The probability that Bob is the last customer to leave the post office comes out as (1 - e^(-λx))^2. The probability that Bob is the last customer to leave the post office can be calculated using the exponential distribution formula.
The exponential distribution is a continuous probability distribution used to model the time between events in a Poisson process. The formula for the exponential distribution is: P(X=x) = λe^(-λx)
Where X is the random variable representing the time between events, λ is the rate parameter, and e is the base of the natural logarithm.
P(Bob is the last customer to leave) = P(Bob's serving time > Alice's serving time) * P(Bob's serving time > Claire's serving time). Since the serving times follow an exponential distribution with parameter λ, we can use the formula to calculate the probabilities:
P(Bob's serving time > Alice's serving time) = ∫_0^∞ λe^(-λx) dx = 1 - e^(-λx)
P(Bob's serving time > Claire's serving time) = ∫_0^∞ λe^(-λx) dx = 1 - e^(-λx)
P(Bob is the last customer to leave) = (1 - e^(-λx))^2
Therefore, the probability that Bob is the last customer to leave the post office is (1 - e^(-λx))^2.
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Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the high temperature of 98 degrees occurs at 6 PM and the average temperature for the day is 85 degrees. Find the temperature, to the nearest degree, at 7 AM. degrees
The temperature at 7 AM is approximately 87 degrees.
The outside temperature over a day can be modeled as a sinusoidal function. In this case, we know that the high temperature of 98 degrees occurs at 6 PM and the average temperature for the day is 85 degrees. To find the temperature at 7 AM, we can use the equation:
T(t) = A sin(B(t - C)) + D
where T(t) is the temperature at time t, A is the amplitude, B is the frequency, C is the horizontal shift, and D is the vertical shift.
We know that the average temperature is 85 degrees, so D = 85. We also know that the high temperature of 98 degrees occurs at 6 PM, so A = (98 - 85)/2 = 6.5 and C = 6.
Now we can plug in the values and solve for the temperature at 7 AM:
T(7) = 6.5 sin(B(7 - 6)) + 85
Since we want to find the temperature to the nearest degree, we can round the answer to the nearest whole number:
T(7) = 6.5 sin(B) + 85 ≈ 87 degrees
Therefore, the temperature at 7 AM is approximately 87 degrees.
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Bobbi bought two text books that cost 120 dollars, but paid 130
dollars because of the sales tax.What was the sales tax?
The sales tax that Bobbi paid was 10 dollars. Below, you will learn how to solve the problem.
To find the sales tax, we can simply subtract the cost of the text books from the total amount paid:
Sales tax = Total amount paid - Cost of text books
Sales tax = 130 dollars - 120 dollars
Sales tax = 10 dollars
Therefore, the sales tax that Bobbi paid was 10 dollars.
In mathematics, subtraction (also called subtraction) is an arithmetic operation that removes quantities from any kind of operation.
After subtracting, we will always have a smaller value than the one we had before.
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(c) \( (35)^{3} \) (the composition of the permutation (3 5 ) three times); (d) \( \left(\begin{array}{ll}1 & 2 \\ 4\end{array}\right)^{2023} \).
The composition of the permutation (3 5 ) three times is (3 5) and the permutation (1 2 4) to the power of 2023 is (1 2 4)
The composition of the permutation (3 5 ) three times is (3 5) and the permutation (1 2 4) to the power of 2023 is (1 2 4).For part (c), we can find the composition of the permutation (3 5) three times by applying the permutation to itself three times. The first time we apply it, we get (5 3), the second time we get (3 5), and the third time we get (5 3) again. Since the permutation (5 3) is the same as the original permutation (3 5), the composition of the permutation (3 5) three times is (3 5).For part (d), we can find the permutation (1 2 4) to the power of 2023 by applying the permutation to itself 2023 times. Since the permutation (1 2 4) is a cycle of length 3, applying it to itself 3 times will give us the identity permutation (1 2 4)(1 2 4)(1 2 4) = (1)(2)(4). Therefore, we can reduce the exponent of 2023 to 2023 mod 3 = 1, and the permutation (1 2 4) to the power of 2023 is the same as the permutation (1 2 4) to the power of 1, which is (1 2 4).
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The formula occurs in the indicated application. Solve for the specified variable.A=P+Prt for r (principal plus interest) r=
To solve for r, we can divide both sides of the equation by Pt: r = (A-P)/Pt
The formula A=P+Prt is used to calculate the total amount of money (A) after a certain period of time when a principal amount (P) is invested at a certain interest rate (r) for a certain amount of time (t). To solve for the specified variable r, we need to rearrange the formula and isolate r on one side of the equation. Here are the steps to do so:
Step 1: Subtract P from both sides of the equation to get:
A - P = P + Prt - P
Step 2: Simplify the right side of the equation to get:
A - P = Prt
Step 3: Divide both sides of the equation by Pt to get:
(A - P) / Pt = r
Step 4: Simplify the left side of the equation to get:
r = (A - P) / Pt
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\[ \begin{array}{c} A=\left[\begin{array}{lll} -5 & 1 & -7 \end{array}\right] \\ B=\left[\begin{array}{llll} -8 & 7 & 5 & -5 \end{array}\right] \\ C=\left[\begin{array}{ll} -4 & -2 \end{array}\right]
A \times B \times C = \left[\begin{array}{ll} -40 & -60 \\ -68 & 70 \\ 6 & 0 \end{array}\right]
To find the product of the matrices A, B and C, we can use the following equation:
$$A \times B \times C = \left[\begin{array}{lll} (A \times B)_{11} & (A \times B)_{12} & (A \times B)_{13} \\ (A \times B)_{21} & (A \times B)_{22} & (A \times B)_{23} \\ (A \times B)_{31} & (A \times B)_{32} & (A \times B)_{33} \end{array}\right] \times C = \left[\begin{array}{ll} (A \times B \times C)_{11} & (A \times B \times C)_{12} \\ (A \times B \times C)_{21} & (A \times B \times C)_{22} \\ (A \times B \times C)_{31} & (A \times B \times C)_{32} \end{array}\right]$$
To find each element of the product, we use the following equation:
$$(A \times B \times C)_{ij} = \sum_{k=1}^{3} A_{ik} \times B_{kj} \times C_{ij}$$
Where $i$ and $j$ represent the row and column numbers respectively. For example, to find the element $(A \times B \times C)_{11}$, we have:
$$(A \times B \times C)_{11} = \sum_{k=1}^{3} A_{1k} \times B_{k1} \times C_{11} = (-5 \times -8 \times -4) + (1 \times 7 \times -4) + (-7 \times 5 \times -4) = -40$$
Therefore, the product of A, B and C is:
$$A \times B \times C = \left[\begin{array}{ll} -40 & -60 \\ -68 & 70 \\ 6 & 0 \end{array}\right]$$
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Roland and Vickie are salespeople who earned the same amount this week, although Vickie made 8 more sales than Roland. Roland earns a base of $49 plus $15 per sale. Vickie earns a base of $145 plus $6 per sale. How many sales did Roland make this week?
Roland made 16 sales this week, while Vickie made 8 more sales than Roland.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables. Equations can either be linear, quadratic, cubic and so on depending on the degree.
Let x represent the number of sales Roland has.
Roland earns a base of $49 plus $15 per sale. HenceL
Total earning by Roland = 15x + 49
Vickie made 8 more sales than Roland. Vickie earns a base of $145 plus $6 per sale.
Total earning by Vickie = 6(x + 8) + 145 = 6x + 193
Roland and Vickie are salespeople who earned the same amount this week, Therefore:
15x + 49 = 6x + 193
9x = 144
x = 16
Roland made 16 sales this week.
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I have no clue how to do this
Simplify the following rational expression: \( \frac{500 x^{3}-108}{40 x^{2}+56 x-48} \) Leave the numerator and denominator in your final answer in fac torm.
The numerator is \((25x^{2}+15x+9)\) and the denominator is \(2(x+2)\).
To simplify the given rational expression, we need to factor the numerator and denominator and then cancel out any common factors.
First, let's factor the numerator:
\(500x^{3}-108=4(125x^{3}-27)=4(5x-3)(25x^{2}+15x+9)\)
Next, let's factor the denominator:
\(40x^{2}+56x-48=8(5x^{2}+7x-6)=8(5x-3)(x+2)\)
Now, we can cancel out the common factor of \(4(5x-3)\) from the numerator and denominator:
\(\frac{4(5x-3)(25x^{2}+15x+9)}{8(5x-3)(x+2)}=\frac{(25x^{2}+15x+9)}{2(x+2)}\)
Therefore, the simplified rational expression is \(\frac{(25x^{2}+15x+9)}{2(x+2)}\).
In this simplified form, the numerator is \((25x^{2}+15x+9)\) and the denominator is \(2(x+2)\).
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Why do we use standard units when measuring an object? (Select all that apply) A. Standard units are used because they are relatively permanent. B. Standard units enable communication over time. C. Standard units enable communication over distance. D. Standard units are exact.
We use standard units when measuring an object because :
A. Standard units are used because they are relatively permanent.
B. Standard units enable communication over time.
C. Standard units enable communication over distance.
D. Standard units are exact.
We use standard units when measuring an object because they are relatively permanent and enable communication over time, distance, and exactness.
Standard units are used because they are relatively permanent. This means that they do not change over time and are consistent. Standard units enable communication over time. Since they are consistent, they allow for accurate communication of measurements even if they are taken at different times.
Standard units enable communication over distance. They allow for accurate communication of measurements even if the people communicating are in different locations. Standard units are exact. This means that they are precise and accurate, allowing for consistent measurements.
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1. (7 points) Find the minima and maxima of the following function at a given interval:y=x4−32x3−2x2+2xin the interval[0,3]. Hints: You may want to use conditional statement to gatekeep the values. However, do not use solveset () function.
The minima and minima of the function y=x^4-(32/3)x^3-2x^2+2x in the interval [0,3] are:
Maxima: x=2
Minima: None
The minima and maxima of a function are the lowest and highest points on the function within a given interval. To find these points, we need to take the derivative of the function and set it equal to zero to find the critical points. The critical points are where the function changes direction, and are potential minima or maxima. We can then use a conditional statement to determine if the critical points are within the given interval and if they are minima or maxima.
The derivative of the function is:
y'=4x^3-3(32/3)x^2-4x+2
Setting the derivative equal to zero, we get:
4x^3-32x^2-4x+2=0
We can use the Rational Root Theorem to find the potential rational roots of this equation. The potential rational roots are ±1, ±2, ±1/2, and ±1/4. Using synthetic division, we find that x=2 is a root. This gives us the factor (x-2), and we can use synthetic division again to find the other factors. The factored form of the equation is:
(x-2)(4x^2-12x+1)=0
Using the quadratic formula, we can find the other two roots:
x=3±√(3^2-4(4)(1))/2(4)
x=3±√(9-16)/8
x=3±√(-7)/8
x=3±i√7/8
The only real root is x=2, so this is the only critical point. We can use a conditional statement to determine if this critical point is within the given interval and if it is a minima or maxima. The critical point x=2 is within the interval [0,3], so we need to determine if it is a minima or maxima. We can do this by taking the second derivative of the function and plugging in the critical point:
y''=12x^2-6(32/3)x-4
y''(2)=12(2^2)-6(32/3)(2)-4
y''(2)=48-64-4
y''(2)=-20
Since the second derivative is negative at the critical point, this means that the critical point is a maxima. Therefore, the maxima of the function is at x=2.
In conclusion, the minima and maxima of the function y=x^4-(32/3)x^3-2x^2+2x in the interval [0,3] are:
- Maxima: x=2
- Minima: None
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Consider the scale drawing and actual drawing of an
office.
Original
1.5 in.
3 yd
Enlargement
2.5 in.
5 yd
Compare the scale drawing to the actual drawing. What
information is needed to find the area?
1. The scale factor is (1) (2) (3) or (4)
2. The area of the scale drawing is (3.75) (4) (8) or (11.5)
3. To find the area of the actual drawing, multiply the
area of the scale drawing by the (inverse) (multiple) (reciprocal) or (square)
of the scale factor.
The answers to each part about the scale factor is given above.
What is scale factor?Scale factor is the ratio of final dimensions to the initial dimensions.
Mathematically, we can write -
K = {final dimension/initial dimension}
Given are the dimensions of the drawing as -
Original 1.5 in. 3 yd
Enlargement 2.5 in. 5 yd
{ 1 } -
We can write the scale factor as -
K = 3/1.5
K = 2
{ 2 } -
Area of the scaled drawing -
A = 2.5 x 5
A = 2.5 x 180
A = 450 square inches
{ 3 } -
To find the area of the actual drawing, multiply the area of the scale drawing by the multiple of the scale factor.
Therefore, the answers to each part about the scale factor is given above.
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Solvex + 4 - 5 = 6.
A. x = -7 and x
-15
B. x = 7 and x = -7
C. x = -7 and x = 15
D. x = 7 and x = -15
Option:-
[tex] \underline{\sf \color{brown}{ B ) x = 7 nd \: x = -7}}[/tex][tex] \: [/tex]
Given:-
[tex] \sf x + 4 - 5 = 6[/tex][tex] \: [/tex]
Solution:-
[tex] \sf \: x + 4 - 5 = 6[/tex][tex] \: [/tex]
[tex] \sf \: x + 4 = 6 + 5[/tex][tex] \: [/tex]
[tex] \sf \: x + 4 = 11[/tex][tex] \: [/tex]
[tex] \sf \: x = 11 - 4[/tex][tex] \: [/tex]
[tex] \boxed { \sf \blue{x = 7}}[/tex][tex] \: [/tex]
or
[tex] \sf \: x + 4 - 5 = 6[/tex][tex] \: [/tex]
[tex] \sf \: x - 1 = 6[/tex][tex] \: [/tex]
[tex] \sf \: x = 6 + 1[/tex][tex] \: [/tex]
[tex] \boxed{ \sf { \color{skyblue}x = 7}}[/tex][tex] \: [/tex]
━━━━━━━━━━━━━━━━━━━━━━━━━━
hope it helps! :)
From Monday through Friday, Earl works in the Tutoring center on another day. On another day Earl cleans bathrooms and in the on another. On Saturday and Sunday, 50% of the days. How many days does work in a week? What percent of Monday through Friday does work?
Earl works 5 days a week, which is 50percentage of Monday through Friday. He works in the Tutoring center one day, cleans bathrooms one day, and has another day for unspecified work.
Earl works 5 days a week. He works in the Tutoring center one day, cleans bathrooms one day, and has another day for unspecified work. This means that he is working 50% of Monday through Friday. On Saturday and Sunday, he has no work. His work schedule is a great example of how one can balance work with free time. It also shows how one can make the most out of their working hours by doing different activities each day. It provides variety and prevents boredom from setting in. The days off also give Earl time to rest and relax, allowing him to be productive the other days. His weekly schedule is a great example of how one can efficiently manage their time.
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the table gives information about the lengths of time spent in minutes, it took some pupil to do their maths homework last week.
Using the lengths of the time spent we can plot the histogram by the values in the table.
What is a histogram how to draw a histogram?A histogram is a visual depiction of a frequency distribution with continuous classes that has been categorised.
To create a histogram, follow the steps shown below.
Mark the class intervals on the X-axis and the frequencies on the Y-axis to get started.
Both axes must have the exact same scales. Intervals between classes must be exclusive. Create rectangles with appropriate frequencies as the heights and bases acting as class intervals.
As the class limits are shown on the horizontal axis and the frequencies are shown on the vertical axis, a rectangle is constructed on each class interval.
If the intervals are identical, the height of each rectangle is proportional to the associated class frequency.
From the given information, we have the following:
Length of time (t) Frequency
0 ≤ t < 10 5
10 ≤ t < 25 24
25 ≤ t < 30 12
30 ≤ t < 50 8
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The complete question is:
Describe the transformation of the equation below from the parent function of y = I x I
y = -2 I x - 3 I + 3
The transformation of the equation y = -2 I x - 3 I + 3 from the parent function y = I x I includes a horizontal shift of 3 units to the right, a vertical stretch by a factor of 2, a reflection across the x-axis, and a vertical shift of 3 units up.
The transformation of the equation y = -2 I x - 3 I + 3 from the parent function y = I x I can be described as follows:
The parent function is shifted 3 units to the right. This is indicated by the "-3" inside the absolute value bars in the equation.
The parent function is vertically stretched by a factor of 2. This is indicated by the "-2" in front of the absolute value bars in the equation.
The parent function is reflected across the x-axis. This is indicated by the negative sign in front of the "2" in the equation.
The parent function is shifted 3 units up. This is indicated by the "+3" outside the absolute value bars in the equation.
In summary, the transformation of the equation y = -2 I x - 3 I + 3 from the parent function y = I x I includes a horizontal shift of 3 units to the right, a vertical stretch by a factor of 2, a reflection across the x-axis, and a vertical shift of 3 units up.
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Select all the equations that are equivalent to 52 = -4 (2n + 1)
A. -4n = 56
B. 52 = -8n - 4
C. -4n - 4 = 62
D. 52 + 4 = -8n
E. n = -7
Answer:
B, D, E
Step-by-step explanation:
52= -4(2n+1)
= -8n-4
52= -8n-4
8n= -4-52
8n= -56
n= -7
-8n= 52+4
= 56
1.5×10^5
bacteria are measured to be in a dirt sample that weighs 11 gram. Use scientific notation to express the number of bacteria that would be in a sample weighing 1919 grams.
Hence, a 19-gram sample would contain 2.5909 x 10⁵ germs.
How come we use measure?
We can compare unknown amounts to known values with the use of measurement. We can quantify the size, length, and speed of objects with the use of measurement. The final result won't be accurate without measurement.
We may start by calculating the bacterium to dirt sample weight ratio:
bacteria per gram = 1.5 x 10⁵ / 11 = 13636.36...
We are able to employ this ratio to determine how many bacteria are present in a 19-gram specimen:
bacteria = bacteria per gram x weight of sample
bacteria = 13636.36... x 19
bacteria = 259090.91...
We must write the number in scientific notation because it is more than 10⁵. This can be achieved by adding a factor of 10⁵ and shifting the decimal place five places to a left:
bacteria = 2.5909 x 10^5
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Isabel has (9)/(10) kilogram of oranges. She ate (2)/(10) kilogram. How much of a kilogram remains
Isabel had 10 kilogram of oranges when she started. She ate 2 kilogram of the oranges, leaving her with 8 kilogram. This means that she has 8/10 kilogram of oranges left.
It is important to understand how to calculate fractions in order to answer questions like this. In this case, the question was asking how much of a kilogram remains after Isabel ate 2 kilogram. To answer this, we had to figure out what fraction of the 10 kilogram Isabel ate, which was 2/10. We then subtracted this fraction from 1 in order to figure out how much of a kilogram remains, which was 8/10.
This kind of calculation is useful when trying to figure out how much of something remains after a certain amount has been taken away. It can be used in a wide variety of contexts, such as when trying to figure out how much of a product or item remains after some has been sold or used. Understanding how to calculate fractions can be very helpful in these kinds of scenarios.
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Assume that y = C(a)^x is an exponential function. Why can a not equal zero?
Answer:
In the exponential function y = C(a)^x, the value of a is the base of the exponent, which determines how fast the function grows or decays. If a were equal to zero, then any value of x would result in y being equal to zero, which would make the function flat and unchanging. Therefore, a cannot be equal to zero in an exponential function, as this would result in an undefined or meaningless expression. Additionally, any number raised to the power of zero is equal to 1, so an exponential function with a base of zero would also violate this mathematical rule.
4. A surveying team needs to measure the distance across the lake. They make the
measurements shown along the ground. What is the distance across the lake?
The distance across the lake is 120 feet.
What is Right Angled Triangle?Right angled triangle are those triangle for which one of the angle is 90 degrees.
Given is a right angled triangle.
Pythagoras theorem states that,
Square of the hypotenuse of a right angled triangle is equal to the sum of the squares of the two legs of the triangle.
The distance across the lake is one of the leg of the right triangle.
Length of hypotenuse = 208 feet + 104 feet
= 312 feet
Length of other leg = 192 feet + 96 feet
= 288 feet
Distance across the lake = √(312² - 288²)
= √14,400
= 120 feet
Hence 120 feet is the distance across the lake.
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so thit i \( \mathrm{A}_{4} \) is targer than a \( \mathrm{B}_{2} . \mathrm{H} \) \[ \begin{array}{l} a=34, c=45, \quad A=194 \\ \rightarrow B_{1}=7 \cdot 3 \cdot \sim B_{2}= \\ -C_{1}= \\ b_{1}= \\ \
(\mathrm{A}_{4}\) is larger than \(\mathrm{B}_{2}\)
Yes, \(\mathrm{A}_{4}\) is larger than \(\mathrm{B}_{2}\). To show this, we can use the following equation:
\[\mathrm{A}_{4} = a \cdot c \cdot \mathrm{H}\]
and
\[\mathrm{B}_{2} = b_{1} \cdot c_{1}\]
Given that \(a = 34\), \(c = 45\), \(\mathrm{H} = 194\), \(b_{1} = 7\), and \(c_{1} = 3\), then \(\mathrm{A}_{4} = 34 \cdot 45 \cdot 194 = 291930\) and \(\mathrm{B}_{2} = 7 \cdot 3 = 21\). As \(291930 > 21\), \(\mathrm{A}_{4}\) is larger than \(\mathrm{B}_{2}\).
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View Policies Current Attempt in
Progress An electronic product contains 47 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the integrated circuits are independent. The product operates only if there are no defective integrated circuits. What is the probability that the product operates? Round your answer to four decimal places (e.g. 98.7654). The probability is
The probability that the product operates is 0.6055.
The probability can be meant as the chance something will be happened or not. The probability that the product operates is the probability that all 47 integrated circuits are not defective. Since the probability that any integrated circuit is defective is 0.01, the probability that it is not defective is 1 - 0.01 = 0.99. Since the integrated circuits are independent, the probability that all 47 are not defective is the product of the probability that each one is not defective. This is given by:
P(product operates) = 0.99⁴⁷ ≈ 0.6055
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Nancy needs her to mark the numbers
and
on the number line. How many parts does she need between 1 and 2, and between -1 and -2, so that she can mark
and
?
If we consider the number line with rational number marked on it, then the number of parts to be present between 1 and 2 and -1 and -2 will be one part each.
A number line is a pictorial representation or drawing of numbers in which there are equal intervals between each number and is used to represent the real numbers on it. Real numbers are those numbers which may be positive or negative integers, rational numbers or irrational numbers. In general, a quantity which can be expressed as an infinite decimal expansion is called as a real number.
If we draw a number line and mark the points as 1, 2, 3,...,∞ and -∞,..., -3, -2, -1 on the right and left hand side of 0, then the intervals between each real number is equal to 1. Hence the number of parts between 1 and 2 is one part and -1 and -2 is one part. However, these parts may be subdivided into more parts to get more fine value (smaller value).
This value will be a fractional value between 1 and 2 or -1 and -2. Hence parts between two numbers on a number line can be infinity, but for sake of simplicity, one is taken in general case.
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8 is 14% of what number? Round your answer to the nearest hundredth if necessary.
Answer:
I think the answer is 57.14
Answer:
57.14
Step-by-step explanation:
57.14 is the result of rounding 57.14 to the nearest 0.01
Three baby penguins and their father were sitting on an iceberg
0.5
0.50, point, 5 meters above the surface of the water. The father dove down
4.7
4.74, point, 7 meters from the iceberg into the water to catch dinner for his kids.
What is the father penguin's position relative to the surface of the water?
Answer:The father's position relative to the surface of the water is 4.2 meters below the surface of the water.
Step-by-step explanation:
What is an expression?
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
The height relative to the water surface is calculated as:-
Height from iceberg to water surface = 0.5 meters
The height from iceberg to deep inside the water is = 4.7 meters
Father's height relative to the water surface is,
H= 4.7 - 0.5 = 4.2 meters.
The image of the condition is also attached with the answer below.
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Put the function y=10x(x+1) in factored form f(x)=a(x-r)(x-s) and state the values of a,r, and s. (Assume r ≤ x)
The function y=10x(x+1) is already in factored form, with a=10, r=0, and s=-1.
A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element of X. The set X is termed the domain of the function and the set Y is called the codomain of the function. Initially, functions represented the idealized relationship between varied quantities and other variables.
To see this, we can rewrite the function as f(x)=10(x-0)(x-(-1)), which matches the form f(x)=a(x-r)(x-s). Therefore, the values of a, r, and s are:
a = 10
r = 0
s = -1
It is important to note that the values of r and s are the x-intercepts of the function, or the values of x that make the function equal to zero. In this case, the x-intercepts are 0 and -1, which correspond to the values of r and s.
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Please i need this by tnight
Answer:
2. 29 3. 9:11, [tex]\frac{9}{11}[/tex], 55 4(a) 10.7
Step-by-step explanation:
2. 29
3. 9:11
[tex]\frac{9}{11}[/tex]
[tex]\frac{11}{20} *100%\\= 55%[/tex]
4(a)10.7
running track in the shape of an oval is shown. The ends of the track form semicircles. A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 56 m and length of one straight edge 130 m. What is the perimeter of the inside of the track? HELP PLEASE INEED THIS
The perimeter of the inside of the track is approximately 354.36 meters.
What is the circumference?
In geometry, the circumference is the perimeter of a circle or ellipse.
To find the perimeter of the inside of the track, we need to find the length of the inside edge of the track and add it to twice the length of the semicircles at each end.
The inside edge of the track is formed by two parallel lines, each offset by a distance of 56 m from the outer edge. The length of this edge is equal to the length of the long straight edge minus twice the offset distance:
length of inside edge = 130 m - 2(56 m)
length of inside edge = 18 m
The length of each semicircle at each end is equal to half the circumference of a full circle with a radius equal to the width of the track (56 m). Therefore, the length of both semicircles is:
2 x (1/2 x 2π x 56 m) = 2π x 56 m
Adding the length of the inside edge to twice the length of the semicircles, we get:
perimeter of inside track = 18 m + 2π x 56 m
perimeter of inside track = 18 m + 112π m
the perimeter of the inside track ≈ 354.36 m (rounded to two decimal places)
Hence, the perimeter of the inside of the track is approximately 354.36 meters.
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The diameter of a quarter is about 1
in.
You trace around the edge of the quarter on a sheet of paper.
What is the area of the circle on the paper?
Use 3.14
as an approximation for π
. Round your answer to the nearest tenth.
The area of the circle which is drawn by tracing around the edge of the quarter on a sheet of paper is 0.78 in.²
What is meant by a quarter of a circle?All points in a plane that are at a specific distance from a specific point, the centre, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.
Each of the four equally sized pieces that make up a circle is known as a quarter of a circle. The quadrant of the circle is the name given to each quarter. One-fourth of the total area of the circle is represented by the area of a quarter circle.
Given,
the diameter of the quarter = 1 in.
When we trace around the edge of the quarter on a sheet of paper, we get a circle of diameter 1 in.
So the radius of the circle r = 1/2 = 0.5 inches
Area of the circle on the paper = πr² = 3.14 × 0.5² = 0.78 in.²
Therefore the area of the circle which is drawn by tracing around the edge of the quarter on a sheet of paper is 0.78 in.²
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Last week, Cindy's Diner sold 7 milkshakes with whipped cream on top and 18 milkshakes without whipped cream. What percentage of the milkshakes had whipped cream?
Answer: The total number of milkshakes sold is 7 + 18 = 25.
The number of milkshakes sold with whipped cream is 7.
To find the percentage of milkshakes with whipped cream, we can use the formula:
percentage = (part/whole) x 100
Substituting the values, we get:
percentage = (7/25) x 100
percentage = 28
Therefore, 28% of the milkshakes had whipped cream.
Step-by-step explanation: