A house painter stands 3.00 m above the ground on a 5.00-m-long ladder that leans against the wall at a point 4.70 m above the ground. The painter weighs 676 N and the ladder weighs 107 N. Assuming no friction between the house and the upper end of the ladder, find the force of friction that the driveway exerts on the bottom of the ladder. If the force of friction is away from the wall, enter a negative value and if the force of friction is toward the wall, enter a positive value.
Answers
Answer:
The force of friction that the driveway exerts on the ladder ≈ -176.03 N
Please see attached force diagram created with MS Visio
Explanation:
The height of the house painter above the ground = 3.00 m
The length of the ladder = 5.00 m
The height above the ground at which the ladder leans on the wall = 4.70 m
The weight of the painter = 676 N
The weight of the ladder = 107 N
The angle of inclination of the ladder, arcsin(4.7/5) ≈ 70.05°
For equilibrium, the sum of moments at a point, ∑M = 0
Taking moment about point A gives;
4.7 × R = 107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5)))
R = (107 × 2.5 × cos(arcsin(4.7/5)) + 676 × 3.0/(tan(arcsin(4.7/5))))/4.7 ≈ 176.03
The reaction force at the top of the ladder, R ≈ 176.03 N
For equilibrium, we have;
The sum of the horizontal forces, ∑Fₓ = 0
The reaction at the top of the ladder, R + The force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] = 0
R + [tex]F_R[/tex] = 0
∴ R = [tex]-F_R[/tex]
R ≈ 176.03 N = [tex]-F_R[/tex]
∴ [tex]F_R[/tex] = -176.03 N
Therefore, the force of friction that the driveway exerts on the bottom of the ladder, [tex]F_R[/tex] ≈ -176.03 N (acting away from the wall).
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EXPLANATION
s = v × t/2
600 m = v × 3.5 s/2
600 m × 2 = v × 3.5 s
1200 m = v × 3.5 s
v = 1200 m/3.5 s
v = 342.86 m/s
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The speed of sound in that place 342.86 m/s
What is speed of sound?
The speed of sound is defined as the distance through which a sound wave’s point, such as a compression or a rarefaction, travels per unit of time.
given
distance of cliff= 600 m
time = 3.5 seconds
speed of sound = ?
distance = speed * time
distance travelled by the sound to come back to the place where the girl was standing will be = 600 * 2 m
speed = distance / time
speed = 600 * 2 m / 3.5 seconds
speed = 1200 / 3.5 = 342.86 m/s
The speed of sound in that place 342.86 m/s
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pretty sure thats my explanation "pretty sure" like my confidence? mark me brainliest bad at spelling lol
will give correct answer brainliest
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he or she is right good jod
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As given in the problem, on a trip you travel at a constant speed of 50 kilometers per hour North for 1 hour. Then you turn West and travel at a constant speed of 40 kilometers per hour for 2 hours.
The final displacement of the trip = √(50² + 80²)
= 94.34 kilometers
The velocity of the trip = total displacement of the trip / time period
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= 31 kilometers per hour
Thus, the velocity of the trip would be 31 kilometers per hour.
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Water will help flush toxins out of the body.
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It is always easier to drink than to eat if you are sick.
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Answer:
A.
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Answer:
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Explanation:
1.
The pressure in a liquid is due to the weight of the column of water above. Since the particles in a liquid are tightly packed, this pressure acts in all directions. For example, the pressure acting on a dam at the bottom of a reservoir is greater than the pressure acting near the top.
2.
Fluid pressure can be caused by gravity, acceleration, or forces in a closed container. Since a fluid has no definite shape, its pressure applies in all directions. Fluid pressure can also be amplified through hydraulic mechanisms and changes with the velocity of the fluid.
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Answer:
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21. A fisherman catches two sturgeons. The smaller of the two has a measured length of 93.46 cm (two dec- imal places and four significant figures), and the larg- er fish has a measured length of 135.3 cm (one deci- mal place and four significant figures). What is the total length of the two fish?
Answers
Answer:
135.3 cm + 93.46cm
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