then, the slope of the line which is perpendicular to this line is - (1/-3) = 1/3.
Then the equation of the line is y = 1/3 x + c.
given the line passes through the point (3,4).
Then,
4 = 1/3×3 + c
c = 3.
Therefore, the equation of the second line is y = 1/3 x + 3.
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A car, with an initial velocity of 22 m/s west, travels for 345 seconds. If it has a final velocity of 44 m/s west what is its’ acceleration?
Answer: 0.064 m/s²
Explanation:
Initial velocity = 22m/s
Final velocity = 44m/s
Time taken = 345 seconds
Acceleration = (Final velocity - Initial velocity) / Time taken
= (44 - 22) / 345
= 22/345
= 0.0637681
= 0.064 m/s²
Therefore, the acceleration is 0.064 m/s².
How much voltage is in a circuit with a current of 0.1 A and a total resistance of 7.29 Ω?
Answer:
0.729
Explanation: by using ohms laws
Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(c) how far apart are Owen and Dina.
The distance between Dina and Owen with respect to Ed is 1.44 × 10¹² m.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In the frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Therefore, the distance between Dina and Owen with respect to Ed is:
L = L(p) √[1-(v²/c²)]
L = (1.8 × 10¹² m)√[1-(0.6c)²/c²)]
L = (1.8 × 10¹² m)(0.8)
L = 1.44 × 10¹² m
The distance is 1.44 × 10¹² m.
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A girl is running in a long distance race. As she runs, her respiration rate 10 points increases. Her body cells must process energy at a faster rate to power her muscles as she runs. Is this action a response to internal stimuli or external stimuli?
A. internal stimuli
B. external stimili
Question 45 points)
Which is an appropriate way to avoid heat related illness when exercising?
Answer:
drinking enough fluids, wearing proper clothing and timing your workout to avoid extreme heat
what is kinetics force
Answer:
Explanation:
Kinetic force is the force caused kinetic energy. Kinetic energy is energy this is in movement such as a moving car or a falling rock.
Planet A has a gravitational field strength of 8.0 N/kg near its surface.
Planet B has three times the mass of Planet A and is half of its size.
What would be the gravitational field strength of planet B near its surface?
Answer: 96 N/kg
Explanation:
Which unit abbreviation is a measurement of force?
A.
m/s
B.
m/s2
C.
N
D.
N/s
Answer:
N
Explanation:
Plato
if i apply 280 n of force to a 40kg object, what will it's acceleration be?
Answer:
f=ma
f=280N
m=40kg
a=?
280=40a
a=280/40
a=70N/kg
What will happen to a satellite's orbit if its engines are turned on, causing it to
gain velocity tangential to its orbit?
O A. The height of its orbit will decrease.
OB. It will lose kinetic energy.
C. It will lose gravitational potential energy.
OD. The height of its orbit will increase.
the first law of thermodynamics states that the degree of disorder in the universe tends to increase
The degree of disorder in the universe tends to increase due to entropy.
ie. the second law of thermodynamic
First law of thermodynamics is the conservation of energy. Energy can change from one form to another form it neither created nor destroyed.
dQ = dU + dW
where
dQ is the heat transferred.
dW is the work done
dU is change in internal energy.
2nd law states entropy of an isolated system always increases.
S > 0
where s is the change in entropy in the universe.
the degree of disorder in the universe tends to increase due to entropy.
ie. the second law of thermodynamic.
The given question is incomplete
the first law of thermodynamics states that the degree of disorder in the universe tends to increase
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Give an example of a situation in which you have experienced sound being reflected, absorbed, and transmitted.
Answer: Absorption is the transformation of radiant power to another type of energy, usually heat, by interaction with matter. The transmittance t of a medium is defined by the ratio of transmitted radiant power to incident radiant power.
Explanation:
Absorption, in wave motion, the transfer of the energy of a wave to matter as the wave passes through it. ... If there is only a small fractional absorption of energy, the medium is said to be transparent to that particular radiation, but, if all the energy is lost, the medium is said to be opaque.
what is the period of an object that makes 6 revolutions a minute
Answer:
[10 section] is gonna be your answer.
What are two types of democracy how are they different?
Answer:
representative and liberal democracy
Explanation:
a representative democracy is an indirect democracy where sovereignty is held by the people's representatives. a liberal democracy is a representative democracy with protection for individual liberty and property by rule of law
The net charge on an atom of a given element changes as ______ are added or removed.
Answer:
Answer is Electrons
Explanation:
If there is gain of electron then it will result a negative charge. And when there is loss of electrons it will result in the formation of positive charge iron.
20.0 m [N] - 15 m [S20degreesE]
Answer:
thank for making me give up on life
Explanation:
I thought the stuff I had was hard wth is even that
Drag each tile to the correct location.
An aspect of climate change involving cloud cover is one example of a negative feedback loop. Complete the steps of this negative feedback
loop.
increased formation
of clouds
decreased temperatures
increased evaporation
from oceans
increased carbon dioxide in
atmosphere
increased greenhouse effect
and warmer temperatures
1
+
increased precipitation
Edmentum. All rights reserved.
Answer:
Look at the image please
Explanation: