A person pushes on a stationary 125 N box with a force of 78 N at 30∘ below the horizontal, as shown in the figure. (Figure 1) The coefficient of static friction between the box and the horizontal floor is 0.72. What is the normal force on the box?

The time taken for the ball to hit the ground is 1.77 s

From the questionn give above, the following data were obtained:

The time taken for the ball to fall to the ground can be obtained as follow:

h = ½gt²

15.3 = ½ × 9.8 × t²

15.3 = 4.9 × t²

Divide both side by 4.9

t² = 15.3 / 4.9

Take the square root of both side

t = √(15.3 / 4.9)

t = 1.77 s

Thus, we can conclude that: it will take the ball 1.77 s to fall to the ground.

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Answer:

3ft/s²

Explanation:

[tex]a = \frac{60 - 45}{5} = 3ft \div {s}^{2} [/tex]

Answer:

okay

Explanation:

why don't you have any question in this app?

Answer:

Approximately [tex]10410\; {\rm N}[/tex] (assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].)

Explanation:

There are two forces on this car:

The net force on this car would be:

[tex](\text{net force}) = (\text{tension}) - (\text{weight})[/tex].

Rearrange to obtain:

[tex](\text{tension}) &= (\text{net force}) + (\text{weight})[/tex].

Let the mass of this car be [tex]m[/tex]. The weight of the car would be [tex]m\, g[/tex].

If the acceleration of the car is [tex]a[/tex], the net force on this car would be [tex]m\, a[/tex].

Thus:

[tex]\begin{aligned}(\text{tension}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= (m)\, (a + g) \\ &= (1000\; {\rm kg}) \, (0.60\; {\rm m \cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 10410\; {\rm N}\end{aligned}[/tex].

Answer:

Fire is in plasma physical state. It contains both gaseous and moist fluidy substances.

[tex].[/tex]

Answer:

Both gas state and liquid state or vapor (plasma overall)

The maximum height  above the point of contact with the bat that the ball would reach would be  88.72 meters

It is the movement of any item or body when it is launched from the the earth's surface and follows any curving course while being affected by the gravitational pull of the planet.

The maximum height of the projectile motion is given by,

Maximum height = v² sin²θ / 2 g

                            =45² sin² 68/ 2 *9.81

                            =88.72 meters

Thus, the maximum height the ball would reach would be 88.72 meters

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Explanation:

[tex]{ \rm{ \vec{B}} = \frac{ \mu_{0}N}{l} } \\ [/tex]

N is number of turns

l is conductor length

mu_0 is permeability

[tex]{ \boxed{ \tt{ \mu_{0} = 4\pi \times {10}^{ - 7} }}}[/tex]

#include <stdio.h>

int main()

{

const int LENGTH = 10;

const int WIDTH = 5;

const char NEWLINE = '\n';

int area;

area = LENGTH * WIDTH;

printf("value of area : %d", area);

printf("%c", NEWLINE);

return 0;

}

Answer:

maximum height,h=31.25m

Explanation:

when an object is thrown vertically upward, v=0.

using the formula, v²= u²+2gh.

since the object is thrown upwards, g= -10m/s

v²=u²-2gh

0²=25²- 2×10×h

0=625-20h

20h = 625

h=31.25m

The age of the sample will be 11460 years.

The half-life of C-14 = 5730 years.

The half- life time is the time taken by the object to attain its position till the half of its initial value.

i.e after 5730 years only half of the C-14 carbon will exists.

To retain one-fourth of the sample, another cycle of 5730 years is required.

This means 2 half-lives should have passed to retain one-fourth of the sample.

so to calculate it's age

[tex]\frac{t}{\frac{t}{\frac{1}{2} } }[/tex] = 2

where t = the age of the sample

with t(1/2) = the half-life time of the sample = 5470 years

2 = the number of half- lives passed

therefore

[tex]\frac{t}{5730}[/tex] = 2

t = 2*5730 = 11460 years

When only one-fourth of the sample will remain, the age of the sample will be 11460 years

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Answer:Visual Merchandising is the practice in the retail industry of optimizing the presentation of product and services to better highlight their features and benefits. The purpose of such visual merchandising is to attract, engage, and motivate the customer towards making a purchase

Explanation:

u welcome

The two actions that the driver could take would be to (a) Push down on the accelerator and then (b) push down on the brakes, therefore the correct answer is option D.

The total displacement covered by any object per unit of time is known as velocity.

When the driver pushes down on the accelerator the velocity and the acceleration would be in the same direction.

When he pushes down on the brakes the acceleration vector would point in the opposite that of velocity, therefore the correct answer is option D.

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The early phases of undertaking an epidemiological, clinical, or lab study include calculating the sample size. There are ethical and methodological guidelines that should be followed when creating a scientific publication.

When it comes to making clinical judgments, two studies that used the same approach and produced equal results but had different sample sizes could provide the researcher with different information. Therefore, contrary to popular belief, samples should not be too tiny or too large in the perfect world. The primary effects of the sample size on study interpretation will be covered in this paper using clinical terminology. Although it can appear at first glance that methodological difficulties are the most important thing, particularly to clinicians.

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The displacement of the victorious snail will be 336.0mm .

The term displacement refers to a change in an object's position. It is a vector quantity and has a direction and magnitude .

We are given here,

Average velocity of snail = Δv = 2.4 mm/s

Time interval taken by snail = Δt = 140 s

The average velocity can be define as, the rate of change in displacement in the particular time interval of the object. The formula can be given as,

Δv =  Δx / Δt

Where,  Δv is the average velocity, Δx is the change in displacement,  Δt is the time interval of an object. Unit can be written as meter/second.

Therefore, the displacement of snail during the race can be calculated by the relation i.e.

Δx =  Δv ×  Δt

Thus , putting the values in above equation we get,

Δx = 2.4mm/s × 140s  

Δx = 336.0 mm

Hence,  the snail would move 336.0 mm in 140s.

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The vertical distance with which the ball clears the crossbar is given by x= 1.34m

We are given in the question that the distance between the kicking point of football and the goal is 54m (59.0544 yd), Height of crossbar is 3.05m, Speed of the ball when it leaves the ground is 26m/s at an angle of 32.6° from horizontal and the acceleration due to gravity is 9.8 m/s².

The ball will follow projectile motion when kicked and the equation for finding time in a projectile motion is given by:

t = d/vcosθ

=> t = 54/(26×cos32.6°)

=> t = 2.5 s

Now newton's second equation of motion for finding distance in y direction is given by:

S= ut - 1/2(at²)

S=(26sin32.6°)2.5 - 1/2(9.8×2.5²)

S= 4.39m

Therefore, the vertical distance with which the ball clears the crossbar is given by x= 4.39 - 3.05 = 1.34m

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A bicycle with 26-inch diameter wheels is traveling at 20 mi/h. Find the angular speed of the wheels in rad/min.

______radians per minute

___revolutions per minuteω =  1320 rad/min, Revolution per minutes = 210.084

Diameter = 24 in

Radius r = 24/2 in = 12 in = 12 × 2.54 cm = 30.48‬ cm = 0.3048 m

Linear Speed v= 15 mi/hr = 15 * 1609.34 / 3600 m/s = 6.7056 m/s

Angular Speed ω = v / r = (6.7056 m/s) / (0.3048 m) = 21.999945

ω =  22 rad/s = 22× 60 rad/min = 1320 rad/min

∴ 1 revolution = 2π rad

⇒1 rad = 1 / 2π rev

so 1320 rad/min = 1320 / 2π  rev/min = 210.0845 rev/min

Revolution per minutes = 210.0845

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A free-falling item is one that is falling solely as a result of gravity, as was discovered in the previous section of this course. A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth).

Its acceleration due to gravity is the acceleration that an object experiences as a result of gravitational force. M/s2 is its SI unit. Gravitational acceleration is a vector, meaning it has a magnitude and a direction. The universal gravitational constant, G, is unaffected by the type of particle, the medium separating the particles, or the passage of time. Because its value is consistent throughout the cosmos, it is referred to as "universal."

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Answer: ill do deeper reaseach because thats hard

Explanation:

The magnitude of resultant vector R = A + B is 12.23 if the act at 140° to each other.

We know that,

A + B = √ ( A² + B² + 2AB cos θ )

Given that,

A = 16.2

B = 6

θ = 140°

A + B = √ ( 16.2² + 6² + ( 2 * 16.2 * 6 * cos 140° ) )

R = √ ( 262.44 + 36 - 148.91 )

R = √ 149.52

R = 12.23

The magnitude of a vector is the numeric value of a vector. It gives the individual values vectors along x, y and z axis.

Therefore, the magnitude of resultant vector is 12.23

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The height reached by the ball is 78.4 m.

Height can be defined as the vertical distance between two points.

To calculate the height reached by  the ball, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the height reached by the ball is 78.4 m.

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One must drive at a speed of 62.5 miles per hour to reach the theatre at time.

Time movie starts in: 40 minutes

Time taken to drive to friend's house: 10 minutes

Time taken to drive to the theatre from friend's house:  15 minutes

Speed = 40 miles per hour

Using the formula to find the distance:

Speed = Distance/Time

40 = Distance/(15/60)

40*0.25 = Distance

10 miles is the distance from the friend's house to the theatre

Now, time taken by friends while playing games = 20 minutes

Time remaining = 40 - 10 - 20 = 10 minutes

The distance required to be covered in 10 minutes is 10 miles

Therefore, using the formula we get:

Speed = 10/(10/60)

Speed = 62.5 miles per hour

Hence, one should drive at a speed of 62.5 miles per hour to reach the theatre on time

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Answer:

0

Explanation:

it takes 84 years for Uranus to orbit the Sun. It only takes 12 years for Jupiter to orbit the Sun. So technically by the time that Jupiter finishes it's one, Uranus will not be able to even finish half of its orbit.

Answer:

[tex]{ \tt{X( \omega) = x(t)}}[/tex]

the final horizontal velocity of the soccer ball is 16.53 (m/s)

Typically, horizontal velocity is defined as horizontal displacement divided by time, expressed in units like meters per second or miles per hour. Simply put, displacement is the separation of a thing from its origin. V stands for the needed soccer ball's initial horizontal velocity (in m/s). T stands for the soccer ball's time of flight, expressed in seconds. The kinematic relations that result from the data given are as follows:

22 = 0 + (1/2) *g*T^2 [g = acceleration due to gravity]

or T^2 = 44/g

or T = √(44/g)

35 = V*T

or V = 35/T

or V = 35*√(g/44)

or V = 35*√ (9.81/44) (Assumed) g = 9.81 m/s2

V = 16.53 (m/s)

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Answer: F=400 N

Explanation:

F=ma ==> F=force, m=mass, a=acceleration

F=100*4

F=400 N

The amount of velocity does the man who standing on a frictionless ice surface move across the ice(V)= 1 m/s in the opposite direction as the book.

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled.

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Here we are given that,

Apply the law of linear momentum

Before the throw:

M₁=Man initial mass= 80kg,

U₁=Man's initial velocity = 0,

M₂=Book  initial mass = 4kg,

U₂=Book's initial velocity = 0.

After the throw:

M₁=Man final mass = 80kg,

V₁=Man's final velocity = V.

M₂=Book final mass = 4kg,

V₂=Book final velocity = 20.

Now we put the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80x0) + (4x0) = (80V) + (4x20)

Or, 0=80V + 80

Or, 80V = -80

Or, V = -80/80

Or, V= -1m/s.

From the above calculation we can conclude that,

The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book

[Note: The (-)Ve sign shows that the opposite direction]

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The tendency of an atom to attract electrons (or electron density) to itself is measured by its electronegativity. It determines the distribution of the shared electrons between the two atoms in a bond. The stronger an atom's electronegativity, the more strongly it would attract electrons to its bonds.

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