A Mars rover traveled from point A to point B at a speed of 4 cm/sec. Worsening conditions during the return trip caused the rover to travel at a speed of 2.5 cm/sec, and increased travel time by 15 minutes. What is the distance between point A and point B?

Answer:

40.5

Step-by-step explanation:

x2 - 81 = 0 --> + 81 to both sides

2x = 81 --> divide by 2 on both sides

x = 40.5

Answer:

2x-81=0

2x=0+81

2x=81

x=81

2

x=40.5 ANSWER.

MARK ME AS A BRAINLIST PLZ.

9514 1404 393

Answer:

  y = 2x +1

Step-by-step explanation:

The line rises 2 units for each 1 unit to the right, so its slope is ...

  m = rise/run = 2/1 = 2

The line crosses the y-axis at y = 1, so the y-intercept is ...

  b = 1

Then the slope-intercept form equation is ...

  y = mx + b . . . . . . . for slope m and y-intercept b

  y = 2x + 1 . . . . . . . . fill in the known values

The midpoint of a line divides the line into equal segments.

See below for the proof of [tex]\mathbf{MN = \frac{1}{2}AC}[/tex]

The given parameters are:

[tex]\mathbf{A = (-5,-4)}[/tex]

[tex]\mathbf{B = (3,-2)}[/tex]

[tex]\mathbf{C = (-1,6)}[/tex]

The coordinates of M (midpoint of AB) are calculated as follows:

[tex]\mathbf{M = \frac{1}{2}(x_1 + x_2, y_1+y_2)}[/tex]

So, we have:

[tex]\mathbf{M = \frac{1}{2}(-5 + 3, -4-2)}[/tex]

[tex]\mathbf{M = \frac{1}{2}(-2, -6)}[/tex]

[tex]\mathbf{M = (-1, -3)}[/tex]

The coordinates of N (midpoint of BC) are calculated as follows:

[tex]\mathbf{N = \frac{1}{2}(x_1 + x_2, y_1+y_2)}[/tex]

So, we have:

[tex]\mathbf{N = \frac{1}{2}(3 - 1, -2 +6)}[/tex]

[tex]\mathbf{N = \frac{1}{2}(2, 4)}[/tex]

[tex]\mathbf{N = (1, 2)}[/tex]

Distance MN is:

[tex]\mathbf{MN = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]

So, we have:

[tex]\mathbf{MN = \sqrt{(-1 - 1)^2 + (-3 - 2)^2}}[/tex]

[tex]\mathbf{MN = \sqrt{29}}[/tex]

Distance AC is calculated as follows:

[tex]\mathbf{AC= \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}[/tex]

So, we have:

[tex]\mathbf{AC= \sqrt{(-5 - -1)^2 + (-4 - 6)^2}}[/tex]

[tex]\mathbf{AC= \sqrt{116}}[/tex]

Split

[tex]\mathbf{AC= \sqrt{4 \times 29}}[/tex]

Take positive square root of 4

[tex]\mathbf{AC= 2\sqrt{29}}[/tex]

To prove that:

[tex]\mathbf{MN = \frac{1}{2}AC}[/tex]

We have:

[tex]\mathbf{\sqrt{29} = \frac{1}{2} \times 2\sqrt{29}}[/tex]

[tex]\mathbf{\sqrt{29} = \sqrt{29}}[/tex]

The above equation is true.

Hence. [tex]\mathbf{MN = \frac{1}{2}AC}[/tex]

Read more about midpoints and distance at:

https://brainly.com/question/11231122

Step-by-step explanation:

that is really, really simple.

h(-3) means that we put the argument (-3) into the formula of the function everywhere where there is x.

h(x) = -3x - 10

so,

h(-3) = -3×-3 - 10 = 9 - 10 = -1

Answer:

-1

Step-by-step explanation:

h(x) = -3x - 10    

h(-3)            means to replace the x in the problem with the value of -3 and  

                   solve.

h(-3) = -3(-3) - 10

h(-3) =  9 - 10

h(3) = -1

Answer:

5, -5

hope this helps

Answer:

Train to BaDussy

Step-by-step explanation:

Answer:

81+71+x=180

152+x=180

x=180-152

x=28°

Step-by-step explanation:

Hope that this is helpful.

Have a great Day.

Answer:mie is

Step-by-step explanation: hehe

Answer:

Step-by-step explanation:

MY SISTER HAVE DIS EQUETION I TELL YOU

Answer:

126°

Step-by-step explanation:

1. We know that 54 degrees and its adjacent are a linear pair, meaning that they add up to 180 degrees. To find the measure of the adjacent angle, we subtract 54 from 180.

2. Now, we know that adjacent of 54 is 126. Also, we know that [tex]l[/tex] ║ [tex]m[/tex] ║ n, and x and 126 degrees are corresponding angles. Corresponding angles are congruent within angle measures, so x = 126 degrees.

________

[tex] \: [/tex]

5x - 10 = 20

5x = 20 + 10

5x = 30

x = 30 ÷ 5

x = 6✔

Answer:

The correct ratio is 7:8, so no, Emma is not correct.

Hello cayleahm253!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

There are 35 boys in 6th grade. The number of girls in 6th grade is 40. Emma says that means the ratio of the number of boys in 6th grade to the number of girls in 6th grade is 3:4. Is Emma correct? If not, what is the correct answer?

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

Okay, so we can see from the question that there are 35 boys & 40 girls in the 6th grade. So the ratio of boys is to girls will be 35:40.

__________________

Solving...

[tex]35 : 40 \\ = \frac{35}{40} \\ \\ \sf \: Cancel \: out \: 35 \: and \: 40 \: to \: get \: 7 \: and \: 8.\\ \\ = \frac{7}{8} \\ = \huge \boxed{\boxed{\bf \: 7 : 8}}[/tex]

__________________

__________________

Hope it'll help you ッ

ℓucαzz

Answer: [tex]5^{3}[/tex]

Step-by-step explanation:

Answer:

x equals 375

Step-by-step explanation:

75+0.70x=0.90x

Answer:

17 - 2= 15

so if you do

15 ÷ 3 = 5

so x= 5

Answer:

25x + 75 ≥ 30

Hope this helps!

Replace all occurrences of x with y + 3 in each equation.

Replace all occurences of x in 6x - 5y = 15 with y + 3.

6 (y+3) -5y = 15

x = y + 3

Simplify 6 (y + 3) - 5y.

Simplify each term.

Apply the distributive property.

6y + 6 · 3 - 5y = 15

x = y + 3

Multiply 6 by 3.

6y + 18 - 5y = 15

x = y + 3

Subtract 5y from 6y.

y + 18 = 15

x = y + 3

Move all terms not containing y to the right side of the equation.

Subtract 18 from both sides of the equation.

y = 15 - 18

x = y + 3

Subtract 18 from 15.

y = -3

x = y + 3

Replace all occurences with y with -3 in each equation.

Replace all occurences of y in x = y + 3 with -3.

x = (-3) + 3

y = -3

Add -3 and 3.

x = 0

y = -3

The solution to the system is the complete set of ordered pairs that are valid solutions.

(0,-3)

The result can be shown in multiple forms.

Point Form:

(0,-3)

Equation Form:

x = 0, y = -3

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The required values are :

Refer to the attachment for solution ~

Answer:

Step-by-step explanation:

Let the number is x in each case.

Use the property below:

We have:

Answer:

[tex]\log_31=0[/tex]

[tex]\log_33=1[/tex]

[tex]\log_3\left(\frac{1}{9}\right)=-2[/tex]

[tex]\log_{3}81=4[/tex]

Step-by-step explanation:

[tex]\textsf{Apply log law}: \quad \log_ax=c \iff x=a^c[/tex]

Therefore:

[tex]\log_3x=0 \implies x=3^0=1[/tex]

[tex]\log_3x=1 \implies x=3^1=3[/tex]

[tex]\log_3x=-2\implies x=3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}[/tex]

[tex]\log_3x=4 \implies x=3^4=81[/tex]

Additionally, the logarithm of 1 with any base is always zero:

[tex]\log_a1=0[/tex]

The logarithm of the same number as the base is always 1:

[tex]\log_aa=1[/tex]

Answer:

um just one question are you sure it's supposed to be d-6 instead of b-6

Step-by-step explanation:

if it's b-6 instead of d then the answer is 1

Work Shown:

45.40 - 40 = 5.40

She made $5.40 in profit. Divide this over the original price to find the percentage profit

(5.40)/(40) = 0.135 = 13.5%

Answer:

23/18 or 1 5/18

Step-by-step explanation:

In mathematics, adding and subtracting fraction required that all fractions are in similar, in converting dissimilar fraction into set of similar fraction requires finding its Least Common Denominator (LCD) or Least Common Multiple (LCM).

Equation Given

5/6 + 4/9

Finding LCM

- List down their multiples

The multiples of 6  = 6 12 18 24

The multiples of 9  = 9 18 27 36

Thus, their Least Common Multiple (LCM) is 18

Converting Dissimilar Fraction into Similar Fraction

The LCM is already the denominator

Divide the LCM by its original denominator then multiply by numerator to get the new numerator

5/6

(18 ÷ 6) × 5 = 15/18, new fraction

4/9

(18 ÷ 9) × 4 = 8/18, new fraction

Evaluate

15/18 + 8/18

= 23/18, or

= 1 5/18

Answer:

23/18 or 1 5/18

Step-by-step explanation:

In mathematics, adding and subtracting fraction required that all fractions are in similar, in converting dissimilar fraction into set of similar fraction requires finding its Least Common Denominator (LCD) or Least Common Multiple (LCM).

Equation Given

5/6 + 4/9

Finding LCM

List down their multiples

The multiple of 6

6 12 18 24

The multiple of 9

9 18 27 36

Thus, their Least Common Multiple (LCM) is 18

- Converting Dissimilar Fraction into Similar Fraction

The LCM is already the denominator

Divide the LCM by its original denominator then multiply by numerator to get the new numerator

5/6

(18 ÷ 6) × 5 = 15/18, new fraction

4/9

(18 ÷ 9) × 4 = 8/18, new fraction

- Evaluate

15/18 + 8/18

= 23/18, or

= 1 5/18

Answer:

is this the full question?

Answer:

it should be 13

Step-by-step explanation:

Answer:

The Range is 13

Step-by-step explanation:

Mean (Average): 13

Median: 12

Range:13

Largest: 21

Smallest: 8

Sum: 195

Count: 15

(Hope this helps can I pls have brainlist (crown)☺️