The location at the point where electric field becomes zero is at 3.6m, when a positive point charge Q1= 2.6×10−5 C is fixed at the origin and a negative point charge Q2= −5.1×10−6 C is fixed at 2.0m.
What is electric field ?Electric field is field around electrically charged particle where columbic force of attraction or repulsion can be experienced by other charged particles. It is denoted by letter E and it's SI unit is V/m Volt per meter or N/C newton per coulomb.
Electric field comes inward to the center of the negative charge and it is going outward for positive charge.
Given,
Q₁= 2.6×10⁻⁵ C
Q₂= −5.1×10⁻⁶ C
x = 2.0m,
In this case there are two charges, one at the origin and other is at 2m distance from origin. Both these charges are kept along positive x axis. looking at the situation there are 2 cases
Case 1 ( electric field in between two charges)
in this case direction of the resultant electric field in between two charges is along positive x direction (direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis which is also in positive x direction).
Case 2 ( right side of the negative charge)
In this case direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis but which is in opposite direction of electric field due to positive charge.
Hence our electric field is zero at right side of the negative charge.
on right side, electric fields due to both charges are opposite to each other then we can write mathematically E₁ - E₂ = 0 at the point where resultant electric field is zero. Where E₁ is elctric field due to positive charge and E₂ is electric field due to negative charge.
E₁ - E₂ = 0
E₁ = E₂
[tex]\frac{kQ_{1}}{x^{2}} = \frac{kQ_{2} }{(x+2)^{2}}[/tex]
[tex]\frac{Q_{1}}{x^{2}} = \frac{Q_{2} }{(x+2)^{2}}[/tex]
[tex]\frac{Q_{1}}{Q_{2} }} = \frac{x^{2} }{(x+2)^{2}}[/tex]
(2.6×10⁻⁵ C ÷ -5.1×10⁻⁶ C) [tex]= \frac{x^{2} }{(x+2)^{2}}[/tex]
[tex]\frac{x^{2} }{(x+2)^{2}}[/tex] = 5.098 ≅ -5.1
x² = 5.1 (x+2)²
x = 2.25(x+2)
x=2.25x + 4.5
x(1-2.25) = 4.5
x(-1.25) = 4.5
x = 3.6m
Hence Electric field is zero at 3.6m from origin.
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A certain planet is impacted by a large asteroid, which sends molten rock flying into space. Two spheres of the molten rock are moving in the same direction. One sphere has a mass of 135 kg and a velocity of 95.0 m/s in the positive y-direction. The other sphere has a mass of 290 kg, and a velocity of 24.0 m/s in the positive y-direction. If the two spheres collide, and fuse together, what would be the velocity of the combined sphere?
77.4 m/s in the negative y-direction
59.5 m/s in the positive y-direction
62.2 m/s in the positive y-direction
46.6 m/s in the positive y-direction
Answer:
46.6 m/s in the positive y-direction.
Explanation:
A gardener pulles a mower with a force 500J, is done in moving the mower along the grassland through a distance of 20m. & Find the angle of application of the foce
The angle of application of the force is theta = arccos(500 J / (F * 20 m))
Force calculation.
We can use the work-energy principle to solve this problem. The work done by the gardener's force is equal to the change in kinetic energy of the mower. Since the mower starts from rest, the initial kinetic energy is zero. Therefore, the work done by the gardener's force is equal to the final kinetic energy of the mower:
Work = Change in kinetic energy
500 J = (1/2)mv^2
where m is the mass of the mower and v is its final velocity.
Since we don't know the mass of the mower or its final velocity, we cannot directly solve for the angle of application of the force. However, we can use the fact that the work done by a force is equal to the product of the magnitude of the force, the displacement, and the cosine of the angle between the force and the displacement:
Work = Fd cos(theta)
where F is the magnitude of the force, d is the displacement, and theta is the angle between the force and the displacement.
Substituting the given values, we have:
500 J = F(20 m) cos(theta)
Solving for the cosine of the angle:
cos(theta) = 500 J / (F * 20 m)
Since we don't know the magnitude of the force, we cannot directly solve for the angle. However, we can rearrange the equation to isolate the angle:
theta = arccos(500 J / (F * 20 m))
Therefore, we need to know the magnitude of the force to find the angle of application.
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The work done on the ship by the tugboat is calculated as 15,000,000 joules.
What is force?Force can be a push or a pull but always with magnitude and direction.
The work done on the ship is given by the equation as : work = force × distance × cos(Ф)
force is the constant horizontal force applied by tugboat, distance is distance moved by ship, and theta is angle between force and direction of motion of the ship. In this case, Ф is zero because the force is in same direction as the motion of ship.
Thus, we calculate the work done on the ship as: work = 5000 N × 3000 m × cos(0)
work = 15,000,000 joules
Therefore, the work done on the ship by the tugboat is 15,000,000 joules.
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a 0.1 kg tennis ball moving at 5m/s [W] is hit by a racquet. If the final velocity of the ball is 5 m/s [E], what is the change of momentum of the ball?
The change in momentum of the ball is 1.0 kg m/s [E].
How to calculated the change in momentum of the ball ?
The change in momentum of the ball can be calculated using the momentum equation:
Δp = pf - pi
Where
Δp is the change in momentum pf is the final momentumpi is the initial momentumThe momentum of an object can be calculated as the product of its mass and velocity:
p = mv
Where
p is momentumm is massv is velocityUsing the given values, we can calculate the initial momentum of the ball:
pi = mvi = (0.1 kg)(5 m/s [W]) = 0.5 kg m/s [W]
Similarly, we can calculate the final momentum of the ball:
pf = mvf = (0.1 kg)(5 m/s [E]) = 0.5 kg m/s [E]
Substituting these values into the momentum equation, we get:
Δp = pf - pi = 0.5 kg m/s [E] - 0.5 kg m/s [W] = 1.0 kg m/s [E]
Therefore, the change in momentum of the ball is 1.0 kg m/s [E].
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A motor is exerting a clockwise torque on a wheel, with a force of 24.4 N, and a lever arm of 0.22 m. An outside force is exerting a counter-clockwise torque, with a force of 7.9 N, and a lever arm of 0.74 m. Assuming that all forces are perpendicular to their respective lever arms, what will be the resulting motion of the wheel?
There is not enough information to know how the wheel will rotate.
The wheel will not rotate.
The wheel will rotate counter-clockwise.
The wheel will rotate clockwise.
Answer:
Since the net torque is negative, this means that the counterclockwise torque is greater than the clockwise torque. As a result, the wheel will rotate in the counterclockwise direction. Therefore, the answer is:
The wheel will rotate counterclockwise.
Explanation:
To determine the resulting motion of the wheel, we need to calculate the net torque acting on the wheel. Clockwise torque is positive, while counterclockwise torque is negative. Therefore, the net torque can be calculated as follows:
Net torque = (Clockwise torque) - (Counterclockwise torque)
Net torque = (24.4 N) x (0.22 m) - (7.9 N) x (0.74 m)
Net torque = 5.368 Nm - 5.846 Nm
Net torque = -0.478 Nm
PLEASE HELP EXPERTS
One type of Personal Noise is:
A. Messages
B. Semantic noise
C. Feedback
D. Prejudice
E. Physical noise
The locations of mineral and gem formation depend on different Earth processes. Some gems need heat, extreme pressure, or even a certain type of rock layer to form.
Which location in the figure shows where opal is most likely to form?
The correct responses are C because opals are found in sedimentary and metamorphic rocks.
3 Location There are two different varieties of opal that are found: volcanic opal, which fills vesicles and fissures in igneous rocks, and the more well-known sedimentary or sandstone type, which is found in Australia's major areas. Volcanic opal makes up the majority of deposits around the world, and a lot of it is prone to crazing.
How robust is opal?A synthetic stone may be flawlessly flat since the two pieces are flattened so they may be bonded together, however the majority of real strong opals have an imperfection in this area that is curved or bumpy due to their natural development.
Thus it's obvious that Position 3 in the image depicts where opal is located.
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Complete question -
The locations of mineral and gem formation depend on different Earth processes. Some gems need heat, extreme pressure, or even a certain type of rock layer to form.
Which location in the figure shows where opal is most likely to form?
Select the correct location.
6. As you drive your car along a country road at night, a deer jumps out of the woods and stands in
the middle of the road ahead of you. This occurs just as you are passing from a 55-mi/h zone to a 50-
mi/h zone. At the 50-mi/h speed-limit sign, you slam on the car's brakes, causing them to lock up,
and skid to a stop inches from the startled deer. As you breathe a sigh of relief, you hear the sound
of a police siren. The policeman proceeds to write you a ticket for driving 56 mi/h in 50-mi/h zone.
Because of your preparation in physics, you are able to use the 25-m-long skid marks that your car
left behind as evidence that you were not speeding. What evidence do you present? You must use
work/energy methods to solve this problem! The coefficients of friction between car tires and dry
concrete are (u=1.0, μ=0.80).
As the speed of the car was less than the posted speed limit of 50 mi/h when the brakes were applied, skid marks provide evidence that driver was not speeding at the time of incident.
What is meant by coefficient of friction?Measure of the amount of friction existing between the two surfaces is called as coefficient of friction.
Change in kinetic energy is: ΔK = 0 - 1/2mv²
W = fd
As f = μN
N = mg
fd = ΔK
μN d = 1/2mv²
μmgd = 1/2mv²
v = √(2μgd/m)
v = √(20.8025*0.45/1) ≈ 29.9 mi/h
Since the car's speed was less than the posted speed limit of 50 mi/h when the brakes were applied, the skid marks provide evidence that the driver was not speeding at the time of the incident.
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What is the proposed method for plate movement?
The movement of plates is explained by the theory of plate tectonics, which proposes that the Earth's lithosphere (made up of rigid plates) moves slowly over the underlying, more fluid asthenosphere due to the circulation of heat from the Earth's interior
What is Tectonics Plates?
Tectonic plates are large pieces of the Earth's lithosphere (made up of the crust and uppermost part of the mantle) that move around on the underlying asthenosphere, a more fluid layer of the mantle. The lithospheric plates are rigid and brittle, and they move in response to forces generated by the circulation of heat in the Earth's interior. The movement of the plates causes many geological features such as mountains, volcanoes, earthquakes, and oceanic trenches.
There are several major and minor tectonic plates, including the Pacific Plate, the North American Plate, the African Plate, the Eurasian Plate, and the Antarctic Plate. These plates interact with each other at their boundaries, which can be divergent (moving apart), convergent (moving towards each other), or transform (sliding past each other).
The lithospheric plates move apart at divergent boundaries, collide at convergent boundaries, and slide past each other at transform boundaries. These interactions at the boundaries cause many geological features such as volcanoes, mountain ranges, and earthquakes. The plate tectonics theory has been supported by various lines of evidence, including the study of earthquakes, magnetic anomalies, and the distribution of fossils and rocks around the world.
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What is the gravitational potential energy of a 9.00kg object that is 3.00m below the ground
relative to a point 5.00m below the ground?
-265J
265J
176J
-176J
The gravitational potential energy of the object is -176J. Option 4 is the answer.
How The answer was obtainedThe gravitational potential energy (U) of an object of mass (m) at a height (h) relative to a reference point where gravitational potential energy is defined to be zero is given by:
U = mgh
where g is the acceleration due to gravity (9.81 m/s^2).
In this problem, the object is 3.00 m below the ground relative to a point 5.00 m below the ground. So, the height of the object relative to the reference point is:
h = -3.00 m - (-5.00 m) = 2.00 m
Note that we use a negative sign for h because the object is below the reference point.
Plugging in the values, we get:
U = (9.00 kg) x (9.81 m/s^2) x (-2.00 m) = -176.22 J
Rounding off to two significant figures, the gravitational potential energy of the object is -176 J. Therefore, the answer is -176J.
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Draw a schematic diagram to show the ball's projectile motion after leaving the ramp with a horizontal velocity. Label the height it dropped and the horizontal distance.
When a ball leaves a ramp with a horizontal velocity, it will follow a curved path known as a projectile motion. The ball will move both horizontally and vertically, with the horizontal velocity remaining constant and the vertical velocity changing due to the force of gravity.
At the point where the ball leaves the ramp, it will have a certain height and horizontal distance from the starting point. As it moves through the air, it will travel a certain horizontal distance before landing on the ground at a lower height.
What is projectile motion?Projectile motion is a type of motion in which an object is launched or thrown into the air, and then moves under the influence of gravity and air resistance. In projectile motion, the object follows a curved path called a trajectory, which consists of both horizontal and vertical components.
The motion of a projectile can be described in terms of its velocity, acceleration, and displacement. At the instant of launch, the object has an initial velocity that can be broken down into horizontal and vertical components. The horizontal component of velocity remains constant throughout the motion, while the vertical component changes due to the effect of gravity.
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If a clock expends 2 W of power from a 1.5 V battery, what amount of current is supplying
the clock?
If a clock expends 2 W of power from a 1.5 V battery, 1.3A of current is supplying the clock
What is meant byelectric current ?
When an external voltage is given to one of the conductor's ends, the movement of particles known as an electric current begins. As a result, the negatively charged electrons that are drawn to the positive terminal of the exterior voltage are subject to an electric field.
The current through a conductor is proportional to the voltage across the conductor, according to Ohm's rule. As long as the temperature (and other physical factors) stay constant, this is true for many materials, including metals. The connection between voltage, current, and resistance in an electrical circuit can be calculated using Ohm's Law.
P ⇒ IV
I ⇒ P/V ⇒ 2/1.5 i.e. 1.3A
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On a certain planet, a 4950 kg rock weighs 22,030 N. If this planet has a radius of 4200 km, what is the mass of the planet?
1.18∗10^24 kg
4.51∗10^24 kg
1.92∗10^25 kg
3.06∗10^25 kg
1.18∗10^24 kg is the mass of the planet where a 4950 kg rock weighs 22,030 N with planet having a radius of 4200 km.
Define Newton's law of gravitation.
According to Newton's law of gravitation, every particle of matter in the universe is attracted to every other particle with a force that varies directly as the product of their masses and inversely as their distance from one another.
The universal power of attraction acting on all matter is known as gravity, also known as gravitation. It has no impact on defining the internal characteristics of common matter because it is by far the weakest known force in nature.
The object weighs m = 4950 kg.
The planet's radius is 4200 km, or 4200*1000 meters.
F= 22030 N, the object's weight
That which we are aware of is G the gravitational constant 6.674x10-11.
We must ascertain: planet's mass is given by M =?
F= GMm/r2
22030 = 6.674x10-11[(4950M)/(42001000)2]
⇒ M =1.18∗10^24 kg
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Through how many radians does the minute hand of a clock rotate in 21 min ?
Answer:
1 Minutes =2Pi/60
21 Minutes=2Pi/60*21
so the answer is, 2.198
Explanation:
we know that
there is 60 min one hour
so the there is 2Pi radians
so 21 minutes is 21/60
and we know the clock hand will travel anticlock wise
and a full circle measures 2Pi radians
and we know that one minute =2Pi /60 radians
so, 21 minutes = (21Pi/60)*60
(Pi=3.14)
21 minutes = 2.19
Calculate the volume of 19 kilograms of petrol if the density of petrol is 800 kg/m³. Give your answer to 2 decimal places.
Answer:
ρ (density) = M / V mass / volume
V = M / ρ = 19 kg / 800 kg/m^3 = .024 m^3
PLEASE ANSWER ALL PARTS TO THE QUESTIONS.
1. Why does the GI tract have a plexus in the muscalaris and nerves in the mucosa? What physiological functions of the tract are supported by these anatomical structures? Think about your answer in the context of Hirschsprung’s disease, a congenital disorder of the colon that involves a defect in the myenteric plexus. What symptom or problem do you imagine the disease would cause?
3. How and why does vomiting too often, for example for sufferers of bulimia, damage the digestive system? Why are the stomach’s gastric secretions harmful, but the oral secretions are not?
3. Name any two of the major types of chemical substances that are broken down in chemical digestion. For each substance, name an enzyme that breaks them down and what final product is actually absorbed by the body for use or storage.
4. Explain how enzymes assist the process of absorption.
5. Name at least two concrete, positive steps you can take to avoid contracting gastroenteritis (in other words, DOs not DON’Ts).
The GI tract has a plexus in the muscalaris, submucosal plexus, and nerves in the mucosa.
What is a GI tract problem?Hirschsprung disease (HD) is a congenital condition defined by the lack of ganglion cells (GC) at the Meissner's plexus (submucosa) and Auerbach's plexus (muscularized) of the terminal rectum.
Vomiting and extensive laxative use can cause digestive system disruption, resulting in stomach bleeding and regurgitation. By vomiting frequently, the esophagus relaxes, allowing stomach contents to ascend up into the pharynx and mouth.
Pepsin, for example, is a protein-degrading enzyme. Another enzyme that breaks down lipids is stomach lipase.
Stomach enzymes are essential for breaking down the food you consume. These proteins hasten molecular processes that convert nutrients into substances that can be absorbed by your digestive system.
Handwashing with detergent reduces the chance of gastroenteritis by up to 47%. Of course, avoiding tainted meals that may contain harmful germs and parasites is essential.
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two capacitors of capacitance C and 2C are connect in parallel and these are charged up to V volt. If the bartwry is removed and dielectric medium of comstant K is put between the plates of the first capacitor , then the potential on each capacitor is ?
tysm!
Initially, the two capacitors are charged up to the same voltage V, so the charge on the capacitor of capacitance C is Q = CV, and the charge on the capacitor of capacitance 2C is Q' = 2CV.
When the battery is removed and a dielectric medium of constant K is inserted between the plates of the first capacitor (of capacitance C), the capacitance of this capacitor becomes KC. The capacitance of the second capacitor remains the same at 2C.
The total charge on the capacitors remains the same, as no charge is lost or gained during this process. Therefore, we have:
Q = Q' = 2CV
After the insertion of the dielectric medium, the potential difference across the two capacitors will be different, as their capacitances have changed. Let V1 be the new potential difference across the capacitor of capacitance KC, and V2 be the potential difference across the capacitor of capacitance 2C.
We know that the total charge on the capacitors remains the same, so we can write:
Q = C1V1 + C2V2
where C1 = KC is the capacitance of the first capacitor (after insertion of the dielectric), and C2 = 2C is the capacitance of the second capacitor.
Substituting the values of C1, C2 and Q, we get:
CV = KV1 + 2CV2
Simplifying, we get:
V1 = (C/K) V - 2V2
But we also know that the potential difference across the two capacitors must be the same, i.e., V = V1 + V2. Substituting the value of V1 in this equation, we get:
V = [(C/K) V - 2V2] + V2
Simplifying, we get:
V2 = (1/3) V/K
Therefore, the potential difference across the capacitor of capacitance KC (after insertion of the dielectric) is:
V1 = (C/K) V - 2V2 = (5/3) V - (2/3) V/K
Thus, the potential on each capacitor after the insertion of the dielectric is V1 = (5/3) V - (2/3) V/K for the capacitor of capacitance KC, and V2 = (1/3) V/K for the capacitor of capacitance 2C.
Question in the photo
Answer:
Find his gravitational then divide it by your potential
At what angle should a circular road be banked so that a car running at 50 Km/hr be safe to go round the circular turn of 200 m radius?
Angle of 5.61° should be banked so that car running at 50 Km/hr be safe to go round the circular turn of 200 m radius.
What is Banking of Road?The process of raising outer edge of the road over its inner edge through certain angle θ is called as banking of road. Banking of road is nothing but the process of making the angle between the surface of road to horizontal surface of the road. The angle made by this two surfaces is called as angle of banking. Banking of road is done for safe turn at high speed.
Angle of banking is given by the formula,
tanθ = v²÷Rg
Where θ = angle of banking
R = Radius of circular turn
g = acceleration due to gravity
Given,
velocity of the car v = 50km/hr = 13.88 m/s
Radius of the circular orbit = 200 m
From formula,
tanθ = 13.88² ÷ (200×9.8)
tanθ = 0.09829
θ = tan⁻¹(0.09829)
θ = 5.61°
Hence angle must be backed at 5.61° to have safe turn.
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A washing machine spins its tube at a rate of 1200 rps . if the tube diameter is 35cm . find velocity of the 1 m of the tube
The rotation per second of the spin of the tube is 1200 rps. The diameter of the tube is 35 cm or 0.35 m. Then, its velocity is 1308 m/s.
What is angular velocity ?Angular velocity is a physical quantity that is the rotational analogue of the linear velocity. The angular velocity of an object is the velocity of rotation that is distance covered by one rotation per second.
Given number of rotations = 1200 rotation per second
circumference of the tube = 2 π r = πd
c = 3.14 × 0.35 m = 1.09 m.
It means that, for one rotation, the tube covers a distance of 1.09 m. In one second it spins 1200 times.
Hence, the total distance travelled in one second = 1200/s × 1.09 m = 1308 m/s.
Therefore, the velocity of the 1 m tube is 1308 m/s.
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Relationship between mass and gravitational force
Answer:
f =ma
hope helps ..... ...
Dave used a lever to get a tree stump out of the ground. if he pushes one side down 2 meters which lifts the stump 0.25m, what is the lever’s mechanical advantage
The lever's mechanical advantage would be 8.
Mechanical advantage calculationThe mechanical advantage of a lever is calculated as the ratio of the length of the effort arm to the length of the resistance arm.
In this case, the effort arm is the distance Dave pushes down on one side of the lever (2 meters), and the resistance arm is the distance the stump is lifted (0.25 meters). Therefore, the mechanical advantage of the lever is:
Mechanical Advantage = Effort Arm/Resistance Arm
Mechanical Advantage = 2/0.25
Mechanical Advantage = 8
So the lever's mechanical advantage is 8.
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Suppose a small comet was on a path to collide with Earth. Its density is 0.5 g/cm3 (500 kg/m3 ). Earth’s radius is 6378 km and Earth’s density is about 5500 kg/m3 (5.5 g/cm3 ). At what height would it disintegrate? (3) Hint: the Roche limit = 2.5 [(density of planet)/(density of moon or other object)]1/3 (radius of planet)
The comet will disintegrate at a height of 70,479,900 m.
Comet's height problemTo find the height at which the comet would disintegrate, we need to determine Earth's Roche limit with respect to the comet.
Roche limit = 2.5 [(density of planet)/(density of moon or other object)]^(1/3) (radius of planet)
Let's assume that the moon has a similar density to the comet, so we can use the Roche limit formula with the following values:
density of planet = 5500 kg/m^3
density of moon or other object = 500 kg/m^3
radius of planet = 6378 km = 6,378,000 m
Roche limit = 2.5 [(5500 kg/m^3)/(500 kg/m^3)]^(1/3) (6,378,000 m)
Roche limit = 76,857,900 m
This means that any object that comes closer to Earth than 76,857,900 m would be torn apart by tidal forces.
Therefore, the comet would disintegrate at a height of 76,857,900 m - 6,378,000 m = 70,479,900 m above Earth's surface.
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Rank the following systems in order of increasing speed of the corresponding wave. Indicate ties where appropriate.
Answer:
the answer can be A because based on what I know every increasing stars from 1 to the biggers numbers
Need help with number 14
Answer:
d
Explanation:
Write a function that takes in two parameters and returns the average of those two parameters.
What is parameters?Parameters are variables that are used to control or adjust the behavior of a particular system or model. They are used to improve the accuracy of a model or to establish baseline values for comparison. Parameters may be used to adjust the size or complexity of a system, the level of accuracy of a model, or the range of a system's inputs. Parameters can also be used to identify specific characteristics of a system, such as its maximum or minimum values, or to monitor its performance. Parameters are an important tool in helping to understand and control the behavior of a system.
The function below takes in two parameters, a and b, and returns the average of those two parameters.
function avg(a, b) {return (a + b) / 2;}
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A firefighter is climbing a ladder for a drill. If the firefighter (including their suit and gear) has a mass of 105 kg, and they climb to a height of 24 m in a period of 68.5 seconds, how much power is the firefighter producing?
173,000 W
36.8 W
944 W
361 W
Answer:
The correct answer is: 361 W
Explanation:
What is the mass of an object that requires 15 n to accelerate at a rate of 1. 5 m/s/s?.
Answer:
Explanation:
Force = mass*acceleration
15=mass*5
mass=3kg
please help me quick
Answer:40m East
Explanation:
Grace is attempting to lift an object off the ground a distance of 3m. She applies 50N of force and generates 75J/s. How long does the lift take?
To lift an object off the ground a distance of 3m, Grace applies 50N of force and generates 75J/s. The time taken by Grace for the lift is 2 seconds.
What is force?A force is an effect that changes, or accelerates, the velocity of a mass-moving object (such as one that is travelling from a state of rest). It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F and is measured in newtons (N), the SI unit of force.
According to Newton's second law, an object's net force is equal to the speed at which its momentum is changing over time. This rule suggests that the acceleration of an object is directly proportional to the net force exerted on the object, is in the direction of the net force, and is inversely proportional to the mass of the object if its mass is constant.
According to the equation,
P = [tex]\frac{W}{t}[/tex]
where,
P is the power,
W is the work done and,
t is the time taken.
W = F×S
where,
F is the applied force and
S is the distance.
Substituting the values and solving for t,
time taken = 2 seconds
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All of the following describe the region in which an electron is most likely to be found
EXCEPT
orbital
isotope
cloud
path
All of the following describe the region in which an electron is most likely to be found except an isotope. Thus, the correct option is B.
What is an isotope?Isotopes can be defined as the distinct nuclear species of the same element. They have the same atomic number and the position in the periodic table as the main atom, however they differ in number of nucleons due to different numbers of neutrons in their nucleus.
Orbital is a volume of space present within an atom where an electron is most likely to be found. The s-orbitals are spherical in shape.
Cloud is the region present near the nucleus where the probability of finding an atom is highest. Cloud are the region of negative charge.
Path can also be defined as orbital. It is the exact route in which the electrons travel in an atom.
Therefore, the correct option is B.
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