Answer:
16 seconds
Explanation:
To do this you would set up the equation 75x=1200. Then you would divide 75 from both sides so you get x=16 or it takes 12 seconds for it to travel 1200 meters
Answer:
Time = 16 s
Explanation:
Distance =Speed x Time
1200 = 75 x time
Time = 1200/75 = 16 sec
If an oxygen molecule traveling at the rms speed bounces back and forth between opposite sides of a cubical vessel of 0.10 m on a side, what is the average force the molecule exerts on one of the walls of the container? Assume the molecule’s velocity is perpendicular to the walls it hits.
Answer:
1.25x10^-19N
Explanation:see attached file pls
if rain drops of equal size fall with terminal velocity of 0.50m/s. what will be the terminal velocity if the drops collaspe to form a big drop?
Answer:
0.25m/s
Explanation:
m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1
m1*0.50m/s=2m1*v2
V2= m1*0.50m/s÷2m1
V2= 0.25m/s
Which dog has the most kinetic energy?
O A. A dog of mass 13 kg running with speed 7 m/s
O B. A dog of mass 10 kg running with speed 8 m/s
O c. A dog of mass 14 kg running with speed 6 m/s
O D. A dog of mass 15 kg running with speed 5 m/s
SUBM
Answer:
C
Explanation:
Answer:
c. A dog of mass 14 kg running with speed 6 m/sation:
a 6 letter word a way of explaining an object or event using a set of facts
Explanation:
A theory is a way of explaining an object or event using a set of facts.
The discharge of a stream is Choose one: likely to decrease downstream in arid regions and increase downstream in temperate regions. typically lower in spring than during summer. constant for the length of the stream. calculated by dividing its cross-sectional area by its velocity.
Answer:
likely to decrease downstream in arid regions and increase downstream in temperate regions
Explanation:
Arid regions are is a region with a severe lack of water, usually to the extent that affect the organisms living in the region. Arid regions are characterized by a very low depth of rainfall per year. Temperate region on the other hand experience more distinct seasonal change and wider temperature change. Temperate regions get a fairly large amount of rainfall per year.
In arid regions, the soil is very dry, and the rate of infiltration and percolation is high relative to the amount of rainfall available. The effect is that more water is infiltrated into the soil as you move downstream, leading to a decrease in the discharge of a stream as you move downstream. Most temperate region have soils that are usually saturated in the peak of the rainfall season, leading to a greater stream discharge as you move downstream.
A classroom measures 3 m X 4m x 6 m.
Calculate the volume of air in the room. Give your answer in
a
cubic metres (mº).
Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0 X 1012 electrons are added to sphere A, then the two spheres are separated. Afterward, what is the charge of sphere A
Answer:
Charge that will be left on sphere A is -8 x 10^-8 C
Explanation:
Number of electrons = 1.0 x 10^12 electrons
charge on an electron is = -1.6 × 10^-19 coulombs
for the number of electron, total charge = (1.0 x 10^12) x (-1.6 × 10^-19)
==> -1.6 x 10^-7 C
Since the two spheres were in contact when the charge was added to one of the spheres A, the sphere will then be distributed between the two spheres A and B equally. This means that after separation, sphere A will be left with
==> (-1.6 x 10^-7 C) ÷ 2 = -8 x 10^-8 C
It has been a hot summer, so when you arrive at a lake, you decide to go for a swim even though it it nighttime. The water is cold. The next day, you go swimming again during the hottest part of the day, and even though the air is warmer the water is still almost as cold. Why?
(a) Water is fairly dense compared with many other liquids.
(b) Water remains in a liquid state for a wide range of temperatures.
(c) Water has a high bulk modulus.
(d) Water has a high specific heat.
Answer:
(d) Water has a high specific heat.
Explanation:
At night, when the temperature of earth goes down due to loss of heat , the temperature of water is lost slowly and temperature of land is lost fast because of high specific heat of water . Water loses as well as gains temperature comparatively slowly due to its high specific heat .
During daytime when earth gains heat , the temperature of land rises more rapidly than water so water appears cool even during daytime when land becomes hotter . It is also due to high heat holding capacity of water or due to high specific heat of water .
5. i) Name two devices based on interaction between magnetic field and current carrying conductor.
Answer:
some common devices that use current carrying conductors and magnetic fields are electric motor electric generator loudspeakers microphones and measuring instruments like galvanometer ammeter and voltmeter
calculate the energy dissipated by an electric iron which draws a current of 5A from a240v power supply for 25minutes
Explanation:
Given,
I = 5 A
V = 240 V
T = 25 mins = 1500 sec
Now,
Energy dissipated = IVT= 5×240×1500 = 1800000 J
Fill in the blanks in the following statements:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_____light years.
3. The more distant a star, the_____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is_____.
5. The closest stars have parallaxes smaller than______arcsecond.
6. The first successful measurements of stellar parallax were made by______in year______for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is______times______then star Bob.
Answer:
Explanation:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_TWO____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_3.3____light years
3. The more distant a star, the_LESS ____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is__TRUE .___.
5. The closest stars have parallaxes smaller than_.002 _____arcsecond.
6. The first successful measurements of stellar parallax were made by_Friedrich Bessel_____in year_1838_____for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is__4____times_nearer_____than star Bob.
In a given chemical reaction the time energy of the products is less than the energy of the reactants which statements is true for this chemical reaction
Answer:
Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.
Explanation:
The energy is sometimes transferred as heat, inflicting the reaction mixture and its surroundings to become hotter. The temperature increase may be detected employing a measuring device. Some samples of exothermic reactions are: Combustion .An chemical reaction may be a chemical process that releases energy by lightweight or heat
Hope this helps...
Have a nice day!!!!
If a 3.5 gram ping pong ball were traveling to the right horizontally at 12 m/s, and a larger 12 g super ball were thrown directly behind it (also to the right) at 15 m/s so that the super ball bumped into and elastically collided with the ping pong ball, what would be the velocities of the two balls after the collision
Answer:
v = 14.32 m/s
Explanation:
According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;
[tex]m_{1} u_{1}[/tex] + [tex]m_{2} u_{2}[/tex] = ([tex]m_{1}[/tex] + [tex]m_{2}[/tex]) v
0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v
0.420 + 1.800 = (0.155) v
2.22 = 0.155 v
⇒ v = [tex]\frac{2.22}{0.155}[/tex]
= 14.323
The velocity of the balls after collision is 14.32 m/s.
Which refers to the rate of change in velocity?
O speed
O acceleration
O direction
O magnitude
Answer:
acceleration is the answer
Answer:
Acceleration
Explanation:
Since 1901, global surface temperatures have risen at an average rate of 0.13oF every ten years. In which way could the average increase in global temperatures influence Earth?
Answer:
The correct answer is "By increasing the amount of flooding because of rising sea levels".
Explanation:
The global temperature chart reflects an approximation across the whole planet's atmosphere. Owing to relatively stable entertain as well as the difficult-to-predict wind but instead, weather patterns structures, the temperature changes we perceive domestically as well as in brief periods could vary dramatically.Doubling the volume of floods due to rising water levels might also significantly affect the ordinary increase in energy consumption on Earth.The maximum pressure most organisms can survive is about 1000 times the atmospheric pressure. Only small, simple organisms such as bacteria can survive such high pressures. What then is the maximum depth at which these organisms can live under the sea (assuming that the density of seawater is 1025 kg/m3)
Answer:
h = 10000 m
Explanation:
The pressure applied at a depth of the liquid is given by:
P =ρgh
where,
P = Maximum Pressure to Survive = (1000)(Atmospheric Pressure)
P = (1000)(101325 Pa) = 1.01 x 10⁸ Pa
ρ = Density of sea water = 1025 kg/m³
g = 9.8 m/s²
h = maximum depth to survive = ?
Therefore,
1.01 x 10⁸ Pa = (1025 kg/m³)(9.8 m/s²)h
h = (1.01 x 10⁸ Pa)/(1025 kg/m³)(9.8 m/s²)
h = 10000 m
2. When backing straight or to the right: a. Position your right hand on the back of the passenger seat. b. Grip the steering wheel at the 12 o’clock position with your left hand. c. Move the wheel left or right in the direction in which you want the rear of the vehicle to go. d. All of the above
Answer:
Option d = all of the above.
Explanation:
This question is more of a driving lesson or tutorial Question and not that scientific, it is logical and the "rule" attached to reversing and driving that is operating of vehicles especially cars, trucks and so on.
All the options given in the Question from option 'a' to option 'c' are all correct when driving backwards that is reversing or backing . Driving backward(backing or reversing) is not as easy as during forward (drive mode).
=> " Position your right hand on the back of the passenger seat. Grip the steering wheel at the 12 o’clock position with your left hand"
REASON: FOR BALANCING.
=> " Move the wheel left or right in the direction in which you want the rear of the vehicle to go."
The above, given in the Question are all correct.
When backing straight or to the right, all of the mentioned options are correct and recommended practices are to Position your right hand on the back of the passenger seat. The correct option is option d.
a) Position your right hand on the back of the passenger seat: This is a technique used by some drivers to help them have a better sense of the vehicle's position and reference point while backing up.
b) Grip the steering wheel at the 12 o'clock position with your left hand: This hand position allows for better control and maneuverability of the steering wheel while backing up.
c) Move the wheel left or right in the direction in which you want the rear of the vehicle to go: This is the fundamental principle of steering while backing up. By turning the wheel in the desired direction, you can guide the rear of the vehicle in that direction.
Therefore, These practices can assist in improving control, visibility, and maneuverability while backing up, ensuring a safer and more effective backing maneuver. The correct option is option d.
To know more about the principle of steering:
https://brainly.com/question/29458022
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f(x)= 10x-5
What is the value of f-1(-4) ?
Answer:
[tex]f^{-1}(-4) = \frac{1}{10}[/tex]
Explanation:
Firstly finding [tex]f^{-1}(x)[/tex]
So,
[tex]f(x) = 10x-5[/tex]
Substitute [tex]y = f(x)[/tex]
[tex]y = 10x-5[/tex]
Exchange the values of x and y
[tex]x = 10y-5[/tex]
Solving for y
[tex]x = 10y-5[/tex]
Adding 5 to both sides
[tex]10y = x+5[/tex]
Dividing both sides by 10
[tex]y = \frac{x+5}{10}[/tex]
Replace [tex]y = f^{-1}(x)[/tex]
[tex]f^{-1}(x) = \frac{x+5}{10}[/tex]
For x = -4
[tex]f^{-1}(-4) = \frac{-4+5}{10}[/tex]
[tex]f^{-1}(-4) = \frac{1}{10}[/tex]
Answer:
[tex]\frac{1}{10}[/tex]
Explanation:
f(x) = y (output)
y = 10x - 5
Switch variables.
Solve for y.
x = 10y - 5
x + 5 = 10y
x/10 + 1/2 = y
[tex]f^{-1}(x)[/tex] = 1/10x + 1/2
Put x as -4.
1/10(-4) + 1/2
-4/10 + 1/2
-4/10 + 5/10
= 1/10
a) A conductor carrying a current I = 12.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A magnetic force per unit length of 0.110 N/m acts on the conductor in the negative y direction. Determine the magnitude of the magnetic field in the region through which the current passes.
Answer:
8.8 mT
Explanation:
Current through the conductor = 12.5 A
Magnetic force per unit length on the wire = 0.110 N/m
Recall that the magnetic force per unit length on a current carrying conductor is in a uniform magnetic field is
[tex]\frac{F}{l}= IBsin\alpha[/tex]
where B is the magnetic field magnitude
[tex]I[/tex] is the current in the conductor
α is the angle the conductor makes with the magnetic field ( since it is perpendicular in this case, α is 90°)
imputing values into the equation, we'll have
0.11 = 12.5 x B x sin 90°
but sin 90° = 1, therefore, we have
0.11 = 12.5B
B = 0.11/12 = 8.8 x 10^-3 T
or rather = 8.8 mT
Two forces are acting on a 5.00 kg mass. One of the forces is 10.0 N south and the other is 15.0 N east. The direction of the acceleration of the mass is
Answer:
The direction of the acceleration of the mass is due East.
Explanation:
Data obtained from the question include the following:
Mass = 5 kg
Force due South = 10 N.
Force due East = 15 N.
To know which direction the acceleration of the mass will go, we must first obtain the resultant force.
This is illustrated below:
Resultant force = 15 – 10 = 5 N
Therefore, the resultant force is 5 N due East since the larger force is due East
Since the resultant force is due East, it means that the mass will accelerate toward the East.
According to the question,
Mass = 5 kgForce due south = 10 NForce due east = 15 NThe resultant force will be:
= [tex]15-10[/tex]
= [tex]5 \ N[/tex]
Since the larger force is due east. Thus the answer above is right.
Learn more about force here:
https://brainly.com/question/1844505
An object weighing 150 N and is suspended from the ceiling by a wire. What is the tension in the cord?
Answer:
150NExplanation:
According to newton's third law of motion, Action and reaction are equal and opposite, hence for an object that weighs 150N suspended by a wire, the tension on the wire is 150N
Ultimately the tension on a string or an object is equal to the mass times gravity(which is same as the weight of the object)
Answer:
its 150
Explanation:
The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a pendulum (to nearest hundredth) if it makes one swing in 2.1 seconds? Use 3.14 for \pi .
Answer:
3.6ft
Explanation:
Using= 2*π*sqrt(L/32)
To solve for L, first move 2*n over:
T/(2*π) = sqrt(L/32)
Next,eliminate the square root by squaring both sides
(T/(2*π))2 = L/32
or
T2/(4π2) = L/32
Lastly, multiply both sides by 32 to yield:
32T2/(4π2) = L
and simplify:
8T²/π²= L
Hence, L(T) = 8T²/π²
But T = 2.1
Pi= 3.14
8(2.1)²/3.14²
35.28/9.85
= 3.6feet
Find “d” in the following figure
Answer:
16 m
Explanation:
Given:
v₀ = 4 m/s
a = 4 m/s²
t = 2 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (4 m/s) (2 s) + ½ (4 m/s²) (2 s)²
Δx = 16 m
A snail at position 3 cm moves to position 20 cm in 8 seconds.
Answer: 17cm.
Explanation:
The equation you're using is:
Δd = df - di
Which means the change in position is equal to the final position minus the starting position. In this case that works out to 20cm - 3cm = 17cm. We're only interested in how much the snail moved, not how long it took to move, so even though they give a time it actually doesn't matter for this question.
Can anyone tell me how to read a micrometer screw gauge I want very clear instructions.
Explanation:
Things you need to know:
Accuracy refers to the maximum error encountered when a particular observation is made.
Error in measurement is normally one-half the magnitude of the smallest scale reading.
Because one has to align one end of the rule or device to the starting point of the measurement, the appropriate error is thus twice that of the smallest scale reading.
Error is usually expressed in at most 1 or 2 significant figures.
Tape
Equipment: It is made up of a long flexible tape and can measure objects or places up to 10 – 50 m in length. It has markings similar to that of the rigid rule. The smallest marking could be as small as 0.1 cm or could be as large as 0.5 cm or even 1 cm.
How to use: The zero-mark of the measuring tape is first aligned flat to one end of the object and the tape is stretched taut to the other end, the reading is taken where the other end of the object meets the tape.
Ruler
Equipment: It is made up of a long rigid piece of wood or steel and can measure objects up to 100 cm in length. The smallest marking is usually 0.1 cm.
How to use: The zero-end of the rule is first aligned flat with one end of the object and the reading is taken where the other end of the object meets the rule.
Vernier Caliper
Equipment: It is made up of a main scale and a vernier scale and can usually measure objects up to 15 cm in length. The smallest marking is usually 0.1 cm on the main scale.
It has:
a pair of external jaws to measure external diameters
a pair of internal jaws to measure internal diameters
a long rod to measure depths
How to use: The jaws are first closed to find any zero errors. The jaws are then opened to fit the object firmly and the reading is then taken.
Micrometer Screw Gauge
Equipment: It is made up of a main scale and a thimble scale and can measure objects up to 5 cm in length. The smallest marking is usually 1 mm on the main scale (sleeve) and 0.01 mm on the thimble scale (thimble). The thimble has a total of 50 markings representing 0.50 mm.
It has:
an anvil and a spindle to hold the object
a ratchet on the thimble for accurate tightening (prevent over-tightening)
How to use: The spindle is first closed on the anvil to find any zero errors ( use the ratchet for careful tightening). The spindle is then opened to fit the object firmly (use the ratchet for careful tightening) and the reading is then taken.
A patient had stunted growth,swelling on face,discolaration of hair and skin disease.the doctor advised him to eat a lot of pulses,grams,albumin of the egg and milk etc.,which is wrong with the patient?Explain in two sentences
Answer:
The patient is suffering from protein deficiency
Explanation:
Protein deficiency is characterized by symptoms such as stunted growth; skin, nail and hair problems, loss of muscle mass, and in extreme cases, kwashiorkor.
Deficiency in protein is usually corrected by taking foods rich in protein such as egg's albumin, milk, pulses, beans, etc; hence the advice of the doctor.
what is the formula of gravitational force
Answer:
[tex]\displaystyle F_g = \frac{GM_1 m_2}{r^2}[/tex]
[tex]F_g[/tex] is the force.
[tex]G[/tex] is the gravitational constant.
[tex]M_1[/tex] is the mass of one object.
[tex]m_2[/tex] is the mass of the other object.
[tex]r[/tex] is the distance between the two objects.
A charged particle with charge of 2 (uC) and mass 10-20 (kg) is traveling with velocity of 108 (m/s) in space. The charge reaches to a region in space with magnetic field of 0.05 (T) and experience a force of 8 (N) exerted by the magnetic field.
A- What is the angle between velocity of particle and magnetic field direction?
B- What is acceleration of charged particle while experiencing the force?
Answer:
Explanation:
A ) Let the angle be θ between magnetic field and velocity of charged particle
Force created on charged particle F
= Bqv sinθ, B is magnetic field , q is charge , v is velocity of charged particle
F = .05 x 2 x 10⁻⁶ x 10⁸ x sinθ
8 = 10 sinθ
sinθ = .8
θ = 53°.
B )
acceleration = force / mass
= 8 / 10⁻²⁰
= 8 x 10²⁰ m / s²
3.27 moles of an ideal gas has a pressure of 125000 Pa at 15.0 ° C What is the volume of the gas?
Answer:
15.96 m³ (corrected to 2 d.p.)
Explanation:
Using idea gas law:
pV = nRT
pressure p = 125000 Pa
volume V = unknown
no. of moles n= 3.27 moles
ideal gas constant R = 8.3145 J K−1 mol−1
Temperature t (in Kelvins) = 15 + 273.15 = 288.15K
125000 x v = 3.27 x 8.3145 x 288.15
v = 15.96 m³ (corrected to 2 d.p.)
Answer:
0.0626 m^3
Explanation:
First, we know that the equation to calculate the behavior of gases is:
PV=nRT
Looking at the problem, we understand that we are needing to solve for V, which means we need to isolate V to solve for it.
The new equation will look something like this:
V=nRT/P
The last step is to simply plug in the remaining variables:
n=3.27
R=8.31 (that is not given but is a standard number that you will always use for "R"/ the ideal gas constant-it helps to right it down somewhere to reference it if you ever need it!)
P=125000
T=288 (the temp needs to be in degrees K, so take 15.0 degrees c and + 273)
Finally, when you input all of those, you will have something that looks like this:
V=(3.27*8.31*288)/125000
V=0.02608205 m^3
V= 0.0626 m^3 (rounded to 3 sig. figs)
I hope this was helpful and easy to understand!
8. You have two iron rods which are identical in appearance, but one is a permanent magnet and the other is unmagnetized. What series of simple experiments can you perform, using only the two rods, which will allow you to determine which of the rods is the permanent magnet
Answer:
Explanation: Let assume that bars are labeled A and B
Method 1
Using just the identical appearing bar magnet and unmagnetized iron bar.
Place the end of bar A in the middle of bar B.
If bar A sticks to bar B, then bar A is the magnet and bar B the umagnetized iron bar.
If bar A jumps to one of the ends of bar B, then bar B is the magnet.
Reason been that the magnetic field on a bar magnet is greatest at the two poles where the field comes out of the magnet. The center, between the poles, will be the weakest part of the field.
Method 2
Another solution would be to separate the two by quite some distance, float them on a piece of cork/wood in a plastic bucket or suspend them from long strings, then see which one consistently (eventually) lines up tending towards the Earth’s magnetic field.