(a) the work done by tension before the block gets to the incline: Wt = 199.2 J. (b) the work done by friction as the block slides on the flat horizontal surface: Wk = - 45.5 J.
a)
consider the motion along the horizontal direction
T = tension force in the rope pulling the mass = 33 N
d = displacement of the mass before it gets to the inclined surface = 6.9 m
ϴ = angle between the tension force and displacement = 29
work done by tension force is given as
[tex]w_{t}[/tex] = work done by tension force = T d Cosϴ
[tex]w_{t}[/tex] = (33 x 6.9) Cos29
[tex]w_{t}[/tex] = 199.2 J
b)
for the mass, the force equation in the vertical direction is given as
T Sinϴ + Fn = mg
inserting the values
33 Sin29 + Fn = 15 x 9.8
Fn = 131 N
uk = Coefficient of kinetic friction = 0.05
the kinetic frictional force is given as
[tex]f_{k} = u_{k} f_{n}[/tex]
inserting the values
[tex]f_{k}[/tex] = (0.05) (131)
[tex]f_{k}[/tex] = 6.6 N
Ф = angle between the displacement "d" and frictional force "[tex]f_{k}[/tex]" = 180
Wk = [tex]f_{k}[/tex] d Cos\Ф
work done by the frictional force is given as inserting the values
Wk = (6.6) (6.9) Cos180
Wk = - 45.5 J
c)
v = speed gained by the mass before it gets to the incline
using work-change in kinetic energy theorem
work done by the external force = change in kinetic energy
Wt + Wk = (0.5)m v2
199.2 + (- 45.5) = (0.5) (15) v2
v = 4.5 m/s
d)
a = acceleration of mass parallel to the incline
consider the motion parallel to the inclined surface
parallel to the incline, the force equation for the motion is given as
T - mg Sin29 = ma
33 - (15 x 9.8) Sin29 = 15 a
a = - 2.6 m/s2
D = distance traveled parallel to the incline before coming to rest
vi = initial velocity at the start of incline = v = 4.5 m/s
v = final velocity as it comes to stop = 0 m/s
using the kinematics equation
vf2 = vi2 + 2 a D
02 = 4.52 + 2(- 2.6) D
D = 3.89 m
e)
h = height gained by the mass on an incline
Sin29 = h/D
hence h = D Sin29
h = 3.89 Sin29
h = 1.89 m
Fg = force of gravity in downward direction = mg = 15 x 9.8 = 147 N
= angle between the force of gravity "Fg" in the down direction and displacement "h" in the upward direction = 180
Work done by gravity is given as
Wg = Fg d Cosα
Wg = (147) (1.89) (Cos180)
Wg = - 277.83 J
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the complete question is:
A mass m = 15 kg is pulled along a horizontal floor, with a coefficient of kinetic friction. k = 0.05, for a distance d = 6.9 m. Then the mass is continued to be pulled up a frictionless incline that makes an angle. = 29?½ with the horizontal. The entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of? = 29?½ (thus on the incline it is parallel to the surface) and has a tension T = 33 1)What is the work done by tension before the block gets to the incline? 2)What is the work done by friction as the block slides on the flat horizontal surface? 3)What is the speed of the block right before it begins to travel up the incline? 4)How far up the incline does the block travel before coming to rest? 5)What is the work done by gravity as it comes to rest?
15 Joules of work was done to move a 4C charged particle in an electric field of 3N/C. How far was the particle moved in the electric field?
Giving out BRAINLIEST. PLEASE help.
The formula for an electric field's work is as follows: The particle was pushed 1.25 metres in the electric field as a result of W = qEd.
When a charge is transferred in an electric field, does work get done?When a charge is transported in an electric field, work is done. A positively charged particle, such a proton, would accelerate in the direction of the arrows if it were placed in an electric field.
W = qEd
Rearranging the formula to solve for d:
d = W/(qE)
Substituting the given values:
[tex]d = 15 J / (4 C * 3 N/C)[/tex]
d = 1.25 meters
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When the capacitor in this circuit is fully charged, what is the current, I1, out of the battery? A. 1.00 A B. 0.67 A C. 0.40 A D. 0.22 A E. 0.0 A
The capacitor is fully charged, no current flows through it. As a result, the current I1 out of the battery is 0 A.
Option E 0.0 A is the correct option.
Explanation:
What is a capacitor?
A capacitor is a passive electronic component that stores energy in an electric field. Capacitors are commonly used in electronic circuits as energy storage devices because they are able to charge and discharge quickly.
What is a circuit?
An electric circuit is a path through which electric current flows in order to achieve a desired outcome. The given circuit consists of a 12 V battery, a 6 Ω resistor, and a 12 μF capacitor. When the capacitor in this circuit is fully charged, the voltage across the capacitor (Vc) is equal to the voltage of the battery (Vb).
From Ohm's law, I = V/RI = 12/6I = 2 A
The current flowing through the resistor is 2 A.
Since the capacitor is fully charged, no current flows through it. As a result, the current I1 out of the battery is 0 A. Option E 0.0 A is the correct option.
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why will a rainbow never have a black stripe? group of answer choices black is not a color on the color spectrum. in direct sunlight, the color back will not appear. dark color spectrum rainbows only appear at night. if there is a black layer, it is no longer called a rainbow. previousnext
Option 1. A rainbow will never have a black stripe because black is not a color on the color spectrum.
A rainbow is an optical and meteorological phenomenon that occurs when light is refracted or dispersed through water droplets present in the Earth's atmosphere, leading to a spectrum of light appearing in the sky. Rainbows are caused by sunlight being refracted and reflected by water droplets in the atmosphere. A rainbow spans a continuous spectrum of colors, ranging from red on the outside to violet on the inside.
The color spectrum refers to the full range of colors that can be seen by the human eye. The visible spectrum, also known as the color spectrum or the optical spectrum, is a portion of the electromagnetic spectrum that can be seen by the human eye. The spectrum of visible light can be separated into various colors that, when combined, form white light. This is due to the fact that visible light is made up of different colors of light.
Sunlight is a type of electromagnetic radiation that comes from the sun. Sunlight is composed of photons that travel through space until they reach Earth's atmosphere. Sunlight appears white to the human eye, but it is actually made up of various colors of light, as seen in a rainbow. The sun emits light at various wavelengths, which can be separated by a prism to reveal the colors in the spectrum.
Black is not a color in the visible light spectrum, and therefore cannot be found in a rainbow. The colors that appear in a rainbow are a result of the sun's light being refracted and reflected by water droplets in the atmosphere. The colors in a rainbow always appear in the same order and do not include black. Therefore, it is concluded that a rainbow will never have a black stripe because black is not a color on the color spectrum.
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light of wavelength 471 nm in air enters a fishbowl filled with water, then exits through the crown-glass wall of the container. what is the wavelength of the light in the water? the refraction index for water is 1.333 and for crown-glass 1.52.
After calculations, we come to know that the wavelength of light in the water is 350 nm.
Let us first calculate the critical angle for crown glass.
The formula for the critical angle is: n2/n1 = sin θ2/sin θ1
Let us plug in the values of refractive indices: n2 = 1.52n1
= 1.00 (air)n2/n1
= 1.52/1
= 1.52sin θ2/sin θ1
= 1.52/1sin θ1
= sin(θ2)/1.52sin θ1
= sin^-1(1/1.52)sin θ1 = 41.1°
The critical angle for crown glass is 41.1°.
The angle of incidence of the light ray in air is the same as the angle of refraction of the light ray in water.
We can use the formula for refraction of light: n2 sin θ2 = n1 sin θ1
Let us plug in the values of refractive indices and angle of incidence: n1 = 1.00 (air) n2 = 1.333 (water)
sin θ1 = sin 0°
= 0sin θ2
= (n1 sin θ1)/n2sin θ2
= (1.00 × 0)/1.333sin θ2 = 0
The angle of refraction of the light ray in water is 0°.
Now, let us calculate the wavelength of light in water using the formula: n1λ1 = n2λ2
Let us plug in the values of refractive indices and wavelength of light in air: n1 = 1.333 (water) n2 = 1.52 (crown glass)λ1 = 471 nmn1λ1
= n2λ21.333 × 471
= 1.52λ2λ2
= 1.333 × 471/1.52λ2 = 350 nm
Therefore, the wavelength of light in the water is 350 nm.
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3.consider two elastic collisions: 1) a golf ball with speed v hits a stationary bowling ball head-on 2) a bowling ball with speed v hits a stationary golf ball head-on in which case does the golf ball have the greater speed after the collision?
Given two elastic collisions; A golf ball with speed v hits a stationary bowling ball head-on and a bowling ball with speed v hits a stationary golf ball head-on. The golf ball have the greater speed after the collision is the first case (A golf ball with speed v hits a stationary bowling ball head-on).
When two elastic bodies collide, the relative speed between them after the collision is equal to the relative speed before the collision. However, the final velocities of the colliding bodies will depend on their masses. In this case, the mass of the bowling ball is more significant than that of the golf ball. Therefore, in the second case, the golf ball will not bounce as fast as in the first case. The coefficient of restitution (e) measures the fraction of relative speed between the two colliding objects after the collision, compared to the relative speed before the collision.
For an elastic collision, the coefficient of restitution is one, which means the relative speed before and after the collision is the same.The following equation can be used to calculate the final velocities: Vf1=(m1−m2/m1+m2) V1+(2m2/m1+m2) V2Vf2=(2m1/m1+m2) V1+(m2−m1/m1+m2) V2where V1 and V2 are the initial velocities of the two objects, m1 and m2 are their masses, and Vf1 and Vf2 are their final velocities.
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a truck with 0.347-m-radius tires travels at 26.4 m/s. what is the angular velocity of the rotating tires in radians per second
The angular velocity of the rotating tires is 76.27 rad/s.
The angular velocity, ω, of a rotating object is the rate at which it rotates around a chosen center point,
ω = Δθ / Δt (angular displacement over time).
A truck with 0.347-m-radius tires travels at 26.4 m/s. We need to determine the angular velocity of the rotating tires in radians per second. The equation that relates speed and angular velocity is
v = ωr
where,ω = angular velocityv = linear velocity, r = radius of the tire. The angular velocity is given by the equation
ω = v / r
Substitute the given values into the formula;
ω = 26.4 m/s / 0.347 mω = 76.27 rad/s
Hence, the angular velocity of the rotating tires in radians per second of a truck with 0.347-m-radius tires that travels at 26.4 m/s is 76.27 rad/s.
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an emf of 20.5 mv is induced in a 499 turn coil when the current is changing at a rate of 11.5 a/s. what is the magnetic flux through each turn of the coil at an instant when the current is 4.00 a? (enter the magnitude.)
The magnetic flux through each turn of the coil at an instant when the current is 4.00 A is 8.18×10^−5 T·m².
An EMF (electromotive force) of 20.5 mV is induced in a 499 turn coil when the current is changing at a rate of 11.5 A/s. The question requires us to calculate the magnetic flux through each turn of the coil at an instant when the current is 4.00 A.
To determine the solution, we'll use the formula of EMF induced in a coil of N turns according to Faraday's law which is expressed as; EMF= -N(dФ/dt) Where, N is the number of turns in the coil, dФ/dt is the rate of change of magnetic flux.
The rate of change of magnetic flux dФ/dt is given as;
dФ/dt = EMF/N
= 20.5×10^-3/499
= 0.041 A/s
We also know that the magnetic flux Ф through each turn of the coil is given as;Ф = NAB where, A is the area of the coil and B is the magnetic field.
Assuming the coil is flat and circular, the area of the coil is given as; A = πr^2 = πd^2/4
Where r is the radius and d is the diameter of the coil. Substituting the value of N, d and dФ/dt, we have;Ф = NAB = N(Bπd^2/4)
= 499(0.041/π)(0.1)^2/4
= 8.18×10^−5 T·m²
Therefore, the magnetic flux through each turn of the coil at an instant when the current is 4.00 A is 8.18×10^−5 T·m².
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A small block is sent through point A with a speed of 6.2 m/s. Its path is without friction until it reaches the section of length L = 14 m, where the coefficient of kinetic friction is 0.71. The indicated heights are h1 = 5.3 m and h2 = 2.9 m. What are the speeds of the block at (a) point B and (b) point C? (c) Does the block reach point D? (d) If so, what is its speed there; if not, how far through the section of friction does it travel?
As a result, the speed at point B is 11.93 M/S. a) The potential energy shift from point A to point B equals the kinetic energy at point B. (b) The block doesn't really achieve point D .
because the kinetic energy at point C is equivalent to the change in potential energy from point A towards point C, which results in a speed of 9.246 m/s at point C.
d) The friction force energy from the block's kinetic energy at point C causes it to move 6.14 meters, which is much less than 14 meters. The power an entity receives as the result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it.
We must put forth effort in order to apply significant force. Once the job is finished, the energy returns towards the item, which then moves at a new, steady velocity.
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most of the exoplanets discovered around other stars a. are more massive than earth and orbit very far from the star. b. are more massive than earth and orbit very close to the star c. are less massive than earth and orbit very far from the star. d. are less massive than earth and orbit very close to the star.
Most of the exoplanets discovered around other stars are more massive than Earth and orbit very close to the star, (option b).
These types of exoplanets are commonly referred to as "hot Jupiters" because they are similar in size to Jupiter, but have much shorter orbital periods due to their close proximity to their host star. Hot Jupiters typically orbit their stars at a distance of less than 0.1 astronomical units (AU), which is much closer than the distance between Mercury and the Sun in our solar system.
The reason why hot Jupiters are easier to detect than smaller planets located further away from their star is that they cause a larger gravitational "wobble" in their star, which can be detected by astronomers using the radial velocity method.
Additionally, the transit method is another commonly used technique to detect exoplanets, and hot Jupiters are more likely to transit their star due to their close proximity.
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a 1.24 kg bowling trophy is held at arm's length, a distance of 0.505 m from the shoulder joint. what torque does the trophy exert about the shoulder if the arm is horizontal?
A 1.24 kg bowling trophy is held at arm's length, a distance of 0.505 m from the shoulder joint. 6.14 Nm torque does the trophy exert about the shoulder if the arm is horizontal
To calculate the torque exerted by the 1.24 kg bowling trophy held at arm's length (0.505 m) from the shoulder joint when the arm is horizontal, you need to follow these steps:
Determine the force exerted by the trophy.
Since the trophy has a mass of 1.24 kg
The force exerted by the trophy due to gravity can be calculated using the equation:
F = m x g
where F is the force,
m is the mass, and
g is the acceleration due to gravity (approximately 9.81 m/[tex]s^2[/tex]).
F = 1.24 kg x 9.81 m/[tex]s^2[/tex] ≈ 12.16 N (Newtons)
Calculate the torque.
Torque (τ) is the rotational force that causes an object to rotate about an axis or pivot point. In this case, the axis is the shoulder joint.
The torque can be calculated using the equation:
τ = r x F x sin(θ)
where τ is the torque,
r is the distance from the axis to the point of force application (0.505 m),
F is the force exerted by the trophy (12.16 N), and
θ is the angle between the force vector and the distance vector.
Since the arm is held horizontally, the force exerted by the trophy is acting vertically downward, which means the angle θ between the force and distance vectors is 90 degrees.
The sine of 90 degrees is 1, so the equation simplifies to:
τ = r x F.
τ = 0.505 m x 12.16 N ≈ 6.14 Nm (Newton meters)
So, the torque exerted by the 1.24 kg bowling trophy about the shoulder joint when the arm is held horizontally at a distance of 0.505 m is approximately 6.14 Nm.
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which layer of the sun is only seen during a total solar eclipse? responses core core photosphere photosphere corona corona convective zone
The layer of the sun that is only seen during a total solar eclipse is the corona.
What is the corona?The corona is a white halo of superheated gases that surrounds the Sun. The corona is a layer of the Sun's atmosphere that is very dim and can only be seen during a total solar eclipse. The corona's temperature is millions of degrees, which is hotter than the Sun's surface. Because of the Sun's magnetic field, the corona is shaped in irregular shapes and elongated formations.
The photosphere is the sun's visible surface, and it is the deepest layer of the sun that we can observe. The sun's core is located at the center of the sun, where fusion takes place to generate energy. The convective zone is just below the surface of the photosphere, and it is where gas moves around in large, circulating patterns to transfer energy to the sun's surface.
The corona, which is a bright, faint halo visible during a total solar eclipse, is the outermost layer of the sun.
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Suppose you are on a cart, initially at rest, which rides on a frictionless horizontal track. If you throw a ball off the cart towards the left, will the cart be put into motion?
Yes, and it moves to the right.
Yes, and it moves to the left.
No, it remains in place
Answer:
Yes, and it moves to the right.
Explanation:
When you throw a ball from a cart which is initially at rest on a frictionless horizontal track towards the left, the cart will move towards the right in accordance with the law of conservation of momentum.
Newton's third law?
Force is a push or pull acting on an object resulting in its interaction with another object. Force is a result of an interaction.
Force can be classified into two categories: contact force such as frictional force and non-contact force such as gravitational force.
According to Newton, when two bodies interact, they exert force on each other, and these forces are known as action and reaction pairs ,which is explained in Newton’s third law of motion.
As the ball goes towards the left, it gains a leftward momentum, and by Newton's third law of motion, the cart gains a rightward momentum, there by moving towards the right, as shown in the diagram below: [text] \boxed{ \text{Cart} \to \leftarrow \text{Ball} }[/tex]
Therefore, the correct option is 'Yes, and it moves to the right.'
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What can you do to a parallel circuit to vary the amount of current that flows through each branch?
To vary the amount of current that flows through each branch of a parallel circuit, we can:
1. Adjust the resistance
2. Add or remove branches
3. Adjust the voltage
1. Adjust the resistance: The amount of current flowing through a branch depends on the resistance in that branch.
You can change the resistance of a branch by adding or removing resistors, or by adjusting the value of variable resistors (also known as potentiometers or rheostats).
As resistance increases, the current flowing through the branch decreases, and vice versa.
2. Add or remove branches: In a parallel circuit, the total current is divided among the individual branches.
By adding or removing branches, you can affect the current distribution among the remaining branches.
For example, if you add an additional branch with the same resistance as the other branches, the current in each branch will be reduced as the total current is now divided among more branches.
3. Adjust the voltage: The current flowing through a branch is directly proportional to the voltage applied to the circuit. By changing the voltage source (battery or power supply) or adjusting the voltage, you can affect the current distribution among the branches.
Increasing the voltage will increase the current in all branches, while decreasing the voltage will decrease the current in all branches.
Remember to always be cautious when working with electrical circuits.
Turn off the power before making any adjustments or changes to the circuit, and follow proper safety procedures.
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Which step of the water cycle is the most important
Answer: evaporation.
Explanation: It soaks up moisture from soil in a garden for example, as well as the biggest oceans and lakes. The water level will decrease as it is exposed to the heat of the sun. (rewrite in your own words)
The coefficient of static friction is 0.60 between the two blocks in the figure. The coefficient of kinetic friction between the lower block and the floor is 0.20. The force causes both blocks to cross a distance of 5.0 m starting from rest. What is the least amount of time in which this motion can be completed without the top block sliding on the lower block?
The least amount of time that can be completed without the top block sliding on the lower block if the coefficient of static friction is 0.6 is 1.09 seconds.
To find the аnswer, the following steps should be tаken: first, cаlculаte the mаximum force of stаtic friction between the two blocks by multiplying the coefficient of stаtic friction by the normаl force. This gives us:
[tex]F_{friction}[/tex] = 0.60 x (10 + 5) x 9.8
= 84.6 N
Since the аpplied force is less thаn the mаximum force of stаtic friction, the two blocks will remаin in stаtic equilibrium аnd will not slide relаtive to eаch other.
Next, we cаn cаlculаte the аccelerаtion of the lower block using the net force аcting on it:
[tex]F_{net}[/tex] = [tex]F_{applied}[/tex] - [tex]F_{friction}[/tex]
= 30 - 84.6
= -54.6 N
Since the force of friction аcts in the opposite direction of the аpplied force, we use а negаtive sign. We cаn then use Newton's second lаw,
F = mа, to find the аccelerаtion:
а = [tex]F_{net}[/tex] ÷ m
= -54.6 ÷ 15
= -3.64 m/s²
Finаlly, we cаn use the kinemаtic equаtion, x = (1/2)аt², to find the time it tаkes for the lower block to trаvel а distаnce of 5.0 m:
5 = (1/2)(-3.64)t²
Solving for t, we get t = 1.09 s
Therefore, the leаst аmount of time that cаn be completed without the top block sliding on the lower block is 1.09 seconds.
Your question is incomplete, but most probably the figures can be seen in the Attachment.
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a nearsighted person has a near point of 14 cm and a far point of 40 cm .what power corrective lens is needed for her to have clear distant vision?
Power of the corrective lens needed for the nearsighted person to have clear distant vision is 0.025 diopters.
What is nearsightedness?Nearsightedness is a common vision condition in which near objects appear clear and objects farther away look blurry.
As P = 1/f
P is power of the lens in diopters, and f is focal length of the lens in meters.
Given, near point of the nearsighted person is 14 cm, which means that her eye can focus on objects that are as close as 14 cm. Given, far point is 40 cm, which means that her eye cannot focus on objects that are farther away than 40 cm.
As 1/f = 1/do + 1/di
do is object distance (which is at infinity for distant objects), di is image distance (which is the distance from the lens to the eye), and f is focal length of lens.
1/f = 1/di
di = f
f = 1/P, we get:
di = 1/P
1/P = 1/di = 1/40 cm
P = 40 cm⁻¹ = 0.025 diopters
Therefore, power of the corrective lens needed for the nearsighted person to have clear distant vision is 0.025 diopters.
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A person sitting in an artificial satellite of the earth feels weightlessness, but a person standing on moon has weight through the moon is a satellite of the earth. Why?
suppose we change the tires of our jaguar xkr to a smaller diameter, and that the speedometer is set to read the linear speed of the jaguar xkr by measuring the angular speed of the tires. how will this affect the speedometer reading when compared to the true linear speed of the jaguar xkr?
If the tires of the Jaguar XKR are changed to a smaller diameter, the speedometer will read a higher linear speed than the actual speed of the Jaguar XKR.
Linear speed is the speed at which an object travels in a straight line. A speedometer is a device that is utilized to measure the speed of a vehicle. The angular speed of the wheels is determined by the speedometer.To calculate the linear speed of the Jaguar XKR, the speedometer measures the angular speed of the wheels. The speedometer's reading will be higher than the true linear speed of the Jaguar XKR if the tires are switched to a smaller diameter.
The angular speed of the smaller tires is greater than the angular speed of the bigger tires. The smaller tires revolve more times per minute than the larger tires. This leads to a higher speedometer reading when compared to the true linear speed of the Jaguar XKR.
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According to the Big Bang theory, how many forces - and which ones - operated in the universe during the GUT era?
A. 2 forces: gravity and a single force that later became the strong, weak, and electromagnetic forces
B. 3 forces: gravity, the strong force, and the electroweak force
C. 2 forces: the strong force and the electroweak force
D. 1 force that represented the unification of all four forces that operate today
A 325 kg merry-go-round with a radius of 1.40 m is spinning clockwise as viewed from above at 4.70 rad/s. A 36.0 kg child is hanging on tightly at 1.25 m from the rotation axis of the merry-go-round. Her father applies friction to the outer rim and the merry-go-round comes to a stop in 5.00 seconds.
Model the merry-go-round as a solid disk and the child as an object.
The inertia of a solid disk with mass M and radius R is I = MR2/2.
The inertia of an object with mass M and radius R is I = MR2.
a) calculate the acceleration of the merry-go-round
b) calculate the torque exerted by the father
c) describe the directions of the initial angular velocity, torque, and acceleration vectors.
Please show work for a and b.
a)The acceleration of the merry-go-round is -1.32 m/s² and b) The torque exerted by the father is 374.8 kg m² and c) The torque is said to be in the opposite direction of the direction of motion if the sign is negative.
What are velocity and acceleration?The word for the variations in displacement rates is velocity. The measurement of a shift in speed is called acceleration. Due to the fact that it comprises both magnitude and directional components, velocity is a form of vector quantity. Another vector number is acceleration, referring to the rate upon which velocity changes.
a) We may use the rotational kinematics equation to get the merry-go-acceleration: round's
ωf = ωi + αt
We know that ωi = 4.70 rad/s and t = 5.00 s.
To find, we may rearrange the equation as follows:
α = (ωf - ωi) / t
α = (0 - 4.70 rad/s) / 5.00 s
α = -0.940 rad/s²
The following is the tangential acceleration formula:
at = rα
where r denotes the merry-go-radius. round's
at = (1.40 m)(-0.940 rad/s²)
at = -1.32 m/s²
It is clear from the negative sign that the tangential acceleration is moving anticlockwise to the starting direction of motion.
b)We may use the equation to determine the torque the father applied:
τ = Iα
I = Imerry-go-round + Ichild
Imerry-go-round = (1/2)MR²
= (1/2)(325 kg)(1.40 m)²
= 318.5 kg m²
Ichild = MR²
= (36.0 kg)(1.25 m)²
= 56.25 kg m²
I = Imerry-go-round + Ichild
= 318.5 kg m² + 56.25 kg m²
= 374.8 kg m²
Substituting :
α = -0.940 rad/s² and I = 374.8 kg m² into the torque equation:
τ = Iα = (374.8 kg m²)(-0.940 rad/s²) = -352.8 Nm
The torque is said to be in the opposite direction of the original direction of motion if the sign is negative. This indicates that the father is slowing the merry-go-round by turning a clockwise torque.
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a cat, also of weight 45.8 n , falls asleep on top of block a. if block b is now set into downward motion, what is its acceleration magnitude?
The acceleration magnitude of block B when a cat of weight 45.8 N falls asleep on top of block A is 9.8 m/s².
Let the mass of block A be m₁ and its weight be W₁.
Let the mass of block B be m₂ and its weight be W₂.
The total mass that is resting on Block B is given by the equation:
m₁ + m₂ = 45.8/9.8
Where 9.8 m/s² is the acceleration due to gravity.
The net force acting on the block B is given by:
F = (m₁ + m₂)g
Where g is the acceleration due to gravity = 9.8 m/s²
The force exerted by block A on block B is given by:
F = m₁g
Therefore the net force on Block B is given by:
Fnet = (m₁ + m₂)g - m₁g
Fnet = m₂g
The acceleration of Block B is given by the equation:
Fnet = m₂a
Therefore, a = Fnet/m₂
We have, Fnet = m₂g
Therefore, a = g
Therefore, The acceleration of block B is equal to the acceleration due to gravity, g which is 9.8 m/s². Hence, the magnitude of its acceleration is 9.8 m/s².
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move the smaller, left, powered, primary coil close to or inside the larger, secondary coil. why is no current generated in the secondary coil? (1 mark)
Current induced only when there is a varying magnetic field is no current generated in the secondary coil.
What is the function of secondary coil?If the secondary winding is linked to an electrical circuit, the electromotive force there will cause current to move in the secondary circuit. A transformer's secondary current is the winding that gets power from the primary winding via electromagnetic induction.
The secondary coil is a part of a transformer, which is an electrical device that is used to transfer electrical energy between circuits through the use of electromagnetic induction. The function of the secondary coil is to receive the electrical energy that is transferred from the primary coil of the transformer and to convert it into a different voltage level, depending on the ratio of the number of turns of wire in the primary and secondary coils.
In other words, the secondary coil of a transformer is responsible for stepping up or stepping down the voltage of the electrical energy that is being transferred from the primary coil. For example, in a step-up transformer, the voltage is increased in the secondary coil, while the current is decreased. Conversely, in a step-down transformer, the voltage is decreased in the secondary coil, while the current is increased.
What use does the secondary coil serve?The main is referred to as such, and the secondary as such. AC electricity enters the main coil here. Where the stream is induced to carry out any type of energy transfer is in the secondary coil. In this instance, a light bulb is lit by the current.
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define the critical temperature for a superconducting material. explain in words any method for measuring the critical temperature in a superconductor.
The critical temperature of a superconducting material is defined as the temperature below which a material exhibits zero electrical resistance and becomes a superconductor. This phenomenon is only observed in certain materials at very low temperatures, typically near absolute zero.
There are several methods for measuring the critical temperature in a super conductor, including resistivity measurements, magnetometry, and specific heat measurements. One of the most common methods is resistivity measurements, which involves measuring the electrical resistance of a sample as a function of temperature. At the critical temperature, the resistance of the material drops abruptly to zero, indicating the transition to a superconducting state.
Another method for measuring the critical temperature is magnetometry, which involves measuring the magnetic properties of the material as a function of temperature. Superconductors typically exhibit perfect diamagnetism, meaning they expel any applied magnetic fields from their interior. The critical temperature can be determined by measuring the temperature at which the material transitions from a magnetically susceptible state to a diamagnetic state.
Finally, specific heat measurements can also be used to measure the critical temperature in a superconductor. Specific heat is the amount of energy required to raise the temperature of a material by a certain amount, and it changes abruptly at the critical temperature. By measuring the specific heat of a material as a function of temperature, the critical temperature can be determined by identifying the temperature at which the specific heat jumps.
In conclusion, the critical temperature is the temperature at which a material exhibits zero electrical resistance and becomes a superconductor. Several methods can be used to measure the critical temperature in a superconductor, including resistivity measurements, magnetometry, and specific heat measurements.
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a copper cable has a current of 1200 a running through it. there is a potential difference of 0.016 v between two points on the cable that are 0.24 m apart. calculate the radius of the cable
The radius of the copper cable is 0.107 mm.
The formula to calculate the radius of the cable is given by;
r=ρl/πV
Where, r is the radius of the cable
ρ is the resistivity of the copper
l is the length of the cable
V is the potential difference between two points on the cable.
The potential difference between two points on the cable is given by;
V=IR
Where, I is the current running through the cable
R is the resistance of the cable.
To determine the radius of the copper cable, we need to calculate its resistance first.
Resistance of the cable can be calculated as;
R=V/IR
Substitute the values given in the equation
R=0.016/(1200 A)=1.33x10^-5 Ω
Now, we can use this resistance value and resistivity of copper to calculate the radius of the cable.
The resistivity of copper is 1.72x10^-8 Ω.m.
So, r=ρl/π
[tex]V_r = 1.72x10^-^8 Ω.
m ×0.24 m/π ×1.33x10^-^5 Ω
r=0.000107 m = 0.107 mm[/tex]
So, the radius of the copper cable is 0.107 mm.
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for a loop of current-carrying wire in a uniform magneticfield the potential energy is a minimum if the magnetic dipolemoment of the loop is:
The potential energy of a current-carrying loop in a uniform magnetic field is at a minimum when the magnetic dipole moment of the loop is aligned with the magnetic field. This means that the loop is in a position of stable equilibrium.
The magnetic dipole moment of a current-carrying loop is given by the product of the current, the area of the loop, and a vector that is perpendicular to the plane of the loop. When the loop is aligned with the magnetic field, the angle between the magnetic dipole moment and the magnetic field is zero, and the potential energy of the loop is at a minimum.
If the loop is tilted away from this position, the potential energy increases, and the loop experiences a restoring torque that tends to align it with the magnetic field.
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a crate rests in the rough bed of a truck. when the truck accelerates to the left at a constant rate, what is the direction of the friction force acting on the crate? (you can assume that the crate doesn't slip in the bed of the truck.)
The friction force acting on the crate will be in the opposite direction to the acceleration of the truck.
The friction force is opposite, because an unbalanced force, such as acceleration, will result in a friction force in the opposite direction. This is known as the Law of Inertia. The magnitude of the friction force will be dependent on the coefficient of friction between the crate and the truck bed, as well as the weight of the crate.
Assuming that the crate does not slip in the bed of the truck, then the friction force will always oppose the acceleration and will remain constant, even if the acceleration increases or decreases. This is because the static friction between the crate and the bed of the truck is much greater than the kinetic friction, and the static friction is only exceeded when the acceleration becomes too great for it to resist.
In summary, when the truck accelerates to the left at a constant rate, the friction force acting on the crate will be in the opposite direction to the acceleration of the truck. This force will remain constant until the acceleration becomes too great for the static friction to resist.
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in the future, a pair of astronauts are sent on a mission to the planet mercury. they watch the sun set one mercurian evening and decide they will go exploring in opposite directions and meet again the next time the sun is setting in the spot where they started. how long will they have to wait for the next sunset at that spot?
Answer:
On Mercury, a day (the time it takes for the planet to complete one full rotation on its axis) is 59 Earth days long. Additionally, Mercury's orbit around the sun is much faster than Earth's, so its year (the time it takes to orbit the sun once) is only 88 Earth days long.
Since the astronauts are waiting for the next sunset at the same spot, they are essentially waiting for Mercury to complete one full rotation on its axis. So they will have to wait for one Mercury day, which is 59 Earth days long.
Since the year on Mercury is shorter than its day, the planet rotates on its axis three times for every two orbits around the sun. This means that there are approximately 1.5 Mercury days in each Mercury year.
Therefore, the astronauts will have to wait for approximately 39.3 Earth days (59 Earth days/Mercury day * 1.5 Mercury days/Mercury year) for the next sunset at the same spot.
Explanation:
Mercury takes approximately 59 Earth days to complete one full rotation on its axis. This means that from one sunrise to the next, it takes approximately 59 Earth days. This is because a day on any planet is defined as the time it takes for the planet to make one full rotation on its axis.
Mercury takes approximately 88 Earth days to complete one orbit around the sun. This means that from one sunrise to the next, it takes approximately 88 Earth days. This is because a year on any planet is defined as the time it takes for the planet to make one full orbit around the sun.
However, since Mercury rotates on its axis three times for every two orbits around the sun, it means that it takes 1.5 Mercury days to complete one full orbit around the sun. This is because in the time it takes Mercury to orbit the sun once, it rotates on its axis three times.
So, if the astronauts wait for one Mercury day (i.e. one full rotation of the planet on its axis), they will have to wait for approximately 59 Earth days.
But since it takes 1.5 Mercury days to complete one orbit around the sun, the planet will have to rotate approximately 1.5 times before the same spot faces the sun again. This means that the astronauts will have to wait for approximately 1.5 Mercury days or 1.5 x 59 Earth days = 88.5 Earth days for the same spot to face the sun again.
Therefore, the astronauts will have to wait for approximately 88.5 Earth days - 59 Earth days (for one Mercury day) = 29.5 Earth days for the next sunset at the same spot. Rounding up, this is approximately 39.3 Earth days.
. a small cart on a 0.5 m long frictionless track moves with a speed of 0.75 m/s. bumpers at either end of the track reverse the cart with no loss of speed. find the period and frequency of the motion
The period and frequency of the motion is 1.33 second and 0.75 Hz respectively.
To solve this problem, we will use the formula for the period of simple harmonic motion. The period is the time taken for the object to complete one full oscillation. In this case, the object is the small cart on the frictionless track. We can use the following formula to calculate the period of the cart:
T=2L/v
where T is the period of the motion, L is the length of the track, and v is the speed of the cart.
In this case, L = 0.5 m and v = 0.75 m/s. Thus,
T=2(0.5 m)/(0.75 m/s)
T=1.33 s
The period of the motion is 1.33 seconds.
To find the frequency of the motion, we use the formula:
f=1/T
T=1.33 s
f=1/1.33
f=0.75 Hz
The frequency of the motion is 0.75 Hz.
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A 120 kg lawn tractor goes up at a 21 degree incline with a constant speed that is 12 m long in 2.5 calculate the power that is developed by the tractor
The lawn tractor generates 1.96 kW of power.
How does a tractor develop power?To generate power, tractors need to consume fuel. Although a number of fuels may be utilized with steam engines, wood and coal were by far the most popular. The use of solid fuels in internal combustion engines is not viable. Turpentine was a fuel that some of the first engine designers utilized.
The lawn tractor's work may be estimated as follows:
W = Fd cosθ
F = mgsinθ = (120 kg)(9.81 m/s²)sin(21°) = 408.9 N
The displacement is the length of the incline:
d = 12 m
The work done by the tractor is:
W = (408.9 N)(12 m)cos0°
= 4,906.8 J
The pace of task completion is determined by the tractor's power, which may be computed as follows:
P = W/t
where t represents how long it took the tractor to ascend the gradient. T = 2.5 s in this instance, so:
P = 4,906.8 J / 2.5 s
= 1,962.7 W or 1.96 kW
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a star's apparent magnitude is a measure of how bright it apppears to us if it is at its actual distane true false
Answer:
true
Explanation:
The apparent brightness of a star is how much energy is coming from the star per square meter per second, as measured on Earth. The further away the star is, the smaller the probability that a given photon emitted by the star will eventually hit Earth. Or said a quantitative form: all else being the same, the apparent brightness of a star is proportional the the inverse square of its distance.