A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of λ, and the cylinder has a net charge per unit length of 2λ . From this information, use Gauss's law to find (b) the charge per unit length on the outer surface of the

Answer:

see attachment for the answer.

Explanation:

If a toy rocket is launched vertically and rises to a height of 250 meters, then the initial velocity of the toy rocket would be 70 m / s.

There are three equations of motion given by Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem, a toy rocket is launched vertically and rises to a height of 250 meters, we have to find the initial velocity of the launch,

By using the third equation of motion given by Newton,

v² - u² = 2×a×s

0² - u² = 2×(-9.81)×250

u² = 4905

u = 70 m / s

Thus, the initial velocity of the toy rocket would be 70 m / s.

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The average speed of the car that travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h is 2km/hr.

The average speed of a moving object can be calculated by dividing the distance moved by the substance by the time taken.

Average speed = Distance/time

According to this question, a car travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h.

Average speed = 28km ÷ 14h = 2km/hr

Therefore, the average speed of the car that travels 10km for 3h, then travels 15km for another 6h, finally travels 3km for 5h is 2km/hr.

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Decibels are used to measure sound (dB). A motorcycle engine operating is roughly 95 dB louder than regular conversation, which is around 60 dB louder than a whisper.

A relative unit of measurement, the decibel (symbol: dB), is equal to one-tenth of a bel (B). It uses a logarithmic scale to express the ratio of two values of a power or root-power quantity. The power ratio between two signals with a one-decibel difference in level is 101/10 (or roughly 1.26), and the root-power ratio is 10120. (approximately 1.12). The unit can convey an absolute value or a change in the relative value. When used in this method, the unit symbol is frequently followed by letter codes that denote the reference value. In the latter situation, the numeric value reflects the ratio of a value to a fixed reference value. A typical suffix is "V" for the reference value of 1 volt, for instance (e.g., "20 dB").

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In a transverse wave, the motion of the disturbance is perpendicular to the direction of the wave motion.

A wave is a disturbance that travels through a medium. Depending on the direction of movement of the individual particles relative to the direction of the propagation of the wave, waves can be divided into longitudinal wave and transverse waves.

A transverse wave is a type of wave in which the individual particles of the medium move in a perpendicular direction relative to the direction of wave propagation. This phenomenon can be observed on a water wave. If we place a floatable object on a rippled water surface, it tends to oscillate up and down. This is because the water molecules are also oscillating up and down, perpendicular to the direction of the wave.

Other examples of transverse waves include electromagnetic waves and seismic waves.

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The car started 15 ml west of Mulberry road.

Consider the East-West route as the x-axis, and place Mulberry Road's intersection at x = 0. This implies that, the west of the intersection is -ve and the east side will be represented positive.

Given the car ends up at 18 mi West to the intersection, implies that it ends at -18mi from x = 0. Also given the total displacement = - 33mi.

Hence, initial position = final position - displacement

                                  = -18 - (- 33)

                                  = -18 + 33

                                  = 15 mi. So, the car started from 15mi from the Mulberry road and from the East of it.

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Answer:

6 kilometers per hour

Explanation:

Distance = 15km

Time= 2 hours 30 minutes

Speed = Distance / Time

Speed = 15 / 2.5

Speed = 6 km per hour.

The speed of the insect is 3.03m/s.

The speed of an object, also known as v in kinematics, is a scalar quantity that refers to the size of the change in that object's position over time or the size of the change in that object's position per unit of time. The instantaneous speed is the upper limit of the average speed as the duration of the time interval gets closer to zero. The average speed of an object over a period of time is calculated by dividing its distance traveled by the length of the interval. Distance divided by time is the dimension of speed.

Explanation:

The frequency that is received by the source after the reflection is given by,

[tex]f_{1} =f_{0} (\frac{V-v}{V-V_{b} } )(\frac{V+v_{b} }{V+v} )[/tex]

[tex]40.4=40 (\frac{343-v}{343-5} ) x (\frac{343+5}{343+v} )\\[/tex]

[tex]v=3.03 m/s[/tex]

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By analyzing the vector, the clothesline tension is 25 N.

We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as

F = (Fx i + Fy j) N

where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.

From the question we know that :

x = 10 m

(midpoint = 5m)

y = 1 m

m = 1 kg

Find the weight

W = m . g

W = 1 x 10

W = 10N

There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write

∑Fy = 0

Ty + Ty - W = 0

2Ty - 10 = 0

2Tsinθ - 10 = 0

Find sinθ

sinθ = y/x

sinθ = 1/5

Substitute the sinθ

2Tsinθ - 10 = 0

2T(1/5) - 10 = 0

2T/5 = 10

T = 25 N

Hence, the clothesline tension is 25 N.

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The buoyant force on the ball in the pool of mercury is greater.

An object is subject to the buoyant force of the liquid ( fully or partially submerged in a liquid ). An object won't sink in a liquid if its buoyant force (pointing upward) exceeds its weight (pointing downward) on the object. A fluid's buoyancy, also known as its upthrust, is the upward force it exerts in opposition to the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth. As a result, the pressure at the bottom of a fluid column is higher than at the top.

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The electric field for 10 cm is 16.2 MN/C

Length of the straight filament = (10cm) (1m/100cm) = 0.1

Electric field for the straight conductor = [tex]E = \frac{2k_{e} \lambda}{r}[/tex]

E = [2(8.99 × 10^9 N·m^2/C^2)(90.0 × 10^-6 C/m)] / 0.1 m

E = 16.2 MN/C

The electric field is directly radially inward, toward the filament.

Electric field is a force produced by a charge near its surroundings. This force is exerted on other charges when brought in the vicinity of this field. SI unit of electric field is N/C (Force/Charge).

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a)The charge per unit length (in C/m) exists on the copper rod is

3.34×10⁻¹² C/m

b) The electric flux through a cube is  0.018 N.m²/C

Electric field = it is a physical field that surrounded by electric charge particle and exert force on another charge particles.

Radius of copper rod = 1 cm. = 0.01m

The electric field strength = 3 N/C.

The electric field at 2 cm from the center of a long copper rod.

a)The charge per unit length (in C/m) exists on the copper rod.

The electric field at a point can be given as

E = λ/2πε₀r

where

λ is linear charge density

ε₀ is the permittivity in free space

r is the radius

λ = E*2πε₀r

    = 3 ×2×3.14×8.85×10⁻¹² ×2×10⁻²

λ = 3.34×10⁻¹² C/m

The charge per unit length (in C/m) exists on the copper rod is

λ = 3.34×10⁻¹² C/m

b) side of the cube is 5cm

charge enclosed inside rod is given by :

q =  λ L

using the equation of gauss law

Ф = q/ε₀

using this in the above equation we get

q(enclosed) = λ L/ε₀

q =  3.34×10⁻¹² C/m × 5× 10⁻²m / 8.85×10⁻¹²C²/N.m²

= 0.018 N.m²/C

the electric flux through a cube is  0.018 N.m²/C

a)The charge per unit length (in C/m) exists on the copper rod is

3.34×10⁻¹² C/m

b) The electric flux through a cube is  0.018 N.m²/C

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The acceleration of the motorboat is proportional to the speed.

The speed of the motorboat when it cuts its engine =

10 m/s

The motion of a motorboat is v.

[tex]v = v _{i} \: e ^{ - ct}[/tex]

[tex]10= v _{i} \: e ^{ - ct} = (v _{1})(1)[/tex]

[tex] v _{i} = 10 \:m /s[/tex]

At t = 20. seconds.

v = 5 m/s

[tex]5= 10 \: e ^{ - c(20 \: s)}[/tex]

[tex] e ^{ - c(20 \: s)} = 0.500[/tex]

At t = 40 seconds.

[tex]v = 10 \: e ^{ - 40 \: c}[/tex]

[tex] = \frac{10}{0.250} [/tex]

= 2.50 m/s

Acceleration of the motor boat is,

[tex]a = \frac{dv}{dt} [/tex]

[tex] = \frac{d}{dt} \: v = v _{i} \: e ^{ - ct}[/tex]

[tex] = v _{i} \: e ^{ - ct}(-c)[/tex]

[tex]= -c(v _{i} \: e ^{ - ct})[/tex]

a = -cv

The acceleration of the motorboat is negative constant into speed.

Therefore, the acceleration of the motorboat is proportional to the speed.

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Dimensions of a steel block that is uniformly rectangular are 1. 00 cm, 2. 00 cm, and 3. 00 cm. It starts to slide at the shallowest angle whenever the block's face comes into contact with the board.

An angle is formed when the two straight lines or rays meet at a common endpoint. The common point of the contact is called the vertex of an angle. The word angle comes from Latin word named ‘angulus,’ meaning “corner.”

In general, an angle is a figure created in Euclidean geometry by two rays that have a common terminus and are referred to as the vertices and sides of the angle, respectively.

The angles produced by the beams are always contained in the plane that comprises two rays.

In conclusion, the block will start to slide at the angle that offers the least resistance once its face makes contact with the board.

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The initial speed of the proton that is projected in the positive x direction into a region of a uniform electric field is 2.84×〖10〗^6 m/s

The equation of motions expresses the speed of an object with initial velocity u, final velocity v, and distance s, as;

v^2= u^2+2 a.s

Making u the subject of the formula,

u^2= -2 a.s

Given that:

a=5.76×〖10〗^13 m/s^2

s =7.00cm or 0.07m

Inserting values,

u^2= -2 ×(-5.76×〖10〗^13  m/s^2)×0.07m

u^2=8.06×〖10〗^12 m^2/s^2

Therefore,

u= √8.06×〖10〗^12 m^2/s^2

u=2.84×〖10〗^6  m/s

Therefore, the initial speed  of the proton is  2.84×〖10〗^6  m/s

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The calculated acceleration is for plane and in 19 s 2.63 m/s2 and 475.25 m respectively.

An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A few instances of acceleration include an apple falling, the moon orbiting the earth, or a car being halted at a set of traffic lights.

We employ the following equation to resolve the first portion of this problem.

Vf = 50 m/s final speed

Initial speed: 0 V

t=time

a=acceleration

a=(Vf-Vo)/t

a= (50-0)/19=2.63m/s^2

The following equation is used for this problem's second component.

X=(Vf^2-Vo^2)/2a

X= (50^2-0^2)/ (2*2.63)

=475.25m

The complete question is- A small turbo prop commuter airplane, starting from rest on a New York airport runway, accelerated for 19.0s before taking off. It's speed at takeoff is 50.0 m/s. Calculate the acceleration of the plane, assuming it remains constant. Part B) In this problem, how far did the plane move while accelerating for 19.0s?

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When alcohol is rubbed on your body, it lowers your skin temperature due to evaporative cooling.

The temperature at which the vapor pressure of a liquid is equal to the pressure of the atmosphere on the liquid and varies according to substances and their components.

When alcohol is rubbed on your body, it lowers your skin temperature, it evaporates and is referred to an endothermic reaction which entails absorption by the body.

Alcohol has a very low boiling point which is why rubbing it on the body will lead to evaporative cooling which will produce a cooling effect and is the most appropriate choice.

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The order of decreasing photon energy is FM radio, AM radio, yellow light, and microwaves.

Electromagnetic radiation: The electromagnetic field's waves, which are conveying electromagnetic radiant energy through space, are what make up electromagnetic radiation. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves. These waves are all a component of the electromagnetic spectrum.

Microwave radiation has wavelengths between one meter and one millimeter, which correspond to frequencies between 300 MHz and 300 GHz, respectively.

Radio waves: The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.

The radio waves have the highest photon energy and the lowest is microwaves.

So, the highest to lowest order is as follows:

FM radio, AM radio, yellow light, and microwaves.

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The energy of this radiation is 4.58 x 10⁻¹⁹ joules.

Ionizing and non-ionizing categories of radiation are typically distinguished based on the energy of the radiated particles. Ionizing radiation carries energies greater than 10 eV, which is enough to ionize atoms and molecules and break chemical bonds. This distinction is important since these compounds differ significantly in how poisonous they are to living creatures. Ionizing radiation is typically produced by radioactive materials that release radiation in the form of photons, electrons, or positrons. Other sources include secondary cosmic rays that interact with Earth's atmosphere to produce muons, mesons, positrons, neutrons, and other particles, as well as X-rays from radiography examinations used in medicine.

Calculations:

wavelength = 434nm = 434 x 10⁻⁹m

planck's constant = h= 6.626 x 10 ⁻³⁴ J

E =?

by using the formula;

E = hc /λ

value for c is 3 x 10⁸ m/s

E is equal to (6.626 x 10 34 J)(3 x 108 m/s) / 434 x 109m.

E = 1.9878 x 10⁻²⁵ / 434 x 10⁻⁹m

E = 4.58 x 10⁻¹⁹ joules

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Answer: the car mass with four would have an accelaration

Explanation:

The earth's liquid outer core is the major cause of the earth’s magnetic field.

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field. The magnetic field of a permanent magnet attracts or repels other magnets as well as ferromagnetic elements like iron. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilised in electromagnets, and electric fields that change over time produce magnetic fields that surround magnetised things.

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Since the net electric flux which is − 6.89 × 10^6 V⋅m through the hull of the submarine is negative, the number of electric field lines leaving the submarine is less than the number entering it.

A submarine (or sub) is a watercraft capable of independent operation underwater. It differs from a submersible, which has the more limited underwater capability. Most large submarines consist of a cylindrical body with hemispherical (or conical) ends and a vertical structure, usually located amidships, that houses communications and sensing devices as well as periscopes. In modern submarines, this structure is the "sail".

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The magnitude of the current in wire 3  is 2.4 A and in a direction pointing in the downward direction.

From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3

[tex]F_2_1=F_2_3[/tex]

Using equation (1) , we get

[tex]\frac{u_0I_2I_1}{0.2} =\frac{u_0I_2I_3}{0.32} \\\\\frac{I_1}{0.2} =\frac{I_3}{0.32} \\\\\frac{1.50}{0.2} =\frac{I_3}{0.32} \\\\0.48=0.2I_3\\\\I_3=2.4A[/tex]

I₃ = 2.4 A and the current is pointing in the downward direction

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The complete question is given below :

A schematic of the information provided in the question can be seen in the image attached below.Two long wires hang vertically. Wire 1 carries an upward current of 1.50 A . Wire 2,20.0cm to the right of wire 1, carries a downward current of 4.00 A . A third wire, wire 3 , is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force. (c) the magnitude and direction of the current in wire 3 .

By the charge density, the surface area of the cylinder charge is 0.20 nC.

We need to know about charge density to solve this problem. The charge density can be determined as

λ = Q / A

where λ is charge density, Q is charge and A is surface area.

The parameter given is the charge density and the solid cylinder shape which are :

λ = 15 nC/m²

r = 2.5 cm = 0.025 m

L = 6.0 cm = 0.06 m

Find the surface area of cylinder

A = 2πrL + 2πr²

A = 2π. 0.025. 0.06 + 2 . π . 0.025²

A = 0.0134 m²

Find the charges

Q = λ x A

Q = 15 x 0.0134

Q = 0.20 nC

Hence, the surface area of the cylinder charge is 0.20 nC.

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The nodes and antinodes of a standing wave always remain in a fixed position.

In a standing wave, the nodes and anti-nodes are present at fixed points.

The pattern of a standing wave shows that nodes result from destructive interference and anti-node result form constructive interference.

From a rest position, if we observe nodes and anti-node positions then we can see that nodes have zero displacement while anti-nodes are points that exhibit maximum displacement between two waves.

To put it simply, in Physics, the nodes and anti-nodes are two integral phases of a standing wave.

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When a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm, with an additional distance of 1.5cm,

Mass m= 0.30 kg

Distance x = 2.0 + 1.5 cm = 0.035 m

Since spring constant k = [tex]{\frac{mg}{x}[/tex] , (g=9.81)

k = [tex]{\frac{0.3*9.81}{0.035}[/tex] = 84.085 N/m

ω = [tex]\sqrt{\frac{k}{m} }[/tex] = [tex]\sqrt{\frac{84.085}{0.3} }[/tex] = 16.74 rad/sec

T = [tex]\frac{2\pi }{w}[/tex] = [tex]\frac{2*3.14}{16.74}[/tex] = 0.375 sec

The spring constant is the force required to stretch or compress the spring divided by the distance the spring is lengthened or shortened. It is used to determine the stability or instability of a spring and thus the system for which it is intended.

Therefore the time period of resulting oscillation is 0.375 sec.

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Answer:

Continental Rift

Explanation:

I had earth science in 2020-2021 my freshman year. Rifting can be caused when hot material from a mantle plume reaches the base of a continental plate and causes the overlying lithosphere to heat up. In addition to this the upwards movement of the plume against the base of the plate results in extensional forces which can cause rifting.

Answer: 1. Reflection

2. Refraction

3.Diffraction

4. Diffration

5.Interference

6. Reflection

7. Refraction

8. Diffraction

Good luck !