a longitudinal sound wave travels from left to right through the air in a room. in what directions do the air particles vibrate as the wave passes?

Answers

Answer 1

The air particles will vibrate both in rightward and leftward direction as the a longitudinal sound wave travels from left to right through the air in a room.

What is a sound wave?

A sound wave is the pattern of disruption brought on by the movement of energy moving through a medium as it propagates away from the source of the sound (such as air, water, or any other liquid or solid matter).

Pressure waves are produced when an object vibrates, such as a ringing phone, and these waves are known as sound waves. The surrounding medium's particles are disturbed by the pressure wave, and those particles disturb the particles next to them, and so on.

Like ocean waves, the disturbance's pattern causes outward movement in all directions. Usually in all directions and with decreased intensity as it gets further away from the source, the wave transmits the sound energy through the medium.

At least as far back as the first century B.C., people have believed that sound travels in waves. Both the Roman philosopher Boethius and the Roman architect and engineer Vitruvius proposed that sound might travel in waves. Galileo Galilei is credited as being the founder of the current science of sound (1564-1642).

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Related Questions

a ball is thrown upward at 25 m/s from the ground. what is the balls velocity after 4 seconds?​

Answers

Answer:

-14.2m/s

Explanation:

Given parameters:

Initial velocity of the ball  = 25m/s

Time  = 4s

Unknown:

Final velocity of the ball  = ?

Solution:

To solve this problem, we use the expression below;

               v  = u - gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

             v = 25  - (9.8 x 4)  = -14.2m/s

what is arthritis


ty for answers

Answers

Answer:

That is when your fingers are bent in a weird way and are distorted...

Explanation:

what is the answer for this question (4x³)²​

Answers

16x to the power of 6
16x to the power of 6 <3

An astronaut weighs 160 Newtons on the surface of of the moon where the acceleration due to gravity is 1.6 m/s/s. What is his weight on EARTH, where the acceleration due to gravity is 10 m/s/s? Include units in your answer. *

Answers

Answer:

The weight of an object with mass M, in a place with gravitational acceleration G, is:

W = M*G

We know that in the moon, with G = 1.6 m/s^2, the weight is 160N

Then we have the equation:

160N = (1.6 m/s^2)*M

With this, we can find the mass of the astronaut.

(160N)/(1.6 m/s^2) = M = 100kg.

Then in the Earth, where the acceleration is G = 10 m/s^2, the weight will be:

W = (10m/s^2)*100kg = 1000 N

Considerando que los coeficientes de dilatación de los siguientes metales son: hierro 11.7 x 10-6; plomo 27.3 x 10-6; cobre 16.7 x 10-6. Si tienes 3 varillas de 4 m de longitud de los diferentes metales al incrementar su temperatura 10°C cada uno, el que tendrá una mayor longitud será e

Answers

Answer:

el plomo será el más largo

Explanation:

Dado que;

longitud inicial (l1) = 4m

Longitud final l2

aumento de temperatura (θ) = 10 ° C

Coeficiente de expansión lineal α

Ahora para el hierro;

α = 11,7 x 10-6

Desde;

l2-l / l1θ = α

l2 = α l1θ + l1

l2 = l1 (αθ + 1)

l2 = 4 ((11,7 x 10-6 * 10) + 1)

l2 = 4.00044 m

Para el plomo

l2 = 4 ((27,3 x 10-6 * 10) + 1)

l2 = 4,00109 m

Para cobre

l2 = 4 ((16,7 x 10-6 * 10) + 1)

l2 = 4.000668 m

Por lo tanto, el plomo será el más largo

I WILL MARK BRAINLIEST

Answers

Answer:

well I mean it would depend on where u live for this question that's the only reason I am confused.. I'm pretty sure it's A thi

I believe the answer is A given by the position of the arrow

How many protons and electrons will each of those elements have after forming ions, and how can you tell

Answers

The proton number is the atomic number of the element, while the electron number is the atomic number minus the charge. A negatively-charged ion or anion has more electrons than protons. Again, the number of protons is the atomic number. The number of electrons is the atomic number added to the charge.

What is the density of water?
HELPPPP PLEASE!!

Answers

Answer:

1g/cm³ or 1000kg/m³ at 4°C

Density of water :
997 kg/m³

The intensity of a sound wave at a fixed distance from a speaker vibrating at 1.00kHz is 0.600 W/m².(a) Determine the intensity that results if the frequency is increased to 2.50 kHz while a constant displacement amplitude is maintained.

Answers

The intensity that results if the frequency is increased to 2.50 kHz while a constant displacement amplitude is maintained is 3.74 W/m².

What do you mean by sound intensity?

The power carried by sound waves per unit area in a direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. One use for this technology is to measure the amount of sound energy present in the air near a listener. Sound pressure and sound intensity are two different physical quantities. Sound pressure, which is correlated with sound intensity, is sensitive to human hearing. While level disparities are referred to as "intensity" differences in consumer audio electronics, sound intensity is a precisely defined quantity that cannot be detected by a straightforward microphone.

I = 2π2ρf2v∆s

Given:

Frequency, [tex]f_{1}=1\;kHz[/tex]

Increased frequency, [tex]f_{2}=2.50\;kHz[/tex]

Intensity at first, [tex]I_{1}=0.6\;W/m^{2}[/tex]

We know that,

[tex]I \propto f^{2}\;A^{2}[/tex]

Here, constant displacement amplitude is maintained,

[tex]A_{1}= A_{2} =A[/tex]

Therefore,

[tex](\frac{I_{2} }{I_{1} } ) = (\frac{f_{2} }{f_{1} } )^{2} \;(\frac{A }{A })^{2}[/tex]

Substitute the known values in the above equation,

[tex](\frac{I_{2} }{0.65} ) = (\frac{2.4}{1} )^{2}[/tex]

By solving the above equation, we get

[tex]I_{2}=3.74\;W/m^{2}[/tex]

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calculate in centimeters the distance traveled in 1 year by a rocket moving 12,000 meters/second

Answers

378,720,000,000,000cm


Cameron flies directly west for 13 km, then turns to the south and flies for another 30 km. He then flies east for 13 km before landing at the airport.

Answers

What’s the questions?

Answer:

Distance = 56km Displacement = 30km

Explanation:

hope I helped

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Answers

Answer:

Wow this I very simple actually, but its hard if you don't know how to do it like me

sam is an astronomer on planet hua, which orbits the distant star barnard. it has recently been accepted that hua is spherical in shape, although its exact size is unknown. while studying in the library, in the city of joy, sam learns that during equinox, barnard is directly overhead in the city of bar, located 1100.0 km north of his location. on the equinox, sam goes outside and measures the altitude of barnard at 78 degrees. what is the radius of hua in km?

Answers

There are 90 degrees directly overhead. Barnard is at 74 degrees at Sam's position, 1300.0 kilometers south. The part of the 360 degree circle that corresponds to Hua's circumference is the difference between 90 and 74, or 16 degrees. 1300.0 km is therefore 16/360 of the circle, or 0.044 times the circumference. 29.250 km is the circumference (1300 divided by 0.044). Radius divided by two gives the circumference equation. Therefore, 2r=29250 and the radius of Hua=4655.3 km

What do you mean by Astronomy?

Astronomy is a scientific science that examines celestial objects and phenomena (from the Ancient Greek "o" (astronoma), "science that investigates the laws of the stars"). In order to describe their creation and evolution, it makes use of mathematics, physics, and chemistry. Planets, moons, stars, nebulae, galaxies, and comets are among the interesting celestial bodies. Supernova explosions, gamma ray bursts, quasar, blazar, pulsar, and cosmic microwave background radiation are examples of relevant phenomena. Astronomy is the study of everything that comes from outside the atmosphere of the Earth. Astronomical cosmology is the study of the cosmos as a whole.

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(b) What If? A particle with charge q is located a very small distance from the center of a very large square on the line perpendicular to the square and going through its center. Determine the approximate electric flux through the square due to the charged particle.

Answers

A particle with charge q is a very small distance from the centre of a very large square on the line perpendicular to the square and going through its centre.

Since the distance between the charge and the centre of the square is very small, the square contains the field lines emerging from the charge.

[tex]\Phi_{E,square} = \frac{q}{2_{\in_{0} } }[/tex]

A particle is a small localized object which can be ascribed to several physical or chemical properties, such as volume, density, or mass.[1][2] They vary greatly in size or quantity, from subatomic particles like the electron to microscopic particles like atoms and molecules, to macroscopic particles like powders and other granular materials. Particles can also be used to create scientific models of even larger objects depending on their density, such as humans moving in a crowd or celestial bodies in motion.

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Why do we use the name electromagnetism to describe the force of an
electromagnet SOMEONE PLS ANSWER FAST

Answers

Answer:

magnet, gravity

Explanation:


A concrete block of mass 35kg is pulled along a horizontal floor with the aid of a rope inclined at an angle of 30⁰ to the horizontal. If the coefficient of friction is 0.75, Calculate the force required to move the block( g = 10 ms⁻²)

A. 401.5 N
B. 226.5 N
C. 211.5 N
D. 245. 7N​

Answers

Answer:

C. 211.5 N

Explanation:

We included a free body diagram representation of the concrete block. The equation of equilibrium in the x-direction:

[tex]\Sigma F_{x} = P\cdot \cos \alpha -\mu_{k}\cdot N = m\cdot a[/tex] (1)

[tex]\Sigma F_{y} = N + P\cdot \sin \alpha -m\cdot g = 0[/tex] (2)

Where:

[tex]P[/tex] - External force exerted on the block, measured in newtons.

[tex]N[/tex] - Normal force from the ground to the block, measured in newtons.

[tex]\alpha[/tex] - Direction of the external force, measured in sexagesimal degrees.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]m[/tex] - Mass of the concrete block, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the concrete block, measured in meters per square second.

The minimum force to move block occurs when net force is zero, from (2) we get that the normal force is:

[tex]N = m\cdot g -P\cdot \sin \alpha[/tex]

And by applying this formula in (1), we get that the external force is:

[tex]P\cdot \cos \alpha - \mu_{k}\cdot (m\cdot g -P\cdot \sin \alpha) = m\cdot a[/tex]

[tex]P\cdot \cos \alpha -\mu_{k}\cdot m\cdot g +\mu_{k}\cdot P\cdot \sin \alpha = 0[/tex]

[tex]P\cdot (\cos \alpha +\mu_{k}\cdot \sin \alpha)=\mu_{k}\cdot m\cdot g[/tex]

[tex]P = \frac{\mu_{k}\cdot m\cdot g}{\cos \alpha +\mu_{k}\cdot \sin \alpha}[/tex]

If we know that [tex]\mu_{k} = 0.75[/tex], [tex]m = 35\,kg[/tex], [tex]g = 10\,\frac{m}{s^{2}}[/tex] and [tex]\alpha = 30^{\circ}[/tex]. then the external force is:

[tex]P = \frac{(0.75)\cdot (35\,kg)\cdot \left(10\,\frac{m}{s} \right)}{\cos 30^{\circ}+0.75\cdot \sin 30^{\circ}}[/tex]

[tex]P \approx 211.518\,N[/tex]

The correct answer is C.

which two statement descibe processes most likely to be involved in the formation of sedimentary rock?

Answers

Answer:

Erosion

Explanation:

Sedimentary rocks are created from the build up of sediments, such sediments can be found in stuff like soil, other rocks and many more. Erosion is involved in these type of rocks because the byproduct of erosion are sediments.

Answer:

Rivers... and Windstorms....

Explanation:

I just did it a p e x

What resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N

Answers

resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N is [tex]20\sqrt{34}[/tex] N

force is produced by a vertical force of 60.0N

force is produced by a horizontal force of 100N

force.- A force is a push or pull of an object.

It is a vector quantity which having magnitude and direction also.

its unit is newton. denoted by capital N.

To find out the resultant of force

R² = ( (60)² + (100)²

R= √(3600 + 10000)

R =[tex]\sqrt{13600}[/tex]  N

[tex]R = 20\sqrt[]{34} N[/tex]

resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N is [tex]20\sqrt{34}[/tex]N  

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A cart sitting at the top of a hill has 9000 J of potential energy. The cart is then pushed and by the time it is half way down the hill it has converted half of its potential energy . If the carts weighs 1000 kilograms then how fast is the cart rolling when it is halfway down the hill?

Answers

Answer:

Explanation:

H

The diagram illustrates that temperature is not always increasing. At what points in the graph is there NO temperature change, why?
A. A-B; the energy is being used to melt the solid
B. B-C; the energy is being used to change the state of matter (melting)
C. C-D; the energy is being used to boil the liquid
D. the temperature is increasing throughout the graph

Answers

Answer:

A

Explanation:

Hopefully this helps

Answer:

A

Explanation:

A circular ring of charge with radius b has total charge q uniformly distributed around it. What is the magnitude of the electric field at the center of the ring? (a) 0(b) ke q / b²(c) ke q² / b²(d) ke q²/ b (e) none of those answers

Answers

The opposing electric fields cancel each other out at the center of the ring, producing a result of zero. A is the correct response.

What is an electric field?

The physical field that surrounds electrically charged particles and pulls or attracts all other charged particles nearby is referred to as the "electric field." It also characterizes the surroundings of a system of charged particles physically.

Given that the ring has a radius of b and a uniformly distributed charge of q all around it, it is perfectly circular.

Given is the electric field that is experienced at the ring's center from opposing directions.

E1 = kₑq/b²

E2 = -kₑq/b²

At the middle, it is exposed to the two opposing electric fields E1 and E2. Thus, the electric field that results is given by:

E = E1 + E2

E = kₑq/b² - kₑq/b²

E = 0

At the center of the circular ring, the opposing electric fields cancel each other out and produce a result of zero.

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What is overtraining?
A.
overloading the muscles too often
B.
progressing through exercises too quickly
C.
muscles that aren't adapting quickly enough
D.
when muscles start atrophying

What is overtraining?
A.
overloading the muscles too often
B.
progressing through exercises too quickly
C.
muscles that aren't adapting quickly enough
D.
when muscles start atrophying

Answers

Answer:

A. overloading the muscles too often

Overtraining is overloading your muscles.

What is overtraining?

Overtraining refers to a process when a person continue to exercise despite that he has reach the limit of his ability and ignores the signs of and continues to train. Many believe they need to stress their muscles to be morefit and improve their performance.

Therefore, Overtraining is overloading your muscles.

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A person is placed in a large, hollow, metallic sphere that is insulated from ground. (b) Explain what will happen if the person also has an initial charge whose sign is opposite that of the charge on the sphere.

Answers

When a person carrying the opposite charge contacts the inner surface of the sphere, the charge jumps to the metal, causing a minor shock.

The charge present on the hollow sphere always remain on its outer surface, and there will be no charge on its interior surface. Because there is no charge on the interior surface of the sphere, touching it will not cause harm. When a person with the opposite sign of the same magnitude charge comes into touch with the sphere, both the sphere and the person are neutralized. It only causes a minor shock when there is difference in magnitude. If no one touches the sphere, the charge on the outside surface will be zero, while the charge on the inside surface will be positive.

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okay please help me I’m timed!

Answers

Answer: It is C

Explanation: A disturbance that transfers energy from one place to another, without transferring matter! I just finished that unit! I hope you find this helpful and your welcome!

the answer you are looking for is c

please help me promise would mark you brainiest

Answers

B. Please mark me the brilliantest pls

please help me swear will mark brainiest

Answers

Answer:

its weight only option a.

A(n) 6.6 kg bowling ball is rolling towards the bowling pins. If its momentum is 15.9 kg*m/s, how fast is it traveling, in m/s?

Answers

Answer:

2.4m/s towards the bowling pins

Explanation:

Given parameters:

Mass of the ball  = 6.6kg

Momentum of the ball  = 15.9kgm/s

Unknown:

Speed of the ball  = ?

Solution:

The momentum is the amount of motion a body posses;

      Momentum = mas x velocity

Insert the parameters and solve;

      15.9  = 6.6 x velocity

        velocity  = 2.4m/s towards the bowling pins

What would be the resulting condition if Earth's axis was perpendicular to the Sun?

a. The winters would be much colder.
b. There would no longer be seasons.
c. The summers would be much hotter.
d. There would be a reversal of seasons.

Answers

I think it is B but I’m not sure but most likely it is

There would no longer be seasons if Earth's axis was perpendicular to the Sun because the variation in the seasons happens due to the tilt of the earth which results in unequal distribution of the sunlight on the earth's surface throughout the year.

Therefore the correct answer is option B.

What is the equator?

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

As given in the problem we have to find what happens if Earth's axis was perpendicular to the Sun,

If the Earth's axis were perpendicular to the Sun, there wouldn't be any seasons since the tilt of the planet causes an uneven distribution of sunlight on its surface throughout the year, which causes seasonal fluctuation.

Thus, the correct answer is option B.

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What is the unit for electrical power?
O volt (V)
O joule (J)
O kilowatt-hour (kWh)
O watt (W)

Answers

Answer:

The answer is Watt

Explanation:

Electricity is measured in Watts and kilowatts

Electricity is measured in units of power called Watts, named to honor James Watt, the inventor of the steam engine. A Watt is the unit of electrical power equal to one ampere under the pressure of one volt. One Watt is a small amount of power.

Watt (W) is the unit for electrical power

Which of the following does not change the resistance of a wire?
1 the medium around a wire.
2 the temperature of a wire
3 the length of a wire
4 the thickness ofa wire

Answers

Answer:

1 the medium around the wire

Explanation:

pls mark brainliest it will be my first just pls

The medium surrounding a wire, like the insulating material, doesn't significantly impact resistance, as long as the wire's physical properties and temperature remain unchanged. The correct ans  is 1. the medium around a wire.

The option that does not change the resistance of a wire is:

The medium around a wire.

Resistance in a wire is primarily determined by its physical properties, such as length, cross-sectional area (thickness), and temperature.

The temperature of a wire affects its resistance. As temperature increases, resistance also tends to increase.

The length of a wire affects resistance; longer wires offer higher resistance than shorter wires, assuming all other factors remain constant.

The thickness of a wire affects resistance; thicker wires (larger cross-sectional area) offer lower resistance than thinner wires.

The medium around a wire (Option 1) does not change the resistance of the wire. The resistance of a wire depends on its material, length, and cross-sectional area (thickness), which are constant properties of the wire. The medium or environment surrounding the wire, such as air or vacuum, does not directly affect its resistance.

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