A piece of lead wire has a diameter of 0.470mm. If less has a density of 11.3g/cc, how long(in metres) should you cut a piece of wire to obtain 0.0236 moles of lead

Answer:

The forelimbs of a bat are different from other mammals as they are modified into wings for the purpose of flying.

Answer:

B

Explanation:

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The correct answer is option c) Three moles of sodium, Na.

We know that

18g of H₂O = 1 mol

So, no. of atoms in H₂O = 3 x 6.022 x 10²³

                                           = 1.81 x 10²⁴ atoms(both H&O atoms combined)

Now,

No. of atoms in 1 mol of H₂ = 2 x 6.022 x 10²³

                                             = 1.2044 x 10²⁴ atoms.

No. of atoms in 2 mol of NaCl = 2 x 6.022 x 10²³

                                                  = 1.2044 × 10²⁴ atoms.

No. of atoms in 2 mol of O₂ = 2 x 6.022 x 10²³

                                              = 1.2044 × 10²⁴ atoms.

No. of atoms in 3 mol Na  = 3 x 6.022 x 10²³  

                                              = 1.81 x 10²⁴ Na atoms.

Therefore, 3 mol of Na contains as many atoms as 18g of H₂O i.e., 1.81 x 10²⁴ atoms.

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Which Of The Following Contains As Many Atoms As 18 G Of Water, H2O?

a) One mole of hydrogen, H₂

b) Three moles of sodium, Na

c) Two moles of sodium chloride, NaCl

d) Two moles of oxygen, O₂

Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons

A = 1*42 + 1*50 + 2*1

A = 94

The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.

Answer: watch Video of HC1O4 + P4010 -> H3PO4 + Cl₂o7 How Do I Balance It?

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Explanation:  video is called      How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)

Play How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)

2:22 minute video

How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)

Answer: 2SeO2(s)+O2(g)+2H2O(l)→2H2SeO4(aq)

Explanation:

Start with the unbalanced equation by writing chemical formulas for each of the reactants and products:

SeO2(s)+O2(g)+H2O(l)→H2SeO4(aq)

Count the number of each atom on each side of the equation to determine whether the equation is balanced:

Reactants: 1 Se atom, 5 O atoms, 2 H atoms

Products: 1 Se atom, 4 O atoms, 2 H atoms

Balance the number of oxygen atoms by adding a coefficient of 2 to aqueous selenic acid on the products' side of the reaction. Then, balance the hydrogen atoms by adding a coefficient of 2 to liquid water on the reactants' side of the reaction. Finally, balance the selenium atoms by adding a coefficient of 2 to solid selenium dioxide on the reactants' side of the reaction to give the following balanced equation:

2SeO2(s)+O2(g)+2H2O(l)→2H2SeO4(aq)

The balanced chemical equation for this reaction is

[tex]\rm2SeO_2(s) + O_2(g) + 2H_2O(l) \rightarrow 2H_2SeO_4 (aq)[/tex]

A balanced chemical equation is defined as a chemical reaction in which the number of atoms of each elements in the reaction and the total charge is same for both the reactants and the products.

It involves the addition of stoichiometric coefficients of the reactants and products.

Selenic acid is majorly used in protecting and changing the color of steel, especially the steel parts on firearms.

Thus, the balanced chemical equation for this reaction is

[tex]\rm2SeO_2(s) + O_2(g) + 2H_2O(l) \rightarrow 2H_2SeO_4 (aq)[/tex]

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Answer:

879.5616802

Explanation:

(N/Na)*W

Explanation:

magnesium can be used for the construction as only when the metal is divided into fine pieces or as a thin sheet, magnesium will burn rapidy.

Answer: 4.48

Explanation: If the last digit in the fractional part of 4.482 is less than 5, then simply remove the last the digit of the fractional part.

Answer:

The answer is 59

Explanation:

Answer:

23 moles

Explanation:

Given data:

number of moles of propane = 7.5 mol

Number of moles of carbon dioxide produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂     →      3CO₂ + 4H₂O

Now we will compare the moles of propane and carbon dioxide.

                        C₃H₈             :             CO₂

                             1                :               3

                           7.5              :           3/1×7.5 = 22.5

22.5≅ 23 moles

The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.

The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.

Thus;

We know that;

Frequency of the wave = 9.3x10^8 Hz

Plank's constant =  6.626 x 10^-34 J.s

E = hf

E = energy of the wave

h = Plank's constant

f = frequency of the waves

E = 9.3x10^8 Hz *  6.626 x 10^-34 J.s

= 6.2 * 10^-25 J

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Answer:

heat production

Explanation:

Answer:bromine , neon , helium , argon , lithium , beryllium

Explanation:

Elements can be divided into three state that are solid, liquid and gas depending the intermolecular forces of attraction, distance between the particles etc. Lithium, beryllium, boron, carbon, sodium, magnesium, iron, copper, etc. are solid at room temperature.

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Elements can be solid liquid or gas at room temperature.

Therefore,  Lithium, beryllium, boron, carbon, sodium, magnesium, iron, copper, etc. are solid at room temperature.

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s block - group 1 and 2 , p block - group 13 to 18 , d block - group 3 to 12, f block - group 3

Thus we can conclude that ,they are names as s,p,d and f blocks because the last electrons enter s, p , d and f orbitals respectively.

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Answer:

\frac  {P_{1}V_{1}}{T_{1}}=\frac  {P_{2}V_{2}}{T_{2}}

Explanation:

Gay-Lussac's law states that at constant volume, the pressure of a gas is directly proportional to the absolute temperature, P ∝ T at constant V. These three gas laws can be combined into a so-called combined gas law, P 1 V 1 T 1 = P 2 V 2 T 2.

Answer:

The first two

Wavelength is measured from crest to crest. Amplitude is from trough to crest or crest to trough

Answer:

2 electrons

Explanation:

Answer: Two equatorial positions so as to minimize the repulsion.

Explanation:

Formula used for calculating number of electrons :

[tex]\frac{1}{2}[V+N-C+A][/tex]

where,

V = number of valence electrons present in central atom  = 8

N = number of monovalent atoms bonded to central atom = 4

C = charge of cation  = 0

A = charge of anion  = 0

Now we have to determine the hybridization of the [tex]XeF_4[/tex]   molecule.

[tex]\frac{1}{2}[8+4-0+0]=6[/tex]

Bond pair electrons = 4

Lone pair electrons = 2

The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.

The molecular geometry will be square planar as two alternate positio ns will be occupied by lone pair of electrons so as to minimize the repulsion.

The structure of tRNA resembles cloverleaf. 

 tRNA is called transfer RNA, which is a small RNA molecule which plays important role in protein synthesis.-It serves as link between messenger RNA and the growing chain of amino acids that make up protein.

 tRNA molecules fold into structure resembling cloverleaf  with four important sites:-

•The acceptor stem (3’-CCA) have an amino acid

•The anticodon  attaches  with the mRNA codon (via complementary base pairing)

•The T arm attaches  with the ribosome (via the E, P and A binding sites)

•The D arm of tRNA activating enzyme (help in adding the amino acid to the acceptor stem).

CCA is codon codes for  prolein amino acid in polypeptide chain.

AUG is initiator codon codes for methionine.

UAG, UAA and UGA are stop codons.

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Answer:

SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of ammonium sulfate and barium nitrate are mixed.

(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) ⇒ BaSO₄(s) + 2 NH₄NO₃(aq)

The complete ionic equation includes all the ions and insoluble species.

2 NH₄⁺(aq) + SO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) ⇒ BaSO₄(s) + 2 NH₄⁺(aq) + 2 NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)

Answer:

b.

i hope is help

Answer:

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]pH = - log(3.16 \times {10}^{ - 8} ) \\ = 7.500312...[/tex]

We have the final answer as

Hope this helps you

Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

Theoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

Finally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:

Answer:

Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.

Explanation:

Answer: (D) 0.025 mol [tex]O_2[/tex]

Explanation:

The given balanced equation is :

[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]

According to stoichiometry :

4 moles of ammonia [tex](NH_3)[/tex] reacts with = 5 moles of oxygen [tex](O_2)[/tex]

Thus 0.30 moles of  ammonia  [tex](NH_3)[/tex]  reacts with = [tex]\frac{5}{4}\times 0.30=0.375[/tex] moles of oxygen [tex](O_2)[/tex]

Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.

moles of oxygen [tex](O_2)[/tex] left = 0.40 - 0.375 = 0.025

Thus 0.025 mol [tex]O_2[/tex] excess reagent remains.

The amount of excess reagent remaining when 0.30 mole NH3 reacts with 0.40 mole O2  is 0.025 mole of O2

An excess reagent is a reactant which is left and can keep reacting after whole reaction.

A limiting reagent is a reactant that is totally consumed in the whole process of the reaction.

The chemical equation for the reaction is represented as:

[tex]\mathbf{4NH_3 + 5O_2 \to 4NO + 6H_2O}[/tex]

From the above reaction,

4 moles of ammonia reacts with 5 moles of oxygen molecule;

If 0.30 moles of ammonia reacts, then the numbers of moles of oxygen required can be computed as:

[tex]\mathbf{= \dfrac{0.3 \times 5}{4}}[/tex]

= 0.375 moles of oxygen.

But, we are given that 0.40 moles of oxygen is present.

Therefore, the amount of oxygen in excess is

= 0.40 moles - 0.375 moles

= 0.025 moles of O2

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