A jumbo jet collides with a sparrow. If neither exerts a greater force of impact, which experiences greater acceleration and why

Answer:

the deeper into the ocean you go, the more pressure is exerted on you

Explanation:

Answer:

the only correct answer is: Photons of lower-frequency light don't have enough energy to eject an electron

Explanation:

This question is in the model of the photoelectric effect, where some electrons are expelled from the metal by the action of a ray of light.

This effect was explained by Einstein supposes that the light rays are formed by photons and the energy of these photons is given by the Planco relation

           K = h f - Ф

where K is the kinetic energy of the ejected electrons and Ф is the work function, it keeps the electrons inside the material.

When analyzing this expression there is a minimum frequency (threshold) for which K = 0

           hf = Ф

Below this frequency the photons in the light beam do not have the energy to expel the electrons from the material.

Let's examine the answers

a) True. You agree with the above

b) False. The analysis is in terms of individual shock

c) False. The expulsion does not have to do with the number of photons but with the energy of each one

therefore the only correct answer is: Photons of lower-frequency light don't have enough energy to eject an electron

Answer:

All the elements except for the ones on the last column (at the left of the periodic table)

Explanation:

Answer:

Tactical movement

Explanation:

Speed and time play a significant factor in Tactical movement. The correct option is B.

Tactical movement refers to the coordinated and strategic movement of military units or teams to achieve a specific objective. It is a fundamental aspect of military operations and involves the use of various tactics and techniques to move troops and equipment safely and efficiently on the battlefield.

Tactical movement can involve various modes of transportation, such as on foot, in vehicles, or by air. It also involves the use of cover and concealment to avoid detection by the enemy, and the use of communication and signal systems to coordinate movements and maintain situational awareness.

The success of the tactical movement depends on many factors, including the terrain and weather conditions, the size and composition of the units involved, the available resources and equipment, and the tactics and strategies employed by both friendly and enemy forces. It requires careful planning, training, and execution to ensure that the movement is successful and achieves the desired outcome.So, tactical movement is an essential component of military operations, and plays a critical role in achieving victory on the battlefield.

Here in the Question,

Tactical movement refers to the movement of military units or teams in a coordinated and strategic manner to achieve a specific objective. In such movements, speed and time are critical factors because they determine the success or failure of the mission. The speed of movement can help to surprise the enemy, take advantage of a weakness in their defense, or seize a key position before they can respond. Time is also important because the longer it takes to achieve the objective, the more likely the enemy is to detect and counter the movement. Therefore, tactical movement requires careful planning and execution to ensure that the right units move at the right speed and at the right time to achieve the desired outcome.

Therefore, the correct option is B i.e Tactical movement.

To learn about Kinetic energy click:

https://brainly.com/question/26472013

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Answer; thermal energy

Explanation:

'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.

Answer:

protons

Explanation:

Answer:

The forward motion of a body in space, such as a planet or moon, and the pull of gravity on it from another body in space.

Explanation:

Earth and many other bodies—including asteroids, comets, and the other planets—move around the sun in curved paths called orbits. Generally, the orbits are elliptical, or oval, in shape. Because of the sun’s relatively strong gravity, Earth and the other bodies constantly fall toward the sun, but they stay far enough away from the sun because of their forward velocity to fall around the sun instead of into it. As a result, they keep orbiting the sun and never crash to its surface. The motion of Earth and the other bodies around the sun is called orbital motion. Orbital motion occurs whenever an object is moving forward and at the same time is pulled by gravity toward another object.

Answer:

a)  F = - 1.21 10⁶ N,  b)  F = - 8.06 10⁴ N

Explanation:

a) For this part let's use the kinematics relations

          v² = v₀² - 2 a x

distance traveled to stop is x = 1.00 cm = 0.0100 cm, final speed is zero

          0 = v₀² - 2 ax

          a = v₀² / 2x

          a = [tex]\frac{19^2 }{2 \ 0.01}[/tex]

          a = 1.81 10⁴ m / s²

this acceleration is in the opposite direction to velocity

let's use Newton's second law

          F = ma

          F = 67.0 (-1.81 10⁴)

          F = - 1.21 10⁶ N

the negative sign indicates that it is going in the opposite direction to the speed

b) in this case it is stopped by an airbag x = 15.0 cm = 0.15 m

         a = v₀² / 2x

         a = [tex]\frac{19^2}{2 \ 0.15}[/tex]

         a = 1.203 10³ m / s²

calculate the force

         F = m a

         F = 67.0 (- 1.203 10³)

         F = - 8.06 10⁴ N

Answer:

[tex]P_{sp}=178.4W/kg[/tex]

Explanation:

From the question we are told that:

Mass of fish [tex]m_f=650kg[/tex]

Cross-sectional area [tex]A=0.92 m^2[/tex]

Drag coefficient of [tex]\mu= 0.0091[/tex]

Seawater  density [tex]\rho= 1026 kg/m^3.[/tex]

Speed of  Fish [tex]v=30 m/s[/tex]  

Generally the equation for Drag force F_d is mathematically given by

[tex]F_d = \mu * \rho *A v^2 /2[/tex]

[tex]F_d = 0.0091* 0.92* 1026* 30^2/2 \\F_d= 3865. 35 N[/tex]  

Generally the equation for high speed  Power  [tex]P_{sp}[/tex] is mathematically given by

[tex]P_{sp}=3865*35*\frac{v}{m_f}[/tex]

[tex]P_{sp}=F_d*35*\frac{30}{650}[/tex]

[tex]P_{sp}=178.4W/kg[/tex]

Answer:

I = 5000 A

Explanation:

We will use Ampere's Law to calculate the current:

[tex]B = \frac{\mu I}{2\pi r}\\\\[/tex]

where,

B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T

μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²

I = Current = ?

r = radius = 10 m

Therefore,

[tex]1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}[/tex]

I = 5000 A

Answer:

[tex]a=2,5m/s^2[/tex]

Explanation:

From the question we are told that:

Coefficient of kinetic friction [tex]\mu= 0.200[/tex]

Vertical Mass [tex]M_v=3kg[/tex]

Horizontal mass [tex]M_h=3.00kg[/tex]  

Generally the equation for kinetic force [tex]F_k[/tex] is mathematically given by

[tex]F_k=\mu N\\F_k=0.2*3\\F_k=0.6[/tex]

Generally the equation for T is mathematically given by

[tex]For M_v=3kg3g-T=3a[/tex]

For [tex]M_h=3kg[/tex]

[tex]T=M_v V+F_k\\T=3.0a+0.6[/tex]

Therefore substituting

[tex]3-3a-0.6=3a\\2.4g=6a[/tex]

[tex]a=2,5m/s^2[/tex]

Answer:

Answer:

Answer:

The ratio of the new volume to the old volume is 8 to 1.

Explanation:

Let's first list what we know:

Since the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.

The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.

Now, let's solve for the volume of the new cube:

[tex]V = s^3[/tex]

[tex]V = 8^3[/tex]

[tex]V = 512[/tex]

The volume of the new cube is 512 [tex]m^3[/tex].

The ratio of the new volume to the old volume is 512 : 64.

Let's simplify the ratio:

512 : 64

8 : 1

The ratio of the new volume to the old volume is 8 to 1.

P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)

There actually three assertions here: one in A and two more in B.

All three assertions, as well as the reasoning described in this mess, are all False.

The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.

Answer:

coiled spring have a potential energy

Answer:

Which of these have a potential energy? A coiled spring.

Explanation:

Have a great day.

Answer:

The equation of momentum for a linear system is simply P = mv where P = momentum (kg·m/sec or lb·ft/sec); m = mass (kg or lb); and v = velocity (m/s or ft/sec). ... By reducing her inertia (I = mr2 where r has been decreased) her angular velocity, ω, must increase in order for the angular momentum to remain constant.

https://www.gstatic.com/education/formulas2/355397047/en/moment_of_inertia.svg

hope this helps?

Explanation:

Answer:

A. The angular acceleration of the disk is -1.047 radians per square second.

B. The disk turns 4.715 radians while stopping.

C. The disk did 0.750 revolutions while stopping.

Explanation:

A. In this case, the disk is deceleration at a constant rate. Hence, the angular acceleration experimented by the object ([tex]\alpha[/tex]), in radians per square second, can be found by means of this kinematic expression:

[tex]\alpha = \frac{\omega-\omega_{o}}{t}[/tex] (1)

Where:

[tex]\omega_{o}[/tex] - Initial angular speed, in radians per second.

[tex]\omega[/tex] - Final angular speed, in radians per second.

[tex]t[/tex] - Time, in seconds.

If we know that [tex]\omega_{o} \approx 3.142\,\frac{rad}{s}[/tex], [tex]\omega = 0\,\frac{rad}{s}[/tex] and [tex]t = 3\,s[/tex], then the angular acceleration of the disk is:

[tex]\alpha = \frac{\omega-\omega_{o}}{t}[/tex]

[tex]\alpha = -1.047\,\frac{rad}{s^{2}}[/tex]

The angular acceleration of the disk is -1.047 radians per square second.

B. The change in position of the disk ([tex]\Delta \theta[/tex]), in radians, is determined by the following kinematic formula:

[tex]\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}[/tex] (2)

If we know that [tex]\omega_{o} \approx 3.142\,\frac{rad}{s}[/tex], [tex]\omega = 0\,\frac{rad}{s}[/tex] and [tex]\alpha = -1.047\,\frac{rad}{s^{2}}[/tex], then the change in position is:

[tex]\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}[/tex]

[tex]\Delta \theta = 4.715\,rad[/tex]

The disk turns 4.715 radians while stopping.

C. A revolution equals 2π radians, then, then number of revolutions done by the disk while stopping is found by simple rule of three:

[tex]\Delta \theta = 4.715\,rad \times \frac{1\,rev}{2\pi\, rad}[/tex]

[tex]\Delta \theta = 0.750\,rev[/tex]

The disk did 0.750 revolutions while stopping.

Answer:

The correct solution is "1230 K".

Explanation:

The given values are:

[tex](V_{rms})_1= 200 \ m/sec[/tex]

[tex](V_{rms})_2= 350 \ m/sec[/tex]

[tex]T_1=400 \ K[/tex]

As we know,

⇒  [tex]V_{rms} \propto \sqrt{T}[/tex]

or,

⇒  [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]

On substituting the values, we get

⇒  [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]

⇒   [tex]T_2=1230 \ K[/tex]

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Answer:

a) 6.24 × 10⁻³ V

b) 4.16 × 10⁻³ m²/s

Explanation:

Given that:

(a)

Area A = 0.026 m²

[tex]\dfrac{dB}{dt}=0.24 \ T/s[/tex]

[tex]e=\dfrac{d\phi}{dt} \\ \\ = \dfrac{d}{dt}(BA) \\ \\ =A\dfrac{dB}{dt} \\\\= 0.026 \times 0.24 \\ \\ = 0.00624\ V \\ \\ \mathbf{= 6.24 \times 10^{-3} \ V}[/tex]

(b)

[tex]Here; \\ \\ e =0\\\\ \dfrac{d}{dt}(BA) =0 \\ \\ \implies B\dfrac{dA}{dt}+ A\dfrac{dB}{dt} = 0 \\ \\ B\dfrac{dA}{dt}= -A\dfrac{dB}{dt} \\ \\ \dfrac{dA}{dt}= -\dfrac{A}{B} \dfrac{dB}{dt} \\ \\ = -\dfrac{0.026}{1.5}\times 0.24 \\ \\ \dfrac{dA}{dt}= 4.16 \times 10^{-3}\ m^2/s[/tex]

Answer:

D) The tray would need to be raised higher before the items start to slide.

Explanation:

The tray would need to be raised higher due to the gritty sandpaper causing it to have more grip or fraction between the two surfaces. In the first experiment it would have a smooth surface to slide across but in the second experiment it would have a rougher surface to slide across.

Example: It would be like taking two different kinds of shoes like tennis shoes and football cleets. Then seeing which one has more traction when going up a hill.

Hope this helps!!

I would say answer D

A is very easy, so that's off the table, while be is a little too advanced for intermediate, and C is way to advanced for intermediate.

So yeah, D

Answer:

C. Solids,Liquids, Gases

Answer:

Magnet withe competitive prices and high quality they offer custom-made magnets in defferent form and made with defferent materials grades

Explanation:

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