Answer: 10x454x0.55=2,497 grams of fruit
List some typical benefits an employee might receive on top of their wage?
Answer:
paid vacation
paid medical
401k
Solve 0 = 4x2+12x+9.
Select the equation that shows the correct
substitution of a, b, and c in the quadratic formula.
121 122 - 4(4309)
2(4)
X=
-12 + 122 +4(4)(9)
2(4)
o
-121 122 – 4(4)(9)
2(4)
Answer:
The correct substitution of a, b, and c in the quadratic formula is given by
[tex]$ x=\frac{-12\pm\sqrt{(12)^2-4(4)(9)}}{2(4)} $[/tex]
[tex]x = - \frac{ 3}{2} \: and \: x = -\frac{ 3}{2} \\\\[/tex]
The solutions of the given quadratic equation are real and equal.
Step-by-step explanation:
The given quadratic equation is
[tex]4x^2+12x+9 = 0[/tex]
The coefficients a, b and c are as follow:
[tex]a = 4 \\\\b = 12\\\\c = 9[/tex]
The quadratic formula is given by
[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]
The correct substitution of a, b, and c in the quadratic formula is given by
[tex]$ x=\frac{-12\pm\sqrt{(12)^2-4(4)(9)}}{2(4)} $[/tex]
Bonus:
The solution of this quadratic equation is given by
[tex]x=\frac{-12\pm\sqrt{(144 - 144)}}{8} \\\\x=\frac{-12\pm\sqrt{0}}{8} \\\\x=\frac{-12\pm 0}{8} \\\\x=\frac{-12 + 0}{8} \: and \: x=\frac{-12 - 0}{8}\\\\x= -\frac{ 3}{2} \: and \: x = -\frac{ 3}{2} \\\\[/tex]
Therefore, the solutions of the given quadratic equation are real and equal.
4(2n + 3) =44 pls someone help me with this??
Answer:
n = 4
Step-by-step explanation:
4(2n + 3) = 44
Expand the brackets.
4(2n) + 4(3) = 44
8n + 12 = 44
Subtract 12 on both sides.
8n + 12 - 12 = 44 - 12
8n = 32
Divide both sides by 8.
(8n)/8 = 32/8
n = 4
Solve the following question
The difference of two numbers is 12 and their sum is 20 find the numbers
Answer:
they are 16 and 4
Step-by-step explanation:
We can call the numbers x and y and we can write:
x - y = 12
x + y = 20
Adding these equations gives us 2x = 32 which means x = 16 and substituting this value into the first equation gives us y = 4.
Answer:
The numbers are 16 and 4
Step-by-step explanation:
Let the two numbers be x and y
x-y = 12
x+y = 20
Add the two equations together
x-y = 12
x+y = 20
-------------------
2x = 32
Divide by 2
2x/2 =32/2
x = 16
Now find y
x+y =20
16+y =20
Subtract 16
y = 20-16
y = 4
|6–x|=5 plzzzzzzzzz help
Answer: x = 1, 11
Step-by-step explanation:
When answering a problem like this, normally, you first isolate the absolute value. As it is already isolated, the next thing you do is split the equation into 6–x=5 and 6–x=-5, because the contents of the absolute value could be negative or positive, and simplifying both into x = 1, and x = 11.
Hope it helps <3
write a function rule for the table be quick plzz
What will be the perimeter and the area of the rectangle below if it is enlarged using a scale factor of 3.5?
Perimeter = 98 cm, area = 588 cm2
Perimeter = 42 cm, area = 109.25 cm2
Perimeter = 42 cm, area = 588 cm2
Perimeter = 98 cm, area = 109.25 cm2
Answer:
first option
Step-by-step explanation:
After it's enlarged, the new dimensions will be 6 * 3.5 = 21 and 8 * 3.5 = 28, therefore, the new perimeter will be 2(21 + 28) = 2 * 49 = 98 and the area will be 21 * 28 = 588.
i need help quick i will mark brainilest
Answer:
x-y
Step-by-step explanation:
X is greater than y so we are subtracting the smaller number from the bigger number
That means we do not need the absolute value signs since x-y will be positive
|x-y| when x> y
x-y
Using numbers
| 5-2| 5>2
5-2
Write the equations after translating the graph of y=|2x|−1: one unit to the left
Answer:
y = | 2(x + 1) - 1
Step-by-step explanation:
Given f(x) then f(x + c) represents a horizontal translation of f(x)
• If c > 0 then shift to the left of c units
• If c < 0 then shift to the right of c units
Here the shift is 1 unit to the left , thus
y = | 2(x + 1) ] - 1
Right triangle ABC is located in A(-1,-2), B(-1,1) and C(3,1) on a coordinate plane. what is the equation of a circle with radius AC?
A) (x+1)*2+(y+2)*2=9
B) (x+1)*2+(y+2)*2=25
C) (x-3)*2+(y-1)*2= 16
D) (x-3)*2+(y-1)*2=25
Answer:
Hey there!
First, we want to find the radius of the circle, which equals the length of line segment AC.
Length of line segment AC, which we can find with the distance formula: [tex]\sqrt{25\\[/tex], which is equal to 5.
The equation for a circle, is: [tex](x-h)^2+(y-k)^2=r^2[/tex], where (h, k) is the center of the circle, and r is the radius.
Although I don't know the center of the circle, I can tell you that it is either choice B or D, because the radius, 5, squared, is 25.
Hope this helps :) (And let me know if you edit the question)
Answer: The equation of the circle is (x+1)²+(y+1)² = 25
Step-by-step explanation: Use the Pythagorean Theorem to calculate the length of the radius from the coordinates given for the triangle location: A(-1,-2), B(-1,1) and C(3,1) The sides of the triangle are AB=3, BC=4, AC=5.
Use the equation for a circle: ( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.
As the directions specify, the radius is AC, so it makes sense to use the coordinates of A (-1,-2) as the center. h is -1, k is -2 The radius 5, squared becomes 25.
Substituting those values, we have (x -[-1])² + (y -[-2])² = 25 .
When substituted for h, the -(-1) becomes +1 and the -(-2) for k becomes +2.
We end up with the equation for the circle as specified:
(x+1)²+(y+1)² = 25
A graph of the circle is attached. I still need to learn how to define line segments; the radius is only the segment of the line between the center (-1,-2) and (1,3)
The number 35 has the property that when its digits are both increased by 2, and
then multiplied, the result is 5 x 7 = 35, equal to the original number.
Find the sum of all two-digit numbers such that when you increase both digits by 2,
and then multiply these numbers, the product is equal to the original number.
Answer: The sum is 127
Step-by-step explanation:
A 2-digit number N = ab can be written as (where a and b are single-digit numbers)
a*10 + b.
Now, we want that:
(a + 2)*(b + 2) = a*10 + b.
So we must find all the solutions to that equation such that a can not be zero (if a = 0, then the number is not a 2-digit number)
We have:
(a + 2)*(b + 2) = a*b + 2*a + 2*b + 4 = a*10 + b
a*b + 2*b - b + 4 = a*10 - a*2
a*b + 4 + b = a*8
a*b + 4 + b - a*8 = 0.
Now we can give one of the variables different values, and see if the equation has solutions:
>a = 1:
1*b + 4 + b - 8 = 0
2*b - 4 = 0
b = 4/2 = 2
Then the number 12 has the property.
> if a = 2:
2*b + 4 + b -16 = 0
3b -12 = 0
b = 12/3 = 4
The number 24 has the property.
>a = 3 is already known, here the solution is 35.
>a = 4.
4*b + 4 + b - 8*4 = 0
5*b + 4 - 32 = 0
5*b = 28
b = 28/5
this is not an integer, so here we do not have a solution.
>if a = 5.
5*b + 4 + b - 8*5 = 0
6b + 4 - 40 = 0
6b - 36 = 0
b = 36/6 = 6
So the number 56 also has the property.
>if a = 6
6*b + 4 + b - 8*6 = 0
7b + 4 - 48 = 0
7b - 44 = 0
b = 44/7 this is not an integer, so here we do not have any solution.
>if a = 7
7*b + 4 + b -8*7 = 0
8b -52 = 0
b = 52/8 = 6.5 this is not an integer, so we here do not have a solution.
>if a = 8
8*b + 4 + b -8*8 = 0
9*b + 4 - 64 = 0
9*b = 60
b = 60/9 this is not an integer, so we here do not have any solution:
>if a = 9
9*b + 4 + b - 8*9 = 0
10b + 4 - 72 = 0
10b -68 = 0
b = 68/10 again, this is not an integer.
So the numbers with the property are:
12, 24, 35 and 56
And the sum is:
12 + 24 + 35 + 56 = 127
what is the frequency distribution table
Step-by-step explanation:
The frequency distribution table is a table that shows the particular values and corresponding frequencies. It consists of two tables first for clas interval and other for frequency.There are many types of frequency distribution such as Grouped frequency distribution, Cumulative frequency distribution., Relative cumulative frequency distribution etc.One way of organizing data is by constructing a frequency distribution table. A tally mark is used to record how often a particular score or number occurs. The number of times a score or number appears is called the frequency.
To construct a frequency distribution table:
a. list the scores or numbers from highest to lowest (or lowest to highest),
b. use tally marks to record how often each score or number appears, and
c. count the marks and record it in the frequency column.
Please answer this question now
Answer:
16.2
Step-by-step explanation:
use Pythagorean theorem
a^2 + b^2 = c^2
15^2 + 6^
225 + 36 = 261
take the sq root of 261
Jake is going to call one person from his contacts at random. He has 30 total contacts. 16 of those contacts are people he met at school.
What is P(Call a person from school)
Answer:16/30
Step-by-step explanation:
An infinite geometric series converges if the common ratio is
Answer:
a proper fraction
pls answer asap i need this answer quick plus the full explanation #7
Tammy has $20 to spend at the movie theater. She spends $9.50 on a movie ticket. If the snack counter sells bags of candy for $3.50 each, how many bags of candy can Tammy buy with the money she has left?
Answer:
She can buy 3 candy bags.
Step-by-step explanation:
Let the number of bags = x.
9.5 + 3.5x = 20
3.5x = 10.5
x = 3
Answer: She can buy 3 candy bags.
Answer:
3
Step-by-step explanation:
With steps , please.
[tex]\bold{\text{Answer:}\quad x=\dfrac{1}{2},\quad y=1,\quad z=\dfrac{1}{3}}[/tex]
Step-by-step explanation:
[tex]\text{Equation 1:}\quad \dfrac{x}{x+y}=\dfrac{1}{3y}\\\\\\.\qquad \qquad \qquad 3xy=x+y\\\\.\qquad \qquad \qquad 3xy-y=x\\\\.\qquad \qquad \qquad y(3x-1)=x\\\\.\qquad \qquad \qquad y=\dfrac{x}{3x-1}[/tex]
[tex]\text{Equation 2:}\quad \dfrac{y}{y+z}=\dfrac{1}{4z}\\\\\\.\qquad \qquad \qquad 4yz=y+z\\\\.\qquad \qquad \qquad 4yz-y=z\\\\.\qquad \qquad \qquad y(4z-1)=z\\\\.\qquad \qquad \qquad y=\dfrac{z}{4z-1}[/tex]
[tex]\text{Equation 3:}\quad \dfrac{z}{z+x}=\dfrac{1}{5x}\\\\\\.\qquad \qquad \qquad 5xz=z+x\\\\.\qquad \qquad \qquad 5xz-z=x\\\\.\qquad \qquad \qquad z(5x-1)=x\\\\.\qquad \qquad \qquad z=\dfrac{x}{5x-1}[/tex]
Set Equation 1 equal to Equation 2 and substitute z per Equation 3
[tex]\dfrac{x}{3x-1}=\dfrac{z}{4z-1}\\\\\\x(4z-1)=z(3x-1)\\\\4xz-x=3xz-z\\\\4x\bigg(\dfrac{x}{5x-1}\bigg)-x=3x\bigg(\dfrac{x}{5x-1}\bigg)-\dfrac{x}{5x-1}\\\\\\4x^2-x(5x-1)=3x^2-x\\\\4x^2-5x^2+x=3x^2-x\\\\0=4x^2-2x\\\\0=2x(2x-1)\\\\0=2x\qquad\qquad 0=2x-1\\\\x=0\qquad \qquad x=\dfrac{1}{2}[/tex]
Solve for y when x = 0:
[tex]\text{Equation 1:}\quad y=\dfrac{0}{3(0)-1}\quad \rightarrow \quad y=0[/tex]
Notice that x + y is in the denominator and denominator cannot equal zero so x = 0 is an invalid solution.
[tex]\text{Solve for y when}\ x=\dfrac{1}{2}:\\\\\text{Equation 1:}\quad y=\dfrac{\frac{1}{2}}{3(\frac{1}{2})-1}\quad \rightarrow \quad y=1[/tex]
[tex]\text{Solve for z when x = \dfrac{1}{2}}:\\\text{Equation 3:}\quad z=\dfrac{\frac{1}{2}}{5(\frac{1}{2})-1}\quad \rightarrow \quad z=\dfrac{1}{3}[/tex] [tex]\text{Solve for z when}\ x=\dfrac{1}{2}:\\\\\text{Equation 3:}\quad z=\dfrac{\frac{1}{2}}{5(\frac{1}{2})-1}\quad \rightarrow \quad z=\dfrac{1}{3}[/tex]
If the area of the trapezoid below is 75 square units, what is the value of x? AB=17 DC=8
A. 1.5
B. 12
C. 6
D. 3
Diagram related to the question can be found in the attached picture below :
Answer: 6 units
Step-by-step explanation:
From the diagram attached to the question:
Length AB = 17
Length DC = 8
height (h) = x
Area of trapezium = 75sq units
The Area (A) of a trapezium is given by:
(1/2) × (a + b) × h
Where ;
a and b are the upper and base lengths of the trapezium
h = height of trapezium
A = (1/2) × (a + b) × h
75 = (1/2) * (17 + 8) * x
75 = 0.5*25*x
75 = 12.5x
x = 75 / 12.5
x = 6 units
At what meter mark will Ario be when Miguel starts the race? Round to the nearest tenth. x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 A number line goes from 0 to 25. A line is drawn from 3 to 25. The point at 3 is labeled Start and the point at 25 is labeled End. Miguel and his brother Ario are both standing 3 meters from one side of a 25-meter pool when they decide to race. Miguel offers Ario a head start. Miguel says he will start when the ratio of Ario’s completed meters to Ario’s remaining meters is 1:4.
Answer: 7.4 meters
Step-by-step explanation:
Start Mark = 3m
End mark = 25m
Total length to race = 25 - 3 = 22m
Position of both Ario and miguel = 3 meter from one side of the pool; that is 3 meters behind the START MARK
Ario's completed to remain ratio = 1:4
Total ratio = 5
Ario's Completed meters = (22/5) * 1 = 4.4m
Therefore, when Miguel starts the race, Ario will be on (4.4meters + number of meters behind the start mark)
= 4.4 meters + 3 meters = 7.4meters
The distance of Ario from the start point when miguel starts is;
7.44 m
We are told that A line is drawn from 3 to 25.This means distance of line = 25 - 3 = 22 m
The start point is at the 3 m mark.Miguel and his brother Ario are standing 3 m from one side of the pool.
This means that they are both 3 meters behind the start point.
We are told that the ratio of Ario’s completed meters to Ario’s remaining meters is 1:4.Thus, ario's completed meters when Miguel will start is;
¹/₅ × 22 = 4.4 m
Since Miguel is 3 m from the start and Ario has just done 4.4 m, then it means that;Distance of miguel from Ario when miguel starts = 3 + 4.4 = 7.4 m
Read more about algebra at; https://brainly.com/question/11408596
Determine if the question is statistic or not, college in Jacksonville do tennis coaches get paid more than football coaches
Answer:
Yes, because to get the answer for this question one of the things you would do is most likely look at a group of statistics average them, and see who gets paid more.
Convert -(3)^1/2 - i to polar form
Answer:
2(cos30°+isin30°)
Step-by-step explanation:
Complex value z is written in a rectangular form as z = x+iy where (x, y) is the rectangular coordinates.
On converting the rectangluar to polar form of the complex number;
x = rcosθ and y = rsinθ
Substituting in the rectangular form of the comlex number above;
z = rcosθ + irsinθ
z = r(cosθ+isinθ)
r is the modulus of the complex number and θ is the argument
r =√x²+y² and θ = tan⁻¹y/x
Given the complex number in rectangular form z = -(3)^1/2 - i
z = -√3 - i
x = -√3 and y = -1
r = √(-√3)²+(-1)²
r = √3+1
r = √4
r = 2
θ = tan⁻¹ (-1/-√3)
θ = tan⁻¹ (1/√3)
θ = 30°
Hence the complex number in polar form will be z = 2(cos30°+isin30°)
plssssssss helppp 3x – 5 = 1
Answer:
x = 2
Step-by-step explanation:
Add 5 to both sides to get the 5 to the right side since we are trying to isolate the variable x:
3x – 5 + 5 = 1 + 5
Simplify: 3x=6
Divide each side by 3 to isolate and solve for x:
3x/3=6/3
Simplify: x=2
plz HELPPPP with this):
Answer:
Graph 4
Step-by-step explanation:
The graph of f(x) = x^3 includes point (0, 0) since f(0) = 0^3 = 0.
The exponent of x is 3. This is not a linear function.
Negative values of x cubed are negative, and positive values of x cubed are positive.
For x < 0, f(x) < 0, and for x > 0, f(x) > 0.
Answer: Graph 4.
For a chemical reaction to occur, at least one-third of the solution must be an acid. If there are five liters of acid, in interval form, how much solution is present?
A. [5,8)
B. (3/5,5]
C. (5/3,5]
D. [5,15]
Answer:
Amount of solution = 15 liter
Step-by-step explanation:
Given:
One third of solution is acid
Amount of acid = 5 Liter
Find:
Amount of solution
Computation:
Amount of solution = Amount of acid (1 / One third of solution is acid)
Amount of solution = Amount of acid (3)
Amount of solution = (5)(3)
Amount of solution = 15 liter
How do you solve -6(4d+5)+7d=-2d
Answer:
d = -2Step-by-step explanation:
-6(4d + 5) + 7d = -2d -24d - 30 + 7d = - 2d -17d - 30 = -2d+2d+30 +2d+30
-15d = 30÷(-15) ÷(-15)
d = -2my mistake it's actually d= -30/19 sometimes I forget you put them in fractions
Dos conductores A y B llenan un estanqe en 20 horas .Si el conductor B fuera un desague el estanq se llenaria en 52 horas ¿En q tiempo se llenara el estanque estando solo abierto el conducto A?
Answer:
Con el conducto A abierto, el estanque se llenará en 32.5 horas.
Step-by-step explanation:
Deje que el volumen de agua presente en el estanque sea x litros
La tasa conjunta sería x / 20 litros por hora.
Para el conducto A, no sabemos la hora, llamemos a esto y así que la tasa aquí será x / y
Para el conducto B tomará 52 horas y su tasa es x / 52
Matemáticamente, cuando sumamos ambas tasas juntas, obtendremos la tasa conjunta; Así; x / y + x / 52 = x / 20
Saca x en ambos lados 1 / y+ 1/52 = 1/20
(52 + y) / 52y = 1/20
20 (52 + y) = 52y
1040 + 20y= 52y
1040 = 52y -20y
32y = 1040 y = 1040/32
y = 32.5 horas
Con el conducto A abierto, el estanque se llenará en 32.5 horas.
Ted and three of his friends went out to eat. They decided to split the bill evenly. Each person paid $16.88. What was the total bill?
Answer:
Total bill = $67.52
Step-by-step explanation:
Ted + 3 = 4
$16.88 × 4 = $67.52
hopefully this helped you :3
Answer:
16.88*4= 67.52 dollars
Step-by-step explanation:
Ted and 3 friends split the bill evenly, each person paid 16.88:
16.88*4= 67.52 dollars
Trignometry Question Please help
Answer:
19.45°
Step-by-step explanation:
Suppose the post is 1 unit high. Then the distance from the post to another corner of the rectangle will satisfy the relation ...
distance/1 = tan(90° -angle of elevation)
So, for the near corner, the distance from the post is ...
distance = tan(90° -36°) = tan(54°) = 1.37638 . . . post lengths
For the other given corner, the distance from the post is ...
distance = tan(90° -22°) = tan(68°) = 2.47509 . . . post lengths
The Pythagorean theorem can be used to find the distance from the post to the diagonally opposite corner:
distance^2 = 1.37638^2 +2.47509^2 = 8.02048
distance = √8.02048 ≈ 2.83205
The relation of this to the angle of elevation is ...
tan(angle of elevation) = 1/2.83205
angle of elevation = arctan(1/2.83205) ≈ 19.45°
_____
In the attached diagram, we have used segments BP and CP as surrogates for the post, so we could determine distances PD and PE that are the sides of the rectangular courtyard. Then the courtyard diagonal is PF. Using PA as a surrogate for the post, we found the angle of elevation from F to A (the top of the post) to be 19.45°, as computed above.
A sample of college students was asked how they felt about their weight. Of the 143 women in the sample who responded, 38 women said that they felt overweight, 99 felt that their weight was about right, and 6 felt that they were underweight. Of the 78 men in the sample, 18 men felt that they were overweight, 35 felt that their weight was about right, and 25 felt that they were underweight (Data source: pennstate3 dataset on the companion website).
a. In the relationship between feelings about weight and sex, which variable is the explanatory variable and which is the response variable?
b. Summarize the observed counts by creating a table similar to Tables 2.2 and 2.3 (p. 21).
c. For the 143 women, find the percentage responding in each category for how they felt about their weight.
d. For the 78 men, find the percentage responding in each category for how they felt about their weight.
e. Using the percentages found in parts (c) and (d), summarize how the women and men differed in how they felt about their weight.
Answer:
a. Feelings about weight is the response (dependent) variable. Sex is the explanatory (independent) variable. The feelings about weight depend on the sex
b. Summary of observed counts
Women Men Total
Overweight 38 18 56
Right weight 99 35 134
Underweight 6 25 31
Number 143 78 221
c. Percentage of the 143 women responding in each category:
1. Overweight = 38/143 = 26.6%
2. Right weight = 99/143 = 69.2%
3. Underweight = 6/143 = 4.2%
d. Percentage of the 78 men responding in each category:
1. Overweight = 18/78 = 23.1%
2. Right weight = 35/78 = 44.9%
3. Underweight = 25/78 = 32%
e. Summary of feelings about weight:
Women Men
Overweight 26.6% 23.1%
Right weight 69.2% 44.9%
Underweight 4.2% 32%
Step-by-step explanation:
a) Data:
Sample size = 221
Women Men Total
Overweight 38 18 56
Right weight 99 35 134
Underweight 6 25 31
Number 143 78 221
b) To obtain the percentage of feelings about weight for each category, the number of those who feel overweight, right weight, or underweight is divided by the total number of women or men. The value obtained, which is in decimal form, is then converted to percentage by multiplying with 100.