The length of the third side of the triangular piece of land is approximately 125.7 m, and the angle between the first and third side is approximately 79.4° .
To find the length and orientation of the third side c, we can use the law of cosines, which states:
c² = a² + b² - 2ab cos(C)
where c is the length of the third side, a and b are the lengths of the first two sides, and C is the angle between sides a and b.
To find the angle C, we can use the law of sines, which states:
sin(C) / c = sin(A) / a = sin(B) / b
where A and B are the angles opposite sides a and b, respectively.
We can use the given measurements to calculate the values of a, b, and A:
a = 80.0 m
b = 105 m
To find angle A, we can use the law of cosines:
A = cos^-1[(b² + c² - a²) / (2bc)]
Since the angle between sides a and b is the same as the angle between sides b and c, we can use the same value for angle A and angle C. Therefore:
C = cos^-1[(a² + b² - c²) / (2ab)]
We can rearrange the law of sines to solve for c:
c = (a sin(C)) / sin(A)
Substituting the values we have calculated:
A = cos^-1[(105² + c² - 80²) / (2 x 105 x c)]
C = cos^-1[(80² + 105² - c²) / (2 x 80 x 105)]
c = (80 sin(C)) / sin(A)
Using a calculator, we get:
A ≈ 38.4°
C ≈ 79.4°
c ≈ 125.7 m
Therefore, the length of the third side and the angle between the first and third side is calulated to be 79.4° and 125.7 m (approx.)
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the cell walls of bactirea
Cell wall of bacteria is involved in dissolving penicillin. So, the correct option is B.
What is cell wall of bacteria?The bacterial cell wall is composed of peptidoglycan which is an essential protective barrier for bacterial cells that surrounds the cytoplasmic membrane of both types of bacteria such as gram-positive and gram-negative bacterial cells.
Peptidoglycan is defined as a rigid, highly conserved, complex structure of polymeric carbohydrates and amino acids. Cell wall of bacteria is involved in dissolving penicillin.
So, the correct option is B.
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a track of mass 2000kg travelling at 12m/s has it initial speed reduces ti 6m/s a constant breaking force over a distance of 40m.what is the breaking force?
The breaking force, given that the truck reduces it speed from 12 m/s to 6 m/s over a distance of 40 m is -2700 N
How do i determine the breaking force?We'll begin by obtaining the deceleration of the truck. Details below:
Initial velocity (u) = 12 m/sFinal velocity (v) = 6 m/s Distance (s) = 40 mDeceleration(a) =?v² = u² + 2as
6² = 12² + (2 × a × 40)
36 = 144 + 80a
Collect like terms
36 - 144 = 80a
-108 = 80
Divide both side by 80
a = -108 / 80
a = -1.35 m/s²
Finally, we shall determine the breaking force. Details below:
Mass (m) = 2000 KgDeceleration (a) = -1.35 m/s²Breaking force (F) =?Force = mass × deceleration
Breaking force = 2000 × -1.35
Breaking force = -2700 N
Thus, the breaking force is -2700 N
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What would be its orbital velocity if Ingenuity is on the surface of Mars?
For the answer, type in your answer (in standard notation, not scientific
notation). Do not write units.
Include two numbers after the decimal (the hundredths place).
The orbital velocity, if Ingenuity is on the surface of Mars is 3549.67 m/s
What is Orbital Velocity ?Orbital velocity is also called as critical velocity. It is minimum velocity must be given to the satellite or the body, so that it can revolve around the planet. i.e. orbital velocity is minimum velocity of body to revolve in stable orbit around a planet.
Orbital velocity is given by,
[tex]v_{c} =\sqrt{\frac{GM}{R+h}}[/tex] where G = Gravitational constant (6.673×10⁻¹¹ Nm²/kg²)
M = Mass of the planet
R = Radius of the planet
h = height of the object(satellite)
Orbital velocity depends on mass of the planet, radius of the planet and height of the object(satellite). It is independent of mass of the body(satellite).
Given,
M = 6.42×10²³ kg
R= 3.4×10⁶ m
h= 0 m (our body is on surface of the mars so)
Putting these values in the equation.
[tex]v_{c} =\sqrt{\frac{GM}{R}}[/tex] = [tex]\sqrt{\frac{(6.673*10^{-11}) (6.42*10^{23}) }{3.4*10^{6}}}[/tex]
[tex]V_{c}[/tex]= 3549.67 m/s
Hence Orbital velocity of Ingenuity on the surface of Mars 3549.67 m/s
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Air passes over the top of an airplane
wing at 170 m/s, and over the bottom
at 130 m/s. What is the difference in
pressure between the top and
bottom of the wing?
Answer:
The difference in airspeed over the top and bottom of an airplane wing results in a difference in air pressure, which generates lift. The Bernoulli's equation relates the pressure of a fluid (including air) to its velocity and the height of the fluid:
P + 1/2 * rho * v^2 + rho * g * h = constant
where P is the pressure of the fluid, rho is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height of the fluid.
Assuming that the density of air is constant and the height of the wing is negligible compared to the other terms in the equation, we can simplify the equation to:
P + 1/2 * rho * v^2 = constant
The constant in the equation is the same at all points along the wing, since the air is a continuous fluid.
The pressure difference between the top and bottom of the wing can be found by calculating the pressure at the top and bottom of the wing using the simplified Bernoulli's equation, and then taking the difference between the two pressures.
Let P1 be the pressure at the bottom of the wing, where the airspeed is 130 m/s, and P2 be the pressure at the top of the wing, where the airspeed is 170 m/s. Then we have:
P1 + 1/2 * rho * (130 m/s)^2 = P2 + 1/2 * rho * (170 m/s)^2
Simplifying and rearranging, we get:
P1 - P2 = 1/2 * rho * (170 m/s)^2 - 1/2 * rho * (130 m/s)^2
Plugging in the density of air (rho = 1.225 kg/m^3), we get:
P1 - P2 = 1/2 * 1.225 kg/m^3 * (170 m/s)^2 - 1/2 * 1.225 kg/m^3 * (130 m/s)^2
Simplifying and calculating, we get:
P1 - P2 = 377.72 Pa
Therefore, the difference in pressure between the top and bottom of the wing is approximately 377.72 Pa.
Carlos was playing on a slide on a sunny summer day. Which property of the slide tells Carlos how much energy the slide absorbed from the Sun?
O the mass
O the color
O the height
O the temperature
Answer:
Its D
Explanation:
just did It :)
If hydropower were to be our primary way for generating electricity, what effect would this have on individuals and the environment?
Answer:
If hydropower were to be our primary way for generating electricity, it would have several effects on individuals and the environment, both positive and negative. Here are some examples:
Positive effects:
Hydropower is a renewable energy source, meaning that it does not produce greenhouse gas emissions and does not contribute to climate change.
Hydropower can provide a stable and reliable source of electricity, as water can be stored in reservoirs and released when needed to generate electricity.
Hydropower can create jobs in construction, maintenance, and operation of hydroelectric power plants.
Negative effects:
The construction of large dams for hydropower generation can have significant impacts on ecosystems and communities. For example, it can disrupt the natural flow of rivers and waterways, causing changes in water temperature, sediment transport, and dissolved oxygen levels, which can harm aquatic habitats and species. It can also lead to the displacement of communities living in the area.
Dams can cause soil erosion, which can lead to the buildup of sediment in rivers and reservoirs, reducing their capacity and lifespan.
The construction of dams and reservoirs can also result in the loss of productive agricultural land and natural habitats.
In areas where water resources are scarce, the use of large amounts of water for hydropower generation can compete with other uses such as agriculture, drinking water supply, and ecosystems.
Overall, the impact of hydropower as a primary source of electricity would depend on the specific location, design, and management of hydroelectric power plants. Proper planning, environmental impact assessments, and community engagement are necessary to minimize negative impacts and maximize benefits.
Explanation:
hope it help pa brainliest po
If Sue completes the work in #1 in 6 seconds, how much power did she provide?
Sue provided 40 watts of power to complete the work in 6 seconds.
Power is the rate at which work is done, or the amount of work done per unit time. It is a measure of how quickly energy is transferred or transformed from one form to another. Since Sue completed the work in 6 seconds, we can calculate her power using the formula,
Power = Work / Time
From question #1, we know that the work done by Sue was 240 J. And the time taken to complete the work was 6 seconds. Substituting these values in the above formula,
Power = Work / Time
Power = 240 J / 6 s
Power = 40 watts
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help!! Sherri is drawing the free body diagram for an object. She says that the object has no net force acting upon it. Which of the following observations would support this statement? (Choose all that apply)
the object that is slowing down.
the object is sitting still
the object that is speeding up
the object is moving with constant velocity
the object that is changing direction.
Answer:
Constant velocity, sitting still
If a body does not have a net force acting upon it, then the object is sitting still or it is moving with constant velocity. Hence, options B and D are correct.
What is a force?A force is an action that modifies or maintains a body's or object's motion. A force is, to put it simply, a push or a pull. An object's speed, direction, and even shape can be altered by forces. Gravitational, electrostatic, and frictional forces are some examples of force.
Thus, when an object has no net force acting upon it, then the object is sitting still or is moving with constant velocity. Hence, options B and D are correct.
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1. A ball is thrown horizontally at a height of 4.91 m above the ground. It has an initial speed of 16.0 m/s. How long will it take to drop to the ground? How far, measured horizontally from the launch point, will it strike the ground?
It will take the ball 1 s to drop to the ground
The distance from the launch point where the ball will strike the ground would be 16.0 m.
Projectile motionWe can use the kinematic equations of motion to solve this problem. The vertical motion of the ball can be described using the equation:
h = vit + 1/2g*t^2
where h is the initial height, vi is the initial vertical velocity (which is zero), g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to fall to the ground. Solving for t, we get:
t = sqrt(2h/g) = sqrt(2*4.91 m/9.8 m/s^2) = 1 s
The horizontal motion of the ball is uniform, since there is no horizontal acceleration. We can use the equation:
d = v*t
where d is the distance traveled, v is the initial horizontal velocity (which is 16.0 m/s), and t is the time taken to hit the ground (which is 1 s). Solving for d, we get:
d = v*t = 16.0 m/s * 1 s = 16.0 m
So the ball will strike the ground 16.0 meters away from the launch point, measured horizontally.
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Imagine two equally charged objects that are hanging a certain distance from one another. How does the force between them change if the distance between them triples?
The force is 1/9 as great
The force becomes 9x's greater
The force becomes 3x's greater
The force is 1/3 as great
Answer The force is multiplied times 9
Explanation:
H e l p.
I need helppppppp please
Answer:
machine D
Explanation:
Three identical capacitors are connected in parallel to a potential source (battery). If a charge of Q flows into this combination, how much charge does each capacitor carry? 3Q Q/2 Q/3 Q
Three identical capacitors are connected in parallel to a potential source (battery). If a charge of Q flows into this combination, Each capacitor will carry a charge of Q/3.
A capacitor is a two-terminal electrical device that can store energy in the form of an electric charge. It consists of two electrical conductors that are separated by a distance. The space between the conductors may be filled by vacuum or with an insulating material known as a dielectric.capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.
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Calculate the moving energy
m=300kg
v=90km/h
Em=?
Answer:
To calculate the moving energy, we can use the formula:
Em = (1/2) * m * v^2
where: m = mass of the object v = velocity of the object
First, we need to convert the velocity from kilometers per hour (km/h) to meters per second (m/s), since the formula requires the velocity to be in m/s:
v = 90 km/h = 25 m/s (approximately, since 1 km/h = 0.27777778 m/s)
Now, we can plug in the values into the formula:
Em = (1/2) * m * v^2 Em = (1/2) * 300 kg * (25 m/s)^2 Em = 281,250 J
Therefore, the moving energy of the object is approximately 281,250 Joules.
A soccer ball with a mass of 0.43 kg is thrown to a 63 kg girl at rest who is wearing roller blades. She catches the ball and moves to the right. Her speed just after catching the ball is 0.2 m/s.
The girl and the ball together move to the right with a velocity of approximately 0.0003 m/s just after the ball is caught. This is a very small velocity, so we can say that the girl is essentially at rest relative to the ground.
What is the conservation of momentum principle?The total momentum of the system before the ball is thrown is zero, since both the ball and the girl are at rest. After the ball is thrown and caught, the total momentum of the system is still zero, since the girl and the ball are now moving together.
Let's first calculate the velocity of the ball just before it is caught by the girl. We can use the conservation of momentum equation:
m1v1 + m2v2 = (m1 + m2)v
where m1 and v1 are the mass and velocity of the ball before it is thrown, m2 and v2 are the mass and velocity of the girl before she catches the ball, and v is their common velocity after the ball is caught.
Since the girl is at rest before catching the ball, v2 = 0. Plugging in the given values, we have:
(0.43 kg)(v1) + (63 kg)(0 m/s) = (0.43 kg + 63 kg)(0.2 m/s)
Solving for v1, we get:
v1 = (63 kg)(0.2 m/s) / (0.43 kg + 63 kg)
v1 ≈ 0.012 m/s
Therefore, the velocity of the ball just before it is caught by the girl is approximately 0.012 m/s.
Now let's calculate the velocity of the girl and the ball together just after the ball is caught. We can again use the conservation of momentum equation:
m1v1 + m2v2 = (m1 + m2)v
where v1 is the velocity of the ball just before it is caught (which we just calculated), m1 and m2 are the masses of the ball and girl, and v is their common velocity just after the ball is caught.
Plugging in the given values, we have:
(0.43 kg)(0.012 m/s) + (63 kg)(0 m/s) = (0.43 kg + 63 kg)(v)
Solving for v, we get:
v = (0.43 kg)(0.012 m/s) / (0.43 kg + 63 kg)
v ≈ 0.0003 m/s
Therefore, the girl and the ball together move to the right with a velocity of approximately 0.0003 m/s just after the ball is caught. This is a very small velocity, so we can say that the girl is essentially at rest relative to the ground.
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pls help Patton launches a water balloon at a speed of 15.8 meters per second in the positive x-direction at an angle of 19.5 above horizontal. What are the components of the velocity vector right before the balloon strikes the ground?
To solve this problem, we need to use trigonometry to break the initial velocity vector into its x and y components.
What is Velocity?
Velocity is a vector quantity that describes the rate at which an object changes its position. It is defined as the displacement of an object per unit time in a particular direction.
In other words, velocity is the speed of an object in a given direction. It is a vector quantity because it has both magnitude (the speed) and direction.
The initial velocity vector can be represented as follows:
v = 15.8 m/s [19.5° above horizontal]
The x-component (vx) of the velocity vector can be found using the cosine function:
cos(19.5°) = vx / 15.8 m/s
vx = 15.8 m/s cos(19.5°) = 14.9 m/s
The y-component (vy) of the velocity vector can be found using the sine function:
sin(19.5°) = vy / 15.8 m/s
vy = 15.8 m/s sin(19.5°) = 5.25 m/s
When the water balloon strikes the ground, its y-velocity component will be zero because it will have reached the ground level. Therefore, the components of the velocity vector right before the balloon strikes the ground are:
vx = 14.9 m/s [to the right]
vy = 5.25 m/s [upward]
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Before a run, you eat an apple with 1,000,000 Joules of binding energy. 550,000 Joules of binding energy are wasted during digestion. How much energy remains J.
The total binding energy of the apple is 1,000,000 Joules. Out of these much energy, 550,000 Joules of binding energy are wasted during digestion. Then, 450000 J or binding energy remains.
What is binding energy ?Binding energy of an object is the minimum energy required to break a chemical bond in a compound or the bonds between the particles of a system.
The binding energy of a substance depends on the bond type, presence of any impurities, temperature, phase of the substance etc. Given the binding energy of the apple is 1,000,000 Joules.
The energy wasted during digestion = 550,000 Joules
then the remaining energy = total energy - wasted energy
= 1,000,000 Joules - 550,000 Joules
= 450000 J.
Therefore, the energy remains in the person is 450000 J.
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Answer question in the photo
The power the force developed in pushing the box up the ramp is 2759.009 watts
How to determine the power the force developed?Power is simply defined as the rate at which work is done. It can be expressed mathematically as
Power (P) = work (W) / time (t)
But
Work = force (F) × distance (d)
Therefore,
P = Fd / t
But
velocity (v) = distance (d) / time (t)
Thus,
Power = force (F) × velocity (v)
With the above formula, we can obtain the power developed by the force. Details below:
Force (F) = 1283.26 NVelocity (v) = 2.15 m/sPower (P) = ?Power = force (F) × velocity (v)
Power = 1283.26 × 2.15
Power = 2759.009 watts
Thus, the power is 2759.009 watts
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How does changing the charge’s value influence the force between the two charges?
As the value of charge 2 __________, the value of the force ___________.
decreases; decreases
increases; decreases
increases; does not change
decreases; does not change
The strength of the repulsion or attraction weakens and drops to one-fourth of its initial value when the gap between the two electrons is doubled.
What exactly is physics' law of attraction?According to the Law of Attraction, when we alter our emotions and thoughts, we alter our electromagnetic field, which attracts a new reality from of the Quantum Field. We must hold that condition of being long sufficient to allow the manifestations to take place after the thought and the sensation have to coincide.
What exactly is physics' law of attraction?According to the Law of Attraction, when we alter our opinions and feelings, we alter our electromagnetic field, which attracts a new reality from Quantum Field. The thought must coincide with the feeling, and we must then maintain that condition of being for long enough to allow the manifestation to take place.
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If a sample of gas occupies 13L of volume at a temperature of 75 K what will be its new temperature if it is expanded to 26 L at constant pressure.
Answer:
150 K
Explanation:
You can use Charles’s Law to solve this problem. Charles’s Law states that the volume of a gas is directly proportional to its temperature in kelvins when pressure is held constant.
Let V1 and T1 be the initial volume and temperature of the gas, and let V2 and T2 be the final volume and temperature of the gas. According to Charles’s Law, we have:
V1 / T1 = V2 / T2
Substituting in the given values for V1 (13 L), V2 (26 L), and T1 (75 K), we get:
13 / 75 = 26 / T2
Solving for T2, we get:
T2 = (26 * 75) / 13
So, T2 = 150 K.
The new temperature of the gas will be 150 K.
two people are being pulled up out of the water by a helicopter the helicopter pulls the two people upwards who weigh a combined 150 kg and lifts them 20 meters. determine the work done by the helicopter
The helicopter generates 29,400 Joule of work. If a helicopter is using two individuals to take them out of the water, the helicopter will hoist the two people, who together weigh 150 kg, 20 meters in the air.
Definition of Completed Work.The definition of work done includes both the forces that were used by the body and also the overall displacement of both the body. A constant total Force is present before to this block. The goal of this force seems to be to propel the body d meters in a straight line in the force's direction.
How is work completed?When a weight is applied across a distance to an item, work is accomplished. This implies that the total energy of an item will be impacted when a push is given to it across a distance.
Work = Force x Distance
= 150 kg x [tex]9.8 m/s^{2}[/tex] x 20 m
= 29,400 J
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Which statement best describes a primary source?
a. the source is written by an expert in the field
b. the source is compiled from other sources
c. the source is written by the person who conducted the expirement
d. the source is filled with mathematical questions
Answer:
C.
Explanation:
c. the source is written by the person who conducted the experiment. A primary source is an original piece of information created at the time under study. It can be a diary, a letter, a photograph, a recording, or any other type of artifact. It provides firsthand information about an event or topic, and is created by a person who was directly involved or witnessed it.
A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/sec. What is the turtles momentum?
Problem:
A 1 kilogram turtle crawls in a straight line at a speed of 0.01 m/sec.what is the turtle momentum?
Given Data:
m (mass) = 1 kg
v (velocity) = 0.01 m/s
p (momentum) = ? unknown
The formula in calculating momentum is p = m × v
Solution:
p = m × v
= 1 kg × 0.01 m/s
= 0.01 kg.m/s
Answer:
Momentum of turtle crawls in a straight line is 0.01 kg.m/s.
Miguel is riding his skateboard down a straight road at 150 meters per minute. If his velocity remains constant, how far will Miguel skate in 3.4 minutes?
Answer:
510m
Explanation:
150m × 3.4 = 510
distance = speed × time
A block is pushed against the spring with
spring constant k (located on the left-hand
side of the track) and compresses the spring a
distance 4.9 cm from its equilibrium position
(as shown in the figure below).
The block starts at rest, is accelerated by
the compressed spring, and slides across a
frictionless track except for a small rough area
on a horizontal section of the track (as shown
in the figure below).
It leaves the track horizontally, flies through
the air, and subsequently strikes the ground.
The acceleration of gravity is 9.81 m/s².
What is the spring constant k?
The spring constant k is approximately 1520 N/m by using conservation of energy?
What is the spring constant?We can use the conservation of energy to find the spring constant k. Initially, the block has potential energy stored in the compressed spring, which is then converted to kinetic energy as the block slides across the track. At the point where the block leaves the track, all of the stored energy has been converted to kinetic energy. Neglecting air resistance, we can assume that the kinetic energy of the block at this point is equal to the potential energy stored in the spring:
[tex](1/2)kx² = (1/2)mv²[/tex]
where x is the distance the spring is compressed (0.049 m), m is the mass of the block, and v is the velocity of the block when it leaves the track.
Since the block is initially at rest, we can also use kinematic equations to relate the velocity of the block to the distance it travels along the track before leaving it. The horizontal displacement of the block is unknown, so we'll call it d:
d = (1/2)at²
where a is the acceleration of the block along the track and t is the time it takes to travel that distance. The acceleration of the block is determined by the force applied by the spring:
F = kx
ma = kx
a = kx/m
Now we can substitute this expression for acceleration into the kinematic equation:
[tex]d = (1/2)(kx/m)t[/tex]²
Since the block leaves the track horizontally, its vertical displacement is given by:
y = (1/2)gt²
where g is the acceleration due to gravity.
Combining these equations, we can eliminate t and solve for k:
[tex](k/m)(0.049)² = g(2y/g)(2d/(k/mg))²[/tex]
Simplifying, we get:
[tex]k = (mg²d)/(0.049²(4y + gd))[/tex]
Substituting the given values for m, d, and y, and the acceleration due to gravity g = 9.81 m/s², we get:
[tex]k = (0.4 kg)(9.81 m/s²)²(2.3 m)/[(0.049 m)²(4(0.8 m) + (9.81 m/s²)(2.3 m))][/tex]
k ≈ 1520 N/m
Therefore, the spring constant k is approximately 1520 N/m.
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PLEASE HELP!!!! A single-celled, microscopic organism, Paramecium caudatum (P. caudatum), was grown in a container with food and freshwater. The growth rate of the P. aurelia population is shown in the graph.
5c78ed99-a73d-456f-987a-379358e65942.jpeg
a. Use the information and graph to describe the relationship among time, food, and the P. Aurelia population.
b. Predict how the P. aurelia population would most likely change if another microscopic organism, Paramecium caudatum (P. caudatum), is added on day 17 to the same container with no additional food or freshwater. Assume that P. caudatum is not a predator of P. aurelia and that both species use the same food. Provide reasoning for your prediction.
What is the net force on a 4000kg car that doubles its velocity from 15m/s west to 30m/s west over ten seconds
Answer:
30,000kg m/s²
Explanation:
Force=mass ×acceleration
Acceleration = Change in Velocity /time
Acceleration =V2-V1/T
Acceleration= 30-15/2
Acceleration =15/2
=7.5m/s²
Force = 4000kg × 7.5m/s²
=30,000kgm/s²
You can also place the answer in Newton (N)
A group of students are preforming an experiment in class using
collision carts on a track. An 8.0 kg cart moving to the right at 4 m/s
hits a 4.0 kg cart moving to the left at 6 m/s. Immediately after the
collision, the 4.0 kg cart moves to the right at 3 m/s. What are the
speed and direction of the 8.0 kg cart after the collision?
Show Your Work
Answer:
The 8.0 kg cart's direction is going towards the right, and its speed is 0.50 m/s.
Explanation:
First the 8.0 kg cart is double of the other. Then the speed of the 8.0 cart 1.5 m/s slower than the other. Then after the collision the 4.0 kg cart goes half its old m/s ( 6 m/s --> 3 m/s ). Put on a diagram, refer to the picture ( sorry about my handwriting ).
Then it will be a total of 0.50 m/s.
Two charged objects have an attractive force of 10 N
The force between charges becomes 2.5 N, if the distance between them is doubled. Option d is the correct choice.
The force between two charged objects is inversely proportional to the square of the distance between them. This means that if the distance between the objects is doubled, the force between them will be reduced to one-fourth (1/2^2) of its original value.
Since the initial force between the objects is 10 N, if the distance between them is doubled, the force between them will become,
10 N / 2^2 = 2.5 N\
Therefore, the correct answer is (d) 2.5 N.
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--Two charged objects have an attractive force of 10 N. If the distance between them is doubled, the force between them is :
a. 40 N
b. 20 N
c. 5 N
d. 2.5 N--
Create an informational poster on three of the most important points of a specific federal educational policy. You poster should explain these points to a general audience.
Identify a specific federal educational policy that you wish to investigate.
Find a minimum of three online resources that describe your chosen policy. One of the resources should be the text of the actual educational policy. You can find a link to each of these documents in the references section of this lesson.
Identify the most important points of the policy, and design a poster that explains these points to a general audience. Your poster should be informative, but also readable.
To complete your assignment, submit:
Your poster.
A list of all references used in the assignment.
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Answer:
Federal Educational Policy: Every Student Succeeds Act (ESSA)
Resources:
1. Every Student Succeeds Act (ESSA): https://www.ed.gov/essa
2. What is the Every Student Succeeds Act (ESSA)?: https://www.edweek.org/ew/section/multimedia/what-is-the-every-student-succeeds-act-essa.html
3. ESSA Overview: https://www2.ed.gov/policy/elsec/leg/essa/overview.html
Poster:
Title: The Every Student Succeeds Act (ESSA)
The Every Student Succeeds Act (ESSA) is a federal educational policy that was signed into law in 2015. It replaces the No Child Left Behind Act and is designed to provide states with more flexibility in how they use federal funds to improve student outcomes.
Here are three of the most important points of ESSA:
1. States have more control over how they use federal funds to improve student outcomes, such as increasing access to high-quality early childhood education and providing more support for struggling schools.
2. ESSA requires states to set challenging academic standards and measure student progress in order to ensure that all students are meeting those standards.
3. ESSA also requires states to provide more support for traditionally underserved students, such as English language learners and students with disabilities, in order to close achievement gaps and ensure that all students have access to a high-quality education.
Explanation:
How would you use knowledge of force of impact to respond to a head-on or side collision
Reduce damage to the passenger compartment by changing the point of impact in a side-impact crash to your engine compartment or rear end. Steer clear of the approaching car as long as it doesn't indicate any other dangers, such as a precipice or incoming traffic.
Young neutered male cattle grown primarily for beef are called steers, also known as bullocks. In terms of the sex and age of cattle, the male begins as a bull calf and develops into a bull if left uncastrated; if castrated, he becomes a steer and in two to three years matures into an ox.
To make them more docile on the range or in feedlots, males kept for beef production are typically castrated. Castration is used to make males more manageable at the labor when they are meant to be used as working oxen or bullocks. See also farmed livestock, cattle, cows, and livestock.
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