A physics class has 40 students. Of​ these, 10 students are physics majors and 14 students are female. Of the physics​ majors, three are female. Find the probability that a randomly selected student is female or a physics major.

The values of x if the distance between the points (x, 4) & (3, x) be 131/2 are approximately 9.39 and -4.39.

To find the values of x if the distance between the points (x, 4) & (3, x) be 131/2, we can use the distance formula:

D = √((x2 - x1)² + (y2 - y1)²)

Where D is the distance, (x1, y1) and (x2, y2) are the coordinates of the two points.

Plugging in the given values, we get:

131/2 = √((3 - x)² + (x - 4)²)

Squaring both sides and simplifying, we get:

169 = (3 - x)² + (x - 4)²

Expanding and rearranging, we get:

2x² - 14x - 110 = 0

Using the quadratic formula, we can find the values of x:

x = (-(-14) ± √((-14)² - 4(2)(-110))) / (2(2))

x = (14 ± √(196 + 880)) / 4

x = (14 ± √1076) / 4

x ≈ 9.39 or x ≈ -4.39

So the values of x are approximately 9.39 and -4.39.

Therefore, the values of x if the distance between the points (x, 4) & (3, x) be 131/2 are approximately 9.39 and -4.39.

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The LCD in this case is 2x^(2). So the solutions to the equation are x = 0 and x = 5.

To solve the equation, we first need to find the least common denominator (LCD) of all the fractions.

Next, we multiply each side of the equation by the LCD to eliminate the fractions:

2x^(2)*(x^(2)-x-6)/(x^(2)) = 2x^(2)*(x-6)/(2x) + 2x^(2)*(2x+12)/(x)

Simplifying the equation gives us:

2x^(2)-2x-12 = x^(2)-3x-12

Next, we move all the terms to one side of the equation:

x^(2)-5x = 0

Finally, we can factor the equation and set each factor equal to zero:

x(x-5) = 0

x = 0 or x = 5

So the solutions to the equation are x = 0 and x = 5.

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Answer:

55/100 and 48/100, in decimal form it will be 0.55 and 0.48

Step-by-step explanation:

11/20 and 12/25

The common denominator in this question will be 100

55/100 and 48/100

Fοr the inequality 12 + 11/6x ≤ 5 + 3x, the cοrrect οptiοns are -

E. 6 ≤ x

F. The sοlutiοn set is (x l x∈R, x ≥ 6].

In Algebra, an inequality is a mathematical statement that uses the inequality symbοl tο illustrate the relatiοnship between twο expressiοns. An inequality symbοl has nοn-equal expressiοns οn bοth sides. It indicates that the phrase οn the left shοuld be bigger οr smaller than the expressiοn οn the right, οr vice versa.

Tο sοlve the inequality 12 + 11/6x ≤ 5 + 3x, we can fοllοw these steps -

Mοve all the terms cοntaining x tο οne side -

12 + 11/6x - 3x ≤ 5

Simplify the left-hand side -

72/6 + 11/6x - 18/6x ≤ 5

(72 + 11x - 18x)/6 ≤ 5

(72 - 7x)/6 ≤ 5

Multiply bοth sides by 6 tο eliminate the fractiοn -

72 - 7x ≤ 30

Mοve all the terms cοntaining x tο οne side -

72 - 30 ≤ 7x

42 ≤ 7x

Divide bοth sides by 7 (since 7 is pοsitive, we dοn't need tο flip the inequality) -

6 ≤ x

Therefοre, the cοrrect statement(s) and number line(s) that can represent the inequality are -

E. 6 ≤ x

F. The sοlutiοn set is (x ∈ R, x ≥ 6].

This means that the sοlutiοn set includes all real numbers greater than οr equal tο 6.

The interval nοtatiοn (6, ∞) cοuld alsο be used tο represent this sοlutiοn set.

Optiοn A is incοrrect because it οnly includes natural numbers (pοsitive integers), but the sοlutiοn set includes all real numbers greater than οr equal tο 6.

Optiοn B is incοrrect because it shοws a number line frοm -7 tο 7, which is nοt relevant tο the sοlutiοn set.

Optiοn C is incοrrect because it shοws an arrοw with a filled circle mοving tοwards pοsitive infinity, which implies that the sοlutiοn set is all pοsitive numbers, but the inequality οnly requires x tο be greater than οr equal tο 6.

Optiοn D is incοrrect because it is tοο limited in scοpe - it οnly tells us that the number substituted fοr x is greater than 6, but dοesn't give us the full sοlutiοn set.

Therefοre, οptiοn E and F are cοrrect.

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The continuous growth rate of a function is given by its derivative.

So, taking the derivative of f(x) with respect to x, we get:

f'(x) = 0.07e^(0.07x)

Therefore, the continuous growth rate of the function is 1.07.

Answer:

Step-by-step explanation:

ISSA PARADE INSIDE MY CITY YEAHHHHH

The answer of the given question based on the graph shows  number of birdhouses Penn and his father can build, if they have enough time to build not more than 10 birdhouses, the correct option is A).

What is Graph?

In mathematics, a graph is a collection of points (called vertices or nodes) and the lines or arcs (called edges) that connect them. Graphs are used to model and analyze a variety of real-world situations, such as social networks, transportation systems, and electrical circuits.

Based on the given graph, the horizontal axis represents the number of birdhouses Penn's father can build and the vertical axis represents the number of birdhouses Penn can build. The graph is bounded by the line x + y = 10, which means that the sum of  number of the birdhouses Penn and his father can build cannot be exceed more than10.

Therefore, the domain of this graph is the set of possible values for the number of birdhouses Penn's father can build, subject to the constraint that the sum of the number of the birdhouses Penn and his father can build cannot be exceed more than 10. This domain is the set of non-negative integers less than or equal to 10, inclusive. In interval notation, this can be written as [0, 10].

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Complete question:-The graph shows the number of birdhouses Penn and his father can build if they have enough time to build no more than 10 birdhouses. What is the domain of this graph?

The final answer of Jane is 13(9)/(30) years old.

To find out how old Jane is, we need to first calculate Bill's age and then add 1(1)/(3) years to it.

Here are the steps:

1. Calculate Bill's age:

- Start with Lisa's age: 12(4)/(5) years

- Add 1(1)/(6) years to it: 12(4)/(5) + 1(1)/(6) = 12(24)/(30) + 1(5)/(30) = 12(29)/(30) = 12 + 29/30 = 12(29)/(30) years

2. Calculate Jane's age:

- Start with Bill's age: 12(29)/(30) years

- Add 1(1)/(3) years to it: 12(29)/(30) + 1(1)/(3) = 12(29)/(30) + 1(10)/(30) = 12(39)/(30) = 12 + 39/30 = 12 + 1(9)/(30) = 13(9)/(30) years

So, Jane is 13(9)/(30) years old.

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The factorization of the polynomial is (x-10)² (x² + 13x + 42).

To factor the given polynomial, we can use the fact that it has a zero at 10 with multiplicity 2. This means that (x-10)² is a factor of the polynomial. We can divide the polynomial by (x-10)² using long division to find the other factor.

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For the given cuboid, it's volume value is deduced as 30 cm³.

What is volume?

Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.

The figure is given as a cuboid.

The length of the cuboid is 5 cm.

The breadth of the cuboid is 6 cm.

The height of the cuboid is 1 cm.

The formula for volume of cuboid is given as -

Volume = length × breadth × height

Substitute the values into the equation -

Volume = 5 × 6 × 1

Volume = 30 cm³

Therefore, the volume value is obtained as 30 cm³.

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Answer:

To find the derivative of the function y = x^2 - x + 3 using the first principle, we start by applying the definition of the derivative:

f'(x) = lim (h -> 0) [f(x+h) - f(x)] / h

where f(x) = x^2 - x + 3.

Now we substitute the function into the equation and simplify:

f'(x) = lim (h -> 0) [(x+h)^2 - (x+h) + 3 - (x^2 - x + 3)] / h

f'(x) = lim (h -> 0) [(x^2 + 2xh + h^2 - x - h + 3) - (x^2 - x + 3)] / h

f'(x) = lim (h -> 0) [2xh + h^2 - h] / h

Now we can cancel out the h in the numerator and denominator, leaving:

f'(x) = lim (h -> 0) [2x + h - 1]

Finally, we take the limit as h approaches 0:

f'(x) = 2x - 1

Therefore, the derivative of y = x^2 - x + 3 with respect to x is f'(x) = 2x - 1.

Step-by-step explanation:

Answer:

[tex]\dfrac{\text{d}y}{\text{d}x}=2x-1[/tex]

Step-by-step explanation:

Differentiating from First Principles is a technique to find an algebraic expression for the gradient at a particular point on the curve.

[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Differentiating from First Principles}\\\\\\$\text{f}\:'(x)=\displaystyle \lim_{h \to 0} \left[\dfrac{\text{f}(x+h)-\text{f}(x)}{(x+h)-x}\right]$\\\\\end{minipage}}[/tex]

The point (x + h, f(x + h)) is a small distance along the curve from (x, f(x)). As h gets smaller, the distance between the two points gets smaller. The closer the points, the closer the line joining them will be to the tangent line.

To differentiate y = x² - x + 3 using first principles, substitute f(x + h) and f(x) into the formula:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{(x+h)^2-(x+h)+3-(x^2-x+3)}{(x+h)-x}\right][/tex]

Simplify the numerator:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{x^2+2hx+h^2-x-h+3-x^2+x-3)}{x+h-x}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2hx+h^2-h}{h}\right][/tex]

Separate into three fractions:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2hx}{h}+\dfrac{h^2}{h}-\dfrac{h}{h}\right][/tex]

Cancel the common factor, h:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\:2x+h-1\:\right][/tex]

As h → 0, the second term → 0:

[tex]\implies \dfrac{\text{d}y}{\text{d}x}=2x-1[/tex]

Answer: y = -5/3x + 4

Step-by-step explanation:

The slope intercept form is y = mx + b

The slope (m) is rise over run, so slope = -5/3

The y-intercept (b) is 4 because that is where the line intersects the y-axis at.

Hope this helps!

Answer:

100%

Step-by-step explanation:

If all 32 the beads were plastic it would be 100%

The ratio of similarity  DEFG to TSRQ is '3: 1'.

Two quadrilaterals are considered similar if they have the same shape but may have different sizes. Similar quadrilaterals have corresponding angles that are congruent, and their corresponding sides are in proportion to each other.

The ratio of similarity is a measure of how much two geometric figures are enlarged or reduced to become similar.

Here we have

Quadrilateral DEFG and Quadrilateral TSRQ.

Where DEFG similar to TSRQ

Hence, the ratio of corresponding sides will be equal

=> DE/TS  = EF/SR  = FG/RQ = DG/TQ

=> 24/8  = 24/8  = 24/8 = 24/8 = 3/1

Therefore,

The ratio of similarity  DEFG to TSRQ is '3: 1'.

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Answer: Yes, you are correct.

Step-by-step explanation:

The relationship between the number of flowers and the number of bouquets is an example of a unit rate.

Answer:

yes

Step-by-step explanation:

it is a unit rate

The required measure of the angle S in the isosceles trapezoid is ∠S = 115°.

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

For isosceles trapezoid,
The sum of the opposite angle is equal to 180°.
∠Q + ∠S = 180

Substitute the value in the above expression,
65 + ∠S = 180
∠S = 180 - 65
∠S = 115°

Thus, the required measure of the angle S in the isosceles trapezoid is ∠S = 115°.

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To divide two polynomials, P(x) and D(x), we can use either synthetic or long division. In this example, we'll use long division to divide P(x) by D(x) and express P in the form P(x)=D(x)⋅Q(x)+R(x).

First, we must make sure the degree of P(x) is greater than or equal to the degree of D(x). In this case, P(x)=-x^3-2x+6 and D(x)=x+1, so P(x) has a greater degree than D(x).

Next, we must write down P(x) and D(x) with the same degree. In this example, we can multiply D(x) by -x^2 to get -x^3+1. Then, P(x)=-x^3-2x+6 and D(x)=-x^3+1.

We can now start the long division process. First, we divide the leading coefficients, -1 and -1, so our quotient is 1. We then multiply the quotient by D(x), which gives us -x^3+1. We subtract this result from P(x), and the result is -2x+6.

Next, we divide the leading coefficients, -2 and -1, so our quotient is 2. We then multiply the quotient by D(x), which gives us -2x^2+2. We subtract this result from our previous result, -2x+6, and the result is 6.

Finally, we have reached the end of the long division process. Our quotient is Q(x)=2x+1 and our remainder is R(x)=6. Therefore, P(x)=D(x)⋅Q(x)+R(x), or -x^3-2x+6=(-x^3+1)⋅(2x+1)+6.

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Answer:(A) Show your work.

Step-by-step explanation:(A) Show your work.

Answer: holy math sucks but check the explanation i gotchu

Step-by-step explanation: A) -2x^6 + 3x^5 - 2x^4 - 15x^3 + 4x^2 -20x - 20

B) No, the product is not equal to (x^3-3x-4)*(-2x^3+x-5). This is because the order of the terms in the product is different than the order of the terms in the expression. The product takes the form of -2x^6 + 3x^5 - 2x^4 - 15x^3 + 4x^2 -20x - 20, whereas the expression has the form of (-2x^3+x-5)*(x^3-3x-4).

The system of inequalities is correctly graphed on Shannon's graph.

Here we have the following system of inequalities:

y ≥ (1/2)*x - 1

x - y > 1

We can rewrite the second inequality as:

y < x - 1

Then the system becoimes:

y ≥ (1/2)*x - 1

y < x - 1

The first line will be one with positive slope, it is solid (due to the symbol ≥) and the shaded area is above the line.

For the second we will have a dashed line, and now the shaded area is below the dashed line.

From that, we caonclude that Shannon's graph is the correct one.

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The function is decreasing in the interval (3, ∞).

f(x) = -x² + 6x - 4

Differentiate the equation with respect to 'x'.

f'(x) = -2x + 6

Put f'(x) = 0

-2x + 6 = 0

x = 6/2

x = 3 (critical point)

Now, write the function as:

f(x) = -x² + 6x - 4

-(x² - 6x + 4) (negative form)

Thus, the function is decreasing in the interval (3, ∞)

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The smallest positive integer value of m is 676.

To find the smallest positive integer value of m, we need to factor 52m into its prime factors and find the smallest value of m that makes 52m a perfect cube.

First, let's factor 52m into its prime factors:

52m = 2 * 2 * 13 * m

A perfect cube has all of its prime factors raised to the power of 3. So, in order for 52m to be a perfect cube, we need to have two more 2's, two more 13's, and two more m's.

This means that m must be equal to 2 * 2 * 13 * 13 = 676.

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Answer:

B. 6

Step-by-step explanation:

3/4 can be added to itsef to be 6/8

6/8

----      6/1   = 6

1/8

Answer:

Step-by-step explanation:

tbh i don't know how to explain it but i feel like its D i multiply and add

If z varies jointly as x and y, then the value of z when x = 20 and y = 8 is 24.

When a variable varies jointly as two other variables, it means that the variable is directly proportional to the product of the two other variables.

In this case, we can use the formula:

z = kxy

where k is a constant of proportionality.

We can find the value of k by using the given values of z, x, and y:

6 = k(4)(10)

6 = 40k

k = 6/40

k = 3/20

Now that we know the value of k, we can use the formula to find z when x = 20 and y = 8:

z = (3/20)xy

z = (3/20)(20)(8)

z = (3)(8)

z = 24

Therefore, the value of z when x = 20 and y = 8 is 24.

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The area is 893/15.

The area can be calculated by evaluating the given expression at the limits of integration and subtracting the two values.

we will evaluate the expression at the upper limit of integration, t = 7:
[(7)/(3)(7)^((3)/(2))-(1)/(5)(7)^((5)/(2))] = [(7)/(3)(7^(3/2))-(1)/(5)(7^(5/2))] = [(7)/(3)(49)-(1)/(5)(16807/49)] = [(343/3)-(33614/245)] = [(343/3)-(274/5)] = [(1715/15)-(822/15)] = 893/15

we will evaluate the expression at the lower limit of integration, t = 0:
[(7)/(3)(0)^((3)/(2))-(1)/(5)(0)^((5)/(2))] = [(7)/(3)(0)-(1)/(5)(0)] = 0

we will subtract the two values to find the area:
893/15 - 0 = 893/15

Therefore, the area is 893/15.

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Answer:

20

Step-by-step explanation:

The following unit multipliers are used:

1 loaf of bread = 400g of flour = 0.4kg of flour: [tex]\frac{0.4kg Of Flour}{1 loaf}[/tex]

1 day = 64 loaves of bread: [tex]\frac{64 loaves}{1 day}[/tex]

∴Mass of flour needed to last for 20 days:

[tex](20 days)[/tex]× [tex]\frac{64loaves}{1day}[/tex] ×[tex]\frac{0.4 kg}{1 loaf}[/tex]

  = 512 kg of flour

                  1 sack = 25 kg of flour

∴ x sacks of flour = 512 kg of flour

Cross-multiplication is applied:

(x sacks of flour)(25 kg of flour) = (1 sack)(512 kg of flour)

∴ x sacks of flour = [tex]\frac{(1 sack)(512kg Of Flour)}{25 kg Of Flour}[/tex]

                             = 20.48 sacks of flours

∴The minimum number of sacks = 20

Margin of error = 1.4

Sample mean = 13.4

=============================================================

Explanation:

To find the margin of error, we subtract the endpoints and divide by 2.

(b-a)/2 = (14.8-12.0)/2 = 1.4 is the margin of error

The b-a portion calculates the width of the confidence interval. It's the distance from one endpoint to the other. Splitting that in half gives the "radius" so to speak of this interval.

----------

The sample mean is at the midpoint of those given confidence interval endpoints.

The midpoint formula will have us add up the values and divide by 2

(a+b)/2 = (12.0+14.8)/2 = 13.4 is the sample mean

The a+b portion is the same as b+a, meaning we could have written that formula as (b+a)/2 as indicated in the next section.

-----------

Take note how similar each formula is:

The only difference is one has a minus sign and the other has a plus sign.

The result of the formula "20 - 4.65" is 15.35, which corresponds to the amount of change the customer gets.

Expressions are separated by mathematical sign i.e positive or negative.

The expression "20 - 4.65" represents the amount of change a customer would receive after ordering from the menu board.

The first part of the expression, "20", represents the amount of money the customer paid for their order. This is the total cost of the items they purchased from the menu board.

The second part of the expression, "4.65", represents the amount of money that the customer spent on their order. This is the subtotal of the items they purchased before tax and any other fees that may be added to the bill.

To calculate the change the customer receives, you subtract the amount the customer spent from the amount they paid. So in this case, the expression "20 - 4.65" gives us the answer of 15.35, which represents the amount of change the customer receives.

As for what the customer ordered, we cannot know for sure based on this expression alone. It's possible that the customer ordered a single item that cost exactly $4.65, or they may have ordered multiple items that added up to that subtotal. Without more information about the menu board and the prices of the items, it's impossible to determine exactly what the customer ordered.

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The correct answer is option b. both the statement are false.


Given that A is a 3×3 matrix such that A^2 −5A+7I=O

Statement I: A^−1 = 1/2 (5I−A)

To find the inverse of a matrix, we need to multiply both sides of the equation by A^−1

A^−1(A^2 −5A+7I)=A^−1(O)

A−5I+7A^−1=O

A^−1=1/7(5I-A)

This statement is false because the inverse of matrix A is not equal to 1/2 (5I−A).

Statement II: The polynomial A^3−2A^2−3A+I can be reduced to 5(A−4I)

To reduce the polynomial, we need to factor it.

A^3−2A^2−3A+I=(A−1)(A^2−A−I)

This statement is also false because the polynomial A^3−2A^2−3A+I cannot be reduced to 5(A−4I).

Therefore, both statements are false and the correct answer is option b. both the statement are false.

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The quadratic function written in vertex form is:

y = -1*(x - 1)^2

We know that the vertex of the parabola is (1, 0), so if the leading coefficient is a, we can write the vertex form:

y = a*(x - 1)^2 + 0

y = a*(x - 1)^2

In this case we know two points on the parabola, the vertex which is at(1, 0) and the y-intercept which is (0, -1).

Using the vertex (1, 0) we can write the parabola as:

y = a*(x - 1)^2 + 0

y = a*(x - 1)^2

Now we can use the values of the other point and replace this in the formula above so we get:

-1 = a*(0 - 1)^2

-1 = a

Then the quadratic function is:

y = -1*(x - 1)^2

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a) To find the linear velocity of a point on the tip of one of the blades, we need to use the formula: V = 2πr/T where V is the linear velocity, r is the radius of the circle, and T is the period of rotation. In this case, the radius of the circle is the length of the propeller blades, which is 3 meters, and the period of rotation is the inverse of the frequency of rotation, which is 1/6 minutes. Plugging in the values, we get: V = 2π(3)/(1/6) = 36π meters per minute. To the nearest meter per minute, the linear velocity is approximately 113 meters per minute.

b) To find the arc length and the area of the circular sector, we need to use the formulas: Arc length = θr and Area = (θr^2)/2 where θ is the central angle in radians, and r is the radius of the circle. In this case, the central angle is 25 degrees, which is equivalent to (25π)/180 radians, and the radius of the circle is 12 cm. Plugging in the values, we get: Arc length = ((25π)/180)(12) = (5π)/3 cm and Area = (((25π)/180)(12^2))/2 = (25π)/3 cm^2. Therefore, the arc length is approximately 5.24 cm and the area is approximately 26.18 cm^2.

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