A penguin is trying to cross the street. It’s velocity v as a function of time t is given in the graph below where rightwards is the positive velocity given. At what time does the penguib have the same positition as t = 0s?

Answer:Gg

Explanation:

Answer:

W=f*d

= 50 * 15

=750 J

Therefore, the work done is 750 joule( J)

Answer:

100N.

Its 100n. :)

Answer:

1st law of motion

Explanation:

it's newton's first law of motion.

Answer:

A C E

Explanation:

Answer:

B

Explanation:

Holding the balloon closer to the stream of water

Holding the balloon closer to the stream of water is an action which would increase the strength of the electric force between the balloon and the water. Thus, the correct option is B.

The repulsive or attractive interaction between any two charged bodies is called as the electric force. This is similar to any force, the impact and effects on the given body are described through the Newton's laws of motion. The electric force is one of the various forces which act on objects.

Electric force is the attractive force which is present between the electrons (negatively charged bodies) and the nucleus. Here, a positive charge or a negative charge creates a field in the empty space which is around it, and we call that empty space as an electric field.

Holding the balloon closer to the stream of water is an action which would increase the strength of the electric force between the balloon and the water.

Therefore, the correct option is B.

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Answer:

hello questions under analysis B are not complete hence I couldn't provide its answers

1)

2) The average expected value is 1000 k ohms

Explanation:

1) The difference between AA and AAA batteries

some of the differences are

2) The average expected value is 1000 k ohms

also it is necessary to measure the resistor because the actual value of resistance gotten from measurement is always different from the value obtained from color coding. also note that The last color band indicates the tolerance.

and the resistor given has Gold as its last color band

Answer:

From the question we are told that

  The length of the rod is  [tex]L_o[/tex]

    The  speed is  v  

     The angle made by the rod is  [tex]\theta[/tex]

Generally the x-component of the rod's length is  

     [tex]L_x =  L_o cos (\theta )[/tex]

Generally the length of the rod along the x-axis  as seen by the observer, is mathematically defined by the theory of  relativity as

       [tex]L_xo  =  L_x  \sqrt{1  - \frac{v^2}{c^2} }[/tex]

=>     [tex]L_xo  =  [L_o cos (\theta )]  \sqrt{1  - \frac{v^2}{c^2} }[/tex]

Generally the y-component of the rods length  is mathematically represented as

      [tex]L_y  =  L_o  sin (\theta)[/tex]

Generally the length of the rod along the y-axis  as seen by the observer, is   also equivalent to the actual  length of the rod along the y-axis i.e [tex]L_y [/tex]

    Generally the resultant length of the rod as seen by the observer is mathematically represented as

     [tex]L_r  =  \sqrt{ L_{xo} ^2 + L_y^2}[/tex]

=>  [tex]L_r  = \sqrt{[ (L_o cos(\theta) [\sqrt{1 - \frac{v^2}{c^2} }\ \ ]^2+ L_o sin(\theta )^2)}[/tex]

=>  [tex]L_r= \sqrt{ (L_o cos(\theta)^2 * [ \sqrt{1 - \frac{v^2}{c^2} } ]^2 + (L_o sin(\theta))^2}[/tex]

=>   [tex]L_r  = \sqrt{(L_o cos(\theta) ^2 [1 - \frac{v^2}{c^2} ] +(L_o sin(\theta))^2}[/tex]

=> [tex]L_r =  \sqrt{L_o^2 * cos^2(\theta)  [1 - \frac{v^2 }{c^2} ]+ L_o^2 * sin(\theta)^2}[/tex]

=> [tex]L_r  =  \sqrt{ [cos^2\theta +sin^2\theta ]- \frac{v^2 }{c^2}cos^2 \theta }[/tex]

=> [tex]L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }[/tex]

Hence the length of the rod as measured by a stationary observer is

       [tex] L_r = L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }[/tex]

   Generally the angle made is mathematically represented

[tex]tan(\theta) =  \frac{L_y}{L_x}[/tex]

=>  [tex]tan {\theta } =  \frac{L_o sin(\theta )}{ (L_o cos(\theta ))\sqrt{ 1 -\frac{v^2}{c^2} } }[/tex]

=> [tex]tan(\theta ) =  \frac{tan\theta}{\sqrt{1 - \frac{v^2}{c^2} } }[/tex]

Explanation:

The special relativity relations allow to find the results for the questions about the measurements made by an observed at rest on the rod are:

     a) The length of the rod is: [tex]L = L_o \sqrt{1 - \frac{v^2}{c^2} \ cos^2\theta_o }[/tex]  

     b) The angle with respect to the x axis is:   [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }[/tex]

Special relativity studies the motion of bodies with speeds close to the speed of light, with two fundamental assumptions.

If we assume that the two systems move in the x-axis, the relationship between the components of the length are:

        [tex]L_x = L_{ox} \ \sqrt{1- \frac{v^2}{c^2} }[/tex]  

        [tex]L_y = L_o_y \\L_z = L_{oz}[/tex]  

Where the subscript "o" is used for the fixed observed on the rod, that is, it is at rest with respect to the body, v and c are the speed of the system and light, respectively.

a) They indicate that the length of the rod is L₀ and it forms an angle θ with the horizontal.

Let's use trigonometry to find the components of the length of the rod in the system at rest, with respect to it.

         sin θ = [tex]\frac{L_{oy}}{L_o}[/tex]  

         cos θ = [tex]\frac{L_{ox}}{L_o}[/tex]  

         [tex]L_{oy}[/tex] = L₀ sin θ

         L₀ₓ = L₀ cos θ

Let us use the transformation relations of the length of the special relativity rod.

x-axis

      [tex]L_x = (L_o cos \theta_o) \ \sqrt{1- \frac{v^2}{c^2} }[/tex]  

y-axis  

      [tex]L_y = L_{o} sin \theta_o[/tex]  

The length of the rod with respect to the observer using the Pythagorean theorem is:

      L² = [tex]L_x^2 + L_y^2[/tex]  

      [tex]L^2 = (L_o cos \theta_o\sqrt{1- \frac{v^2}{c^2} })^2 + (L_o sin \theta_o)^2[/tex]

      [tex]L_2 = L_o^2 ( cos^2 \theta_o - cos^2 \theta_o \frac{v^2}{c^2} + sin^2\theta_o)[/tex]  

      [tex]L^2 = L_o^2 ( 1 - \frac{v^2}{c^2} \ cos^2 \theta_o)[/tex]  

      [tex]L= Lo \sqrt{1- \frac{v^2}{c^2} cos^2 \theta_o}[/tex]  

b) the angle with the x-axis measured by the stationary observer is:

     [tex]tna \theta = \frac{L_y}{L_x}[/tex]

    [tex]tan \ theta = \frac{L_o sin \theta_o}{L_o cos \theta_o \sqrt{1- \frac{v^2}{c^2} } }[/tex]  

    [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]  

In conclusion, using the special relativity relations we can find the results for the questions about the measurements made by an observed at rest on the rod are:

      a) The length of the rod is:  [tex]L = L_o \sqrt{1- \frac{v^2}{c^2} \ cos^2\theta_o }[/tex]

      b) The angle to the x axis is:  [tex]tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }[/tex]

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Answer:

false because they have no fee electrons

False, it is a poor conductor of heat. They are great insulators though.

Answer:

B. The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly

Answer:

The control rods absorb excess neutrons, keeping them from causing too many uranium atoms to split too quickly.

Explanation:

I took the test before.  

You can see my other article just search in search engine with: Learningandassignments diy4pro

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Nuclear Energy- Quiz

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Newton's First Law of Motion states "An object continues to be in its state of rest or of uniform motion along a straight line unless acted upon by an unbalanced force".

Answer:

red I think

Explanation:

it's on red so I googled some of it and the closest was red

Answer:

Red

Explanation:

Assuming it takes off from rest, the runway should have length x such that

(148 m/s)² - 0² = 2 (3 m/s²) x

which follows from the formula,

v² - u² = 2 a ∆x

(where u is initial speed and v is final speed; the other two's significance should be obvious)

Solve for x :

x = (148 m/s)² / (2 (3 m/s²))

x ≈ 3650.67 m

Answer:

30.52 °F

1572 lbs/ft²

0.0019 slug/ft³

Explanation:

Given that

Pressure at sea level, P₁ = 14.8 PSI

Temperature, T₁ = 80 °F

At 8,000 ft (m) altitude

for altitude h, less than 36000 ft, the model used to modify temperature and pressure is written below

T = 59 - 0.00356h, where h is the altitude

T = 59 - 0.00356(8,000)

T = 59 - 28.48

T = 30.52 °F

Next, we find the pressure which is calculated using the formula

P = 2116 [(T + 459.7)/518.6]^5.256

P = 2116 [(30.52 + 459.7) / 518.6]^5.256

P = 2116 [490.22/518.6]^5.256

P = 2116 (0.945)^5.256

P = 2116 * 0.743

P = 1572 lbs/ft²

The density is gotten using the formula

ρ = P / [1718 (T + 459.7)]

ρ = 1572 / [1718 (30.52 + 459.7)]

ρ = 1572 / (1718 * 490.22)

ρ = 1572 / 842198

ρ = 0.0019 slug/ft³

The average speed of the girl is 2.26 m/s.

The average speed is calculated by dividing the total distance traveled by the total time taken. In this case, the girl traveled a total distance of 120 m + 80 m = 200 m. She took a total time of 15 s + 12 s = 27 s to travel this distance.

Therefore, the average speed is:

average speed = total distance / total time

average speed = 200 m / 27 s

average speed = 2.26 m/s

The average speed does not take into account the direction of the motion. The girl traveled in two different directions, so the average speed is not a meaningful measure of her speed.

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Answer:

2

Explanation:

It is simple coman sense

Answer:

cause it too powerful lol ;)

Answer:

30m/s

Explanation:

m1v1=m2v2

12 * 10=4* v2

120/4 =v2

V2=30m/s

Answer:

they have opposite charges

Answer:

I think it’s adding neutrons

Explanation:

Answer:

Maybe when you bump into the refrigerator and the magnet falls?

Explanation:

This is an example of you interacting with electromagnetics because you must have bumped into something and made a magnet fall.

I hope it helps?

If it does help can I have a brainliest?

Answer:

C

Explanation:

because it is TM

Answer:

could u give a more longer understanding

Answer:

3.8 m/s/s^2

Explanation:

The acceleration due to gravity on the planet where a 80 kg astronaut weighs only 304 N is 3.8 m/s².

The gravitational force is the force by which an object attracts other objects into its centre of mass. The force it exerts depends on the mass of the body and distance between them. Earth attracts every objects on its surface to the ground by gravitational force

The acceleration arises in the body due to the force of gravitation is called acceleration due to gravity (g). It varies from planets to planet. The weight we experience in earth is due to the gravity.

Weight = m g

where m is the mass.

given the mass of an astronaut = 80 kg

weight  = 304 N

then g = weight/ mass

           = 304 N / 80 Kg = 3.8 m/s²

Therefore, the acceleration due to gravity of the planet is 3.8 m/s².

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Answer:

Explanation:

The kinetic energy of the  145g is

mass= 0.145kg

velocity= 37m/s

KE=1/2mv^2

KE=1/2(0.145*37^2)

KE=1/2(0.145*1369)

KE=1/2(198.505)

KE=198.505/2

KE=99.25J

Now since the kinetic energy of the 2.7g must be 99.25J

mass =2.7g= 0.0027kg

99.25=1/2(0.0027)v^2

99.25=0.00135v^2

99.25/0.00135=v^2

73518.5185185=v^2

v=√73518.5185185

v=271.14m/s

Answer:

  7) 5 m/s

  8) 1.5 m/s

  9) -9 m/s^2

  10) 2.2 m/s

  11) 5 s

Explanation:

These problems make use of the relations:

  a = ∆v/∆t

  d = 1/2at^2 . . . . acceleration to/from rest

  v^2 = 2ad . . . . . acceleration to/from rest

In each case, choose the formula appropriate to the question, fill in the given values, and solve for what's missing.

__

7) v^2 = 2ad

  v = √(2(9.8 m/s^2)(1.5 m)) = √(29.4 m^2/s^2) ≈ 5 m/s

__

8) d = 1/2at^2

  a = 2d/t^2 = 2(75 m)/(10 s)^2 = 1.5 m/s^2

__

9) a = ∆v/∆t

  a = (-45 m/s)/(5 s) = -9 m/s^2

__

10) a = ∆v/∆t

  ∆v = a·∆t = (0.09 m/s^2)(10 s) = 0.9 m/s

Vivian's final speed is the initial speed plus the change in speed:

  1.3 m/s + 0.9 m/s = 2.2 m/s

__

11) a = ∆v/∆t

  ∆t = ∆v/a = (0.50 cm/s -0.75 cm/s)/(-0.05 cm/s^2) = -.25/-.05 s = 5 s

Answer:

7.34x

Explanation:

Depends on how long it was in the air. 7.34x, x is how many seconds.

Answer:

Looks like a cosine function graph. The wave pattern is transversal waves . The faster the amplitude the higher the wave. The force of the drop hitting the water pushes the water down and out causing waves  If the water hits from a higher amplitude the waves raise bigger . When you increase the frequency of the water drops the waves move faster but no bigger.  When you increase the frequency of the water drops the wave ripples faster .

Explanation:

An answer to part of your question

A transverse wave is the kind of wave pattern I observe in the sink in the top view.

Transverse waves

A transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations

Answer: Peregrine falcons are famed for their high-speed, high-altitude stoops. Hunting prey at perhaps the highest speed of any animal places a stooping falcon under extraordinary physical, physiological, and cognitive demands, yet it remains unknown how this behavioural strategy promotes catch success. Because the behavioral aspects of stooping are intimately related to its biomechanical constraints, we address this question through an embodied cognition approach. We model the falcon’s cognition using guidance laws inspired by theory and experiment, and embody this in a physics-based simulation of predator and prey flight. Stooping maximizes catch success against agile prey by minimizing roll inertia and maximizing the aerodynamic forces available for maneuvering but requires a tightly tuned guidance law, and exquisitely precise vision and control.

Explanation: