Answer:
[tex]take \: the \: number = x \\ thenx \times 6 = 2 \times 19 \\ \\ 6x = 38 \\ x = \frac{38}{6} \\ x = 6.33 \\ thank \: you[/tex]
Help me out please! Anybody? I’m so confused
A man is considered overweight if he has a body mass index of 27.8 kg/m2 or greater. This point is used because it represents the sex-speci c 85th percentile for males 20-29 years of age in the 1976-1980 National Health and Nutrition Examination Survey. In 1994, of 700 men 20-34 years old, 160 were found to be overweight, whereas, in 1980, of 750 men 20-34 years old, 130 were found to be overweight. At the 1% signi cance level, do the data provide sucient evidence to conclude that for men 20-34 years old, a higher percentage were overweight in 1994 than 14 years earlier?
Answer:
oknulhidgzfczgxdgggysfrggugdchggjghhc
2) Write the Inverse for the following linear function: f(x) f(x) = -x +5 F. F-'(x) = (x - 5) G. 8-1(x) = x +5 1.8-(x) = x - 5 1. f-'(x) = (x + 5)
Answer:
[tex]f(x)^{-1}=-x+5[/tex]
Step-by-step explanation:
It looks like the function is f(x)=-x+5.
To find the inverse, first replace f(x) with y.
y=-x+5
Switch the y and x.
x=-y+5.
Solve for y.
x-5=-y
-x+5=y
[tex]f(x)^{-1}=-x+5[/tex]
I hope this helps!
pls ❤ and mark brainliest pls
Two similar figures are similar based on the transformation (x,y) (12x, 3a(squared)y) what is/ are the value(s) of a?
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Answer:
a = ±2
Step-by-step explanation:
For similar figures, the same scale factor applies to both x and y.
12 = 3a²
4 = a²
a = ±√4 = ±2
I don’t understand how to complete this problem. Will mark brainly
Answer:
6 units²Step-by-step explanation:
Area of ΔABC is:
A = 1/2*AB*CDWe have:
AC = 3AD = 1.8Find CD using Pythagorean:
CD² = AC² - AD² ⇒ CD² = 3² - 1.8² ⇒ CD² = 5.76 ⇒ CD = √5.76 = 2.4Find DB using the following identity, coming from ratios of corresponding sides of similar triangles:
CD² = AD*DB5.76 = 1.8*DBDB = 5.76/1.8DB = 3.2Find AB:
AB = AD + DBAB = 1.8 + 3.2AB = 5Find the area of ΔABC:
A = 1/2*5*2.4A = 6 units²Julie knows that the adult population gets, on average, eight hours of sleep each night. A hypothesis test can help her see if college students are different from the adult population. Julie tabulated that her sample of 101 students got an average of 7.1 hours of sleep each night, with a standard deviation of 2.48. Using the data provided and the formula below, what is the t-statistic that Julie calculates
Answer:
-3.64
Step-by-step explanation:
You are designing a metal sculpture that will be placed in front of your school. You sketch an initial design
with a scale of 1 cm = 2 feet. The design shows that the sculpture has a length of 8 feet.
After reviewing your design, the principal asks you to use the same drawing, but change the scale to 1 cm
= 5 feet.
What will be the length of the sculpture using the new scale?
A. 8 feet
B. 12 feet
C. 15 feet
D. 20 feet
Using proportions, it is found that the length of the sculpture using the new scale is given by:
D. 20 feet.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The initial scale is of 1 cm = 2 feet, with a sculpture of 8 feet, hence the length of the drawing is given by:
l = 8/2 = 4 cm.
For the new scale, 1 cm = 5 feet, and you keep the drawing of 4 cm, hence the length of the sculpture is given by:
l = 4 x 5 = 20 feet.
Hence option D is correct.
More can be learned about proportions at https://brainly.com/question/24372153
#SPJ1
Can someone help with trig identities?
(calculators are allowed)
Answer:
d
Step-by-step explanation:
cosA^2 = 1 - sinA^2
subtitute 1/4 below
= 1 - (1/4)^2
= 1 - 1/16
after calculation
= - 0.9682
4. Find the difference. Put
your answer in lowest terms.
9/11 - 1/3 =
Os
Brainteaser
Unscramble the following letters to form words:
Tsydhau
Fydari
Fydari will be rearranged as "Friday"
Tsydhau B will be rearranged as "Thusday"
Scrambled words are words that are awkwardly arranged to mislead or cause confusion. The opposite of scrambled is unscrambled.
Unscrambling a word means rearranging the words in order to give them a new meaning.
According to the question given, the scrambled words are Tsydhau and
Fydari
Unscrambling the words means rearranging the words to give them new meaning. Hence:
Fydari will be rearranged as "Friday"
Tsydhau B will be rearranged as "Thusday"
Learn more about scrambling here: https://brainly.com/question/23187632
order these numbers in ascending order. 14, -60, 6.28,-19
Answer:
-60 , -19 , 6.28 , 14
Step-by-step explanation:
Order the number in ascending order, or from least to greatest. Note that the bigger the negative number, the smaller the number. The bigger the positive number, the bigger the number:
-60 , -19 , 6.28 , 14
~
Note: For 6.28, the decimal point results in 6 being in the ones place, 2 being in the tenths place, 8 being in the hundredths place. By the rules regarding the usage of decimals, place values after the decimal point will be significantly less then the place values before the decimal point, and would be used to determine a more exact value.
Help please! What’s do you see/notice about the pattern below?
Answer:
Uhm, I see there's a pattern, but there are only 2 green boxes, whole there are 4 orange boxes in every figure.
Find the product of 2v3 • 3 V6
Write your answer in simplest radical form.
55) James left the science museum driving east 1.6 hours before Kim. Kim drove in the opposite direction going 24 km/h slower than James for 1.8 hours after which time they were 258.4 km apart. How fast did James drive?
Please show ur work, I already have the answer but I need to know how to do it. If your answer matched up with the answer key and is correct with work I will give brainliest
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Answer:
58 km/h
Step-by-step explanation:
Let s represent James's speed. Then s-24 is Kim's speed. The relationship between time, speed, and distance is ...
d = st
Since the two were traveling in opposite directions, their distance apart is the sum of the distances they drove. James drove for 1.6 more hours than the 1.8 hours Kim drove, so their total distance is ...
(1.6 +1.8)s +1.8(s -24) = 258.4
5.2s -43.2 = 258.4 . . . . . . . . . . . . collect terms
5.2s = 301.6 . . . . . . . . . . . add 43.2
s = 58 . . . . . . . . . . . divide by 5.2
James drove at 58 km/h.
After a grueling year of work, you (Padcha) decide you need absolute peace and quiet for about a month (February). You visit San Pedro de Atacama in the Atacama dessert of Chile, one of the most pristine and beautiful spots on earth. Every morning you have an espresso with a Swiss veterinarian, Dieter, that has retired there and maintains a small hotel and cafe. After week 2 of peace and quiet you become restless for a more meaningful existence.
In a conversation Dieter you learn that he also raises Llama's, Alpacas, and Vicuñas (all members of the Camel Family) for their wool. The conversation follow--
Dieter: "Padcha, I have this problem related to the nutrition of my animals. I know the nutritional content of the feeds I have available (see the Daily Nutritional Requirements for Animals table). I also know the cost of a kilogram of each feed (see table). I would love to have a way of selecting a mix of Corn, Tankage, and Alfalfa that minimizes my daily cost of providing good nutrition for my animals."
Padcha: "Dieter, I think I might be able to help. In LP optimization, there is a problem that is called the nutrition problem. Of course, it is not only about nutrition, it's also about allocating available resources, in an optimal way (minimal cost), to satisfy requirements. You can image, that there are a lot of problems like that in business. A typical constraint, say for carbohydrates, would read-- the number of kilos of Corn times 90, plus the number of kilos of Tankage times 20, plus the number of kilos of Alfalfa times 40 must equal a minimum 200 units of carbohydrates. The constraint shows how we use the resources/decision variables (kilos of Corn, etc.) to satisfy nutritional needs.
Daily Nutritional Requirements for Animals
Kg. Corn KG. Tankage Kg. Alfalfa Min. Daily Reqs.
Carbohydrates 90 20 40 200
Protein 30 80 60 180
Vitamins 10 20 60 150
$Cost of feed/Kg. 35 30 25
a) What is the LP for the nutrition problem?
b) Solve the problem using Solver. What is the value of the optimal solution? What is the number of kilos of Corn, Tankage, and Alfalfa? (Place the Answer Report below)
c) What if the requirements were raised by 1 unit for carbohydrates (from 200 to 201). Without re-solving the problem, what is the new optimal solution value and the units of carbohydrates? (Provide the logic for your answer.)
d) What is the allowable range of values for the coefficient of the Tankage in the objective function, for which a change of the optimal decision variables will not occur?
Answer:YA IM THAT KIND OF GUY I NEED POINTS
Step-by-step explanation:
YA IM THAT KIND OF GUY I NEED POINTS
help plz answer quickly
Answer:
plane EBG
Step-by-step explanation:
plane C is also named plane EBG
Answer:
[tex]\\ \sf\longmapsto Plane EBG[/tex]
We can't name it EBF as it is a axis and coplanar points
Also nEF is not a satisfactory name .
So the correct option is C
What is the best definition of a. Angle
Answer:
the space (usually measured in degrees) between two intersecting lines or surfaces at or close to the point where they meet.
Step-by-step explanation:
The graph of y = va is translated 5 units to the left and 7 units up. What is the equation of the graph that results
from this translation?
Answer:
B
Step-by-step explanation:
i did this a couple years ago should be right if im correct
An open box is to be made from a square piece of cardboard, 36 inches by 36 inches, by removing a small square from each corner and folding up the flaps to form the sides. What are the dimensions of the box of greatest volume that can be constructed in this way?
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Answer:
24 in square by 6 in deep
Step-by-step explanation:
Let x represent the side of the square cut from each corner. Then the dimensions of the base of the box are 36-2x in each direction. The total volume of the box is ...
V = LWH = (36 -2x)(36 -2x)x = x(4x² -144x +1296)
The volume will be a maximum where dV/dx = 0.
dV/dx = 12x^2 -288x +1296 = 0
x² -24x +108 = 0 . . . . divide by 12
(x -6)(x -18) = 0 . . . . . factor
x = 6 or 18 . . . . . . x = 18 gives a minimum volume; we want x = 6
Then the dimensions are 36 -2(6) = 24 inches square by 6 inches deep.
12. Solve x^2 + 6x - 16 = 0 by completing the square.
Please help and show work
Answer:
x is 2 and -8
Step-by-step explanation:
[tex] {x}^{2} + 6x - 16 = 0[/tex]
general equation
[tex] {ax}^{2} + (sum)x + product = 0[/tex]
sum is 6, product is -16
for completing squares,
first divide the sum by 2:
[tex] = \frac{6}{2} = 3[/tex]
add the square of the result on (x² + 6x) and subtract it from the product:
[tex] ( {x}^{2} + 6x + {3}^{2} ) - 16 - {3}^{2} = 0 \\ {(x + 3)}^{2} - 25 = 0 \\ {(x + 3)}^{2} = 25[/tex]
take square root:
[tex] \sqrt{ {(x + 3)}^{2} } = \sqrt{25 } \\ x + 3 = ±5 \\ x = ±5 - 3[/tex]
x is either: 5-3 or -5-3
[tex]x = 2 \: \: and \: - 8[/tex]
please answer this question
Answer:
3
Step-by-step explanation:
[tex]log(3x^{3}) - log(x^{2}) = log(\frac{3x^{3}}{x^{2}})\\log(27) - log(x) = log(\frac{27}{x} )\\[/tex]
therefore,
[tex]\frac{3x^{3} }{x^{2} } = \frac{27}{x} \\3x=\frac{27}{x} \\3x^{2} =27\\x= +3\\x=-3[/tex]
however, since logarithms cannot have negative arguments, x can only be +3
i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.
JKL and CDE are congruent. If JKL = 137, what is CDE
<CDE = 137°
When two triangles are congruent:
The corresponding angles are equalThe sizes and shapes are equalThe areas are equalThe perimeters are equalSince △JKL and △CDE are congruent, all the corresponding angles are equal.
Therefore, <JKL = <CDE = 137°
Learn more here: https://brainly.com/question/12077512
Find all points on the curve x^2y^2+xy=2 where the slope of the tangent line is −1
Differentiate both sides with respect to x and solve for the derivative dy/dx :
[tex]\dfrac{\mathrm d}{\mathrm dx}\left[x^2y^2+xy\right] = \dfrac{\mathrm d}{\mathrm dx}[2] \\\\ \dfrac{\mathrm d}{\mathrm dx}\left[x^2\right]y^2 + x^2\dfrac{\mathrm d}{\mathrm dx}\left[y^2\right] + \dfrac{\mathrm d}{\mathrm dx}\left[x\right]y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 2xy^2 + x^2(2y)\dfrac{\mathrm dy}{\mathrm dx} + y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ (2x^2y+x)\dfrac{\mathrm dy}{\mathrm dx} = -2xy^2-y \\\\ \dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{2xy^2+y}{2x^2y+x}[/tex]
This gives the slope of the tangent to the curve at the point (x, y).
If the slope of some tangent line is -1, then
[tex]-\dfrac{2xy^2+y}{2x^2y+x} = -1 \\\\ \dfrac{2xy^2+y}{2x^2y+x} = 1 \\\\ 2xy^2+y = 2x^2y+x \\\\ 2xy^2-2x^2y + y - x = 0 \\\\ 2xy(y-x)+y-x = 0 \\\\ (2xy+1)(y-x) = 0[/tex]
Then either
[tex]2xy+1 = 0\text{ or }y-x=0 \\\\ \implies y=-\dfrac1{2x} \text{ or }y=x[/tex]
In the first case, we'd have
[tex]x^2\left(-\dfrac1{2x}\right)^2+x\left(-\dfrac1{2x}\right) = \dfrac14-\dfrac12 = -\dfrac14\neq2[/tex]
so this case is junk.
In the second case,
[tex]x^2\times x^2+x\times x=x^4+x^2=2 \\\\ x^4+x^2-2 = (x^2-1)(x^2+2)=0[/tex]
which means either
[tex]x^2-1 = 0 \text{ or }x^2+2 = 0 \\\\ x^2 = 1 \text{ or }x^2 = - 2[/tex]
The second case here leads to non-real solutions, so we ignore it. The other case leads to [tex]x=\pm1[/tex].
Find the y-coordinates of the points with x = ±1 :
[tex]x=1 \implies y^2+y=2 \implies y=-2 \text{ or }y=1 \\\\ x=-1\implies y^2-y=2\implies y=-1\text{ or }y=2[/tex]
so the points of interest are (1, -2), (1, 1), (-1, -1), and (-1, 2).
I will give brainliest !!
Answer:
D
Step-by-step explanation:
When all the members in a domain has only but one member in the do main then function has been satisfied.
considering a situation of,
4 1
6 1
8 2
the domain has only one member in the Co domain hence which makes it a function
what are formulas used to solve polynomials?
Answer:
Polynomial Equation Degree Example
Linear Equations 1 -3x + 1 = 4x + 5
Quadratic Equations 2 x^2 – 6x + 9 = 0
Cubic Equations 3 x^3 – 2x^2 + 3x = -5
Quartic Equations 4 x^4 – 2x^2 = -4
Step-by-step explanation:
Linear Equations
Linear equations are polynomial equations that have a degree of 1.
ax + b = 0
Solving for solutions for this type of equation will require us to isolate the unknown variable on one side of the equation. Master your craft in solving linear equations here.
Quadratic Equations
Quadratic equations are polynomial equations with a degree of 2.
ax2 + bx + c = 0
There are different ways we can solve quadratic equations – it mostly depends on the form of the quadratic expression on the right-hand side.
We can factor quadratic expressions and apply the zero-property.
Applying special algebraic properties such as the difference of two squares, perfect square trinomial properties, and completing the square.
Lastly, we can also use the quadratic formula to find the zeroes of quadratic equations.
Polynomial Equations (with a degree of 3 or higher)
Here’s the exciting part: what if we need to find the zeros of the solutions of a polynomial equation with degrees that are 3 or higher?
Some cubic and quartic equations can be factored by grouping and be reduced to equations with a smaller degree. There are times, however, that finding the actual factors can be challenging.
The digit 5 is usually rounded up, but it can also be rounded down. How would you round the numbers in the equation 9.5 + 4.7 + 3.2 + 7.5 = x to the nearest whole number without getting an overestimate or an underestimate?
Answer:
I would round 5 up and anything below 5 would be rounded down.
10 + 4 + 3 + 8 = x
25 = x
Answer:
Let me know if I explain this wrong but from what I understand, what you would do is 9m5 and 7.5 together ad .5 and .5 are 1. That means 9+1+7. Next is 4.7 and 3.2 The problem with this us that .7 and .2 are .9 however that is important. 4+3 is 7 and we know .9 so it's 7.9. now just add the whole numbers and 7.9 and then you get your perfect answer. this answer was mainly just distributive property. hope I helped
suppose Point G represents a duck flying over a Lake, point H and J represent two ducks swimming on the lake. Which is a true statement?
Answer:
Choice D. There is exactly one plane that contains the three ducks: [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex].
Step-by-step explanation:
The three points [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex] are distinct since each of the three points represents a different duck.
There's only one line through two distinct points in a 2D cartesian plane.
Likewise, given two distinct points ([tex]\sf G[/tex] and [tex]\sf J[/tex]) in a 3D space, there would be only one line two the two points.
Assume that plane [tex]\sf L[/tex] represents the plane that contains the surface of the lake.
A line is in a plane if and only if all points on that line are in the said plane.
Point [tex]\sf G[/tex] is on the line that contains [tex]\sf G\![/tex] and [tex]\sf H[/tex]. However, since point [tex]\!\sf G[/tex] denotes the flying duck, this point would not be in [tex]\sf L[/tex] (the plane that contains the surface of the lake.)
Hence, the line that contains [tex]\sf G\![/tex] and [tex]\sf H\![/tex] would not be in plane [tex]\sf L\![/tex].
Given three distinct points in a 3D space, there would be exactly one plane that contains the three points.
Hence, three points in a 3D space would not be non-coplanar.
In this question, point [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex] are all distinct. Hence, there would be exactly one plane that contains these three points.
If the mean of a positively skewed distribution is 65, which of these values
could be the median of the distribution?
A. 60
B. 65
C. 70
D. 75
B: is correctly in my opinion
Answer:
60
Step-by-step explanation:
its the answer
Which number is the largest?
Answer:
54.895
Step-by-step explanation:
hopes it's help you
brainiest to whoever right
Answer:
x = 33
AB = 60
Step-by-step explanation:
18 + 2x -6 = x+45
x = 33
AB = 33× 2 -6
= 60