Answer:
Ac = v²/r
where, Ac is centripetal acceleration
v is velocity
r is radius
5 = (20)²/r
r = 400/5
r = 80m
from,
w = 2πf
where, w = angular velocity and f frequency
w = v/r
f = n/T
then,
v = 2πrn ,n = 1 to complete 1 cycle
T
T = 2πr/v
T = 2π*80/20
T = 25.14seconds.
The car would take 25.14s to complete 1 cycle of the roundabout.
what is deviation of light by prism
Answer:
When a ray of light passes from one medium to another it changes its path, this phenomenon of light is called the deviation of light. When a ray of light passes through a prism it suffers refraction twice. Once while it enters the prism and again while it emerges from it.
When the pushing force is increased to 88.2 N, the box just begins to move. What is the Friction Force if it is moving at a constant velocity? What is the coefficient of friction between the ground and box?
In order to calculate frictional force look below..
The formula given by
[tex]\\ \sf\longmapsto F_f=\mu N[/tex]
Or
[tex]\\ \sf\longmapsto F_f=\mu mg[/tex]
u is coefficient of friction
N is normal reaction.
Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?
the electrical energy used to pump the water up to a mountain lake is 1.2 x 10 to the power 12 J only 6.2 x 10 to the power 11 J of electrical energy is generated when the water is released calculate the efficiency of this energy storage scheme
Answer:
Explanation:
ake is 1.2 x 10^12 J. Only 6.2 x 10^11 J of electrical energy is generated when the water is released. Calculate the efficiency of this energy
How did ancient organisms become fossil fuels?
Answer:
One of the most widespread beliefs about fossil fuels — oil, natural gas and coal — is that these substances started out as dinosaurs. There’s even an oil company, Sinclair, that uses an Apatosaurus as its icon. That dino-source story is, however, a myth. What is true: These fuels got their start long, long ago — at a time when those “terrible lizards” still walked the Earth.
Fossil fuels store energy in the bonds between the atoms that make up their molecules. Burning the fuels breaks apart those bonds. This releases the energy that originally came from the sun. Green plants had locked up that solar energy within their leaves using photosynthesis, millions of years ago. Animals ate some of those plants, moving that energy up the food web. Others plants just died and decayed.
Any of these organisms, when they die, can be turned into fossil fuels, notes Azra Tutuncu. She’s a geoscientist and petroleum engineer at the Colorado School of Mines in Golden. But it takes the right conditions, including an oxygen-free (anoxic) environment. And time. A whole lot of time.
The coal we burn today got its start some 300 million years ago. Back then, dinosaurs roamed the Earth. But they didn’t get incorporated into coal. Instead, plants in bogs and swamps died. As this greenery sunk to the bottom of those wet areas, it partially decayed and turned into peat. Those wetlands dried out. Other materials then settled down and covered the peat. With heat, pressure and time, that peat transformed into coal. To extract coal, people now have to dig deeply into the earth.
Ancient living organisms are buried quickly and altered by intense heat and pressure to form fossil fuels. Fossil fuels include solid coal, liquid petroleum, and liquid natural gas.
Source; Goo_gle
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Why potential energy is remian constant when solid body is heated?
When adding vectors, what cannot change?
A. the vectors' length and direction
B. anything can change
C. only the vectors' length
D. only the vectors' direction
please help!!
Answer:
A
Explanation:
you cannot change the length and direction
number A is right I think
Question 2 of 10
You are riding a bicycle. If you apply a forward force of 125 N, and you and
the bicycle have a combined mass of 82 kg, what will be the forward
acceleration of the bicycle? (Assume there is no friction.)
A. 1.67 m/s2
B. 3.37 m/s2
C. 0.66 m/s2
D. 1.52 m/s2
O
Answer:
D - 1.52 m/s2
Explanation:
force: 125 N
Mass: 82 kg
you just divide the force by the mass which would be approximately 1.52
What provides the centripetal force for the moon's orbit around Earth?
Answer:
Gravitational attraction provides the centripetal force needed to keep planets in orbit around the Sun and all types of satellite in orbit around the Earth. This centripetal force is supplied by gravity. The Earth's gravity keeps the Moon orbiting us. Centripetal force is perpendicular to velocity and causes uniform circular motion. The gravitational attraction of the Sun is an inward force acting on Earth. This force produces the centripetal acceleration of the orbital motion. Centripetal forces are always directed toward the center of the circular path.
Explanation:
Answer: C.
the gravitational pull of the Sun
Explanation: plato :3
Hope this helps!
identify impacts of air pollution
Answer:
Explanation:
High levels of air pollution can cause an increased risk of heart attack, wheezing, coughing, and breathing problems, and irritation of the eyes, nose, and throat. Air pollution can also cause worsening of existing heart problems, asthma, and other lung complications.
Ambient air pollution accounts for an estimated 4.2 million deaths per year due to stroke, heart disease, lung cancer and chronic respiratory diseases. Around 91% of the world's population lives in places where air quality levels exceed WHO limits.
Serious Effects of Pollution on Our Humans and Environment
Environment Degradation. The environment is the first casualty for the increase in pollution weather in air or water. ...
Human Health. ...
Global Warming. ...
Ozone Layer Depletion. ...
Infertile Land.
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1. A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?
a. 0.4 kg
b. 1.6 kg
c. 2.4 kg
d. 0.8 kg
2. Which of the following would be a situation with unbalanced forces?
a. Two people pulling on the same side of a wheelbarrow
b. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d. Two people not touching a crate that is sitting stationary.
3. Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary
a. The force of gravity on the object is different if it is stationary or not.
b. The force of friction on the object is different if it is stationary or not
c. The force of the push on the object is different if it is stationary or not
d. The normal force on the object is different if it is stationary or not.
Thanks In Advance!! (I will mark brainliest) :)
Answer:
1. A. 0.4 kg
2. B. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
3. If an object is stationary the net force is zero.
3. B. The force of friction on the object is different if it is stationary or not
Explanation:
2. If two tug of war teams were pulling with the same force, neither team would move the rope would be at a stand still.
Answer:
The above person to the right is correct except for Number 2. The answer for that will be a.
Explanation:
Remember that equal is a big hint that the scenario is balanced forces since all forces are canceling out thus the object doesn't move. In a. two people are pulling a wheel barrel on the same side. This means one side has more force than the other hence the wheel barrel moves.
Un avión vuela horizontalmente con una velocidad de 800 km/h y deja caer
un proyectil desde una altura de 500 respecto al suelo. a) ¿Cuánto tiempo
transcurre antes de que el proyectil se impacte en el suelo?; b) ¿Qué distancia
horizontal recorre el proyectil después de iniciar su caída?
The projectiles launch allows to find the results for the questions of the launch of the bomb are:
a) The fall time is: t = 10.1 s
b) The distance traveled is: x = 2.24 10³ m
Projectile launching is an application of kinematics where the acceleration on the x-axis is zero and the acceleration on the y-axis is gravity acceleration.
a) Let's find the time until we reach the ground.
The initial vertical velocity is zero, the initial height is I = 500 m, when reaching the ground its height y = 0.
[tex]y = y_o + v_o_y - \frac{1}{2} g t^2[/tex]
0 = y₀ + 0 - ½ g t²
t = [tex]\sqrt{\frac{2y_o}{g}[/tex]
t = [tex]\sqrt{\frac{2 \ 500}{9.8} }[/tex]
t = 10.1 s
b) We look for the horizontal distance traveled.
Let's reduce to the international measurement system (SI).
v = 800 km / h ([tex]\frac{1000m}{1km}[/tex]) ([tex]\frac{1h}{3600s}[/tex]) = 222.22 m / s
x = vₓ t
x = 22.22 10.1
x = 2.24 10³ m
In conclusion, using the projectile launch relationships, we can find the results for the questions that are:
a) The fall time is: t = 10.1 s
b) The distance traveled is: x = 2.24 10³ m
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What element is chemically similar to carbon
nonmental
that should be the answer
Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
What is the maximum height of the cannonball?
Explanation:
The final velocity at the cannon ball's maximum height is zero ([tex]v_y = 0[/tex]). We can use the equation
[tex]v_y^2 = 0 = v_{0y}^2 - 2gy_{max}[/tex]
[tex]\Rightarrow y_{max} = \dfrac{v_{0y}^2}{2g}[/tex]
[tex]y_{max} = \dfrac{(25\:\text{m/s})^2}{2(9.8\:\text{m/s}^2)}[/tex]
[tex]\:\:\:\:\:\:\:=31.9\:\text{m}[/tex]
An object of mass 1.0 kg is at rest on a smooth inclined plane with height h, length 8 m,
and which makes an angle of 30° with the horizontal. The object is allowed to move, it
slides down and onto a rough horizontal surface. After traveling a distance of 4 m it hits a spring and travels 1.3 m more, all along the rough horizontal surface. The spring
constant is 26.5 N/m. What is the coefficient of kinetic friction for the horizontal surface?
The coefficient of kinetic friction for the rough horizontal surface is 0.66.
The given parameters;
mass of the object, m = 1 kglength of the inclined plane, L = 8 mangle of inclination of the plane, θ = 30⁰ distance traveled before hitting the spring, d₁ = 4 mdistance traveled after hitting the spring, d₂ = 1.3 mthe spring constant, k = 26.5 N/mApply work-energy theorem; the work done the force of friction is equal to the energy stored in the spring.
[tex]F_kd_1 = \frac{1}{2} kd_2^2\\\\\mu_kmg cos(\theta)d_1 = \frac{1}{2} kd_2^2\\\\\mu_k(1 \times 9.8 \times cos(30)\times 4) = \frac{1}{2} \times 26.5 \times (1.3)^2\\\\33.95\mu_k = 22.39\\\\\mu_k = \frac{22.39}{33.95} \\\\\mu_k = 0.66[/tex]
Thus, the coefficient of kinetic friction for the rough horizontal surface is 0.66.
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A rock falls to the ground with a force of 300N and air resistance pushes back up on the rock with a
force of 45N. Which is true of the rock?
Answer:
what are the choices
Explanation:
don't worry i'll edit it
1. According to the picture, which is the least dense?
O A. the chess piece
O B. the toy soldier
O C. the liquid in the container
O D. There is no way to tell,
According to the picture, the chess piece is the least dense. The correct option is A.
The amount of mass that a substance has in relation to its volume is referred to as its density. It is a measurement of how closely together the molecules or particles are arranged within a given object or material.
Typically, floating objects are less dense than the liquid they are in. The fact that the chess piece is floating on the water suggests that it is less dense than the liquid.
It might be an alternative, though, if the toy soldier is also floating and not submerged. More visual context is necessary for precise determination.
Thus, the correct option is A.
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Lab: Motion with Constant Acceleration Assignment: Lab Report
Write your lab report
Someone please help me do this, ill give brainliest
Answer:
Table C:
Fan Speed Observations of Position vs. Time Graphs
Low:
The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.
Medium:
The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.
High:
The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.
Explanation:
hope it helps
Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.
Materials:
Smooth, inclined plane
Cart or tiny wheeled object
Stopwatches and timers
Measuring tape or meterstick
Procedure:
Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.
Place the cart or small wheeled object at the bottom of the inclined plane.
Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.
Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.
As soon as the cart is freed and begins to move, start the stopwatch or timer.
Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.
Determine the time intervals (Δt) between each position for velocity analysis
Data:
Position (m) Time (s) Time Interval (Δt) (s)
0.0 0.00 -
0.5 0.50 0.50
1.0 0.75 0.25
1.5 1.10 0.35
2.0 1.50 0.40
Analysis:
Calculate the average velocity between each position by dividing the position change by the time interval (x/t).
Create a graph that plots average velocity (V_avg) versus time (t).
Results:
A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.
Conclusion:
The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.
Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
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If a rock is thrown vertically upward from the surface of Mars with velocity of 20 m/s, its height (in meters) after t seconds is h = 20t − 1.86t2. (a) What is the velocity (in m/s) of the rock after 2 s? 12.56 Correct: Your answer is correct. m/s (b) What is the velocity (in m/s) of the rock when its height is 25 m on its way up? On its way down? (Round your answers to two decimal places.) up 8.07 Incorrect: Your answer is incorrect. m/s down -8.07 Incorrect: Your answer is incorrect. m/s
The velocity of the rock after 2s is 12.56 m/s.
The velocity of the rock at 25 m upwards is 14.68 m/s.
The velocity of the rock at 25 m downwards is -15.97 m/s.
The given parameters;
velocity of the rock, u = 20 m/sheight of the rock, h = 20t - 1.8t²The velocity of the rock after 2s is calculated as follows;
[tex]v = \frac{dh}{dt}= 20 -2(1.86)t \\\\v = 20 - 3.72t\\\\at \ t= 2 \ s \\\\v = 20 - 3.72(2) = 12.56 \ m/s[/tex]
The velocity of the rock when the height is 25 m:
h = 20t - 1.8t²
25 = 20t - 1.8t²
1.8t² - 20t + 25 = 0
solve for the time of motion "t" using quadratic formula
a = 1.8, b = -20, c = 25
[tex]t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-(-20) \ \ +/- \ \ \sqrt{(-20)^2 - 4(1.8\times 25)} }{2(1.8)}\\\\t = 9.67s, \ \ or \ 1.43 \ s[/tex]
The value of t that will give 25 m upwards using the motion model is 1.43 s;
h = 20(1.43) - 1.86(1.43)² = 25 m
The velocity of the rock at 25 m upwards (t = 1.43 s) is calculated as follows;
[tex]v = \frac{dh}{dt} = 20 -3.72t\\\\v = 20 - 3.72(1.43) \\\\v = 14.68 \ m/s[/tex]
The velocity of the rock at 25 m downwards (t = 9.67 s) is calculated as;
[tex]v = \frac{dh}{dt} = 20 - 3.72t\\\\v = 20 - 3.72(9.67)\\\\v = -15.97 \ m/s[/tex]
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What does it mean when my teacher asks me to "use appropriate figures"?
Answer:
In science
Explanation:
When a teacher tells you so use the appropriate figures. He/she means to use the proper amount of Sig figs or Significant digits.
Example: Is the picture
In the example the answer is 7.31 because you have to take the less number of significant digits
Answer:
figures that are relevant or suitable for the question asked
1.Which term describes the sum of the number of protons and neutrons in an atom?
Your answer is → Mass number
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
A Wheatstone Bridge type circuit is shown (10marks) R1=20ohms, R2=10ohms, R3=8ohms, R4=5ohms, and R5=2ohms and also has 10V battery. Determine A. the p.d. between terminals B and D, and (5 marks) B. The value to which R4 must be adjusted in order to reduce the current through R3 to zero (balance the bridge). (5marks)
Answer:
Dunno
Explanation:
Dunno
Two horses are side by side on a carousel. Which has a greater tangential speed the one closer to the center or the one farther from the center? Explain your answer.
Answer:
The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.
Explanation:
Consider the frame shown in (Figure 1). The suspended cylinder has a mass of 90 kg .
Determine the x and y components of reaction at pin B on BC using scalar notation.
Determine the x and y components of force at pin C using scalar notation.
A system in equilibrium has a moment sum of zero and the sum of upward
forces equal to the sum of the downward forces.
The correct values are;
The x and y component of the reaction at pin B are;
Bₓ = 1471.5 N
[tex]B_y[/tex] = 1103.625 N
The x and y component of the force at pin C are;
Cₓ = 588.6 N
[tex]C_y[/tex] = 220.725 N
Reasons:
The weight of the cylinder, W = 90 kg × 9.81 m/s² = 882.9 N
Considering member AB, gives;
[tex]\sum M_A[/tex] = [tex]B_y[/tex] × 2 - [tex]B_x[/tex] × 1.5 = 0 ⇒ [tex]B_y[/tex] = 0.75·Bₓ
Considering member CB, gives;
[tex]\mathbf{\sum M_C}[/tex] = -[tex]B_y[/tex] × 2 + 882.9 × 2.5 = 0 ⇒ [tex]B_y = \dfrac{882.9 \times 2.5}{2} = 1103.625[/tex]
[tex]B_y[/tex] = 0.75·Bₓ ⇒ [tex]B_x = \dfrac{B_y}{0.75} = \dfrac{1103.625}{0.75} = 1471.5[/tex]
The x and y component of the reaction at pin B are;
Bₓ = 1471.5 N, [tex]B_y[/tex] = 1103.625 N
[tex]\mathbf{\sum F_y}[/tex] = 0 ⇒ -[tex]C_y[/tex] + [tex]B_y[/tex] - 882.9 = 0 ⇒ [tex]-C_y[/tex] + 1103.625 - 882.9 = 0
[tex]C_y[/tex] = 1103.625 - 882.9 = 220.725
[tex]\sum F_x[/tex] = 0 ⇒ -Cₓ + Bₓ - 882.9 = 0 ⇒ -Cₓ + 1471.5 - 882.9 = 0
Cₓ = 588.6
The x and y component of the reaction at pin C are;
Cₓ = 588.6 N, and [tex]C_y[/tex] = 220.725 N
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Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2
Due to the fact that no one can consume .04 of a tablet, we can round down this answer to 1. This means that Mr. Jones should take C- 1 tablet per day.
I hope I've helped! :)
Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, he should take 1 tablet per day. The correct option is C.
What is prescription?The doctor suggests the medicine to be taken by the patient for the treatment of any disease or symptom is called as prescription.
Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, Mr. Jones must take 1 tablet per day.
No one can consume .04 of a tablet, we can round off 1.04 to 1. This means that Mr. Jones should take 1 tablet per day.
Thus, the correct option is C.
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A brick is thrown upward from the top of a building at an angle of 25 degrees to the horizontal with an initial speed of 15 m/s. If the brick is in flight for 4 s before it hits the ground, how tall is the building?
Answer:
First, find the maximum height, which according to the values given, can be stated as:
H=(u²sin²theta)/2g
u=15m/s, theta=25 degrees, g=9.8m/s²
H= (15² * (sin 25)²))/2*9.8
H= (225*0.179)/19.6
H= 40.275/19.6
=2.06m
To find the velocity at maximum height:
Use the formula
v²=u²-2gH
It's minus because the brick was thrown upwards
So plugging everything into the above formula:
v²=15²-2*9.8*2.06
v²=225–40.376
v²=184.624
v=√184.624
v=13.59m/s
What is the most likely reason for some antelope to employ selective brain cooling
Answer:
The brain is a part of the body that is particularly sensitive to high temperature. Hence some ungulates, like the Thomson's gazelle, use a counter-current heat exchanging structure known as the carotid rete to keep the brain cooler than the body.The cooled arterial blood then continues toward the brain.
From what material did the moon form?How are eras and periods of the geologic time scale named?
Answer:
this
Explanation:
because of this its this ok
Answer: They are named for the places where geologists first described rocks or fossils from that time.
Explanation: ingenuity
10 basic rules of badminton?
Explanation:
Rules
A match consists of the best of three games of 21 points.
The player/pair winning a rally adds a point to its score.
At 20-all, the player/pair which first gains a 2-point lead wins that game.
At 29-all, the side scoring the 30th point wins that game.
The player/pair winning a game serves first in the next game.
A badminton match can be played by two opposing players (singles) or four opposing players (doubles).
A competitive match must be played indoors utilising the official court dimensions.
A point is scored when the shuttlecock lands inside the opponent's court or if a returned shuttlecock hits the net or lands outside of the court the player will lose the point.
At the start of the rally, the server and receiver stand in diagonally opposite service courts.
A legal serve must be hit diagonally over the net and across the court.
A badminton serve must be hit underarm and below the server's waist height with the racquet shaft pointing downwards, the shuttlecock is not allowed to bounce. After a point is won, the players will move to the opposite serving stations for the next point.
The rules do not allow second serves.
During a point a player can return the shuttlecock from inside and outside of the court.
A player is not able to touch the net with any part of their body or racket.
A player must not deliberately distract their opponent.
A player is not able to hit the shuttlecock twice.
A 'let' may be called by the referee if an unforeseen or accidental issue arises.
A game must include two rest periods. These are a 90-second rest after the first game and a 5-minute rest after the second game.